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  • Radio buttons + array elements

    - by Mark
    I have a form that can be dynamically duplicated (with JS) so that the user can enter as much data as he wants. This works great for text inputs, because I just leave the name attribute the same (ending with a []) and then when the values are posted, it just returns me an array. Now I just realized that this doesn't work so well for radio buttons, because the names actually need to be unique for each set. But from the data standpoint, each set only returns one value, so retrieving the data from the POST data wouldn't be a problem, it just screws up the functionality of my form. There's no way around this, is there? I'm just screwed and I can't use arrays?

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  • Selecting pictures from database

    - by user1691618
    Okay guys, I need some help. I'm trying to design a page where a user can ask a question and upload up to 4 pictures. I have 2 database tables, questions and image_table. I have everything uploading correctly, so that's not my problem. What I am having trouble doing is selecting images from the image_table database that only correspond to that question. I can't figure out how to do this. Any help would be GREATLY appreciated.

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  • Uncaught syntax error: Adding <li> elements to an <ul>

    - by ThePagan
    I keep getting an uncaught syntex error which I know usually means your code has a missing closing something. I keep failing to see what it is that I am missing. The idea of the function is that it extracts the a links ID and Text content and add's it to an un-ordered list. The links have a class of 'ingredient_add' and the unordered list has an ID of 'ingredientsAdded'. I can't see what I've missed here. $(document).ready(function() { $('.ingredient_add').click(function() { event.preventDefault(); var id = this.id; var value = this.text(); $('#ingredientsAdded').append("<li id='"+id+"'>"+value+"</li>"); }); //end add to list }); // end document ready()

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  • Problem with modifying a page with ajax, and the browser keeping the unmodified page in cache.

    - by David Lawson
    Hey there, I have a situation where my page loads some information from a database, which is then modified through AJAX. I click a link to another page, then use the 'back' button to return to the original page. The changes to the page through AJAX I made before don't appear, because the browser has the unchanged page stored in the cache. Is there a way of fixing this without setting the page not to cache at all? Thanks :)

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  • How to hide/show div using jQuery without altering dimensions?

    - by Byron S
    I have a div that is holding a google chart: <div id="chart_div" style="width: 600px; height: 300px;"></div> It has one CSS property: display: none. On the click of a button, I would like to have the chart be displayed using jQuery hide() and show(). It's working, however, the chart's dimensions are set to something different than I have specified and refuse to change to what I have specified. Here is my jquery code: $(document).ready(function(){ var chart = $('#chart_div'); $('#submit').click(function(){ chart.show('slow'); }); }); Let me know if theres any more code you would like to see. By the way, the chart div is not being contained in anything else so that isn't the problem.

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  • Upload picture directly to the server

    - by Rajeev
    In the following link http://www.tuttoaster.com/create-a-camera-application-in-flash-using-actionscript-3/ how to make the picture upload directly to the server after taking a picture from webcam package { import flash.display.Sprite; import flash.media.Camera; import flash.media.Video; import flash.display.BitmapData; import flash.display.Bitmap; import flash.events.MouseEvent; import flash.net.FileReference; import flash.utils.ByteArray; import com.adobe.images.JPGEncoder; public class caml extends Sprite { private var camera:Camera = Camera.getCamera(); private var video:Video = new Video(); private var bmd:BitmapData = new BitmapData(320,240); private var bmp:Bitmap; private var fileReference:FileReference = new FileReference(); private var byteArray:ByteArray; private var jpg:JPGEncoder = new JPGEncoder(); public function caml() { saveButton.visible = false; discardButton.visible = false; saveButton.addEventListener(MouseEvent.MOUSE_UP, saveImage); discardButton.addEventListener(MouseEvent.MOUSE_UP, discard); capture.addEventListener(MouseEvent.MOUSE_UP, captureImage); if (camera != null) { video.smoothing = true; video.attachCamera(camera); video.x = 140; video.y = 40; addChild(video); } else { trace("No Camera Detected"); } } private function captureImage(e:MouseEvent):void { bmd.draw(video); bmp = new Bitmap(bmd); bmp.x = 140; bmp.y = 40; addChild(bmp); capture.visible = false; saveButton.visible = true; discardButton.visible = true; } private function saveImage(e:MouseEvent):void { byteArray = jpg.encode(bmd); fileReference.save(byteArray, "Image.jpg"); removeChild(bmp); saveButton.visible = false; discardButton.visible = false; capture.visible = true; } private function discard(e:MouseEvent):void { removeChild(bmp); saveButton.visible = false; discardButton.visible = false; capture.visible = true; } } }

