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  • Printable Version of Google Visualizations DataTable

    - by maleki
    I have a custom routing application that takes information for a route from google maps. It then creates a Google Visualizations DataTable to hold all the steps in the route. My current problem is that in order to reduce overflow for very large routes, I have enabled paging in the options of the DataTable. This leads to a not so printer friendly version because only the portion of the data that is shown in the table will be printed. The other portions of the table are loaded dynamically by the API when you click prev and next. Is there a not so hard way to get the DataTable to be printer friendly when it comes time without sacrificing the ability to have paging enabled?

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  • How to code a 'Next in Results' within search results in PHP

    - by thebluefox
    Right, bit of a head scratcher, although I've got a feeling there's an obvious answer and I'm just not seeing the wood for the trees. Baiscally, using Solr as a search engine for my site, bringing back 15 results per page. When you click on a result, you get a detail page, that has a "Next in Results" link on it, which obviously forwards you on to the next result. Whats the best way of doing this? I've come up with a few solutions but they're either too inpractical or just don't work. I could store all the ids in a session array, then grab the one after the current one and put that in the link. But with possibly hundreds/thousands of results, the memory that array would need, and the performance hit of dealing with it isn't practical. I could take the same approach and put it into the db, but I'll still have to deal with a potentially huge array when I grab them out of the db. Or; I could do the search again, only returning the id's, and grab the one after the one we're currently looking at. I think this could be the best option? Although it does seem kind of messy, namely because of when I have to select the id thats on a different 'page' (ie the 16th, 31st etc result). Unless I pass through where it was in the results, and select from there, but that still doesn't seem like the right way to do it. I'm really sorry if this is just complete nonsense, any help is massively appreciated as always, Cheers guys!

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  • How do i make divs go into another row when full?

    - by acidzombie24
    My code is something like the below. When theres 3 images everything is fine once theres 4 it gets full and moves the entire div.top into another row. How do i make the div inside top just start a new row instead? I tried writing .top width=500px but once it hits or passes it instead the images inside are squeeze together instead of each being 150x150. I tried max-width on top instead and in opera and chrome i see the border of top as 500width but the images continue to render pass it. (i have a firefox problem with my div so the width looks fixed to something else). So how do i make these divs go into another row? and not try to squeeze together <div class="top"> <div><a href><img/></a></div> <div><a href><img/></a></div> <div><a href><img/></a></div> </div>

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  • CSS: How to affect OTHER elements when a div is hovered

    - by Trufa
    I think this is a very basic question but I not sure how/if it can be done. What I want to do is to is a certain div is hovered, affect the properties of another div. For example, in this simple example when you hover over #cube it changes the background-color but what I that when I hover over #container, #cubeis affected. I don't want to explain further cause I think it might be confusing, but please ask the the question is no clear enough!! Thanks in advance!! jQueriers: abstain yourselves!! only CSS answers :)

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  • Modular GWT design concerns

    - by GlGuru
    Hi, I have a couple of questions regarding a modular GWT based application framework. I have some ideas about them but being new to the field of web development I feel they are far from ideal. I'd appreciate a few comments and suggestions in this regard. Here are my questions: I am developing a framework which will allow third parties to embed GWT applications into our website and do some communication with them using simple iFrame postMessage. All these third party modules are going to use our SDK which is also GWT based. The problem arises that even though all the modules will be using the same codebase there is going to be a massive overheard in the amount of duplicate Javascript code (i.e. our common SDK code base which is quite large) being downloaded on the client's machine. This is highly redundant and problematic, not only due to the sheer size of duplicate code but, also due to the fact that subsequent updates of the SDK would require the modules to be recompiled which is going to create a DLL hell kind of scenario in the long run. What is the best way of doing this kind of thing? Is there a way where I can have some static GWT code (i.e. the SDK) and the dynamic GWT module refers to it (even if lies on a different domain) and it all work happily? The other part of the problem lies in providing robust scripting front end to the SDK. At first it appears to be trivial since Javascript itself is a scripting language. However, I do not know how to load and call a piece of pure Javascript code at runtime? I am willing to put restrictions on the target Javascript (i.e. having a function main and unique namespace or something). Furthermore the Javascript will come as a string from a database and not as a full URL. If its doable in Javascript how does one get this right in GWT i.e. forcing the compiler to emit a certain function in the generated Javascript? This I believe can be lesser of a problem by having a stub Javascript with all the right requirements which just loads up a GWT generated Javascript. Is any of this possible at all? I generally hate to be this verbose but I hope to find a quick solution to the problem as its holding up my progress. I'd highly appreciate any comments, suggestions and experiences.

