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  • Group by SQL with count

    - by snorlaks
    Lets say we have got rows like that: MyTable ID Name Product 1 Adam x 2 Adam y 3 Adam z 4 Peter a 5 Peter b Using query like: Select Name, Count(Product) from MyTable group by Name results will be: Adam 3 Peter 2 But I would like results like: 1 Adam x 3 2 Adam y 3 3 Adam z 3 4 Peter a 2 5 Peter b 2 I hope Ypu know what I mean Could You help me with that query, thanks for help, Bye

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  • Mounting NFS share between OSX and Centos VM

    - by Adam
    I'm having issues mounting an NFS share I've made on my Mac host (server) from a Centos VM (client). I'm getting a permission denied error. I have this line in /etc/exports on server: /Users/adam/Sites/ 192.168.1.223(rw) and in /etc/fstab on client: 192.168.1.186:/Users/adam/Sites/ /home/adam/Sites/ nfs rw 0 0 I'm sure this is a simple configuration issue, but I've never set up NFS properly before. Extra info: # mount -v 192.168.1.186:/Users/adam/Sites/ /home/adam/Sites/ mount: no type was given - I'll assume nfs because of the colon mount.nfs: timeout set for Mon Nov 26 07:31:40 2012 mount.nfs: trying text-based options 'vers=4,addr=192.168.1.186,clientaddr=192.168.1.223' mount.nfs: mount(2): Protocol not supported mount.nfs: trying text-based options 'addr=192.168.1.186' mount.nfs: prog 100003, trying vers=3, prot=6 mount.nfs: trying 192.168.1.186 prog 100003 vers 3 prot TCP port 2049 mount.nfs: prog 100005, trying vers=3, prot=17 mount.nfs: trying 192.168.1.186 prog 100005 vers 3 prot UDP port 958 mount.nfs: mount(2): Permission denied mount.nfs: access denied by server while mounting 192.168.1.186:/Users/adam/Sites/

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  • Code Golf: Code 39 Bar Code

    - by gwell
    The challenge The shortest code by character count to draw an ASCII representation of a Code 39 bar code. Wikipedia article about Code 39: http://en.wikipedia.org/wiki/Code_39 Input The input will be a string of legal characters for Code 39 bar codes. This means 43 characters are valid: 0-9 A-Z (space) and -.$/+%. The * character will not appear in the input as it is used as the start and stop characters. Output Each character encoded in Code 39 bar codes have nine elements, five bars and four spaces. Bars will be represented with # characters, and spaces will be represented with the space character. Three of the nine elements will be wide. The narrow elements will be one character wide, and the wide elements will be three characters wide. A inter-character space of a single space should be added between each character pattern. The pattern should be repeated so that the height of the bar code is eight characters high. The start/stop character * (bWbwBwBwb) would be represented like this: # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # ^ ^ ^^ ^ ^ ^ ^^^ | | || | | | ||| narrow bar -+ | || | | | ||| wide space ---+ || | | | ||| narrow bar -----+| | | | ||| narrow space ------+ | | | ||| wide bar --------+ | | ||| narrow space ----------+ | ||| wide bar ------------+ ||| narrow space --------------+|| narrow bar ---------------+| inter-character space ----------------+ The start and stop character * will need to be output at the start and end of the bar code. No quiet space will need to be included before or after the bar code. No check digit will need to be calculated. Full ASCII Code39 encoding is not required, just the standard 43 characters. No text needs to be printed below the ASCII bar code representation to identify the output contents. The character # can be replaced with another character of higher density if wanted. Using the full block character U+2588, would allow the bar code to actually scan when printed. Test cases Input: ABC Output: # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # Input: 1/3 Output: # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # Input: - $ (minus space dollar) Output: # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # Code count includes input/output (full program).

