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  • Calling subactivity from subactivity

    - by yogsma
    I have three activities in my android app. First activity is main application screen which gives option to open second screen containing second activity. But when I click on the button on second activity which was supposed to open third activity screen, I get "Application has stopped unexpectedly" error. <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="org.anddev.android.SampleApp" android:versionCode="1" android:versionName="1.0"> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".FirstActivity" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".SecondActivity" android:label="@string/app_name" > </activity> <activity android:name=".ThirdActivity" android:label="@string/app_name" > </activity> </application>

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  • changing WCF endpoint does not persist data.

    - by Vinay Pandey
    Hi All, I have an application that has reference of a WCF service on machine A, now on certain situation I want tu use similar service hosted on machine B. When I changed the endpoint using following:- EndpointAddress endpoint = new EndpointAddress(new Uri(ConfigurationManager.AppSettings["ServiceURLForMachineB"])); BasicHttpBinding binding = new BasicHttpBinding(); binding.SendTimeout = TimeSpan.FromMinutes(1); binding.OpenTimeout = TimeSpan.FromMinutes(1); binding.CloseTimeout = TimeSpan.FromMinutes(1); binding.ReceiveTimeout = TimeSpan.FromMinutes(10); binding.AllowCookies = false; binding.BypassProxyOnLocal = false; binding.HostNameComparisonMode = HostNameComparisonMode.StrongWildcard; binding.MessageEncoding = WSMessageEncoding.Mtom; binding.TextEncoding = System.Text.Encoding.UTF8; binding.TransferMode = TransferMode.Buffered; binding.UseDefaultWebProxy = true; repositoryService = new WorkflowRepositoryServiceClient(binding, endpoint); When I call login method although method is called from machine B, but username and password in Login(string username,string password) are coming null on machine B. Any Idea what I am doing wrong here?

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  • Suggestion on UPnP presentation

    - by Microkernel
    Hi all, I am working on an embedded device (bit higher end in terms of system resources but still an embedded one) which has lot of media content in it. I am trying to make it UPnP complaint and want to be able to control this device using a UPnP complaint control point/companion device like ipad. The step towards this is to be able to present the playlist content to the user. We thought of using HTML5 as a format to use. But as I am a noob in web technologies, I am not sure whats the best way to produce and present rich dynamic web pages. The content thats presented are video/audio listing that device can play and want this listing to be generated using the user's input criteria. So, what would be the best way to generate these dynamic pages which are rich and rendered as HTML5 pages. (looked at XML & XSLT, but there seems to be some limitations in how well one can use XSLT from some rewviews I saw). Thanks Microkernel PS: This may be silly or very basic as I am a embedded systems developer and not even a noob in web technologoes...

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  • Java getInputStream 400 errors

    - by Bill Szerdy
    When I contact a web service using a Java HttpUrlConnection it just returns a 400 Bad Request (IOException). How do I get the XML information that the server is returning; it does not appear to be in the getErrorStream of the connection nor is it in any of the exception information. When I run the following PHP code against a web service: <?php $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "https://www.myclientaddress.com/here/" ); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1 ); curl_setopt($ch, CURLOPT_POST,1 ); curl_setopt($ch, CURLOPT_POSTFIELDS,"username=ted&password=scheckler&type=consumer&id=123456789&zip=12345"); $result=curl_exec ($ch); echo $result; ?> it returns the following: <?xml version="1.0" encoding="utf-8"?> <response> <status>failure</status> <errors> <error name="RES_ZIP">Zip code is not valid.</error> <error name="ZIP">Invalid zip code for residence address.</error> </errors> </response> so I know the information exists

