Search Results

Search found 13602 results on 545 pages for 'python decorators'.

Page 352/545 | < Previous Page | 348 349 350 351 352 353 354 355 356 357 358 359  | Next Page >

  • How to limit choice field options based on another choice field in django admin

    - by umnik700
    I have the following models: class Category(models.Model): name = models.CharField(max_length=40) class Item(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) class Demo(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) item = models.ForeignKey(Item) In the admin interface when creating a new Demo, after user picks category from the dropdown, I would like to limit the number of choices in the "items" drop-down. If user selects another category then the item choices should update accordingly. I would like to limit item choices right on the client, before it even hits the form validation on the server. This is for usability, because the list of items could be 1000+ being able to narrow it down by category would help to make it more manageable. Is there a "django-way" of doing it or is custom JavaScript the only option here?

    Read the article

  • min() and max() give error: TypeError: 'float' object is not iterable

    - by PythonUser3.3
    markList=[] Lmark=0 Hmark=0 while True: mark=float(input("Enter your marks here(Click -1 to exit)")) if mark == -1: break markList.append(mark) markList.sort() mid = len(markList)//2 if len(markList)%2==0: median=(markList[mid]+ markList[mid-1])/2 print("Median:", median) else: print("Median:" , markList[mid]) Lmark==(min(mark)) print("The lowest mark is", Lmark) Hmark==(max(mark)) print("The highest mark is", Hmark) My program is a basic grade calculator using lists. My program asks the user to input their grades into a list in which it then calculates your average and finds your lowest and highest mark. I have found the average but I can't seem to figure out how to find the lowest and highest grade. Can you please show me pr tell me what to do?

    Read the article

  • Django - The included urlconf doesn't have any patterns in it

    - by unsorted
    My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) I have a folder called urls and a file ajax.py inside. (I also created a blank init.py in the same folder so that urls would be recognized.) This is ajax.py. from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^star/(?P<object_id>\d+)$', 'resume.students.ajax-calls.star'), ) Anyone know what's wrong? This is driving me crazy. Thanks,

    Read the article

  • Custom pyGTK button

    - by Wallter
    I would like to create a button that I can control the look of the button using pyGTK. How would I go about doing this? I would like to be able to point to a new image for each 'state' the button is in (i.e. Pressed, mouse over, normal...etc.)

    Read the article

  • django admin site make CharField a PasswordInput

    - by Paul
    I have a Django site in which the site admin inputs their Twitter Username/Password in order to use the Twitter API. The Model is set up like this: class TwitterUser(models.Model): screen_name = models.CharField(max_length=100) password = models.CharField(max_length=255) def __unicode__(self): return self.screen_name I need the Admin site to display the password field as a password input, but can't seem to figure out how to do it. I have tried using a ModelAdmin class, a ModelAdmin with a ModelForm, but can't seem to figure out how to make django display that form as a password input...

    Read the article

  • SQL Alchemy MVC and cross controller joins

    - by Khorkrak
    When using SQL Alchemy for abstracting your data access layer and using controllers as the way to access objects from that abstraction layer, how should joins be handled? So for example, say you have an Orders controller class that manages Order objects such that it provides getOrder, saveOrder, etc methods and likewise a similar controller for User objects. First of all do you even need these controllers? Should you instead just treat SQL Alchemy as "the" thing for handling data access. Why bother with object oriented controller stuff there when you instead have a clean declarative way to obtain and persist objects without having to write SQL directly either. Well one reason could be that perhaps you may want to replace SQL Alchemy with direct SQL or Storm or whatever else. So having controller classes there to act as an intermediate layer helps limit what would need to change then. Anyway - back to the main question - so assuming you have these two controllers, now lets say you want the list of orders for a certain set of users meeting some criteria. How do you go about doing this? Generally you don't want the controllers crossing domains - the Orders controllers knows only about Orders and the User controller just about Users - they don't mess with each other. You also don't want to go fetch all the Users that match and then feed a big list of user ids to the Orders controller to go find the matching Orders. What's needed is a join. Here's where I'm stuck - that seems to mean either the controllers must cross domains or perhaps they should be done away with altogether and you simply do the join via SQL Alchemy directly and get the resulting User and / or Order objects as needed. Thoughts?