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  • Overflow in table cells

    - by Ezdaroth
    I need to create a chat layout that uses all the available space and scales nicely, but has few fixed sizes. Here's the structure: <table style="width: 100%; height: 100%"> <tr> <td></td> <td style="width: 200px; background: red;"></td> </tr> <tr> <td style="height: 100px; background: blue"></td> <td></td> </tr> </table> However, I want to place a lot of content in the first table cell and I want it to scroll, so it won't expand the table. Is it possible to make it overflow properly, without having a fixed height for the cell? Simply adding overflow: auto doesn't seem to work. PS. I hate tables, but can't figure out a very clean and cross-browser way to do a layout like this with divs and css. If someone can come up with one, I'll gladly use it.

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  • Table-cell property ignores width

    - by user1251698
    I have set a CSS propery table-cell for a div. I have also specified the width for the div and set overflow hidden. But because of the table-cell property the div does not care about the width. If I place any large image, it goes out of the width. How can i use the table-cell and use the fixed width for the div? .right{ display: table-cell; overflow: hidden !important; vertical-align: top; width: 400px; }

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  • How do I get a div to float to the bottom of its container?

    - by Stephen Martin
    I have floated images and inset boxes at the top of a container using float:right (or left) many times. Recently I hit a need to float a div at the bottom right corner of another div with the normal text wrap that you get with float (text wrapped above and to the left only). I thought this must be relatively easy even though float has no bottom value but I haven't been able to do it using a number of techniques and searching the web hasn't come up with anything other than using absolute positioning but this doesn't give the correct word wrap behaviour. I had thought this would be a very common design but apparently it isn't. If nobody has a suggestion I'll have to break my text up into separate boxes and align the div manually but that is rather precarious and I'd hate to have to do it on every page that needs it.

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  • Blogger Code Image linking to post page

    - by Jm Agas
    Is this possible to achieve in blogger? My goal is to make Static page images to become clickable and link it to the actual post page. I know its possible by editing each post but I want to make it automatic. For example: In 9gag.com when you click the image from the homepage it will actually link you to the post page. I want to do the same but in blogger. Something like this <b:if cond='data:blog.pageType != &quot;static_page&quot;'><a expr:href='data:post.url'><static page images></a></b:if> Screenshot: http://i.stack.imgur.com/YAWkL.jpg

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  • Can I pop up alert in javascript using php.

    - by Shantanu Gupta
    I want to trigger javascript alert using PHP. Is it possible I want to use it in head section, for displaying it at load time. <head> <?php $valid="valid"; if(!isset($valid)) echo "<script type=\"text/javascript\"> alert('Hi');</script>"; ?> </head> EDIT i want to display javascript alert() at load time after checking existance of session

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  • Floats not staying inside div in webkit browser, but do if cached.

    - by Shadi Almosri
    Hiya All, I have a rather strange bug which i can't make sense of that is apearing in webkit based browsers (chrome and safari). When this page http://bluprintliving.mammalworld.com/turnmill-street loads for the first time the content seems to jump out of the container but only at the end of the render. on refresh it stays in and behaves. Generally the page in cache and out of cache looks different. Anyone have any ideas or clues they can shed on this issue? Much appreciated. Shadi ** Update ** Bug appears in: Chrome: 4.1.249.1064 (45376) Chromium: 5.0.349.0 (40908) Safari: 4.0.5 (531.22.7)

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  • How can I created PDF output from rrdcgi?