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  • Rexml - Parsing Data

    - by Paddy
    I have a XML File in the following format: <?xml version='1.0' encoding='UTF-8'?> <entry xmlns='http://www.w3.org/2005/Atom' xmlns:gwo='http://schemas.google.com/analytics/websiteoptimizer/2009' xmlns:app='http://www.w3.org/2007/app' xmlns:gd='http://schemas.google.com/g/2005' gd:etag='W/&quot;DUYGRX85fCp7I2A9WxFWEkQ.&quot;'><id>https://www.google.com/analytics/feeds/websiteoptimizer/experiments/1025910</id><updated>2010-05-31T02:12:04.124-07:00</updated><app:edited>2010-05-31T02:12:04.124-07:00</app:edited><title>Flow Experiment</title><link rel='gwo:goalUrl' type='text/html' href='http://cart.personallifemedia.com/dlg/download.php'/><link rel='alternate' type='text/html' href='https://www.google.com/websiteoptimizer'/><link rel='self' type='application/atom+xml' href='https://www.google.com/analytics/feeds/websiteoptimizer/experiments/1025910'/><gwo:analyticsAccountId>16334726</gwo:analyticsAccountId><gwo:autoPruneMode>None</gwo:autoPruneMode><gwo:controlScript>..... I have to parse and get the data for gd:etag and how do I do it? I was able to get the value using SimpleXML, but i wanted to achieve it in ReXML. Please do advice.

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  • How do I post a .wav file from CS5 Flash, AS3 to a Java servlet?

    - by Muostar
    Hi, I am trying to send a byteArray from my .fla to my running tomcat server integrated in Eclipse. From flash I am using the following code: var loader:URLLoader = new URLLoader(); var header:URLRequestHeader = new URLRequestHeader("audio/wav", "application/octet-stream"); var request:URLRequest = new URLRequest("http://localhost:8080/pdp/Server?wav=" + tableID); request.requestHeaders.push(header); request.method = URLRequestMethod.POST; request.data = file;//wav; loader.load(request); And my java servlet looks as follows: try{ int readBytes = -1; int lengthOfBuffer = request.getContentLength(); InputStream input = request.getInputStream(); byte[] buffer = new byte[lengthOfBuffer]; ByteArrayOutputStream output = new ByteArrayOutputStream(lengthOfBuffer); while((readBytes = input.read(buffer, 0, lengthOfBuffer)) != -1) { output.write(buffer, 0, readBytes); } byte[] finalOutput = output.toByteArray(); input.close(); FileOutputStream fos = new FileOutputStream(getServletContext().getRealPath(""+"/temp/"+wav+".wav")); fos.write(finalOutput); fos.close(); When i run the flash .swf file and send the bytearray to the server, I receive following in the server's console window:: (loads of loads of Chinese symbols) May 20, 2010 7:04:57 PM org.apache.tomcat.util.http.Parameters processParameters WARNING: Parameters: Character decoding failed. Parameter '? (loads of loads of Chinese symbols) and then looping this for a long time. It is like I recieve the bytes but not encoding/decoding them correctly. What can I do?

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  • Exposing a service to external systems - How should I design the contract?

    - by Larsi
    Hi! I know this question is been asked before here but still I'm not sure what to select. My service will be called from many 3 party system in the enterprise. I'm almost sure the information the service will collect (MyBigClassWithAllInfo) will change during the products lifetime. Is it still a good idea to expose objects? This is basically what my two alternatives: [ServiceContract] public interface ICollectStuffService { [OperationContract] SetDataResponseMsg SetData(SetDataRequestMsg dataRequestMsg); } // Alternative 1: Put all data inside a xml file [DataContract] public class SetDataRequestMsg { [DataMember] public string Body { get; set; } [DataMember] public string OtherPropertiesThatMightBeHandy { get; set; } // ?? } // Alternative 2: Expose the objects [DataContract] public class SetDataRequestMsg { [DataMember] public Header Header { get; set; } [DataMember] public MyBigClassWithAllInfo ExposedObject { get; set; } } public class SetDataResponseMsg { [DataMember] public ServiceError Error { get; set; } } The xml file would look like this: <?xml version="1.0" encoding="utf-8"?> <Message>   <Header>     <InfoAboutTheSender>...</InfoAboutTheSender>   </Header>   <StuffToCollectWithAllTheInfo>   <stuff1>...</stuff1> </StuffToCollectWithAllTheInfo> </Message> Any thought on how this service should be implemented? Thanks Larsi

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  • How do I serialize an enum value as an int?