    Read the article

  • How to exit an if clause

    - by Roman Stolper
    What sorts of methods exist for prematurely exiting an if clause? There are times when I'm writing code and want to put a break statement inside of an if clause, only to remember that those can only be used for loops. Lets take the following code as an example: if some_condition: ... if condition_a: # do something # and then exit the outer if block ... if condition_b: # do something # and then exit the outer if block # more code here I can think of one way to do this: assuming the exit cases happen within nested if statements, wrap the remaining code in a big else block. Example: if some_condition: ... if condition_a: # do something # and then exit the outer if block else: ... if condition_b: # do something # and then exit the outer if block else: # more code here The problem with this is that more exit locations mean more nesting/indented code. Alternatively, I could write my code to have the if clauses be as small as possible and not require any exits. Does anyone know of a good/better way to exit an if clause? If there are any associated else-if and else clauses, I figure that exiting would skip over them.

    Read the article

  • load a pickle file from a zipfile

    - by eric.frederich
    For some reason I cannot get cPickle.load to work on the file-type object returned by ZipFile.open(). If I call read() on the file-type object returned by ZipFile.open() I can use cPickle.loads though. Example .... import zipfile import cPickle # the data we want to store some_data = {1: 'one', 2: 'two', 3: 'three'} # # create a zipped pickle file # zf = zipfile.ZipFile('zipped_pickle.zip', 'w', zipfile.ZIP_DEFLATED) zf.writestr('data.pkl', cPickle.dumps(some_data)) zf.close() # # cPickle.loads works # zf = zipfile.ZipFile('zipped_pickle.zip', 'r') sd1 = cPickle.loads(zf.open('data.pkl').read()) zf.close() # # cPickle.load doesn't work # zf = zipfile.ZipFile('zipped_pickle.zip', 'r') sd2 = cPickle.load(zf.open('data.pkl')) zf.close() Note: I don't want to zip just the pickle file but many files of other types. This is just an example.

    Read the article

  • Django: query with ManyToManyField count?

    - by AP257
    In Django, how do I construct a COUNT query for a ManyToManyField? My models are as follows, and I want to get all the people whose name starts with A and who are the lord or overlord of at least one Place, and order the results by name. class Manor(models.Model): lord = models.ManyToManyField(Person, null=True, related_name="lord") overlord = models.ManyToManyField(Person, null=True, related_name="overlord") class Person(models.Model): name = models.CharField(max_length=100) So my query should look something like this... but how do I construct the third line? people = Person.objects.filter( Q(name__istartswith='a'), Q(lord.count > 0) | Q(overlord.count > 0) # pseudocode ).order_by('name'))

    Read the article

  • Chipmunk warning still present with --release

    - by Kaliber64
    I'm using Python27 on Windows 7 64-bit. I downloaded the source for Chipmunk 6.2.x and compiled Pymunk with --release and -c ming32. Almost zero problems. Lots of path not found cause I'm bad. All prints seem to have disappeared but I get spammed with EPA iteration warnings. I've seen a couple discussions but no solutions. Possible chipmunk betas to fix the float errors causing the double truths causing the warning. I picked the latest stable version I think. My program is seriously bogged down with all the prints. class NullDevice(): def write(self, s): pass sys.stdout=NullDevice() Does not disable the C prints .< Any help?

    Read the article

  • How to transfer url parameters to repoze custom predicate checkers

    - by user281521
    I would like to create a repoze custom predicate checker that is capable to access url parameters and validate something. But I would like to use allow_only to set this permission checker in all the controller's scope. Something like: class MyController(BaseController): allow_only = All(not_anonymous(msg=l_(u'You must be logged on')), my_custom_predicate(msg=l_(u'something wrong'))) def index(self, **kw): return dict() then, my_custom_predicate should check the url paramters for every request in every MyController method, and do whatever it do. The problem is just that: how to allow my_custom_predicate to check the url parameters, using it in that way I wrote above.

    Read the article

  • How do I pass a lot of parameters to views in Dango?

