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  • Is software development an engineering discipline?

    - by Vaibhav Garg
    Can software development be considered engineering? If no, what are the things that it lacks in order to be qualified as an engineering discipline? Related to this is this question on Stack Overflow about the difference between a programmer and a software engineer. There is the Software Engineering Institute at Carnigie Mellon University that prescribes and maintains the CMMI standards. Is this something that will turn development into engineering?

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  • Excel: count number of unique/distinct row in range with condition

    - by Bertvan
    I have a an excel sheet with: in Col A: week numbers in Col B: dates (timesheet entries) I need to know the number of days worked for each week, so I need to the number of unique date entries per week number. I found formula's (both array as non-array) that handle this for a fixed range, but I want to have the results in another column per week number. So, the result of the added dataset below would be (the colon is just for clarity): 14: 2 15: 3 17: 6 20: 2 21: 3 If this is the source data: 14: 4/04/2012 14: 4/04/2012 15: 10/04/2012 15: 10/04/2012 15: 11/04/2012 17: 26/04/2012 17: 26/04/2012 17: 26/04/2012 17: 26/04/2012 17: 27/04/2012 17: 27/04/2012 20: 14/05/2012 20: 14/05/2012 21: 23/05/2012 21: 23/05/2012 21: 25/05/2012

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  • How to set up RAID 1 on Dell PERC S300 With Existing OS Install

    - by Daniel Dugger
    We have a server that is being used in production, but it was not originally meant to. The main thing I want to add to it is a Dell PERC S300 RAID Card to have the main hard drive (Windows Server 2008 R2) mirrored on another hard drive. I can not initialize the disk and wipe the the OS to create the array and then re-install. Is there a way to create the array with a current hard drive, without affecting it, and just mirroring the drive? If that card is not an option, is there a card that would allow that? The server is a Dell PowerEdge T110 II.

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  • Put Unused Tabs on Hold in Firefox

    - by Asian Angel
    If you have a lot of content heavy webpages open in Firefox, it soon adds up on memory usage. The BarTab extension puts unused tabs on hold and keeps them unloaded until you are ready to access them. Before When you have a few tabs open things are not so bad. But if you have something like 30+ tabs open then Firefox is definitely going to have a much larger memory footprint. For the moment all six tabs are active in our example… After Once the extension is installed you can see quite a difference in the tab bar. Five of the six websites are literally on hold and display as about:blank. In the screenshot above all six tabs were restored from a previous session, but to put new tabs on hold the preferences will have to be modified. Notice that you can have active tabs placed on hold if you do not access them within a set time (“x” seconds, minutes, hours, or days). You may also add your favorite websites as exclusions. Newly opened tabs can now be placed on hold until you are ready for them. Need to place a currently accessed tab on hold? Use the tab context menu to unload the page. Once you use the tab context menu to place a tab on hold your browser will shift over to the closest active tab. You will notice the difference in memory usage when you put a lot of intensive pages on hold. Conclusion If you keep a high number of content heavy webpages open in Firefox then the BarTab extension will help reduce memory usage while browsing. Links Download the BarTab extension (Mozilla Add-ons) Similar Articles Productive Geek Tips Quick Tip: Use Tab Characters in Textarea Boxes in FirefoxYou Really Want to Completely Disable Tabs in Firefox?Quick Hits: 11 Firefox Tab How-TosQuick Tip: Save Windows and Tabs When Restarting FirefoxMake Firefox Use Multiple Rows of Tabs TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 VMware Workstation 7 Acronis Online Backup Gmail Button Addon (Firefox) Hyperwords addon (Firefox) Backup Outlook 2010 Daily Motivator (Firefox) FetchMp3 Can Download Videos & Convert Them to Mp3 Use Flixtime To Create Video Slideshows

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  • Look up and string operation; fetch a value based on searching a partial string

    - by Sam
    I have 2 sets of data. One set to be filled up by fetching relevant data from a data array. DATA to be FILLED: Part#1 Part#2 ------ ------- 4021006 3808587 3870480 3083410 3873905 3890030 4002065 3699803 3930218 ARRAY OF DATA: Part#1 Part#2 ------ ------- 4021006;3808587 1 3808587 2 3870480;3083410;4002065 3 3083410 34 3873905 54 3890030 32 4002065;3930218 65 3699803 75 3930218 68 I need to match Part#1 and find Part#2. EXPECTED OUTPUT Part#1 Part#2 ------ ------- 4021006 1 3808587 1;2 3870480 3 3083410 3;4 3873905 54 3890030 32 4002065 3;65 3699803 75 3930218 65;68 Can anyone help.

