Search Results

Search found 19975 results on 799 pages for 'disk queue length'.

Page 421/799 | < Previous Page | 417 418 419 420 421 422 423 424 425 426 427 428  | Next Page >

  • External hard drive no detected in a vista ultimate

    - by raghavendra
    Hi, I have created a partition in my external HD and later i am trying to install XP over Vista . So i have entered into my DOS prompt and i choose the DISK TYPE and i choose external DD and i tried to CLEAN it , Immediately my external HD is asked for FORMAT and i rejected it . After that i restarted my system , therefore i cannot able to see my external HD on my sysmen External HD: Seagate Free agent(500GB)

    Read the article

  • How to enable attachment using Apache File upload

    - by Stardust
    I am using Apache commons File upload API to Store the file from JSP to servlets in temp directory, but I don't know what should I do next to send the email as an attachment using javamail API. How can I retrieve those files which is written in temp directory using Apache Fileupload API to send them as attachment to mail Server. How will writing those files either to memory or disk will help me?

    Read the article

  • ignore extra spaces when using fgets

    - by Gary
    Hi, I'm using fgets with stdin to read in some data, with the max length i read in being 25. With one of the tests I'm running on this code, there are a few hundred spaces after the data that I want - which causes the program to fail. Can someone advise me as to how to ignore all of these extra spaces when using fgets and go to the next line? Thanks

    Read the article

  • Are hash collisions with different file sizes just as likely as same file size?

    - by rwmnau
    I'm hashing a large number of files, and to avoid hash collisions, I'm also storing a file's original size - that way, even if there's a hash collision, it's extremely unlikely that the file sizes will also be identical. Is this sound (a hash collision is equally likely to be of any size), or do I need another piece of information (if a collision is more likely to also be the same length as the original). Or, more generally: Is every file just as likely to produce a particular hash, regardless of original file size?

    Read the article

  • PHP script works fine until I send it a parameter from HTTPService in Flash Builder 4?

    - by ben
    I'm using a PHP script to read an RSS feed in my Flex 4 app. The script works when I put the url of the feed in the actual script, but I can't get it to work when I try to send the URL as a parameter from a HTTPService in Flex. Can anyone tell me what I'm doing wrong? Here is the HTTPService from Flex 4 that I'm using: <mx:HTTPService url="http://talk.6te.net/proxy.php" id="proxyService" method="POST" result="rssResult()" fault="rssFault()"> <mx:request> <url> http://feeds.feedburner.com/nah_right </url> </mx:request> </mx:HTTPService> This is the script that works: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, "http://feeds.feedburner.com/nah_right"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> But this is what I actually want to use, but it doesn't work: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, $_REQUEST['url']); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> Here is the request and response output of the HTTPService from the network monitor in Flash Builder 4 (using the PHP script that doesn't work): Request: POST /proxy.php HTTP/1.1 Host: talk.6te.net User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Content-type: application/x-www-form-urlencoded Content-length: 97 url=%0A%09%09%09%09%09http%3A%2F%2Ffeeds%2Efeedburner%2Ecom%2Fnah%5Fright%0A%20%20%20%20%09%09%09 Response: HTTP/1.1 200 OK Date: Mon, 10 May 2010 03:23:27 GMT Server: Apache X-Powered-By: PHP/5.2.13 Content-Length: 15 Content-Type: text/html <url> malformed I've tried putting the URL in " " in the HTTPService, but that didn't do anything. Any help would be greatly appreciated!

    Read the article

  • OperationContext.Current is null and all other contexts too

    - by HeavyWave
    I have a WCF service defined as following: [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] [ServiceBehavior(IncludeExceptionDetailInFaults = true, InstanceContextMode = InstanceContextMode.PerCall)] public partial class FrontEndService : IFrontEndService However, most of the time (but not always -_-) InstanceContext.Current is null, as well as HttpContext.Current and OperationContext.Current is also null. What am I missing? What I want to do is store some data in HttpContext.Current.Items or a similar collection that exists for the length of the request.

    Read the article

  • Can you find a pattern to sync files knowing only dates and filenames?

