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  • System.Web.Services.Protocols.SoapHttpClientProtocol.ReadResponse request failed with HTTP status 40

    - by John Galt
    I am trying to make some enhancements to a production web app. After quite a bit of unit testing on my WinXP IIS 5.1 development machine, everything works on my localhost so I used the Visual Studio 2008 PUBLISH dialog on my Dev PC to push the following projects to a staging server: the primary web app the "primary" webservice (the home page tries to invoke this WS) a "secondary" webservice (not yet a problem because home page does not invoke this WS) I get the following when I try to browse to the home page of the web app typing this into my browser: link text Server Error in '/zVersion2' Application. The request failed with HTTP status 404: Not Found. Description: An unhandled exception occurred during the execution of the current web request.Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Net.WebException: The request failed with HTTP status 404: Not Found. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [WebException: The request failed with HTTP status 404: Not Found.] System.Web.Services.Protocols.SoapHttpClientProtocol.ReadResponse(SoapClientMessage message, WebResponse response, Stream responseStream, Boolean asyncCall) +431289 System.Web.Services.Protocols.SoapHttpClientProtocol.Invoke(String methodName, Object[] parameters) +204 ProxyZipeeeService.WSZipeee.Zipeee.GetMessageByType(Int32 iMsgType) in C:\Documents and Settings\johna\My Documents\Visual Studio 2008\Projects\ProxyZipeeeService\ProxyZipeeeService\Web References\WSZipeee\Reference.vb:2168 Zipeee.frmZipeee.LoadMessage() in C:\Documents and Settings\johna\My Documents\Visual Studio 2008\Projects\Zipeee\frmZipeee.aspx.vb:43 Zipeee.frmZipeee.Page_Load(Object sender, EventArgs e) in C:\Documents and Settings\johna\My Documents\Visual Studio 2008\Projects\Zipeee\frmZipeee.aspx.vb:33 System.Web.UI.Control.OnLoad(EventArgs e) +99 System.Web.UI.Control.LoadRecursive() +50 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +627 Version Information: Microsoft .NET Framework Version:2.0.50727.3607; ASP.NET Version:2.0.50727.3082 Here is a bit of the corresponding source code: Public wsZipeee As New ProxyZipeeeService.WSZipeee.Zipeee Dim dsStandardMsg As DataSet Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load If Not Page.IsPostBack Then LoadMessage() End If End Sub Private Sub LoadMessage() Dim iCnt As Integer Dim iValue As Integer dsStandardMsg = wsZipeee.GetMessageByType(BizConstants.MsgType.Standard) End Sub I suspect I may have configured things incorrectly on the staging server. The staging server is Win Server 2003 ServicePack 2 running IIS 6.0. When I published the primary site and the 2 webservices on the staging server called MOJITO I created the physical directories for each on the D drive. Then using INETMGR, I configured the following virtual directories: zVersion2 zVersion2wsSQL zVersion2wsEmergency All of the above are configured to use a new application pool I setup and named zVersion2aspNet20. The default web site for this machine MOJITO is configured to use ASP.NET 1.1 and the IP address is set to (All Unassigned). The production versions of the latter 2 webservices run on the MOJITO machine (named ZipeeeService and EmergencyService respectively). Can my staging versions of the above webservices (named zVersion2wsSQL and zVersion2wsEmergency respectively) co-exist on the same web server with the same IP address? Please note that when I test the zVersion2wsSQL webservice independently (from INETMGR right-mouse and click Browse) it works as expected (i.e. presenting all the methods of the webservice) like this snippet: GetMessageByType MessageName="Get_x0020_Message_x0020_By_x0020_Type" I can test this webmethod by clicking on it and it presents the Test dialog (because it takes a simple datatype and I am invoking it on localhost (i.e. MOJITO): **Get Message By Type** **Test** To test the operation using the HTTP POST protocol, click the 'Invoke' button. Parameter Value iMsgType: _______ [INVOKE button] SOAP 1.1 ....etc. I fear I may have rambled with too much information so I will stop but I hope someone can help me as I cannot understand why this request results in a "not found". Thanks.

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  • JQuery ajax request returns error and status 0

    - by Kucebe
    I use this pseudo-class to make ajax request to server: function RequestManager(url, params, success, error){ //save this ajax configuration this._ajaxCall = null; this._url= url; this._type = params.type; this._timer = params.timer || 0; this._success = function(){ alert("ok"); }; this._error = function(){ alert("ko"); }; } RequestManager.prototype = { require : function(tag){//here there will be a tag object in array format if(this.timer>0){ //wait this.timer } if(this.ajaxCall != null ){ this.ajaxCall.abort(); this.ajaxCall = null; } var self = this; this.ajaxCall = $.ajax({ url: this._url, type: this._type, data: tag, success: function(xmlResponse){ var responseArray = []; var response = _extractElements(xmlResponse, arrayResponse); self._success(response); }, error: self._error, complete : function(xhr, statusText){ alert(xhr.status); return null; } }); } When i instantiate a new object, and i use it to load a request, it always return to me error, and status code is 0. Server correctly generates an xml document. Why i can't get a correct 200 code back?

