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  • a function that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n

    - by martin
    I need to write a function called multipleOf3 that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n and here is the result i want [Note: No number returned can be greater than the value of the parameter n] Examples: multipleOf3(0) -- 0 multipleOf3(1) -- 0 multipleOf3(2) -- 0 multipleOf3(3) -- 0 or 3 multipleOf3(20) -- 0 or 3 or 6 or 9 or 12 or 15 or 18

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  • maching strings

    - by kiran
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions for def countSubStringMatch(target,key): and def countSubStringMatchRecursive (target, key): For the remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures.

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  • Common elements comparison between 2 lists.

    - by Daniel
    def common_elements(list1, list2): """ Return a list containing the elements which are in both list1 and list2 >>> common_elements([1,2,3,4,5,6], [3,5,7,9]) [3, 5] >>> common_elements(['this','this','n','that'],['this','not','that','that']) ['this', 'that'] """ for element in list1: if element in list2: return list(element) Got that so far, but can't seem to get it to work! Thanks

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  • Problems with 'while' loop and 'for' loop when reading through file

    - by David Beckham
    I wasted plenty of hours trying to figure out the problem but no luck. Tried asking the TA at my school, but he was useless. I am a beginner and I know there are a lot of mistakes in it, so it would be great if I can get some detail explanation as well. Anyways, basically what I am trying to do with the following function is: Use while loop to check and see if random_string is in TEXT, if not return NoneType if yes, then use a for loop to read lines from that TEXT and put it in list, l1. then, write an if statement to see if random_string is in l1. if it is, then do some calculations. else read the next line Finally, return the calculations as a whole. TEXT = open('randomfile.txt') def random (TEXT, random_string): while random_string in TEXT: for lines in TEXT: l1=TEXT.readline().rsplit() if random_string in l1: ''' do some calculations ''' else: TEXT.readline() #read next line??? return #calculations return None

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  • Preventing a security breach

    - by Wiz
    I am creating a website where you "post", and the form content is saved in a MySql database, and upon loading the page, is retrieved, similar to facebook. I construct all the posts and insert raw html into a template. The thing is, as I was testing, I noticed that I could write javascript or other HTML into the form and submit it, and upon reloading, the html or JS would treated as source code, not a post. I figured that some simple encoding would do the trick, but using is not working. Is there an efficient way to prevent this type of security hole?

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  • Defining the hash of an object as the sum of hashes of its members

    - by Space_C0wb0y
    I have a class that represents undirected edges in a graph. Every edge has two members vertex1 and vertex2 representing the vertices it connects. The problem is, that an edge can be specified two directions. My idea was now to define the hash of an edge as the sum of the hashes of its vertices. This way, the direction plays no role anymore, the hash would be the same. Are there any pitfalls with that?

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  • How to quickly parse a list of strings

    - by math
    If I want to split a list of words separated by a delimiter character, I can use >>> 'abc,foo,bar'.split(',') ['abc', 'foo', 'bar'] But how to easily and quickly do the same thing if I also want to handle quoted-strings which can contain the delimiter character ? In: 'abc,"a string, with a comma","another, one"' Out: ['abc', 'a string, with a comma', 'another, one'] Related question: How can i parse a comma delimited string into a list (caveat)?

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  • Extending appengine's db.Property with caching

    - by Noio
    I'm looking to implement a property class for appengine, very similar to the existing db.ReferenceProperty. I am implementing my own version because I want some other default return values. My question is, how do I make the property remember its returned value, so that the datastore query is only performed the first time the property is fetched? What I had is below, and it does not work. I read that the Property classes do not belong to the instances, but to the model definition, so I guess that the return value is not cached for each instance, but overwritten on the model every time. Where should I store this _resolved variable? class PageProperty(db.Property): data_type = Page def get_value_for_datastore(self, model_instance): page = super(PageProperty, self).get_value_for_datastore(model_instance) self._resolved = page return page.key().name() def make_value_from_datastore(self, value): if not hasattr(self, '_resolved'): self._resolved = Page.get_by_name(value) return self._resolved

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  • how am I supposed to call the function?

    - by user1816768
    I wrote a program which tells you knight's movement (chess). For example if I wanted to know all possible moves, I'd input: possibilites("F4") and I'd get ['D3', 'D5', 'E2', 'E6', 'G2', 'G6', 'H3', 'H5'] as a result, ok I did that, next, I had to write a function in which you input two fields and if those fields are legal, you'd get True and if they're not you'd get False(I had to use the previous function). For example: legal("F4","D3") >>>True code: def legal(field1,field2): c=possibilities(field1) if field1 and field2 in a: return True return False I'm having a problem with the following function which I have to write: I have to put in path of the knight and my function has to tell me if it's legal path, I'm obliged to use the previous function. for example: >>> legal_way(["F3", "E1", "G2", "H4", "F5"]) True >>> legal_way(["F3", "E1", "G3", "H5"]) False >>> legal_way(["B4"]) True I know I have to loop through the list and put first and second item on it in legal(field1,field2) and if it's false, everything is false, but if it's true I have to continue to the end, and this has to work also if I have only one field. I'm stuck, what to do? def legal_way(way): a=len(way) for i in range(0,a-2): if a==1: return true else if legal(way[i],way[i+1]: return True return False and I get True or index out of range

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  • Prevent web2py from caching ?

