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  • Download JDK onto a remote server

    - by itsadok
    I want to get the latest JDK onto a server in a remote location. Downloading the JDK from Sun's website requires jumping through all kinds of hoops until you actually get the file. I'm not sure exactly if they use cookies or my IP address, but simply copying the file URL and trying wget on the server doesn't work. Googling for mirrors of the JDK, I could only find old versions. Right now I'm left with the option of downloading it into my computer, then uploading it to the server. This feels slow and stupid. Anyone got a better idea? EDIT: Thanks for all the replies. Just to clarify, as I'm writing this I'm rsyncing the 78MB file to my server. It should be done in about an hour, so it's not such a big deal. However, since this is not the first time I'm doing this, I was hoping for a better solution for next time. Solution: What I ended up doing was sudo aptitude install lynx-cur www-browser http://java.sun.com/javase/downloads/ From there it's mostly using the arrow and enter keys, and answering "Yes" to a lot of lynx security questions (about cookies and certificates). Thanks to resonator.

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  • How to configure a shortcut for an SSH connection through a SSH tunnel

    - by Simone Carletti
    My company production servers (FOO, BAR...) are located behind two gateway servers (A, B). In order to connect to server FOO, I have to open a ssh connection with server A or B with my username JOHNDOE, then from A (or B) I can access any production server opening a SSH connection with a standard username (let's call it WEBBY). So, each time I have to do something like: ssh johndoe@a ... ssh webby@foo ... # now I can work on the server As you can imagine, this is a hassle when I need to use scp or if I need to quickly open multiple connections. I have configured a ssh key and also I'm using .ssh/config for some shortcuts. I was wondering if I can create some kind of ssh configuration in order to type ssh foo and let SSH open/forward all the connections for me. Is it possible? Edit womble's answer is exactly what I was looking for but it seems right now I can't use netcat because it's not installed on the gateway server. weppos:~ weppos$ ssh foo -vv OpenSSH_5.1p1, OpenSSL 0.9.7l 28 Sep 2006 debug1: Reading configuration data /Users/xyz/.ssh/config debug1: Applying options for foo debug1: Reading configuration data /etc/ssh_config debug2: ssh_connect: needpriv 0 debug1: Executing proxy command: exec ssh a nc -w 3 foo 22 debug1: permanently_drop_suid: 501 debug1: identity file /Users/xyz/.ssh/identity type -1 debug2: key_type_from_name: unknown key type '-----BEGIN' debug2: key_type_from_name: unknown key type 'Proc-Type:' debug2: key_type_from_name: unknown key type 'DEK-Info:' debug2: key_type_from_name: unknown key type '-----END' debug1: identity file /Users/xyz/.ssh/id_rsa type 1 debug2: key_type_from_name: unknown key type '-----BEGIN' debug2: key_type_from_name: unknown key type 'Proc-Type:' debug2: key_type_from_name: unknown key type 'DEK-Info:' debug2: key_type_from_name: unknown key type '-----END' debug1: identity file /Users/xyz/.ssh/id_dsa type 2 bash: nc: command not found ssh_exchange_identification: Connection closed by remote host

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  • Problems with "Read Only" on a Samba share from Windows machines

    - by fistameeny
    We have a Ubuntu 10.04 Server that has a bunch of Samba shares on it that Windows workstations connect to. Each Windows workstation has a valid username/password to access the shares, which have restricted access governed by Samba. The problem we are experiencing is that Samba doesn't seem to be able to mimic the Windows way of handling "Read Only" attributes. Say I have two users, UserA and UserB, both a group called Staff - UserA creates a file that is readable/writeable by the group (ie. chmod rwxrwx---). If UserA then sets the "Read Only" flag, this changes the permissions to r-xr-x--- (i.e. no write for anyone). As UserB is in the same group as UserA, they should be able to remove the "Read Only" permission - however, they can't as Samba won't allow it. Is there a way to force Samba to allow users within the same group to remove the "Read Only" from a file not created by them? Edit: The Samba smb.conf is as follows: The share is defined in the smb.conf as: [global] log file = /var/log/samba/log.%m passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . obey pam restrictions = yes map to guest = bad user encrypt passwords = true passwd program = /usr/bin/passwd %u passdb backend = tdbsam dns proxy = no netbios name = ubsrv server string = ubsrv unix password sync = yes os level = 20 syslog = 0 usershare allow guests = yes panic action = /usr/share/samba/panic-action %d max log size = 1000 pam password change = yes workgroup = workgroup [Projects] valid users = @Staff writeable = yes user = @Staff create mode = 0777 path = /srv/samba/Projects directory mode = 0777 store dos attributes = Yes The folder itself looks like this: ls -l /srv/samba/ drwxrwxrwx 2 nobody Staff 4096 2010-11-04 10:09 Projects Thanks in advance, Matt

