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  • Randomised objects are assigning themselves to more than one array location

    - by Thaddeus Aid
    this.size = 9; this.populationSize = 10; Random rand = new Random(); Integer[][] easy1 = new Integer[size][size]; easy1 = this.initializeEasy1(easy1); this.sudokuArray = new Sudoku[this.populationSize]; for (int i = 0; i < this.sudokuArray.length; i++){ long seed = rand.nextLong(); System.out.println("" + seed); this.sudokuArray[i] = new Sudoku(easy1, this.size, seed); } I am building an evolutionary sudoku solver and I am having a problem where the last Sudoku object is overwriting all the other objects in the array. Where in the code did I mess up? /edit here is the constructor of the class public Sudoku(Integer[][] givensGrid, int s, long seed){ this.size = s; this.givens = givensGrid; this.grid = this.givens.clone(); Random rand = new Random(seed); System.out.println("Random " + rand.nextInt()); // step though each row of the grid for (int i = 0; i < size; i++){ ArrayList<Integer> numbers = new ArrayList<Integer>(); numbers = this.makeNumbers(numbers); // step through each column to find the givens and remove from numbers for (int j = 0; j < size; j++){ if (this.grid[i][j] != 0){ numbers.remove(this.grid[i][j]); } } // go back through the row and assign the numbers randomly for (int j = 0; j < size; j++){ if (this.grid[i][j] == 0){ int r = rand.nextInt(numbers.size()); this.grid[i][j] = numbers.get(r); numbers.remove(r); } } } System.out.println("============="); System.out.println(this.toString()); }

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  • one more time about loop that doesn't work

    - by unit
    I have asked a couple of questions about this for loop: String[] book = new String [ISBN_NUM]; bookNum.replaceAll("-",""); if (bookNum.length()!=ISBN_NUM) throw new ISBNException ("ISBN "+ bookNum + " must be 10 characters"); for (int i=0;i<bookNum.length();i++) { if (Character.isDigit(bookNum.charAt(i))) book[j]=bookNum.charAt(i); //this is the problem right here j++; if (book[9].isNotDigit()|| book[9]!="x" || book[9]!="X") throw new ISBNException ("ISBN " + bookNum + " must contain all digits" + "or 'X' in the last position"); } which will not compile. An answer I had from the other question I asked told me that the line where the error occurs is wrong in that bookNum.charAt(i) is an (immutable) string, and I can't get the values into a book array that way. What I need to do on my assignment is check an ISBN number (bookNum) to see that it is all numbers, except the last digit can be an 'x' (valid ISBN). Is this the best way to do it? If so, what the hell am I doing wrong? If not, what method would be a better one to use?

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  • ask. help me to compare two array of integers and the order does not matter.

    - by stdnoit
    [Example] <1 2 3 4 = <3 1 2 4 <1 2 3 4 != <3 4 1 1 and ummm it is in java. cant use hashmap table or anything just pure without library. I know there are two ways. 1. sort them and compare the array index by index 2. use two for loops and compare the outer index with the inner index. ( i have been trying with this but still not working) for(int i = 0; i < n; i++) { for(int j = 0; j < n; j++) { if(a[i] != a[j] && j == n) return false; } } return true; anything wrong with the code ? thanks

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  • Circle class in java

    - by user292395
    I need to get the Java code for the below problem asap. Create a class Circle that will allow us to define a circle with a specific radius. Your class should include the following methods: A constructor that can create a circle with a specified radius. A method setRadius that sets a specific value as a new radius for an existing circle. A method getRadius that returns the radius of an existing circle. A method toString that returns a String with all the information about an existing circle. A method computeArea that computes the area of a circle A method computePerimeter that computes the perimeter of a circle.

