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  • Tricky SQL query involving consecutive values

    - by Gabriel
    I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • Creating an excel macro to sum lines with duplicate values

    - by john
    I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • Are there any well known algorithms to detect the presence of names?

    - by Rhubarb
    For example, given a string: "Bob went fishing with his friend Jim Smith." Bob and Jim Smith are both names, but bob and smith are both words. Weren't for them being uppercase, there would be less indication of this outside of our knowledge of the sentence. Without doing grammar analysis, are there any well known algorithms for detecting the presence of names, at least Western names?

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  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

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  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

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  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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  • Run script after switching user account "to the same account"

    - by Peter Sivák
    In Ubuntu, when I click on Switch User Account... and then choose the same account to log in (for example if my name is John Smith, I click on switch user account and then log into the John Smith account again), how can I run a script after that? (I know, that I can run a script after "first" login by putting it in /etc/profile file, but this script is not executed again when I choose switch user account and then immediately log in back to the same account.)

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  • GDL Presents: Women Techmakers with JESS3

    GDL Presents: Women Techmakers with JESS3 Join Leslie, COO and Co-founder of JESS3, in conversation with Megan Smith and Betsy Masiello, as they discuss Leslie's experience growing a design business from two employees to a transnational operation. Hosts: Megan Smith - Vice President, Google [x] | Betsy Masiello - Policy Manager Guest: Leslie Bradshaw - President, COO and Co-founder, JESS3 From: GoogleDevelopers Views: 0 3 ratings Time: 01:00:00 More in Science & Technology

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  • Add Your Own Domain to Your WordPress.com Blog

    - by Matthew Guay
    Now that you’ve got a nice blog on WordPress.com, why not get your own domain to brand your site?  Here’s how you can easily register a new domain or move your existing domain to your WordPress site. By default, your free WordPress address is yourblog’sname.wordpress.com.  But whether this is a personal or a company blog, it can be nice to have your own domain to really brand your site and make it your own.  Or, if you already have another website and want to use WordPress as a blog for it, you could even add blog.yoursite.com or any other subdomain. Adding a domain to your WordPress.com is a paid upgrade; registering and mapping a new domain to your account costs $14.97 a year, while mapping a domain you already own to your WordPress blog costs $9.97 a year. Getting Started Login to your blog’s dashboard, click the arrow beside Upgrades in the sidebar, and select Domains. Enter the domain or subdomain you want to add to your site in the text box, and click Add domain to blog.   If you entered a new domain you want to register, WordPress will make sure the domain is available and then present you a registration form to register the domain.  Enter your information, and then click Register Domain.   Or, if you enter a domain that’s already registered, you will see the following prompt. If this domain is a domain you own, you can map it to WordPress.com.  Login to your domain registrar account and switch your nameserver to: NS1.WORDPRESS.COM NS2.WORDPRESS.COM NS3.WORDPRESS.COM Your DNS settings page for your domain may be different, depending on your registrar.  Here’s how our domain settings looked. Alternately, if you’re wanting to map a subdomain, such as blog.yoursite.com to your WordPress blog, create the following CNAME record on your domain register.  You may have to contact your domain registrar’s support to do this.  Substitute your subdomain, domain, and blog name when creating the record. subdomain.yourdomain.com. IN CNAME yourblog.wordpress.com. Once your settings are correct, click Try Again in your WordPress dashboard.  The DNS settings may take a while to update, but once WordPress can tell your DNS settings point to it, you will see the following confirmation screen.  Click Map Domain to add this domain to your WordPress blog. Now you’re ready to pay for your domain mapping or registration.  Depending on your purchase, the information and price shown may be different.  Here we’re mapping a domain we already have registered, so it costs $9.97.  Select your method of payment, enter your payment information or signin with your Paypal account, and continue as usual. Once your purchase is finished, you’ll be returned to the Domains page on WordPress.  Try going to your new domain, and make sure it opens your blog.  If it works, then click the bullet beside the new domain, and click Update Primary Domain.  Now, when people visit your WordPress site, they’ll see your new domain in the address bar.  You can still access your blog from your old yourname.wordpress.com address, but it will redirect to you new domain. Conclusion Having a personalized domain is a great way to make your blog more professional, while still taking advantage of the ease of use that WordPress.com offers.  And, if you have your own domain, you can easily move to your site traffic to a different hosting provider in the future if you need to.  The process is slightly complicated, but for $15/year we found this one of the best upgrades you could do to your WordPress.com blog. If you want to see an example of a site created with Wordpress, check out Matthew’s tech site techinch.com. And, if you’re just getting started with WordPress, check out our series on how to Start your WordPress.com blog, Personalize it, and Easily Post Content to it from anywhere. Similar Articles Productive Geek Tips Add Social Bookmarking (Digg This!) Links to your Wordpress BlogHow-To Geek SoftwareHow To Start Your Own Professional Blog with WordPressDisable Logon to Windows Computers When Not Connected to a DomainMake a Backup Copy of your Production Wordpress Blog on Ubuntu TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Use ILovePDF To Split and Merge PDF Files TimeToMeet is a Simple Online Meeting Planning Tool Easily Create More Bookmark Toolbars in Firefox Filevo is a Cool File Hosting & Sharing Site Get a free copy of WinUtilities Pro 2010 World Cup Schedule