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  • Problems with "Read Only" on a Samba share from Windows machines

    - by fistameeny
    Hi, We have a Ubuntu 10.04 Server that has a bunch of Samba shares on it that Windows workstations connect to. Each Windows workstation has a valid username/password to access the shares, which have restricted access governed by Samba. The problem we are experiencing is that Samba doesn't seem to be able to mimic the Windows way of handling "Read Only" attributes. Say I have two users, UserA and UserB, both a group called Staff - UserA creates a file that is readable/writeable by the group (ie. chmod rwxrwx---). If UserA then sets the "Read Only" flag, this changes the permissions to r-xr-x--- (i.e. no write for anyone). As UserB is in the same group as UserA, they should be able to remove the "Read Only" permission - however, they can't as Samba won't allow it. Is there a way to force Samba to allow users within the same group to remove the "Read Only" from a file not created by them? Edit: The Samba smb.conf is as follows: The share is defined in the smb.conf as: [global] log file = /var/log/samba/log.%m passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . obey pam restrictions = yes map to guest = bad user encrypt passwords = true passwd program = /usr/bin/passwd %u passdb backend = tdbsam dns proxy = no netbios name = ubsrv server string = ubsrv unix password sync = yes os level = 20 syslog = 0 usershare allow guests = yes panic action = /usr/share/samba/panic-action %d max log size = 1000 pam password change = yes workgroup = workgroup [Projects] valid users = @Staff writeable = yes user = @Staff create mode = 0777 path = /srv/samba/Projects directory mode = 0777 store dos attributes = Yes The folder itself looks like this: ls -l /srv/samba/ drwxrwxrwx 2 nobody Staff 4096 2010-11-04 10:09 Projects Thanks in advance, Matt

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  • Why am I getting this error in the logs?

    - by Matt
    Ok so I just started a new ubuntu server 11.10 and i added the vhost and all seems ok ...I also restarted apache but when i visit the browser i get a blank page the server ip is http://23.21.197.126/ but when i tail the log tail -f /var/log/apache2/error.log [Wed Feb 01 02:19:20 2012] [error] [client 208.104.53.51] File does not exist: /etc/apache2/htdocs [Wed Feb 01 02:19:24 2012] [error] [client 208.104.53.51] File does not exist: /etc/apache2/htdocs but my only file in sites-enabled is this <VirtualHost 23.21.197.126:80> ServerAdmin [email protected] ServerName logicxl.com # ServerAlias DocumentRoot /srv/crm/current/public ErrorLog /srv/crm/logs/error.log <Directory "/srv/crm/current/public"> Order allow,deny Allow from all </Directory> </VirtualHost> is there something i am missing .....the document root should be /srv/crm/current/public and not /etc/apache2/htdocs as the error suggests Any ideas on how to fix this UPDATE sudo apache2ctl -S VirtualHost configuration: 23.21.197.126:80 is a NameVirtualHost default server logicxl.com (/etc/apache2/sites-enabled/crm:1) port 80 namevhost logicxl.com (/etc/apache2/sites-enabled/crm:1) Syntax OK UPDATE <VirtualHost *:80> ServerAdmin [email protected] ServerName logicxl.com DocumentRoot /srv/crm/current/public <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /srv/crm/current/public/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost>

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  • Is it possible to download extremely large files intelligently or in parts via SSH from Linux to Windows?

    - by Andrew
    I have a ~35 GB file on a remote Linux Ubuntu server. Locally, I am running Windows XP, so I am connecting to the remote Linux server using SSH (specifically, I am using a Windows program called SSH Secure Shell Client version 3.3.2). Although my broadband internet connection is quite good, my download of the large file often fails with a Connection Lost error message. I am not sure, but I think that it fails because perhaps my internet connection goes out for a second or two every several hours. Since the file is so large, downloading it may take 4.5 to 5 hours, and perhaps the internet connection goes out for a second or two during that long time. I think this because I have successfully downloaded files of this size using the same internet connection and the same SSH software on the same computer. In other words, sometimes I get lucky and the download finishes before the internet connection drops for a second. Is there any way that I can download the file in an intelligent way -- whereby the operating system or software "knows" where it left off and can resume from the last point if a break in the internet connection occurs? Perhaps it is possible to download the file in sections? Although I do not know if I can conveniently split my file into multiple files -- I think this would be very difficult, since the file is binary and is not human-readable. As it is now, if the entire ~35 GB file download doesn't finish before the break in the connection, then I have to start the download over and overwrite the ~5-20 GB chunk that was downloaded locally so far. Do you have any advice? Thanks.