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  • Code Golf: Collatz Conjecture

    - by Earlz
    Inspired by http://xkcd.com/710/ here is a code golf for it. The Challenge Given a positive integer greater than 0, print out the hailstone sequence for that number. The Hailstone Sequence See Wikipedia for more detail.. If the number is even, divide it by two. If the number is odd, triple it and add one. Repeat this with the number produced until it reaches 1. (if it continues after 1, it will go in an infinite loop of 1 -> 4 -> 2 -> 1...) Sometimes code is the best way to explain, so here is some from Wikipedia function collatz(n) show n if n > 1 if n is odd call collatz(3n + 1) else call collatz(n / 2) This code works, but I am adding on an extra challenge. The program must not be vulnerable to stack overflows. So it must either use iteration or tail recursion. Also, bonus points for if it can calculate big numbers and the language does not already have it implemented. (or if you reimplement big number support using fixed-length integers) Test case Number: 21 Results: 21 -> 64 -> 32 -> 16 -> 8 -> 4 -> 2 -> 1 Number: 3 Results: 3 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1 Also, the code golf must include full user input and output.

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  • Code Golf: 1x1 black pixel

    - by Joey Adams
    Recently, I used my favorite image editor to make a 1x1 black pixel (which can come in handy when you want to draw solid boxes in HTML cheaply). Even though I made it a monochrome PNG, it came out to be 120 bytes! I mean, that's kind of steep. 120 bytes. For one pixel. I then converted it to a GIF, which dropped the size down to 43 bytes. Much better, but still... Challenge The shortest image file or program that is or generates a 1x1 black pixel. A submission may be: An image file that represents a 1x1 black pixel. The format chosen must be able to represent larger images than 1x1, and cannot be ad-hoc (that is, it can't be an image format you just made up for code golf). Image files will be ranked by byte count. A program that generates such an image file. Programs will be ranked by character count, as usual in code golf. As long as an answer falls into one of these two categories, anything is fair game.

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  • Code Golf: Leibniz formula for Pi

    - by Greg Beech
    I recently posted one of my favourite interview whiteboard coding questions in "What's your more controversial programming opinion", which is to write a function that computes Pi using the Leibniz formula. It can be approached in a number of different ways, and the exit condition takes a bit of thought, so I thought it might make an interesting code golf question. Shortest code wins! Given that Pi can be estimated using the function 4 * (1 - 1/3 + 1/5 - 1/7 + ...) with more terms giving greater accuracy, write a function that calculates Pi to within 0.00001. Edit: 3 Jan 2008 As suggested in the comments I changed the exit condition to be within 0.00001 as that's what I really meant (an accuracy 5 decimal places is much harder due to rounding and so I wouldn't want to ask that in an interview, whereas within 0.00001 is an easier to understand and implement exit condition). Also, to answer the comments, I guess my intention was that the solution should compute the number of iterations, or check when it had done enough, but there's nothing to prevent you from pre-computing the number of iterations and using that number. I really asked the question out of interest to see what people would come up with.

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  • Code Golf - p day

    - by gnibbler
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character, followed by an approximation of p. Input is a single number, R. Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation of p is given by dividing twice the number of * characters by R². The approximation should be correct to at least 6 significant digits. Leading or trailing zeros are permitted, so for example any of 3, 3.000000, 003 is accepted for the inputs of 2 and 4. Code count includes input/output (i.e., full program). Test Cases Input 2 Output *** *** 3.0 Input 4 Output ***** ******* ******* ***** 3.0 Input 8 Output ******* ************* *************** *************** *************** *************** ************* ******* 3.125 Input 10 Output ********* *************** ***************** ******************* ******************* ******************* ******************* ***************** *************** ********* 3.16

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  • Code Golf - PI day

    - by gnibbler
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character. Followed by an approximation of pi Input is a single number, R Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation of pi is given by dividing the twice the number of * characters by R squared. The approximation should be correct to at least 6 significant digits. Leading or trailing zeros are permitted, so for example any of 3,3.000000,003 is accepted for the inputs of 2 and 4 Code count includes input/output (i.e full program). Test Cases Input 2 Output *** *** 3.0 Input 4 Output ***** ******* ******* ***** 3.0 Input 8 Output ******* ************* *************** *************** *************** *************** ************* ******* 3.125 Input 10 Output ********* *************** ***************** ******************* ******************* ******************* ******************* ***************** *************** ********* 3.16

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  • Selecting by observation in R table

    - by Stedy
    I was working through the Rosetta Code example of the knapsack problem in R and I came up with four solutions. What is the best way to output only one of the solutions based on the observation number give in the table? > values[values$value==max(values$value),] I II III value weight volume 2067 9 0 11 54500 25 25 2119 6 5 11 54500 25 25 2171 3 10 11 54500 25 25 2223 0 15 11 54500 25 25 My initial idea was to save this output to a new variable, then query the new variable such as: > newvariable <- values[values$value==max(values$value),] > newvariable2 <- newvariable[2,] > newvariable2 I II III value weight volume 2119 6 5 11 54500 25 25 This gives me the desired output but is there a cleaner way to do it?

