Search Results

Search found 16643 results on 666 pages for 'exception handling'.

Page 309/666 | < Previous Page | 305 306 307 308 309 310 311 312 313 314 315 316  | Next Page >

  • A Question about using jython when run a receving socket in python

    - by abusemind
    Hi, I have not a lot of knowledge of python and network programming. Currently I am trying to implement a simple application which can receive a text message sent by the user, fetch some information from the google search api, and return the results via text message to the user. This application will continue to listening to the users messages and reply immediately. How I get the text short message sent by the user? It's a program named fetion from the mobile supplier in China. The client side fetion, just like a instant communication tool, can send/receive messages to/from other people who are using mobile to receive/send SMS. I am using a open source python program that simulates the fetion program. So basically I can use this python program to communate with others who using cell phone via SMS. My core program is based on java, so I need to take this python program into java environment. I am using jython, and now I am available to send messages to users by some lines of java codes. But the real question is the process of receving from users via SMS. In python code, a new thread is created to continuously listen to the user. It should be OK in Python, but when I run the similar process in Jython, the following exception occurs: Exception in thread Thread:Traceback (most recent call last): File "D:\jython2.5.1\Lib\threading.py", line 178, in _Thread__bootstrap self.run() File "<iostream>", line 1389, in run File "<iostream>", line 1207, in receive File "<iostream>", line 1207, in receive File "<iostream>", line 150, in recv File "D:\jython2.5.1\Lib\select.py", line 223, in native_select pobj.register(fd, POLLIN) File "D:\jython2.5.1\Lib\select.py", line 104, in register raise _map_exception(jlx) error: (20000, 'socket must be in non-blocking mode') The line 150 in the python code is as follows: def recv(self,timeout=False): if self.login_type == "HTTP": time.sleep(10) return self.get_offline_msg() pass else: if timeout: infd,outfd,errfd = select([self.__sock,],[],[],timeout)//<---line 150 here else: infd,outfd,errfd = select([self.__sock,],[],[]) if len(infd) != 0: ret = self.__tcp_recv() num = len(ret) d_print(('num',),locals()) if num == 0: return ret if num == 1: return ret[0] for r in ret: self.queue.put(r) d_print(('r',),locals()) if not self.queue.empty(): return self.queue.get() else: return "TimeOut" Because of I am not very familiar with python, especially the socket part, and also new in Jython use, I really need your help or only advice or explanation. Thank you very much!

    Read the article

  • DriverManager always returns my custom driver regardless of the connection URL

    - by JGB146
    I am writing a driver to act as a wrapper around two separate MySQL connections (to distributed databases). Basically, the goal is to enable interaction with my driver for all applications instead of requiring the application to sort out which database holds the desired data. Most of the code for this is in place, but I'm having a problem in that when I attempt to create connections via the MySQL Driver, the DriverManager is returning an instance of my driver instead of the MySQL Driver. I'd appreciate any tips on what could be causing this and what could be done to fix it! Below is a few relevant snippets of code. I can provide more, but there's a lot, so I'd need to know what else you want to see. First, from MyDriver.java: public MyDriver() throws SQLException { DriverManager.registerDriver(this); } public Connection connect(String url, Properties info) throws SQLException { try { return new MyConnection(info); } catch (Exception e) { return null; } } public boolean acceptsURL(String url) throws SQLException { if (url.contains("jdbc:jgb://")) { return true; } return false; } It is my understanding that this acceptsURL function will dictate whether or not the DriverManager deems my driver a suitable fit for a given URL. Hence it should only be passing connections from my driver if the URL contains "jdbc:jgb://" right? Here's code from MyConnection.java: Connection c1 = null; Connection c2 = null; /** *Constructors */ public DDBSConnection (Properties info) throws SQLException, Exception { info.list(System.out); //included for testing Class.forName("com.mysql.jdbc.Driver").newInstance(); String url1 = "jdbc:mysql://server1.com/jgb"; String url2 = "jdbc:mysql://server2.com/jgb"; this.c1 = DriverManager.getConnection( url1, info.getProperty("username"), info.getProperty("password")); this.c2 = DriverManager.getConnection( url2, info.getProperty("username"), info.getProperty("password")); } And this tells me two things. First, the info.list() call confirms that the correct user and password are being sent. Second, because we enter an infinite loop, we see that the DriverManager is providing new instances of my connection as matches for the mysql URLs instead of the desired mysql driver/connection. FWIW, I have separately tested implementations that go straight to the mysql driver using this exact syntax (al beit only one at a time), and was able to successfully interact with each database individually from a test application outside of my driver.