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  • "could not find suitable fingerprints matched to available hardware" error

    - by Alex
    I have a thinkpad t61 with a UPEK fingerprint reader. I'm running ubuntu 9.10, with fprint installed. Everything works fine (I am able to swipe my fingerprint to authenticate any permission dialogues or "sudo" prompts successfully) except for actually logging onto my laptop when I boot up or end my session. I receive an error below the gnome login that says "Could not locate any suitable fingerprints matched to available hardware." What is causing this? here are the contents of /etc/pam.d/common-auth file # # /etc/pam.d/common-auth - authentication settings common to all services # # This file is included from other service-specific PAM config files, # and should contain a list of the authentication modules that define # the central authentication scheme for use on the system # (e.g., /etc/shadow, LDAP, Kerberos, etc.). The default is to use the # traditional Unix authentication mechanisms. # # As of pam 1.0.1-6, this file is managed by pam-auth-update by default. # To take advantage of this, it is recommended that you configure any # local modules either before or after the default block, and use # pam-auth-update to manage selection of other modules. See # pam-auth-update(8) for details. # here are the per-package modules (the "Primary" block) auth sufficient pam_fprint.so auth [success=1 default=ignore] pam_unix.so nullok_secure # here's the fallback if no module succeeds auth requisite pam_deny.so # prime the stack with a positive return value if there isn't one already; # this avoids us returning an error just because nothing sets a success code # since the modules above will each just jump around auth required pam_permit.so # and here are more per-package modules (the "Additional" block) auth optional pam_ecryptfs.so unwrap # end of pam-auth-update config #auth sufficient pam_fprint.so #auth required pam_unix.so nullok_secure

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  • Apache 2.4 with PHP-FPM

    - by tubaguy50035
    I'm trying to setup Apache 2.4 with PHP-FPM 5.4 using the new modules with Apache 2.4. The following is what I have currently in my virtual host file: <VirtualHost *:80> ServerAdmin root@localhost DocumentRoot /var/www #Directory permissions <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride None Require all granted </Directory> CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost> I have PHP-FPM running using Unix sockets with a sock file located at /var/run/php5-fpm.sock. How do I proxy my requests to this sock file? I've seen some sites say to use ProxyPassMatch and others are saying Rewrite Rule. Are there pros or cons on either side? Also, most sites I'm seeing are showing ProxyPassMatch with a regex to only pass .php files. Could I also send it .html files? For whatever reason, we have a ton of PHP inside .html files. Edit: As noted in the comments, it looks like mod_proxy_fcgi doesn't support Unix sockets. Is there another module I should be using?

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  • How do I permanently delete /var/log/lastlog?

    - by GregB
    My /var/log/lastlog file is huge. I know it's really only a few kilobytes, but tar isn't smart enough to know that, so when I image a virtual machine, my restore fails because it thinks I'm trying to load more data than I have capacity on my disk. I want to delete /var/log/lastlog and stop any and all logging to the file. I'm aware of the security implications. This logging needs to stop to preserve my backup strategy. I've made a change to /etc/pam.d/login which I was told would disable logging to /var/log/lastlog, but it does not appear to work as /var/log/lastlog keeps growing. # Prints the last login info upon succesful login # (Replaces the `LASTLOG_ENAB' option from login.defs) #session optional pam_lastlog.so Any ideas? EDIT For anyone interested, I use Centrify Express to authenticate my users via LDAP. Centrify Express is "free", but one of the drawbacks is that I can't manage user UIDs via LDAP, so they are given a dynamic UID when they login to a server. Centrify picks some crazy high UID values (so they don't conflict with local users on the server, presumably). /var/log/lastlog is indexed by UID, and grows to accommodate the largest UID on the system. This means that when a Centrify user logs in, they get a UID in the upper-end of the UID range, which causes lastlog to allocate an obscene amount of space, according to the file system. ~$ ll /var/log/lastlog -rw-rw-r-- 1 root root 291487675780 Apr 10 16:37 /var/log/lastlog ~$ du -h /var/log/lastlog 20K /var/log/lastlog More Into --- Sparse Files

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  • How to add a user to Wheel group?

    - by Natasha Thapa
    I am trying to add a use to wheel group using in a Ubuntu server. sudo usermod -aG wheel john I get: usermod: group 'wheel' does not exist On my /etc/sudoers I have this: > cat /etc/sudoers > # sudoers file. > # > # This file MUST be edited with the 'visudo' command as root. > # > # See the sudoers man page for the details on how to write a sudoers file. > # > > # Host alias specification > > # User alias specification > > # Cmnd alias specification > > # Defaults specification > > # User privilege specification root ALL=(ALL) ALL %root ALL=(ALL) NOPASSWD: ALL > > %wheel ALL=(ALL) NOPASSWD: ALL Do I have to do groupadd of wheel?