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  • asp.net - pdf printing status

    - by BhejaFry
    Hi folks, I need to print PDF's generated in an asp.net application using crystal reports. Upon printing, a database table gets updated with the status 'printed'. How do we handle situation where let's say, the printer runs out of paper? I know this is on client-side, so what's the right way to handle issues like this? TIA

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  • Android GPS status

    - by nr1
    Hi, how can i check the current status of the GPS receiver? I already checked the LocationListener onStatusChanged method but somehow it seems that is not working, or just the wrong possibility. So basically i just need to know if the gps icon at the top of the screen is blinking (no actual fix) or solid (fix is available) thx!

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  • Failed to load resource: the server responded with a status of 406 (Not Acceptable)

    - by skip
    I am trying to send json data and get back json data as well. I've <annotation-driven /> configured in my servlet-context.xml and I am using Spring framework version 3.1.0.RELEASE. When I send the request the browser tells me that it is not happy with the data returned from the server and gives me 406 error. And when I see the response from the server I see the whole 406 page returned by tomcat 6 server. I have got following in my pom for Jackson/Jackson processor: <!-- Jackson --> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-core-asl</artifactId> <version>1.9.4</version> </dependency> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-mapper-asl</artifactId> <version>1.9.4</version> </dependency> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-xc</artifactId> <version>1.9.4</version> </dependency> <!-- Jackson JSON Processor --> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-mapper-asl</artifactId> <version>1.8.1</version> </dependency> Following is the jquery code I am using to send the json request: $(function(){$(".sutmit-button").click(function(){ var dataString=$("#app-form").serialize(); $.ajax({ type:"POST", url:"apply.json", data:dataString, success:function(data, textStatus, jqXHR){ console.log(jqXHR.status); console.log(data); $('.postcontent').html("<div id='message'></div>"); $('#message').html("<h3>Request Submitted</h3>").append("<p>Thank you for submiting your request.</p>").hide().fadeIn(1500,function(){$('#message');}); }, error:function(jqXHR, textStatus, errorThrown) { console.log(jqXHR.status); $('.postcontent').html("<div id='message'></div>"); $('#message').html("<h3>Request failed.</h3>").hide().fadeIn(1500,function(){$('#message');}); }, dataType: "json" }); return false;});}); Following is the Controller that is handling the request: @RequestMapping(method = RequestMethod.POST, value="apply", headers="Accept=application/json") public @ResponseBody Application processFranchiseeApplicationForm(HttpServletRequest request) { //... Application application = new Application(...); //... logger.debug(application); return application; } I am not able to figure out the reason why I might be getting this error. Could someone help me understand why am I getting the given error? Thanks.

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  • Apache - Reverse Proxy and HTTP 302 status messsage

    - by Rob
    My team is trying to setup an Apache reverse proxy from a customer's site into one of our web applications. http://www.example.com/app1/some-path maps to http://internal1.example.com/some-path Inside our application we use struts and have redirect = true set on certain actions in order to provide certain functionality. The 302 status messages from these re-directs cause the user to break out of the proxy resulting in an error page for the end user. HTTP/1.1 302 Found Location: http://internal.example.com/some-path/redirect Is there any way to setup the reverse proxy in apache so that the redirects work correctly? http://www.example.com/app1/some-path/redirect

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  • Proper use of HTTP status codes in a "validation" server

    - by Romulo A. Ceccon
    Among the data my application sends to a third-party SOA server are complex XMLs. The server owner does provide the XML schemas (.xsd) and, since the server rejects invalid XMLs with a meaningless message, I need to validate them locally before sending. I could use a stand-alone XML schema validator but they are slow, mainly because of the time required to parse the schema files. So I wrote my own schema validator (in Java, if that matters) in the form of an HTTP Server which caches the already parsed schemas. The problem is: many things can go wrong in the course of the validation process. Other than unexpected exceptions and successful validation: the server may not find the schema file specified the file specified may not be a valid schema file the XML is invalid against the schema file Since it's an HTTP Server I'd like to provide the client with meaningful status codes. Should the server answer with a 400 error (Bad request) for all the above cases? Or they have nothing to do with HTTP and it should answer 200 with a message in the body? Any other suggestion? Update: the main application is written in Ruby, which doesn't have a good xml schema validation library, so a separate validation server is not over-engineering.