    Read the article

  • android 2.2 google map error

    - by shenbryant
    I used google.map api to develop a project which works well on android 2.1. But when I run the same project on android 2.2, it encountered some errors. The shown errors are " -- AndroidRuntime FATAL EXCEPTION:main -- AndroidRuntime java.lang.NoClassDefFoundError:android.net.NetworkConnectivityListener -- AndroidRuntime at com.google.android.maps.MapActivity.onCreate(MapActivity.java:199) " I don't know where is the problem? Can anyone help me? I will apreciate it very much!

    Read the article

  • no appropriate default constructor available . (when creating a child class)

    - by numerical25
    I am creating some custom exception classes doing the following class GXException { public: GXException(LPCWSTR pTxt):pReason(pTxt){}; LPCWSTR pReason; }; class GXVideoException : GXException { public: GXVideoException(LPCWSTR pTxt):pReason(pTxt){}; LPCWSTR pReason; }; When I created GXVideoException to extend GXException, I get the following error 1>c:\users\numerical25\desktop\intro todirectx\godfiles\gxrendermanager\gxrendermanager\gxrendermanager\gxexceptions.h(14) : error C2512: 'GXException' : no appropriate default constructor available

    Read the article

  • Postgresql spawning a ridiculous number of postmaster processes

    - by Kevin Loney
    For some reason postgres is spawning 700 postmaster processes for handling database requests and the postgres log file if full of 'unexpected EOF on client connection', 'incomplete startup packet' and 'sorry, too many clients already'. netstat tells me that all the open connections are local and I'm pretty sure are coming from postgres internally. This particular instance has been running just fine for the last 230 days or so and nothing has changed configuration wise. Any thoughts on where I should be looking to try and resolve this issue? This is my first time diagnosing a problem like this so if there is any steps I can take to help narrow down the cause that would be helpful as well.

    Read the article

  • URL load error during adding

    - by Steven
    hi, i have a string say Path ="C:\AAA\bin" which is a path to a project's bin folder. I used new URL(Path) during invocation of addURL method of URLClassLoader class. ex- addURL(sysLoader,new URL(Path)) ; its giving unknown protocol:c exception whats the problem?Help

    Read the article

  • How to redirect (or Alias) jump page with Apache

    - by Meltemi
    I'm not an Apache expert but need to make a small change to a web server. We are introducing a "jump page" URL that is different from a primary URL (for tracking reasons). /productA/index.html /productA/jump_index.html Basically i want to log that jump_index.html was requested and then return index.html. I don't want the client to wait 8 seconds or so for a redirect. How should we be handling this? Simply symlink (or alias) the file in the filesystem? Use mod_alias Alias Match (if so how exactly)? something better still? Edit: mod_rewrite in httpd.conf: <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{REQUEST_METHOD} ^TRACE RewriteRule .* - [F] </IfModule>

