Search Results

Search found 8646 results on 346 pages for 'echo flow'.

Page 307/346 | < Previous Page | 303 304 305 306 307 308 309 310 311 312 313 314  | Next Page >

  • Getting a UIImage from MySQL using PHP and jSON

    - by Daniel
    I'm developing a little news reader that retrieves the info from a website by doing a POST request to a URL. The response is a jSON object with the unread-news. E.g. the last news on the App has a timeStamp of "2013-03-01". When the user refreshes the table, it POSTS "domain.com/api/api.php?newer-than=2013-03-01". The api.php script goes to the MySQL database and fetches all the news posted after 2013-03-01 and prints them json_encoded. This is // do something to get the data in an array echo $array_of_fetched_data; for example the response would be [{"title": "new app is coming to the market", "text": "lorem ipsum dolor sit amet...", image: XXX}] the App then gets the response and parses it, obtaining an NSDictionary and adds it to a Core Data db. NSDictionary* obtainedNews = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error]; My question is: How can I add an image to the MySQL database, store it, pass it using jSON trough a POST HTTP Request and then interpret it as an UIImage. It's clear that to store an UIImage in CoreData, they must be transform into/from NSData. How can I pass the NSData back and forth to a MySQL db using php and jSON? How should I upload the image to the db? (Serialized, as a BLOB, etc)

    Read the article

  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

    Read the article

  • Any suggestions to improve my PDO connection class?

    - by Scarface
    Hey guys I am pretty new to pdo so I basically just put together a simple connection class using information out of the introductory book I was reading but is this connection efficient? If anyone has any informative suggestions, I would really appreciate it. class PDOConnectionFactory{ public $con = null; // swich database? public $dbType = "mysql"; // connection parameters public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } }

    Read the article

  • jquery getjson works fine in mac, and fails in windows

    - by viper
    this code loads the data jQuery.ajax({ type: "GET", url: "getOptionsJson.php", cache: false, dataType: "json", data: "config_id="+config_id, success: function(json) { jQuery.extend(dataArr, json.ajax); jQuery.extend(opts, json.ajax2); printResult(config_id); }, error: function() { alert('Error. Please try again'); location.reload(); } }); this code generates it <?php header('Content-type: application/javascript'); echo json_encode(array( "ajax" => array(1 => "test", 2 => "test 2"), "ajax2" => array(1 => "test 3", 2 => "test 4") ); ?> when im working on mac, everything goes fine, but today i tried it on widnows, and it doesnt work. the code flows like its success, but opts and dataArr are null i tried all headers (application/json, text/html, etc) i checked if getOptionsJson.php is called correctly via mail function filnally firebug says that im getting response, but theres no content and file is just 1kb i tried even changing datatype to xml, still fails ie gives a hint, it says 'there's error on site' which reffers to 127 line of jquery file any idea?

    Read the article

  • How do I return the value of the owner and id attributes respectively from an XML result set using P

    - by pharma_joe
    I am using PHP to iterate over the following result set, the aim is to build a hyperlink for each result using a foreach loop. I have stored the XML result in $images, and have constructed this loop: foreach ($images as $image) { //Build link to each photo returned //base URL $flickrPhotoUrl = 'http://www.flickr.com/photos/'; //Append user ID $flickrPhotoUrl .= ""; echo $flickrPhotoUrl; } Here is a sample result from Flickr: <photos page="1" pages="10982" perpage="10" total="109813"> <photo id="4616840471" owner="47823583@N03" secret="1b83173bc0" server="4013" farm="5" title="Strawberry Bears" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616612597" owner="12658756@N08" secret="f626214382" server="4059" farm="5" title="Yarn Chef Minestrone - Grickle Grass" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616469567" owner="26284268@N00" secret="6911a66838" server="4022" farm="5" title="P5130121.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617076736" owner="26284268@N00" secret="8b990acba4" server="4047" farm="5" title="P5130106.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616470013" owner="26284268@N00" secret="44600b3836" server="4036" farm="5" title="P5130125.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616466147" owner="26284268@N00" secret="554eab8667" server="4052" farm="5" title="P5130116.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617082398" owner="26284268@N00" secret="4a2b663442" server="3350" farm="4" title="P5130118.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617078272" owner="26284268@N00" secret="357737017b" server="4013" farm="5" title="P5130109.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617081446" owner="26284268@N00" secret="1f87726497" server="4048" farm="5" title="P5130117.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617077676" owner="26284268@N00" secret="77ca9f754a" server="3330" farm="4" title="P5130108.JPG" ispublic="1" isfriend="0" isfamily="0"></photo>

    Read the article

  • Error 100 When Attempting to post from app to Facebook wall?