    - by Robert MacLean
    Imagine if you will a operating system that had the following methods for files Create File: Creates (writes) a new file to disk. Calling this if a file exists causes a fault. Update File: Updates an existing file. Call this if a file doesn't exist causes a fault. Read File: Reads data from a file. Enumerate files: Gets all files in a folder. Files themselves in this operating system only have the following meta data: Created Time: The original date and time the file was created, by the Create File method. Modified Time: The date and time the file was last modified by the Update File method. If the file has never been modified, this will equal the Create Time. You have been given the task of writing an application which will sync the files between two directories (lets call them bill and ted) on a machine. However it is not that simple, the client has required that The application never faults (see methods above). That while the application is running the users can add and update files and those will be sync'd next time the application runs. Files can be added to either the ted or bill directories. File names cannot be altered. The application will perform one sync per time it is run. The application must be almost entirely in memory, in other words you cannot create a log of filenames and write that to disk and then check that the next time. The exception to point 6 is that you can store date and times between runs. Each date/time is associated with a key labeled A through J (so you have 10 to use) so you can compare keys between runs. There is no way to catch exceptions in the application. Answer will be accepted based on the following conditions: First answer to meet all requirements will be accepted. If there is no way to meet all requirements, the answer which ensures the smallest amount of missed changes per sync will be accepted. A bounty will be created (100 points) as soon as possible for the prize. The winner will be selected one day before the bounty ends. Please ask questions in the comments and I will gladly update and refine the question on those.

    Read the article

  • Reducing Integer Fractions Algorithm - Solution Explanation?

    - by Andrew Tomazos - Fathomling
    This is a followup to this problem: Reducing Integer Fractions Algorithm Following is a solution to the problem from a grandmaster: #include <cstdio> #include <algorithm> #include <functional> using namespace std; const int MAXN = 100100; const int MAXP = 10001000; int p[MAXP]; void init() { for (int i = 2; i < MAXP; ++i) { if (p[i] == 0) { for (int j = i; j < MAXP; j += i) { p[j] = i; } } } } void f(int n, vector<int>& a, vector<int>& x) { a.resize(n); vector<int>(MAXP, 0).swap(x); for (int i = 0; i < n; ++i) { scanf("%d", &a[i]); for (int j = a[i]; j > 1; j /= p[j]) { ++x[p[j]]; } } } void g(const vector<int>& v, vector<int> w) { for (int i: v) { for (int j = i; j > 1; j /= p[j]) { if (w[p[j]] > 0) { --w[p[j]]; i /= p[j]; } } printf("%d ", i); } puts(""); } int main() { int n, m; vector<int> a, b, x, y, z; init(); scanf("%d%d", &n, &m); f(n, a, x); f(m, b, y); printf("%d %d\n", n, m); transform(x.begin(), x.end(), y.begin(), insert_iterator<vector<int> >(z, z.end()), [](int a, int b) { return min(a, b); }); g(a, z); g(b, z); return 0; } It isn't clear to me how it works. Can anyone explain it? The equivilance is as follows: a is the numerator vector of length n b is the denominator vector of length m

    Read the article

  • How to group files by date using PowerShell?

    - by Shane Cusson
    I have a folder with 2000+ files. I want to count the files by date. so with: Mode LastWriteTime Length Name ---- ------------- ------ ---- -a--- 2010-03-15 12:54 AM 10364953 file1.txt -a--- 2010-03-15 1:07 AM 10650503 file2.txt -a--- 2010-03-16 1:20 AM 10118657 file3.txt -a--- 2010-03-16 1:33 AM 9735542 file4.txt -a--- 2010-03-18 1:46 AM 10666979 file5.txt I'd like to see: Date Count ---------- ------ 2010-03-15 2 2010-03-16 2 2010-03-18 1 Thanks!

