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  • Sort a list of dicts by dict values

    - by ensnare
    I have a list of dictionaries: [{'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}, {'title':'Apple News','title_url':'Apple_News','id':2}] I'd like to sort it by the title, so elements with A go before Z: [{'title':'Apple News','title_url':'Apple_News','id':2}, {'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}] What's the best way to do this? Also, is there a way to ensure the order of each dictionary key stays constant, e.g., always title, title_url, then id? Thank you.

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  • How do I compare two complex data structures?

    - by Phil H
    I have some nested datastructures, each something like: [ ('foo', [ {'a':1, 'b':2}, {'a':3.3, 'b':7} ]), ('bar', [ {'a':4, 'd':'efg', 'e':False} ]) ] I need to compare these structures, to see if there are any differences. Short of writing a function to explicitly walk the structure, is there an existing library or method of doing this kind of recursive comparison?

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  • Django - foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = type_g.type_id, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT n.*, l.* FROM objtree_nodes n JOIN objtree_labels l ON (n.node_id = l.node_id) WHERE n.type_id = 15 AND n.parent_id = 50 AND l.type_id = 1 Any help is GREATLY appreciated. Regards

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  • how do i insert spaces into a string using the range function?

    - by user1319219
    If I have a string, for example which reads: 'Hello how are you today Joe' How am I able to insert spaces into it at regular intervals? So for example I want to insert spaces into it using the range function in these steps: range(0,27,2). So it will look like this: 'He lo ho w ar e yo u to da y Jo e' It now has a space at every 2nd index going up to it's end. How do I do this does anyone know? thanks.

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  • PyParsing: Is this correct use of setParseAction()?

    - by Rosarch
    I have strings like this: "MSE 2110, 3030, 4102" I would like to output: [("MSE", 2110), ("MSE", 3030), ("MSE", 4102)] This is my way of going about it, although I haven't quite gotten it yet: def makeCourseList(str, location, tokens): print "before: %s" % tokens for index, course_number in enumerate(tokens[1:]): tokens[index + 1] = (tokens[0][0], course_number) print "after: %s" % tokens course = Group(DEPT_CODE + COURSE_NUMBER) # .setResultsName("Course") course_data = (course + ZeroOrMore(Suppress(',') + COURSE_NUMBER)).setParseAction(makeCourseList) This outputs: >>> course.parseString("CS 2110") ([(['CS', 2110], {})], {}) >>> course_data.parseString("CS 2110, 4301, 2123, 1110") before: [['CS', 2110], 4301, 2123, 1110] after: [['CS', 2110], ('CS', 4301), ('CS', 2123), ('CS', 1110)] ([(['CS', 2110], {}), ('CS', 4301), ('CS', 2123), ('CS', 1110)], {}) Is this the right way to do it, or am I totally off? Also, the output of isn't quite correct - I want course_data to emit a list of course symbols that are in the same format as each other. Right now, the first course is different from the others. (It has a {}, whereas the others don't.)

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  • Inlines in Django Admin

    - by Oli
    I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

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  • django link format words joined with hypens

    - by soField
    href="http://www.torontolife.com/daily/daily-dish/restauranto/2010/03/10/best-new-restaurants-2010-james-chatto-names-five-honourable-mentions/"Best new restaurants 2010: honourable mentions is django has built in mechanism to format links above i mean words joined with hypens how can achieve this ?

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  • How to get the related_name of a many-to-many-field?

    - by amann
    I am trying to get the related_name of a many-to-many-field. The m2m-field is located betweeen the models "Group" and "Lection" and is declared in the group-model as following: lections = models.ManyToManyField(Lection, blank=True) The field looks like this: <django.db.models.fields.related.ManyToManyField object at 0x012AD690> The print of field.__dict__ is: {'_choices': [], '_m2m_column_cache': 'group_id', '_m2m_name_cache': 'group', '_m2m_reverse_column_cache': 'lection_id', '_m2m_reverse_name_cache': 'lection', '_unique': False, 'attname': 'lections', 'auto_created': False, 'blank': True, 'column': 'lections', 'creation_counter': 71, 'db_column': None, 'db_index': False, 'db_table': None, 'db_tablespace': '', 'default': <class django.db.models.fields.NOT_PROVIDED at 0x00FC8780>, 'editable': True, 'error_messages': {'blank': <django.utils.functional.__proxy__ object at 0x00FC 7B50>, 'invalid_choice': <django.utils.functional.__proxy__ object at 0x00FC7A50>, 'null': <django.utils.functional.__proxy__ object at 0x00FC7 A70>}, 'help_text': <django.utils.functional.__proxy__ object at 0x012AD6F0>, 'm2m_column_name': <function _curried at 0x012A88F0>, 'm2m_db_table': <function _curried at 0x012A8AF0>, 'm2m_field_name': <function _curried at 0x012A8970>, 'm2m_reverse_field_name': <function _curried at 0x012A89B0>, 'm2m_reverse_name': <function _curried at 0x012A8930>, 'max_length': None, 'name': 'lections', 'null': False, 'primary_key': False, 'rel': <django.db.models.fields.related.ManyToManyRel object at 0x012AD6B0>, 'related': <RelatedObject: mymodel:group related to lections>, 'related_query_name': <function _curried at 0x012A8670>, 'serialize': True, 'unique_for_date': None, 'unique_for_month': None, 'unique_for_year': None, 'validators': [], 'verbose_name': 'lections'} Now the field should be accessed via a lection-instance. So this is done by lection.group_set But i need to access it dynamically, so there is the need to get the related_name attribute from somewhere. Here in the documentation, there is a note that it is possible to access ManyToManyField.related_name, but this doesn't work for my somehow.. Help would be a lot appreciated. Thanks in advance.