    - by IMAPC
    I'm playing around with the Facebook API, and have gotten far enough to get the access token into my app, but when I go to actually send a post to my Facebook wall I get the error message, {"error":{"message":"(#100) You can't post this because it has a blocked link.","type":"OAuthException","code":100}}1 I'm not attempting to send any kind of link, just "Hello, World!" so this seems pretty weird to me :\ Here's my code so far: $content = urlencode("Hello, World!"); $accesstoken = urlencode($row['fbid']); $result = getPageWithPOST("https://graph.facebook.com/me/feed", "access_token=" . $accesstoken . "&message=" . $content); echo $result; where getPageWithPOST is, function getPageWithPOST($url, $posts) { $c = curl_init(); curl_setopt($c, CURLOPT_URL, $url); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, $posts); $content = curl_exec ($c); curl_close ($c); return $content; } thanks!

    Read the article

  • PHP sessions dying in a few seconds

    - by beauchette
    I have a problem with my server : my sessions are dying on their own after a few seconds. here are two page examples : page1.php : <? session_start(); $_SESSION['x'] = 'moo'; ?> page2.php : <? session_start(); echo $_SESSION['x']; ?> php's settings are debian's untouched : no auto start, 1440 seconds maxlifetime, etc so, if I visit page1.php et then page2.php I'm supposed to see 'moo' for 24 minutes, in my case, you have 'moo' for about 5 seconds. Then I observed that the actual session file, was 44 bytes long, and then 0 a few seconds later, without any other intervention than a few 'ls' to observe the phenomenon, I really have no clue as to what happens and any help would be appreciated. EDIT: after some fiddling (mainly not doing much besides restarting my server 3 or 4 times) I was able to have my quick example working. and then I noticed that sessions in my session.save_path directory are all 44 bytes except for some that are 0 bytes, so it's like it's working but not always. which is even more frustrating.

    Read the article

  • php cURL. preg_match , extract text from xhtml

    - by Michael
    I'm trying to extract the price from the bellow html page/link using php cURL and preg_match . Basically I'm expecting for this code to output 4,550 but for some reasons I get Notice: Undefined offset: 1 in C:\wamp\www\test.php on line 22 I think that the pattern is correct because if I put the html itself in a variable and escape the "" it works ! . Also if I output (echo $result;) it displays the html properly grabbed from foxtons website so I just can't figure it out why the whole thing doesn't work . I need to make this work and also I would appreciate if you would tell me why is that notice generated and why my current script doesn't work. $url = "http://www.foxtons.co.uk/search?bedrooms_from=0&property_id=727717"; $ch = curl_init($url); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch,CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($ch); curl_exec($ch); curl_close($ch); $result2 = str_replace('"', '\"', $result); $tagname1= ");<\/script "; $tagname2= "<\/noscript per month<\/a"; $pattern = "/$tagname1(.*?)$tagname2/"; preg_match($pattern, $result, $matches); $prices = $matches[1]; print_r($prices); ?

    Read the article

  • Formating a table date field from the Model in Codeigniter

    - by Landitus
    Hi, I', trying to re-format a date from a table in Codeigniter. The Controller is for a blog. I was succesfull when the date conversion happens in the View. I was hoping to convert the date in the Model to have things in order. Here's the date conversion as it happens in the View. This is inside the posts loop: <?php foreach($records as $row) : ?> <?php $fdate = "%d <abbr>%M</abbr> %Y"; $dateConv = mdate($fdate, mysql_to_unix($row->date)); ?> <div class="article section"> <span class="date"><?php echo $dateConv ;?></span> ... Keeps going ... This is the Model: class Novedades_model extends Model { function getAll() { $this->db->order_by('date','desc'); $query = $this->db->get('novedades'); if($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } How can I convert the date in the Model? Can I access the date key and refactor it?

    Read the article

  • Get Mail with PHP and IMAP in Gmail just loading

    - by Oscar Godson
    I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = '[email protected]'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

    Read the article

  • Mail function wont send eMail. ERROR

    - by Peter
    I think i tried to fix this issue fr 3 days now and cant seem to find the problem. I use XAMPP and use this code: <?php $to = "[email protected]"; $subject = "Test mail"; $message = "Hello! This is a simple email message."; $from = "[email protected]"; $headers = "From: $from"; $res= mail($to,$subject,$message,$headers); echo " $res Mail Sent."; ?> when i enter that page i get an error that says: Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set( My php.init file in xampp are as follow: [mail function] ; For Win32 only. ; http://php.net/smtp SMTP = smpt.gmail.com ; http://php.net/smtp-port smtp_port = 25 That is all my codes.