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  • Fastest light-weight image viewer over forwarded x11 session (linux)

    - by Matthew
    I have a slow network connection over which I'm forwarding x11 over ssh. I want to view images on the remote host (Ubuntu) quickly and efficiently. I'm looking for an image viewer that will take into account the image viewer window's resolution and downsize the image before sending it over the network, instead of sending the full size image. The images I want to view will be around 5MB and I only need to be able to browse through tiny thumbnails of the images to identify the image I'm looking for. It is not necessary to be able to see more than one image at a time. Highest speed over slow network connection is the priority. Thanks! Matthew EDIT: It's possible that the way x11 forwarding works, only the image at the display resolution will be transferred anyway. If that's true, please confirm and the question still stands for which image viewer will be the fastest over a slow connection

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  • How to count the most recent value based on multiple criteria?

    - by Andrew
    I keep a log of phone calls like the following where the F column is LVM = Left Voice Mail, U = Unsuccessful, S = Successful. A1 1 B1 Smith C1 John D1 11/21/2012 E1 8:00 AM F1 LVM A2 2 B2 Smith C2 John D2 11/22/2012 E1 8:15 AM F2 U A3 3 B3 Harvey C3 Luke D3 11/22/2012 E1 8:30 AM F3 S A4 4 B4 Smith C4 John D4 11/22/2012 E1 9:00 AM F4 S A5 5 B5 Smith C5 John D5 11/23/2012 E5 8:00 AM F5 LVM This is a small sample. I actually have over 700 entries. In my line of work, it is important to know how many unsuccessful (LVM or U) calls I have made since the last Successful one (S). Since values in the F column can repeat, I need to take into consideration both the B and C column. Also, since I can make a successful call with a client and then be trying to contact them again, I need to be able to count from the last successful call. My G column is completely open which is where I would like to put a running total for each client (G5 would = 1 ideally while G4 = 0, G3 = 0, G2 = 2, G1 = 1 but I want these values calculated automatically so that I do not have scroll through 700 names).

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  • gnu screen - mouse does not work in nested screen session

    - by Matthew
    I started a screen session inside another screen session, both on my local machine. This is using cygwin, but I don't think it matters. I have tried via ssh to a real unix machine but the behaviour is the same. Mouse works great in the first screen session, I'm able to open vim with :set mouse=a and I can click to move the cursor or switch tabs, and the mouse wheel scrolls. But in the nested session it does not work, mouse is only useful for selecting terminal text that gets put in the clipboard, but is not able to interact with vim. I want this to work because I usually work with a local screen session, then ssh to a remote server and have a remote screen session running too (hence the nesting) and I like to scroll swiftly in vim by using the mouse wheel. Can anyone tell me why the mouse works in the first layer of screen but not in the second, nested screen session, and how I can make it work? Thanks in advance, Matthew

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  • MS Word 2010: Hide citation title when 2 publications by same first author from different years are in one citation block

    - by srunni
    I'm trying to hide the display of the titles for two publications by the same first author from different years that are in the same citation block. By default, the title is shown in citations when there are two publications by the same author in a given document. The easiest way to get around this is to right click on the citation, click "Edit Citation", and then suppress the title. However, the issue with this is that if there are 2 citations in 1 citation block (i.e., "(Smith, J., et al. 2010, Smith, J., et al. 2011)" rather than "(Smith, J., et al. 2010) (Smith, J., et al. 2011)"), then using that suppress option only suppresses the title for the first citation (in this case, the 2010 publication). OTOH, if I try to initially insert the publications in separate citation blocks, I can suppress the title in both citations, but I can't cut and paste one into the other's citation block. I can click "Cut" and the citation that was just cut disappears, but the "Paste" option is not available when my cursor is in the second citation block. Any ideas? Thanks!