    - by Espo
    I want to serialize my enum-value as an int, but i only get the name. Here is my (sample) class and enum: public class Request { public RequestType request; } public enum RequestType { Booking = 1, Confirmation = 2, PreBooking = 4, PreBookingConfirmation = 5, BookingStatus = 6 } And the code (just to be sure i'm not doing it wrong) Request req = new Request(); req.request = RequestType.Confirmation; XmlSerializer xml = new XmlSerializer(req.GetType()); StringWriter writer = new StringWriter(); xml.Serialize(writer, req); textBox1.Text = writer.ToString(); This answer (to another question) seems to indicate that enums should serialize to ints as default, but it doesn't seem to do that. Here is my output: <?xml version="1.0" encoding="utf-16"?> <Request xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <request>Confirmation</request> </Request> I have been able to serialize as the value by putting an "[XmlEnum("X")]" attribute on every value, but this just seems wrong.

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  • PHP XML Parsing

    - by ashchawla
    Hi I am making get request in PHP but the parser is having issues. I am looking for a way to retreive the value of URL in the following example. The response xml looks like this. <?xml version="1.0" encoding="iso-8859-1" standalone="no"?> <testtemplate JobName="test1"> <Sources> <Source xmlns="http://www.microsoft.com/test/schema/api"> <System> <SystemIdentifier>HTTPS</SystemIdentifier> <URL>http://example.com</URL> </System> </Source> </Sources> <testtemplate> and my PHP code looks like this: $xml = DOMDocument::LoadXML($response); $mypath = new DOMXPath($xml); $mypath->registerNamespace("a", "http://www.microsoft.com/test/schema/api"); $url = $mypath->evaluate("/testtemplate/Sources/Source/System/URL"); $message = $url->item(0)->value; print($message); Any help would be appreciated. Thanks Ashish

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  • HTTP Handler error when downloading files - SSL

    - by Chiefy
    Ok big problem as this is affecting two projects on our new server. We have a file that is downloaded by users, the files are downloaded using a HTTPHandler. Since moving the site to the server and setting SSL the downloads have stopped working and we get an error message "Unable to download DownloadDocument.ashx" from site". DownloadDocument.ashx is the handler page that is set in the web.config and the button that goes there is a hyperlink with the id of the document as a querystring. Ive read the article on http://support.microsoft.com/kb/316431 and read a few other requests on this site but nothing seems to be working. This problem only happens in IE and works fine when I run it on the server in http instead of https. public override void HandleRequest(HttpContext context) { Guid guid = new Guid(context.Request.QueryString["ID"]); DataTable dt = Documents.GetDocument(guid); if (dt != null) { context.Response.Cache.SetCacheability(HttpCacheability.Private); context.Response.AddHeader("content-disposition", string.Format("attachment; filename={0}", dt.Rows[0]["DocumentName"].ToString())); context.Response.AddHeader("Content-Transfer-Encoding", "binary"); context.Response.AddHeader("Content-Length", ((byte[])dt.Rows[0]["Document"]).Length.ToString()); context.Response.ContentType = string.Format("application/{0}", dt.Rows[0]["Extension"].ToString().Remove(0, 1)); context.Response.Buffer = true; context.Response.BinaryWrite((byte[])dt.Rows[0]["Document"]); context.Response.Flush(); context.Response.End(); } } The above is my current code for the request. Ive used the base handler on http://haacked.com/archive/2005/03/17/AnAbstractBoilerplateHttpHandler.aspx. Any ideas on what this might be and how we can fix it. Thanks in advance for all responses.