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  • error C2059: syntax error : ']', i cant figure out why this coming up in c++

    - by user320950
    void display_totals(); int exam1[100][3];// array that can hold 100 numbers for 1st column int exam2[100][3];// array that can hold 100 numbers for 2nd column int exam3[100][3];// array that can hold 100 numbers for 3rd column int main() { int go,go2,go3; go=read_file_in_array; go2= calculate_total(exam1[],exam2[],exam3[]); go3=display_totals; cout << go,go2,go3; return 0; } void display_totals() { int grade_total; grade_total=calculate_total(exam1[],exam2[],exam3[]); } int calculate_total(int exam1[],int exam2[],int exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j; calc_tot=read_file_in_array(exam[100][3]); exam1[][]=exam[100][3]; exam2[][]=exam[100][3]; exam3[][]=exam[100][3]; for(i=0;i<100;i++); { if(exam1[i] <=90 && exam1[i] >=100) { above90++; cout << above90; } } return exam1[i],exam2[i],exam3[i]; } int read_file_in_array(int exam[100][3]) { ifstream infile; int num, i=0,j=0; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++); // array numbers less than 100 { for(j=0;j<3;j++); // while reading get 1st array or element infile >> exam[i][j]; cout << exam[i][j] << endl; } } infile.close(); return exam[i][j]; }

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  • How do I add an object to a binary tree based on the value of a member variable?

    - by Max
    How can I get a specific value from an object? I'm trying to get a value of an instance for eg. ListOfPpl newListOfPpl = new ListOfPpl(id, name, age); Object item = newListOfPpl; How can I get a value of name from an Object item?? Even if it is easy or does not interest you can anyone help me?? Edited: I was trying to build a binary tree contains the node of ListOfPpl, and need to sort it in the lexicographic. Here's my code for insertion on the node. Any clue?? public void insert(Object item){ Node current = root; Node follow = null; if(!isEmpty()){ root = new Node(item, null, null); return; }boolean left = false, right = false; while(current != null){ follow = current; left = false; right = false; //I need to compare and sort it if(item.compareTo(current.getFighter()) < 0){ current = current.getLeft(); left = true; }else { current = current.getRight(); right = true; } }if(left) follow.setLeft(new Node(item, null, null)); else follow.setRight(new Node(item, null, null)); }

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  • How to return a copy of the data in C++

    - by Josh Curren
    I am trying to return a new copy of the data in a C++ Template class. The following code is getting this error: invalid conversion from ‘int*’ to ‘int’. If I remove the new T then I am not returning a copy of the data but a pointer to it. template<class T> T OrderedList<T>::get( int k ) { Node<T>* n = list; for( int i = 0; i < k; i++ ) { n=n->get_link(); } return new T( n->get_data() ); // This line is getting the error ********** }

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  • Very simple code for number search gives me infinite loop

    - by Joshua
    Hello, I am a newbie Computer Science high school student and I have trouble with a small snippet of code. Basically, my code should perform a basic CLI search in an array of integers. However, what happens is I get what appears to be an infinite loop (BlueJ, the compiler I'm using, gets stuck and I have to reset the machine). I have set break points but I still don't quite get the problem...(I don't even understand most of the things that it tells me) Here's the offending code (assume that "ArrayUtil" works, because it does): import java.util.Scanner; public class intSearch { public static void main(String[] args) { search(); } public static void search() { int[] randomArray = ArrayUtil.randomIntArray(20, 100); Scanner searchInput = new Scanner(System.in); int searchInt = searchInput.nextInt(); if (findNumber(randomArray, searchInt) == -1) { System.out.println("Error"); }else System.out.println("Searched Number: " + findNumber(randomArray, searchInt)); } private static int findNumber(int[] searchedArray, int searchTerm) { for (int i = 0; searchedArray[i] == searchTerm && i < searchedArray.length; i++) { return i; } return -1; } } This has been bugging me for some time now...please help me identify the problem!

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  • tiled images in swing

    - by sasquatch90
    I have task to prepare two windows with swing. One contains grid of squares, with random numbers in them. In second I need to load pieces of tiled image and then show them in the correct order, forming tiled image. Windows should look like this : http://img535.imageshack.us/img535/3129/lab8a.jpg Okay so how to bite this ? I've used swing only few times to draw some 2d polylines, so basically I just theoretically now what to do. Ok, so window number 1: I start with creating Jframe for the window. Then I do for loop and in it create 16 JLabels with random numbers in them ? How to set margins between each tile and the whole window ? Window number 2 : So I start the same, but instead of loading numbers I add images ? Now, how can I load image from file and then set it as background ?