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  • Connecting to Active Directory Application Mode from Perl

    - by Khurram Aziz
    I am trying to connect to Active Directory Application Mode instance. The instance is conenctable from third party LDAP clients like Softerra LDAP Browser. But I am getting the following error when connecting from Perl Net::LDAP=HASH(0x876d8e4) sending: Net::LDAP=HASH(0x876d8e4) received: 30 84 00 00 00 A7 02 01 02 65 84 00 00 00 9E 0A 0........e...... 01 01 04 00 04 84 00 00 00 93 30 30 30 30 30 34 ..........000004 44 43 3A 20 4C 64 61 70 45 72 72 3A 20 44 53 49 DC: LdapErr: DSI 44 2D 30 43 30 39 30 36 32 42 2C 20 63 6F 6D 6D D-0C09062B, comm 65 6E 74 3A 20 49 6E 20 6F 72 64 65 72 20 74 6F ent: In order to 20 70 65 72 66 6F 72 6D 20 74 68 69 73 20 6F 70 perform this op 65 72 61 74 69 6F 6E 20 61 20 73 75 63 63 65 73 eration a succes 73 66 75 6C 20 62 69 6E 64 20 6D 75 73 74 20 62 sful bind must b 65 20 63 6F 6D 70 6C 65 74 65 64 20 6F 6E 20 74 e completed on t 68 65 20 63 6F 6E 6E 65 63 74 69 6F 6E 2E 2C 20 he connection., 64 61 74 61 20 30 2C 20 76 65 63 65 00 __ __ __ data 0, vece.` My directory structure is Partition: CN=Apps,DC=MyCo,DC=COM User exists as CN=myuser,CN=Apps,DC=MyCo,DC=COM I have couple of other entries of the custom class which I am interested to browse; those instances appear fine in ADSI Edit, Softerra LDAP Browser etc. I am new to Perl....My perl code is #!/usr/bin/perl use Net::LDAP; $ldap = Net::LDAP->new("127.0.0.1", debug => 2, user => "CN=myuser,CN=Apps,DC=MyCo,DC=COM", password => "secret" ) or die "$@"; $ldap->bind(version => 3) or die "$@"; print "Connected to ldap\n"; $mesg = $ldap->search( filter => "(objectClass=*)" ) or die ("Failed on search.$!"); my $max = $mesg->count; print "$max records found!\n"; for( my $index = 0 ; $index < $max ; $index++) { my $entry = $mesg->entry($index); my $dn = $entry->dn; @attrs = $entry->attributes; foreach my $var (@attrs) { $attr = $entry->get_value( $var, asref => 1 ); if ( defined($attr) ) { foreach my $value ( @$attr ) { print "$var: $value\n"; } } } } $ldap->unbind();

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  • Code Golf: MSM Random Number Generator

    - by Vivin Paliath
    The challenge The shortest code by character count that will generate (pseudo)random numbers using the Middle-Square Method. The Middle-Square Method of (pseudo)random number generation was first suggested by John Von Neumann in 1946 and is defined as follows: Rn+1 = mid((Rn)2, m) For example: 34562 = 11943936 mid(11943936) = 9439 94392 = 89094721 mid(89094721) = 0947 9472 = 896809 mid(896809) = 9680 96802 = 93702400 mid(93702400) = 7024 Test cases: A seed of 8653 should give the following numbers (first 10): 8744, 4575, 9306, 6016, 1922, 6940, 1636, 6764, 7516, 4902

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  • The Skyline Problem.