    Read the article

  • wpf c# media player questions

    - by Sankar
    I'm making a media player in wpf using c#. I had 3 questions. 1) I tried making a seeker XAML: <Slider Name="timelineSlider" Margin="40,91,26,0" ValueChanged="SeekToMediaPosition" Height="32" VerticalAlignment="Top" /> Code: private void Element_MediaOpened(object sender, EventArgs e) { timelineSlider.Maximum = ply.NaturalDuration.TimeSpan.TotalMilliseconds; } private void SeekToMediaPosition(object sender, RoutedPropertyChangedEventArgs<double> e) { int SliderValue = (int)timelineSlider.Value; TimeSpan ts = new TimeSpan(SliderValue, SliderValue, SliderValue, SliderValue, SliderValue); ply.Position = ts; } When I run the program, I open the mp3 and play it but the seeker won't move. When I click on the seeker to move it to a certain position, the song stops playing but the seeker moves. What's the problem and how do I fix it? How do I create a volume increase/decrease bar? How can I open several mp3s and queue them up like a playlist? Thank you

    Read the article

  • Ab Initio - Formatting a number in Left alignment

    - by Veera
    I have a requirement in Ab Initio to format a number in left alignment. I shouldn't be using String conversion (as Strings are left aligned by default), as it might cause compatibility problems in the other end. For example, if my Field has 7 bytes length, and I'm getting only two digits as my input, then these two digits should go into the first two bytes of my field (left aligned), instead of the last two bytes. So, is there any in-built function in Ab Initio, that can format a number as left aligned?

    Read the article

  • Retrieving ids of chid divs using jquery?

    - by user187580
    Hello, Please have a look on the code below .. <div id="click_me">Save</div> <div id="blocks_sortable"> <div id="block_1"> <h2>Block 1</h2> <div class="items_sortable connectedSortable"> <div id="item_1"> <span>Item 1</span></div> <div id="item_2"> <span>Item 2</span></div> <div id="item_3"> <span>Item 3</span></div> </div> </div> <div id="block_2"> <h2>Block 2</h2> <div class="items_sortable connectedSortable"> <div id="item_4"> <span>Item 4</span></div> <div id="item_5"> <span>Item 5</span></div> <div id="item_6"> <span>Item 6</span></div> </div> </div> </div> <script> $("#click_me").click(function() { var result = $("#blocks_sortable > div"); for(var i=0; i<result.length; i++){ var str = ""; var str2 = ""; var block = result[i]; //div object //retrieve block id and create the string with id str += "block="+$(block).attr("id")+"&items="; //trying to select all the items of the current Block var result2 = $(block+" > div"); for(var j=0; j<result2.length; j++){ var item = result2[j]; str2 += $(item).attr("id")+","; } //end for items str = str+str2; // looking for a final string in the format of .. block=block_1&items=item_1,item_2,item_3 for loop 1 alert(str); } }); </script> It is not working. Is there any easier and working solution to get these ids. Please help. Thank you.

    Read the article

  • Java - Highest, Lowest and Average

    - by Emily
    Hello, I've just started studying and I need help on one of my exercises. I need the end user to input a rain fall number for each month. I then need to out put the average rainfall, highest month and lowest month and the months which rainfall was above average. I keep getting the same number in the highest and lowest and I have no idea why. I am seriously pulling my hair out. Any help would be greatly appreciated. This is what I have so far: public class rainfall { /** * @param args */ public static void main(String[] args) { int[] numgroup; numgroup = new int [13]; ConsoleReader console = new ConsoleReader(); int highest; int lowest; int index; int tempVal; int minMonth; int minIndex; int maxMonth; int maxIndex; System.out.println("Welcome to Rainfall"); for(index = 1; index < 13; index = index + 1) { System.out.println("Please enter the rainfall for month " + index); tempVal = console.readInt(); while (tempVal>100 || tempVal<0) { System.out.println("The rating must be within 0...100. Try again"); tempVal = console.readInt(); } numgroup[index] = tempVal; } lowest = numgroup[0]; for(minIndex = 0; minIndex < numgroup.length; minIndex = minIndex + 1); { if (numgroup[0] < lowest) { lowest = numgroup[0]; minMonth = minIndex; } } highest = numgroup[1]; for(maxIndex = 0; maxIndex < numgroup.length; maxIndex = maxIndex + 1); { if (numgroup[1] > highest) { highest = numgroup[1]; maxMonth = maxIndex; } } System.out.println("The average monthly rainfall was "); System.out.println("The lowest monthly rainfall was month " + minIndex); System.out.println("The highest monthly rainfall was month " + maxIndex); System.out.println("Thank you for using Rainfall"); } private static ConsoleReader ConsoleReader() { return null; } } Thanks, Emily

