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  • How to test jQuery Ajax with php?

    - by vladv
    I tried to just send some information to a php file using Jquery Ajax. I wanted to send some info to the php file every time a click is made. <script> $(document).ready(function() { $('#checkbox').click(function() { $.ajax({type : "POST", url : "test.php", data : "ffs=somedata&ffs2=somedata2", succes : function() { alert("something"); } }); }); }); </script> <body> <input type = "checkbox" name = "checkbox" id = "checkbox"> </body> The php file looks like this: <?php echo $_POST['ffs']; ?> Now, I see the POST going, (using firebug). I get no errors, but nothing happens in the php file. Also success is never reached, so no alert is triggered. What should I do in the php file so that I can trigger success and also see the sent info?

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • How to separate sets of numbers onto separate lines

    - by Fred
    About the script: The script below will create 300 sets of random characters. What is presently happening, is that it creates them but shows them all on one line, in one big chunk. With all the searching and testing I've done to try and achieve this, I have had no success. I would like to know which code and where to put it, so that each SET (300) of 15 characters long, will show and be saved to file. Here is my script: <?php function GetID($x){ $characters = array_merge(range('A','Z'),range('a','z'),range(2,9)); shuffle($characters); for($x=0;$x<=299;$x++){ } for (; strlen($ReqID)<$x;){ $ReqID .= $characters[mt_rand(0, count($characters))]; } return $ReqID; } $ReqID .= GetID(5); $ReqID .= "-"; $ReqID .= GetID(5); $ReqID .= "-"; $ReqID .= GetID(5); echo $ReqID; $fh = fopen("file.txt","a+"); fwrite($fh, ("$ReqID")."\n"); fclose($fh); ?>

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  • Creating PHP strings using other variables...works manually, can't figure out how automatically

    - by Matt
    Hello, I'm trying to get a variable to be formed automatically using data pulled from a mysql database. I know the data is being pulled from the database in some form resembling its original form, but that data does not act the same as data that is manually typed and assigned to a string. For example, if a cell in a mysql table says... I said "goodbye" before I left. She also said "goodbye." ...and I manually copy/paste it and add the necessary escapes... $string1 = " I said \"goodbye\" before I left. She also said \"goodbye.\" "; ...that does not equal... $string1 = $mysqlResultArray['specificCellWithQuoteShownAbove'] Interestingly, if I echo both versions of $string1 and view the output, they appear to be exactly the same. But they do not function the same when put through various functions I've created. The functions only work if I do the manual copy/paste method--which is not what I want, obviously. I'm not sure if it has to do with the line breaks or the escapes--or some combination of the two. But while both strings are superficially the same, they are apparently functionally different and I don't know why. So how can I create $string1 without manually copy/pasting the contents from the mysql entry and instead querying for the data and assigning it to $string1 in such a way that it's exactly functionally equivalent as the manual copy/pasted string?

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  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

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  • Do ORMs normally allow circular relations? If so, how would they handle it?

    - by SeanJA
    I was hacking around trying to make a basic orm that has support for the one => one and one => many relationships. I think I succeeded somewhat, but I am curious about how to handle circular relationships. Say you had something like this: user::hasOne('car'); car::hasMany('wheels'); car::property('type'); wheel::hasOne('car'); You could then do this (theoretically): $u = new user(); echo $u->car->wheels[0]->car->wheels[1]->car->wheels[2]->car->wheels[3]->type; #=> "monster truck" Now, I am not sure why you would want to do this. It seems like it wastes a whole pile of memory and time just to get to something that could have been done in a much shorter way. In my small ORM, I now have 4 copies of the wheel class, and 4 copies of the car class in memory, which causes a problem if I update one of them and save it back to the database, the rest get out of date, and could overwrite the changes that were already made. How do other ORMs handle circular references? Do they even allow it? Do they go back up the tree and create a pointer to one of the parents? DO they let the coder shoot themselves in the foot if they are silly enough to go around in circles?

