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• error message: clientside validation

  - by user281180

  What is the meaning of the following error message?How can I use the EnableClienTValidation()? Error 3 'System.Web.Mvc.HtmlHelper' does not contain a definition for 'EnableClientValidation' and no extension method 'EnableClientValidation' accepting a first argument of type 'System.Web.Mvc.HtmlHelper' could be found (are you missing a using directive or an assembly reference?) c:\Dev\DEV\test3\Code\MvcUI\Views\Customer\Create.aspx 11 13 MvcUI I have reference the following:`" type="text/javascript" <script src="<%=Url.Content("~/Scripts/jquery.validate.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftAjax.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftMvcAjax.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftMvcJQueryValidation.js" )%>" type="text/javascript"></script> `

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• Cannot decode complete cipher list in .NET SslStream handshake.

  - by karmasponge

  While attempting to move from a 'C' based SSL implementation to C# using the .NET SslStream and we have run into what look like cipher compatibility issues with the .NET SslStream and a AS400 machine we are trying to connect to (which worked previously). When we call SslStream.AuthenticateAsClient it is sending the following: 16 03 00 00 37 01 00 00 33 03 00 4d 2c 00 ee 99 4e 0c 5d 83 14 77 78 5c 0f d3 8f 8b d5 e6 b8 cd 61 0f 29 08 ab 75 03 f7 fa 7d 70 00 00 0c 00 05 00 0a 00 13 00 04 00 02 00 ff 01 00 Which decodes as (based on http://www.mozilla.org/projects/security/pki/nss/ssl/draft302.txt) [16] Record Type [03 00] SSL Version [00 37] Body length [01] SSL3_MT_CLIENT_HELLO [00 00 33] Length (51 bytes) [03 00] Version number = 768 [4d 2c 00 ee] 4 Bytes unix time [… ] 28 Bytes random number [00] Session number [00 0c] 12 bytes (2 * 6 Cyphers)? [00 05, 00 0a, 00 13, 00 04, 00 02, 00 ff] - [RC4, PBE-MD5-DES, RSA, MD5, PKCS, ???] [01 00] Null compression method The as400 server responds back with: 15 03 00 00 02 02 28 [15] SSL3_RT_ALERT [03 00] SSL Version [00 02] Body Length (2 Bytes) [02 28] 2 = SSL3_RT_FATAL, 40 = SSL3_AD_HANDSHAKE_FAILURE I'm specifically looking to decode the '00 FF' at the end of the cyphers. Have I decoded it correctly? What does, if anything, '00 FF' decode too? I am using the following code to test/reproduce: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Net.Sockets; using System.Net.Security; using System.Security.Authentication; using System.IO; using System.Diagnostics; using System.Security.Cryptography.X509Certificates; namespace TestSslStreamApp { class DebugStream : Stream { private Stream AggregatedStream { get; set; } public DebugStream(Stream stream) { AggregatedStream = stream; } public override bool CanRead { get { return AggregatedStream.CanRead; } } public override bool CanSeek { get { return AggregatedStream.CanSeek; } } public override bool CanWrite { get { return AggregatedStream.CanWrite; } } public override void Flush() { AggregatedStream.Flush(); } public override long Length { get { return AggregatedStream.Length; } } public override long Position { get { return AggregatedStream.Position; } set { AggregatedStream.Position = value; } } public override int Read(byte[] buffer, int offset, int count) { int bytesRead = AggregatedStream.Read(buffer, offset, count); return bytesRead; } public override long Seek(long offset, SeekOrigin origin) { return AggregatedStream.Seek(offset, origin); } public override void SetLength(long value) { AggregatedStream.SetLength(value); } public override void Write(byte[] buffer, int offset, int count) { AggregatedStream.Write(buffer, offset, count); } } class Program { static void Main(string[] args) { const string HostName = "as400"; TcpClient tcpClient = new TcpClient(HostName, 992); SslStream sslStream = new SslStream(new DebugStream(tcpClient.GetStream()), false, null, null, EncryptionPolicy.AllowNoEncryption); sslStream.AuthenticateAsClient(HostName, null, SslProtocols.Ssl3, false); } } }

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• How to embed a font in website

