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• Jquery Mobile splitview like Android Gmail app [closed]

  - by JDev

  Since I don't know much about jquery mobile, CSS, i don't know what we call this. I want to create a splitview like Android gmail app (image attached). but i am not sure how to create arrow cut on the active (clicked) listview only (like shown in the image) and other listview are normal. Can someone guide me how to approach it. Sorry for confusing everyone. Updated the image with black circle. the nice inward arrow (shown under black circle) is what i am looking for. As you see this inward arrow will appear only for the active left side listview only and others will have a straight line, also left side has a distinct appearance. I want to know the approach for these using jquery mobile, jquery, css etc.

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• How can I initialize a 2d array in Perl?

  - by Mark

  How do I initialize a 2d array in perl? I am trying the following code: 0 use strict; 10 my @frame_events = (((1) x 10), ((1) x 10)); 20 print "$frame_events[1][1]\n"; but it gives the following error: Can't use string ("1") as an ARRAY ref while "strict refs" in use at ./dyn_pf.pl line 20. This syntax only seems to initialize a 1d array as print "$frame_events[1]\n" works. Though perl doesn't give any error during the assignment.

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• Passing a multi-line string as an argument to a script in Windows

  - by Zack Mulgrew

  I have a simple python script like so: import sys lines = sys.argv[1] for line in lines.splitlines(): print line I want to call it from the command line (or a .bat file) but the first argument may (and probably will) be a string with multiple lines in it. How does one do this? Of course, this works: import sys lines = """This is a string It has multiple lines there are three total""" for line in lines.splitlines(): print line But I need to be able to process an argument line-by-line. EDIT: This is probably more of a Windows command-line problem than a Python problem. EDIT 2: Thanks for all of the good suggestions. It doesn't look like it's possible. I can't use another shell because I'm actually trying to invoke the script from another program which seems to use the Windows command-line behind the scenes.

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• jquery change element to element

  - by Isis

  Hello <div class="leftlink" id="mcontacts"> <img src="test.gif" class="arrowred"/> <a href="/contacts/" class="u">????????</a> </div> if(window.location == 'http://my.site.com/contacts/') { $('.menuwelcome').css('display', 'block'); $('.leftlink').find('????????').css('font-weight', 'bold'); $('#mcontacts').find('a').html('<b>????????</b>').remove(); } How do remove tag "a" html, and change his for '<b>????????</b>' ? =) Than you, sorry for bad english

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• Printing contents of a dynamically created iframe from parent window

  - by certainlyakey

  I have a page with a list of links and a div which serves as a placeholder for the pages the links lead to. Everytime user clicks on a link an iframe is created in the div and its src attribute gets the value of the link href attribute - simple and clear, sort of external web pages gallery. What i do have a problem with is printing the contents of the iframe. To do this i use this code: function PrintIframe() { frames["name"].focus(); frames["name"].print(); } The issue seems to be that iframe is created dynamically by JQuery - when I insert an iframe right into the html code, the browser prints the external page all right. But with the same code injected by JavaScript nothing happens. I tried to use JQ 1.3 'live' event on "Print" link, no success. Is there a way to overcome this?

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• Python Regular Expression TypeError

  - by spaghettiwestern

  I am writing my first python program and I am running into a problem with regex. I am using regular expression to search for a specific value in a registry key. import _winreg import re key = _winreg.OpenKey(_winreg.HKEY_LOCAL_MACHINE,"Software\\Microsoft\\Windows\\CurrentVersion\\Uninstall\\{26A24AE4-039D-4CA4-87B4-2F83216020FF}") results=[] v = re.compile(r"(?i)Java") try: i = 0 while 1: name, value, type = _winreg.EnumValue(key, i) if v.search(value): results.append((name,value,type)) i += 1 except WindowsError: print for x in results: print "%-50s%-80s%-20s" % x I am getting the following error: exceptions.TypeError: expected string or buffer I can use the "name" variable and my regex works fine. For example if I make the following changes regex doesn't complain: v = re.compile(r"(?i)DisplayName") if v.search(name): Thanks for any help.

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• Converting time period strings to value/unit pair

  - by randomtoor

  I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

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• Why is this Python class copying another class contents?

  - by fjfnaranjo

  Hello guys. I'm trying to understand an estrange behavior in Python. I have the next python code: class IntContainer: listOfInts = [] def __init__(self, initListOfInts): for i in initListOfInts: self.listOfInts.append(i) def printInts(self): print self.listOfInts if __name__ == "__main__": intsGroup1 = [1,2,3,4] intsGroup2 = [4,5,6,7] intsGroups = [intsGroup1,intsGroup2] intsContainers = [] for ig in intsGroups: newIntContainer = IntContainer(ig) intsContainers.append(newIntContainer) for ic in intsContainers: print ic.listOfInts I expect to get something like: [1, 2, 3, 4] [4, 5, 6, 7] But i get: [1, 2, 3, 4, 4, 5, 6, 7] [1, 2, 3, 4, 4, 5, 6, 7] I have check the next question: http://stackoverflow.com/questions/1876905/why-is-python-reusing-a-class-instance-inside-in-function And a lot of Python reference, but I can not understand what is happening. I think is related with the newIntContainer identifier reutilization, but I do not understand it deeply. Why Python appears to reused the last reference for the new object, even if I have added it to a permanent list? What can I do to resolve this behavior? Thanks ;)

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• C++ new line not translating

  - by m3n

  First off, I'm a complete beginner at C++. I'm coding something using an API, and would like to pass text containing new lines to it, and have it print out the new lines at the other end. If I hardcode whatever I want it to print out, like so printInApp("Hello\nWorld"); it does come out as separate lines in the other end, but if I retrieve the text from the app using a method that returns a const char then pass it straight to printInApp (which takes const char as argument), it comes out as a single line. Why's this and how would I go about to fix it?

