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  • Standard Android Button with a different color

    - by Mike
    I'd like to change the color of a standard Android button slightly in order to better match a client's branding. For example, see the "Find a Table" button for the OpenTable application: The best way I've found to do this so far is to change the Button's drawable to the following drawable located in res/drawable/red_button.xml: <?xml version="1.0" encoding="utf-8"?> <selector xmlns:android="http://schemas.android.com/apk/res/android"> <item android:state_pressed="true" android:drawable="@drawable/red_button_pressed" /> <item android:state_focused="true" android:drawable="@drawable/red_button_focus" /> <item android:drawable="@drawable/red_button_rest" /> </selector> But doing that requires that I actually create three different drawables for each button I want to customize (one for the button at rest, one when focused, and one when pressed). That seems more complicated and non-DRY than I need. All I really want to do is apply some sort of color transform to the button. Is there an easier way to go about changing a button's color than I'm doing?

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  • Cross-Platform Language + GUI Toolkit for Prototyping Multimedia Applications

    - by msutherl
    I'm looking for a language + GUI toolkit for rapidly prototyping utility applications for multimedia installations. I've been working with Max/MSP/Jitter for many years, but I'd like to add a text-based language to my 'arsenal' for tasks apart from 'content production'. (When it comes to actual media synthesis, my choices are clear [SuperCollider + MSP for audio, Jitter + Quartz + openFrameworks for video]). I'm looking for something that maintains some of the advantages of Max, but is lower-level, faster, more cross-platfrom (Linux support), and text-based. Integration with powerful sound/video libraries is not a requirement. Some requirements: Cross-platform (at least OSX and Linux, Windows is a plus) Fast and easy cross-platform GUIs with no platform-specific modification GUI code separated from backend code as much as possible Good for interfacing with external serial devices (micro-controllers) Good network support (UDP/TCP) Good libraries for multi-media (video, sound, OSC) are a plus Asynchronous synchronous UNIX integration is a plus The options that come to mind: AS3/Flex (not a fan of AS3 or the idea of running in the Flash Player) openFrameworks (C++ framework, perhaps a bit too low level [looking for fast development time] and biased toward video work) Java w/ Processing libraries (like openFrameworks, just slower) Python + Qt (is Qt appropriate for rapid prototyping?) Python + Another GUI toolkit SuperCollider + Swing (yucky GUI development) Java w/ SWT Any other options? What do you recommend?

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  • No resource type specified (at 'id' with value '@+id\st')

    - by Refaat
    I'm new at android programming, I'm now trying to make some buttons, I configured these buttons using the following code: The MainActivity class : public class MainActivity extends Activity { /** Called when the activity is first created. */ Button st,nd,center; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); st = (Button)findViewById(R.id.st); st = (Button)findViewById(R.id.center); st = (Button)findViewById(R.id.nd); } } and the XML Layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background" > <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello from animation!!" /> <button android:layout_width="100dp" android:layout_height="50dp" android:text="1st half" android:id="@+id\st" /> // and the other two points defined the same way </LinearLayout> And i got that syntax error: error: Error: No resource type specified (at 'id' with value '@+id\st'). // and the same error with the other two buttons HINT: The R class is imported and accessible from the MainActivity class but it can't read R.id.

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  • Removing related elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same "Id" values as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements (i.e. those that have the same "Id" values). The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • CallbackValidator called with empty string

    - by Paolo Tedesco
    I am writing a custom configuration section, and I would like to validate a configuration property with a callback, like in this example: using System; using System.Configuration; class CustomSection : ConfigurationSection { [ConfigurationProperty("stringValue", IsRequired = false)] [CallbackValidator(Type = typeof(CustomSection), CallbackMethodName = "ValidateString")] public string StringValue { get { return (string)this["stringValue"]; } set { this["stringValue"] = value; } } public static void ValidateString(object value) { if (string.IsNullOrEmpty((string)value)) { throw new ArgumentException("string must not be empty."); } } } class Program { static void Main(string[] args) { CustomSection cfg = (CustomSection)ConfigurationManager.GetSection("customSection"); Console.WriteLine(cfg.StringValue); } } And my App.config file looks like this: <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <section name="customSection" type="CustomSection, config-section"/> </configSections> <customSection stringValue="lorem ipsum"/> </configuration> My problem is that when the ValidateString function is called, the value parameter is always an empty string, and therefore the validation fails. If i just remove the validator, the string value is correctly initialized to the value in the configuration file. What am I missing?