    Read the article

  • jQuery: AJAX call isn't updating page

    - by Cortopasta
    Thought I had a simple AJAX call using $.POST(), but apparently my function isn't firing, and nothing is updating :-/ Here is the call: $(".answerVerse ul li").click(function(){ var rank = $(this).removeClass("star_empty star_full star_highlight").attr("class"); var verse_id = $(this).parent().parent().find(".verseId").html(); var answer_id = $(this).parent().parent().find(".answerId").html(); var place = this; $.post("rank.php", { rank: rank, verse_id: verse_id, answer_id: answer_id },function(data){ $(place).parent().removeClass().addClass(data.newVerseRank); for (i=0;i<=5;i++) { $(".answerVerse ul."+i).each(function(){ $(".answerVerse ul."+i+" li."+i).prevAll().andSelf().removeClass("star_empty").addClass("star_full"); }); } }, "json"); }); And here is the PHP (rank.php) that it calls: require_once("dbcon.php"); $user = new user(); $user->updateVerseRank($_POST['verse_id'], $_POST['rank']); $user->getVerse($_POST['verse_id']); $user->getAnswer($_POST['answer_id']; $arr = array ('newVerseRank'=>htmlspecialchars(round($user->verse[3])),'newVerseVotes'=>htmlspecialchars(round($user->verse[4])),'newAnswerRank'=>htmlspecialchars($user->answer[3])); echo json_encode($arr); Why am I not updating the page? I know it's something dumb I'm doing seeing as how this is my first attempt at AJAX and JSON :-/ Just trying to learn

    Read the article

  • SELECT SUM PHP MySQL problem

    - by user345426
    This is driving me nuts! Below you will find my PHP/MySQL code but I will post the direct mySQL statement here: SELECT SUM( ot.value ) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP( o.date_purchased ) >=1262332800 AND UNIX_TIMESTAMP( o.date_purchased ) <=1264924800 AND o.sales_rep_id = '2' When I execute this statement inside of phpMyAdmin I get the sum for ot.value which is associated to "msa". Although, when I run my php code it does not return a value. Anyone see the problem? // works in phpMyAdmin but not displaying during PHP execution! $monthly_sales_amount_sql = "SELECT SUM(ot.value) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP(o.date_purchased) >= $start_timestamp AND UNIX_TIMESTAMP(o.date_purchased) <= $end_timestamp AND o.sales_rep_id = '" . $sales_rep_id "'"; $result = mysql_query($monthly_sales_amount_sql); $row = mysql_fetch_assoc($result); echo "MSA: " . $row['msa'] . "<BR><BR>";

    Read the article

  • sort files by date in PHP

    - by sasori
    hi, I currently have an index.php file which allows me to output the list of files inside the same directory, the output shows the names then I used filemtime() function to show the date when the file was modified. my problem now is, how will I sort the output to show the latest modified file ?, I've been thinking for awhile how to do this. if only I am doing it with mysql interaction there will be no problem at all. please show me an example how to sort and output the list of files starting from the latest modified one. this is what i have for now if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $lastModified = date('F d Y, H:i:s',filemtime($file)); if(strlen($file)-strpos($file,".swf")== 4){ echo "<tr><td><input type=\"checkbox\" name=\"box[]\"></td><td><a href=\"$file\" target=\"_blank\">$file</a></td><td>$lastModified</td></tr>"; } } } closedir($handle); }

    Read the article

  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

    Read the article

  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

    Read the article

  • Convert charset in mysql query

    - by Yousf
    Hi, I have a question about converting charset from inside mysql query. I have a 2 databases. One for the website (joomla), the other for forum (IPB). I am doing query from inside joomla, which by default have "SET NAMES UTF8". I want to query a table inside the forum databases. A table called "ibf_topics". This table has latin1 encoding. I do the following to select anything from the not-utf8 table. //convert connection to handle latin1. $query = "SET NAMES latin1"; $db->setQuery($query); $db->query(); $query = "select id, title from other_database.ibf_topics"; $db->setQuery($query); $db->query(); //read result into an array. //return connection to handle UTF8. $query = "SET NAMES UTF8"; $db->setQuery($query); $db->query(); After that, when I want to use the selected tile, I use the following: echo iconv("CP1256", "UTF-8", $topic['title']) The question is, is there anyway to avoid all this hassle? For now, I can't change forum database to UTF8 and I can't change joomla database to latin1 :S