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  • which default.list should i modify for default applications and what are the differences between the 2

    - by damien
    I would like to add miro to the default application GUI in system settings/default applications.I added ;miro.desktopnext to all rhythmbox.desktop entries eventually discovering if it was not added to audio/x-vorbis+ogg=rhythmbox.desktop as audio/x-vorbis+ogg=rhythmbox.desktop;miro.desktop it would not appear in the system settings/default applications drop down list for audio. I can find default.list in either /etc/gnome/defaults.list or /usr/share/applications/defaults.list modifying either gives me the same results.What is the difference and which is the correct list to modify?

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  • My Package Version Number Appears Greater Yet apt-get Doesn't Select It

    - by nutznboltz
    Backstory: It was determined that when using lxc container VMs the Nagios nrpe shutdown script when run on the host of the containers would kill the nrpe processes inside the containers. This was remediated by changing the script to use pidfiles instead of searching the process table for the nrpe process. Regrettably start-stop-daemon is a C program that resulted from translating a Perl script and it shows. There are far too many global varibles in start-stop-daemon.c and although there are some nice blocks of comments there are far to few comments that explain the intent behind variable names such as "schedule" (the string "schedule" appears in many contexts.) The manual page for start-stop-daemon strongly suggests that unless you use the "--retry" option the start-stop-daemon program may return before the process it sent a signal to actually calls exit() and terminates, however it doesn't actually state this in plain English. The obtuseness of start-stop-daemon is most likely the reason that the "fixed" version of the script includes a dubious comment indicating that sometimes the pid file has not been removed. I can easily see why someone would not understand that he left the --retry option missing. This bug also causes failures when the script is given the "restart" option; the nrpe daemon will shutdown but not start up again. Did I mention that since applying the update our nrpe servers started crashing over and over? Repairing this is why I am doing this work. I have been working on remediating the fix. You can see my current work in this PPA. Actual Question: The upstream version number of nagios-nrpe-server in lucid-updates is 2.12-4ubuntu1.10.04.1 My PPA uses this version number 2.12-4ubuntu1.10.04.1.1~ppa1~lucid1 I check the rules here and use this test program and I am lead to believe that the version number I use in my PPA is greater than the one in lucid-updates yet when I ran: sudo add-apt-repository ppa:nutznboltz/nrpe-unbreak-lp-600941 sudo apt-get update sudo aptitiude dist-upgrade The replacement package was not installed. I was able to install it using sudo aptitude install nagios-nrpe-server=2.12-4ubuntu1.10.04.1.1~ppa1~lucid1 Can anyone explain this behavior? Why didn't my version number appear greater to "aptitude dist-upgrade"? Thanks $ cat /etc/apt/preferences Package: * Pin: release a=lucid-backports Pin-Priority: 400 Package: * Pin: release a=lucid-security Pin-Priority: 990 Package: * Pin: release a=lucid-updates Pin-Priority: 900 Package: * Pin: release a=lucid-proposed Pin-Priority: 400 $ ls /etc/apt/preferences.d/ $ Should not make any difference as a PPA cannot be in any of those pockets. I went ahead and bumped the version number in the PPA to 2.12-4ubuntu1.10.04.2~ppa1~lucid1. I'll see if that makes a difference. I do notice that lintian complains: W: nagios-nrpe-server: debian-revision-not-well-formed 2.12-4ubuntu1.10.04.2~ppa1~lucid1

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  • Top 5 White Hat Techniques in SEO

    SEO techniques that help your site to get better page rank in search engines can be both White Hat and Black Hat. White hat techniques are accepted as ethical and useful long term, while black hat methods forcibly manipulate page rankings which are either discarded or not preferred because they flout the ethical norms. You should know the difference between these two and select a firm that utilizes only white hat techniques.

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  • Safer RAID5 rebuilds using partially failed disks?