    Read the article

  • Setting Priorities on Buttons

    - by JONY
    Hello Android Developers, I am trying to figure out how to set priorities on imagebutton. I want to have a layout with a bunch of Icon or buttons that can be selected either by touch, radio, or checked box. As these images are selected they are set on queue to be displayed in order of Precedence. (that is to be pre-determined). The images are displayed once the main action button is touched. Any help will be greatly appreciated. Thank you,

    Read the article

  • Uncompres a gzip file from CURL, on php

    - by PartySoft
    Does anyone know how to uncompress the contents of a gzip file that i got with curl? for example: http://torcache.com/torrent/63ABC1435AA5CD48DCD866C6F7D5E80766034391.torrent responded HTTP/1.1 200 OK Server: nginx Date: Wed, 09 Jun 2010 01:11:26 GMT Content-Type: application/x-bittorrent Content-Length: 52712 Last-Modified: Tue, 08 Jun 2010 15:09:58 GMT Connection: keep-alive Expires: Fri, 09 Jul 2010 01:11:26 GMT Cache-Control: max-age=2592000 Content-Encoding: gzip Accept-Ranges: bytes then the compressed gzip, i tried gzdecode but doesn't work , gzeflate as well doesn't they simply don't get any response, and the contents of the files are no more than 2k

    Read the article

  • How to get predecessor and successors from an adjacency matrix

    - by NickTFried
    Hi I am am trying to complete an assignment, where it is ok to consult the online community. I have to create a graph class that ultimately can do Breadth First Search and Depth First Search. I have been able to implement those algorithms successfully however another requirement is to be able to get the successors and predecessors and detect if two vertices are either predecessors or successors for each other. I'm having trouble thinking of a way to do this. I will post my code below, if anyone has any suggestions it would be greatly appreciated. import java.util.ArrayList; import java.util.Iterator; import java.util.LinkedList; import java.util.Queue; import java.util.Stack; public class Graph<T> { public Vertex<T> root; public ArrayList<Vertex<T>> vertices=new ArrayList<Vertex<T>>(); public int[][] adjMatrix; int size; private ArrayList<Vertex<T>> dfsArrList; private ArrayList<Vertex<T>> bfsArrList; public void setRootVertex(Vertex<T> n) { this.root=n; } public Vertex<T> getRootVertex() { return this.root; } public void addVertex(Vertex<T> n) { vertices.add(n); } public void removeVertex(int loc){ vertices.remove(loc); } public void addEdge(Vertex<T> start,Vertex<T> end) { if(adjMatrix==null) { size=vertices.size(); adjMatrix=new int[size][size]; } int startIndex=vertices.indexOf(start); int endIndex=vertices.indexOf(end); adjMatrix[startIndex][endIndex]=1; adjMatrix[endIndex][startIndex]=1; } public void removeEdge(Vertex<T> v1, Vertex<T> v2){ int startIndex=vertices.indexOf(v1); int endIndex=vertices.indexOf(v2); adjMatrix[startIndex][endIndex]=1; adjMatrix[endIndex][startIndex]=1; } public int countVertices(){ int ver = vertices.size(); return ver; } /* public boolean isPredecessor( Vertex<T> a, Vertex<T> b){ for() return true; }*/ /* public boolean isSuccessor( Vertex<T> a, Vertex<T> b){ for() return true; }*/ public void getSuccessors(Vertex<T> v1){ } public void getPredessors(Vertex<T> v1){ } private Vertex<T> getUnvisitedChildNode(Vertex<T> n) { int index=vertices.indexOf(n); int j=0; while(j<size) { if(adjMatrix[index][j]==1 && vertices.get(j).visited==false) { return vertices.get(j); } j++; } return null; } public Iterator<Vertex<T>> bfs() { Queue<Vertex<T>> q=new LinkedList<Vertex<T>>(); q.add(this.root); printVertex(this.root); root.visited=true; while(!q.isEmpty()) { Vertex<T> n=q.remove(); Vertex<T> child=null; while((child=getUnvisitedChildNode(n))!=null) { child.visited=true; bfsArrList.add(child); q.add(child); } } clearVertices(); return bfsArrList.iterator(); } public Iterator<Vertex<T>> dfs() { Stack<Vertex<T>> s=new Stack<Vertex<T>>(); s.push(this.root); root.visited=true; printVertex(root); while(!s.isEmpty()) { Vertex<T> n=s.peek(); Vertex<T> child=getUnvisitedChildNode(n); if(child!=null) { child.visited=true; dfsArrList.add(child); s.push(child); } else { s.pop(); } } clearVertices(); return dfsArrList.iterator(); } private void clearVertices() { int i=0; while(i<size) { Vertex<T> n=vertices.get(i); n.visited=false; i++; } } private void printVertex(Vertex<T> n) { System.out.print(n.label+" "); } }