    Read the article

  • Google App Engine 1.3.1 <admin-console> Issue

    - by Taylor L
    I attempted to add an <admin-console> section to my appengine-web.xml and I got the exception below. The <admin-console> element is a valid element according to the appengine-web.xsd. It's also documented in the app engine docs. Any ideas as to what is wrong? <admin-console> <page name="My Admin" url="/app/admin" /> </admin-console> Feb 14, 2010 12:40:09 AM com.google.apphosting.utils.config.AppEngineWebXmlReader readAppEngineWebXml SEVERE: Received exception processing C:/development/taylor/myapp/target/myapp-web-0.0.1-SNAPSHOT\WEB-INF/appengine-web.xml com.google.apphosting.utils.config.AppEngineConfigException: Unrecognized element <admin-console> at com.google.apphosting.utils.config.AppEngineWebXmlProcessor.processSecondLevelNode(AppEngineWebXmlProcessor.java:99) at com.google.apphosting.utils.config.AppEngineWebXmlProcessor.processXml(AppEngineWebXmlProcessor.java:46) at com.google.apphosting.utils.config.AppEngineWebXmlReader.processXml(AppEngineWebXmlReader.java:94) at com.google.apphosting.utils.config.AppEngineWebXmlReader.readAppEngineWebXml(AppEngineWebXmlReader.java:61) at com.google.appengine.tools.admin.Application.<init>(Application.java:88) at com.google.appengine.tools.admin.Application.readApplication(Application.java:120) at com.google.appengine.tools.admin.AppCfg.<init>(AppCfg.java:107) at com.google.appengine.tools.admin.AppCfg.<init>(AppCfg.java:58) at com.google.appengine.tools.admin.AppCfg.main(AppCfg.java:54) at net.kindleit.gae.EngineGoalBase.runAppCfg(EngineGoalBase.java:140) at net.kindleit.gae.DeployGoal.execute(DeployGoal.java:38) at org.apache.maven.plugin.DefaultPluginManager.executeMojo(DefaultPluginManager.java:579) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalAndHandleFailures(DefaultLifecycleExecutor.java:498) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeTaskSegmentForProject(DefaultLifecycleExecutor.java:265) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeTaskSegments(DefaultLifecycleExecutor.java:191) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.execute(DefaultLifecycleExecutor.java:149) at org.apache.maven.DefaultMaven.execute_aroundBody0(DefaultMaven.java:223) at org.apache.maven.DefaultMaven.execute_aroundBody1$advice(DefaultMaven.java:304) at org.apache.maven.DefaultMaven.execute(DefaultMaven.java:1) at org.apache.maven.embedder.MavenEmbedder.execute_aroundBody2(MavenEmbedder.java:904) at org.apache.maven.embedder.MavenEmbedder.execute_aroundBody3$advice(MavenEmbedder.java:304) at org.apache.maven.embedder.MavenEmbedder.execute(MavenEmbedder.java:1) at org.apache.maven.cli.MavenCli.doMain(MavenCli.java:176) at org.apache.maven.cli.MavenCli.main(MavenCli.java:63) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.codehaus.plexus.classworlds.launcher.Launcher.launchEnhanced(Launcher.java:289) at org.codehaus.plexus.classworlds.launcher.Launcher.launch(Launcher.java:229) at org.codehaus.plexus.classworlds.launcher.Launcher.mainWithExitCode(Launcher.java:408) at org.codehaus.plexus.classworlds.launcher.Launcher.main(Launcher.java:351) at org.codehaus.classworlds.Launcher.main(Launcher.java:31)

    Read the article

  • Visual Studio soft-crashing when encountering XAML Errors in initialize.

    - by Aren
    I've been having some serious issues with Visual Studio 2010 as of late. It's been crashing in a peculiar way when I encounter certain types of XAML errors during the InitializeComponent() of a control/window. The program breaks and visual studio gears up like it's catching an exception (because it is) and then stops midway displaying a broken highlight in my XAML file with no details as to what is wrong. Example: There is not pop outs, or details Anywhere about what is wrong, only a callstack that points to my InitializeComponent() call. Now normally I'd just do some trial and error to fix this problem, and find out where i messed up, but the real problem isn't my code. Visual Studio is rendered completely useless at this point. It reports my application still in "Running" mode. The Stop/Break/Restart buttons on the toolbar or in the menus don't do anything (but grey out). Closing the application does not stop this behaviour, closing visual studio gets it stuck in a massive loop where it yells at me complaining every file open is not in the debug project, then repeats this process when i have exausted every open file. I have to force-close devenv.exe, and after this happening 3-4 times in a row it's a lot of wasted time (as my projects are usually pretty big and studio can be quite slow @ loading). To the point Has anyone else experienced this? How can I stop studio from locking up. Can I at LEAST get information out of this beast another way so i can fix my XAML error sooner rather than after 3-4 trial-and-error compiles yielding the same crash? Any & All help would be appreciated. Visual Studio 2010 version: 10.0.30319.1RTM Edit & Update FWIW, mostly the errors that cause this are XamlParseExceptions (I figured this out after i found what was wrong with my XAML). I think I need to be clearer though, Im not looking for the solution to my code problem, as these are usually typos / small things, I'm looking for a solution to VStudio getting all buggered up as a result. The particular error in the above image that 100% for sure caused this was a XamlParseException caused by forgetting a Value attribute on a data trigger. I've fixed that part but it still doesn't tell my why my studio becomes a lump of neutered program when a perfectly normal exception is thrown in the parsing of the XAML. Code that will cause this issue (at least for me) This is the base template WPF Application, with the following Window.xaml code. The problem is a missing Value="True" on the <DataTrigger ...> in the template. It generates a XamlParseException and Visual Studio Crashes as described above when debugging it. Final Notes The following solutions did not help me: Restarting Visual Studio Rebooting Reinstalling Visual Studio