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  • Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

    - by ipalaus
    I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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  • How do I get Facebook Application Login to work

    - by Javaaaa
    I just started making an application for Facebook, however I ran into problem early on. The first step I want people to do is to give permission to access their profile. All over the web are examples of how to do this with: $user_id = $facebook->require_login(); However, this is the way it works using the Old PHP API. I have downloaded and installed the new one in my application folder and it is not working anymore. My question is (and i really have been searching for an answer for a long time) what is the code to do this with the new API? (and related question: is it better to use the old API, or learn to work with the new one when I am just starting making apps right now) I have this code now; <?php // Awesome Facebook Application // // Name: - // require_once 'facebook-php-sdk/src/facebook.php'; // Create our Application instance. $facebook = new Facebook(array( 'appId' => $app_id, 'secret' => $app_secret, 'cookie' => true )); $loginUrl = $facebook->getLoginUrl(array( 'req_perms' => 'email,user_birthday,publish_stream,sms,status_update,user_location' )); echo "<p>hello, <fb:name uid=\"$user_id\" useyou=\"false\" />!</p>"; ?>

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  • div content margin pushing container

    - by jef2904
    Hi, Im running into an issue that's really baffleing me. I have a container that I want to apply a background to an postion it in the top right of the browser screen. The div inside has a top margin of 4em and this is pushing the container div here is the CSS #container { background: transparent url("../images/house-bg.png") top right no-repeat scroll; } #wrapper { background: #FFF; width: 960px; height: 600px; margin: 4em auto 0; border: 10px solid #C3CF21; -moz-border-radius: 20px; -webkit-border-radius: 20px; border-radius: 20px; -moz-box-shadow: 0 0 25px #444; -webkit-box-shadow: 0 0 25px #444; box-shadow: 0 0 25px #444; } and heres the HTML <div id="container"> <div id="wrapper"> <div id="header"> </div> <div id="main"> </div> </div> <div id="footer"> &copy; Copyright <?php echo date("Y");?> Company, Inc. </div> </div> I want the margin of the wrapper to be inside the container div instead of outside. I've tried multiple display properties and position properties to no avail. The only thing that fixes it is inserting an "&nbsp;" before the start of the #wrapper but theres got to be a CSS fix to this. Thanks in Advanced, Jorge

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  • Why isn't my submit button centered?

    - by William
    For some reason my submit button isn't centered. http://prime.programming-designs.com/test_forum/viewboard.php?board=0 #submitbutton{ margin: auto; border: 1px solid #DBFEF8; background-color: #DBFEF8; color: #000000; margin-top: 5px; width: 100px; height: 20px; } here's the html. <form method=post action=add_thread.php?board=<?php echo''.$board.''; ?>> <div id="formdiv"> <div class="fieldtext1">Name</div> <div class="fieldtext1">Trip</div> <input type="text" name=name size=25 /> <input type="text" name=trip size=25 /> <div class="fieldtext2">Comment</div> <textarea name=post rows="4" cols="70"></textarea> <div class="fieldtext2">Fortune</div> <input type="checkbox" name="fortune" value="fortune" /> </div> <input type=submit value="Submit" id="submitbutton"> </form>

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  • Replacing text with apostrophe text via sed in applescript

    - by bob stinton
    I have an applescript to find and replace a number of strings. I ran in the problem of having a replacement string which contained & some time ago, but could get around it by putting \& in the replacement property list. However an apostrophe seems to be far more annoying. Using a single apostrophe just gets ignored (replacement doesn't contain it), using \' gives a syntax error (Expected “"” but found unknown token.) and using \' gets ignored again. (You can keep doing that btw, even number gets ignored uneven gets syntax error) I tried replacing the apostrophe in the actual sed command with double quotes (sed "s…" instead of sed 's…'), which works in the command line, but gives a syntax error in the script (Expected end of line, etc. but found identifier.) The single quotes mess with the shell, the double quotes with applescript. I also tried '\'' as was suggested here and '"'"' from here. Basic script to get the type of errors: set findList to "Thats.nice" set replaceList to "That's nice" set fileName to "Thats.nice.whatever" set resultFile to do shell script "echo " & fileName & " | sed 's/" & findList & "/" & replaceList & " /'"

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  • Unable to Get values from Web Form to a PHP Class to Display

    - by kentrenholm
    I am having troubles getting the value from my variables submitted via a web form using a PHP class file. Here is my structure of the web page: Order Form Page Process.php Page Book.php Page I can easily get the user data entered (on Order Form Page), process, and display it on the Process.php page. The issue is that I must create a Book class and print the details of the data using the Book class. I have an empty constructor printing out "created" so I know my constructor is being called. I also am able to print the word "title" so I know I can print to the screen by using the Book class. My issue is that I can't get values in my variables in the Book class. Here is my variable declaration: private $title; Here is my printDetails function: public function printDetails () { echo "Title: " . $this->title . "<br />"; } Here is my new instance of the book class: $bookNow = new book; Here are my get and set functions: function __getTitle($title) { return $this->$title; } function __setTitle($title,$value) { $this->$title = $value; } I do have four other variables that I'm looking to display as well. Each of those have their own variable declaration, a line in printDetails, and their own setter and getter. Lastly, I also have a call to the Book class in my process PHP. It looks like this: function __autoload($book) { include $book . '.php'; } $bookNow = new book(); Any help, much appreciated. It must be something so very small (I'm hoping).