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  • not able to register sip user on red5server, using red5phone

    - by sunil221
    I start the red5, and then i start red5phone i try to register sip user , details i provide are username = 999999 password = **** ip = asteriskserverip and i got --- Registering contact -- sip:[email protected]:5072 the right contact could be --- sip :99999@asteriskserverip this is the log: SipUserAgent - listen -> Init... Red5SIP register [SIPUser] register RegisterAgent: Registering contact <sip:[email protected]:5072> (it expires in 3600 secs) RegisterAgent: Registration failure: No response from server. [SIPUser] SIP Registration failure Timeout RegisterAgent: Failed Registration stop try. Red5SIP Client leaving app 1 Red5SIP Client closing client 35C1B495-E084-1651-0C40-559437CAC7E1 Release ports: sip port 5072 audio port 3002 Release port number:5072 Release port number:3002 [SIPUser] close1 [SIPUser] hangup [SIPUser] closeStreams RTMPUser stopStream [SIPUser] unregister RegisterAgent: Unregistering contact <sip:[email protected]:5072> SipUserAgent - hangup -> Init... SipUserAgent - closeMediaApplication -> Init... [SIPUser] provider.halt RegisterAgent: Registration failure: No response from server. [SIPUser] SIP Registration failure Timeout please let me know if i am doing anything wrong. regards Sunil

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  • java.lang.ExceptionInInitializerError Exception when creating Application Context in Spring

    - by cyotee
    I am practicing with Spring, and am getting a java.lang.ExceptionInInitializerError exception when I try to instantiate the context. The Exception appears below, with my code following it. I have simplified my experiment from before. The Exception Oct 17, 2012 5:54:22 PM org.springframework.context.support.AbstractApplicationContext prepareRefresh INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@570c16b7: startup date [Wed Oct 17 17:54:22 CDT 2012]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:195) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:128) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:535) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:449) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at helloworld.HelloWorldTest.main(HelloWorldTest.java:13) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:105) ... 7 more My configuration XML <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:c="http://www.springframework.org/schema/c" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <bean id="messageContainer" class="helloworld.MessageContainer"> <property name="message" value="Hello World"> </property> </bean> <bean id="messageOutputService" class="helloworld.MessageOutputService"> </bean> My test class. package helloworld; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class HelloWorldTest { /** * @param args */ public static void main(String[] args) { ApplicationContext context = new ClassPathXmlApplicationContext("HelloWorldTest-context.xml"); MessageContainer message = context.getBean(MessageContainer.class); MessageOutputService service = context.getBean(MessageOutputService.class); service.outputMessageToConsole(message); } }

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  • MXML composite container initialization error

    - by mkorpela
    I'm getting an odd error from my composite canvas component: An ActionScript error has occurred: Error: null at mx.core::Container/initialize()[C:\autobuild\galaga\frameworks\projects\framework\src\mx\core\Container.as:2560] at -REMOVED THIS FOR STACK OVERFLOW-.view::EditableCanvas/initialize()[.../view/EditableCanvas .... It seems to be related to the fact that my composite component has a child and I'm trying to add one in the place I'm using the component. So how can I do this correctly? Component code looks like this (EditableCanvas.mxml): <?xml version="1.0" encoding="utf-8"?> <mx:Canvas xmlns:mx="http://www.adobe.com/2006/mxml"> <mx:Script> <mx:Image id="editTextImage" source="@Embed('/../assets/icons/small/edit.png')"/> </mx:Canvas> The code that is using the code looks like this: <view:EditableCanvas width="290" height="120" backgroundColor="#FFFFFF" horizontalScrollPolicy="off" borderStyle="solid" cornerRadius="3"> <mx:Text id="textContentBox" width="270" fontFamily="nautics" fontSize="12" text="{_text}"/> </view:EditableCanvas>

