XSLT: need to replace document('')
- by Daziplqa
I've the following xslt file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- USDomesticCountryList - USE UPPERCASE LETTERS ONLY -->
<xsl:variable name="USDomesticCountryList">
<entry name="US"/>
<entry name="UK"/>
<entry name="EG"/>
</xsl:variable>
<!--// USDomesticCountryList -->
<xsl:template name="IsUSDomesticCountry">
<xsl:param name="countryParam"/>
<xsl:variable name="country" select="normalize-space($countryParam)"/>
<xsl:value-of select="normalize-space(document('')//xsl:variable[@name='USDomesticCountryList']/entry[@name=$country]/@name)"/>
</xsl:template>
</xsl:stylesheet>
I need to replace the "document('')" xpath function, what should I use instead?
I've tried to remove it completely but the xsl document doesn't work for me!
I need to to so because the problem is :
I am using some XSLT document that uses the above file, say document a.
So I have document a that includes the above file (document b).
I am using doc a from java code, I am do Caching for doc a as a javax.xml.transform.Templates object to prevent multiple reads to the xsl file on every transformation request.
I found that, the doc b is re-calling itself from the harddisk, I believe this is because of the document('') function above, so I wanna replace/remove it.
Thanks.