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  • Command line switching

    - by Larry
    I have read through some suggestions but I am just not technical enough to get this I think. I am a CAD designer and each file has 5 files associated with it. I have 3 sets of 5 files, and each set needs to go into its own zip file, placed on a separate server. For example: "C:\Program Files\7-zip\7z.exe" a file1.zip "O:\server2\map files\BC\BC.d*"-0 "C:\Program Files\7-zip\7z.exe" a file2.zip "O:\server2\map files\BC\ON.d*"-0 "C:\Program Files\7-zip\7z.exe" a file3.zip "O:\server2\map files\BC\AB.d*"-0 and I am in directory "S:\server\map files\provinces" (for example). These lines run within an existing batch file and by the time it reaches the 3 lines above, it's in the S: directory sample above. So it's looking on my pc for the 7-zip program, creating 3 zip file names which it does, but places those zip files on a separate server which it doesn't and the first zip file also includes all the other 10 files, the second zip file the same plus the first zip file, and the third the same with the other two zip files making me think the code isn't recognizing the part after file1.zip where I am trying to tell it what files to include and where to place the zip files. Ultimately, I want to either have the system create a new zip file if the old one was deleted, or copy the new files into the existing zip and overwrite any older files, and for these zip files to be placed in a separate location which is where we share our files with other personnel from within our company. The S: drive is for all originals, and O: is for sharing. Is there a list of all switching options with many different samples?

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  • how to write or what is the concept behind the file unlocker program

    - by Jach Many
    Recently i was trying to delete a file thinking that i had closed the program which is manipulating the file but it did not delete because the program was still running. I misunderstood that file as an unwanted file. So i used the file unlocker program to find which process is manipulating that file. That program really worked well by showing the process which was handling that file. and that file was http://download.cnet.com/Unlocker/3000-2248_4-10493998.html. What i want to know is i would like to write a program in win32 C or .net to mimic the same process. Just to find which process is handling which file. and if possible to close it. Or i want to know the concept behind that. I know this cannot be explained in a few paragraphs yet if i could get some references or external links to references then that could be nice.

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  • Pass string between two threads in java

    - by geeta
    I have to search a string in a file and write the matched lines to another file. I have a thread to read a file and a thread to write a file. I want to send the stringBuffer from read thread to write thread. Please help me to pass this. I amm getting null value passed. write thread: class OutputThread extends Thread{ /****************** Writes the line with search string to the output file *************/ Thread runner1,runner; File Out_File; public OutputThread() { } public OutputThread(Thread runner,File Out_File) { runner1 = new Thread(this,"writeThread"); // (1) Create a new thread. this.Out_File=Out_File; this.runner=runner; runner1.start(); // (2) Start the thread. } public void run() { try{ BufferedWriter bufferedWriter=new BufferedWriter(new FileWriter(Out_File,true)); System.out.println("inside write"); synchronized(runner){ System.out.println("inside wait"); runner.wait(); } System.out.println("outside wait"); // bufferedWriter.write(line.toString()); Buffer Buf = new Buffer(); bufferedWriter.write(Buf.buffers); System.out.println(Buf.buffers); bufferedWriter.flush(); } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } } Read Thraed: class FileThread extends Thread{ Thread runner; File dir; String search_string,stats; File Out_File,final_output; StringBuffer sb = new StringBuffer(); public FileThread() { } public FileThread(CountDownLatch latch,String threadName,File dir,String search_string,File Out_File,File final_output,String stats) { runner = new Thread(this, threadName); // (1) Create a new thread. this.dir=dir; this.search_string=search_string; this.Out_File=Out_File; this.stats=stats; this.final_output=final_output; this.latch=latch; runner.start(); // (2) Start the thread. } public void run() { try{ Enumeration entries; ZipFile zipFile; String source_file_name = dir.toString(); File Source_file = dir; String extension; OutputThread out = new OutputThread(runner,Out_File); int dotPos = source_file_name.lastIndexOf("."); extension = source_file_name.substring(dotPos+1); if(extension.equals("zip")) { zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while(entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if(entry.isDirectory()) { (new File(entry.getName())).mkdir(); continue; } searchString(runner,entry.getName(),new BufferedInputStream(zipFile.getInputStream(entry)),Out_File,final_output,search_string,stats); } zipFile.close(); } else { searchString(runner,Source_file.toString(),new BufferedInputStream(new FileInputStream(Source_file)),Out_File,final_output,search_string,stats); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } /********* Reads the Input Files and Searches for the String ******************************/ public void searchString(Thread runner,String Source_File,BufferedInputStream in,File output_file,File final_output,String search,String stats) { int count = 0; int countw = 0; int countl=0; String s; String[] str; String newLine = System.getProperty("line.separator"); try { BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); //OutputFile outfile = new OutputFile(); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(output_file,true)); Buffer Buf = new Buffer(); //StringBuffer sb = new StringBuffer(); StringBuffer sb1 = new StringBuffer(); while((s = br2.readLine()) != null ) { str = s.split(search); count = str.length-1; countw += count; if(s.contains(search)){ countl++; sb.append(s); sb.append(newLine); } if(countl%100==0) { System.out.println("inside count"); Buf.setBuffers(sb.toString()); sb.delete(0,sb.length()); System.out.println("outside notify"); synchronized(runner) { runner.notify(); } //outfile.WriteFile(sb,bufferedWriter); //sb.delete(0,sb.length()); } } } synchronized(runner) { runner.notify(); } br2.close(); in.close(); if(countw == 0) { System.out.println("Input File : "+Source_File ); System.out.println("Word not found"); System.exit(0); } else { System.out.println("Input File : "+Source_File ); System.out.println("Matched word count : "+countw ); System.out.println("Lines with Search String : "+countl); System.out.println("Output File : "+output_file.toString()); System.out.println(); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } }