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • How to filter what is shown in the for-each loop in XSL

    - by Denoteone
    I thought it would be as easy as tell the for-each to only select top_coach_sales_vw that has "Site" equal to "PB" but when I run the script it does not loop through any of the data in the XML. I am escaping the single quotes because it is part of a php echo. <xsl:for-each select="NewDataSet/top_coach_sales_vw[Site==\'PB\']"> <td><xsl:value-of select="name"/></td> <td><xsl:value-of select="Site"/></td> <td><xsl:value-of select="Status"/></td> </xsl:for-each> XML: <NewDataSet> <top_coach_sales_vw> <name>Mike</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Bill</name> <Site>EL</Site> <State>Talking</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Ted</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> </NewDataSet>

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  • Mimic Coldfusion's debug output in PHP?

    - by TekiusFanatikus
    I'm trying to mimic Coldfusion's debug output in PHP. Here's an example of what it looks like (ie. Execution Time section): I've turned to XDebug. Ideally, the exception stack error output would be what I'd be looking for. However, it only shows up when an exception occurs. I also tried something like (in our CMS-ish app) this (original question here): $content.= "<?php xdebug_start_trace('e:/xdebug/trace');?>"; $content.= "<?php require('".$page['file_'.LG]."'); ?>"; $content.= "<?php xdebug_stop_trace();?>"; ... $content.= "<?php echo readfile('e:/xdebug/trace.xt');?>"; However, I get an insane, browser crashing HTML table dropped at the bottom of page. Not very efficient. My php.ini config: xdebug.trace_format = 2 xdebug.collect_vars = 1 xdebug.collect_params = 4 xdebug.dump_globals = 1 xdebug.dump.SERVER = 'REQUEST_URI' xdebug.show_local_vars = 1 xdebug.show_mem_delta = 1 I'm just wondering if someone has already done something similar?

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  • MySQL SELECT Statement not working when executed from PHP

    - by Andrew K
    Hello all, I have the following piece of code, executing a pretty simple MySQL query: $netnestquery = 'SELECT (`nested`+1) AS `nest` FROM `ipspace6` WHERE `id`<='.$adaddr.' AND `subnet`<='.$postmask.' AND `type`="net" AND `addr` NOT IN(SELECT `id` FROM `ipspace6` WHERE `addr`<'.$adaddr.' AND `type`="broadcast") ORDER BY `id`,`subnet` DESC LIMIT 1'; $netnestresults = mysql_query($netnestquery); $netnestrow = mysql_fetch_array($netnestresults); $nestlvl = $netnestrow['nest']; echo '<br> NESTQ: '.$netnestquery; Now, when I execute this in PHP, I get no results; an empty query. However, when I copy and paste the query echoed by my code (for debug purposes) into the mysql command line, I get a valid result: mysql> SELECT (`nested` + 1) AS `nest` FROM `ipspace6` WHERE `id`<=50552019054038629283648959286463168512 AND `subnet`<=36 AND `type`='net' AND `addr` NOT IN (SELECT `id` FROM `ipspace6` WHERE `addr`<50552019054038629283648959286463168512 AND `type`='broadcast') ORDER BY `id`,`subnet` DESC LIMIT 1; +------+ | nest | +------+ | 1 | +------+ 1 row in set (0.00 sec) Can anybody tell me what I'm doing wrong? I can't put quotes around my variables, as then MySQL will try to evaluate the variable as a string, when it is, in fact, a very large decimal. I think I might just be making a stupid mistake somewhere, but I can't tell where.

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  • PHP Array saved to Text file

    - by coffeemonitor
    I've saved a response from an outside server to a text file, so I don't need to keep running connection requests. Instead, perhaps I can use the text file for my manipulation purposes, until I'm read for re-connecting again. (also, my connection requests are limited to this outside server) Here is what I've saved to a text file: records.txt Array ( [0] => stdClass Object ( [id] => 552 [date_created] => 2012-02-23 10:30:56 [date_modified] => 2012-03-09 18:55:26 [date_deleted] => 2012-03-09 18:55:26 [first_name] => Test [middle_name] => [last_name] => Test [home_phone] => (123) 123-1234 [email] => [email protected] ) [1] => stdClass Object ( [id] => 553 [date_created] => 2012-02-23 10:30:56 [date_modified] => 2012-03-09 18:55:26 [date_deleted] => 2012-03-09 18:55:26 [first_name] => Test [middle_name] => [last_name] => Test [home_phone] => (325) 558-1234 [email] => [email protected] ) ) There's actually more in the Array, but I'm sure 2 are fine. Since this is a text file, and I want to pretend this is the actual outside server (sending me the same info), how do I make it a real array again? I know I need to open the file first: <?php $fp = fopen('records.txt', "r"); // open the file $theData = fread($fh, filesize('records.txt')); fclose($fh); echo $theData; ?> So far $theData is a string value. Is there a way to convert it back to the Array it originally came in as?