    - by Octopus
    I have created a rrdcgi script to display information about the system performance with graphs. Now I would like to add an option for the users to create PDF on the fly with the details on current page (images and information) and header and footer. I also want the generated PDF files to be saved in some location so that that can be easily accessed next time. Is this possible to do with rrdcgi or any perl code would be really appreciated. I need this options

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  • Page content layout issues

    - by Prupel
    I'm designing a theme for a blog and I'm having some trouble trying to get a layout working. Here's an image of what I want. This diagram represents the individual posts and not the website itself, so it will be contained in a box of it's own, lets call it .container. Also the purple and green are in another box, let's call it .content. The other elements will be called by their color for now. so here's more or less what the CSS looks like: .container { display:block; margin:0 25px; } .gray, .blue, .content { display:block; width:100%; } .purple { display:inline-block; width:125px; height:100%; text-align:center; } .green { display:inline-block; } That's all there is at the moment. I tried float but that made no effect. What's happening is something like this. Here's a few more things you should know: .container's width is NOT set it is auto .purple and .green don't necessarily need to be the same size as long as .green doesn't go to that side. .purple CAN have a set height .green is where the meat is, that's where the actual post goes, keep that in mind. I don't think tables will help, the problem is inside .content.

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  • Echo mysql results in a loop?

    - by Roy D. Porter
    I am using turn.js to make a book. Every div within the 'deathnote' div becomes a new page. <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page </div> //ends book What I am doing is trying to get 3 'content' (content being a name and cause of death) divs onto 1 page, and then generate a new page. So here is what i want: <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"> //creates new page but leaves it open <div> CONTENT </div> <div> CONTENT </div> <div> CONTENT </div> </div> //ends the page </div> //ends book Seems simple enough, however the content is data from a MySQL DB, so i have to echo it in using PHP. Here is what i have so far <div id="deathnote"> <div style="background-image:url(images/coverpage.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <?php $pagecount = 0; $db = new mysqli('localhost', 'username', 'passw', 'DB'); if($db->connect_errno > 0){ die('Unable to connect to database [' . $db->connect_error . ']'); } $sql = <<<SQL SELECT * FROM `TABLE` SQL; if(!$result = $db->query($sql)){ die('There was an error running the query [' . $db->error . ']'); } //IGNORE ALL OF THE GARBAGE ABOVE. IT IS SIMPLE CONNECTING SCRIPT THAT I KNOW WORKS //THE METHOD I AM HAVING TROUBLE WITH IS BELOW $pagecount = 0; while($row = $result->fetch_assoc()){ //GETS THE VALUE (and makes sure it isn't nothing echo '<div style="background-image:url(images/paper.jpg);">'; //THIS OPENS A NEW PAGE while ($pagecount !== 3) { //KEEPS COUNT OF HOW MUCH CONTENT DIVS IS ON THE PAGE while($row = $result->fetch_assoc()){ //START A CONTENT DIV echo '<div class="content"><div class="name">' . $row['victim'] . '</div><div class="cod">' . $row['cod'] . '</div></div>'; //END A CONTENT DIV $pagecount++; //UP THE PAGE COUNT } } $pagecount=0; //PUT IT BACK TO 0 echo '</div>'; //END PAGE } $db->close(); ?> <div style="background-image:url(images/backpage.jpg);"></div> //BACK PAGE </div> At the moment i seem to be causing and infinite loop so the page won't load. The problem resides within the while loops. Any help is greatly appreciated. Thanks in advance guys. :)

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  • IE7,8 Alpha PNG fade

    - by dclowd9901
    Does anyone know what is causing this issue? http://i.imgur.com/z1pzh.png The div in question has a solid 1x1 alpha opaque png repeating in its background-image property, and it's supposed to be all one bg color, not that fading effect. It doesn't appear in FF, Opera or Chrome. If you need more details, I can provide some CSS, but I assure you the CSS is in order. If someone doesn't just out-and-out know why this is happening, they more than likely won't find an answer looking in the code.