    - by Joe
    Hi ! I'm working with web2py and for some reason web2py seems to fail to notice when code has changed in certain cases. I can't really narrow it down, but from time to time changes in the code are not reflected, web2py obviously has the old version cached somewhere. The only thing that helps is quitting web2py and restarting it (i'm using the internal server). Any hints ? Thank you !

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  • gevent, sockets and syncronisation

    - by schlamar
    I have multiple greenlets sending on a common socket. Is it guaranteed that each package sent via socket.sendall is well separated or do I have to acquire a lock before each call to sendall. So I want to prevent the following scenario: g1 sends ABCD g2 sends 1234 received data is mixed up, for example AB1234CD expected is either ABCD1234 or 1234ABCD Update After a look at the sourcecode I think this scenario cannot happen. But I have to use a lock because g1 or g2 can crash on the sendall. Can someone confirm this?

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  • AppEngine: Can I write a Dynamic property (db.Expando) with a name chosen at runtime?

    - by MarcoB
    If I have an entity derived from db.Expando I can write Dynamic property by just assigning a value to a new property, e.g. "y" in this example: class MyEntity(db.Expando): x = db.IntegerProperty() my_entity = MyEntity(x=1) my_entity.y = 2 But suppose I have the name of the dynamic property in a variable... how can I (1) read and write to it, and (2) check if the Dynamic variable exists in the entity's instance? e.g. class MyEntity(db.Expando): x = db.IntegerProperty() my_entity = MyEntity(x=1) # choose a var name: var_name = "z" # assign a value to the Dynamic variable whose name is in var_name: my_entity.property_by_name[var_name] = 2 # also, check if such a property esists if my_entity.property_exists(var_name): # read the value of the Dynamic property whose name is in var_name print my_entity.property_by_name[var_name] Thanks...

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  • Own params to PeriodicTask run() method in Celery

    - by Alex Isayko
    Hello to all! I am writing a small Django application and I should be able to create for each model object its periodical task which will be executed with a certain interval. I'm use for this a Celery application, but i can't understand one thing: class ProcessQueryTask(PeriodicTask): run_every = timedelta(minutes=1) def run(self, query_task_pk, **kwargs): logging.info('Process celery task for QueryTask %d' % query_task_pk) task = QueryTask.objects.get(pk=query_task_pk) task.exec_task() return True Then i'm do following: >>> from tasks.tasks import ProcessQueryTask >>> result1 = ProcessQueryTask.delay(query_task_pk=1) >>> result2 = ProcessQueryTask.delay(query_task_pk=2) First call is success, but other periodical calls returning the error - TypeError: run() takes exactly 2 non-keyword arguments (1 given) in celeryd server. So, can i pass own params to PeriodicTask run() ? Thanks!

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  • Is it possibile to modify a link value with Beautifulsoup without recreating the all link?

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo</a> <a href="http://www.bar.com" rel="nofollow">this is bar</a> </p> is it possible to modify the <a> node values ("this i foo" and "this is bar") adding the suffix "PARSED" to the value without recreating the all link? The result need to be like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo_PARSED</a> <a href="http://www.bar.com" rel="nofollow">this is bar_PARSED</a> </p> And code should be something like: from BeautifulSoup import BeautifulSoup soup = BeautifulSoup(html) for link_tag in soup.findAll('a'): link_tag.string = link_tag.string + '_PARSED' #This obviously does not work

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  • Search one element of a list in another list recursively

    - by androidnoob
    I have 2 lists old_name_list = [a-1234, a-1235, a-1236] new_name_list = [(a-1235, a-5321), (a-1236, a-6321), (a-1234, a-4321), ... ] I want to search recursively if the elements in old_name_list exist in new_name_list and returns the associated value with it, for eg. the first element in old_name_list returns a-4321, second element returns a-5321, and so on until old_name_list finishes. I have tried the following and it doesn't work for old_name, new_name in zip(old_name_list, new_name_list): if old_name in new_name[0]: print new_name[1] Is the method I am doing wrong or I have to make some minor changes to it? Thank you in advance.