  - by Mayur

  Hi All, I am trying to embed my custom font in my web site, got a link folder from http://www.fontsquirrel.com/fontface/generator this site after uploading a font on this site, it gives me a css @font-face { font-family: 'VoltaEFTU-Regular'; src: url('voltaeftu-regular-webfont.eot'); src: local('?'), url('voltaeftu-regular-webfont.woff') format('woff'), url('voltaeftu-regular-webfont.ttf') format('truetype'), url('voltaeftu-regular-webfont.svg#webfonttKmU3jX8') format('svg'); font-weight: normal; font-style: normal; } but its not working in my machines how can i embed a font in my web site.... Thanks Mayur Mate

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• Counting HTML images with Python

  - by user2537246

  I need some feedback on how to count HTML images with Python 3.01 after extracting them, maybe my regular expression are used properly. Here is my code: import re, os import urllib.request def get_image(url): url = 'http://www.google.com' total = 0 try: f = urllib.request.urlopen(url) for line in f.readline(): line = re.compile('<img.*?src="(.*?)">') if total > 0: x = line.count(total) total += x print('Images total:', total) except: pass

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• invite friends in a dialog in a Facebook application

  - by Shani1351

  I'm trying to create a Facebook application that displays a friend invite dialog within the application using Facebook's Javascript API (FB.ui). To do that I followed this tutorial I have two problems : The action url I've put in the request-form is "http://apps.facebook.com/appname/post_invite.php" but I see that the iframe source after the post is "http://mydomain.com/post_invite.php" and when this iframe tries to do : parent.closeInviteWidget(); I get an error saying : "Permission denied for < http: //mydomain.com (document.domain has not been set) to get property Window.closeInviteWidget from < http:// apps.facebook.com (document.domain=< http:// facebook.com)." The skip button inside the request-form opens the action url in a new window (new browser tab) and not post to itself like the invite button. How can I fix those problems? -------------------- UPDATE : -------------------------------- I've tried to do what ifaour said and changed the code to : function inviteFriends(user_name, category_id, category_name) { url = appBaseUrl + "/index.php?category_id=" + category_id; req = "<fb:req-choice url='" + url + "' label='Authorize My Application' />"; content = user_name + " opened a new category called " + category_name + ". " + req; action = 'post_invite.php'; fbmi_text = '<fb:request-form action="' + action + '" target="_self" method="post" invite="true" type="Invite" content="' + content + '" <fb:multi-friend-selector showborder="false" actiontext="Invite yor friends" email_invite="false" import_external_friends="false" /> </fb:request-form>'; FB.ui({ method:'fbml.dialog', width:'750px', fbml:fbmi_text }); } When I use FireBug and look at the invite form it looks like this: <form id="req_form_4d20682f73ddb6e71722794" content="I've opened a new category called dsfsd. <fb:req-choice url='http://apps.facebook.com/appname/index.php?category_id=60' label='Authorize My Application' /> type="Invite" invite="true" method="post" target="_self" action="http://apps.facebook.com/appname/post_invite.php"> ... </form> But I still get the same error : Permission denied for <http://mydomain.com> (document.domain has not been set) to get property Window.closeInviteWidget from <http://apps.facebook.com> (document.domain=<http://facebook.com>)...

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• jQuery AJAX Redirection problem

  - by meosoft

  Hello please consider this: On page A I have a link that takes you to page B when JS is off, but when JS is on, I want to replace content on current page with content from the page B. Pages A and B are in fact the same script that is able to tell AJAX calls from regular ones and serve the content appropriately. Everything works fine, as long as there are no redirects involved. But, sometimes there is a 301 redirect and what seems to be happening is that client browser then makes a second request, which will return with a 200 OK. Only the second request is sent without a X-Requested-With header, therefore I cannot tell within my script wether it came from AJAX or not, and will send a complete page instead of just the content. I have tried checking for 301 status code in my error, success, and complete handlers but none of them worked. It seems to be handling the 301 behind the scenes. Could anyone help me with this? jQuery 1.4, PHP 5 Edit: People requested the code to this, which I didn't think was necessary but here goes: // hook up menu ajax loading $('#menu a').live("click", function(){ // update menu highlight if($(this).parents('#menu').size() > 0){ $("#menu>li").removeClass("current_page_item"); $(this).parent().addClass("current_page_item"); } // get the URL where we will be retrieving content from var url = $(this).attr('href'); window.location.hash = hash = url; $.ajax({ type: "GET", url: url, success: function(data){ // search for an ID that is only present if page is requested directly if($(data).find('#maincontent').size() > 0){ data = $(data).find('#maincontent .content-slide *').get(); } // the rest is just animating the content into view $("#scroller").html(data); $('.content-slide').each(setHeight); $('.content-slide').animate({ left: "0px" }, 1000, 'easeOutQuart', function(){ $('#home').css("left", "-760px").html(data); $('#scroller').css("left", "-760px"); $('.content-slide').each(setHeight); } ); } }); return false; });