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  • possible to auto zoom out if user's resolution < x ?

    - by Haroldo
    my site is aimed purely at the laptop market (dont ask why or argue!), all my users (or 95%+) we on a screen width of 1200+, netbooks are now taking off, with a resolution of 1024 wide. my site still looks great on a netbook if you zoom out once (ctrl-minus), but i don't want to rely on users knowing about ctrl-minus. what are my options besides redesign? I'm keen not to have zoom buttons on my page. is there a javascript zoomer outer?!!!

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  • In the following list, how do I prevent jQuery from interacting with part of it.

    - by kylex
    I have the following list structure: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> with the following jQuery: $("ul>li>ul").hide(); $("ul>li>ul>li>ul").hide(); $("ul>li>ul>li>ul>ul>li").hide(); $('.active').parents().show();????????? $("ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); $("ul>li>ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); What I would like is this: When an li class is topActive, everything within that class down to the current class can not be affected by the jQuery that causes the list to slide up and down. so in the case provided the following would show, along with the top level: One Two Two-1 Two-2 Three And when I mouse over either, Two, or Two-1 or Two-2 nothing happens, but if I mouse over Three, the jQuery will cause it to slide up or slide down. In this example: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> When I mouseover Two-1, it will slide down, but when I mouse out Two-1 will remain. One Two Two-1 Two-2 Three Any suggestsions for either a CSS or jQuery implementation (or mixture of the two)?

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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • SetInterval missing property in js class

    - by sebastian
    I wrote simple class in JS witch works, but i had problem when i try use setInterval with it. Ex. if i do something like that ball = new ball(5,10,0, '#canvas'); ball.draw(); ball.draw(); ball.draw(); ball.draw(); It works. But this: ball = new ball(5,10,0, '#canvas'); setInterval(ball.draw, 100); Not work. I get error that values are undefined. function ball (x,y,z,holdingEl) { this.r = 5; //zmienna przechowujaca promien pilki this.size = this.r *2; // zmienna przechowujaca rozmiar this.ballSpeed = 100; // predkosc pilki this.ballWeight = 0.45; // masa pilki this.maxFootContactTime = 0.2; // maksymalny czas kontaktu pilki z noga - stala this.ctx = jQuery(holdingEl)[0].getContext("2d"); // obiekt pilki this.intVal = 100 // predkosc odswiezania this.currentPos = { // wspolrzedne pozycji x: x, y: y, z: z } this.interactionPos = { // wspolrzedne pozycji ostatniej interakcji x: -1, y: -1, z: -1 } this.direct = { // kierunek w kazdej plaszczyznie x : 1, y : 0, z : 0 } this.draw = function (){ this.ctx.clearRect(0,0,1100,800); this.ctx.beginPath(); this.ctx.arc(this.currentPos.x, this.currentPos.y, this.r, 0, Math.PI*2, true); this.ctx.closePath(); this.ctx.fill(); } }

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  • CSS Forms/Input Maniuplation

    - by user983969
    input:required{ background-color:#f00; } input:required label{ color: #FF3434; } I have the above CSS code currently for my form, I want to be able to make the label red when the field is required. My input field is: <label for="frmComTelephone">Telephone</label> <input type="number" name="Telephone" id="frmComTelephone"/> But that CSS isn't working how do I solve this? 2ND problem is I have the following CSS: input:focus { background-color:yellow; } input[type="text"], input[type="date"],input[type="time"],input[type="number"],textarea,select { border-radius:5px; border-width: 1px; border-style: solid; border-color: #C6C6C6; height:41px; background-color: #FF3434; width: 100%; } But when the item is focused it doesn't change to yellow, if i remove "background-color: #FF3434;" it turns yellow on focus? Is what I am doing not able to be done? Or am I going about this wrong? Thanks

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