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  • Image overlapping in widget

    - by Hunt
    I am trying to create a widget in android in which when I click over image the image gets changed with a new one -- kind of toggle image. But when I click over it, the image overwrites over the old one rather then replacing the new one. I don't know whether this is the way the widget works or am I doing something wrong. My images are semi-transparent so in case one overrides another one can see the image which is being overlapped. This is the code that I have written in OnReceive by overriding it: @Override public void onReceive(Context context, Intent intent){ if (intent.getAction().equals(iAlertConstant.ACTION_WIDGET_UPDATE_FROM_WIDGET)) { RemoteViews remoteViews = new RemoteViews(context.getPackageName(),R.layout.mywidget); remoteViews.setImageViewResource(R.id.btnOnOff,R.drawable.offbtn); ComponentName thisWidget = new ComponentName(context, EmergencyWidget.class); AppWidgetManager.getInstance(context).updateAppWidget(thisWidget, remoteViews); } else super.onReceive(context, intent); } Layout <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:background="@drawable/widget_background" android:paddingLeft="10.0dip" android:paddingTop="8.0dip" android:paddingRight="10.0dip" android:paddingBottom="8.0dip" android:layout_width="fill_parent" android:layout_height="72dp" android:layout_marginLeft="10.0dip" android:layout_marginTop="10.0dip" android:layout_marginRight="10.0dip" android:id="@+id/emergencyWidget" android:orientation="horizontal"> <ImageView android:background="@drawable/offbtn" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginTop="7dp" android:layout_marginLeft="4dp" android:layout_marginRight="4dp" android:layout_gravity="right" android:id="@+id/btnOnOff" /> </LinearLayout>

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  • data transmission between two sites

    - by SaMSa
    I'm use Asp.Net Mvc 4 www.hostname.com to my site from my report.hostname2.com send and receive data to move directly to that address by the string bi codebehind. querysstring not, because sending a very long string I mean rapor.coskunoglu.net/Pdf address to send string data to move directly to that address PDF of the screen to make it appear so. How can I do this? Thank you, take it easy. I'm sorry, my english is not good. EDIT: I want to use POST. sb - my StringBuilder. byte[] bytt = Encoding.UTF8.GetBytes(sb.ToString()); WebRequest wr = WebRequest.Create("http://report.hostname2.com/Pdf"); wr.ContentType = "application/x-www-form-urlencoded"; wr.ContentLength = bytt.Length; wr.Method = "POST"; Stream st = wr.GetRequestStream(); st.Write(bytt, 0, bytt.Length); st.Close(); After you send the POST I want to go to report.hostname2.com. Did you see this my job?

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  • Leveraging hobby experience to get a job

    - by Bernard
    Like many other's I began programming at an early age. I started when I was 11 and I learned C when I was 14 (now 26). While most of what I did were games just to entertain myself I did everything from low level 2D graphics, and binary I/O, to interfacing with free API's, custom file systems, audio, 3D animations, OpenGL, web sites, etc. I worked on a wide variety of things trying to make various games. Because of this experience I have tested out of every college level C/C++ programming course I have ever been offered. In the classes I took, my classmates would need a week to do what I finished in class with an hour or two of work. I now have my degree now and I have 2 years of experience working full time as a web developer however I would like to get back into C++ and hopefully do simulation programming. Unfortunately I have yet to do C++ as a job, I have only done it for testing out of classes and doing my senior project in college. So most of what I have in C++ is still hobby experience and I don't know how to best convey that so that I don't end up stuck doing something too low level for me. Right now I see a job offer that requires 2 years of C++ experience, but I have at least 9 (I didn't do C++ everyday for the last 14 years). How do I convey my experience? How much is it truly worth? and How do I get it's full value? The best thing that I can think of is a demo and a portfolio, however that only comes into play after an interview has been secured. I used a portfolio to land my current job. All answers and advice are appreciated.

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  • Android: Why my user Interface does not get drawn when I Inflate the resource layout file?

    - by Einiosaurus
    First of all, I'm a newbie on Android programming, so please be detailed in your answers. I have a layout main.xml file with format similar to <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "vertical" android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "horizontal"   android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <EditText android:id="@+id/a" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <TextView android:id="@+id/xSquared" android:layout_width = "fill_parent" android:layout_height = "wrap_content" android:text = "@string/equationPart1" /> </LinearLayout> <LinearLayout ... </LinearLayout> </LinearLayout> In my Java source file, I inflate the UI using command: setContentView(R.layout.main); public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); } However, when I run the emulator, the UI does not show up like what I expect. Instead, it just display a simple EditText text box. I wonder what is going wrong. Is it because I put a layout inside another layout? I don't think there is any problem with that right?