    - by arcticmac
    There have been lots of articles posted recently about how RAID5 is dangerous because of long resilver times, and in particular because of increasing chances of encountering a URE during the resilver. Obviously this is a significant concern. However, it seems that in many cases of interest (as long as you're keeping some kind of eye on your disks), when it comes time to rebuild the array, the disk that I'm replacing is still mostly readable. If you try to explain this predicament to the average layperson, they are typically very confused as to why you have two almost completely functional disks but can't produce one working array. It seems to me that there ought to be some way to take advantage of this to make rebuilds safer, as long as I'm willing to have the RAID5 be read-only for a couple of days while it rebuilds. Conceptually, what I have in mind looks something like this: When a disk fails, immediately take the RAID5 offline or mount it read-only Attach a new disk (either in a spare bay, or externally via eSATA) and begin rebuilding it to replace the failed one. If known, perhaps start with the stripes in which the failure occurred, to minimize the chances of losing those if another disk fails. In the event that a second disk experiences a URE or other failure during the rebuild, try to source that data from the disk that is being replaced. Presumably if this happens, more rebuilding would be necessary. When complete, shut down the server, swap the replacement drive into the original bay if desired, and bring the array back up. Obviously such a process would not be appropriate for applications where uptime is critical or data loss cannot be tolerated, but it seems to me that this could help considerably to improve the reliability of RAID5. I assume that there's not a good way to implement a recovery like this at present, given that I haven't seen any indication of tools that are designed to do this, and that it seems like it would be rather obtuse to work out manually. Are there also technical issues with it that I haven't thought of (I'm still fairly new to RAID stuff)? Any thoughts on how hard something like this would be to implement (e.g. in linux md raid)?

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  • How to pause/resume transfer of large files?

    - by Olivier Lalonde
    I recently had to copy about 20 GB of data split between about 20 files from my laptop to an external hard drive. Since this operation takes quite a while (at ~560kb/s), I was wondering if there was any way to pause the transfer and resume it later (in case, I need to interrupt the transfer). As a side question, is there any performance difference between copying from the terminal vs copying from Nautilus?

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  • Algorithm to find all tiles within a given radius on staggered isometric map

    - by kasztelan
    Given staggered isometric map and a start tile what would be the best way to get all surrounding tiles within given radius(middle to middle)? I can get all neighbours of a given tile and distance between each of them without any problems but I'm not sure what path to take after that. This feature will be used quite often (along with A*) so I'd like to avoid unecessary calculations. If it makes any difference I'm using XNA and each tile is 64x32 pixels.

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  • When does 'optimizing code' == 'structuring data'?

    - by NewAlexandria
    A recent article by ycombinator lists a comment with principles of a great programmer. #7. Good programmer: I optimize code. Better programmer: I structure data. Best programmer: What's the difference? Acknowledging subjective and contentious concepts - does anyone have a position on what this means? I do, but I'd like to edit this question later with my thoughts so-as not to predispose the answers.

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  • Cannot reinstall MySql in 11.10 - ERROR: There's not enough space in /var/lib/mysql/

    - by Robin McCain
    I've tried it all (removing all the packages associated with MySQL) but keep getting stuff like this: Preconfiguring packages ... (Reading database ... 142196 files and directories currently installed.) Unpacking mysql-server-5.1 (from .../mysql-server-5.1_5.1.63-0ubuntu0.11.10.1_amd64.deb) ... ERROR: There's not enough space in /var/lib/mysql/ dpkg: error processing /var/cache/apt/archives/mysql-server-5.1_5.1.63-0ubuntu0.11.10.1_amd64.deb (--unpack): subprocess new pre-installation script returned error exit status 1 Errors were encountered while processing: /var/cache/apt/archives/mysql-server-5.1_5.1.63-0ubuntu0.11.10.1_amd64.deb E: Sub-process /usr/bin/dpkg returned an error code (1) Here is my drive space map. root@kyle:/# df Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/kyle-root 59361428 59021768 0 100% / udev 1014052 8 1014044 1% /dev tmpfs 409304 1476 407828 1% /run none 5120 0 5120 0% /run/lock none 1023256 0 1023256 0% /run/shm /dev/sda1 233191 46888 173862 22% /boot /dev/md0 1922858288 1048513192 776669500 58% /media/array The root volume actually only has about 10 gigabytes in use on the hard drive (which has a 60 gig partition). /dev/md0 is a 2 TB raid array.

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  • Software RAID 10 on Linux

    - by vpetersson
    For a long time, I've been thinking about switching to RAID 10 on a few servers. Now that Ubuntu 10.04 LTS is live, it's time for an upgrade. The servers I'm using are HP Proliant ML115 (very good value). It has four internal 3.5" slots. I'm currently using one drive for the system and a RAID5 array (software) for the remaining three disks. The problem is that this creates a single-point-of-failure on the boot drive. Hence I'd like to switch to a RAID10 array, as it would give me both better I/O performance and more reliability. The problem is only that good controller cards that supports RAID10 (such as 3Ware) cost almost as much as the server itself. Moreover software-RAID10 does not seem to work very well with Grub. What is your advice? Should I just keep running RAID5? Have anyone been able to successfully install a software RAID10 without boot issues?