    Read the article

  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

    Read the article

  • Getting an non-object error in my php script

    - by Disowned
    Hey I was trying to call a script to made some changes to an html file, however when I run the script it tells me that it's making a call to a non-object. Obviously I did something wrong, but what? Here's the script. /*Dom controllers*/ $dom = new DOMDocument(); $dom->loadHTML('index.html'); $id = $dom->getElementById('contact_us'); $p = $dom->appendChild(new DOMElement('p')); $op = $dom->getElementsByTagName('p'); /* Dem POST vars used by dat Ajax mah ziggen, yeah boi*/ if (isset($_POST['Home']) && isset($_POST['About']) && isset($_POST['Contact']) && isset($_POST['sexyText'])){ $home = $_POST['Home']; $about = $_POST['About']; $contact = $_POST['Contact']; $text = $_POST['sexyText']; trim($home); trim($about); trim($contact); trim($text); } function post(){ global $dom, $id, $home, $about, $contact, $text, $textp, $p, $op; $textp = $dom->createTextNode($text); $p->appendChild($textp); $id->replaceChild($p, $op); $dom->saveHTMLFile('index.html'); } post(); echo 1; ?> The error happens at the replaceChild function.

    Read the article

  • Combining XmlWriter objects?

    - by Kevin
    The way my application is structured, each component generates output as XML and returns an XmlWriter object. Before rendering the final output to the page, I combine all XML and perform an XSL transformation on that object. Below, is a simplified code sample of the application structure. Does it make sense to combine XmlWriter objects like this? Is there a better way to structure my application? The optimal solution would be one where I didn't have to pass a single XmlWriter instance as a parameter to each component. function page1Xml() { $content = new XmlWriter(); $content->openMemory(); $content->startElement('content'); $content->text('Sample content'); $content->endElement(); return $content; } function generateSiteMap() { $sitemap = new XmlWriter(); $sitemap->openMemory(); $sitemap->startElement('sitemap'); $sitemap->startElement('page'); $sitemap->writeAttribute('href', 'page1.php'); $sitemap->text('Page 1'); $sitemap->endElement(); $sitemap->endElement(); return $sitemap; } function output($content) { $doc = new XmlWriter(); $doc->openMemory(); $doc->writePi('xml-stylesheet', 'type="text/xsl" href="template.xsl"'); $doc->startElement('document'); $doc->writeRaw( generateSiteMap()->outputMemory() ); $doc->writeRaw( $content->outputMemory() ); $doc->endElement(); $doc->endDocument(); $output = xslTransform($doc); return $output; } $content = page1Xml(); echo output($content); Update: I may abandon XmlWriter altogether and use DomDocument instead. It is more flexible and it also seemed to perform better (at least on the crude tests I created).

    Read the article

  • Passing a Batch File an Argument Containing a Quote Containing a Space

    - by Synetech inc.
    Hi, On many occasions I have dealt with passing batch files arguments with spaces, quotes, percents, and slashes and all sorts of combinations of them. Usually I managed to figure out how to accomplish what I want, but this time I am stuck. I have tried a couple of hundred combinations now and my head is starting to hurt. I’ve reduced the problem quite nicely. It’s a simple requirement: pass a double-quoted space from one batch file to another. That is, one batch file should pass some string X to another so that the the second one echos " ". I just can’t figure out what X should be. Here is a minimal batch file that demonstrates and attempt that does not work. (This BAT file takes the place of both by calling itself.) ::Goal is to print: ::" " ::That is, to pass a quoted space from a BAT file to a BAT file if not (%1)==() goto recurse %0 "" "" :recurse echo %1 pause It does not work. I’ve tried using "\" \"", """ """, """" """", "\"" "\"", ""\" \""", "^" ^"", ^"" "^", and so on. Either they print double double-quotes, lose everything after the space, or something else (that is wrong). Any ideas? Thanks.

    Read the article

  • PHP for loop isn't looping after APC installation

    - by BoRo
    So I installed APC and i all of the sudden my for loops only run once and increment the value then stops. I dont get what's going on, it worked fine before APC was installed. Any Suggestions? EDIT: I managed to narrow it down to the increment. for some reason if I have an array let's say string[], and have the for loop list through the values like with string[$i] It only does it for the first one, I can manually echo/print out the array elements to check if the array is the problem but all elements have the appropriate data/values. EDIT #2: Well the code looks something like (it scrapes a page for images and gets some data from it): $str = explode('<div class="images" align="center">',$str); for($i=1;$i<11;$i++){ $url3 = $str[$i]; $url3 = extstr3($url3,'class="filename">','</div>'); $urlname = extstr3($url3,'<a href="','</a>'); $name = extstr3($urlname,'target="_blank">','.jpg'); $url3 = extstr3($url3,'<a href="','" target="_blank">'); $name = str_replace ('_', ' ', $name); . . .

