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• TFS How does merging work?

  - by Johannes Rudolph

  I have a release branch (RB, starting at C5) and a changeset on trunk (C10) that I now want to merge onto RB. The file has changes at C3 (common to both), one in CS 7 on RB, and one in C9 (trunk) and one in C10). So the history for my changed file looks like this: RB: C5 -> C7 Trunk: C3 -> C9 -> C10 When I merge C10 from trunk to RB, I'd expect to see a merge window showing me C10 | C3 | C7 since C3 is the common ancestor revision and C10 and C7 are the tips of my two branches respectively. However, my merge tool shows me C10 | C9 | C7. My merge tool is configured to show %1(OriginalFile)|%3(BaseFile)|%2(Modified File), so this tells me TFS chose C9 as the base revision. This is totally unexpected and completely contrary to the way I'm used to merges working in Mercurial or Git. Did I get something wrong or is TFS trying to drive me nuts with merging? Is this the default TFS Merge behavior? If so, can you provide insight into why they chose to implement it this way? I'm using TFS 2008 with VS2010 as a Client.

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• addChild, etc. using NSTreeController and NSTreeNode (snow leopard)

  - by John Velman

  I have a setup with an object (OTNodeDatum) (OT for OutlineTest) to be the represented object in NSTreeNode. NSTreeNode is the Class shown in the attributes page for NSTreeController. I have document based app, no core data. On MyDocument init, I set up content with an NSMutableArray containing one item, an NSTreeNode with a represented object which contains a single property (yes, name). Add button, Add Child button, Delete button, hooked up via interface builder to the NSTreeController add action, etc. It works up to a point. When I do an add, I get a new blank line which I can edit, but the inserted text goes away when I leave the cell. When I do a delete, things get deleted. When I do add child, nothing happens. I think I have to subclass either NSTreeNode, or NSTreeController to get the right behavior in terms of adding children and adding a new represented object in addition to adding a new tree node. IS this on the right track? If I subclass NSTreeController would I just override the add, addChild, to get the right thing to happen? And what could I mess up? I can't seem to find any guidance on this, although I've spent a long time looking. Thanks. John V

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• Applet Not Loading In Java 1.6.0_16

  - by Wayne Hartman

  I am running a Java applet compiled in 1.5 and am experiencing odd behavior when running it on computers running 1.6.0_07 and 1.6.0_16. On the *_07 version, the applet initializes and loads in the browser perfectly fine. However, computers with the *_16 are not loading at all. Even more strange, there is nothing in the Java Console to indicate any problems will loading the applet in the browser. If I run the applet from as a standalone app on said machines, it loads up just fine. The compatibility mode in the JNLP is set to 1.5+. Firefox reports no errors attempting to load the applet. Even with full tracing and logging set to all, nothing is reported in the console window. Quick facts: The JAR is signed Compiled in 1.5 Works flawlessly in browsers (FF & IE) running *_07 Does not work in browsers (FF & IE) running *_16 Works running as stand alone app in *_16 JNLP set to 1.5+ Clients are mixed *_07, *_16, and other version of 1.6 Things I have tried: Forcing the JVM to use version 1.6.0_07. This requires the user to download *_07. In my situation this is not an option, unfortunately. Ran the app on *_16 as a standalone app. This works fine, but this needs to run as an applet. Ideas?

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• commitAnimations is not resizing my UIImageView subview

  - by AaronG

  I have created a UIView as a subview and to that subview I have added a UIImageView as a subview. UIView *viewCreated; UIButton *buttonCreated; UIImageView *imageViewCreated; CGRect myFrame = CGRectMake(0, 0, 1024, 1024); viewCreated = [[UIView alloc] initWithFrame:myFrame]; [viewCreated setTag:intTag]; viewCreated.backgroundColor = [UIColor redColor]; [self.view addSubview:viewCreated]; [self randomize]; UIImage *d1Image = [UIImage imageNamed:[NSString stringWithFormat:@"image%d.png", randomNumber]]; imageViewCreated = [[UIImageView alloc] initWithFrame:CGRectMake(0.0f,0.0f,1024.0f, 1024.0f)]; [imageViewCreated setImage:[UIImage imageNamed:[NSString stringWithFormat:@"image%d.png", randomNumber]]]; [viewCreated addSubview:imageViewCreated]; //[imageViewCreated release]; return [viewCreated autorelease]; But when this code executes only the first subview is animated and resized. The UiimageView moves 200 pixels to the left but does not get resized. NSLog(@"sender tag %i",[sender tag]); UIView *currentView = [self.view viewWithTag:[sender tag]]; [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:1.5]; currentView.frame = CGRectMake(-200, 0,40, 102); [UIView commitAnimations]; I am pretty sure am I not creating the subviews correctly programmatically, because when I do it in Interface Builder it works as expected. Do I have to do something specific to actually attach the behavior of the second subview to the first subview?