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  • Model def in View State

    - by tinzawtun
    In my ruby on rails project in model, I have some of definition. class PlaySport < ActiveRecord::Base belongs_to :user belongs_to :sport def self.getLevel end def self.check_play_sport(cuser_id,sport_id) end def current_playing_sport end def all_played_sports end end I catch for this relation like this current_user.play_sports.current_playing_sport But I get the undefined method error "current_playing_sports" What is wrong

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  • Facebook: Hide Your Status Updates From Your Boss/Ex or Any Specific Friend

    - by Gopinath
    Sometime we want to hide our status updates from specific people who are already accepted as Friends in Facebook. Do you wonder why we need to accept someone as friend and then hide status updates from them? Well, may be you have to accept a friend request from your boss, but certainly love to hide status updates as well as other Facebook activities from him. Something similar goes with few annoying friends whom you cant’ de-friend but like to hide your updates. Thanks to Facebook for providing fine grain privacy options on controlling what we want to share and with whom we want to share. It’s very easy to block one or more specific friends from seeing your status updates. Here are the step by step instructions: 1. Login to Facebook and go to Privacy Settings Page. It shows a page something similar to what is shown in the below image. 2. Click on “Customize settings” link 3. Expand the privacy options available in the section Things I Share -> Posts by me. Choose Customise from the list of available options   4. Type the list of unwanted friend’s names in to input box of the section "Hide this from”. Here is a screen grab of couple of my friends whom I added for writing this post 5. Click the Save Settings button. That’s all. Facebook will ensure that these people will not see your status updates on their news feed. Enjoyed the Facebook Tip? Join Tech Dreams on Facebook to read all our blog posts on your Facebook’s news feed. Join us on Facebook to read all our stories right inside your Facebook news feed.

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  • Clementine current song as empathy status

    - by pahnin
    Any plugin available to set Clementine's current playing song as empathy status [update] I've tried it and was not succesful, here is my problem http://stackoverflow.com/questions/7671763/error-setting-status-to-empathy-with-dbus/7760194#7760194 but I've figured out that it is not possible to set status of empathy through dbus http://telepathy.freedesktop.org/spec/Connection_Interface_Simple_Presence.html#Method:SetPresence regards [update]

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  • How to change Port 27000 from filtered to open status

    - by Nadarajah Ranjan
    In my ubuntu box I am running flexlm licensing software on port 27000 and I am able to pull the license from the this port to run the simulation software locally. I am also trying to run the same software in another Linux machine (opensuse) by using the flexlm license from the Ubuntu box. However, my opensuse box is unable to communicate with port 27000 in my Ubuntu box. I have turned off the firewall on the Ubuntu box, played around with iptables and when I do a nmap from my opensuse box to Ubuntu box the message I get is that port 27000 is on filtered status. My understanding is that filtered status does not allow the opensuse box to communicate with Ubuntu. My question is how to change port 27000 from filtered status to open status? Hope someone can help me out. Thank you.

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  • Need to Determine the Engine Status?

    - by user702295
    If you need to establish the status of the engine, begin with this SQL: select status, engine, engine_version,fore_column_name from dm.forecast_history The status of an engine run is stored in the FORECAST_HISTORY table, in the “status” field.  We can also find in that table the FORE_COLUMN_NAME field. This field includes the name of the column in SALES_DATA in which the relevant forecast is stored. Here are the possible statuses: -1, -2 : The engine failed in the initialization phase.  Which means, before the engine manager created the engines.  0 : The engine stopped in the optimization phase.  Which means, after the engines were created.  1: The engine finished the run successfully.  2: Forecast was never calculated for the relevant column that is mentioned in FORE_COLUMN_NAME.  

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  • Showing "Failed" for a SharePoint 2010 Timer Job Status

    - by Damon
    I have been working with a bunch of custom timer jobs for last month.  Basically, I'm processing a bunch of SharePoint items from the timer job and since I don't want the job failing because of an error on one item, so I'm handing errors on an item-by-item basis and just continuing on with the next item.  The net result of this, I soon found, is that my timer job actually says it ran successfully even if every single item fails.  So I figured I would just set the "Failed" status on the timer job is anything went wrong so an administrator could see that not all was well. However, I quickly found that there is no way to set a timer job status.  If you want the status to show up as "Failed" then the only way to do it is to throw an exception.  In my case, I just used a flag to store whether or not an error had occurred, and if so the the timer job throws a an exception just before existing to let the status display correctly.