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• how to access anti aliasing method of a font with CSS

  - by Daniel Ramirez-Escudero

  I've had this problem in a lot of different webs. You have a font which has different anti-aliasing options, the designer uses the same font with different anti-aliasing options on different parts of the text on the web. So there is a difference between some elements. In this case I have sharp, crisp, strong and smooth. I've used a font generator to get the code to access it via @font-face. Even so, I also have the original .otf if important to know. Is there a method to access this? I upload a picture of what I mean and my actual code: ![@font-face { font-family: 'light'; src: url('../_fnt/light/gothamrnd-light.eot'); src: url('../_fnt/light/gothamrnd-light.eot?#iefix') format('embedded-opentype'), url('../_fnt/light/gothamrnd-light.woff') format('woff'), url('../_fnt/light/gothamrnd-light.ttf') format('truetype'), url('../_fnt/light/gothamrnd-light.svg#../_fnt/light/gothamrnd-light') format('svg'); font-weight: normal; font-style: normal; }]![enter image description here][1]

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• MVC + Extjs + IIS6 + Wildcard Mapping = Post Form resulting in 302 object moved

  - by Orkun Balkanci

  Everything seems to work fine until i want to submit the form and update the database. Wildcard mapping works on requests like "/navigation/edit/1", but when i submit the form as: var ajaxPost = function(Url, Params) { Ext.Ajax.request({ url: Url, params: Params, method: 'POST', async: false, scope: this }); }; it says "200 bad response: syntax error" and in firebug there is "Failed to load source for: http://.../Navigation/edit/1". Any help?

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• Problems with sticky footer html css

