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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Wordpress inserting comments via wp_insert_comment()

    - by Cyber Junkie
    Hello all happy holidays! :) I'm trying to insert comments in my wordpress blog via the wp_insert_comment() function. It's for a plugin I'm trying to make. I have this code in my header for testing. It works every time I refresh the page. $agent = $_SERVER['HTTP_USER_AGENT']; $data = array( 'comment_post_ID' => 256, 'comment_author' => 'Dave', 'comment_author_email' => '[email protected]', 'comment_author_url' => 'http://www.someiste.com', 'comment_content' => 'Lorem ipsum dolor sit amet...', 'comment_author_IP' => '127.3.1.1', 'comment_agent' => $agent, 'comment_date' => date('Y-m-d H:i:s'), 'comment_date_gmt' => date('Y-m-d H:i:s'), 'comment_approved' => 1, ); $comment_id = wp_insert_comment($data); It successfully inserts comments into the database. The problem: Comments don't show via the Disqus comment system. I compared table rows and I noticed that user_agent differs. Normal comments use for example, Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv... and Disqus comments use Disqus/1.1(2.61):119598902 numbers are different for each comment. Does anyone know how to insert comments with wp_insert_comment() when Disqus is enabled?

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  • JDBC ResultSet.getString Before/After Start/End of ResultSet Exception

    - by Geowil
    I have done a lot of searching about this topic through Google but I have yet to find someone using getString() in the way that I am using it so I have not been able to fix this issue in the normal ways that are suggested. What I am trying to do is to obtain all of the information from the database and then use it to populate a table model within the program. I do so by obtaining the data with getString and place it into a String[] object: try { while (rSet.next()) { String row[] = {rSet.getString("DonorName"),rSet.getString("DonorCharity"),((String)rSet.getString("DonationAmount"))}; model.addRow(row); } } However I am always getting a dialog error message stating those error messages in the title: Exception: Before start of result set Exception: After end of result set The data is still added and everything works correctly but it is just annoying to have to dismiss those message windows. Does anyone have some suggestions?

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  • Echoing a pseudo column value after a COUNT

    - by rob - not a robber
    Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

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  • The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs

    - by Matthew Chambers
    Hello I am getting the below message on a table i am trying to create The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs Anyone know the answer to this please -- Table warrington_central.job -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS warrington_central.job ( id MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT , alias_title VARCHAR(255) NOT NULL , reference_number VARCHAR(100) NOT NULL , title VARCHAR(255) NOT NULL , primary_category SMALLINT(5) UNSIGNED NOT NULL , secondary_category SMALLINT(5) UNSIGNED NOT NULL , tertiary_category SMALLINT(5) UNSIGNED NULL , address_id BIGINT(20) UNSIGNED NOT NULL , geolocation_id BIGINT(20) UNSIGNED NULL , company VARCHAR(255) NOT NULL , description VARCHAR(10000) NOT NULL , skills_required VARCHAR(10000) NOT NULL , job_type TINYINT(2) UNSIGNED NOT NULL , experience_months_required TINYINT(2) UNSIGNED NOT NULL , experience_years_required TINYINT(2) UNSIGNED NOT NULL , salary_range VARCHAR(30) NOT NULL , extra_benefits_above_salary VARCHAR(500) NOT NULL , available_from DATE NULL , available_to DATE NULL , extra_location_details VARCHAR(1000) NOT NULL , contact_email VARCHAR(100) NOT NULL , contact_phone_number VARCHAR(20) NOT NULL , contact_mobile_number VARCHAR(20) NOT NULL , terms_conditions_application VARCHAR(5000) NOT NULL , link_to_profile ENUM('0','1') NOT NULL , created_on DATETIME NOT NULL , updated_on DATETIME NOT NULL , updated_by BIGINT(20) UNSIGNED NOT NULL , add_contact_form ENUM('0','1') NOT NULL , admin_package_id TINYINT(1) UNSIGNED NOT NULL , package_start_date DATETIME NOT NULL , package_end_date DATETIME NULL , package_comment VARCHAR(500) NOT NULL , viewable_to_members_only ENUM('0','1') NOT NULL , advertise_to DATETIME NULL , show_comment ENUM('0','1') NOT NULL , hits BIGINT(20) UNSIGNED NOT NULL DEFAULT 0 , visible ENUM('0','1') NOT NULL DEFAULT '0' , approved ENUM('I/* large SQL query (3.9 KB), snipped at 2,000 characters / / SQL Error (1118): Row size too large. The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs */ SHOW WARNINGS;

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  • manage.py runserver not working

    - by Dan Appleyard
    I am new to django and python in general, so pardon me for any simple mistakes I may be doing. I am trying to setup my first django project on my local windows vista machine. I have created the project successfully with no problems. The issue I am coming across is when my settings.py has values for my database keys, the manage.py runserver command is failing. If I have values in settings before I run the command, as soon as I run it I get errors. If I have already run the command and the server is running, as soon as I edit the settings file with values, the errors show up in my still open command prompt. The inner most exception seems to "Error loading MySQLdb module: No module named MYSQLdb". If I leave the settings.py blank, the command executes with no problems. Any advice would be greatly appreciated! Thanks

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  • How to join nearly identical several queries into one?

