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  • problem getting a form image background

    - by Deumber
    I'm creating a datagridview transparent //I got the parent background image Bitmap parentBackGround = new Bitmap(this.Parent.BackgroundImage); //Set the area i want to create equal to the size of my grid Rectangle rect = new Rectangle(this.Location.X, this.Location.Y, this.Width, this.Height); //And draw in the entire grid the area of the background image that is cover with my grid, making a "transparent" effect. graphics.DrawImage(parentBackGround.Clone(rect, PixelFormat.Format32bppRgb), gridBounds); When the backgroundimage of the grid's parent is show in an normal layout all work ok, but if the layout is stretch, center or any other, the transparency effent gone, have you any idea to fix it?

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  • (Python/Pyramid) Better ways to have standard list/form editors?

    - by badcat
    I'm working on a number of Pyramid (former Pylons) projects, and often I have the need to display a list of some content (let's say user accounts, log entries or simply some other data). A user should be able to paginate through the list, click on a row and get a form where he/she can edit the contents of that row. Right now I'm always re-inventing the wheel by having Mako templates which use webhelpers for the pagination, Jquery UI for providing a dialog and I craft the editor form and AJAX requests on the client and server side by hand. As you may know, this eats up painfully much time. So what I'm wondering is: Is there a better way of providing lists, editor dialog and server/client communication about this, without having to re-invent the wheel every time? I heard Django takes off a big load of that by providing user accounts and other stuff out of the box; but in my case it's not just about user accounts, it can be any kind of data that is stored on the server-side in a SQL database, which should be able to be edited by a user. Thanks in advance!

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  • How can I make my password fields always empty?

    - by ggfan
    I have a form field where users can change their passwords, but if they set their settings to remember passwords, their password shows up. Is there a way to make the field always empty? So that they always have to type their password. <label for="oldpassword" class="styled">Old password:</label> <input type="password" id="oldpassword" name="oldpassword"/><br />

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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  • Select multiple submit issue - POST is empty if not selected

    - by Dasun
    I have a multiple select as below. It allows me to select options as below. Assume that 3 sports are selected. When the items are select as shown above form submit is successful. But unfortunately if the sports are not selected like below when the form is submitted post is empty. Select box <select style="width: 100px; height: 80px;" class="input" id="selected_sport_list" name="selected_sport_list[]" multiple=""> <option value="2">sport 2</option> <option value="3">sport 3</option> <option value="5">sport test x</option></select> How can I make sure that when the form is submitted particular items are selected? Is it possible to use jquery to fix this ? or how? Thanks

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  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

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  • Transfer values from one selection box to another

    - by Tonya Cash
    I need to populate the first box with the items from a db table. Users would choose from the first box, and either drag value(items) to the second for selection, or would select items, and then click a button to move them over to the 2nd box. After that I need to update the db with the selected values/items.

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • Multi-model form problem

    - by raphael_turtle
    (I'm just learning rails so....) I have a photo model and a gallery model, habtm associations and a join table. I'm making a photo gallery. The gallery page has a title field and description field. User creates gallery title, then goes to the photo page and checkboxes each image they want in that gallery. I get the error "undefined method `to_i' for ["1", {"title"="1"}]:Array" when trying to save/update a photo with a gallery title(with the checkbox) <% form_for @photo, :html => {:multipart => true } do |f| %> <%= f.error_messages %> <p> <%= f.label :title %> <%= f.text_field :title %> </p> <p> <%= f.label :description %> <%= f.text_area :description %> </p> <p> <%= f.label :image %> <%= f.file_field :image %> </p> <% for gallery in @photo.galleries %> <% fields_for "painting[gallery_attributes][]", gallery do |g| %> <div> <%= g.check_box :title %> <%= gallery.title %> </div> <% end %> <% end %> <p><%= submit_tag 'Update' %></p> <% end %> How much of this is horribly wrong? Can someone point me in the right direction?, I can't find any tutorials relating to this for 2.3 and above.