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• commons-exec: hanging when I call executor.execute(commandLine);

  - by Stefan Kendall

  I have no idea why this is hanging. I'm trying to capture output from a process run through commons-exec, and I continue to hang. I've provided an example program to demonstrate this behavior below. import java.io.DataInputStream; import java.io.IOException; import java.io.PipedInputStream; import java.io.PipedOutputStream; import org.apache.commons.exec.CommandLine; import org.apache.commons.exec.DefaultExecutor; import org.apache.commons.exec.ExecuteException; import org.apache.commons.exec.PumpStreamHandler; public class test { public static void main(String[] args) { String command = "java"; PipedOutputStream output = new PipedOutputStream(); PumpStreamHandler psh = new PumpStreamHandler(output); CommandLine cl = CommandLine.parse(command); DefaultExecutor exec = new DefaultExecutor(); DataInputStream is = null; try { is = new DataInputStream(new PipedInputStream(output)); exec.setStreamHandler(psh); exec.execute(cl); } catch (ExecuteException ex) { } catch (IOException ex) { } System.out.println("huh?"); } }

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• emacs: Inferior-mode python-shell appears "lagged"

  - by Begbie00

  Hi all - I'm a Python(3.1.2)/emacs(23.2) newbie teaching myself tkinter using the pythonware tutorial found here. Relevant code is pasted below the question. Question: when I click the Hello button (which should call the say_hi function) why does the inferior python shell (i.e. the one I kicked off with C-c C-c) wait to execute the say_hi print function until I either a) click the Quit button or b) close the root widget down? When I try the same in IDLE, each click of the Hello button produces an immediate print in the IDLE python shell, even before I click Quit or close the root widget. Is there some quirk in the way emacs runs the Python shell (vs. IDLE) that causes this "lagged" behavior? I've noticed similar emacs lags vs. IDLE as I've worked through Project Euler problems, but this is the clearest example I've seen yet. FYI: I use python.el and have a relatively clean init.el... (setq python-python-command "d:/bin/python31/python") is the only line in my init.el. Thanks, Mike === Begin Code=== from tkinter import * class App: def __init__(self,master): frame = Frame(master) frame.pack() self.button = Button(frame, text="QUIT", fg="red", command=frame.quit) self.button.pack(side=LEFT) self.hi_there = Button(frame, text="Hello", command=self.say_hi) self.hi_there.pack(side=LEFT) def say_hi(self): print("hi there, everyone!") root = Tk() app = App(root) root.mainloop()

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• Browser performance when combining image resizing with animated movement

  - by Steve Reichgut

  I have been tasked with the job of converting a Flash animation into HTML. The animation is rather complex and requires the need to move multiple images (9) from location (x,y) to location (x2,y2) while simultaneously increasing the image size from 215px wide to 930px wide. While doing some initial testing of this animation with just 1-2 images, I noticed a lot of choppiness in FF handling of this animation. To try and isolate the problem, I removed the dynamic resizing of the animation and just moved it from point A to point B. What was interesting was that I saw the same behavior when simply moving a 930px image that was resized down to 215px (via the CSS width or inline width properties). When I try the same animation with a different image that is actually 215px wide, it performed smoothly. I then tried the same animation with the original 930px wide image (with no resizing) and it performed well also. This makes me wonder if the browser is having to "resize" the image down to 215px each time it is moved which is causing the choppiness. Is this a correct assumption? If so, is there any other way to optimize the animation to allow for simultaneous image resizing and image movement? Notes: 1) One optimization I have done is to position the images absolutely in order to minimize the reflow process. 2) I have tested the animation using both jQuery and the fX animation framework.