  - by CJava

  I'm having trouble making a sticky footer, whatever I do the code completely messes up and re-arranged positioning of other elements. I'm using multiple div elements. I have tried pretty much most tutorials on stickying footers online like http://www.cssstickyfooter.com/using-sticky-footer-code.html Help would be much appreciated. Thanks a lot! html: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta name="generator" content="HTML Tidy for Linux (vers 25 March 2009), see www.w3.org"> <title>Southend-on-Sea Independant Tourist Guide</title> <!--Attached CSS to keep constant throughout site--> <link rel="stylesheet" type="text/css" href="style.css"> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <meta name="description" content="An independant tourist guide on Southend-on-Sea"> <meta name="keywords" content="southend, southend-on-sea, tourist guide, tourist, independant"> <meta name="author" content="Callum Stevens"> <link rel="shortcut icon" type="image/x-icon" href="/favicon.ico"><!--[if !IE 7]> <style type="text/css"> #wrap {display:table;height:100%} </style> <![endif]--> <link rel="stylesheet" type="text/css" href="style.css"> <link rel="stylesheet" type="text/css" href="navigation.css"> </head> <body> <div id="container"> <div id="content"> <div id="header"> <table width="200" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td><img src="southendpiersept2006edit.jpg" width="700" height="389" alt="southend pier site logo"></td> </tr> </table> </div> <div id="navigation"> <ul> <li class="home"><a href="index.htm">Home</a></li> <li class="places"><a href="places.htm">Places to go</a></li> <li class="things"><a href="things.htm">Things to do</a></li> <li class="where"><a href="where.htm">Where to stay</a></li> <li class="getting"><a href="getting.htm">Getting&lt; here/a&gt;</a></li> <li class="about"><a href="getting.htm"></a><a href="getting.htm"></a><a href="about.htm">About the town</a></li> <li class="contact"><a href="contact.htm">Contact us</a></li> </ul> <table width="700" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td></td> </tr> </table> </div> <br> <br> <h1>Southend-On-Sea</h1> <br> <h2>Welcome to Southend-On-Sea Tourist Information Site. You're #1 stop for finding out about Southend!</h2> <br> <h3>This site aims to help you in getting here, finding accomodation, and letting you know whats going on.</h3> <p>paragraph</p> <p id="p2">paragraph2</p> </div> </div> <div id="footer"></div> </body> </html> style.css: html, body { margin: 0px; padding: 0px; text-align:center } body{ background: url(bg.jpg) repeat-x;} #content { text-align:center width:67%; } h2 { text-transform: capitalize;} navigation.css #navigation ul { width: 700px; height: 50px; position: absolute; /** Places image at the top of the page **/ top: 389px; /** Determines the height from the top of the page **/ left: 15.3%; /** Determines the width from the left of the page **/ background: url(menu.jpg) no-repeat 0 0; list-style: none; margin: 0; padding: 0; } #navigation li { display: inline; } #navigation li a:link, #navigation li a:visited { border: none; width: 100px; height: 50px; display: block; position: absolute; top: 0; text-indent: -7000px; outline: none; } #navigation li.home a:link, #navigation li.home a:visited { left: 0; } #navigation li.places a:link, #navigation li.places a:visited { left: 100px } #navigation li.things a:link, #navigation li.things a:visited { left: 200px } #navigation li.where a:link, #navigation li.where a:visited { left: 300px } #navigation li.getting a:link, #navigation li.getting a:visited { left: 400px } #navigation li.about a:link, #navigation li.about a:visited { left: 500px } #navigation li.contact a:link, #navigation li.contact a:visited { left: 600px } #navigation li.home a:hover { background: url(menu.jpg) no-repeat 0 -50px; } #navigation li.places a:hover { background: url(menu.jpg) no-repeat -100px -50px; } #navigation li.things a:hover { background: url(menu.jpg) no-repeat -200px -50px; } #navigation li.where a:hover { background: url(menu.jpg) no-repeat -300px -50px; } #navigation li.getting a:hover { background: url(menu.jpg) no-repeat -400px -50px; } #navigation li.about a:hover { background: url(menu.jpg) no-repeat -500px -50px; } #navigation li.contact a:hover { background: url(menu.jpg) no-repeat -600px -50px; }

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• getting web page data as json object?

  - by encryptor

  I have a url, the data of which page i need as a json object. I ve tried xmlhttprequest and ajaxobject both but doesnt work. It doesnt even give a responseText when I give it as an alert Ill post both the code snippets here. url = http://mydomain.com:port/a/b/c AJAX : var ajaxRequest = new ajaxObject(URL); ajaxRequest.callback = function (responseText,responseStatus) { alert(responseStatus); JSONData = responseText.parseJSON(); processData(JSONData); } USING xmlhttprequest: var client = new XMLHttpRequest(); client.open('GET',URL,true ); data = JSON.parse(client.responseText); alert(data.links.length); can someone please help me out with this. I understand cross scripting may be an issue, but how to come over it? and shouldn't then too it should give the alerts as zero or null

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• Where to put the application ID in YQL

  - by earlyriser

  I'm trying to read an xml response from YQL: $url = 'http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20geo.places%20where%20woeid%3D%22'.$woeid.'%22'; if (!$xml=simplexml_load_file($url) ) { //DO STUFF } This code works. Now i'm trying to put my application ID in the url string but I don't know how it should be done. Thanks.

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• Requirements for connecting to Oracle with JDBC?