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  • Creating a timesheet for work using PHP MySQL

    - by Justin
    I am trying to create a time-sheet for my work. I don't know if getting myself into a lot of work by doing this as I am quiet new to PHP and MYSQL but I do have a good understanding/knowledge of the two. I want the below fields in my database. Job weekPeriod ------A list of weeks Monday Sunday dateWorked ------List Of dates in the form coming from a database e.g. 1/1/2011 startTime ------List of times from 12:00am11:00pm 30 min intervals e.g. 11:30-12:30 endTime ------List of times from 12:00am11:00pm 30 min intervals e.g. 11:30-12:30 totalHours ------Automated amount ------Automated based on dayWorked comments ------Any messages here I want to be able to fill in some drop down boxes through a form that will then submit all information to my database. I want the script to know that if the date worked is on a Weekday Mon-Fri e.g. my rate of pay is 30.00ph On a sat it is 35.00ph and on a Sunday it is 40ph I then want to create a page where i select a particular week and see how many hours i worked and how much i earn and so on. Please let me know if there is such a program already established or if this is something that requires a bit of time and if I could do it being new to PHP and MYSQL

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  • Possible to view PHP code of a website?

    - by Camran
    Is it possible to somehow view another websites php files/codes? Or to rephrase the question, Can my php codes be viewed by anybody except for those who have access to the file? If so, how cant I best prevent this? Thanks Ps: Server OS is Ubuntu 9.10 and PHP version is 5+ (Apache2)

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  • class selector refuses after append to body

    - by supersize
    I'm appending loads of divs in a wrapper: var cubes = [], allCubes = '', for(var i = 0; i < 380; i++) { var randomleft = Math.floor(Math.random()*Math.floor(Math.random()*1000)), randomtop = Math.floor(Math.random()*Math.floor(Math.random()*1000)); allCubes += '<div id="cube'+i+'" class="cube" style="position: absolute; border: 2px #000 solid; left: '+randomleft+'px; top: '+randomtop+'px; width: 9px; height: 9px; z-index: -1"></div>'; } $('#wrapper').append(allCubes); // performance for(var i = 0; i < 380; i++) { cubes.push($('#cube'+i)); } and then I would like to make them all draggable with jQueryUI and log their current position. var allc = $('.cube'); allc.draggable().on('mouseup', function(i) { allc.each(function() { var nleft = $(this).offset().left; var ntop = $(this).offset().top; console.log('cubes['+i+'].animate({ left:'+nleft+',top:'+ntop+'})'); }); }); Unfortunenately it does not work. They are neither draggable nor there comes up a log. Thanks

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  • div overlay background

    - by jree
    In my application am using transparent div like a show modal dialog.Its working fine in firefox but not working well in internet explorer. What is the solution to work similar in both Thanks

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  • change value upon select