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• Problem with my Jquery loading in my Codeigniter views

  - by sico87

  Hello, I am working on a one page website that allows the users to add and remove pages from there navigation as and when they would like too, the way it works is that if the click 'Blog' on the main nav a 'Blog' section should appear on the page, if they then click 'News' the 'News' section should also be visible, however the way I have started to implement this it seems I can only have one section at a time, can my code be adpated to allow multiple sections to shown on the main page. Here is my code for the page that has the main menu and the users selections on it. <!DOCTYPE html> <head> <title>Development Site</title> <link rel="stylesheet" href="/media/css/reset.css" media="screen"/> <link rel="stylesheet" href="/media/css/generic.css" media="screen"/> <script type="text/javascript" src="/media/javascript/jquery-ui/js/jquery.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.core.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.accordion.js"></script> <script type="text/javascript"> $(document).ready(function() { $('a.menuitem').click(function() { var link = $(this), url = link.attr("href"); $("#content_pane").load(url); return false; // prevent default link-behavior }); }); </script> </head> <body> <li><a class="menuitem" href="inspiration">Inspiration</a></li> <li><a class="menuitem" href="blog">Blog</a></li> <div id="content_pane"> </div> </body> </html>

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• Android Plugin in Eclipse 3.5 on Ubuntu 64bit got problems with properties

  - by Zordid

  Hi there! I got a huge problem with the Android Development Tools ADT running in Eclipse Galileo (3.5.1) on Ubuntu 9.10, 64bit. On this platform, I do not manage to see any property edit dialogs for layout properties. E.g. the one where you can select a string resource ID for text fields, or a drawable ID for image fields or backgrounds. Whenever I click on the ... button next to the property value - nothing happens, except this button disappears. Properties with a list of possible values, e.g. "wrap_content" or "fill_parent" are displayed in a dropdown box directly in the properties field. On a different system I work in a Windows environment with Eclipse 3.4 and the same ADT: no problems whatsoever, everything works fine, the dialogs come perfectly. Does anyone know what to do here? Where's the problem? Why does Eclipse not tell me that something goes wrong? Thanks! NEW DISCOVERIES: I found out that it might not even be an Android problem, but a general Eclipse problem that I can see with all version (Ganymede, Galileo, Helios) on my Linux (Ubuntu) system. It must be a simple UI problem: the button with ... next to the values does not receive the mouse click!! I managed to see the appropriate dialogs to edit the property values by doubleclicking the button - crazy, strange, ugly behavior! But why on earth does nobody else know about this problem - I cannot find anything else on the net about it! Could it be related to this strange "GDK native window problem" on Gnome? HELP!

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• How to get Facebook Login Button To Display "Logout"

  - by Will Merydith

  I apologize ahead of time if this is clearly documented somewhere on the FB developer site - but I can't find it (so please link me if appropriate). I've implemented the FB login button on a website using GAE + Python. Here is the HTML: <fb:login-button></fb:login-button> <div id="fb-root"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: 'ad16a806fc10bef5d30881322e73be68', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { // A user has logged in, and a new cookie has been saved } else { // The user has logged out, and the cookie has been cleared } }); </script> Currently the behavior is - if I click on the "login" button, I am asked to allow the application access to FB. Which I then choose, "OK". But then the login button is still showing "login" and not "logout". How do I implement that? On the server or client side?

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• First could access the repository next cannot

  - by Banani

  Hi! I have configured svnserve (1.6.5,plain, without apache) on Fedora 12. I could ran the following svn subcommands which access the repository after configuration. Such as, commit, update,checkout, list. But, when next time ( after stopping,ctrl-c and then starting svnserve)I tried above commands, could not access the repository. This is happening both from local and remote machine. I ran svn and svnserve as below. 'svn commit svn://127.0.0.1/myrepository/' from local client. 'svnserve -d --foregorund --listen-port=3690 -r /path-to-repository/mypository/' To understand the problem better, I created another repository and found similar behavior . Frist I could access the repository and next I could not. I tried doing strace on svnserve, but don't uderstand much of it. Below is the partial output. accept(3, {sa_family=AF_INET, sin_port=htons(54425), sin_addr=inet_addr("127.0.0 .1")}, [16]) = 4 fcntl64(4, F_GETFD) = 0 fcntl64(4, F_SETFD, FD_CLOEXEC) = 0 waitpid(-1, 0xbfcdf31c, WNOHANG|WSTOPPED) = -1 ECHILD (No child processes) clone(child_stack=0, flags=CLONE_CHILD_CLEARTID|CLONE_CHILD_SETTID|SIGCHLD, chil d_tidptr=0xb7743758) = 9737 close(4) = 0 accept(3, 0xbfcdf2bc, [128]) = ? ERESTARTSYS (To be restarted) --- SIGCHLD (Child exited) @ 0 (0) --- sigreturn() = ? (mask now []) waitpid(-1, [{WIFEXITED(s) && WEXITSTATUS(s) == 0}], WNOHANG|WSTOPPED) = 9737 waitpid(-1, 0xbfcdf31c, WNOHANG|WSTOPPED) = -1 ECHILD (No child processes) My question: Why user are not able to access the repository anymore? What information the strace output gives about this problem? Any help is much appreciated. Thanks. Banani