    - by Mark
    I'm very new to Django and I'm trying to build an application to present my data in tables and charts. Till now my learning process went very smooth, but now I'm a bit stuck. My pageview retrieves large amounts of data from a database and puts it in the context. The template then generates different html-tables. So far so good. Now I want to add different charts to the template. I manage to do this by defining <img src=".../> tags. The Matplotlib chart is generate in my chartview an returned via: response=HttpResponse(content_type='image/png') canvas.print_png(response) return response Now I have different questions: the data is retrieved twice from the database. Once in the pageview to render the tables, and again in the chartview for making the charts. What is the best way to pass the data, already in the context of the page to the chartview? I need a lot of charts, each with different datasets. I could make a chartview for each chart, but probably there is a better way. How do I pass the different dataset names to the chartview? Some charts have 20 datasets, so I don't think that passing these dataset parameters via the url (like: <imgm src="chart/dataset1/dataset2/.../dataset20/chart.png />) is the right way. Any advice?

    Read the article

  • How can I graph the Lines of Code history for git repo?

    - by dbr
    Basically I want to get the number of lines-of-code in the repository after each commit. The only (really crappy) ways I have found is to use git filter-branch to run "wc -l *", and a script that run git reset --hard on each commit, then ran wc -l To make it a bit clearer, when the tool is run, it would output the lines of code of the very first commit, then the second and so on.. This is what I want the tool to output (as an example): me@something:~/$ gitsloc --branch master 10 48 153 450 1734 1542 I've played around with the ruby 'git' library, but the closest I found was using the .lines() method on a diff, which seems like it should give the added lines (but does not.. it returns 0 when you delete lines for example) require 'rubygems' require 'git' total = 0 g = Git.open(working_dir = '/Users/dbr/Desktop/code_projects/tvdb_api') last = nil g.log.each do |cur| diff = g.diff(last, cur) total = total + diff.lines puts total last = cur end

    Read the article

  • IOError: [Errno 13] Permission denied when trying to read an file in google app engine

    - by mahesh
    I want to read an XML file and parse it, for that I had used SAX parser which requires file as input to parse. For that I had stored my XML file in Entity called XMLDocs with following property XMLDocs Entity Name name : Property of string type content : property of blob type (will contain my xml file) Reason I had to store file like this as I had not yet provide my billing detail to google Now when I try to open this file in my I am getting error of permission denied.. Please help me, what I have to do... You can see that error by running my app at www.parsepython.appspot.com

    Read the article

  • Modern, Non-trivial, Pygame Tutorials?

    - by Gregg Lind
    What are some 'good', non-trivial Pygame tutorials? I realize good is relative. As an example, a good one (to me) is the one that describes how to use pygame.camera. It's recent uses a modern PyGame (1.9) non-trivial, in that it shows how to use it the module for a real application. I'd like to find others. A lot of the ones on the Pygame site are from 1.3 era or earlier! Info on related projects, like Gloss is welcome as well. (If your answer is "read the source of some pygame games", please link to the source of particular ones and note what is good about them)

    Read the article

  • Some jQuery-powered features not working in Chrome

    - by Enchantner
    I'm using a jCarouselLite plugin for creating two image galleries on the main page of my Django-powered site. The code of elements with navigation arrows is generating dynamically like this: $(document).ready(function () { $('[jq\\:corner]').each(function(index, item) { item = $(item); item.corner(item.attr('jq:corner')) }) $('[jq\\:menu]').each(function (index, item) { item = $(item); item.menu(item.attr('jq:menu')) }) $('[jq\\:carousel]').each(function(index, item) { item = $(item); var args = item.attr('jq:carousel').split(/\s+/) lister = item.parent().attr('class') + '_lister' item.parent().append('<div id="'+ lister +'"></div>'); $('#' + lister).append("<a class='nav left' href='#'></a><a class='nav right' href='#'></a>"); toparrow = $(item).position().top + $(item).height() - 50; widtharrow = $(item).width(); $('#' + lister).css({ 'display': 'inline-block', 'z-index': 10, 'position': 'absolute', 'margin-left': '-22px', 'top': toparrow, 'width': widtharrow }) $('#' + lister + ' .nav.right').css({ 'margin-left': $('#' + lister).width() + 22 }) item.jCarouselLite({ btnNext: '#' + lister + ' .nav.right', btnPrev: '#' + lister + ' .nav.left', visible: parseInt(args[0]) }) }) The problem is that if page is loaded through an url, typed in the adress bar, some functions doesn't work and the second gallery appears with the wrong parameters, but if I came to this page via clicking link - everything works perfectly. It happends only in Google Chrome (Ubuntu, stable 5.0.360.0), but not in Firefox or Opera. What could be the reason?