    - by zeroDivisible
    I just came across this little problem on UVA's Online Judge and thought, that it may be a good candidate for a little code-golf. The problem: You are to design a program to assist an architect in drawing the skyline of a city given the locations of the buildings in the city. To make the problem tractable, all buildings are rectangular in shape and they share a common bottom (the city they are built in is very flat). The city is also viewed as two-dimensional. A building is specified by an ordered triple (Li, Hi, Ri) where Li and Ri are left and right coordinates, respectively, of building i and Hi is the height of the building. In the diagram below buildings are shown on the left with triples (1,11,5), (2,6,7), (3,13,9), (12,7,16), (14,3,25), (19,18,22), (23,13,29), (24,4,28) and the skyline, shown on the right, is represented by the sequence: 1, 11, 3, 13, 9, 0, 12, 7, 16, 3, 19, 18, 22, 3, 23, 13, 29, 0 The output should consist of the vector that describes the skyline as shown in the example above. In the skyline vector (v1, v2, v3, ... vn) , the vi such that i is an even number represent a horizontal line (height). The vi such that i is an odd number represent a vertical line (x-coordinate). The skyline vector should represent the "path" taken, for example, by a bug starting at the minimum x-coordinate and traveling horizontally and vertically over all the lines that define the skyline. Thus the last entry in the skyline vector will be a 0. The coordinates must be separated by a blank space. If I will not count declaration of provided (test) buildings and including all spaces and tab characters, my solution, in Python, is 223 characters long. Here is the condensed version: B=[[1,11,5],[2,6,7],[3,13,9],[12,7,16],[14,3,25],[19,18,22],[23,13,29],[24,4,28]] # Solution. R=range v=[0 for e in R(max([y[2] for y in B])+1)] for b in B: for x in R(b[0], b[2]): if b[1]>v[x]: v[x]=b[1] p=1 k=0 for x in R(len(v)): V=v[x] if p and V==0: continue elif V!=k: p=0 print "%s %s" % (str(x), str(V)), k=V I think that I didn't made any mistake but if so - feel free to criticize me. EDIT I don't have much reputation, so I will pay only 100 for a bounty - I am curious, if anyone could try to solve this in less than .. lets say, 80 characters. Solution posted by cobbal is 101 characters long and currently it is the best one. ANOTHER EDIT I thought, that 80 characters is a sick limit for this kind of problem. cobbal, with his 46 character solution totaly amazed me - though I must admit, that I spent some time reading his explanation before I partially understood what he had written.

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  • Rewriting UNIX cal(1)

    - by dharmatech
    Hello, Today I was testing out SRFI 19 and wrote a simple version of the UNIX cal(1) command. Here's a version in R6RS Scheme which runs in Ikarus and Ypsilon. A few example runs. Schemers: How would you write it? Use your favorite implementation. Ruby and Python: I'm guessing that y'all have elegant date and time libraries. I'm sure you can put the Schemers to shame. ;-) Let's see what ya got. I'd also like to see Haskell and golfed versions. Is there a Stack Overflow tag for re-implementations of UNIX commands? :-) Ed

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  • Code Golf - Banner Generation

    - by Claudiu
    When thanking someone, you don't want to just send them an e-mail saying "Thanks!", you want to have something FLASHY: Input: THANKS!! Output: TTT H H AAA N N K K SSS !!! !!! T H H A A NNN K K S !!! !!! T HHH AAA NNN KK SSS !!! !!! T H H A A N N K K S T H H A A N N K K SSS !!! !!! Write a program to generate a banner. You only have to generate upper-case A-Z along with spaces and exclamation points (what is a banner without an exclamation point?). All characters are made up of a 3x5 grid of the same character (so the S is a 3x5 grid made of S). All output should be on one row (so no newlines). Here are all the letters you need: Input: ABCDEFGHIJKL Output: AAA BBB CCC DD EEE FFF GGG H H III JJJ K K L A A B B C D D E F G H H I J K K L AAA BBB C D D EE FF G G HHH I J KK L A A B B C D D E F G G H H I J J K K L A A BBB CCC DD EEE F GGG H H III JJJ K K LLL Input: MNOPQRSTUVWX Output: M M N N OOO PPP QQQ RR SSS TTT U U V V W W X X MMM NNN O O P P Q Q R R S T U U V V W W X M M NNN O O PPP Q Q RR SSS T U U V V WWW X M M N N O O P QQQ R R S T U U V V WWW X M M N N OOO P QQQ R R SSS T UUU V WWW X X Input: YZ! Output: Y Y ZZZ !!! Y Y Z !!! YYY Z !!! Y Z YYY ZZZ !!! The winner is the shortest source code. Source code should read input from stdin, output to stdout. You can assume input will only contain [A-Z! ]. If you insult the user on incorrect input, you get a 10 character discount =P. I was going to require these exact 27 characters, but to make it more interesting, you can choose how you want them to look - whatever makes your code shorter! To prove that your letters do look like normal letters, show the output of the last three runs.