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• Iterating through a range of dates in Python

  - by ShawnMilo

  This is working fine, but I'm looking for any feedback on how to do it better. Right now I think it's better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension. Any suggestions are welcome. day_count = (end_date - start_date).days + 1 for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]: print strftime("%Y-%m-%d", single_date.timetuple()) Notes: I'm not actually using this to print; that's just for demo purposes. The variables start_date and end_date are datetime.date objects, because I don't need the timestamps (they're going to be used to generate a report). I checked the StackOverflow questions which were similar before posting this, but none were exactly the same. Sample Output (for a start date of 2009-05-30 and an end date of 2009-06-09): 2009-05-30 2009-05-31 2009-06-01 2009-06-02 2009-06-03 2009-06-04 2009-06-05 2009-06-06 2009-06-07 2009-06-08 2009-06-09

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• Copy one column over another in a delimited file

  - by user275455

  For instance, I needed to remove column 25 and replace it with a copy of column 22 in a simple csv file with no embedded delimiters. The best I could come up with was the awkward looking: awk -F, '{ for(x=1;x<25;x++){printf("%s,", $x)};printf("%s,",$22);for(x=26;x<59;x++){printf ("%s,", $x)};print $59}' I would expect something like cut -d, -f1-24,23,26-59 to work but cut doesn't seem to want to print the same column two times... Is there a more elegant way to do it using anything typicaly available in a linux shell environment?

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• Printing a list using reflection

  - by TFool

  public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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• Multi-threading does not work correctly using std::thread (C++ 11)

  - by user1364743

  I coded a small c++ program to try to understand how multi-threading works using std::thread. Here's the step of my program execution : Initialization of a 5x5 matrix of integers with a unique value '42' contained in the class 'Toto' (initialized in the main). I print the initialized 5x5 matrix. Declaration of std::vector of 5 threads. I attach all threads respectively with their task (threadTask method). Each thread will manipulate a std::vector<int> instance. I join all threads. I print the new state of my 5x5 matrix. Here's the output : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 It should be : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 0 0 0 0 0 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 Here's the code sample : #include <iostream> #include <vector> #include <thread> class Toto { public: /* ** Initialize a 5x5 matrix with the 42 value. */ void initData(void) { for (int y = 0; y < 5; y++) { std::vector<int> vec; for (int x = 0; x < 5; x++) { vec.push_back(42); } this->m_data.push_back(vec); } } /* ** Display the whole matrix. */ void printData(void) const { for (int y = 0; y < 5; y++) { for (int x = 0; x < 5; x++) { printf("%d ", this->m_data[y][x]); } printf("\n"); } printf("\n"); } /* ** Function attached to the thread (thread task). ** Replace the original '42' value by another one. */ void threadTask(std::vector<int> &list, int value) { for (int x = 0; x < 5; x++) { list[x] = value; } } /* ** Return the m_data instance propertie. */ std::vector<std::vector<int> > &getData(void) { return (this->m_data); } private: std::vector<std::vector<int> > m_data; }; int main(void) { Toto toto; toto.initData(); toto.printData(); //Display the original 5x5 matrix (first display). std::vector<std::thread> threadList(5); //Initialization of vector of 5 threads. for (int i = 0; i < 5; i++) { //Threads initializationss std::vector<int> vec = toto.getData()[i]; //Get each sub-vectors. threadList.at(i) = std::thread(&Toto::threadTask, toto, vec, i); //Each thread will be attached to a specific vector. } for (int j = 0; j < 5; j++) { threadList.at(j).join(); } toto.printData(); //Second display. getchar(); return (0); } However, in the method threadTask, if I print the variable list[x], the output is correct. I think I can't print the correct data in the main because the printData() call is in the main thread and the display in the threadTask function is correct because the method is executed in its own thread (not the main one). It's strange, it means that all threads created in a parent processes can't modified the data in this parent processes ? I think I forget something in my code. I'm really lost. Does anyone can help me, please ? Thank a lot in advance for your help.

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• How do record updates behave internally?