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  • How to solve docbuiler saxexception: unexpected end of document?

    - by user211992
    I have a service that gives some car information in an xml format. <?xml version="1.0" encoding='UTF-8'?> <car> <id>5</id> <name>qwer</name> </car> <car> <id>6</id> <name>qwert</name> </car> Now the problem that I'm having is that my DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); Document doc = docBuilder.parse(xml); Sometimes throws a SAXException (sometimes it works just fine, but when I reboot the server (still in development) I sometimes keep getting it) with as cause SAXException: unexpected end of document. But when I place a bufferreader there to see what it's receiving and I copy the value into an xml document and I open it in firefox/ie it looks just fine.

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  • (Android) Seems like my JSON query is getting double encode

    - by A Gardner
    Hi, I am getting some weird errors with my Android App. It appears that this code is double encoding the JSON string. What should be sent is ?{"email":"[email protected]","password":"asdf"} or ?%7B%22email%22:%22..... what the server is seeing is %257B%2522email%2522:%2522 .... which means the server sees %7B%22email%22:%22 ..... This confuses the server. Any ideas why this is happening? Thanks for your help Code: DefaultHttpClient c = new DefaultHttpClient(); if(cookies!=null) c.setCookieStore(cookies); if(loginNotLogout){ jso.put("email", userData.email); jso.put("password", userData.password); } URI u = null; if(loginNotLogout) u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); else u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); HttpGet httpget = new HttpGet(u); HttpResponse response = c.execute(httpget); ret.jsonString = EntityUtils.toString(response.getEntity());

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  • Why is Firefox prompting to download a file that is POST'd to?

    - by alex
    This is the most peculiar thing. It is from an old in house CMS. When I attempt to submit my changes, it prompts to save the file linked in the action attribute of the form. Headers Request POST /~site/edit/articles/article_save.php?id=54 HTTP/1.1 Host: example.com User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://example.com Content-Type: multipart/form-data; boundary=---------------------------10102754414578508781458777923 Content-Length: 940 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="title" Home Content -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="catid" 18 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="activecheck" 1 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="image" -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgToolbarSelectBlock" <p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="content" <p>Edit your article in this text box.</p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgEditor" true -----------------------------10102754414578508781458777923-- Response HTTP/0.9 200 OK And then Firefox shows.... I can't determine from the response headers as to why this is prompting to open/save. It has always worked. All other PHP files on the site work fine. Anyone have a clue? Thanks Update Apparently, it just crashes Safari.

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  • What does "Value does not fall within expected range" mean in runtime error?

    - by manuel
    Hi, I'm writing a plugin (dll file) using /clr and trying to implement speech recognition using .NET. But when I run it, I got a runtime error saying "Value does not fall within expected range", what does the message mean? public ref class Dialog : public System::Windows::Forms::Form { public: SpeechRecognitionEngine^ sre; private: System::Void btnSpeak_Click(System::Object^ sender, System::EventArgs^ e) { Initialize(); } protected: void Initialize() { //create the recognition engine sre = gcnew SpeechRecognitionEngine(); //set our recognition engine to use the default audio device sre->SetInputToDefaultAudioDevice(); //create a new GrammarBuilder to specify which commands we want to use GrammarBuilder^ grammarBuilder = gcnew GrammarBuilder(); //append all the choices we want for commands. //we want to be able to move, stop, quit the game, and check for the cake. grammarBuilder->Append(gcnew Choices("play", "stop")); //create the Grammar from th GrammarBuilder Grammar^ customGrammar = gcnew Grammar(grammarBuilder); //unload any grammars from the recognition engine sre->UnloadAllGrammars(); //load our new Grammar sre->LoadGrammar(customGrammar); //add an event handler so we get events whenever the engine recognizes spoken commands sre->SpeechRecognized += gcnew EventHandler<SpeechRecognizedEventArgs^> (this, &Dialog::sre_SpeechRecognized); //set the recognition engine to keep running after recognizing a command. //if we had used RecognizeMode.Single, the engine would quite listening after //the first recognized command. sre->RecognizeAsync(RecognizeMode::Multiple); //this->init(); } void sre_SpeechRecognized(Object^ sender, SpeechRecognizedEventArgs^ e) { //simple check to see what the result of the recognition was if (e->Result->Text == "play") { MessageBox(plugin.hwndParent, L"play", 0, 0); } if (e->Result->Text == "stop") { MessageBox(plugin.hwndParent, L"stop", 0, 0); } } };