    - by Devyn
    Hi, Assume I have an order_dummy table where order_dummy_id, order_id, user_id, book_id, author_id are stored. You may complain the logic of my table but I somehow need to do it that way. I want to execute following queries. SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 1 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 2 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 3 ORDER BY `order_dummy_id` DESC LIMIT 1 Please keep in mind that several numbers of same book is included in one order. Therefore, I list order_dummy_id by descending and limit 1 so only LATEST ORDER of A BOOK is shown. But my goal is to show other books in that way in one table. I used group by like this ... SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 GROUP BY book_id but it only shows order_dummy_id with ascending result. I have no idea anymore. Looking forward your kindness help!

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  • Zend Framework - counting rows in select clause ?

    - by moogeek
    Hello! I'm investigating Zend Framework and currently stucked in counting resulting rows of sql query... Every method I try (from documentation and some blogposts and tutorials) returns an error (like Call to undefined function) or simply gives the incorrect value. I've tried this: $checkquery = $db->select() ->from('users', 'COUNT(*)') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=fetchRow($checkquery)->num; ...then this one: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=count($checkquery->fetchAll()); and even: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=$checkquery->fetchAll()->num; Also rowCount() and count(fetchRow()) and count(fetchAll()->toArray()). But always I got an error message or duplicate inserts in db in further insert function. So what is the correct way to do the resulting row calculation in select clause in Zend Framework 1.9 (I use this one) ?

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  • How phpmyadmin, php and everything else works?

    - by Tom
    Ok, I guess I got crazy, but really. How phpmyadmin works? Does it have his own phpmyadmin or what? And how php works? Why writing echo 'hello'; it returns hello in the browser? I am really interested on how these things really works, maybe you know any books or smth to figure it out? Thank you.

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  • database change after pressing 'X' button

    - by Anup Prakash
    What i know:- We can use Ajax to change database from javascript. So whenever we press the 'X' button on title bar it calls "onbeforeunload" event. And by this event we can change the database. But in my case, i want to change the status of user only when user click on 'X' button. Not in case of changing the page. As because changing the page is unloading the page. and closing the page is also unloading the page(As much i know). Is there any way to differentiate between closing the page and moving from one page to other page? I want to use it for changing the status of user(i.e. login/logout), whenever he presses cross button. I don't want to set status "logout" when user changes the page. I want to set status "logout" when user 'X' the button. Plese help me.

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  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

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  • How to handle customers with multiple addresses in CakePHP

    - by Ryan
    I'm putting together a system to track customer orders. Each order will have three addresses; a Main contact address, a billing address and a shipping address. I do not want to have columns in my orders table for the three addresses, I'd like to reference them from a separate table and have some way to enumerate the entry so I can determine if the addressing is main, shipping or billing. Does it make sense to create a column in the address table for AddressType and enumerate that or create another table - AddressTypes - that defines the address enumeration and link to that table? I have found other questions that touch on this topic and that is where I've taken my model. The problem I'm having is taking that into the cakePHP convention. I've been struggling to internalize the direction OneToMany relationships are formed - the way the documentation states feels backwards to me. Any help would be appreciated, Thanks!

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  • sending +-200 emails using php mail() function in a loop

    - by Glenn
    Note: It is worth noting that the mail() function is not suitable for larger volumes of email in a loop. This function opens and closes an SMTP socket for each email, which is not very efficient. Source: PHP manual What are larger volumes? A 100 or a 1000?? Can I safely make it loop 200 times without much problems? (I can't install pear)

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  • SQL Databases and table design/organization