    Read the article

  • Email notification when an error occurs

    - by user279521
    I need to design a bug alert system, where the web support team is notified via email when a user of our website encounters an error of any sort (database exception, or a 404) What would be the best way to design this section of the project? Any ideas would be appreciated.

    Read the article

  • Getting started with XSD validation with .NET

    - by Rosarch
    Here is my first attempt at validating XML with XSD. The XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <config xmlns="Schemas" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="config.xsd"> <levelVariant> <filePath>SampleVariant</filePath> </levelVariant> <levelVariant> <filePath>LegendaryMode</filePath> </levelVariant> <levelVariant> <filePath>AmazingMode</filePath> </levelVariant> </config> The XSD, located in "Schemas/config.xsd" relative to the XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"> <xs:element name="config"> <xs:complexType> <xs:sequence> <xs:element name="levelVariant"> <xs:complexType> <xs:sequence> <xs:element name="filePath" type="xs:anyURI"> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Right now, I just want to validate the XML file precisely as it appears currently. Once I understand this better, I'll expand more. Do I really need so many lines for something as simple as the XML file as it currently exists? The validation code in C#: public void SetURI(string uri) { XElement toValidate = XElement.Load(Path.Combine(PATH_TO_DATA_DIR, uri) + ".xml"); // begin confusion // exception here string schemaURI = toValidate.Attributes("xmlns").First().ToString() + toValidate.Attributes("xsi:noNamespaceSchemaLocation").First().ToString(); XmlSchemaSet schemas = new XmlSchemaSet(); schemas.Add(null, schemaURI); XDocument toValidateDoc = new XDocument(toValidate); toValidateDoc.Validate(schemas, null); // end confusion root = toValidate; } Running the above code gives this exception: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Any illumination would be appreciated.

    Read the article

  • C++ exceptions binary compatibility

    - by aaa
    hi. my project uses 2 different C++ compilers, g++ and nvcc (cuda compiler). I have noticed exception thrown from nvcc object files are not caught in g++ object files. are C++ exceptions supposed to be binary compatible in the same machine? what can cause such behavior?

    Read the article

  • PackageManager: Not granting permission

    - by scott
    Im trying to force my phone to go to sleep as soon as i turn my screen off, but whenever i install with adb, packagemanager informs me that it wont grant the permission i need, so my service throws an exception. I was able to install another app called power save mode toggle which has the same permission, and it seems to work, so i should be able to get this to work, right?

    Read the article

  • How to get Alfresco login ticket without user password, but with impersonating user with user principal name (UPN)

    - by dok
    I'm writing a DLL that has function for getting Alfresco login ticket without using user password, using only a user principal name (UPN). I’m calling alfresco REST API service /wcservice. I use NTLM in Alfresco. I’m impersonating users using WindowsIdentity constructor as explained here http://msdn.microsoft.com/en-us/library/ms998351.aspx#paght000023_impersonatingbyusingwindowsidentity. I checked and user is properly impersonated (I checked WindowsIdentity.GetCurrent().Name property). After impersonating a user, I try to make HttpWebRequest and set its credentials with CredentialsCache.DefaultNetworkCredentials. I get the error: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() When I use new NetworkCredential("username", "P@ssw0rd") to set request credentials, I get Alfresco login ticket (HttpStatusCode.OK, 200). Is there any way that I can get Alfresco login ticket without user password? Here is the code that I'm using: private string GetTicket(string UPN) { WindowsIdentity identity = new WindowsIdentity(UPN); WindowsImpersonationContext context = null; try { context = identity.Impersonate(); MakeWebRequest(); } catch (Exception e) { return e.Message + Environment.NewLine + e.StackTrace; } finally { if (context != null) { context.Undo(); } } } private string MakeWebRequest() { string URI = "http://alfrescoserver/alfresco/wcservice/mg/util/login"; HttpWebRequest request = WebRequest.Create(URI) as HttpWebRequest; request.CookieContainer = new CookieContainer(1); //request.Credentials = new NetworkCredential("username", "p@ssw0rd"); // It works with this request.Credentials = CredentialCache.DefaultNetworkCredentials; // It doesn’t work with this //request.Credentials = CredentialCache.DefaultCredentials; // It doesn’t work with this either try { using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { StreamReader sr = new StreamReader(response.GetResponseStream()); return sr.ReadToEnd(); } } catch (Exception e) { return (e.Message + Environment.NewLine + e.StackTrace); } } Here are records from Alfresco stdout.log (if it helps in any way): 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,550 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.526239ms 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] New NTLM auth request from 10.**.**.** (10.**.**.**:1229) 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,566 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.400909ms 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Received type1 [Type1:0xe20882b7,Domain:<NotSet>,Wks:<NotSet>] 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Client domain null 17:18:04,675 DEBUG [app.servlet.NTLMAuthenticationFilter] Sending NTLM type2 to client - [Type2:0x80000283,Target:AlfrescoServerA,Ch:197e2631cc3f9e0a]