  - by redxaxder

  data Thing = Thing {a :: Int, b :: Int, c :: Int, (...) , z :: Int} deriving Show foo = Thing 1 2 3 4 5 (...) 26 mkBar x = x { c = 30 } main = do print $ mkBar foo What is copied over when I mutate foo in this way? As opposed to mutating part of a structure directly. Data Thing = Thing {a :: IORef Int, b :: IORef Int, (...) , z :: IORef Int} instance Show Thing where (...something something unsafePerformIO...) mkFoo = do a <- newIORef 1 (...) z <- newIORef 26 return Thing a b (...) z mkBar x = writeIORef (c x) 30 main = do foo <- mkFoo mkBar foo print foo Does compiling with optimizations change this behavior?

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• Debugging (displaying) SQL command sent to the db by SQLAlchemy

  - by morpheous

  I have an ORM class called Person, which wraps around a person table: After setting up the connection to the db etc, I run the ff statement. people = session.query(Person).all() The person table does not contain any data (as yet), so when I print the variable people, I get an empty list. I renamed the table referred to in my ORM class People, to people_foo (which does not exist). I then run the script again. I was surprised that no exception was thrown when attempting to access a table that does not exist. I therefore have the following 2 questions: How may I setup SQLAlchemy so that it propagates db errors back to the script? How may I view (i.e. print) the SQL that is being sent to the db engine If it helps, I am using PostgreSQL as the db

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• Can somebody tell me why this Jquery tooltip is not showing up?

  - by alex

  <link rel="stylesheet" type="text/css" href="jquery-tooltip/jquery.tooltip.css"/> <script type="text/javascript" src="jquery-tooltip/jquery.tooltip.js"></script> <div id="baby" title="My tootip">The text</div> <script type="text/javascript"> $(function(){ $('#baby').tooltip({ track: true, delay: 0, showURL: false, showBody: " - ", extraClass: "pretty", fixPNG: true, opacity: 0.95, left: -120 }); }); </script> The files are found, and they are not 404.

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• Why use threading data race will occur, but will not use gevent

  - by onlytiancai

  My test code is as follows, using threading, count is not 5,000,000 , so there has been data race, but using gevent, count is 5,000,000, there was no data race . Is not gevent coroutine execution will atom "count + = 1", rather than split into a one CPU instruction to execute? # -*- coding: utf-8 -*- import threading use_gevent = True use_debug = False cycles_count = 100*10000 if use_gevent: from gevent import monkey monkey.patch_thread() count = 0 class Counter(threading.Thread): def __init__(self, name): self.thread_name = name super(Counter, self).__init__(name=name) def run(self): global count for i in xrange(cycles_count): if use_debug: print '%s:%s' % (self.thread_name, count) count = count + 1 counters = [Counter('thread:%s' % i) for i in range(5)] for counter in counters: counter.start() for counter in counters: counter.join() print 'count=%s' % count

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• Parse and Break: why break cannot be used for getting out of "any" or "some" rule ?

  - by Rebol Tutorial

  Let say I have to parse a hierarchical set of tags <tag> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> </tag> Why can't I use break inside some or any to get out of a level hierarchy ? This would allow to do that kind of parsing instead of having a headache to do so ? I'm asking this because I read here http://www.codeconscious.com/rebol/parse-tutorial.html it would create an infinite loop This case produces an infinite loop. Because the BREAK is within a sub-rule of the rule that SOME is processing. The BREAK does not affect success/failure status or the input pointer - it just exits a rule early: rule-to-break: [(print "Break") break] == [(print "Break") break] parse "X" [some [rule-to-break] "X"] Break *Break* ... Break *Break*(escape)

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• The return value should be a list but doesn't return as expected?! - Python newbie

  - by user1432941

  Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

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• python compare time

  - by Jesse Siu

  i want to using python create filter for a log file. get recent 7 days record. but when i didn't know how to compare time. like current time is 11/9/2012, i want to get records from 04/9/2012 to now the log file like Sat Sep 2 03:32:13 2012 [pid 12461] CONNECT: Client "66.249.68.236" Sat Sep 2 03:32:13 2012 [pid 12460] [ftp] OK LOGIN: Client "66.249.68.236", anon password "[email protected]" Sat Sep 2 03:32:14 2012 [pid 12462] [ftp] OK DOWNLOAD: Client "66.249.68.236", "/pub/10.5524/100001_101000/100022/readme.txt", 451 i using this one def OnlyRecent(line): print time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") print time.time() if time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") < time.time(): return True return False But it shows (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 14, 5, 246, -1) 1347332968.08 the time format is different, and it can't compare time. So how to set this comparison in 7 days. Thanks

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• Regular Expression Program

  - by david robers

  Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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• jQuery UI 1.8.13 sudden error

  - by user837306

  We have been using Jquery from this link http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.13/jquery-ui.min.js for drag and drop. Suddenly we notice it is not working now and there is no code change done our side. We notice the error is pointing to these line and error is TypeError: a.curCSS is not a function? What will be solution to this problem? e&&e.call(i)},g)}):this._focus.apply(this,arguments)},scrollParent:function(){var g;g=a.browser.msie&&/(static|relative)/.test(this.css("position"))||/absolute/.test(this.css("position"))?this.parents().filter

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• Json request with Javascript

  - by chota

  Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

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• Check and avoid if a char is being entered in a int

  - by John

  Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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• remove the spaces...

  - by tekknolagi

  !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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