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• substitution cypher with different alphabet length

  - by seanizer

  I would like to implement a simple substitution cypher to mask private ids in URLs I know how my IDs will look like (combination of upperchase ascii, digits and underscore), and they will be rather long, as they are composed keys. I would like to use a longer alphabet to shorten the resulting codes (I'd like to use upper and lower case ascii letters, digits and nothing else). So my incoming alphabet would be [A-Z0-9_] (37 chars) and my outgoing alphabet would be [A-Za-z0-9] (62 chars) so a compression of almost 50% would be available. let's say my URLs look like this: /my/page/GFZHFFFZFZTFZTF_24_F34 and I want them to look like this instead: /my/page/Ft32zfegZFV5 Obviously both arrays would be shuffled to bring some random order in. This does not have to be secure. if someone figures it out: fine, but I don't want the scheme to be obvious. My desired solution would be to convert the string to an integer representation of radix 37, convert the radix to 62 and use the second alphabet to write out that number. is there any sample code available that does something similar? Integer.parseInt ( http://java.sun.com/javase/6/docs/api/java/lang/Integer.html#parseInt%28java.lang.String,%20int%29 ) has some similar logic, but it is hard-coded to use standard digit behavior Any hints? I am using java to implement this but code or pseudo-code in any other language is of course also helpful

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• Why are a visual studio project's command-line settings stored per user? Is it OK to check-in (and

  - by DanO

  We're creating an application that understands some command-line parameters. There are some default's we would like to supply on the command-line when debugging, and these are easily set in the project settings as explained here. The thing is visual studio stores these settings in a *.csproj.user file, and the default settings for integrated source control do not check-in *.user files. We would like to just have these default command-line parameters in everyone's IDE when debugging this project. Often (but not always) when visual studio guides you into doing things a certain way it is for good reason. We probably don't want to just check-in someone's .csproj.user file... right? This question is has a few parts: Why does Visual Studio store this particular setting per user? Is there a way to alter this behavior? - Would doing so bring bad juju? Under these circumstances is it OK to check-in and share a .user file? Is there a better way to accomplish what we are trying to do here? Thank you -

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• String Length Evaluating Incorrectly

  - by Justin R.

  My coworker and I are debugging an issue in a WCF service he's working on where a string's length isn't being evaluated correctly. He is running this method to unit test a method in his WCF service: // Unit test method public void RemoveAppGroupTest() { string addGroup = "TestGroup"; string status = string.Empty; string message = string.Empty; appActiveDirectoryServicesClient.RemoveAppGroup("AOD", addGroup, ref status, ref message); } // Inside the WCF service [OperationBehavior(Impersonation = ImpersonationOption.Required)] public void RemoveAppGroup(string AppName, string GroupName, ref string Status, ref string Message) { string accessOnDemandDomain = "MyDomain"; RemoveAppGroupFromDomain(AppName, accessOnDemandDomain, GroupName, ref Status, ref Message); } public AppActiveDirectoryDomain(string AppName, string DomainName) { if (string.IsNullOrEmpty(AppName)) { throw new ArgumentNullException("AppName", "You must specify an application name"); } } We tried to step into the .NET source code to see what value string.IsNullOrEmpty was receiving, but the IDE printed this message when we attempted to evaluate the variable: 'Cannot obtain value of local or argument 'value' as it is not available at this instruction pointer, possibly because it has been optimized away.' (None of the projects involved have optimizations enabled). So, we decided to try explicitly setting the value of the variable inside the method itself, immediately before the length check -- but that didn't help. // Lets try this again. public AppActiveDirectoryDomain(string AppName, string DomainName) { // Explicitly set the value for testing purposes. AppName = "AOD"; if (AppName == null) { throw new ArgumentNullException("AppName", "You must specify an application name"); } if (AppName.Length == 0) { // This exception gets thrown, even though it obviously isn't a zero length string. throw new ArgumentNullException("AppName", "You must specify an application name"); } } We're really pulling our hair out on this one. Has anyone else experienced behavior like this? Any tips on debugging it?