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  • Can pydoc/help hide the documentation for inherited class methods and attributes?

    - by EOL
    When declaring a class that inherits from a specific class: class C(dict): added_attribute = 0 the documentation for C lists all the methods of dict (either through help(C) or pydoc). Is there a way to hide the inherited methods from the automatically generated documentation (the documentation string can refer to the base class, for non-overwritten methods)? This would be useful: pydoc lists the functions defined in a module after its classes. Thus, when the classes have a very long documentation, a lot of less than useful information is printed before the new functions provided by the module are presented, which makes the documentation harder to exploit (you have to skip all the documentation for the inherited methods until you reach something specific to the module being documented).

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  • Extend argparse to write set names in the help text for optional argument choices and define those sets once at the end

    - by Kent
    Example of the problem If I have a list of valid option strings which is shared between several arguments, the list is written in multiple places in the help string. Making it harder to read: def main(): elements = ['a', 'b', 'c', 'd', 'e', 'f'] parser = argparse.ArgumentParser() parser.add_argument( '-i', nargs='*', choices=elements, default=elements, help='Space separated list of case sensitive element names.') parser.add_argument( '-e', nargs='*', choices=elements, default=[], help='Space separated list of case sensitive element names to ' 'exclude from processing') parser.parse_args() When running the above function with the command line argument --help it shows: usage: arguments.py [-h] [-i [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]]] [-e [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]]] optional arguments: -h, --help show this help message and exit -i [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]] Space separated list of case sensitive element names. -e [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]] Space separated list of case sensitive element names to exclude from processing What would be nice It would be nice if one could define an option list name, and in the help output write the option list name in multiple places and define it last of all. In theory it would work like this: def main_optionlist(): elements = ['a', 'b', 'c', 'd', 'e', 'f'] # Two instances of OptionList are equal if and only if they # have the same name (ALFA in this case) ol = OptionList('ALFA', elements) parser = argparse.ArgumentParser() parser.add_argument( '-i', nargs='*', choices=ol, default=ol, help='Space separated list of case sensitive element names.') parser.add_argument( '-e', nargs='*', choices=ol, default=[], help='Space separated list of case sensitive element names to ' 'exclude from processing') parser.parse_args() And when running the above function with the command line argument --help it would show something similar to: usage: arguments.py [-h] [-i [ALFA [ALFA ...]]] [-e [ALFA [ALFA ...]]] optional arguments: -h, --help show this help message and exit -i [ALFA [ALFA ...]] Space separated list of case sensitive element names. -e [ALFA [ALFA ...]] Space separated list of case sensitive element names to exclude from processing sets in optional arguments: ALFA {a,b,c,d,e,f} Question I need to: Replace the {'l', 'i', 's', 't', 's'} shown with the option name, in the optional arguments. At the end of the help text show a section explaining which elements each option name consists of. So I ask: Is this possible using argparse? Which classes would I have to inherit from and which methods would I need to override? I have tried looking at the source for argparse, but as this modification feels pretty advanced I don´t know how to get going.

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  • How would make this run with an if statement and one for loop?

