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  • C++ function-pointer and inheritance

    - by pingvinus
    In parent class I have function, that operates under an array of functions, declared in child-class, number of functions for every child-class may vary. But since every function uses some object-variables, I can't declare them as static. I've try to do something like this: class A { public: typedef int (A::*func)(); func * fs; void f() { /*call functions from this->fs*/ } }; class B : public A { public: int smth; B(int smth) { this->smth = smth; this->fs = new func[1]; fs[0] = &B::f; } int f() { return smth + 1; } }; But, obviously it doesn't work. Any suggestions?

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  • Rails Model for Playlist that can contain tracks and albums using polymorphism

    - by philk
    I struggle to find a model how to store a playlist with different type of items on it in Rails. Consider I have class Track end class Album has_many :tracks end class PlaylistItem belongs_to :playable belongs_to :playlist end class Playable belongs_to :playable, :polymorph => true end class Playlist has_many :playlist_items end I think I can use a polymorphic model "Playable" here since the Playlist can contain Tracks, Albums and maybe in the future also Movies. Also I would like to use STI for Track and Albums since they share some common attributes like title and length but also have totally different attributes. I modeled it like described here but it does not work. Anybody any idea how to model a Playlist that can contain many items of different kind?

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  • Guice ThrowingProvider problem

    - by KARASZI István
    According to the ThrowingProvider documentation of Guice I have the following interface: public interface IConfigurableProvider<T> extends ThrowingProvider<T, ConfigException> {} I have multiple classes that implements this interface, let assume I have the following: public class SomethingProvider extends ConfiguredProvider implements IConfigurableProvider<Something> {} Of course this class implements the necessary method: public Something get() throws ConfigException { /* ... */ } In my module, I have the following code in MyModule.java ThrowingProviderBinder.create(binder()) .bind(IConfigurableProvider.class, Something.class) .to(SomethingProvider.class); But when I start my application the following error produced: 6) No implementation for com.package.Something was bound. while locating com.package.Something for parameter 5 at com.package.OtherClass.<init>(OtherClass.java:78) at com.package.MyModule.configure(MyModule.java:106) I don't really know where should I start looking for the bug.

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  • Tab on hover mode while mouse over drop down menu

    - by Hwang
    How could I have the tab to be on hover mode while I rollover the drop down sub-menu. Does it require javascript or it could be done solely on CSS? <li id="anchor" class="title dropdown"><a href="#">Main Tab</a> <div class="column"> <ul> <li class="subtitle">Button 1</li> <li class="subtitle">Button 2</li> <li class="subtitle">Button 3</li> </div> </li>

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  • Why my :hover aren't working?

    - by user1628488
    I have am nav, and when i hover some elements, the submenu should be displayed 'block', but this dont work. See <!doctype html> <html lang="pt-br"> <head> <meta charset="utf-8" /> <meta name="robots" content="noindex, nofollow" /> <meta name="generator" content="Notepad++" /> <meta name="author" content="Erick Ribeiro" /> <meta http-equiv="refresh" content="60" /> <title>Mozilla Firefox</title> <style type="text/css"> *{ font-family: calibri; } #menu { float: left; } .submenu { margin-top: 26px; padding: 10px; border: solid 1px rgb(224, 224, 224); background: rgb(254, 254, 254); color: rgb(0, 128, 224); border-radius: 0 0 4px 4px; } #menuHome:hover ~ #submenuControle { display: block; opacity: 0; color: red; } #submenuHome { display: none; opacity: 0; } #submenuControle { display: block; opacity: 1; } #submenuGestão { display: none; opacity: 0; } #submenuRL { display: none; opacity: 0; } #submenuSI { display: none; opacity: 0; } ul { float: left; list-style-type: none; padding: 0; margin: 0; } li { display: inline; float:left; } .primeiroItem { border: solid rgb(224, 224, 224); border-top-width: 1px; border-right-width: 1px; border-bottom-width: 1px; border-left-width: 1px; border-radius: 4px 0 0 4px; } .naoPrimeiroItem { border: solid rgb(224, 224, 224); border-top-width: 1px; border-right-width: 1px; border-bottom-width: 1px; border-left-width: 0; } .ultimoItem { border: solid rgb(224, 224, 224); border-top-width: 1px; border-right-width: 1px; border-bottom-width: 1px; border-left-width: 0; border-radius: 0 4px 4px 0; } a { text-decoration:none; padding: 8px; border: solid 1px; color: rgb(0, 0, 0); background: rgb(240,240, 240); } a:visited { color: rgb(0, 0, 0); } </style> <script type="text/javascript"> </script> </head> <body> <nav id="menu"> <ul> <li><a id="menuHome" class="primeiroItem" href="#">Home</a></li> <li><a id="menuControle" class="naoPrimeiroItem" href="#">Controle</a></li> <li><a id="menuGestao" class="naoPrimeiroItem" href="#">Gestão</a></li> <li><a id="menuRL" class="naoPrimeiroItem" href="#">Relatórios e Listas</a></li> <li><a id="menuSI" class="ultimoItem" href="#">Sistema Informação</a></li> </ul> <div id="submenuHome" class="submenu"> </div> <div id="submenuControle" class="submenu"> BSC Comunicação Treinamento Documentos Controle de Acesso </div> <div id="submenuGestão" class="submenu"> ASV Treinamento Suprimentos Chamados</div> <div id="submenuRL" class="submenu"> Listas Relatórios </div> <div id="submenuSI" class="submenu"> </div> </nav> </body> </html>