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• WinForms programing - Modal and Non-Modal forms problem

  - by Povilas

  I have a problem with modality of the forms under C#.NET. Let's say I have main form #0 (see the image below). This form represents main application form, where user can perform various operations. However, from time to time, there is a need to open additional non-modal form to perform additional main application functionality supporting tasks. Let's say this is form #1 in the image. On this #1 form there might be opened few additional modal forms on top of each other (#2 form in the image), and at the end, there is a progress dialog showing a long operation progress and status, which might take from few minutes up to few hours. The problem is that the main form #0 is not responsive until you close all modal forms (#2 in the image). I need that the main form #0 would be operational in this situation. However, if you open a non-modal form in form #2, you can operate with both modal #2 form and newly created non modal form. I need the same behavior between the main form #0 and form #1 with all its child forms. Is it possible? Or am I doing something wrong? Maybe there is some kind of workaround, I really would not like to change all ShowDialog calls to ShowDialog...

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• Powerpoint displays a "can't start the application" error when an Excel Chart object is embedded in

  - by A9S6

  This is a very common problem when Excel Worksheet or Chart is embedded into Word or Powerpoint. I am seeing this problem in both Word and Powerpoint and the reason it seems is the COM addin attached to Excel. The COM addin is written in C# (.NET). See the attached images for error dialogs. I debugged the addin and found a very strange behavior. The OnConnection(...), OnDisConnection(...) etc methods in the COM addin works fine until I add an event handler to the code. i.e. handle the Worksheet_SheetChange, SelectionChange or any similar event available in Excel. As soon as I add even a single event handler (though my code has several), Word and Powerpoint start complaining and do not Activate the embedded object. On some of the posts on the internet, people have been asked to remove the anti-virus addins for office (none in my case) so this makes me believe that the problem is somewhat related to COM addins which are loaded when the host app activates the object. Does anyone have any idea of whats happening here?

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• Database nesting layout confusion

  - by arzon

  I'm no expert in databases and a beginner in Rails, so here goes something which kinda confuses me... Assuming I have three classes as a sample (note that no effort has been made to address any possible Rails reserved words issue in the sample). class File < ActiveRecord::Base has_many :records, :dependent => :destroy accepts_nested_attributes_for :records, :allow_destroy => true end class Record < ActiveRecord::Base belongs_to :file has_many :users, :dependent => :destroy accepts_nested_attributes_for :users, :allow_destroy => true end class User < ActiveRecord::Base belongs_to :record end Upon entering records, the database contents will appear as such. My issue is that if there are a lot of Files for the same Record, there will be duplicate record names. This will also be true if there will be multiple Records for the same user in the the Users table. I was wondering if there is a better way than this so as to have one or more files point to a single Record entry and one or more Records will point to a single User. BTW, the File names are unique. Files table: id name 1 name1 2 name2 3 name3 4 name4 Records table: id file_id record_name record_type 1 1 ForDaisy1 ... 2 2 ForDonald1 ... 3 3 ForDonald2 ... 4 4 ForDaisy1 ... Users table: id record_id username 1 1 Daisy 2 2 Donald 3 3 Donald 4 4 Daisy Is there any way to optimize the database to prevent duplication of entries, or this should really the correct and proper behavior. I spread out the database into different tables to be able to easily add new columns in the future.