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  • Code Golf: Word Search Solver

    - by Maxim Z.
    Note: This is my first Code Golf challenge/question, so I might not be using the correct format below. I'm not really sure how to tag this particular question, and should this be community wiki? Thanks! This Code Golf challenge is about solving word searches! A word search, as defined by Wikipedia, is: A word search, word find, word seek, word sleuth or mystery word puzzle is a word game that is letters of a word in a grid, that usually has a rectangular or square shape. The objective of this puzzle is to find and mark all the words hidden inside the box. The words may be horizontally, vertically or diagonally. Often a list of the hidden words is provided, but more challenging puzzles may let the player figure them out. Many word search puzzles have a theme to which all the hidden words are related. The word searches for this challenge will all be rectangular grids with a list of words to find provided. The words can be written vertically, horizontally, or diagonally. Input/Output The user inputs their word search and then inputs a word to be found in their grid. These two inputs are passed to the function that you will be writing. It is up to you how you want to declare and handle these objects. Using a strategy described below or one of your own, the function finds the specific word in the search and outputs its starting coordinates (simply row number and column number) and ending coordinates. If you find two occurrences of the word, you must output both's set of coordinates. Example Input: A I Y R J J Y T A S V Q T Z E X B X G R Z P W V T B K U F O E A F L V F J J I A G B A J K R E S U R E P U S C Y R S Y K F B B Q Y T K O I K H E W G N G L W Z F R F H L O R W A R E J A O S F U E H Q V L O A Z B J F B G I F Q X E E A L W A C F W K Z E U U R Z R T N P L D F L M P H D F W H F E C G W Z B J S V O A O Y D L M S T C R B E S J U V T C S O O X P F F R J T L C V W R N W L Q U F I B L T O O S Q V K R O W G N D B C D E J Y E L W X J D F X M Word to find: codegolf Output: row 12, column 8 --> row 5, column 1 Strategies Here are a few strategies you might consider using. It is completely up to you to decide what strategy you want to use; it doesn't have to be in this list. Looking for the first letter of the word; on each occurrence, looking at the eight surrounding letters to see whether the next letter of the word is there. Same as above, except looking for a part of a word that has two of the same letter side-by-side. Counting how often each letter of the alphabet is present in the whole grid, then selecting one of the least-occurring letters from the word you have to find and searching for the letter. On each occurrence of the letter, you look at its eight surrounding letters to see whether the next and previous letters of the word is there.

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  • Code Golf: Tic Tac Toe

    - by Aistina
    Post your shortest code, by character count, to check if a player has won, and if so, which. Assume you have an integer array in a variable b (board), which holds the Tic Tac Toe board, and the moves of the players where: 0 = nothing set 1 = player 1 (X) 2 = player 2 (O) So, given the array b = [ 1, 2, 1, 0, 1, 2, 1, 0, 2 ] would represent the board X|O|X -+-+- |X|O -+-+- X| |O For that situation, your code should output 1 to indicate player 1 has won. If no-one has won you can output 0 or false. My own (Ruby) solution will be up soon. Edit: Sorry, forgot to mark it as community wiki. You can assume the input is well formed and does not have to be error checked. Update: Please post your solution in the form of a function. Most people have done this already, but some haven't, which isn't entirely fair. The board is supplied to your function as the parameter. The result should be returned by the function. The function can have a name of your choosing.