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  • JAX-B annotations for elements that inherit from a parent

    - by AlexM
    When adding JAX-B Java annotations for Java classes - if I have a parent Class Entry, with two children, Book and JournalArticle, Would I add these annotations for all three classes: @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement ie: @XmlSeeAlso({au.com.library.Book.class, au.com.library.JournalArticle.class}) @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public abstract class Entry implements Serializable{ private static final long serialVersionUID = -1895155325179947581L; @XmlElement(name="title") protected String title; @XmlElement(name="author") protected String author; @XmlElement(name="year") protected int year; and @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public class Book extends Entry { @XmlElement(name="edition") private String edition; @XmlElement(name="publisher") private String publisher; @XmlElement(name="placeOfPublication") private String placeOfPub; and @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public class JournalArticle extends Entry { @XmlElement(name="journalTitle") private String journalTitle; @XmlElement(name="volume") private String volume; @XmlElement(name="issue") private String issue; @XmlElement(name="pageNumbers") private String pgNumbers;

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  • What is wrong with my version of strchr?

    - by Eduard Saakashvili
    My assignment is to write my own version of strchr, yet it doesn't seem to work. Any advice would be much appreciated. Here it is: char *strchr (const char *s, int c) //we are looking for c on the string s { int dog; //This is the index on the string, initialized as 0 dog = 0; int point; //this is the pointer to the location given by the index point = &s[dog]; while ((s[dog] != c) && (s[dog] != '\0')) { //it keeps adding to dog until it stumbles upon either c or '\0' dog++; } if (s[dog]==c) { return point; //at this point, if this value is equal to c it returns the pointer to that location } else { return NULL; //if not, this means that c is not on the string } }

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  • SQL query joining rows with same value

    - by user1285737
    I need to write a query that creates a view that calculates the total cost of each sale, by considering quantity and price of each bought item. The view should return the debit and total cost. In the answer each debit-number should only occur once. Thanks in advance Table ITEM: ID NAME PRICE 118 Jeans 100 120 Towel 20 127 Shirt 55 Table DEBIT: DEBIT ITEM Quantity 100581 118 5 100581 120 1 100586 127 5

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  • Help me understand why page sizes are a power of 2?

    - by eric
    Answer I need help with is: Recall that paging is implemented by breaking up an address into a page and offset number. It is most efficient to break the address into X page bits and Y offset bits, rather than perform arithmetic on the address to calculate the page number and offset. Because each bit position represents a power of 2, splitting an address between bits results in a page size that is a power of 2. i don't quite understand this answer, can anyone give a simpler explanation?

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  • How could i evaluate this to a code.?

    - by WM
    There is a medieval puzzle about an old woman and a basket of eggs. On her way to market, a horseman knocks down the old woman and all the eggs are broken. The horseman will pay for the eggs, but the woman does not remember the exact number she had, only that when she took the eggs in pair, there was one left over; similarly, there was one left over when she took them three or five at a time. When she took them seven at a time, however, none were left. Write an application that can determine the smallest number of eggs the woman could have had.

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  • Basic C# problem

    - by Juan
    Determine if all the digits of the sum of n -numbers and swapped n are odd. For example: 36 + 63 = 99, y 409 + 904 = 1313. Visual Studio builds my code, there is still something wrong with it ( it doesnt return an answer) can you please help me here? using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { long num = Convert.ToInt64(Console.Read()); long vol = voltea(num); long sum = num + vol; bool simp = simpares(sum); if (simp == true) Console.Write("Si"); else Console.Write("No"); } static private bool simpares(long x) { bool s = false; long [] arreglo = new long [1000]; while ( x > 0) { arreglo [x % 10] ++; x /=10; } for (long i=0 ; i <= arreglo.Length ; i++) { if (arreglo [i]%2 != 0) s = true; } return s; } static private long voltea(long x) { long v = 0; while (v > 0) { v = 10 * v + x % 10; x /= 10; } return v; } } }

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  • Sorting a very large text file in Java