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  • Java Client-Server problem when sending multiple files

    - by Jim
    Client public void transferImage() { File file = new File(ServerStats.clientFolder); String[] files = file.list(); int numFiles = files.length; boolean done = false; BufferedInputStream bis; BufferedOutputStream bos; int num; byte[] byteArray; long count; long len; Socket socket = null ; while (!done){ try{ socket = new Socket(ServerStats.imgServerName,ServerStats.imgServerPort) ; InputStream inStream = socket.getInputStream() ; OutputStream outStream = socket.getOutputStream() ; System.out.println("Connected to : " + ServerStats.imgServerName); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); for (int itor = 0; itor < numFiles; itor++) { String fileName = files[itor]; System.out.println("transfer: " + fileName); File sentFile = new File(fileName); len = sentFile.length(); len++; System.out.println(len); out.println(len); out.println(sentFile); //SENDFILE bis = new BufferedInputStream(new FileInputStream(fileName)); bos = new BufferedOutputStream(socket.getOutputStream( )); byteArray = new byte[1000000]; count = 0; while ( count < len ){ num = bis.read(byteArray); bos.write(byteArray,0,num); count++; } bos.close(); bis.close(); System.out.println("file done: " + itor); } done = true; }catch (Exception e) { System.err.println(e) ; } } } Server public static void main(String[] args) { BufferedInputStream bis; BufferedOutputStream bos; int num; File file = new File(ServerStats.serverFolder); if (!(file.exists())){ file.mkdir(); } try { int i = 1; ServerSocket socket = new ServerSocket(ServerStats.imgServerPort); Socket incoming = socket.accept(); System.out.println("Spawning " + i); try { try{ if (!(file.exists())){ file.mkdir(); } InputStream inStream = incoming.getInputStream(); OutputStream outStream = incoming.getOutputStream(); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); String length2 = inm.readLine(); System.out.println(length2); String filename = inm.readLine(); System.out.println("Filename = " + filename); out.println("ACK: Filename received = " + filename); //RECIEVE and WRITE FILE byte[] receivedData = new byte[1000000]; bis = new BufferedInputStream(incoming.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(ServerStats.serverFolder + "/" + filename)); long length = (long)Integer.parseInt(length2); length++; long counter = 0; while (counter < length){ num = bis.read(receivedData); bos.write(receivedData,0,num); counter ++; } System.out.println(counter); bos.close(); bis.close(); File receivedFile = new File(filename); long receivedLen = receivedFile.length(); out.println("ACK: Length of received file = " + receivedLen); } finally { incoming.close(); } } catch (IOException e){ e.printStackTrace(); } } catch (IOException e1){ e1.printStackTrace(); } } The code is some I found, and I have slightly modified it, but I am having problems transferring multiple images over the server. Output on Client: run ServerQueue.Client Connected to : localhost transfer: Picture 012.jpg 1312743 java.lang.ArrayIndexOutOfBoundsException Connected to : localhost transfer: Picture 012.jpg 1312743 Cant seem to get it to transfer multiple images. But bothsides I think crash or something because the file never finishes transfering

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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • How To Quickly Reboot Directly from Windows 7 to XP, Vista, or Ubuntu