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  • The (Totally) Phantom Menace Takes a Hard Look at Star Wars Saber Duels [Video]

    - by Jason Fitzpatrick
    If you feel like the light saber duels in Star Wars are long on choreography and short on actual brutal combat, you’re sure to get a chuckle out of this “training” guide highlighting how not to kill your opponent. [via Neatorama] What’s the Difference Between Sleep and Hibernate in Windows? Screenshot Tour: XBMC 11 Eden Rocks Improved iOS Support, AirPlay, and Even a Custom XBMC OS How To Be Your Own Personal Clone Army (With a Little Photoshop)

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  • SQL SERVER – Weekly Series – Memory Lane – #034

    - by Pinal Dave
    Here is the list of selected articles of SQLAuthority.com across all these years. Instead of just listing all the articles I have selected a few of my most favorite articles and have listed them here with additional notes below it. Let me know which one of the following is your favorite article from memory lane. 2007 UDF – User Defined Function to Strip HTML – Parse HTML – No Regular Expression The UDF used in the blog does fantastic task – it scans entire HTML text and removes all the HTML tags. It keeps only valid text data without HTML task. This is one of the quite commonly requested tasks many developers have to face everyday. De-fragmentation of Database at Operating System to Improve Performance Operating system skips MDF file while defragging the entire filesystem of the operating system. It is absolutely fine and there is no impact of the same on performance. Read the entire blog post for my conversation with our network engineers. Delay Function – WAITFOR clause – Delay Execution of Commands How do you delay execution of the commands in SQL Server – ofcourse by using WAITFOR keyword. In this blog post, I explain the same with the help of T-SQL script. Find Length of Text Field To measure the length of TEXT fields the function is DATALENGTH(textfield). Len will not work for text field. As of SQL Server 2005, developers should migrate all the text fields to VARCHAR(MAX) as that is the way forward. Retrieve Current Date Time in SQL Server CURRENT_TIMESTAMP, GETDATE(), {fn NOW()} There are three ways to retrieve the current datetime in SQL SERVER. CURRENT_TIMESTAMP, GETDATE(), {fn NOW()} Explanation and Comparison of NULLIF and ISNULL An interesting observation is NULLIF returns null if it comparison is successful, whereas ISNULL returns not null if its comparison is successful. In one way they are opposite to each other. Here is my question to you - How to create infinite loop using NULLIF and ISNULL? If this is even possible? 2008 Introduction to SERVERPROPERTY and example SERVERPROPERTY is a very interesting system function. It returns many of the system values. I use it very frequently to get different server values like Server Collation, Server Name etc. SQL Server Start Time We can use DMV to find out what is the start time of SQL Server in 2008 and later version. In this blog you can see how you can do the same. Find Current Identity of Table Many times we need to know what is the current identity of the column. I have found one of my developers using aggregated function MAX () to find the current identity. However, I prefer following DBCC command to figure out current identity. Create Check Constraint on Column Some time we just need to create a simple constraint over the table but I have noticed that developers do many different things to make table column follow rules than just creating constraint. I suggest constraint is a very useful concept and every SQL Developer should pay good attention to this subject. 2009 List Schema Name and Table Name for Database This is one of the blog post where I straight forward display script. One of the kind of blog posts, which I still love to read and write. Clustered Index on Separate Drive From Table Location A table devoid of primary key index is called heap, and here data is not arranged in a particular order, which gives rise to issues that adversely affect performance. Data must be stored in some kind of order. If we put clustered index on it then the order will be forced by that index and the data will be stored in that particular order. Understanding Table Hints with Examples Hints are options and strong suggestions specified for enforcement by the SQL Server query processor on DML statements. The hints override any execution plan the query optimizer might select for a query. 2010 Data Pages in Buffer Pool – Data Stored in Memory Cache One of my earlier year article, which I still read it many times and point developers to read it again. It is clear from the Resultset that when more than one index is used, datapages related to both or all of the indexes are stored in Memory Cache separately. TRANSACTION, DML and Schema Locks Can you create a situation where you can see Schema Lock? Well, this is a very simple question, however during the interview I notice over 50 candidates failed to come up with the scenario. In this blog post, I have demonstrated the situation where we can see the schema lock in database. 2011 Solution – Puzzle – Statistics are not updated but are Created Once In this example I have created following situation: Create Table Insert 1000 Records Check the Statistics Now insert 10 times more 10,000 indexes Check the Statistics – it will be NOT updated Auto Update Statistics and Auto Create Statistics for database is TRUE Now I have requested two things in the example 1) Why this is happening? 2) How to fix this issue? Selecting Domain from Email Address This is a straight to script blog post where I explain how to select only domain name from entire email address. Solution – Generating Zero Without using Any Numbers in T-SQL How to get zero digit without using any digit? This is indeed a very interesting question and the answer is even interesting. Try to come up with answer in next 10 minutes and if you can’t come up with the answer the blog post read this post for solution. 2012 Simple Explanation and Puzzle with SOUNDEX Function and DIFFERENCE Function In simple words - SOUNDEX converts an alphanumeric string to a four-character code to find similar-sounding words or names. DIFFERENCE function returns an integer value. The  integer returned is the number of characters in the SOUNDEX values that are the same. Read Only Files and SQL Server Management Studio (SSMS) I have come across a very interesting feature in SSMS related to “Read Only” files. I believe it is a little unknown feature as well so decided to write a blog about the same. Identifying Column Data Type of uniqueidentifier without Querying System Tables How do I know if any table has a uniqueidentifier column and what is its value without using any DMV or System Catalogues? Only information you know is the table name and you are allowed to return any kind of error if the table does not have uniqueidentifier column. Read the blog post to find the answer. Solution – User Not Able to See Any User Created Object in Tables – Security and Permissions Issue Interesting question – “When I try to connect to SQL Server, it lets me connect just fine as well let me open and explore the database. I noticed that I do not see any user created instances but when my colleague attempts to connect to the server, he is able to explore the database as well see all the user created tables and other objects. Can you help me fix it?” Importing CSV File Into Database – SQL in Sixty Seconds #018 – Video Here is interesting small 60 second video on how to import CSV file into Database. ColumnStore Index – Batch Mode vs Row Mode Here is the logic behind when Columnstore Index uses Batch Mode and when it uses Row Mode. A batch typically represents about 1000 rows of data. Batch mode processing also uses algorithms that are optimized for the multicore CPUs and increased memory throughput. Follow up – Usage of $rowguid and $IDENTITY This is an excellent follow up blog post of my earlier blog post where I explain where to use $rowguid and $identity.  If you do not know the difference between them, this is a blog with a script example. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Memory Lane, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • How do I align my partition table properly?