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  • Setting a preferred item of a many-to-one in Django

    - by Mike DeSimone
    I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

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  • What's the preferred way to use helper methods in Ruby?

    - by DR
    Disclaimer: Although I'm asking in context of a Rails application, I'm not talking about Rails helpers (i.e. view helpers) Let's say I have a helper method/function: def dispatch_job(job = {}) #Do something end Now I want to use this from several places (mostly controllers, but also a few BackgrounDRb workers) What's the preferred way to do this? I can think of two possibilities: 1. Use a class and make the helper a static method: class MyHelper def self.dispatch_job(job = {}) end end class MyWorker def run MyHelper.dispatch_job(...) end end 2. Use a module and include the method into whatever class I need this functionality module MyHelper def self.dispatch_job(job = {}) end end class MyWorker include MyHelper def run dispatch_job(...) end end 3. Other possibilities I don't know yet ... The first one is more Java-like, but I'm not sure if the second one is really an appropriate use of Ruby's modules.

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  • Java cannot find symbol enum

    - by JDelage
    Hi, I'm modeling a chess game on Java, and I'm having some problem. Here's what the code looks like (the relevant parts): Enum class Couleur.java: public enum Couleur {BLANC, NOIR} Piece.java: public abstract class Piece { (...) public Piece(Couleur couleurParam){ this.couleurPiece = couleurParam; } (...) } And finally Tour.java: public class Tour extends Piece { (...) public Tour(Couleur couleurParam){ super(couleurParam); } (...) } All the .java files are in the same folder. Yet at compile I get a "cannot find symbol symbol : variable NOIR location: class Plateau" (Plateau is the class that instantiates Tour.) Can anyone help me figure out what's wrong here? Many thanks, JDelage

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  • Visual-C++ Linker Error

    - by LordByron
    I have a class called MODEL in which public static int theMaxFrames resides. The class is defined in its own header file. theMaxFrames is accessed by a class within the MODEL class and by one function, void set_up(), which is also in the MODEL class. The Render.cpp source file contains a function which calls a function in the Direct3D.cpp source file which in turn calls the set_up() function through a MODEL object. This is the only connection between these two source files and theMaxFrames. When I try to compile my code I get the following error messages: 1Direct3D.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1Render.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1C:\Users\Byron\Documents\Visual Studio 2008\Projects\xFileViewer\Debug\xFileViewer.exe : fatal error LNK1120: 1 unresolved externals

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  • Does importing of packages change visibility of classes?