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  • error: cannot fork() for status: Resource temporarily unavailable (git)

    - by Elnaz Shahmehr
    when I want to do something: add , remove, pull , push in github, I just have this error in my terminal Thanks in advance! selnaz:iOS-Tidinfo Lnaz$ git add . error: cannot fork() for status: Resource temporarily unavailable fatal: Could not run git status --porcelain fatal: git status --porcelain failed fatal: git status --porcelain failed fatal: git status --porcelain failed fatal: git status --porcelain failed fatal: git status --porcelain failed fatal: git status --porcelain failed Edit: selnaz:iOS-Tidinfo Lnaz$ ulimit -a core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited file size (blocks, -f) unlimited max locked memory (kbytes, -l) unlimited max memory size (kbytes, -m) unlimited open files (-n) 256 pipe size (512 bytes, -p) 1 stack size (kbytes, -s) 8192 cpu time (seconds, -t) unlimited max user processes (-u) 709 virtual memory (kbytes, -v) unlimited Edit2 selnaz:iOS-Tidinfo Lnaz$ ps xfu | wc -l ps: illegal option -- f usage: ps [-AaCcEefhjlMmrSTvwXx] [-O fmt | -o fmt] [-G gid[,gid...]] [-u] [-p pid[,pid...]] [-t tty[,tty...]] [-U user[,user...]] ps [-L] 0

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  • Apache Server Status page in port 8443

    - by batman
    I'm very new to apache. I tried to enable the server status page of apache. I added the status.conf and status.load to mods-enabled directory. I changed the config of apache2.conf to include all mods-enabled directory. This is the config of staus.conf: <IfModule mod_status.c> # # Allow server status reports generated by mod_status, # with the URL of http://servername/server-status # Uncomment and change the "192.0.2.0/24" to allow access from other hosts. # <Location /server-status> SetHandler server-status Order deny,allow Deny from all Allow from 127.0.0.1 ::1 # Allow from 192.0.2.0/24 </Location> # Keep track of extended status information for each request ExtendedStatus On # Determine if mod_status displays the first 63 characters of a request or # the last 63, assuming the request itself is greater than 63 chars. # Default: Off #SeeRequestTail On <IfModule mod_proxy.c> # Show Proxy LoadBalancer status in mod_status ProxyStatus On </IfModule> </IfModule> The default settings. I restarted my server. I'm redirecting all ports to 8443. Which in turn turns my requests to localhost:8443/server-status. Which does throw an 404 error. Are there any way to get around this? Thanks in advance.

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  • Zend Framework REST service HTTP status code problem

    - by Baversjo
    I'm trying to create a REST service in zend framework. I'm using zend server. Here's my code: class ArticleController extends Zend_Rest_Controller { public function postAction() { //Create the acticle and return it $data = array("foo" => 0, "boo" => 11); $this->getResponse()->setHttpResponseCode(201); $this->_helper->json($data); } The HTTP response returns the appropriate headers and JSON data but under the JSON data there's an apache error document. The only way I can think of to remove the appended error document is to add the following in my httpd.conf file: ErrorDocument 201 " " But what's the "corrent" way of doing this?

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  • How return 304 status with FileResult in ASP.NET MVC RC1

    - by Maysam
    As you may know we have got a new ActionResult called FileResult in RC1 version of ASP.NET MVC. Using that, your action methods can return image to browser dynamically. Something like this: public ActionResult DisplayPhoto(int id) { Photo photo = GetPhotoFromDatabase(id); return File(photo.Content, photo.ContentType); } In the HTML code, we can use something like this: <img src="http://mysite.com/controller/DisplayPhoto/657"> Since the image is returned dynamically, we need a way to cache the returned stream so that we don't need to read the image again from database. I guess we can do it with something like this, I'm not sure: Response.StatusCode = 304; This tells the browser that you already have the image in your cache. I just don't know what to return in my action method after setting StatusCode to 304. Should I return null or something?

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  • How can I get 'git status' to always use short format?

    - by Adam Lindberg
    I'd like git status to always use the short format: $ git status --short M src/meck.erl M test/meck_tests.erl ?? erl_crash.dump ?? meck_test_module.coverdata There does not seem to exist a configuration option for this, and git config --global alias.status "status --short" does not work. I haven't managed to create and alias in zsh either. How can I make git status to use the short format by default.

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  • Pretty automatically updating lighttpd server status

    - by Marko
    I am trying to use your modified lighttpd server-status. server-status mod is enabled and running, I am geting lighttpd status but I can not use yours becouse I can not use port 80 again ($SERVER["socket"] == "192.168......:80" { status.status-url = "/server-status" server.document-root = "/var/www/status" mimetype.assign = ( ".html" = "text/html" ) index-file.names = ( "pretty-status.html" ) } this gives me an error on lighty restart saying port (= already in use. Any help?

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