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  • Rails - CSV export: prompt for file download

    - by Pierre
    Hello, I want to give my users the ability to export a table to CSV. So in my controller, I've added on top of the file: respond_to :html, :js, :csv I'm also setting the headers if the requested format is csv: if params[:format] == 'csv' generate_csv_headers("negotiations-#{Time.now.strftime("%Y%m%d")}") end Code for generate_csv_headers(in application_controller) is: def generate_csv_headers(filename) headers.merge!({ 'Cache-Control' => 'must-revalidate, post-check=0, pre-check=0', 'Content-Type' => 'text/csv', 'Content-Disposition' => "attachment; filename=\"#{filename}\"", 'Content-Transfer-Encoding' => 'binary' }) end I've also created a view named index.csv.erb to generate my file: <%- headers = ["Id", "Name"] -%> <%= CSV.generate_line headers %> <%- @negotiations.each do |n| -%> <%- row = [ n.id, n.name ] -%> <%= CSV.generate_line row %> <%- end -%> I don't have any error, but it simply displays the content of the CSV file, while I'd expect a prompt from the browser to download the file. I've read a lot, but could not find anything that'd work. Do you have an idea? thanks, p.

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  • Create x509 certificate with openssl/makecert tool

    - by Zé Carlos
    I'm creating a x509 certificate using makecert with the following parameters: makecert -r -pe -n "CN=Client" -ss MyApp I want to use this certificate to encrypt and decrypt data with RSA algoritm. I look to generated certificate in windows certificate store and everything seems ok (It has a private key, public key is a RSA key with 1024 bits and so on..) Now i use this C# code to encrypt data: X509Store store = new X509Store("MyApp", StoreLocation.CurrentUser); store.Open(OpenFlags.ReadOnly); X509Certificate2Collection certs = store.Certificates.Find(X509FindType.FindBySubjectName, "Client", false); X509Certificate2 _x509 = certs[0]; using (RSACryptoServiceProvider rsa = (RSACryptoServiceProvider)_x509.PrivateKey) { byte[] dataToEncrypt = Encoding.UTF8.GetBytes("hello"); _encryptedData = rsa.Encrypt(dataToEncrypt, true); } When executing the Encrypt method, i receive a CryptographicException with message "Bad key". I think the code is fine. Probably i'm not creating the certificate properly. Any comments? Thanks ---------------- EDIT -------------- If anyone know how to create the certificate using OpenSsl, its also a valid answer for me.

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  • smartGWT: retrieve data from server to populate a listGrid

    - by Gabriele
    I'm searching a way to populate a ListGrid with an XML response from a server. This is an example of my server response: <?xml version="1.0" encoding="UTF-8"?> <tbody id="tbody"> <tr> <word>The</word> <frequence>12</frequence> </tr> <tr> <word>best</word> <frequence>3</frequence> </tr> ... And this is how I can populate the ListGrid using a file (item.xml) where I have saved the xml result: public class Frequenze extends DataSource { private static Frequenze instance = null; public static Frequenze getInstance() { if (instance == null) { instance = new Frequenze("frequence"); } return instance; } public Frequenze(String id) { setID(id); setRecordXPath("//tr"); DataSourceTextField wordField = new DataSourceTextField("word", "Word"); wordField.setRequired(true); DataSourceIntegerField frequenceField = new DataSourceIntegerField("frequence", "Frequence"); frequenceField.setRequired(true); setFields(wordField, frequenceField); setDataURL("ds/item.xml"); setClientOnly(true); } } Now I want not to use the file, but I'm searching a way to retrieve the data directly from the server. Anyone know how I get this?