    - by Roman
    I jsut learned that A class may be declared with the modifier public, in which case that class is visible to all classes everywhere. If a class has no modifier (the default, also known as package-private), it is visible only within its own package. This is a clear statement. But this information interfere with my understanding of importing of packages (which easily can be wrong). I thought that importing a package I make classes from the imported package visible to the importing class. So, how does it work? Are public classes visible to all classes everywhere under condition that the package containing the public class is imported? Or there is not such a condition? What about the package-private classes? They are invisible no mater if the containing package was imported or not? ADDED: It seems to me that I got 2 answers which are marked as good (up-voted) and which contradict eachother.

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  • How is this statement making sense? (Sun's naming convention for Java variables)

    - by polygenelubricants
    I've been quoting this segment from Sun's document for the past few days, and only now do I stop and think about what it's saying, and I can't make sense out of it. Please keep in mind that English is not my first language. Naming conventions Variables: Except for variables, all instance, class, and class constants are in mixed case with a lowercase first letter. How is this making sense? Isn't this saying that class names are in mixed case with a lowercase first letter? Like I should name it class myClass? And class constants are also in mixed case with a lowercase first letter? Like I should name it Integer.maxValue? And is it really saying anything about how variables themselves should be named? Am I not parsing this properly or is this actually a blatant error?

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  • C++: How to use types that have not been defined?

    - by Jen
    C++ requires all types to be defined before they can be used, which makes it important to include header files in the right order. Fine. But what about my situation: Bunny.h: class Bunny { ... private: Reference<Bunny> parent; } The compiler complains, because technically Bunny has not been completely defined at the point where I use it in its own class definition. This is not sufficient: class Bunny; class Bunny { ... private: Reference<Bunny> parent; } Apart from re-writing my template class Reference so it takes a pointer type (in which case I can use the forward declaration of Bunny), I don't know how to solve this. Any suggestions?

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  • How to remove hyperlink but keep text for an array of links?

    - by Keith Donegan
    My question is fairly similar to this question: Remove hyperlink but keep text? but, I can't seem to workout how I can feed an array of class names and do this in one go? For Example <a class="unwrap" href="#">Blah</a> <a class="unwrap" href="#">Blah</a> <a href="#">Blah</a> <a class="unwrap" href="#">Blah</a> I would just like the links with the unwrap class to be modified.

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  • PHP Magic methods not working

    - by user991047
    I am trying to create a registry class with magic __set and __get my class looks like class Registry { private $vars = array(); public function __set($key, $value) { $this->vars[$key] = $value; dump($key, $value); } public function __get($index) { $this->vars[$index]; } } but if i try to save some variable in registry class in gets only the $key the $value is alway NULL. here is the sample code how I am try to call this class $registry = new registry; $registry->router = $router; $registry->title = "Welcome ";

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  • Should the name of my classes begin with 'Q' in Qt?

    - by Venemo
    Hello Everyone, When I first started working with Qt, it was extremely annoying that every class has a name beginning with 'Q', but now I've got used to it. I'm using Qt Creator, and it highlights code quite well. However, it only highlights class names beginning with 'Q'. And it highlights everything beginning with 'Q' even if there is no such type. It doesn't highlight custom class names. That makes me wonder, should I also begin all my class names with 'Q'? Or at least the reusable ones? (I mean, those that I put in a class library, or reuse in another app.) I've seen several places where they named their classes this way. Is it a good thing? I found this page about Qt's naming conventions, but it doesn't deal with this question. Also, I don't understand why Qt doesn't use namespaces.

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  • JPA 2.1 Schema Generation (TOTD #187)