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  • set an input value from jquery function

    - by user1499220
    I'm simply trying to set a value for an input but it doesn't work. Here is my jquery function : function display_form() { try { $('#start_date').val('2012/08/21'); }catch (e){ alert('error'); } window.alert( $('[name=start_date]').val() ); } This shows "undefined". Here is my form : <input id="start_date" name="start_date" type="text" size="6" /> Should I put somewhere the id of the form that I want to use? I just followed what is said in the documentation of jquery but it doesn't seem to work. Could anyone help me ?

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  • Rails: validate presence of parent_id in has_many association

    - by deb
    I have a projects resource that has many tasks. I want to ensure that every task has a project_id by adding validates_presence_of :project_id to the tasks model. However, when creating a new project with tasks, the project_id won't be available until the record saves, therefore I can't use validates_presence_of :project_id. So my question is, how do I validate presence of project_id in the task model? I want to ensure every task has a parent. ... class Project < ActiveRecord::Base has_many :tasks, :dependent => :destroy accepts_nested_attributes_for :tasks, :allow_destroy => true ... class Task < ActiveRecord::Base belongs_to :project validates_presence_of :project_id

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • django - where to clean extra whitespace from form field inputs?

    - by Westerley
    I've just discovered that Django doesn't automatically strip out extra whitespace from form field inputs, and I think I understand the rationale ('frameworks shouldn't be altering user input'). I think I know how to remove the excess whitespace using python's re: #data = re.sub('\A\s+|\s+\Z', '', data) data = data.strip() data = re.sub('\s+', ' ', data) The question is where should I do this? Presumably this should happen in one of the form's clean stages, but which one? Ideally, I would like to clean all my fields of extra whitespace. If it should be done in the clean_field() method, that would mean I would have to have a lot of clean_field() methods that basically do the same thing, which seems like a lot of repetition. If not the form's cleaning stages, then perhaps in the model that the form is based on? Thanks for your help! W.

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  • Send form with jQuery using keypress()

    - by kexxcream
    What I have so far: I have a form in PHP that contain the following: <input type="submit" id="0" name="0" value="This button"> <input type="submit" id="1" name="1" value="This button"> <input type="hidden" id="response" name="response" value="150"> The problem: I would like to send the response value together with either name=1 or name=0, depending on which button the user submit. However, this should be done using the keyboard letters A and S. If a user press the letter A then the value 0 should be submitted, and if S is pressed then the value 1 should be sent. The jQuery code: $(document).ready(function() { // listens for any navigation keypress activity $(document).keypress(function(e) { switch(e.which) { // user presses the "a" case 97: submitViaKeypress("0"); break; // user presses the "s" key case 115: submitViaKeypress("1"); break; } }); }); // shows a given element and hides all others function submitViaKeypress(element_id) { var response = $('#response').attr('value'); $.ajax({ type: "POST", url: "initiate.php", data: "response=" + response + "&" + element_id + "=" + element_id }); } Goal: That "initiate.php receive two POST variables (response and either 0 or 1).

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  • how to avoid storing several times a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with an email field. The form of A displays an input in which the user should insert the email correctly. But as everybody knows, sometimes they don't do it. To fix this I have inserted an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validating all the fields, i use a global validator to compare the data of the two fields. This works, but I don't want to have the email stored two times in the database (I don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • Two part form in Rails

    - by samuel02
    I have some two nested resources, so that a Product can have many Bookings. On one page in a different controller I want to create a new booking and since it's a "general" booking I want a select menu to appear in a modal window where the user is able to pick one of the existing products and then go to the booking page. How can I do this? I have no problem setting up the modal and the "New booking" page is already there. What I need is a form that generates a list of existing products, picks the selected product id and then gets /products/:product_id/bookings/new . Any help appreciated! I realize my title does not describe my problem very good so better suggestions are highly welcome!

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  • Nested form child only updates if parent changes.