    Read the article

  • Single console in eclipse for both Server and Client

    - by rits
    I am building a client server application using Java Sockets (in Windows XP). For that I need different consoles for both Client and Server(for Input and Output operations). But in eclipse both share a single console. Is there any plugin or some sort of cheat through which I can do this. After googling I got this, http://dev.eclipse.org/newslists/news.eclipse.newcomer/msg17138.html But, this seems to be only for write operations, not read operations. Also, I tried the following to launch application manually, but even this is not working........ package mypack; import java.io.BufferedOutputStream; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.OutputStream; import java.io.PrintStream; public class MySystem { public static void changeStream(String mainFile) throws IOException{ File temp = new File(".") ; String parentPath = temp.getCanonicalPath() ; System.out.println(parentPath); //creation of batch file starts here try{ File f = new File(parentPath + "\\a.bat") ; System.out.println("Created : " + f.createNewFile()); //f.deleteOnExit() ; FileOutputStream fos = new FileOutputStream(f) ; String str = "java " + mainFile ; String batchCommand="@echo off\n"+str+"\npause\nexit"; char arr[] = batchCommand.toCharArray() ; System.out.println(str) ; for(int i = 0 ; i < arr.length ; i++){ fos.write(arr[i]) ; } fos.close() ; } catch(Exception e){ } //creation of batch file ends here //execution of batch file starts here try{ Runtime r = Runtime.getRuntime() ; System.out.println(parentPath + "\\a.bat") ; Process p = r.exec(new String[]{"cmd","/k","start a.bat"},null,new File(parentPath)) ; OutputStream os = (OutputStream)p.getOutputStream() ; System.setOut( new PrintStream(os) ) ; System.out.println("Hello"); } catch(Exception e){ e.printStackTrace(); } //execution of batch file ends here } public static void main(String[] args) throws IOException { MySystem.changeStream("MySystem") ; } }

    Read the article

  • StackOverflowException in c# when no local variable in the function

    - by dnkulkarni
    when i do this static void Main() { Main(); } I receive stackoverflow exception. As i have read so far about C# they say ONLY local variable of value types (and short living ones) will go on stack. But here in the code there are no local variable to go on stack then what overflows it ? I know from assembly code line Perspective that reference to Main() will go on stack too ? Is that right ?

    Read the article

  • In a DDD approach, is this example modelled correctly?