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  • How do I correctly set up Application Request Routing in IIS7 to route SSL requests?

    - by Matthew Belk
    I have a 3-node web farm being managed by IIS7 and Application Request Routing. I have a folder hierarchy in my web app that needs to be secured via SSL. What is the best practice for getting ARR to correctly route these SSL requests? I have installed the same certificate on all web farm servers and the server running ARR. I have tried enabling and disabling the SSL Off-loading feature Thanks, Matthew

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  • Wait for function to finish before starting again.

    - by Matthew Brown
    Good Morning, I am trying to call the same function everytime the user presses a button. Here is what happens at the moment.. User clicks button - Calls function - function takes 1000ms+ to finish (due to animation with jQuery and AJAX calls) What I want to happen is every time the user presses the button it adds the function to the queue, waits for the previous call to finish, and then starts.. Is this possible? Sorry if my explanation is a bit confusing.. Thanks Matthew

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  • How to convert an object to the serialized syntax for data in jquery.ajax function?

    - by Matthew
    I have an object that I want to send with my jquery.ajax function but I can't find anything that will convert it to the serialized format I need. $.ajax({ type: 'post', url: 'www.example.com', data: MyObject, success: function(data) { $('.data').html(data) } }) MyObject = [ { "UserId": "2", "UserLevel": "5", "FirstName": "Matthew" }, { "UserId": "4", "UserLevel": "5", "FirstName": "Craig" } ]

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  • To ref or not to ref

    - by nmarun
    So the question is what is the point of passing a reference type along with the ref keyword? I have an Employee class as below: 1: public class Employee 2: { 3: public string FirstName { get; set; } 4: public string LastName { get; set; } 5:  6: public override string ToString() 7: { 8: return string.Format("{0}-{1}", FirstName, LastName); 9: } 10: } In my calling class, I say: 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: }   After having a look at the code, you’ll probably say, Well, an instance of a class gets passed as a reference, so any changes to the instance inside the CallSomeMethod, actually modifies the original object. Hence the output will be ‘John-Doe’ on the first call and ‘Smith-Doe’ on the second. And you’re right: So the question is what’s the use of passing this Employee parameter as a ref? 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: } The output is still the same: Ok, so is there really a need to pass a reference type using the ref keyword? I’ll remove the ‘ref’ keyword and make one more change to the CallSomeMethod method. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } In line 17 you’ll see I’ve ‘new’d up the incoming Employee parameter and then set its properties to new values. The output tells me that the original instance of the Employee class does not change. Huh? But an instance of a class gets passed by reference, so why did the values not change on the original instance or how do I keep the two instances in-sync all the times? Aah, now here’s the answer. In order to keep the objects in sync, you pass them using the ‘ref’ keyword. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } Viola! Now, to prove it beyond doubt, I said, let me try with another reference type: string. 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(ref name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(ref string name) 12: { 13: name = "def"; 14: } 15: } The output was as expected, first ‘abc’ and then ‘def’ - proves the 'ref' keyword works here as well. Now, what if I remove the ‘ref’ keyword? The output should still be the same as the above right, since string is a reference type? 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(string name) 12: { 13: name = "def"; 14: } 15: } Wrong, the output shows ‘abc’ printed twice. Wait a minute… now how could this be? This is because string is an immutable type. This means that any time you modify an instance of string, new memory address is allocated to the instance. The effect is similar to ‘new’ing up the Employee instance inside the CallSomeMethod in the absence of the ‘ref’ keyword. Verdict: ref key came to the rescue and saved the planet… again!

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  • It's Not TV- It's OTN: Top 10 Videos on the OTN YouTube Channel