    Read the article

  • How do I make my multicast program work between computers on different networks?

    - by George
    I made a little chat applet using multicast. It works fine between computers on the same network, but fails if the computers are on different networks. Why is this? import java.io.*; import java.net.*; import java.awt.*; import java.awt.event.*; import javax.swing.*; public class ClientA extends JApplet implements ActionListener, Runnable { JTextField tf; JTextArea ta; MulticastSocket socket; InetAddress group; String name=""; public void start() { try { socket = new MulticastSocket(7777); group = InetAddress.getByName("233.0.0.1"); socket.joinGroup(group); socket.setTimeToLive(255); Thread th = new Thread(this); th.start(); name =JOptionPane.showInputDialog(null,"Please enter your name.","What is your name?",JOptionPane.PLAIN_MESSAGE); tf.grabFocus(); }catch(Exception e) {e.printStackTrace();} } public void init() { JPanel p = new JPanel(new BorderLayout()); ta = new JTextArea(); ta.setEditable(false); ta.setLineWrap(true); JScrollPane sp = new JScrollPane(ta); p.add(sp,BorderLayout.CENTER); JPanel p2 = new JPanel(); tf = new JTextField(30); tf.addActionListener(this); p2.add(tf); JButton b = new JButton("Send"); b.addActionListener(this); p2.add(b); p.add(p2,BorderLayout.SOUTH); add(p); } public void actionPerformed(ActionEvent ae) { String message = name+":"+tf.getText(); tf.setText(""); tf.grabFocus(); byte[] buf = message.getBytes(); DatagramPacket packet = new DatagramPacket(buf,buf.length, group,7777); try { socket.send(packet); } catch(Exception e) {} } public void run() { while(true) { byte[] buf = new byte[256]; String received = ""; DatagramPacket packet = new DatagramPacket(buf, buf.length); try { socket.receive(packet); received = new String(packet.getData()).trim(); } catch(Exception e) {} ta.append(received +"\n"); ta.setCaretPosition(ta.getDocument().getLength()); } } }

    Read the article

  • UITableView Search

    - by lkl
    Hi all, I'm using the following code for my search on my table: - (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope { [searchParent removeAllObjects]; for(NSString *a in parent) { NSComparisonResult result = [a compare:searchText options:(NSCaseInsensitiveSearch) range:NSMakeRange(0, [searchText length])]; if(result == NSOrderedSame){ [searchParent addObject:a]; } } } It's working fine, however, only for one character. I get the following in the console: *** Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[NSCFArray objectAtIndex:]: index (0) beyond bounds (0)' Any help is appreciated greatly! Thanks

    Read the article

  • How build a global function to have the recent background-Positions for continue animation after cha

    - by andi
    Try to find a global function, to get and to put the backgroundPosition-values, but I feel a bit confused. Here is the function: function global_backgroundPosition_Menu(num){ $('#Navigation_1') .css({ backgroundPosition: num + "px 0" }) } /////////////////// An here I want to call and put the function: if ($('#Navigation_1 li.leistungen.active').length != 0){ global_backgroundPosition_Menu(); $('#Navigation_1') .css({ backgroundImage: "url(images/background/menu_highlight_hg.png)", backgroundRepeat: "no-repeat", }) .animate({ backgroundPosition: "30px 0" }) global_backgroundPosition_Menu(30) };

    Read the article

  • How would you organize this Javascript?