    Read the article

  • Django model field value preprocessing before returning

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

    Read the article

  • Trying to set up nested while loops using a boolean switch

    - by thorn100
    First time posting. I'm trying to set up a while loop that will ask the user for the employee name, hours worked and hourly wage until the user enters 'DONE'. Eventually I'll modify the code to calculate the weekly pay and write it to a list, but one thing at a time. The problem is once the main while loop executes once, it just stops. Doesn't error out but just stops. I have to kill the program to get it to stop. I want it to ask the three questions again and again until the user is finished. Thoughts? Please note that this is just an exercise and not meant for any real world application. def getName(): """Asks for the employee's full name""" firstName=raw_input("\nWhat is your first name? ") lastName=raw_input("\nWhat is your last name? ") fullName=firstName.title() + " " + lastName.title() return fullName def getHours(): """Asks for the number of hours the employee worked""" hoursWorked=0 while int(hoursWorked)<1 or int(hoursWorked) > 60: hoursWorked=raw_input("\nHow many hours did the employee work: ") if int(hoursWorked)<1 or int(hoursWorked) > 60: print "Please enter an integer between 1 and 60." else: return hoursWorked def getWage(): """Asks for the employee's hourly wage""" wage=0 while float(wage)<6.00 or float(wage)>20.00: wage=raw_input("\nWhat is the employee's hourly wage: ") if float(wage)<6.00 or float(wage)>20.00: print ("Please enter an hourly wage between $6.00 and $20.00") else: return wage ##sentry variables employeeName="" employeeHours=0 employeeWage=0 booleanDone=False #Enter employee info print "Please enter payroll information for an employee or enter 'DONE' to quit." while booleanDone==False: while employeeName=="": employeeName=getName() if employeeName.lower()=="done": booleanDone=True break print "The employee's name is", employeeName while employeeHours==0: employeeHours=getHours() if employeeHours.lower()=="done": booleanDone=True break print employeeName, "worked", employeeHours, "this week." while employeeWage==0: employeeWage=getWage() if employeeWage.lower()=="done": booleanDone=True break print employeeName + "'s hourly wage is $" + employeeWage

    Read the article

  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

    Read the article

  • pylab.savefig() and pylab.show() image difference

    - by Jack1990
    I'm making an script to automatically create plots from .xvg files, but there's a problem when I'm trying to use pylab's savefig() method. Using pylab.show() and saving from there, everything's fine. Using pylab.show() Using pylab.savefig() def producePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): fc = sp.interp1d(timestep[::jump], energy_values[::jump],kind='cubic') xnew = numpy.linspace(0, finish, finish*2) pylab.plot(xnew, fc(xnew),type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def produceSimplePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): pylab.plot(timestep, energy_values,type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def linearRegression(timestep, energy_values, type_line = 'g'): #, jump = 1,finish = 100): from scipy import stats import numpy #print 'fuck' timestep = numpy.asarray(timestep) slope, intercept, r_value, p_value, std_err = stats.linregress(timestep,energy_values) line = slope*timestep+intercept pylab.plot(timestep, line, type_line) def plottingTime(Title,file_name, timestep, energy_values ,loc, jump , finish): pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) linearRegression(timestep,energy_values) import numpy Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2f" %(Average),'Linear Reg'),loc) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4], bbox_inches= None, pad_inches=0) #if __name__ == '__main__': #plottingTime(Title,timestep1, energy_values, jump =10, finish = 4800) def specialCase(Title,file_name, timestep, energy_values,loc, jump, finish): #print 'Working here ...?' pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) import numpy from pylab import * Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2g" %(Average), Title),loc) locs,labels = yticks() yticks(locs, map(lambda x: "%.3g" % x, locs)) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4] , bbox_inches= None, pad_inches=0) Thanks in advance, John

    Read the article

  • How can this verbose, unpythonic routine be improved?