    - by The Geek
    One of the biggest annoyances with a dual-boot system is having to wait for your PC to reboot to select the operating system you want to switch to, but there’s a simple piece of software that can make this process easier. This guest article was written by Ryan Dozier from the Doztech tech blog. With a small piece of software called iReboot we can skip the above step all together and instantly reboot into the operating system we want right from Windows. Their description says: “Instead of pressing restart, waiting for Windows to shut down, waiting for your BIOS to post, then selecting the operating system you want to boot into (within the bootloader time-limit!); you just select that entry from iReboot and let it do the rest!” Don’t worry about iReboot reconfiguring  your bootloader or any dual boot configuration you have. iReboot will only boot the selected operating system once and go back to your default settings. Using iReboot iReboot is quick and easy to install. Just download it, link below, run through the setup and select the default configuration. iReboot will automatically figure out what operating systems you have installed and appear in the taskbar. Go over to the taskbar and right click on the iReboot icon and select which operating system you want to reboot into. This method will add a check mark on the operating system you want to boot into. On your next reboot the system will automatically load your choice and skip the Windows Boot Manager. If you want to reboot automatically just select “Reboot on Selection” in the iReboot menu.   To be even more productive, you can install iReboot into each Windows operating system to quickly access the others with a few simple clicks.   iReboot does not work in Linux so you will have to reboot manually. Then wait for the Windows Boot Manager to load and select your operating system.   Conclusion iReboot works on  Windows XP, Windows Vista,  and Windows 7 as well as 64 bit versions of these operating systems. Unfortunately iReboot is only available for Windows but you can still use its functionality in Windows to quickly boot up your Linux machine. A simple reboot in Linux will take you back to Windows Boot Manager. Download iReboot from neosmart.net Editor’s note: We’ve not personally tested this software over at How-To Geek, but Neosmart, the author of the software, generally makes quality stuff. Still, you might want to test it out on a test machine first. If you’ve got any experience with this software, please be sure to let your fellow readers know in the comments. Similar Articles Productive Geek Tips Restart the Ubuntu Gnome User Interface QuicklyKeyboard Ninja: 21 Keyboard Shortcut ArticlesTest Your Computer’s Memory Using Windows Vista Memory Diagnostic ToolEnable or Disable UAC From the Windows 7 / Vista Command LineSet Windows as Default OS when Dual Booting Ubuntu TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird Follow Finder Finds You Twitter Users To Follow Combine MP3 Files Easily QuicklyCode Provides Cheatsheets & Other Programming Stuff Download Free MP3s from Amazon

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  • Riak "error":"insufficient_vnodes_available"

    - by Wolfiem
    We have 4 nodes Riak installation. They are running on Ubuntu 12.04 LTS Precise installed servers. We have installed 1.1.4 at August 1st 2012 and upgraded 1.2.0 when its available. Server names are: f1 - 10.10.0.12 - This is the first installed server. We have joined other ones to this server. This also serves Riak control. s2 - 10.10.0.22 - s3 - 10.10.0.23 - s4 - 10.10.0.24 - This server also serves Riak control. This morning we've seen "insufficient nodes available" error at our applications log and restarted all nodes. 3 of them became available except "f1" UPDATE : while I prepare this message live 3 nodes became unavailable and need restart Riak. wolfiem@f01:~$ sudo /etc/init.d/riak start Riak failed to start within 15 seconds, see the output of 'riak console' for more information. If you want to wait longer, set the environment variable WAIT_FOR_ERLANG to the number of seconds to wait. I've tried to set WAIT_FOR_ERLANG value to 60 seconds but I can't. adding this line in vm.args didn't work: -env WAIT_FOR_ERLANG 60 I also tried to set this from terminal but it didn't work either. wolfiem@f01:~$ export WAIT_FOR_ERLANG=60 It still says "Riak failed to start within 15 seconds" This is the console.log output: 2012-09-11 10:58:02.532 [info] <0.7.0> Application lager started on node '[email protected]' 2012-09-11 10:58:02.560 [warning] <0.148.0>@riak_core_ring_manager:reload_ring:231 No ring file available. 2012-09-11 10:58:02.585 [error] <0.164.0> CRASH REPORT Process <0.164.0> with 0 neighbours exited with reason: eaddrnotavail in gen_server:init_it/6 line 320 This is the error.log output 2012-09-11 10:58:02.585 [error] <0.164.0> CRASH REPORT Process <0.164.0> with 0 neighbours exited with reason: eaddrnotavail in gen_server:init_it/6 line 320 This is the crash.log output: 2012-09-11 10:58:02 =CRASH REPORT==== crasher: initial call: mochiweb_socket_server:init/1 pid: <0.164.0> registered_name: [] exception exit: {eaddrnotavail,[{gen_server,init_it,6,[{file,"gen_server.erl"},{line,320}]},{proc_lib,init_p_do_apply,3,[{file,"proc_lib.erl"},{line,227}]}]} ancestors: [riak_core_sup,<0.135.0>] messages: [] links: [<0.136.0>] dictionary: [] trap_exit: true status: running heap_size: 377 stack_size: 24 reductions: 403 neighbours: You can find the riak console output below: wolfiem@f01:~$ riak console Attempting to restart script through sudo -H -u riak Exec: /usr/lib/riak/erts-5.9.1/bin/erlexec -boot /usr/lib/riak/releases/1.2.0/riak -embedded -config /etc/riak/app.config -pa /usr/lib/riak/basho-patches -args_file /etc/riak/vm.args -- console Root: /usr/lib/riak Erlang R15B01 (erts-5.9.1) [source] [64-bit] [smp:8:8] [async-threads:64] [kernel-poll:true] =INFO REPORT==== 11-Sep-2012::10:44:18 === alarm_handler: {set,{system_memory_high_watermark,[]}} ** /usr/lib/riak/lib/observer-1.1/ebin/etop_txt.beam hides /usr/lib/riak/lib/basho-patches/etop_txt.beam ** Found 1 name clashes in code paths 10:44:19.099 [info] Application lager started on node '[email protected]' 10:44:19.130 [warning] No ring file available. 10:44:19.158 [error] CRASH REPORT Process <0.164.0> with 0 neighbours exited with reason: eaddrnotavail in gen_server:init_it/6 line 320 /usr/lib/riak/lib/os_mon-2.2.9/priv/bin/memsup: Erlang has closed. =INFO REPORT==== 11-Sep-2012::10:44:19 === alarm_handler: {clear,system_memory_high_watermark} Erlang has closed {"Kernel pid terminated",application_controller,"{application_start_failure,riak_core,{shutdown,{riak_core_app,start,[normal,[]]}}}"} Crash dump was written to: /var/log/riak/erl_crash.dump Kernel pid terminated (application_controller) ({application_start_failure,riak_core,{shutdown,{riak_core_app,start,[normal,[]]}}})