    - by Alice
    Hi, I have a large text file I need to sort in Java. The format is: word [tab] frequency [new line] The algorithm for sorting is: Read some of the file, filtering for purlely alphabetic words. Once you have X number of alphabetic words, call Collections.sort and write the result to a file. Repeat until you have finished reading the file. Start reading two sorted files, comparing line by line for the word with higher frequency, and writing at the same time to a new file as to not load much into your memory Repeat until all files are merged into one large file Right now I've divided the large file into smaller ones (sorted by descending frequency) with 10,000 lines each. I know I need to somehow merge these files back together, but I'm not sure how to go about this. I've created a LinkedList to keep track of all the files created. The algorithm says to compare each line in the two files, except I've tried a case where , say file1 = 8,6,5,3,1 and file2 = 9,8,8,8,8. Then if I compare them line by line I would get file3 = 9,8,8,6,8,5,8,3,8,1 which is incorrectly sorted (they should be in decreasing order). I think I'm misunderstanding some part of the algorithm. If someone could point out what I should do instead, I'd greatly appreciate it. Thanks. edit: Yes this is an assignment. We aren't allowed to increase memory unfortunately :(

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  • Finding number of different paths

    - by peiska
    I have a game that one player X wants to pass a ball to player Y, but he can be playing with more than one player and the others players can pass the ball to Y. I want to know how many different paths can the ball take from X to Y? for example if he is playing with 3 players there are 5 different paths, 4 players 16 paths, if he is playing with 20 players there are 330665665962404000 paths, and 40 players 55447192200369381342665835466328897344361743780 that the ball can take. the number max. of players that he can play with is 500. I was thinking in using Catalan Numbers? do you think is a correct approach to solve this? Can you give me some tips.

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  • Using Java method to display HTML code

    - by javArc
    Hey folks, ok so this is my problem, I need to display HTML code in a jsp, which wouldn't be a problem, except a requirement for this project is that we place all the code in a public class file and have seperate methods for each chunk(header, sidebar footer, etc). Now here's where i'm confused: "Your method should take the PrintWriter as a parameter to print out each line of HTML, and should have a return type of void" What does that mean? How do I pass the PrintWriter into a method? Does this make sense to anyone?

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  • Big O Complexity of a method

    - by timeNomad
    I have this method: public static int what(String str, char start, char end) { int count=0; for(int i=0;i<str.length(); i++) { if(str.charAt(i) == start) { for(int j=i+1;j<str.length(); j++) { if(str.charAt(j) == end) count++; } } } return count; } What I need to find is: 1) What is it doing? Answer: counting the total number of end occurrences after EACH (or is it? Not specified in the assignment, point 3 depends on this) start. 2) What is its complexity? Answer: the first loops iterates over the string completely, so it's at least O(n), the second loop executes only if start char is found and even then partially (index at which start was found + 1). Although, big O is all about worst case no? So in the worst case, start is the 1st char & the inner iteration iterates over the string n-1 times, the -1 is a constant so it's n. But, the inner loop won't be executed every outer iteration pass, statistically, but since big O is about worst case, is it correct to say the complexity of it is O(n^2)? Ignoring any constants and the fact that in 99.99% of times the inner loop won't execute every outer loop pass. 3) Rewrite it so that complexity is lower. What I'm not sure of is whether start occurs at most once or more, if once at most, then method can be rewritten using one loop (having a flag indicating whether start has been encountered and from there on incrementing count at each end occurrence), yielding a complexity of O(n). In case though, that start can appear multiple times, which most likely it is, because assignment is of a Java course and I don't think they would make such ambiguity. Solving, in this case, is not possible using one loop... WAIT! Yes it is..! Just have a variable, say, inc to be incremented each time start is encountered & used to increment count each time end is encountered after the 1st start was found: inc = 0, count = 0 if (current char == start) inc++ if (inc > 0 && current char == end) count += inc This would also yield a complexity of O(n)? Because there is only 1 loop. Yes I realize I wrote a lot hehe, but what I also realized is that I understand a lot better by forming my thoughts into words...

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  • How to define a class with variable properties?

    - by user1723326
    I'm making a database program. I want the user to be able to define their own columns, as many as they want. How would I then define each record in its class file?(Since the properties would be different user to user) EDIT: It's part of a school assignment-it's going to hold different scores and the likes for the teacher for different students they can add, but they will also be able to add a new assignment, test(a column) .

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