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• problem when cloning jQuery UI datepicker

  - by h3

  I have a div in which there is a datepicker. I use something like this to clone it: mydiv = $('#someDiv'); // works fine so far mydiv.find('input.datefield').datepicker(); // clone without the events and insert newDiv = myDiv.clone(false).insertAfter(myDiv); // datepicker won't re-init if this class is present newDiv.find('.hadDatepicker').removeClass('hadDatepicker'); // reinitialize datepicker newDiv.find('input.datefield').datepicker(); This is a stripped down version of my code. It works and the calendar shows up as expected where it is expected .. but when a date is clicked, the previous datepicker's value gets updated.. (the one from which it was cloned). I've tried to destroy the (inexisting) instance before like this: newDiv.find('input.datefield').datepicker('destroy').datepicker(); No luck .. I've checked how it keeps track of instances and manually cleared the data like this: newDiv.find('input.datefield').data('datepicker', false).datepicker('destroy').datepicker(); Still no luck. What I don't understand is that only the date selection behavior is buggy, everything else works as expected. I really don't know what else to check now ..

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• Trap SIGPIPE when trying to write without reader

  - by Matt

  I am trying to implement a named-pipe communication solution in BASH between two processes. The first process runs a script which echo something in a named-pipe: send(){ echo 'something' > $NAMEDPIPE } And the second script is supposed to read the named-pipe via another script which contains: while true;do if read line < $NAMEDPIPE;do someCommands fi done Not that the named pipe has been previously created using the traditional command mkfifo $NAMEDPIPE My problem is that the reader script is not always running so that if the writer script try to write in the named-pipe it stay blocked until a reader connect the pipe. I want to avoid this behavior, and a solution would be to trap a SIGPIPE signal. Indeed, according to man 7 signal is supposed to be send when trying to write in a pipe with no reader. So I changed my red function by: read(){ trap 'echo "SIGPIPE received"' SIGPIPE echo 'something' > $NAMEDPIPE } But when I run the reader script, the script stay blocked, and not "SIGPIPE received" appears... Am I mistaking on the signal mechanism or is there any better solution to my problem ? Thank you for your help.

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• iPad keyboard will not dismiss if navigation controller presentation style is "form sheet".

  - by Kalle

  UPDATE: This is apparently "works as intended" classed by Apple. See accepted answer below for details. Update: this question is about a behavior discovered in the iPad keyboard, where it refuses to be dismissed if shown in a modal dialog with a navigation controller. Basically, if I present the navigation controller with the following line: navigationController.modalPresentationStyle = UIModalPresentationFormSheet; The keyboard refuses to be dismissed. If I comment out this line, the keyboard goes away fine. ... I've got two textFields, username and password; username has a Next button and password has a Done button. The keyboard won't go away if I present this in a modal navigation controller. WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; [self.view addSubview:b.view]; DOES NOT WORK broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; navigationController.modalPresentationStyle = UIModalPresentationFormSheet; navigationController.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release]; If I remove the navigation controller part and present 'b' as a modal view controller by itself, it works. Is the navigation controller the problem? WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; b.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:b animated:YES]; [b release]; WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release];

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• How to make NSView not clip its bounding area?

  - by Jeremy L

  I created an empty Cocoa app on Xcode for OS X, and added: - (void)applicationDidFinishLaunching:(NSNotification *)aNotification { self.view = [[NSView alloc] initWithFrame:NSMakeRect(100, 100, 200, 200)]; self.view.wantsLayer = YES; self.view.layer = [CALayer layer]; self.view.layer.backgroundColor = [[NSColor yellowColor] CGColor]; self.view.layer.anchorPoint = CGPointMake(0.5, 0.5); self.view.layer.transform = CATransform3DMakeRotation(30 * M_PI / 180, 1, 1, 1); [self.window.contentView addSubview:self.view]; } But the rotated layer's background is clipped by the view's bounding area: I thought since some version of OS X and iOS, the view won't clip the content of its subviews and will show everything inside and outside? On iOS, I do see that behavior, but I wonder why it shows up like that and how to make everything show? (I am already using the most current Xcode 4.4.1 on Mountain Lion). (note: if you try the code above, you will need to link to Quartz Core, and possibly import the quartz core header, although I wonder why I didn't import the header and it still compiles perfectly)

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• Problem pushing multiple view controllers onto navigation controller stack

  - by Jim

  Hi, I am trying to push three view controllers onto the navigation controller. [self.navigationController pushViewController:one animated:YES]; [self.navigationController pushViewController:two animated:YES]; [self.navigationController pushViewController:three animated:YES]; The desired behavior is that view three will show, and when the back button is pressed it will go to view two and then to view one... What actually happens is that view one is visible and pressing back goes to view two and then back again it goes to view one. Which is to say that view one is shown instead of view three. Very strangely, looking at the viewController array of the navigationController after the calls above show the right entries, and looking at the visibleViewController property shows that it has view three in it... even though view one is visible. If i navigate to a sub view from the visible view one (that shows in the place of view three) and press back from that sub view... it goes to view three. It looks like it is showing view one, but knows it is on view three... I am completely confused... any ideas? Jim