  - by Lord Torgamus

  I'm a newbie to Java-related web development, and I can't seem to get a simple program with JDBC working. I'm using off-the-shelf Oracle 10g XE and the Eclipse EE IDE. From the books and web pages I've checked so far, I've narrowed the problem down to either an incorrectly written database URL or a missing JAR file. I'm getting the following error: java.sql.SQLException: No suitable driver found for jdbc:oracle://127.0.0.1:8080 with the following code: import java.sql.*; public class DatabaseTestOne { public static void main(String[] args) { String url = "jdbc:oracle://127.0.0.1:8080"; String username = "HR"; String password = "samplepass"; String sql = "SELECT EMPLOYEE_ID FROM EMPLOYEES WHERE LAST_NAME='King'"; Connection connection; try { connection = DriverManager.getConnection(url, username, password); Statement statement = connection.createStatement(); System.out.println(statement.execute(sql)); connection.close(); } catch (SQLException e) { System.err.println(e); } } } What is the proper format for a database URL, anyways? They're mentioned a lot but I haven't been able to find a description. Thanks! EDIT (the answer): Based on duffymo's answer, I got ojdbc14.jar from http://www.oracle.com/technology/software/tech/java/sqlj_jdbc/htdocs/jdbc_10201.html and dropped it in the Eclipse project's Referenced Libraries. Then I changed the start of the code to ... try { Class.forName("oracle.jdbc.driver.OracleDriver"); } catch (ClassNotFoundException e) { System.err.println(e); } // jdbc:oracle:thin:@<hostname>:<port>:<sid> String url = "jdbc:oracle:thin:@GalacticAC:1521:xe"; ... and it worked.

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• PHP RegExpr error Unkown modifier '('

  - by Anonymous

  I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

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• VB.NET 2.0 - StackOverflowException when using Thread Safe calls to Windows Forms Controls

  - by LamdaComplex

  I have a Windows Forms app that, unfortunately, must make calls to controls from a second thread. I've been using the thread-safe pattern described on the http://msdn.microsoft.com/en-us/library/ms171728.aspx. Which has worked great in the past. The specific problem I am having now: I have a WebBrowser control and I'm attempting to invoke the WebBrowser.Navigate() method using this Thread-Safe pattern and as a result I am getting StackOverflow exceptions. Here is the Thread-Safe Navigate method I've written. Private Delegate Sub NavigateControlCallback(ByRef wb As WebBrowser, ByVal url As String) Private Sub AsyncNavigate(ByRef wb As WebBrowser, ByVal URL As String) Try If wb.InvokeRequired Then Dim callback As New NavigateControlCallback(AddressOf AsyncNavigate) callback(wb, url) Else wb.Navigate(url) End If Catch ex As Exception End Try End Sub Is there a Thread-Safe way to interact with WinForms components without the side effect of these StackOverflowExceptions?

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• Not able to get data from Json completely