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  • Trying to create a group of button sprites

    - by user1449653
    Good day, I have like 15 images I need to be buttons. I have buttons working with a Box() (Box - looks like this) class Box(pygame.sprite.Sprite): def __init__(self): pygame.sprite.Sprite.__init__(self) self.image = pygame.Surface((35, 30)) self.image = self.image.convert() self.image.fill((255, 0, 0)) self.rect = self.image.get_rect() self.rect.centerx = 25 self.rect.centery = 505 self.dx = 10 self.dy = 10 I am trying to make the buttons work with image sprites. So I attempted to copy the class style of the box and do the same for my Icons.. code looks like this... class Icons(pygame.sprite.Sprite): def __init__(self): pygame.sprite.Sprite.__init__(self) self.image = pygame.image.load("images/airbrushIC.gif").convert() self.rect = self.image.get_rect() self.rect.x = 25 self.rect.y = 550 the code in the main() rect = image.get_rect() rect.x = 25 rect.y = 550 ic1 = Icons((screen.get_rect().x, screen.get_rect().y)) screen.blit(ic1.image, ic1.rect) pygame.display.update() This code produces a positional (accepts 1 argument but 2 are there) error or an image is not referenced error (inside the Icon class). I'm unsure if this is the right way to go about this anyways.. I know for sure that I need to load all the images (as sprites)... store them in an array... and then have my mouse check if it is clicking one of the items in the array using a for loop. Thanks. EDIT QUESTION 2: class Icons(pygame.sprite.Sprite): def init(self, *args): pygame.sprite.Sprite.init(self, *args) self.image = pygame.image.load("images/airbrushIC.gif").convert() self.rect = self.image.get_rect() ic1 = self.image self.rect.x = 10 self.rect.y = 490 self.image = pygame.image.load("images/fillIC.gif").convert() self.rect = self.image.get_rect() ic2 = self.image self.rect.x = 10 self.rect.y = 540 Thanks to your help I got the Icons class loading ONE image. Its not loading both. Obviously because its being overwritten by the second one. It seems that "class" for this purpose isn't what I need. Which begs the question how I make sprites outside of a class.. If there is a way to make the class work please let me know.

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  • Debugging (displaying) SQL command sent to the db by SQLAlchemy

    - by morpheous
    I have an ORM class called Person, which wraps around a person table: After setting up the connection to the db etc, I run the ff statement. people = session.query(Person).all() The person table does not contain any data (as yet), so when I print the variable people, I get an empty list. I renamed the table referred to in my ORM class People, to people_foo (which does not exist). I then run the script again. I was surprised that no exception was thrown when attempting to access a table that does not exist. I therefore have the following 2 questions: How may I setup SQLAlchemy so that it propagates db errors back to the script? How may I view (i.e. print) the SQL that is being sent to the db engine If it helps, I am using PostgreSQL as the db

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  • Word filter that groups words?

    - by Legend
    Is there any library that achieves the following: Convert Microsoft Windows 98 Microsoft Windows XP Windows 7 Windows Ultimate Desktop Windows to Windows 4 The complicated part here is to recognize that "Desktop Windows" is an anomaly here and not count it. If nothing is added before the word "Windows", perhaps it can be counted but if there is something else and the suffix does not match any popular suffix, it can still be counted. Maybe I am a little vague here but perhaps someone could have an idea about what I am talking about here. Any suggestions?

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  • Convert octet string to human readable

    - by Michael Lang
    Using the pysnmp framework i get some values doing a snmp walk. Unfortunately for the oid 1.3.6.1.21.69.1.5.8.1.2 (DOCS-CABLE-DEVICE-MIB) i get a weird result which i cant correctly print here since it contains ascii chars like BEL ACK When doing a repr i get: OctetString('\x07\xd8\t\x17\x03\x184\x00') But the output should look like: 2008-9-23,3:24:52.0 the format is called "DateAndTime". How can i translate the OctetString output to a "human readable" date/time ?

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  • if else-if making code look ugly any cleaner solution?

    - by Vishal
    I have around 20 functions (is_func1, is_fucn2, is_func3...) returning boolean I assume there is only one function which returns true and I want that! I am doing: if is_func1(param1, param2): # I pass 1 to following abc(1) # I pass 1 some_list.append(1) elif is_func2(param1, param2): # I pass 2 to following abc(2) # I pass 1 some_list.append(2) ... . . elif is_func20(param1, param2): ... Please note: param1 and param2 are different for each, abc and some_list take parameters depending on the function. The code looks big and there is repetition in calling abc and some_list, I can pull this login in a function! but is there any other cleaner solution? I can think of putting functions in a data structure and loop to call them.

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  • trying to WHOIS a site within IRC

    - by SourD
    if data.find('!whois') != -1: s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect(("com.whois-servers.net", 43)) s.send('www.msn.com' + "\r\n") response = '' while True: d = s.recv(4096) response += d if d == '': break s.send('PRIVMSG ' + chan + " " + response + '\r\n') s.close() when I type !whois on the channel, it doesnt do anything, I'm probably doing this wrong. Any help will be appreciate it. Thanks. Note: There's another socket already connected.

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  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

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