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  • dpkg: error processing /var/cache/apt/archives/python2.6-minimal_2.6.6-5ubuntu1_i386.deb (--unpack)

    - by udo
    I had an issue (Question 199582) which was resolved. Unfortunately I am stuck at this point now. Running root@X100e:/var/cache/apt/archives# apt-get dist-upgrade Reading package lists... Done Building dependency tree Reading state information... Done Calculating upgrade... Done The following NEW packages will be installed: file libexpat1 libmagic1 libreadline6 libsqlite3-0 mime-support python python-minimal python2.6 python2.6-minimal readline-common 0 upgraded, 11 newly installed, 0 to remove and 0 not upgraded. Need to get 0B/5,204kB of archives. After this operation, 19.7MB of additional disk space will be used. Do you want to continue [Y/n]? Y (Reading database ... 6108 files and directories currently installed.) Unpacking python2.6-minimal (from .../python2.6-minimal_2.6.6-5ubuntu1_i386.deb) ... new installation of python2.6-minimal; /usr/lib/python2.6/site-packages is a directory which is expected a symlink to /usr/local/lib/python2.6/dist-packages. please find the package shipping files in /usr/lib/python2.6/site-packages and file a bug report to ship these in /usr/lib/python2.6/dist-packages instead aborting installation of python2.6-minimal dpkg: error processing /var/cache/apt/archives/python2.6-minimal_2.6.6-5ubuntu1_i386.deb (--unpack): subprocess new pre-installation script returned error exit status 1 Errors were encountered while processing: /var/cache/apt/archives/python2.6-minimal_2.6.6-5ubuntu1_i386.deb E: Sub-process /usr/bin/dpkg returned an error code (1) results in above error. Running root@X100e:/var/cache/apt/archives# dpkg -i python2.6-minimal_2.6.6-5ubuntu1_i386.deb (Reading database ... 6108 files and directories currently installed.) Unpacking python2.6-minimal (from python2.6-minimal_2.6.6-5ubuntu1_i386.deb) ... new installation of python2.6-minimal; /usr/lib/python2.6/site-packages is a directory which is expected a symlink to /usr/local/lib/python2.6/dist-packages. please find the package shipping files in /usr/lib/python2.6/site-packages and file a bug report to ship these in /usr/lib/python2.6/dist-packages instead aborting installation of python2.6-minimal dpkg: error processing python2.6-minimal_2.6.6-5ubuntu1_i386.deb (--install): subprocess new pre-installation script returned error exit status 1 Errors were encountered while processing: python2.6-minimal_2.6.6-5ubuntu1_i386.deb results in above error. Running root@X100e:/var/cache/apt/archives# dpkg -i --force-depends python2.6-minimal_2.6.6-5ubuntu1_i386.deb (Reading database ... 6108 files and directories currently installed.) Unpacking python2.6-minimal (from python2.6-minimal_2.6.6-5ubuntu1_i386.deb) ... new installation of python2.6-minimal; /usr/lib/python2.6/site-packages is a directory which is expected a symlink to /usr/local/lib/python2.6/dist-packages. please find the package shipping files in /usr/lib/python2.6/site-packages and file a bug report to ship these in /usr/lib/python2.6/dist-packages instead aborting installation of python2.6-minimal dpkg: error processing python2.6-minimal_2.6.6-5ubuntu1_i386.deb (--install): subprocess new pre-installation script returned error exit status 1 Errors were encountered while processing: python2.6-minimal_2.6.6-5ubuntu1_i386.deb is not able to fix this. Any clues how to fix this?