    - by Anurag
    How do you usually organize complex web applications that are extremely rich on the client side. I have created a contrived example to indicate the kind of mess it's easy to get into if things are not managed well for big apps. Feel free to modify/extend this example as you wish - http://jsfiddle.net/NHyLC/1/ The example basically mirrors part of the comment posting on SO, and follows the following rules: Must have 15 characters minimum, after multiple spaces are trimmed out to one. If Add Comment is clicked, but the size is less than 15 after removing multiple spaces, then show a popup with the error. Indicate amount of characters remaining and summarize with color coding. Gray indicates a small comment, brown indicates a medium comment, orange a large comment, and red a comment overflow. One comment can only be submitted every 15 seconds. If comment is submitted too soon, show a popup with appropriate error message. A couple of issues I noticed with this example. This should ideally be a widget or some sort of packaged functionality. Things like a comment per 15 seconds, and minimum 15 character comment belong to some application wide policies rather than being embedded inside each widget. Too many hard-coded values. No code organization. Model, Views, Controllers are all bundled together. Not that MVC is the only approach for organizing rich client side web applications, but there is none in this example. How would you go about cleaning this up? Applying a little MVC/MVP along the way? Here's some of the relevant functions, but it will make more sense if you saw the entire code on jsfiddle: /** * Handle comment change. * Update character count. * Indicate progress */ function handleCommentUpdate(comment) { var status = $('.comment-status'); status.text(getStatusText(comment)); status.removeClass('mild spicy hot sizzling'); status.addClass(getStatusClass(comment)); } /** * Is the comment valid for submission */ function commentSubmittable(comment) { var notTooSoon = !isTooSoon(); var notEmpty = !isEmpty(comment); var hasEnoughCharacters = !isTooShort(comment); return notTooSoon && notEmpty && hasEnoughCharacters; } // submit comment $('.add-comment').click(function() { var comment = $('.comment-box').val(); // submit comment, fake ajax call if(commentSubmittable(comment)) { .. } // show a popup if comment is mostly spaces if(isTooShort(comment)) { if(comment.length < 15) { // blink status message } else { popup("Comment must be at least 15 characters in length."); } } // show a popup is comment submitted too soon else if(isTooSoon()) { popup("Only 1 comment allowed per 15 seconds."); } });

    Read the article

  • Uploading multiple files simultaneously with Flex

    - by David
    I have been working on a flex uploader, where the user can select multiple files. It works fine when the files are uploaded in a queue (one at a time), however as soon as I try to have it upload 2 files at once I run into issues. It seems that files will often lock up, and either stay at 1% until every other file is uploaded, or just not complete at all. There is never more than one file uploading at a time. Is there some issue with calling .upload on multiple files at once in Flex?

    Read the article

  • Detecting a Key Press Squashed by Another Application

    - by Eric Smith
    I have a WPF application I'm planning to use as an overlay for a DirectX game (specifically Bad Company 2). I'm using WM_KEYBOARD_LL hook to detect KeyDown events so I can bring my app to the foreground when a specific button is pressed. This works perfectly except for when the game is running (I've also noticed this problem with Window's "Chess Titans" so it may be a DirectX thing). As far as I can work out, when the game detects a keyboard press, it "eats" the event and doesn't pass the CallNextHookEx() method like it should, which would allow the key press message to be moved along to the next application in the queue. I'm wondering if there's any sort of work-around to this? It seems kind of unfair that a single application can just willy-nilly eat up messages like that. Thanks! :) Relevant MSDN documentation: http://msdn.microsoft.com/en-us/library/ms644985%28VS.85%29.aspx

    Read the article

  • JMS have javax.jms.InvalidDestinationException when client stop working

    - by Tran
    I use JMS for sending requests from a client to a server. My client sends a request to the server. While the server is working with my request, my client stops (network problem) before the server finishes. When the server is finished, it'll return to the client, but the server can't see the client which sent the request to server, at which point, the server will return an exception in log file. The exception is : javax.jms.InvalidDestinationException: Cannot publish to a deleted Destination: temp-queue://ID:PC0092-49463-1344231871819-0:0:9 [^] My question is: what do I need to do in this case? Can I catch or disable this exception? And how can I do it? (Sorry, If my english is not good.)

    Read the article

< Previous Page | 417 418 419 420 421 422 423 424 425 426 427 428  | Next Page >