  - by Abhinav Raja

  i am getting JSON data from http://abinet.org/?json=1 and displaying the titles in a ListView. the code is working fine but the problem is, it is skipping few titles in my ListView and one title is being repeated. You can see the json data from url given above by copy paste it in JSON editor online http://www.jsoneditoronline.org/ i want titles in the "posts" array to be displayed in ListView, however it is being displayed like this: if you see the JSON data from the link above, its missing like 3 titles (they should come between the first and second title) and 5th title is being repeated. Dont know why this is happening. What minor adjustments i need to do? Please help me. this is my code : public class MainActivity extends Activity { // URL to get contacts JSON private static String url = "http://abinet.org/?json=1"; // JSON Node names private static final String TAG_POSTS = "posts"; static final String TAG_TITLE = "title"; private ProgressDialog pDialog; JSONArray contacts = null; TextView img_url; ArrayList<HashMap<String, Object>> contactList; ListView lv; LazyAdapter adapter; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); lv = (ListView) findViewById(R.id.newslist); contactList = new ArrayList<HashMap<String, Object>>(); new GetContacts().execute(); } private class GetContacts extends AsyncTask<Void, Void, Void> { protected void onPreExecute() { super.onPreExecute(); // Showing progress dialog pDialog = new ProgressDialog(MainActivity.this); pDialog.setMessage("Please wait..."); pDialog.setCancelable(false); pDialog.show(); } protected Void doInBackground(Void... arg0) { // Making a request to url and getting response JSONParser jParser = new JSONParser(); // Getting JSON from URL JSONObject jsonObj = jParser.getJSONFromUrl(url); // if (jsonStr != null) { try { // Getting JSON Array node contacts = jsonObj.getJSONArray(TAG_POSTS); // looping through All Contacts for (int i = 0; i < contacts.length(); i++) { // JSONObject c = contacts.getJSONObject(i); JSONObject posts = contacts.getJSONObject(i); String title = posts.getString(TAG_TITLE).replace("&#8217;", "'"); JSONArray attachment = posts.getJSONArray("attachments"); for (int j = 0; j< attachment.length(); j++){ JSONObject obj = attachment.getJSONObject(j); JSONObject image = obj.getJSONObject("images"); JSONObject image_small = image.getJSONObject("thumbnail"); String imgurl = image_small.getString("url"); HashMap<String, Object> contact = new HashMap<String, Object>(); contact.put("image_url", imgurl); contact.put(TAG_TITLE, title); contactList.add(contact); } } } catch (JSONException e) { e.printStackTrace(); } return null; } @Override protected void onPostExecute(Void result) { super.onPostExecute(result); // Dismiss the progress dialog if (pDialog.isShowing()) pDialog.dismiss(); adapter=new LazyAdapter(MainActivity.this, contactList); lv.setAdapter(adapter); } } } this is my JsonParser class (although its not required): public JSONParser() { } public JSONObject getJSONFromUrl(String url) { // Making HTTP request try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputStreamReader( is, "iso-8859-1"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "n"); } is.close(); json = sb.toString(); } catch (Exception e) { Log.e("Buffer Error", "Error converting result " + e.toString()); } // try parse the string to a JSON object try { jObj = new JSONObject(json); } catch (JSONException e) { Log.e("JSON Parser", "Error parsing data " + e.toString()); } // return JSON String return jObj; } } and this is adapter class: public class LazyAdapter extends BaseAdapter { private Activity activity; private ArrayList<HashMap<String, Object>> data; private static LayoutInflater inflater=null; public LazyAdapter(Activity a,ArrayList<HashMap<String, Object>> d) { activity = a; data=d; inflater = (LayoutInflater)activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE); } public int getCount() { return data.size(); } public Object getItem(int position) { return position; } public long getItemId(int position) { return position; } public View getView(int position, View convertView, ViewGroup parent) { View vi=convertView; if(convertView==null) vi = inflater.inflate(R.layout.third_row, null); TextView title = (TextView)vi.findViewById(R.id.headline3); // title SmartImageView iv = (SmartImageView) vi.findViewById(R.id.imageicon); HashMap<String, Object> song = new HashMap<String, Object>(); song = data.get(position); // Setting all values in listview title.setText((CharSequence) song.get(MainActivity.TAG_TITLE)); iv.setImageUrl((String) song.get("image_url")); thumb_image); return vi; } } Please help me. I am stuck at this for more than a week now. I think there is just something to be changed in my MainActivity class.

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• Twitter Trends API weekly.json causing error "Cannot use object of type stdClass as array"

  - by tucson

  I have the following PHP code: $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$URL); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); $result = curl_exec($ch); curl_close($ch); $obj = json_decode($result); foreach ($obj[0]->trends as $trend) echo utf8_decode($trend->name); which works fine for URL #1 (into the variable $URL): http://api.twitter.com/1/trends/1.json?exclude=hashtags but causes an error "Cannot use object of type stdClass as array" for URL #2: http://api.twitter.com/1/trends/weekly.json?exclude=hashtags I have searched for a while, but can't figure out a code to fix this and handle both URLs. Any help would be much appreciated.

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• a + sing in email address

  - by d.andreykiv

  Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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• How do i use latest Pulseaudio in 11.10?

  - by YumYumYum

  Ubuntu 11.04 i had pulseaudio from source compiled and i used it to learn, it always worked (git versions). But since i have Ubuntu 11.10, i can install it but i can not use it anymore like i do in 11.04 before. Everytime i play something its throwing this: $ speaker-test speaker-test 1.0.24.2 Playback device is default Stream parameters are 48000Hz, S16_LE, 1 channels Using 16 octaves of pink noise Rate set to 48000Hz (requested 48000Hz) Buffer size range from 192 to 2097152 Period size range from 64 to 699051 Using max buffer size 2097152 Periods = 4 ALSA lib pcm_pulse.c:746:(pulse_prepare) PulseAudio: Unable to create stream: Invalid argument Unable to set hw params for playback: Input/output error Setting of hwparams failed: Input/output error How to make pulseaudio work in 11.10 from source?