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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  • “compute launch button tooltip” error in eclipse

    - by Brahms
    I'm trying to run Android SDK with Eclipse for the first time. I have never used Eclipse before and I'm running into the following error message over and over again, with no specific trigger: "compute launch button tooltip has encountered a problem" I tried to Google it but I can't find a solution. It's driving me crazy, please help. I'm using Ubuntu 12.04 LTS. I tried re-installing Eclipse, same thing.

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  • SQL Error (2003): Can't connect to MySQL server on 'X.X.X.X.' (10051) - What does this error mean?

    - by BeeS
    I get following error when i try to connect via "HeidiSQL" to my database server (local network) SQL Error (2003): Can't connect to MySQL server on 'X.X.X.X.' (10051) SSH Connection via Putty works fine. I checked the my.cnf file on the server (Ubuntu), but settings like bind_address are correct. Is it possible that my wireless modem (SpeedTouch) makes this trouble? (Because my provider changed the download speed) !? Thank you very much for your help!

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  • Why won't ruby recognize Haml under ubuntu64 while using jekyll static blog generator?

    - by oldmanjoyce
    I have been trying, quite unsuccessfully, to run henrik's fork of the jekyll static blog generator on Ubuntu 64-bit. I just can't seem to figure this out and I've tried a bunch of different things. Originally I posted this over at stackoverflow, but this is probably the better spot for it. The base stats of my machine: Ubuntu 9.04, 64 bit, ruby 1.8.7 (2008-08-11 patchlevel 72) [x86_64-linux], rubygems 1.3.1. When I attempt to build the site, this is what happens: $ jekyll --pygments Configuration from ./_config.yml Using Sass for CSS generation You must have the haml gem installed first Using rdiscount for Markdown Building site: . - ./_site /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/core_ext.rb:27:in `method_missing': undefined method 'header' for #, page=# ..... cut ..... (NoMethodError) from (haml):9:in `render' from /home/chris/.gem/gems/haml-2.2.3/lib/haml/engine.rb:167:in 'render' from /home/chris/.gem/gems/haml-2.2.3/lib/haml/engine.rb:167:in 'instance_eval' from /home/chris/.gem/gems/haml-2.2.3/lib/haml/engine.rb:167:in 'render' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/convertible.rb:72:in 'render_haml_in_context' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/convertible.rb:105:in 'do_layout' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/post.rb:226:in 'render' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/site.rb:172:in 'read_posts' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/site.rb:171:in 'each' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/site.rb:171:in 'read_posts' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/site.rb:210:in 'transform_pages' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/../lib/jekyll/site.rb:126:in 'process' from /home/chris/.gem/gems/henrik-jekyll-0.5.2/bin/jekyll:135 from /home/chris/.gem/bin/jekyll:19:in `load' from /home/chris/.gem/bin/jekyll:19 I added spaces to the left of the ClosedStruct to enable better visibility - sorry that my inline html/formatting isn't perfect. I also cut out some middle text that is just data. $ gem list *** LOCAL GEMS *** actionmailer (2.3.4) actionpack (2.3.4) activerecord (2.3.4) activeresource (2.3.4) activesupport (2.3.4) classifier (1.3.1) directory_watcher (1.2.0) haml (2.2.3) haml-edge (2.3.27) henrik-jekyll (0.5.2) liquid (2.0.0) maruku (0.6.0) open4 (0.9.6) rack (1.0.0) rails (2.3.4) rake (0.8.7) rdiscount (1.3.5) RedCloth (4.2.2) stemmer (1.0.1) syntax (1.0.0) Some showing for path verification: $ echo $PATH /home/chris/.gem/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games $ which haml /home/chris/.gem/bin/haml $ which jekyll /home/chris/.gem/bin/jekyll

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  • Install qpid-tool

    - by c0mrade
    Does anyone know how to install qpid-tool on ubuntu/centOS? http://www.redhat.com/docs/en-US/Red_Hat_Enterprise_MRG/1.1/html/Messaging_User_Guide/sect-Messaging_User_Guide-Command_Line_Tools-Using_qpid_tool.html Can't fing binary files or anything

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  • Setting up APACHE-JAMES Server

    - by venomrld
    I am trying to setup Apache-James Server on Ubuntu, in which I am getting the annoying error: JAVA_HOME not defined correctly We cannot execute I have already referred to the documentations and set up the PATH and JAVA_HOME variables correctly in the /etc/profile file. Upon calling echo, I get the values in the output screen. Where am I missing? echo $JAVA_HOME /usr/local/jdk1.6.0_27 echo $PATH $PATH:/usr/local/jdk1.6.0_27/bin Please Help !!

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