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  • Can anyone get app-engine plugin working with Grails on mac os x?

    - by tim
    I have been trying for 4 days to get app-engine and grails working together on my mac to no avail. I am using latest groovy/grails and appengine sdk versions. Im following the app-engine plugin step by step on the grails site.. http://grails.org/plugin/app-engine Groovy Version: 1.7.1 JVM: 1.5.0_22 Grails 1.3.0.RC1 echo $APPENGINE_HOME reveals /Users/markstim/appengine-java-sdk-1.3.2 I perform the following steps 1. grails create-app myapp 2. cd myapp; grails list-plugins reveals hibernate 1.3.0.RC1 -- Hibernate for Grails tomcat 1.3.0.RC1 -- Apache Tomcat plugin for Grails add the following line to Config.groovy google.appengine.application="myapp" install the plugin for app-engine grails install-plugin app-engine and answer 'jpa' when asked (no errors yet) installed plugins list now looks like app-engine 0.8.9 -- Grails AppEngine plugin gorm-jpa 0.7.1 -- GORM-JPA Plugin then grails run-app and get this error as the server is coming up... [java] WARNING: Nested in org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'pluginManager' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is org.codehaus.groovy.grails.exceptions.NewInstanceCreationException: Could not create a new instance of class [GormJpaGrailsPlugin]!: [java] java.lang.NoClassDefFoundError: org.grails.jpa.JpaPluginSupport then if i navigate to localhost:8080 I get HTTP ERROR: 503 Problem accessing /myapp. Reason: SERVICE_UNAVAILABLE Powered by Jetty://

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  • Zend Framework Form Element Validators - validate a field even if not required

    - by Jeremy Hicks
    Is there a way to get a validator to fire even if the form element isn't required? I have a form where I want to validate the contents of a texbox (make sure not empty) if the value of another form element, which is a couple of radio buttons, has a specific value selected. Right now I'm doing this by overriding the isValid() function of my form class and it works great. However, I'd like to move this to either its on validator or use the Callback validator. Here's what I have so far, but it never seems to get called unless I change the field to setRequired(true) which I don't want to do at all times, only if the value of the other form element is set to a specific value. // In my form class's init function $budget = new Zend_Form_Element_Radio('budget'); $budget->setLabel('Budget') ->setRequired(true) ->setMultiOptions($options); $budgetAmount = new Zend_Form_Element_Text('budget_amount'); $budgetAmount->setLabel('Budget Amount') ->setRequired(false) ->addFilter('StringTrim') ->addValidator(new App_Validate_BudgetAmount()); //Here is my custom validator (incomplete) but just testing to see if it even gets called. class App_Validate_BudgetAmount extends Zend_Validate_Abstract { const STRING_EMPTY = 'stringEmpty'; protected $_messageTemplates = array( self::STRING_EMPTY => 'please provide a budget amount' ); public function isValid($value) { echo 'validating...'; var_dump($value); return true; } }

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  • PHP MySQLi isn't letting me alter a table (adding a new column)

    - by asdasd
    Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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  • FDs not closed in FUSE filesystem

    - by cor
    Hi, I have a problem while implementing a fuse filesystem in python. for now i just have a proxy filesystem, exactly like a mount --bind would be. But, any file created, opened, or read on my filesystem is not released (the corresponding FD is not closed) Here is an example : yume% ./ProxyFs.py `pwd`/test yume% cd test yume% ls mdr yume% echo test test yume% ls mdr test yume% ps auxwww | grep python cor 22822 0.0 0.0 43596 4696 ? Ssl 12:57 0:00 python ./ProxyFs.py /home/cor/esl/proxyfs/test cor 22873 0.0 0.0 6352 812 pts/1 S+ 12:58 0:00 grep python yume% ls -l /proc/22822/fd total 0 lrwx------ 1 cor cor 64 2010-05-27 12:58 0 - /dev/null lrwx------ 1 cor cor 64 2010-05-27 12:58 1 - /dev/null lrwx------ 1 cor cor 64 2010-05-27 12:58 2 - /dev/null lrwx------ 1 cor cor 64 2010-05-27 12:58 3 - /dev/fuse l-wx------ 1 cor cor 64 2010-05-27 12:58 4 - /home/cor/test/test yume% Does anyone have a solution to actually really close the fds of the file I use in my fs ? I'm pretty sure it's a mistake in the implementation of the open, read, write hooks but i'm stucked... Let me know if you need more details ! Thanks a lot Cor