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• Remove the Parent tag in xml using php

  - by Wasim

  I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

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• how to display a image in java application

  - by Nubkadiya

  i want to display a image in my java application. i found a code to download the image from the webserver. what that code do is it takes the image and show it in the jframe. i want to use a label to show the image or soemthing else. so i can put it in my java application. can someone help me. it shouldnt be JFrame please help me here is my code Image image = null; try { URL url = new URL("http://www.personal.psu.edu/acr117/blogs/audrey/images/image-2.jpg"); image = ImageIO.read(url); } catch (IOException e) { } // Use a label to display the image JFrame frame = new JFrame(); JLabel lblimage = new JLabel(new ImageIcon(image)); frame.getContentPane().add(lblimage, BorderLayout.CENTER); frame.setSize(300, 400); frame.setVisible(true); } can someone help me

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• PHP + CURL How to get file name

  - by Gunjan

  I'm trying to download users profile picture from facebook in PHP using this function public static function downloadFile($url, $options = array()) { if (!is_array($options)) $options = array(); $options = array_merge(array( 'connectionTimeout' => 5, // seconds 'timeout' => 10, // seconds 'sslVerifyPeer' => false, 'followLocation' => true, // if true, limit recursive redirection by 'maxRedirs' => 2, // setting value for "maxRedirs" ), $options); // create a temporary file (we are assuming that we can write to the system's temporary directory) $tempFileName = tempnam(sys_get_temp_dir(), ''); $fh = fopen($tempFileName, 'w'); $curl = curl_init($url); curl_setopt($curl, CURLOPT_FILE, $fh); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, $options['connectionTimeout']); curl_setopt($curl, CURLOPT_TIMEOUT, $options['timeout']); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, $options['sslVerifyPeer']); curl_setopt($curl, CURLOPT_FOLLOWLOCATION, $options['followLocation']); curl_setopt($curl, CURLOPT_MAXREDIRS, $options['maxRedirs']); curl_exec($curl); curl_close($curl); fclose($fh); return $tempFileName; } The problem is it saves the file in the /tmp directory with a random name and without the extension. How can I get the original name of the file (I'm more interested in the original extension) The important things here are: The url actually redirects to image so i cant get it from original url the final url does not have the file name in headers

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• How to avoid or minimise use of check/conditional statement in my scenario?

  - by Muneeb Nasir

  I have scenario, where I got stream and I need to check for some value. If I got any new value I have to store it in any of data structure. It seems very easy, I can place conditional statement if-else or can use contain method of set/map to check either received is new or not. But the problem is checking will effect my application performance, in stream I will receive hundreds for value in second, if I start checking each and every value I received then for sure it effect performance. Anybody can suggest me any mechanism or algorithm to solve my issue, either by bypassing checks or at least minimize them?

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• How can I connect two users so they can share common object (game instance) with use of J2EE web tec

  - by Corvus

  My idea is that player 1 creates a game (for two players), server returns him a URL, player 1 sends this URL to player 2 and the player 2 opens URL and that connects him to the game. What is the best and the easiest way to achieve this using JSP and related technologies?

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• Applescript, how to get network address of a file

  - by CRP

  We are a network of Mac computers. I would like to send email addresses to colleagues with links to files on network locations. I made the following applescript: tell application "Finder" set uuu to URL of the first item of (get the selection) set the clipboard to uuu end tell which puts the URL of the currently selected file into the clipboard, which can then be pasted into the message (using the Add Link menu item), providing, for example: file://localhost/Volumes/Commerciale/Clienti/ unfortunately these links do not work. If I select Go To Folder from the menu item, I can get to the folder using an afp:// type url. Is there any way to get this via applescript like I do with url above? Thanks

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• twitter basic authorisation not working?

  - by Bunny Rabbit

  URL url = new URL("http://twitter.com/statuses/update.xml"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setDoOutput(true); String cridentials = new sun.misc.BASE64Encoder().encode((username + ":" + password).getBytes()); conn.setRequestProperty ("Authorization", "Basic " + cridentials); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(status); wr.flush(); wr.close(); why the above code for updating twitter status is not working ? i am running it on google app engine.

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