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• NetBeans parameter fill after code completion

  - by byte

  This is a particularly annoying problem I'm having, and I can't be the only one to have issue with it. In NetBeans, when you type part of a method, then hit CTRL-SPACE, it displays the code-completion popup, whereupon you can hit tab to finish out the word. This is great, and pretty much how all IDE's operate. Example: Thread.sl < CTRL-SPACE Thread.sleep Yay! Problem is that in this context, once you type in a paren, it auto-fills the parameters for the method with their default names, and inserts a closing paren (regardless of whether you have disabled the option to automatically close them on the preferences page for code completion). This behavior is NOT present if you had manually typed out the full name. How is this helpful to anyone? You've got to type over it your actual variable that you will be passing, and NetBeans gives you no option to prevent the closing paren on code-completion. Does anyone have a way to solve this issue, without having to dive into the netbeans source and build it just for this minor of an issue?

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• Using PLINQ to calculate and update values within the enclosure does not work

  - by Keith

  I recently needed to do a running total on a report. Where for each group, I order the rows and then calculate the running total based on the previous rows within the group. Aha! I thought, a perfect use case for PLINQ! However, when I wrote up the code, I got some strange behavior. The values I was modifying showed as being modified when stepping through the debugger, but when they were accessed they were always zero. Sample Code: class Item { public int PortfolioID; public int TAAccountID; public DateTime TradeDate; public decimal Shares; public decimal RunningTotal; } List<Item> itemList = new List<Item> { new Item { PortfolioID = 1, TAAccountID = 1, TradeDate = new DateTime(2010, 5, 1), Shares = 5.335m, }, new Item { PortfolioID = 1, TAAccountID = 1, TradeDate = new DateTime(2010, 5, 2), Shares = -2.335m, }, new Item { PortfolioID = 2, TAAccountID = 1, TradeDate = new DateTime(2010, 5, 1), Shares = 7.335m, }, new Item { PortfolioID = 2, TAAccountID = 1, TradeDate = new DateTime(2010, 5, 2), Shares = -3.335m, }, }; var found = (from i in itemList where i.TAAccountID == 1 select new Item { TAAccountID = i.TAAccountID, PortfolioID = i.PortfolioID, Shares = i.Shares, TradeDate = i.TradeDate, RunningTotal = 0 }); found.AsParallel().ForAll(x => { var prevItems = found.Where(i => i.PortfolioID == x.PortfolioID && i.TAAccountID == x.TAAccountID && i.TradeDate <= x.TradeDate); x.RunningTotal = prevItems.Sum(s => s.Shares); }); foreach (Item i in found) { Console.WriteLine("Running total: {0}", i.RunningTotal); } Console.ReadLine(); If I change the select for found to be .ToArray(), then it works fine and I get calculated reuslts. Any ideas what I am doing wrong?

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• Calling a subclass method from a superclass

  - by Shaun

  Preface: This is in the context of a Rails application. The question, however, is specific to Ruby. Let's say I have a Media object. class Media < ActiveRecord::Base end I've extended it in a few subclasses: class Image < Media def show # logic end end class Video < Media def show # logic end end From within the Media class, I want to call the implementation of show from the proper subclass. So, from Media, if self is a Video, then it would call Video's show method. If self is instead an Image, it would call Image's show method. Coming from a Java background, the first thing that popped into my head was 'create an abstract method in the superclass'. However, I've read in several places (including Stack Overflow) that abstract methods aren't the best way to deal with this in Ruby. With that in mind, I started researching typecasting and discovered that this is also a relic of Java thinking that I need to banish from my mind when dealing with Ruby. Defeated, I started coding something that looked like this: def superclass_method # logic this_media = self.type.constantize.find(self.id) this_media.show end I've been coding in Ruby/Rails for a while now, but since this was my first time trying out this behavior and existing resources didn't answer my question directly, I wanted to get feedback from more-seasoned developers on how to accomplish my task. So, how can I call a subclass's implementation of a method from the superclass in Rails? Is there a better way than what I ended up (almost) implementing?

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