    - by Tag
    Just created an acc on SO to ask this :) Assuming this simplified example: building a web application to manage projects... The application has the following requirements/rules. 1) Users should be able to create projects inserting the project name. 2) Project names cannot be empty. 3) Two projects can't have the same name. I'm using a 4-layered architecture (User Interface, Application, Domain, Infrastructure). On my Application Layer i have the following ProjectService.cs class: public class ProjectService { private IProjectRepository ProjectRepo { get; set; } public ProjectService(IProjectRepository projectRepo) { ProjectRepo = projectRepo; } public void CreateNewProject(string name) { IList<Project> projects = ProjectRepo.GetProjectsByName(name); if (projects.Count > 0) throw new Exception("Project name already exists."); Project project = new Project(name); ProjectRepo.InsertProject(project); } } On my Domain Layer, i have the Project.cs class and the IProjectRepository.cs interface: public class Project { public int ProjectID { get; private set; } public string Name { get; private set; } public Project(string name) { ValidateName(name); Name = name; } private void ValidateName(string name) { if (name == null || name.Equals(string.Empty)) { throw new Exception("Project name cannot be empty or null."); } } } public interface IProjectRepository { void InsertProject(Project project); IList<Project> GetProjectsByName(string projectName); } On my Infrastructure layer, i have the implementation of IProjectRepository which does the actual querying (the code is irrelevant). I don't like two things about this design: 1) I've read that the repository interfaces should be a part of the domain but the implementations should not. That makes no sense to me since i think the domain shouldn't call the repository methods (persistence ignorance), that should be a responsability of the services in the application layer. (Something tells me i'm terribly wrong.) 2) The process of creating a new project involves two validations (not null and not duplicate). In my design above, those two validations are scattered in two different places making it harder (imho) to see whats going on. So, my question is, from a DDD perspective, is this modelled correctly or would you do it in a different way?

    Read the article

  • asp.net cannot update database

    - by tom
    string ConnectionString = WebConfigurationManager.ConnectionStrings["dbnameConnectionString"].ConnectionString; SqlConnection myConnection = new SqlConnection(ConnectionString); myConnection.Open(); try { string qry = "UPDATE customers SET firstname=@firstname WHERE cid=1"; SqlCommand insertQuery = new SqlCommand(qry, myConnection); insertQuery.Parameters.Add(new SqlParameter("@firstname", txtFirstname.Text)); insertQuery.ExecuteNonQuery(); myConnection.Close(); } catch (Exception ee) { } Any suggestions?

    Read the article

  • Using the same style in many listviews

    - by Erik
    I want to use the same style in many listviews. And in my style i have defined the gridview columns also. But when i try to run, it throws an exception: View can't be shared by more than one ListView. How can i solve this?

    Read the article

  • How to add Listview in tab activity?

    - by sandip armal
    I have one "SubjectTabActivity" and i need to show listview on this activity. But when i want to implement ListActivity it doesn't show listActivity. I have two(addchapter,addsubject) xml file with "SubjectTabActivity". and i need to show my database item il list view in respective xml file. but i don't understand how to do that? How to add Listactivity in TabActivity?. Please give me any reference or code. Thanks in advance.. Here is my reference code. public class MasterMainActivity extends TabActivity { LayoutInflater layoutInflater = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.master); Intent intent=getIntent(); setResult(RESULT_OK, intent); layoutInflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE); TabHost tabHost = getTabHost(); TabHost.TabSpec tab1spec = tabHost.newTabSpec("tabOneSpec"); ImageView imgView = new ImageView(this); imgView.setBackgroundResource(R.drawable.subject); tab1spec.setIndicator("Subject", imgView.getBackground()); tab1spec.setContent(new TabContentLayout()); TabHost.TabSpec tab2spec = tabHost.newTabSpec("tabTwoSpec"); tab2spec.setContent(new TabContentLayout()); ImageView imgView1 = new ImageView(this); imgView1.setBackgroundResource(R.drawable.chapter); tab2spec.setIndicator("Chapter", imgView1.getBackground()); tabHost.addTab(tab1spec); tabHost.addTab(tab2spec); } private class TabContentLayout implements TabHost.TabContentFactory { @Override public View createTabContent(String tag) { View view = null; if(tag.equals("tabOneSpec")) { try { //static final String[] FRUITS = new String[] { "Apple", "Avocado", "Banana", // "Blueberry", "Coconut", "Durian", "Guava", "Kiwifruit", //"Jackfruit", "Mango", "Olive", "Pear", "Sugar-apple" }; view = (LinearLayout) layoutInflater.inflate(R.layout.subjecttabview, null); //setListAdapter(new ArrayAdapter<String>(this, R.layout.subjecttabview,FRUITS)); } catch(Exception e) { e.printStackTrace(); } } if(tag.equals("tabTwoSpec")) { try { view = (LinearLayout) layoutInflater.inflate(R.layout.chaptertabview, null); } catch(Exception e) { e.printStackTrace(); } } return view; } } How to add ListActivity in this TabActivity

    Read the article

< Previous Page | 305 306 307 308 309 310 311 312 313 314 315 316  | Next Page >