    - by arungupta
    This blog explained some of the key features of JPA 2.1 earlier. Since then Schema Generation has been added to JPA 2.1. This Tip Of The Day (TOTD) will provide more details about this new feature in JPA 2.1. Schema Generation refers to generation of database artifacts like tables, indexes, and constraints in a database schema. It may or may not involve generation of a proper database schema depending upon the credentials and authorization of the user. This helps in prototyping of your application where the required artifacts are generated either prior to application deployment or as part of EntityManagerFactory creation. This is also useful in environments that require provisioning database on demand, e.g. in a cloud. This feature will allow your JPA domain object model to be directly generated in a database. The generated schema may need to be tuned for actual production environment. This usecase is supported by allowing the schema generation to occur into DDL scripts which can then be further tuned by a DBA. The following set of properties in persistence.xml or specified during EntityManagerFactory creation controls the behaviour of schema generation. Property Name Purpose Values javax.persistence.schema-generation-action Controls action to be taken by persistence provider "none", "create", "drop-and-create", "drop" javax.persistence.schema-generation-target Controls whehter schema to be created in database, whether DDL scripts are to be created, or both "database", "scripts", "database-and-scripts" javax.persistence.ddl-create-script-target, javax.persistence.ddl-drop-script-target Controls target locations for writing of scripts. Writers are pre-configured for the persistence provider. Need to be specified only if scripts are to be generated. java.io.Writer (e.g. MyWriter.class) or URL strings javax.persistence.ddl-create-script-source, javax.persistence.ddl-drop-script-source Specifies locations from which DDL scripts are to be read. Readers are pre-configured for the persistence provider. java.io.Reader (e.g. MyReader.class) or URL strings javax.persistence.sql-load-script-source Specifies location of SQL bulk load script. java.io.Reader (e.g. MyReader.class) or URL string javax.persistence.schema-generation-connection JDBC connection to be used for schema generation javax.persistence.database-product-name, javax.persistence.database-major-version, javax.persistence.database-minor-version Needed if scripts are to be generated and no connection to target database. Values are those obtained from JDBC DatabaseMetaData. javax.persistence.create-database-schemas Whether Persistence Provider need to create schema in addition to creating database objects such as tables, sequences, constraints, etc. "true", "false" Section 11.2 in the JPA 2.1 specification defines the annotations used for schema generation process. For example, @Table, @Column, @CollectionTable, @JoinTable, @JoinColumn, are used to define the generated schema. Several layers of defaulting may be involved. For example, the table name is defaulted from entity name and entity name (which can be specified explicitly as well) is defaulted from the class name. However annotations may be used to override or customize the values. The following entity class: @Entity public class Employee {    @Id private int id;    private String name;     . . .     @ManyToOne     private Department dept; } is generated in the database with the following attributes: Maps to EMPLOYEE table in default schema "id" field is mapped to ID column as primary key "name" is mapped to NAME column with a default VARCHAR(255). The length of this field can be easily tuned using @Column. @ManyToOne is mapped to DEPT_ID foreign key column. Can be customized using JOIN_COLUMN. In addition to these properties, couple of new annotations are added to JPA 2.1: @Index - An index for the primary key is generated by default in a database. This new annotation will allow to define additional indexes, over a single or multiple columns, for a better performance. This is specified as part of @Table, @SecondaryTable, @CollectionTable, @JoinTable, and @TableGenerator. For example: @Table(indexes = {@Index(columnList="NAME"), @Index(columnList="DEPT_ID DESC")})@Entity public class Employee {    . . .} The generated table will have a default index on the primary key. In addition, two new indexes are defined on the NAME column (default ascending) and the foreign key that maps to the department in descending order. @ForeignKey - It is used to define foreign key constraint or to otherwise override or disable the persistence provider's default foreign key definition. Can be specified as part of JoinColumn(s), MapKeyJoinColumn(s), PrimaryKeyJoinColumn(s). For example: @Entity public class Employee {    @Id private int id;    private String name;    @ManyToOne    @JoinColumn(foreignKey=@ForeignKey(foreignKeyDefinition="FOREIGN KEY (MANAGER_ID) REFERENCES MANAGER"))    private Manager manager;     . . . } In this entity, the employee's manager is mapped by MANAGER_ID column in the MANAGER table. The value of foreignKeyDefinition would be a database specific string. A complete replay of Linda's talk at JavaOne 2012 can be seen here (click on CON4212_mp4_4212_001 in Media). These features will be available in GlassFish 4 promoted builds in the near future. JPA 2.1 will be delivered as part of Java EE 7. The different components in the Java EE 7 platform are tracked here. JPA 2.1 Expert Group has released Early Draft 2 of the specification. Section 9.4 and 11.2 provide all details about Schema Generation. The latest javadocs can be obtained from here. And the JPA EG would appreciate feedback.