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  • hint and textview with right gravity and a singleline

    - by codeScriber
    I've opened a bug but i was wondering if anyone encountered this issue and knows a workaround. If you define a text view with a hint inside it, give it right gravity (android:gravity="right") then if you define android:singleLine=true or android:maxLines="1" or android:scrollHorizonatally="true" you don't see the hint. removing the right gravity returns the hint to the left side, removing all the tree params i mentioned above puts the hint on the right side. i want my hint on the right, but i need a single horizontal line... here's the sample layout that doesn't show the hint: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content" android:padding="5dp"> <EditText android:layout_width="fill_parent" android:layout_gravity="center_vertical|right" android:layout_height="wrap_content" android:layout_margin="6dp" android:textSize="16sp" android:paddingRight="5dp" android:id="@+id/c" android:gravity="right" android:hint="hello!!!" android:scrollHorizontally="true" android:maxLines="1" android:singleLine="true"/> </LinearLayout> i checked on 1.6 and 2.1 emulators and it reproduces 100%, i'm prettysure it's a bug, i don't see the connection between single line and the hint.... what's more the hint got it's own layout in the TextView (mLayout and mHintLayout both exists, in onDraw if the text length is 0 mHintLayout if mHint is not null is used).

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  • parse xml with elementtree, custom sorting

    - by microspace
    I want to parse xml file in utf-8 and sort it by some field. Soring is made by custom alphabet (s1 from sourcecode). History of question is here: sorting of list containing utf-8 charachters. I've found how to sort xml here. Sorting work correctly, the problem is with elementtree, I must admit that it doesn't work on python3 Here is source code: #!/usr/bin/env python # -*- coding: utf-8 -*- #import xml.etree.ElementTree as ET # Python 2.5 import elementtree.ElementTree as ET s1='aáàAâÂbBcCçÇdDeéEfFgGgGhHiIîÎíiiIjJkKlLmMnNóoOöÖpPqQrRsSsStTuUûúÛüÜvVwWxXyYzZ' s2='11111122334455666aabbccddeeeeeeffgghhiijjkklllllmmnnooppqqrrsssssttuuvvwwxxyy' trans = str.maketrans(s1, s2) def unikey(seq): return seq[0].translate(trans) tree = ET.parse("tosort.xml") container = tree.find("entries") data = [] for elem in container: keyd = elem.findtext("k") data.append((keyd, elem)) print (data) data.sort(key=unikey) print (data) container[:] = [item[-1] for item in data] tree.write("sorted.xml", encoding="utf-8") Here are instructions to import elementtree module. When I import module this way :import xml.etree.ElementTree as ET, I get a message: Traceback (most recent call last): File "pcs.py", line 19, in <module> container[:] = [item[-1] for item in data] File "/usr/lib/python3.1/xml/etree/ElementTree.py", line 210, in __setitem__ assert iselement(element) AssertionError When I use this method to import: import elementtree.ElementTree as ET, I get this message: Traceback (most recent call last): File "pcs.py", line 4, in <module> import elementtree.ElementTree as ET File "/usr/local/lib/python3.1/dist-packages/elementtree/ElementTree.py", line 794, in <module> _escape = re.compile(eval(r'u"[&<>\"\u0080-\uffff]+"')) File "<string>", line 1 u"[&<>\"\u0080-\uffff]+" ^ SyntaxError: invalid syntax I use Python 3.1.3 (r313:86834, Nov 28 2010, 11:28:10). In python2.6 elementtree work without a problem. Content of tosort.xml: <xdxf> <entries> <ar><k>zaaaa</k>definition1</ar> <ar><k>saaaa</k>definition2</ar> ... ... </entries> </xdxf>