    - by Jorge Castro
    I am in the process of building my first RAID5 array. I've used mdadm to create the following set up: root@bondigas:~# mdadm --detail /dev/md1 /dev/md1: Version : 00.90 Creation Time : Wed Oct 20 20:00:41 2010 Raid Level : raid5 Array Size : 5860543488 (5589.05 GiB 6001.20 GB) Used Dev Size : 1953514496 (1863.02 GiB 2000.40 GB) Raid Devices : 4 Total Devices : 4 Preferred Minor : 1 Persistence : Superblock is persistent Update Time : Wed Oct 20 20:13:48 2010 State : clean, degraded, recovering Active Devices : 3 Working Devices : 4 Failed Devices : 0 Spare Devices : 1 Layout : left-symmetric Chunk Size : 64K Rebuild Status : 1% complete UUID : f6dc829e:aa29b476:edd1ef19:85032322 (local to host bondigas) Events : 0.12 Number Major Minor RaidDevice State 0 8 16 0 active sync /dev/sdb 1 8 32 1 active sync /dev/sdc 2 8 48 2 active sync /dev/sdd 4 8 64 3 spare rebuilding /dev/sde While that's going I decided to format the beast with the following command: root@bondigas:~# mkfs.ext4 /dev/md1p1 mke2fs 1.41.11 (14-Mar-2010) /dev/md1p1 alignment is offset by 63488 bytes. This may result in very poor performance, (re)-partitioning suggested. Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=16 blocks, Stripe width=48 blocks 97853440 inodes, 391394047 blocks 19569702 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 11945 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 Writing inode tables: ^C 27/11945 root@bondigas:~# ^C I am unsure what to do about "/dev/md1p1 alignment is offset by 63488 bytes." and how to properly partition the disks to match so I can format it properly.