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  • Why is log4j not behaving as expected?

    - by Kieveli
    I have a co-worker who is trying to get log4j to behave as follows: Log to Stdout By default, disable most output Show only messages from java.sql.PrepareStatement at level debug and up He's getting caught up in the 'level' vs 'priority'. Here is his config file: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE log4j:configuration SYSTEM "D:/Java/apache-log4j-1.2.15/src/main/resources/org/apache/log4j/xml/log4j.dtd" > <log4j:configuration> <!-- Appenders --> <appender name="stdout" class="org.apache.log4j.ConsoleAppender"> <layout class="org.apache.log4j.PatternLayout"> <param name="ConversionPattern" value="%5p %d{ISO8601} [%t][%x] %c - %m%n" /> </layout> </appender> <!-- Loggers for ibatus and JDBC database --> <logger name="java.sql.PreparedStatement"> <level value="debug"/> </logger> <!-- The Root Logger --> <root> <level value="error"/> <appender-ref ref="stdout"/> </root> </log4j:configuration> The output from this shows no messages in the log output. How does he need to change his log4j.xml config file to make it behave as he's expecting?

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  • Java Mvc And Hibernate

    - by GigaPr
    Hi i am trying to learn Java, Hibernate and the MVC pattern. Following various tutorial online i managed to map my database, i have created few Main methods to test it and it works. Furthermore i have created few pages using the MVC patter and i am able to display some mock data as well in a view. the problem is i can not connect the two. this is what i have My view Looks like this <%@ include file="/WEB-INF/jsp/include.jsp" %> <html> <head> <title>Users</title> <%@ include file="/WEB-INF/jsp/head.jsp" %> </head> <body> <%@ include file="/WEB-INF/jsp/header.jsp" %> <img src="images/rss.png" alt="Rss Feed"/> <%@ include file="/WEB-INF/jsp/menu.jsp" %> <div class="ContainerIntroText"> <img src="images/usersList.png" class="marginL150px" alt="Add New User"/> <br/> <br/> <div class="usersList"> <div class="listHeaders"> <div class="headerBox"> <strong>FirstName</strong> </div> <div class="headerBox"> <strong>LastName</strong> </div> <div class="headerBox"> <strong>Username</strong> </div> <div class="headerAction"> <strong>Edit</strong> </div> <div class="headerAction"> <strong>Delete</strong> </div> </div> <br><br> <c:forEach items="${users}" var="user"> <div class="listElement"> <c:out value="${user.firstName}"/> </div> <div class="listElement"> <c:out value="${user.lastName}"/> </div> <div class="listElement"> <c:out value="${user.username}"/> </div> <div class="listElementAction"> <input type="button" name="Edit" title="Edit" value="Edit"/> </div> <div class="listElementAction"> <input type="image" src="images/delete.png" name="image" alt="Delete" > </div> <br /> </c:forEach> </div> </div> <a id="addUser" href="addUser.htm" title="Click to add a new user">&nbsp;</a> </body> </html> My controller public class UsersController implements Controller { private UserServiceImplementation userServiceImplementation; public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("users"); List<User> users = this.userServiceImplementation.get(); modelAndView.addObject("users", users); return modelAndView; } public UserServiceImplementation getUserServiceImplementation() { return userServiceImplementation; } public void setUserServiceImplementation(UserServiceImplementation userServiceImplementation) { this.userServiceImplementation = userServiceImplementation; } } My servelet definitions <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <bean name="/home.htm" class="com.rssFeed.mvc.HomeController"/> <bean name="/rssFeeds.htm" class="com.rssFeed.mvc.RssFeedsController"/> <bean name="/addUser.htm" class="com.rssFeed.mvc.AddUserController"/> <bean name="/users.htm" class="com.rssFeed.mvc.UsersController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> </bean> <bean id="userServiceImplementation" class="com.rssFeed.ServiceImplementation.UserServiceImplementation"> <property name="users"> <list> <ref bean="user1"/> <ref bean="user2"/> </list> </property> </bean> <bean id="user1" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName1"/> <property name="lastName" value="lastName1"/> <property name="username" value="username1"/> <property name="password" value="password1"/> </bean> <bean id="user2" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName2"/> <property name="lastName" value="lastName2"/> <property name="username" value="username2"/> <property name="password" value="password2"/> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans> and finally this class to access the database public class HibernateUserDao extends HibernateDaoSupport implements UserDao { public void addUser(User user) { getHibernateTemplate().saveOrUpdate(user); } public List<User> get() { User user1 = new User(); user1.setFirstName("FirstName"); user1.setLastName("LastName"); user1.setUsername("Username"); user1.setPassword("Password"); List<User> users = new LinkedList<User>(); users.add(user1); return users; } public User get(int id) { throw new UnsupportedOperationException("Not supported yet."); } public User get(String username) { return null; } } the database connection occurs in this file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver"/> <property name="url" value="jdbc:hsqldb:hsql://localhost/rss"/> <property name="username" value="sa"/> <property name="password" value=""/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean" > <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/rssFeed/domain/User.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory"/> </bean> <bean id="userDao" class="com.rssFeed.dao.hibernate.HibernateUserDao"> <property name="sessionFactory" ref="sessionFactory"/> </bean> </beans> Could you help me to solve this problem i spent the last 4 days and nights on this issue without any success Thanks