    - by chap
    In this video (10 sec) you can see that the nested attribute is only updated if it's parent model is changed. Using rails 3.0.0.beta and full project is on github. Summary of models and form: class Project < ActiveRecord::Base has_many :tasks accepts_nested_attributes_for :tasks end class Task < ActiveRecord::Base belongs_to :project has_many :assignments accepts_nested_attributes_for :assignments end class Assignment < ActiveRecord::Base belongs_to :task end form_for(@project) do |f| Project: f.text_field :name f.fields_for :tasks do |task_form| Task: task_form.text_field :name task_form.fields_for :assignments do |assignment_form| Assignment: assignment_form.text_field :name end end f.submit end

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  • form validation with jquery and livevalidation

    - by ImpY
    I'm trying to do some form validation with livevaldation & jquery. I've a formular with an input field like that: <div id="prenameDiv" class="control-group"> `<input id="prename" name="prename" class="input-large" placeholder="Max" >` </div> So if there's an error on validation 'livevalidaton' adds the class 'LV_invalid_field' to the input - it looks like that: <div id="prenameDiv" class="control-group"> <input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" > </div> That's ok, but now I'll add another class 'error' to the div 'prenameDiv' when the DOM changes that it looks like that: <div id="prenameDiv" class="control-group error"> `<input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" ` </div> I tried it that way: if ($("#prenameDiv").bind("DOMSubtreeModified")){ `if ($("#prename").hasClass("LV_invalid_field")) {` $("#prenameDiv").addClass("error"); } } But nothing changes? Do you have some ideas?

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  • Change Image in Resources at Runtime

    - by zaidwaqi
    Hi, My understanding of Resources is that I can combine resources i.e. images and my program into single executable. Let's say I have image pic1.png and I put it into Resource of my project, and is accessible with Properties.Resource.pic1. For example, PictureBox pb = new PictureBox(); pb.Image = Properties.Resource.pic1; What I want to do is for that my program will be able to replace this image at runtime. For example, my program runs, and locate newPicture.png, and use this new image to replace pic1.png that was originally used. Maybe my question is better reworded as "Can I include new image into Resources at runtime?" Please help. Thanks.

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • $_POST Variable Detected in Chrome but not in Firefox

    - by user1707973
    I am using 2 images in a form to sort out query results from the database. The form is submitted using the POST method. When i click on the first image, the query results have to be sorted in ascending order, and when i click on the second, the results have to be sorted in the descending order. This is the code for the form: <form name="" action="" method="post"> <input type="hidden" name="typep" value="price" /> <input type="image" name="sort" value="asc" src="images/asc-ar.png" /> <input type="image" name="sort" value="desc" src="images/dsc-ar.png" /> </form> Now this is the code for checking if the $_REQUEST['sort'] variable is set and therefore whether sorting is required or not. if ($_REQUEST['sort'] != "") { $sort = $_REQUEST['sort']; $typep = $_REQUEST['typep']; //query to be executed depending on values of $sort and $typep } Firefox does detect the $_REQUEST['typep'] variable but not the $_REQUEST['sort'] one. This works perfectly in Chrome though. When i test the site in Firefox, it doesn't detect the $_REQUEST['sort'] variable and therefore the if condition evaluates to false and the search results don't get sorted.

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  • Directions and Opinions on Creating Update System for the Application.

    - by AlwaysBeCoding
    Hi people. I just try to figure out a good solution on designing the update process for a windows form application i created. I think of a button inside the app for manual checking of an update and checking when starting the app. Only I'm not familiar with technics. I though to have the update setup file in a FTP Server and checking the server for an update with a txt file in there with filename and version info. When app is finished downloading the update, closing and starting the update setup file. Any suggestions, opinions on the subject?

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  • create php form, show message depending user choice

    - by user1056615
    I want to create a php form with checkbox, like this: < form method="post> <input type="checkbox" name="formpractise[]" value="A" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="B" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="C" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="D" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="E" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="F" /> <br/> <br/> <input type="submit" name="formsubmit" value="Submit" /> </form> When the user select checkbox I want to print a message according user choice. Not the choice he made, a message depending his choice.

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