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  • Running Multiple Queries in Oracle SQL Developer

    - by thatjeffsmith
    There are two methods for running queries in SQL Developer: Run Statement Run Statement, Shift+Enter, F9, or this button Run Script No grids, just script (SQL*Plus like) ouput is fine, thank you very much! What’s the Difference? There are some obvious differences between the two features, the most obvious being the format of the output delivered. But there are some other, more subtle differences here, primarily around fetching. What is Fetch? After you run send your query to Oracle, it has to do 3 things: Parse Execute Fetch Technically it has to do at least 2 things, and sometimes only 1. But, to get the data back to the user, the fetch must occur. If you have a 10 row query or a 1,000,000 row query, this can mean 1 or many fetches in groups of records. Ok, before I went on the Fetch tangent, I said there were two ways to run statements in SQL Developer: Run Statement Run statement brings your query results to a grid with a single fetch. The user sees 50, 100, 500, etc rows come back, but SQL Developer and the database know that there are more rows waiting to be retrieved. The process on the server that was used to execute the query is still hanging around too. To alleviate this, increase your fetch size to 500. Every query ran will come back with the first 500 rows, and rows will be continued to be fetched in 500 row increments. You’ll then see most of your ad hoc queries complete with a single fetch. Scroll down, or hit Ctrl+End to force a full fetch and get all your rows back. Run Script Run Script runs the contents of the worksheet (or what’s highlighted) as a ‘script.’ What does that mean exactly? Think of this as being equivalent to running this in SQL*Plus: @my_script.sql; Each statement is executed. Also, ALL rows are fetched. So once it’s finished executing, there are no open cursors left around. The more obvious difference here is that the output comes back formatted as plain old text. Run one or more commands plus SQL*Plus commands like SET and SPOOL The Trick: Run Statement Works With Multiple Statements! It says ‘run statement,’ but if you select more than one with your mouse and hit the button – it will run each and throw the results to 1 grid for each statement. If you mouse hover over the Query Result panel tab, SQL Developer will tell you the query used to populate that grid. This will work regardless of what you have this preference set to: DATABASE – WORKSHEET – SHOW QUERY RESULTS IN NEW TABS Mind the fetch though! Close those cursors by bring back all the records or closing the grids when you’re done with them.

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  • Are there advantages to using a DVCS for a solo developer?

    - by SnOrfus
    Right now, I use visual svn on my server, and have ankhsvn/tortoise on my personal machine. It works fine enough, and I don't have to change, but if I can see some benefits of using a DVCS, then I might give it a go. However, if there's no point or difference using it without other people, then I won't bother. So again, I ask, are there any benefits to using a DVCS when you're the only developer?

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  • Increase Performance of VS 2010 by using a SSD

    - by System.Data
    After searching on the internet for performance improvements when using Visual Studio 2010 with a solid state hard drive, I heard a lot of different opinions. A lot of people said that there isn't really a benefit when using a SSD, but in contrast others said the exact opposite. I am a bit confused with the contrasting opinions and I cannot really make a decision whether buying a SSD would make a difference. What are your experiences with this issue and which SSD did you use?

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  • How to store generated eigen faces for future face recognition?

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong? 2.Instead of running the training set everytime how eigen faces generated are stored so that stored eigen faces are used for future face recoginition for a new input image.So it reduces wastage of time.

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  • Vectorization of matlab code for faster execution

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); Running time for 50 images:Elapsed time is 103.947573 seconds. QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong?

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  • Gathering all data in single iteration vs using functions for readable code

    - by user828584
    Say I have an array of runners with which I need to find the tallest runner, the fastest runner, and the lightest runner. It seems like the most readable solution would be: runners = getRunners(); tallestRunner = getTallestRunner(runners); fastestRunner = getFastestRunner(runners); lightestRunner = getLightestRunner(runners); ..where each function iterates over the runners and keeps track of the largest height, greatest speed, and lowest weight. Iterating over the array three times, however, doesn't seem like a very good idea. It would instead be better to do: int greatestHeght, greatestSpeed, leastWeight; Runner tallestRunner, fastestRunner, lightestRunner; for(runner in runners){ if(runner.height > greatestHeight) { greatestHeight = runner.height; tallestRunner = runner; } if(runner.speed > ... } While this isn't too unreadable, it can get messy when there is more logic for each piece of information being extracted in the iteration. What's the middle ground here? How can I use only a single iteration while still keeping the code divided into logical units?

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