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  • How to vertically align text in a button with a background drawable?

    - by neutrino
    I had a simple button set up with a background image defined like android:background="?attr/button" where ?attr/button was a reference to a simple 9-patch png. Everything worked fine, text in the button was aligned correctly. Then I needed to have a different background for a pressed state of the button. So I changed that to android:background="@drawable/state_button" where @drawable/state_button is an xml with the following states <?xml version="1.0" encoding="utf-8"?> <selector xmlns:android="http://schemas.android.com/apk/res/android"> <item android:state_pressed="true" android:drawable="@drawable/button_pressed" /> <!-- pressed --> <item android:state_focused="true" android:drawable="@drawable/button_pressed" /> <!-- focused --> <item android:drawable="@drawable/button" /> <!-- default --> </selector> And after that I can't align the text properly. If I put android:gravity="center_vertical" the text is drawn about 1/4 of the button height from the top. I double-checked my 9-patch images, everything seems fine with them. And I also tried having regular pngs for the background, it also doesn't change anything.

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  • Object Oriented Perl interface to read from and write to a socket

    - by user654967
    I need a perl client-server implementation as a wrapper for a server in C#. A perl script passes the server address and port number and an input string to a module, this module has to create the socket and send the input string to the server. The data sent has to follow ISO-8859-1 encoding. On receiving the information, the client has to first receive 3 byte, then the next 8 bytes, this has the length of the data that has to be received next.. so based on the length the client has to read the next data. each of the data that is read has to be stored in a variable and sent another module for further processing. Currently this is what my perl client looks like..which I'm sure isn't right..could someone tell me how to do this..and set me on the right direction.. sub WriteInfo { my ($addr, $port, $Input) = @_; $socket = IO::Socket::INET->new( Proto => "tcp", PeerAddr => $addr, PeerPort => $port, ); unless ($socket) { die "cannot connect to remote" } while (1) { $socket->send($Input); } } sub ReadData { while (1) { my $ExecutionResult = $socket->recv( $recv_data, 3); my $DataLength = $socket->recv( $recv_data, 8); $DataLength =~ s/^0+// ; my $decval = hex($DataLength); my $Data = $socket->recv( $recv_data, $decval); return($Data); } thanks a lot.. Archer

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  • What is the easiest way to add compression to WCF in Silverlight?