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  • Read XML with PHP

    - by sea_1987
    I am trying to check a field in some XML that is returned from an outside. The XML is returned in a variable call $out and when you view the source of the page you get a XML output of the following, <?xml version="1.0" encoding="UTF-8"?> <ResponseBlock Live="FALSE" Version="3.51"> <Response Type="AUTH"> <OperationResponse> <TransactionReference>23-9-1334895</TransactionReference> <TransactionCompletedTimestamp>2010-04-30 15:59:05</TransactionCompletedTimestamp> <AuthCode>AUTH CODE:TEST</AuthCode> <TransactionVerifier>AlaUOS1MOnN/iwc5s2WPDm5ggrCLwesUnHs9h+W0N3CRaln2W6lh+6dtaRFFhLdwfnw6y7lRemyJUYl9a3dpWfzORE6DaZkFMb+dIb0Ne1UxjFEJkrEtjzx/i8KSayrIBrT/yGZOoOT42EZ9loc+UkdGk/pqYvj8bZztvgBNo2Ak=</TransactionVerifier> <Result>1</Result> <SettleStatus>0</SettleStatus> <SecurityResponseSecurityCode>1</SecurityResponseSecurityCode> <SecurityResponsePostCode>1</SecurityResponsePostCode> <SecurityResponseAddress>1</SecurityResponseAddress> </OperationResponse> <Order> <OrderInformation>This is a test order</OrderInformation> <OrderReference>Order0001</OrderReference> </Order> </Response> </ResponseBlock> I want check what value is in the 'Result' field. I am unsure how to access the information using PHP, so far I have, $xml = simplexml_load_string($out); Many Thanks

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  • Coldbox Security Interceptor

    - by faheem
    Hi I am new to coldbox and working on a guestbook messaging forum. does anyone know how I can apply some rule in coldbox to show edit and delete for specified users of admin or user in the edit page. I am not sure how to specify this as I already have my rules here as shown in securityRules.xml: SecurityRules.XML <?xml version="1.0" encoding="UTF-8"?> <!-- Declare as many rule elements as you want, order is important Remember that the securelist can contain a list of regular expression if you want ex: All events in the user handler user\..* ex: All events .* ex: All events that start with admin ^admin If you are not using regular expression, just write the text that can be found in an event. <whitelist>ehSecurity\.dspLogin,ehSecurity\.doLogin,ehSecurity\.dspLogoff</whitelist> --> <rules> <rule> <whitelist>^entries,ehSecurity\..*,registry\..*</whitelist> <securelist></securelist> <roles>admin</roles> <permissions>read,write</permissions> <redirect>ehSecurity.dspLogin</redirect> </rule> <rule> <whitelist>^entries,ehSecurity\..*,main\..*,^registry</whitelist> <securelist></securelist> <roles>author,admin</roles> <permissions>read</permissions> <redirect>ehSecurity.dspLogin</redirect> </rule> </rules>

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  • I need a true mouseOver...

    - by invertedSpear
    Ok, so mouseOver and RollOver, and their respective outs work great as long as your mouse is actually over the item, or one of it's children. My problem is that I may have another UI component "between" my mouse and the item I want to process the mouse/rollover(maybe a button that is on top of a canvas, but is not a child of the canvas). The mouse is still over the component, there's just something else that it's over at the same time. Any tips or help how to deal with this? Let me know if I'm not being clear enough. Here is a simplified code example detailing my question copy/paste that into your flex/flash builder and you'll see what I mean: <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" width="500" height="226" creationComplete="ccInit()"> <mx:Script> <![CDATA[ private function ccInit():void{ myCanv.addEventListener(MouseEvent.ROLL_OVER,handleRollOver); } private function handleRollOver(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",1); myCanv.addEventListener(MouseEvent.ROLL_OUT,handleRollOut); } private function handleRollOut(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",0); myCanv.removeEventListener(MouseEvent.ROLL_OUT,handleRollOut); } ]]> </mx:Script> <mx:Canvas id="myCanv" x="10" y="10" width="480" height="200" borderStyle="solid" borderColor="#000000" backgroundColor="#FFFFFF" backgroundAlpha="0"> </mx:Canvas> <mx:Button x="90" y="50" label="Button" width="327" height="100"/> </mx:Application>