    - by fmark
    Is there a more pythonic way of doing this? I am trying to find the eight neighbours of an integer coordinate lying within an extent. I am interested in reducing its verbosity without sacrificing execution speed. def fringe8((px, py), (x1, y1, x2, xy)): f = [(px - 1, py - 1), (px - 1, py), (px - 1, py + 1), (px, py - 1), (px, py + 1), (px + 1, py - 1), (px + 1, py), (px + 1, py + 1)] f_inrange = [] for fx, fy in f: if fx < x1: continue if fx >= x2: continue if fy < y1: continue if fy >= y2: continue f_inrange.append((fx, fy)) return f_inrange

    Read the article

  • Refresh decorator

    - by Morgoth
    I'm trying to write a decorator that 'refreshes' after being called, but where the refreshing only occurs once after the last function exits. Here is an example: @auto_refresh def a(): print "In a" @auto_refresh def b(): print "In b" a() If a() is called, I want the refresh function to be run after exiting a(). If b() is called, I want the refresh function to be run after exiting b(), but not after a() when called by b(). Here is an example of a class that does this: class auto_refresh(object): def __init__(self, f): print "Initializing decorator" self.f = f def __call__(self, *args, **kwargs): print "Before function" if 'refresh' in kwargs: refresh = kwargs.pop('refresh') else: refresh = False self.f(*args, **kwargs) print "After function" if refresh: print "Refreshing" With this decorator, if I run b() print '---' b(refresh=True) print '---' b(refresh=False) I get the following output: Initializing decorator Initializing decorator Before function In b Before function In a After function After function --- Before function In b Before function In a After function After function Refreshing --- Before function In b Before function In a After function After function So when written this way, not specifying the refresh argument means that refresh is defaulted to False. Can anyone think of a way to change this so that refresh is True when not specified? Changing the refresh = False to refresh = True in the decorator does not work: Initializing decorator Initializing decorator Before function In b Before function In a After function Refreshing After function Refreshing --- Before function In b Before function In a After function Refreshing After function Refreshing --- Before function In b Before function In a After function Refreshing After function because refresh then gets called multiple times in the first and second case, and once in the last case (when it should be once in the first and second case, and not in the last case).

    Read the article

  • A graph-based tuple merge?

    - by user1644030
    I have paired values in tuples that are related matches (and technically still in CSV files). Neither of the paired values are necessarily unique. tupleAB = (A####, B###), (A###, B###), (A###, B###)... tupleBC = (B####, C###), (B###, C###), (B###, C###)... tupleAC = (A####, C###), (A###, C###), (A###, C###)... My ideal output would be a dictionary with a unique ID and a list of "reinforced" matches. The way I try to think about it is in a graph-based context. For example, if: tupleAB[x] = (A0001, B0012) tupleBC[y] = (B0012, C0230) tupleAC[z] = (A0001, C0230) This would produce: output = {uniquekey0001, [A0001, B0012, C0230]} Ideally, this would also be able to scale up to more than three tuples (for example, adding a "D" match that would result in an additional three tuples - AD, BD, and CD - and lists of four items long; and so forth). In regards to scaling up to more tuples, I am open to having "graphs" that aren't necessarily fully connected, i.e., every node connected to every other node. My hunch is that I could easily filter based on the list lengths. I am open to any suggestions. I think, with a few cups of coffee, I could work out a brute force solution, but I thought I'd ask the community if anyone was aware of a more elegant solution. Thanks for any feedback.

    Read the article

  • Convert a sequence of sequences to a dictionary and vice-versa

    - by louis
    One way to manually persist a dictionary to a database is to flatten it into a sequence of sequences and pass the sequence as an argument to cursor.executemany(). The opposite is also useful, i.e. reading rows from a database and turning them into dictionaries for later use. What's the best way to go from myseq to mydict and from mydict to myseq? >>> myseq = ((0,1,2,3), (4,5,6,7), (8,9,10,11)) >>> mydict = {0: (1, 2, 3), 8: (9, 10, 11), 4: (5, 6, 7)}

    Read the article

< Previous Page | 348 349 350 351 352 353 354 355 356 357 358 359  | Next Page >