    - by caryden
    I have a silverlight 2 beta 2 application that accesses a WCF web service. Because of this, it currently can only use basicHttp binding. The webservice will return fairly large amounts of XML data. This seems fairly wasteful from a bandwidth usage standpoint as the response, if zipped, would be smaller by a factor of 5 (I actually pasted the response into a txt file and zipped it.). The request does have the "Accept-Encoding: gzip, deflate" - Is there any way have the WCF service gzip (or otherwise compress) the response? I did find this link but it sure seems a bit complex for functionality that should be handled out-of-the-box IMHO. OK - at first I marked the solution using the System.IO.Compression as the answer as I could never "seem" to get the IIS7 dynamic compression to work. Well, as it turns out: Dynamic Compression on IIS7 was working al along. It is just that Nikhil's Web Developer Helper plugin for IE did not show it working. My guess is that since SL hands the web service call off to the browser, that the browser handles it "under the covers" and Nikhil's tool never sees the compressed response. I was able to confirm this by using Fiddler which monitors traffic external to the browser application. In fiddler, the response was, in fact, gzip compressed!! The other problem with the System.IO.Compression solution is that System.IO.Compression does not exist in the Silverlight CLR. So from my perspective, the EASIEST way to enable WCF compression in Silverlight is to enable Dynamic Compression in IIS7 and write no code at all.

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  • create dynamic navigation from xml file in flash cs3

    - by mjr
    action script newbie here :-) What I want to do is this, hand an xml file to a swf and have the swf generate a dynamic text box and button for each of the links in the xml file a rudimentary navigation here's the xml <?xml version="1.0" encoding="UTF-8"?> <page> <page name="Page Name 1" url="/page-1/" /> <page name="Page Name 2" url="/page-2/" /> <page name="Page Name 3" url="/page-3/" /> <page name="Page Name 4" url="/page-4/" /> </page> and in my fla I have a button in my library named 'nav_button' there's a layer named actions and in frame 1 I have this var xml:XML; var xmlList:XMLList; var xmlLoader:URLLoader = new URLLoader(); var button:Button = new Button(); xmlLoader.load(new URLRequest("links.xml")); xmlLoader.addEventListener(Event.COMPLETE, xmlLoaded); function xmlLoaded(event:Event):void { xml = XML(event.target.data); xmlList = xml.children(); trace(xml.length()); for(var i:int = 0; i < xmlList.length(); i++) { button = new Button(); button.x = 25; button.y = i * 50 +25; addChild(button); } } the xml imports fine, but when it comes to the for loop and adding the buttons and text boxes to the stage, I'm toast

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  • How to parse XML to flex Data Grid contents.

    - by Jeeva
    My xml file which is in a webserver is show below. <root> <userdetails> <username>raja</username> <status>offline</status> </userdetails> <userdetails> <username>Test</username> <status>online</status> </userdetails> </root> How can i parse this to flex data grid contents. I tried with below coding < ?xml version="1.0" encoding="utf-8"? < mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" creationComplete="initApp()" < mx:HTTPService id="userList" result="handleData(event)" resultFormat="object" url="http://apps.facebook.com/ajparkin/user_list.xml" / <mx:Script> <![CDATA[ import mx.collections.ArrayCollection; import mx.rpc.events.ResultEvent; import mx.controls.Alert; public function initApp():void { userList.send(); } [Bindable] var userdetailsArray:ArrayCollection; private function handleData(evt:ResultEvent):void { this.userdetailsArray= evt.result.userdetails; } ]]> </mx:Script> <mx:DataGrid dataProvider="{userdetailsArray}"> <mx:columns> <mx:DataGridColumn dataField="username" headerText="User Name"/> <mx:DataGridColumn dataField="status" headerText="Status" /> </mx:columns> </mx:DataGrid> </mx:Application> I'm getting only the field names not the data.

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