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  • jQuery append div to a specific

    - by ip
    Hi How do I append a element a specific index of the children elements using jQuery append e.g. if I have: <div class=".container"> <div class="item"><div> <div class="item"><div> <div class="item"><div> <div class="item"><div> </div> and I want to append another item between the second and third item?

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  • jQuery slideUp and slideDwon issues

    - by Alex
    I need the classes 'two and three' to be hidden as soon as the page load and than be able to click again on the menu to slide it down, I am having probles with the following code: $(document).ready(function() { $('.two, .three').slideUp('slow'); $('.active_wrapper').click(function(){ $('.two, .three').slideDown('slow'); }); }); HTML <div class="nav_wrapper"> <div class="active_wrapper one"><a class="active" href="">home</a></div> <div class="two"><a href="about.html">about</a></div> <div class="three"><a href="project.html">project</a></div> </div>

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  • Escaping if/else in Jade template

    - by Collin Estes
    So I have a simply block of html in my jade template with a loop: each dude, i in dudes div(class='someClass') div.otherStuff span.someContent #{name} I want to apply a data attribute to my top most div when a certain looping condition is met, in this case the first dude, I set it up like this each dude, i in dudes if i == 0 div(class='someClass, data-someAttr='first dude') else div(class='someClass') div.otherstuff span.someContent Setup like this it causes the div.otherStuff div and the span.someContent to only display on the else condition. I've moved the tab spaces around on those items but I can't get it escape that else and give the div.otherStuff and span.someContent to both the first dude and the subsequent dudes after that. I've also tried setting that data attr to a variable and trying to apply it that way but without any success. What I end up doing to get around it is this: each dude, i in dudes if i == 0 div(class='someClass, data-someAttr='first dude') div.otherstuff span.someContent else div(class='someClass') div.otherstuff span.someContent How do I escape that if/else so I dont have to duplicate the div.otherStuff and span.someContent?

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  • What is the best way to "override" enums?

    - by Tyler
    I have a number of classes which extend an abstract class. The abstract parent class defines an enum with a set of values. Some of the subclasses inherit the parent class's enum values, but some of the subclasses need the enum values to be different. Is there any way to somehow override the enum for these particular subclasses, and if not, what is a good way to achieve what I'm describing? class ParentClass { private MyEnum m_EnumVal; public virtual MyEnum EnumVal { get { return m_EnumVal; } set { m_EnumVal = value; } } public enum MyEnum { a, b, c }; } class ChildClass : ParentClass { private MyEnum m_EnumVal; public virtual MyEnum EnumVal { get { return m_EnumVal; } set { m_EnumVal = value; } } public enum MyEnum { d, e, f }; }

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  • Global variables in hadoop.

    - by Deepak Konidena
    Hi, My program follows a iterative map/reduce approach. And it needs to stop if certain conditions are met. Is there anyway i can set a global variable that can be distributed across all map/reduce tasks and check if the global variable reaches the condition for completion. Something like this. While(Condition != true){ Configuration conf = getConf(); Job job = new Job(conf, "Dijkstra Graph Search"); job.setJarByClass(GraphSearch.class); job.setMapperClass(DijkstraMap.class); job.setReducerClass(DijkstraReduce.class); job.setOutputKeyClass(IntWritable.class); job.setOutputValueClass(Text.class); } Where condition is a global variable that is modified during/after each map/reduce execution.

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  • Deserializing only select properties of an Entity using JDOQL query string?

    - by user246114
    Hi, I have a rather large class stored in the datastore, for example a User class with lots of fields (I'm using java, omitting all decorations below example for clarity): @PersistenceCapable class User { private String username; private String city; private String state; private String country; private String favColor; } For some user queries, I only need the favColor property, but right now I'm doing this: SELECT FROM " + User.class.getName() + " WHERE username == 'bob' which should deserialize all of the entity properties. Is it possible to do something instead like: SELECT username, favColor FROM " + User.class.getName() + " WHERE username == 'bob' and then in this case, all of the returned User instances will only spend time deserializing the username and favColor properties, and not the city/state/country properties? If so, then I suppose all the other properties will be null (in the case of objects) or 0 for int/long/float? Thank you

