PHP & WP: Render Certain Markup Based on True False Condition
- by rob
So, I'm working on a site where on the top of certain pages I'd like to display a static graphic and on some pages I would like to display an scrolling banner.
So far I set up the condition as follows:
<?php
$regBanner = true;
$regBannerURL = get_bloginfo('stylesheet_directory'); //grabbing WP site URL
?>
and in my markup:
<div id="banner">
<?php
if ($regBanner) {
echo "<img src='" . $regBannerURL . "/style/images/main_site/home_page/mock_banner.jpg' />";
}
else {
echo 'Slider!';
}
?>
</div><!-- end banner -->
In my else statement, where I'm echoing 'Slider!' I would like to output the markup for my slider:
<div id="slider">
<img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/1.jpg" alt="" />
<img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/2.jpg" alt="" />
<img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/3.jpg" alt="" />
.............
</div>
My question is how can I throw the div and all those images into my else echo statement? I'm having trouble escaping the quotes and my slider markup isn't rendering.