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  • Reading text files line by line, with exact offset/position reporting

    - by Benjamin Podszun
    Hi. My simple requirement: Reading a huge ( a million) line test file (For this example assume it's a CSV of some sorts) and keeping a reference to the beginning of that line for faster lookup in the future (read a line, starting at X). I tried the naive and easy way first, using a StreamWriter and accessing the underlying BaseStream.Position. Unfortunately that doesn't work as I intended: Given a file containing the following Foo Bar Baz Bla Fasel and this very simple code using (var sr = new StreamReader(@"C:\Temp\LineTest.txt")) { string line; long pos = sr.BaseStream.Position; while ((line = sr.ReadLine()) != null) { Console.Write("{0:d3} ", pos); Console.WriteLine(line); pos = sr.BaseStream.Position; } } the output is: 000 Foo 025 Bar 025 Baz 025 Bla 025 Fasel I can imagine that the stream is trying to be helpful/efficient and probably reads in (big) chunks whenever new data is necessary. For me this is bad.. The question, finally: Any way to get the (byte, char) offset while reading a file line by line without using a basic Stream and messing with \r \n \r\n and string encoding etc. manually? Not a big deal, really, I just don't like to build things that might exist already..

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  • Data of the web services in a RSS

    - by vymz
    I only have the .wsdl and I want to put the data that the web services return in the RSS. And in a web page of SAP, I can only upload RSS, so I need put the information of the web services in the RSS For example, I put the information manually(name and total value) in the fields <title> and <descripcion>, these data are extracted from the web services. But sometimes I don´t know how much information brings the web service. Also, I know that RSS is not to store information such as web services. <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0"> <channel> <title>Test RSS</title> <link>http://solutions.com</link> <description>RSS</description> <item> <title>Luiz</title> <link>http://www.solutions.com/prueba1</link> <description>10</description> </item> <item> <title>Clodoaldo</title> <link>http://www.solutions.com/prueba2</link> <description>5</description> </item>

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  • I find a problem with sending receiving parameter

    - by kawtousse
    how to get the xml translation to html dropdownlist with ajax. I send the parameter with GET method but the JSP FILE THAT GENERATES THE XML DONT RECEIVE IT. var url="responsexml.jsp"; url=url+"?projectCode="+prj.options[prj.selectedIndex].value; xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); and then in responsexml.jsp I do like that: <% String projectcode= (String)request.getParameter("projectCode"); System.out.println("++++projectCode:=" +projectcode); Session s = null; Transaction tx; try { s = HibernateUtil.currentSession(); tx = s.beginTransaction(); Query query = s.createQuery("SELECT from Wa wa where wa.ProjectCode='"+projectcode+"'"); response.setContentType("text/xml"); PrintWriter output = response.getWriter(); output.write( "<?xml version=\"1.0\" encoding=\"utf-8\"?>"); //response.setHeader("Cache-Control", "no-cache"); //constriure le xml if(projectcode!=null) { for(Iterator it=query.iterate();it.hasNext();) { if(it.hasNext()) { Wa object=(Wa)it.next(); //out.print( "<item id=\"" +object.getIdWA() + "\" name=\"" + object.getWAName() + "\" />"); output.write("<wa>"); output.write( "<item id=\"" + object.getIdWA() + "\" name=\"" + object.getWAName() + "\" />"); output.write("</wa>"); } } } } catch (HibernateException e) { e.printStackTrace(); } %> </body> </html> With this code I dont have my xml file. I got this error: The server did not understand the request, or the request was invalid. Erreur de traitement de la ressource http://www.w3.o... PLEASE HELP.

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  • How do I use XML Builder to create xml in rails?