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  • Can't append to second container

    - by George Katsanos
    I have the following script: (function($) { $.fn.easyPaginate = function(options){ var defaults = { step: 4, delay: 100, numeric: true, nextprev: true, controls: 'pagination', current: 'current' }; var options = $.extend(defaults, options); var step = options.step; var lower, upper; var children = $(this).children(); var count = children.length; var obj, next, prev; var page = 1; var timeout; var clicked = false; function show(){ clearTimeout(timeout); lower = ((page-1) * step); upper = lower+step; $(children).each(function(i){ var child = $(this); child.hide(); if(i>=lower && i<upper){ setTimeout(function(){ child.fadeIn('fast') }, ( i-( Math.floor(i/step) * step) )*options.delay ); } if(options.nextprev){ if(upper >= count) { next.addClass('stop'); } else { next.removeClass('stop'); }; if(lower >= 1) { prev.removeClass('stop'); } else { prev.addClass('stop'); }; }; }); $('li','#'+ options.controls).removeClass(options.current); $('li[data-index="'+page+'"]','#'+ options.controls).addClass(options.current); if(options.auto){ if(options.clickstop && clicked){}else{ timeout = setTimeout(auto,options.pause); }; }; }; function auto(){ if(upper <= count){ page++; show(); } else { page--; show(); } }; this.each(function(){ obj = this; if(count>step){ var pages = Math.floor(count/step); if((count/step) > pages) pages++; var ol = $('<ol id="'+ options.controls +'" class="pagin"></ol>').insertAfter(obj); if(options.nextprev){ prev = $('<li class="prev">prev</li>') .appendTo(ol) .bind('click', function() { //check to see if there are any more pages in the negative direction if (page > 1) { clicked = true; page--; show(); } }); } if(options.numeric){ for(var i=1;i<=pages;i++){ $('<li data-index="'+ i +'">'+ i +'</li>') .appendTo(ol) .click(function(){ clicked = true; page = $(this).attr('data-index'); show(); }); }; }; if(options.nextprev){ next = $('<li class="next">next</li>') .appendTo(ol) .bind('click', function() { //check to see if there are any pages in the positive direction if (page < (count / 4)) { clicked = true; page++; show(); } }); } show(); }; }); }; })(jQuery); jQuery(function($){ $('ul.news').easyPaginate({step:4}); }); which is a carousel-like plugin that produces this html structure for the navigation: <ol id="pagination" class="pagin"><li class="prev">prev</li><li data-index="1" class="">1</li><li data-index="2" class="">2</li><li data-index="3" class="current">3</li><li class="next stop">next</li></ol> And all I want is to enclose this list in a div. Seems simple, but appendTo doesn't want to cooperate with me, or I'm doing something wrong (I'd appreciate if you would help me understand what that is..) So I'm modifying as such: var ol = $('<ol id="'+ options.controls +'" class="pagin"></ol>'); var tiv = $('<div id="lala"></div>'); ol.appendTo('#lala'); tiv.insertAfter(obj); I know how to chain, but I'm in "debugging" mode trying to understand why I don't get the result I imagine I would get: <div id="lala> <ol id="pagination><li>...... </li></ol> </div> I tried putting some console.log's to see the status of my variables but couldn't find something useful.. I guess there's something with DOM insertion I don't get.

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  • Dart Can't get logging statements to compile

    - by Nate Lockwood
    I'm trying to learn how to implement logging using the examples/tutorial in: http://blog.dartwatch.com/2013/05/campaign-to-use-real-logging-instead-of.html#comment-form But having imported the libraries this line in main will not compile because the class 'PrintHandler' is not recognized and Google has not been a help in this case. My server application consists of a main and three classes. I'm new at Dart. Below I've extracted the logging code that I added. In what library is 'PrintHandler'? Is this a class I need to write? library server; import 'package:logging_handlers/logging_handlers_shared.dart'; import 'package:logging/logging.dart'; final _serverLogger = new Logger("server"); // top level logger void main() { Logger.root.onRecord.listen(new PrintHandler()); // default PrintHandler _serverLogger.fine("Server created"); } class A { } class B { } class C { }

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