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  • Decision Tree code golf

    - by Chris Jester-Young
    In Google Code Jam 2009, Round 1B, there is a problem called Decision Tree that lent itself to rather creative solutions. Post your shortest solution; I'll update the Accepted Answer to the current shortest entry on a semi-frequent basis, assuming you didn't just create a new language just to solve this problem. :-P Current rankings: 107 Perl 121 PostScript (binary) 136 Ruby 154 Arc 160 PostScript (ASCII85) 170 PostScript 192 Python 199 Common Lisp 214 LilyPond 222 JavaScript 273 Scheme 280 R 312 Haskell 314 PHP 339 m4 346 C 406 Fortran 462 Java 476 Java (well, kind of) 718 OCaml 759 F# 1741 sed C++ not qualified for now

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  • Why do people still use Vi and Emacs?

    - by mawg
    This is not a subjective question. I am genuinely looking for techinccal reasons to do so. I will risk offending some folks (not intended as an offence – maybe as a goad) by saying that I have been coding for 30+ years and used to be religously attched to each of them, but as soone as I saw editor-cum-IDE which seemed to offer more, I moved on. Is there any compelling reason, in this day and age, to choose Vi / Emacs over – say- Eclipse for code editing? Even Notepad++ for win-doze users seems to offer more. Just sayin'

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  • Code Golf: Quickly Build List of Keywords from Text, Including # of Instances

    - by Jonathan Sampson
    I've already worked out this solution for myself with PHP, but I'm curious how it could be done differently - better even. The two languages I'm primarily interested in are PHP and Javascript, but I'd be interested in seeing how quickly this could be done in any other major language today as well (mostly C#, Java, etc). Return only words with an occurrence greater than X Return only words with a length greater than Y Ignore common terms like "and, is, the, etc" Feel free to strip punctuation prior to processing (ie. "John's" becomes "John") Return results in a collection/array Extra Credit Keep Quoted Statements together, (ie. "They were 'too good to be true' apparently")Where 'too good to be true' would be the actual statement Extra-Extra Credit Can your script determine words that should be kept together based upon their frequency of being found together? This being done without knowing the words beforehand. Example: "The fruit fly is a great thing when it comes to medical research. Much study has been done on the fruit fly in the past, and has lead to many breakthroughs. In the future, the fruit fly will continue to be studied, but our methods may change." Clearly the word here is "fruit fly," which is easy for us to find. Can your search'n'scrape script determine this too? Source text: http://sampsonresume.com/labs/c.txt Answer Format It would be great to see the results of your code, output, in addition to how long the operation lasted.

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  • Palindrome Golf

    - by Claudiu
    The goal: Any language. The smallest function which will return whether a string is a palindrome. Here is mine in Python: R=lambda s:all(a==b for a,b in zip(s,reversed(s))) 50 characters. The accepted answer will be the current smallest one - this will change as smaller ones are found. Please specify the language your code is in.

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  • Examples of IOC/DI over Singleton

    - by Amitd
    Hi, Just started learning/reading about DI and IOC frameworks. Also I read many articles on SO and internet that say that one should prefer DI/IOC over singleton. Can anyone give/link examples of exactly how DI/IOC eliminates/solves the various issues regarding the Singleton pattern? (hopefully code and explanation for better understanding) Also given a system has already implemented Singleton pattern, how to refactor/implement DI/IOC for the same? (any examples for the same?) (Language/Framework no bars..C# would be helpful) Thanks

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  • Code Golf: Easter Spiral

    - by friol
    What's more appropriate than a Spiral for Easter Code Golf sessions? Well, I guess almost anything. The Challenge The shortest code by character count to display a nice ASCII Spiral made of asterisks ('*'). Input is a single number, R, that will be the x-size of the Spiral. The other dimension (y) is always R-2. The program can assume R to be always odd and = 5. Some examples: Input 7 Output ******* * * * *** * * * * ***** * Input 9 Output ********* * * * ***** * * * * * * *** * * * * * ******* * Input 11 Output *********** * * * ******* * * * * * * * *** * * * * * * * * ***** * * * * * ********* * Code count includes input/output (i.e., full program). Any language is permitted. My easily beatable 303 chars long Python example: import sys; d=int(sys.argv[1]); a=[d*[' '] for i in range(d-2)]; r=[0,-1,0,1]; x=d-1;y=x-2;z=0;pz=d-2;v=2; while d>2: while v>0: while pz>0: a[y][x]='*'; pz-=1; if pz>0: x+=r[z]; y+=r[(z+1)%4]; z=(z+1)%4; pz=d; v-=1; v=2;d-=2;pz=d; for w in a: print ''.join(w); Now, enter the Spiral...