    Read the article

  • Can anyone get app-engine plugin working with Grails on mac os x?

    - by tim
    I have been trying for 4 days to get app-engine and grails working together on my mac to no avail. I am using latest groovy/grails and appengine sdk versions. Im following the app-engine plugin step by step on the grails site.. http://grails.org/plugin/app-engine Groovy Version: 1.7.1 JVM: 1.5.0_22 Grails 1.3.0.RC1 echo $APPENGINE_HOME reveals /Users/markstim/appengine-java-sdk-1.3.2 I perform the following steps 1. grails create-app myapp 2. cd myapp; grails list-plugins reveals hibernate 1.3.0.RC1 -- Hibernate for Grails tomcat 1.3.0.RC1 -- Apache Tomcat plugin for Grails add the following line to Config.groovy google.appengine.application="myapp" install the plugin for app-engine grails install-plugin app-engine and answer 'jpa' when asked (no errors yet) installed plugins list now looks like app-engine 0.8.9 -- Grails AppEngine plugin gorm-jpa 0.7.1 -- GORM-JPA Plugin then grails run-app and get this error as the server is coming up... [java] WARNING: Nested in org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'pluginManager' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is org.codehaus.groovy.grails.exceptions.NewInstanceCreationException: Could not create a new instance of class [GormJpaGrailsPlugin]!: [java] java.lang.NoClassDefFoundError: org.grails.jpa.JpaPluginSupport then if i navigate to localhost:8080 I get HTTP ERROR: 503 Problem accessing /myapp. Reason: SERVICE_UNAVAILABLE Powered by Jetty://

    Read the article

  • Appending Comment Number Anchors to Comments

    - by John
    Hello, I am using a PHP file called comments.php that has a query that enters values into a mySQL table called "comment." As the query does this, it auto-generates a field called "commentid", which is set to auto_increment in MySQL. The file also contains a loop what echoes out all comments for a given submission. It all works fine and dandy, but I want to simultaneously pull this "commentid" and turn it into a hashtag / anchor that when appended to the end of the URL makes that comment at the top of the user's browser. Someone said on another question that in order to do this one thing I should do is create an anchor on the row where the comment is being printed out. How can I do this? Thanks in advance, John The query that inserts comments into the MySQL table "comment": $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); The fields in the table "comment": commentid loginid submissionid comment datecommented The row in a loop where the comments are echoed out: echo '<td rowspan="3" class="commentname1">'.stripslashes($row["comment"]).'</td>';

    Read the article

  • function not printing out anything

    - by Abdul Latif
    I have the following function below: public function setupHead($title){ $displayHead .='<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>'.$title.'</title>'; $displayHead .='<script type="text/javascript" src="'.PATH.'js/jquery-1.3.2.min.js"></script> <script type="text/javascript" src="'.PATH.'js/thickbox.js"></script> <script type="text/javascript" src="'.PATH.'js/ui.core.js"></script> <!--<script type="text/javascript" src="'.PATH.'js/js.js"></script>--> <link rel="stylesheet" href="'.PATH.'css/thickbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" href="'.PATH.'css/styles.css"> <link rel="stylesheet" type="text/css" href="'.PATH.'css/menu_allbrowsers.css"> <link rel="stylesheet" href="'.PATH.'css/news.css" type="text/css" media="screen" /> <link rel="stylesheet" href="'.PATH.'css/text.css" type="text/css" media="screen" /> <script type="text/javascript" src="'.PATH.'js/swfobject.js"></script> <!--[if IE 7]><link rel="stylesheet" type="text/css" href="'.PATH.'css/IE7menu.css" /><![endif]--> <!--[if IE 6]><link rel="stylesheet" type="text/css" href="'.PATH.'css/ie6.css" /><![endif]--> <!--[if IE 7]><link rel="stylesheet" type="text/css" href="'.PATH.'css/ie7.css" /><![endif]--> </head>'; return $displayHead; } but when it call is using: echo classname->setupHead($title); nothing gets displayed. doesn't php allow html in strings? Thanks in advance

    Read the article

< Previous Page | 303 304 305 306 307 308 309 310 311 312 313 314  | Next Page >