    - by Bob Rhubart
    It's been a while since we checked in on what people are watching on the Oracle Technology Network YouTube Channel. Here are the Top 10 video for the last 30 days. Tom Kyte: Keeping Up with the Latest in Database Technology Tom Kyte expands on his keynote presentation at the Great Lakes Oracle Conference with tips for developers, DBAs and others who want to make sure they are prepared to work with the latest database technologies. That Jeff Smith: Oracle SQL Developer Oracle SQL Developer product manager Jeff Smith (yeah, that Jeff Smith) talks about his presentations at the Great Lakes Oracle Conference and shares his reaction to keynote speaker C.J. Date's claim that "SQL dropped the ball." Gwen Shapira: Hadoop and Oracle Database Oracle ACE Director Gwen Shapira @gwenshap talks about the fit between Hadoop and Oracle Database and dives into the details of why Oracle Loader for Hadoop is 5x faster. Kai Yu: Virtualization and Cloud Oracle ACE Director Kai Yu talks about the questions he is most frequently asked when he does presentations on cloud computing and virtualization. Mark Sewtz: APEX 4.2 Mobile App Development Application Express developer Marc Sewtz demos the new features he built into APEX4.2 to support Mobile App Development. Jeremy Schneider: RAC Attack Oracle ACE Jeremy Schneider @jer_s describes what you can expect when you come to a RAC (Real Application Cluster) Attack. Frits Hoogland: Exadata Under the Hood Oracle ACE Director Frits Hoogland (@fritshoogland) talks about the secret sauce under Exadata's hood. David Peake: APEX 4.2 New Features David Peake, PM for Oracle Application Express, gives a quick overview of some of the new APEX features. Greg Marsden: Hugepages = Huge Performance on Linux Greg Marsden of Oracle's Linux Kernel Engineering Team talks about some common customer performance questions and making the most of Oracle Linux 6 and Transparent HugePages. John Hurley: NEOOUG and GLOC 2013 Northeast Ohio Oracle User Group president John Hurley talks about the background and success of the 2013 Great Lakes Oracle Conference.

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  • Aggregating Excel cell contents that match a label [migrated]

    - by Josh
    I'm sure this isn't a terribly difficult thing, but it's not the type of question that easily lends itself to internet searches. I've been assigned a project for work involving a complex spreadsheet. I've done the usual =SUM and other basic Excel formulas, and I've got enough coding background that I'm able to at least fudge my way through VBA, but I'm not certain how to proceed with one part of the task. Simple version: On Sheet 1 I have a list of people (one on each row, person's name in column A), on sheet 2 I have a list of groups (one on each row, group name in column A). Each name in Sheet 1 has its own row, and I have a "Data Validation" dropdown menu where you choose the group each person belongs to. That dropdown is sourced from Sheet 2, where each group has a row. So essentially the data validation source for Sheet 1's "Group" column is just "=Sheet2!$a1:a100" or whatever. The problem is this: I want each group row in Sheet 2 to have a formula which results in a list of all the users which have been assigned to that group on Sheet 1. What I mean is something the equivalent of "select * from PeopleTab where GROUP = ThisGroup". The resulting cell would just stick the names together like "Bob Smith, Joe Jones, Sally Sanderson" I've been Googling for hours but I can't think of a way to phrase my search query to get the results I want. Here's an example of desired result (Dash-delimited. Can't find a way to make it look nice, table tags don't seem to work here): (Sheet 1) Bob Smith - Group 1 (selected from dropdown) Joe Jones - Group 2 (selected from dropdown) Sally Sanderson - Group 1 (selected from dropdown) (Sheet 2) Group 1 - Bob Smith, Sally Sanderson (result of formula) Group 2 - Joe Jones (result of formula) What formula (or even what function) do I use on that second column of sheet 2 to make a flat list out of the members of that group?

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  • Junit test bluej [closed]

    - by user1721929
    Can someone make a junit test of this? public class PersonName { int NumberNames(String wholename) { // store the name passed in to the method String testname=wholename; // initialize number of names found int numnames=0; // on each iteration remove one name while(testname.length()>numnames) { // take the "white space" from the beginning and end testname = testname.trim(); // determine the position of the first blank // .. end of the first word int posBlank= testname.indexOf(' '); // cut off word /** * it continues to the stop sign because that is where you commanded it to end */ testname=testname.substring(posBlank+1,testname.length()); // System.out.println(numnames); // System.out.println(testname); numnames++; System.out.println(testname); } return numnames; } public static void main(String args[]) { PersonName One= new PersonName(); System.out.println(One.NumberNames("Bobby")); System.out.println(One.NumberNames("Bobby Smith")); System.out.println(One.NumberNames("Bobby L. Smith")); System.out.println(One.NumberNames(" Bobby Paul Smith Jr. ")); } }

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  • Syncing contacts to iOS device with Exchange

    - by flackend
    I set up a Microsoft Exchange account on my iOS device to sync my Gmail contacts. But Microsoft Exchange is ignoring phone numbers that are labeled as 'iPhone' or 'main'. For example, John Smith: On Mac and Gmail: John Smith main: 123-334-1212 home: 123-330-1002 work: 123-330-8211 iPhone: 123-778-5556 On iOS device (via Exchange sync): John Smith home: 123-330-1002 work: 123-330-8211 I'd like to sync my contacts from my Mac to iCloud and Gmail, but you can't do both: Is there a solution to sync iOS and Gmail contacts without using Exchange? Thanks for any help!

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