    - by Angela
    I am trying the following, but the output XML is badly formed: def submit xml = Builder::XmlMarkup.new xml.instruct! xml.mail xml.documents xml.document xml.template xml.source "gallery" xml.name "Postcard: Image fill front" @xml_display = xml end I need it to look more like this: <?xml version="1.0" encoding="UTF-8"?> <mail> <documents> <document> <template> <source>gallery</source> <name>Postcard: Image fill front</name> </template> <sections> <section> <name>Text</name> <text>Hello, World!</text> </section> <section> <name>Image</name> <attachment>...attachment id...</attachment> </section> </sections> </document> </documents> <addressees> <addressee> <name>John Doe</name> <address>123 Main St</address> <city>Anytown</city> <state>AZ</state> <postal-code>10000</postal-code> </addressee> </addressees> </mail>

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  • Is it necessary to "escape" character "<" and ">" for javascript string?

    - by Morgan Cheng
    Sometimes, server side will generate strings to be embedded in inline JavaScript code. For example, if "UserName" should be generated by ASP.NET. Then it looks like. <script> var username = "<%UserName%>"; </script> This is not safe, because a user can have his/her name to be </script><script>alert('bug')</script></script> It is XSS vulnerability. So, basically, the code should be: <script> var username = "<% JavascriptEncode(UserName)%>"; </script> What JavascriptEncode does is to add charater "\" before "/" and "'" and """. So, the output html is like. var username = "<\/scriptalert(\'bug\')<\/script<\/script"; Browser will not interpret "<\/script" as end of script block. So, XSS in avoided. However, there are still "<" and "" there. It is suggested to escape these two characters as well. First of all, I don't believe it is a good idea to change "<" to "&lt;" and "" to "&gt;" here. And, I'm not sure changing "<" to "\<" and "" to "\" is recognizable to all browsers. It seems it is not necessary to do further encoding for "<" and "". Is there any suggestion on this? Thanks.

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  • cookies handling on webrequest and response

    - by manish patel
    I have created a application that has a function mainpost. It is created to post data on a https sites. Here I want to handle cookies in this function. How can I do this task? public string Mainpost(string website, string content) { // this is what we are sending string post_data = content; // this is where we will send it string uri = website; // create a request HttpWebRequest request = (HttpWebRequest) WebRequest.Create(uri); request.KeepAlive = false; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; // turn our request string into a byte stream byte[] postBytes = Encoding.ASCII.GetBytes(post_data); // this is important - make sure you specify type this way request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); // now send it requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); // grab te response and print it out to the console along with the status // code HttpWebResponse response = (HttpWebResponse)request.GetResponse(); string str = (new StreamReader(response.GetResponseStream()).ReadToEnd()); Console.WriteLine(response.StatusCode); return str; }

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  • Deploy GWT Application to Google App Engine using NetBeans

    - by Yan Cheng CHEOK
    Hello, I try to deploy a GWT application, to Google App Engine using NetBeans. I had successful run GWT sample http://code.google.com/webtoolkit/doc/latest/tutorial/create.html using Personal GlassFish v3 Prelude Domain, by 1) Copy generated source code from StockWatcher to C:\Projects\StockWatcherNetbeans\src\java\com\google\ 2) Modify C:\Projects\StockWatcherNetbeans\nbproject\gwt.properties gwt.module=com.google.gwt.stockwatcher.StockWatcher 3) Select Personal GlassFish v3 Prelude Domain, and run. All works fine! Now, I try to select Google App Engine server, and run. However, I get the error "There is no appengine web project opened!" I check... There is file called C:\Projects\StockWatcherNetbeans\war\WEB-INF\appengine-web.xml with content <?xml version="1.0" encoding="UTF-8"?> <appengine-web-app xmlns="http://appengine.google.com/ns/1.0" xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://kenai.com/projects/nbappengine/downloads/download/schema/appengine-web.xsd appengine-web.xsd'> <application>StockWatcherNetbeans</application> <version>1</version> </appengine-web-app> I am using NetBeans 6.7.1 GWT4NB (GWT Plugin for NetBeans) 2.6.12 Google App Engine plugin for NetBeans from http://kenai.com/downloads/nbappengine/1.0_NetBeans671/updates.xml Anything I had missed out? Even when I right click to the project, the Deploy to Google App Engine options is disabled. And yes, please do not ask me why not use Eclipse.