    - by Nick Jacobs
    I'm trying to get this to run by using an if statment, a for loop, and a list. The list is part of the parameters. I am not sure how to write the if statement and have the program loop through all of the different words and set everything how it is supposed to be. newSndIdx=0; for i in range (8700, 12600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (15700, 17600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (18750, 22350+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (23700, 27250+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (106950, 115300+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx+=1

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  • Good looking programs that are built using wxPython for their UI

    - by ChrisC
    I need inspiration and motivation so I'm trying to find examples of different programs that have interesting and attractive UI's created free using wxPython. My searches have been slow to find results. I'm hoping you guys know of some of the best ones out there. btw, I've seen these: http://www.wxpython.org/screenshots.php and the list under "Applications Developed with wxPython" on the wxPython Wikipedia page. Update: only need Windows examples

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  • List all form related errors in django

    - by Mridang Agarwalla
    Hi, Is there a direct way of listing out 'all' form errors in Django templates. I'd like to list out both field and non-field errors and any other form errors. I've found out how to do this on a per-field basis but as said earlier, I'd like to list out everything. The method I'm using doesn't seem to list out everything. {% for error in form.errors %} {{ error|escape }} {% endfor %} Thanks.

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  • google contacts api service account oauth2.0 sub user

    - by user3709507
    I am trying to use the Google Contacts API to connect to a user's contact information, on my Google apps domain. Generating an access_token using the gdata api's ContactsService clientlogin function while using the API key for my project works fine, but I would prefer to not store the user's credentials, and from the information I have found that method uses OAuth1.0 So, to use OAuth2.0 I have: Generated a Service Account in the developer's console for my project Granted access to the service account for the scope of https://www.google.com/m8/feeds/ in the Google apps domain admin panel Attempted to generate credentials using SignedJwtAssertionCredentials: credentials = SignedJwtAssertionCredentials( service_account_name=service_account_email, private_key=key_from_p12_file, scope='https://www.google.com/m8/feeds/', sub=user_email') The problem I am running into is that attempting to generate an access token using this method fails. It succeeds in generating the token when I remove the sub parameter, but then that token fails when I try to fetch the user's contacts. Does anyone know why this might be happening?

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  • Shuttle control in wxPython

    - by Mridang Agarwalla
    Hi, I'm trying to implement a shuttle control in wxPython but there doesn't seem to be one. I've decided to use two listbox controls. The shuttle control looks like this: I've got two listboxes — one's populated, one's not. Could someone show me how to add a selected item to the second list box when it is double clicked? It should be removed from the first. When it is double clicked in the second, it should be added to the first and removed from the second. The shuttle control implements these by default but it's a pity it isn't there. Thank you.

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  • Djangoo Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

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  • compare two following values in numpy array

    - by Billy Mitchell
    What is the best way to touch two following values in an numpy array? example: npdata = np.array([13,15,20,25]) for i in range( len(npdata) ): print npdata[i] - npdata[i+1] this looks really messed up and additionally needs exception code for the last iteration of the loop. any ideas? Thanks!

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  • Sending file over socket

    - by johannix
    I'm have a problem sending data as a file from one end of a socket to the other. What's happening is that both the server and client are trying to read the file so the file never gets sent. I was wondering how to have the client block until the server's completed reading the file sent from the client. I have this working with raw packets using send and recv, but figured this was a cleaner solution... Client: connects to server creating socket connection creates a file on socket and sends data waits for file from server Server: waits for file from client Complete interraction: client sends data to server server sends data to client

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  • Trie Backtracking in Recursion

    - by Darksky
    I am building a tree for a spell checker with suggestions. Each node contains a key (a letter) and a value (array of letters down that path). So assume the following sub-trie in my big trie: W / \ a e | | k k | | is word--> e e | ... This is just a subpath of a sub-trie. W is a node and a and e are two nodes in its value array etc... At each node, I check if the next letter in the word is a value of the node. I am trying to support mistyped vowels for now. So 'weke' will yield 'wake' as a suggestion. Here's my searchWord function in my trie: def searchWord(self, word, path=""): if len(word) > 0: key = word[0] word = word[1:] if self.values.has_key(key): path = path + key nextNode = self.values[key] return nextNode.searchWord(word, path) else: # check here if key is a vowel. If it is, check for other vowel substitutes else: if self.isWord: return path # this is the word found else: return None Given 'weke', at the end when word is of length zero and path is 'weke', my code will hit the second big else block. weke is not marked as a word and so it will return with None. This will return out of searchWord with None. To avoid this, at each stack unwind or recursion backtrack, I need to check if a letter is a vowel and if it is, do the checking again. I changed the if self.values.has_key(key) loop to the following: if self.values.has_key(key): path = path + key nextNode = self.values[key] ret = nextNode.searchWord(word, path) if ret == None: # check if key == vowel and replace path # return nextNode.searchWord(... return ret What am I doing wrong here? What can I do when backtracking to achieve what I'm trying to do?

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