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  • Code Golf: Zigzag pattern scanning

    - by fbrereto
    The Challenge The shortest code by character count that takes a single input integer N (N = 3) and returns an array of indices that when iterated would traverse an NxN matrix according to the JPEG "zigzag" scan pattern. The following is an example traversal over an 8x8 matrix (referenced from here:) Examples (The middle matrix is not part of the input or output, just a representation of the NxN matrix the input represents.) 1 2 3 (Input) 3 --> 4 5 6 --> 1 2 4 7 5 3 6 8 9 (Output) 7 8 9 1 2 3 4 (Input) 4 --> 5 6 7 8 --> 1 2 5 9 6 3 4 7 10 13 14 11 8 12 15 16 (Output) 9 10 11 12 13 14 15 16 Notes: The resulting array's base should be appropriate for your language (e.g., Matlab arrays are 1-based, C++ arrays are 0-based). This is related to this question.

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  • File Fix-it codegolf (GCJ 2010 1B-A)

    - by KirarinSnow
    Last year (2009), the Google Code Jam featured an interesting problem as the first problem in Round 1B: Decision Tree As the problem seemed tailored for Lisp-like languages, we spontaneously had an exciting codegolf here on SO, in which a few languages managed to solve the problem in fewer characters than any Lisp variety, using quite a number of different techniques. This year's Round 1B Problem A (File Fix-it) also seems tailored for a particular family of languages, Unix shell scripts. So continuing the "1B-A tradition" would be appropriate. :p But which language will end up with the shortest code? Let us codegolf and see! Problem description (adapted from official page): You are given T test cases. Each test case contains N lines that list the full path of all directories currently existing on your computer. For example: /home/awesome /home/awesome/wheeeeeee /home/awesome/wheeeeeee/codegolfrocks /home/thecakeisalie Next, you are given M lines that list the full path of directories you would like to create. They are in the same format as the previous examples. You can create a directory using the mkdir command, but you can only do so if the parent directory already exists. For example, to create the directories /pyonpyon/fumufumu/yeahyeah and /pyonpyon/fumufumu/yeahyeahyeah, you would need to use mkdir four times: mkdir /pyonpyon mkdir /pyonpyon/fumufumu mkdir /pyonpyon/fumufumu/yeahyeah mkdir /pyonpyon/fumufumu/yeahyeahyeah For each test case, return the number of times you have to call mkdir to create all the directories you would like to create. Input Input consists of a text file whose first line contains the integer T, the number of test cases. The rest of the file contains the test cases. Each test case begins with a line containing the integers N and M, separated by a space. The next N lines contain the path of each directory currently existing on your computer (not including the root directory /). This is a concatenation of one or more non-empty lowercase alphanumeric strings, each preceded by a single /. The following M lines contain the path of each directory you would like to create. Output For each case, print one line containing Case #X: Y, where X is the case number and Y is the solution. Limits 1 = T = 100. 0 = N = 100. 1 = M = 100. Each path contains at most 100 characters. Every path appears only once in the list of directories already on your computer, or in the list of desired directories. However, a path may appear on both lists, as in example case #3 below. If a directory is in the list of directories already on your computer, its parent directory will also be listed, with the exception of the root directory /. The input file is at most 100,000 bytes long. Example Larger sample test cases may be downloaded here. Input: 3 0 2 /home/sparkle/pyon /home/sparkle/cakes 1 3 /z /z/y /z/x /y/y 2 1 /moo /moo/wheeeee /moo Output: Case #1: 4 Case #2: 4 Case #3: 0 Code Golf Please post your shortest code in any language that solves this problem. Input and output may be handled via stdin and stdout or by other files of your choice. Please include a disclaimer if your code has the potential to modify or delete existing files when executed. Winner will be the shortest solution (by byte count) in a language with an implementation existing prior to the start of Round 1B 2010.

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