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  • Malware - Technical anlaysis

    - by nullptr
    Note: Please do not mod down or close. Im not a stupid PC user asking to fix my pc problem. I am intrigued and am having a deep technical look at whats going on. I have come across a Windows XP machine that is sending unwanted p2p traffic. I have done a 'netstat -b' command and explorer.exe is sending out the traffic. When I kill this process the traffic stops and obviously Windows Explorer dies. Here is the header of the stream from the Wireshark dump (x.x.x.x) is the machines IP. GNUTELLA CONNECT/0.6 Listen-IP: x.x.x.x:8059 Remote-IP: 76.164.224.103 User-Agent: LimeWire/5.3.6 X-Requeries: false X-Ultrapeer: True X-Degree: 32 X-Query-Routing: 0.1 X-Ultrapeer-Query-Routing: 0.1 X-Max-TTL: 3 X-Dynamic-Querying: 0.1 X-Locale-Pref: en GGEP: 0.5 Bye-Packet: 0.1 GNUTELLA/0.6 200 OK Pong-Caching: 0.1 X-Ultrapeer-Needed: false Accept-Encoding: deflate X-Requeries: false X-Locale-Pref: en X-Guess: 0.1 X-Max-TTL: 3 Vendor-Message: 0.2 X-Ultrapeer-Query-Routing: 0.1 X-Query-Routing: 0.1 Listen-IP: 76.164.224.103:15649 X-Ext-Probes: 0.1 Remote-IP: x.x.x.x GGEP: 0.5 X-Dynamic-Querying: 0.1 X-Degree: 32 User-Agent: LimeWire/4.18.7 X-Ultrapeer: True X-Try-Ultrapeers: 121.54.32.36:3279,173.19.233.80:3714,65.182.97.15:5807,115.147.231.81:9751,72.134.30.181:15810,71.59.97.180:24295,74.76.84.250:25497,96.234.62.221:32344,69.44.246.38:42254,98.199.75.23:51230 GNUTELLA/0.6 200 OK So it seems that the malware has hooked into explorer.exe and hidden its self quite well as a Norton Scan doesn't pick anything up. I have looked in Windows firewall and it shouldn't be letting this traffic through. I have had a look into the messages explorer.exe is sending in Spy++ and the only related ones I can see are socket connections etc... My question is what can I do to look into this deeper? What does malware achieve by sending p2p traffic? I know to fix the problem the easiest way is to reinstall Windows but I want to get to the bottom of it first, just out of interest.

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  • ZipArchive on the iPhone unzips files but they are empty

    - by user345131
    I'm trying to use ZipArchive on the iPhone to unzip a simple text file. It returns with no error but the file is empty. I would love to know why this doesn't work. I am using the following methods: -(void)alert:(NSString*)message { UIAlertView *myAlert = [[UIAlertView alloc] initWithTitle:@"" message:message delegate:self cancelButtonTitle:@"Ok" otherButtonTitles:nil, nil]; [myAlert show]; [myAlert release]; } -(void)unzip { NSString *sourcepath = [[NSBundle mainBundle] pathForResource:@"secret" ofType:@"zip"]; NSString*filename = @"secret.txt"; NSArray *docPaths =NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES); NSString *destinationpath = [docPaths objectAtIndex: 0]; if (filename != nil ) destinationpath = [destinationpath stringByAppendingPathComponent: filename]; ZipArchive* za = [[ZipArchive alloc] init]; if( [za UnzipOpenFile:sourcepath Password:@""] ) { BOOL ret = [za UnzipFileTo:destinationpath overWrite:YES]; if( NO==ret ) [self alert:@"Problem"]; else [self alert:@"Success"]; [za UnzipCloseFile]; } [za release]; NSString *test = [[NSString alloc] initWithContentsOfFile:destinationpath encoding:NSASCIIStringEncoding error:nil]; [self alert:test]; }

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