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  • Jquery Sorting by Letter

    - by Batfan
    I am using jquery to sort through a group of paragraph tags (kudos to Aaron Harun). It pulls the value "letter" (a letter) from the url string and displays only paragraphs that start with that letter. It hides all others and also consolidates the list so that there are no duplicates showing. See the code: var letter = '<?php echo(strlen($_GET['letter']) == 1) ? $_GET['letter'] : ''; ?>' function finish(){ var found_first = []; jQuery('p').each(function(){ if(jQuery(this).text().substr(0,1).toUpperCase() == letter){ if(found_first[jQuery(this).text()] != true){ jQuery(this).addClass('current-series'); found_first[jQuery(this).text()] = true; }else{ jQuery(this).hide(); } } else{ jQuery(this).hide();} }) } Been working with this all day and I have 2 Questions on this: Is there a way to get it to ignore the word 'The', if it's first? For example, if a paragraph starts with 'The Amazing', I would like it to show up on the 'A' page, not the 'T' page, like it currently is. Is there a way to have a single page for (all) numbers? For example, the url to the page would be something similar to domain.com/index.php?letter=0 and this would show only the paragraph tags that start with a number, any number. I can currently do this with single numbers but, I would like 1 page for all numbers.

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  • cURL + HTTP_POST, keep getting 500 error. Has no idea?

    - by mysqllearner
    Okay, I want to make a HTTP_POST using cURL to a SSL site. I already imported the certificate to my server. This is my code: $url = "https://www.xxx.xxx"; $post = "";# all data that going to send $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $post); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0'); $exe = curl_exec($ch); $getInfo = curl_getinfo($ch); if ($exe === false) { $output = "Error in sending"; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } else if($geInfo['http_code'] != 777){ $output = "No data returned. Error: " . $geInfo['http_code']; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } curl_close($c); echo $output; It keep returned "500". Based on w3schools, 500 means Internal Server Error. Is my server having problem? How to solve/troubleshoot this?

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  • DOMNode reference doesn't work anymore after appending it to another element twice

    - by Robbie Groenewoudt
    Hi, I'm using the a wrapper around the PHP5-class DOMDocument to generate my HTML. This makes it easy to modify the HTML by using the DOM. An example is creating element #1 and adding it to the element #2 and still be able to modify element #1 directly. A problem arises however with the following: Element #1 is added to element #2 Element #2 is added to element #3 Element #1 is modified but no changes are visible in the DOM of element #3 (which contains #1 and #2) A simplified sample code: <?php $doc1 = new DOMDocument(); $el1 = $doc1->createElement('h1', 'Hello'); $doc1->appendChild($el1); $doc2 = new DOMDocument(); $el2 = $doc2->createElement('h2', 'World'); $doc2->appendChild($el2); $doc3 = new DOMDocument(); $el3 = $doc3->createElement('h3', 'Today'); $doc3->appendChild($el3); // Import el1 into el2 $el1 = $doc2->importNode($el1, true); $el2->appendChild( $el1 ); $doc1 = $doc2; // Import el2 into el3 $el2 = $doc3->importNode($el2, true); //$el1 = $doc3->importNode($el1, true); Necessary? $el3->appendChild($el2); $doc2 = $doc3; // Modify el1 $el1->nodeValue = "Boo"; // This doesn't work? //$el2->nodeValue = "Boo"; // Changing element2 or 3 works... // Display result echo $doc3->saveHTML(); ?>` Any idea's on why modifying $el1 won't work? (While $el2 works fine) Or an easy way to set $el1 to the right element?

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  • mysql_connect() acces denied for system@localhost(using password NO)

    - by user309381
    class MySQLDatabase { public $connection; function _construct() { $this-open_connection(); } public function open_connection() { $this-connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if(!$this-connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db(DB_NAME,$this-connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query(/*$sql*/) { $sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //return $result; while( $found_user = mysql_fetch_assoc($result)) { echo $found_user ['username']; } } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); $database-open_connection(); $database-query(); $database-close_connection(); ?

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