    - by Link
    what i'm aiming is to show the other div when it selects one of the two options Full time and Part Time and if possible compute a different value for each When the user selects Part time the value of PrcA will change to PrcB this is the code i used <!====================================================================================> <script language="javascript"> <!--// function dm(amount) { string = "" + amount; dec = string.length - string.indexOf('.'); if (string.indexOf('.') == -1) return string + '.00'; if (dec == 1) return string + '00'; if (dec == 2) return string + '0'; if (dec > 3) return string.substring(0,string.length-dec+3); return string; } function calculate() { QtyA = 0; TotA = 0; PrcA = 1280; PrcB = 640; if (document.form1.qtyA.value > "") { QtyA = document.form1.qtyA.value }; document.form1.qtyA.value = eval(QtyA); TotA = QtyA * PrcA; document.form1.totalA.value = dm(eval(TotA)); Totamt = eval(TotA) ; document.form1.GrandTotal.value = dm(eval(Totamt)); } //--> </script> <!====================================================================================> <p> <label for="acct" style="margin-right:90px;"><strong>Account Type<strong><font color=red size=3> * </font></strong></label> <select name="acct" style="background-color:white;" class="validate[custom[serv]] select-input" id="acct" value=""> <option value="Full Time">Full-Time</option> <option value="Part Time">Part-Time</option> <option selected="selected" value=""></option> </select></p> <!====================================================================================> <script> $(document).ready(function() { $("input[name$='acct']").select(function() { var test = $(this).val(); $("div.desc").hide(); $("#acct" + test).show(); }); }); </script> <!====================================================================================> <p> <table><tr><td> <lable style="margin-right:91px;"># of Agent(s)<font color=red size=3> * </font></lable> </td><td> <input style="width:25px; margin-left:5px;" type="text" class="validate[custom[agnt]] text-input" name="qtyA" id="qtyA" onchange="calculate()" /> </td><td> <div id="acctFull Time" class="desc"> x 1280 = </div> <div id="acctPart Time" class="desc" style="display:none"> x 640 = </div> </td><td> $<input style="width:80px; margin-left:5px;" type="text" readonly="readonly" name="totalA" id="totalA" onchange="calculate()" /> </p> </td></tr></table> is there any way for me to achieve this?

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  • Is there a need for zero-out DIV's margin and padding?

    - by ssg
    I wonder if on any browser div element comes with a preset margin/padding value other than zero. As far as I know, div and span come with zero padding and margin values by standard to make them suitable canvas for style decoration. Even better, is there a definite standard for default styles for all elements that is cross-browser which we can make assumptions upon? For instance FORM comes with top/bottom margins, OL/UL come with padding-left's. I occasionally see a * { margin: 0; padding: 0; } and this just looks like a dirty hack without knowing the reasons or consequences. Anyone has any better approach to this?

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  • How important is the website logo on a page?

    - by meo
    I have stopped to insert "img" tags for the logo of the page. Because its not an image that is part of the content, its a design element but its still a information I want to have control over. So I just write the title in a "a" element as display: block, overflow: hidden and I push the text out with some padding. I think thats a good solution for SEO because you are keeping control of how important the logo should be on a page. But now my dilemma is starting. How important is the logo of a page? "A list apart" puts the logo in a h1 element. But is the logo really that important? On article pages you have two H1 elements (the logo and the title of the article) Most of the sites just use a img balbal /a, but I don't like this solution. Because I just want to use img for images that are part of the content... Its kinda philosophical question, I hope you can give me some input or some articles to read about that...

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  • Checkbox not checking inside div in Firefox

    - by mike
    Weird problem. I don't know if anyone can shed some light on this? I have a checkbox inside a div. It works fine in IE but not Firefox. I have to click the space around the checkbox that is occupied by the div (sort of like a label) for the checkbox to tick on and off. Directly clicking the checkbox does not show it as ticked on or off, even though in firebug it is showing that it is in a checked state and an unchecked state. Only in FF does this happen.....

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  • How to override "inherited" z-indexes?

    - by Earlz
    I am needing to override the notion of inherited z-indexes. For instance in this code <style> div{ background-color:white; top: 0px; bottom: 0px; left: 0px; right: 0px; } </style> <div style="position: fixed; z-index: 2;"> div 1 <div style="position: fixed; z-index: 3;"> div 2 </div> </div> <div style="position: fixed; z-index: 2;"> div 3 </div> http://jsbin.com/epoqo3/3 I want for div 2 to be displayed, but instead div 3 is displayed. How can I change this behavior without changing my structure.

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  • i get error when i try to upload a file?

    - by getaway
    I keep getting an error:Notice: Undefined index: on line 35 line 35: $handle = new Upload($_FILES['my_field']); this is my input field <input type="file" size="32" name="my_field" value="" /> I do not understand this error, thanks!!! EDIT: <form name="upload" id="upload" enctype="multipart/form-data" method="post" action="actions/upload.php" /> <p><input type="file" size="32" name="my_field" value="" /></p> <p class="button"><input type="hidden" name="action" value="image" /> <br> <input style="margin-left:224px;" type="submit" name="submit" value="upload" />

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