    - by John McMullen
    (NOOB disclaimer) I'm working on a system (a type of map), that is accessed mostly via 3 fields: ID (auto incremented), X coordinate, and Y coordinate. As it is right now, i have all data on the map, stored in 1 table. Whenever the map display is loaded it simply queries the database for contents in x and y, and the DB gives the data (other fields in the same entry). If an item on the map is doing something, it has a flag saying its doing something, and then has an ID of the action in another table holding that type of 'actions'. Essentially, for all map data, its stored in 1 table. All actions of a certain type are stored in their own table. I'm a noob, and i'm wondering what the most effective/efficient structure for such a design? (a map that has items, and each item has stats/actions). I'm using PHP atm, using standard SQL queries to get my data. Should i split up the tables so that there are only x number of entries on a table? (coord range limits)? Should it just keep growing and growing? There's a lot of queries to the table... so just tryin to see what is best :/

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  • PHP escape $ sign and echo a string my fetching database

    - by pnm123
    Hello, I want to know how to echo a string that have a $ sign from a database. At this time, the value on database 'Buy one for $5.00' converts to 'Buy one for .00'. Ex:- Field: title | Value: Buy one for $5.00 <?php $row = mysql_fetch_array..... $title = $row['title']; echo $title; ?> Thank you, pnm123

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  • Query in sql involving joins of two table

    - by Satish
    I have two tables reports and holidays. reports: (username varchar(30),activity varchar(30),hours int(3),report_date date) holidays: (holiday_name varchar(30), holiday_date date) select * from reports gives +----------+-----------+---------+------------+ | username | activity | hours | date | +----------+-----------+---------+------------+ | prasoon | testing | 3 | 2009-01-01 | | prasoon | coding | 4 | 2009-01-03 | | prasoon | coding | 4 | 2009-01-06 | | prasoon | coding | 4 | 2009-01-10 | +----------+-----------+---------+------------+ select * from holidays gives +--------------+---------------+ | holiday_name | holiday_date | +--------------+---------------+ | Diwali | 2009-01-02 | | Holi | 2009-01-05 | +--------------+---------------+ Is there any way by which I can output the following? +-------------+-----------+---------+-------------------+ | date | activity | hours | holiday_name | +-------------+-----------+---------+-------------------+ | 2009-01-01 | testing | 3 | | | 2009-01-02 | | | Diwali | | 2009-01-03 | coding | 4 | | | 2009-01-04 | Absent | Absent | | | 2009-01-05 | | | Holi | | 2009-01-06 | coding | 4 | | | 2009-01-07 | Absent | Absent | | | 2009-01-08 | Absent | Absent | | | 2009-01-09 | Absent | Absent | | | 2009-01-10 | coding | 4 | | +-------------+-----------+---------+-------------------+ In other words I want to fill the activity and hours columns with "Absent" on the dates which are neither in table reports nor in table holidays. How can I write a specific query for it. The query should give the output between two specific dates.

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  • PHP PDO fetch null

    - by Jacob
    How do you check if a columns value is null? Example code: $db = DBCxn::getCxn(); $sql = "SELECT exercise_id, author_id, submission, result, submission_time, total_rating_votes, total_rating_values FROM submissions LEFT OUTER JOIN submission_ratings ON submissions.exercise_id=submission_ratings.exercise_id WHERE id=:id"; $st = $db->prepare($sql); $st->bindParam(":id", $this->id, PDO::PARAM_INT); $st->execute(); $row = $st->fetch(); if($this->total_rating_votes == null) // this doesn't seem to work even though there is no record in submission_ratings???? { ... }

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  • a query is inserted from PHPMYAdmin but not from PHP

    - by iyad al aqel
    i'm writing a php code to insert form values in a forum values $dbServer = mysql_connect("localhost" , "root", "") ; if(!$dbServer) die ("Unable to connect"); mysql_select_db("kfumWonder"); $name= $_POST['name'] ; $password= md5($_POST['password']); $email= $_POST['email'] ; $major= $_POST['major'] ; $dateOfBirth=$_POST['dateOfBirth'] ; $webSite = $_POST['website']; $joinDate= date("Y m d") ; $query = "INSERT INTO user (name, password, email, major, dob, website, join_date) Values ('$name', '$password', '$email', '$major', '$dateOfBirth', '$webSite' , '$joinDate')" ; //echo $query ; $result = mysql_query($query) ; if (! $result ) echo " no results " ; this works perfectly fine when i took the printed query and run it in PHPMyAdmin but when i run this code nothing happens , any ideas !?

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  • How to compare filename of uploaded file and string

    - by user225269
    I use this code to upload image files in xammp server: <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 100000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file, File must be less than 100Kb in size with .jpg, .jpeg, or .gif file extension"; } ?> What do I do to compare the file name of the uploaded files with the text inputted by the user? My goal is to be able to compare the user input(ID number) and the file name of the image file which should also be an ID number. So that I will be able to display the image that corresponds with the ID Number provided. What do I need to do?Please give me an idea on how can I achieve this. Thanks

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