Search Results

Search found 17149 results on 686 pages for 'python twitter'.

Page 430/686 | < Previous Page | 426 427 428 429 430 431 432 433 434 435 436 437  | Next Page >

  • What kind of data do I pass into a Django Model.save() method?

    - by poswald
    Lets say that we are getting POSTed a form like this in Django: rate=10 items= [23,12,31,52,83,34] The items are primary keys of an Item model. I have a bunch of business logic that will run and create more items based on this data, the results of some db lookups, and some business logic. I want to put that logic into a save signal or an overridden Model.save() method of another model (let's call it Inventory). The business logic will run when I create a new Inventory object using this form data. Inventory will look like this: class Inventory(models.Model): picked_items = models.ManyToManyField(Item, related_name="items_picked_set") calculated_items = models.ManyToManyField(Item, related_name="items_calculated_set") rate = models.DecimalField() ... other fields here ... New calculated_items will be created based on the passed in items which will be stored as picked_items. My question is this: is it better for the save() method on this model to accept: the request object (I don't really like this coupling) the form data as arguments or kwargs (a list of primary keys and the other form fields) a list of Items (The caller form or view will lookup the list of Items and create a list as well as pass in the other form fields) some other approach? I know this is a bit subjective, but I was wondering what the general idea is. I've looked through a lot of code but I'm having a hard time finding a pattern I like.

    Read the article

  • How to include a dynamic page contents into a template ?

    - by Ankit
    Hi All, I have to include a dynamic page content into my template, Say I have a left panel which gets the data dynamically through a view. Now, I have to include this left panel into all my pages but I do not want to duplicate the code for all the pages. Is there any way, I can write a single script and include it in all my templates to display the left panel in all my pages? Thanks in advance.

    Read the article

  • Django: Get bound IP address inside settings.py

    - by Silver Light
    Hello! I want to enable debug (DEBUG = True) For my Django project only if it runs on localhost. How can I get user IP address inside settings.py? I would like something like this to work: #Debugging only on localhost if user_ip = '127.0.0.1': DEBUG = True else: DEBUG = False How do I put user IP address in user_ip variable inside settings.py file?

    Read the article

  • Updating a modul leve shared dictionary

    - by Vishal
    Hi, A module level dictionary 'd' and is accessed by different threads/requests in a django web application. I need to update 'd' every minute with a new data and the process takes about 5 seconds. What could be best solution where I want the users to get either the old value or the new value of d and nothing in between. I can think of a solution where a temp dictionary is constructed with a new data and assigned to 'd' but not sure how this works! Appreciate your ideas. Thanks

    Read the article

  • How do I delete in Django? (mysql transactions)

    - by alex
    If you are familiar with Django, you know that they have a Authentication system with User model. Of course, I have many other tables that have a Foreign Key to this User model. If I want to delete this user, how do I architect a script (or through mysql itself) to delete every table that is related to this user? My only worry is that I can do this manually...but if I add a table , but I forget to add that table to my DELETE operation...then I have a row that links to a deleted, non-existing User.

    Read the article

  • Change|Assign parent for the Model instance on Google App Engine Datastore

    - by Vladimir Prudnikov
    Is it possible to change or assign new parent to the Model instance that already in datastore? For example I need something like this task = db.get(db.Key(task_key)) project = db.get(db.Key(project_key)) task.parent = project task.put() but it doesn't works this way because task.parent is built-in method. I was thinking about creating a new Key instance for the task but there is no way to change key as well. Any thoughts?

    Read the article

  • Processing forms that generate many rows in DB

    - by Zack
    I'm wondering what the best approach to take here is. I've got a form that people use to register for a class and a lot of times the manager of a company will register multiple people for the class at the same time. Presently, they'd have to go through the registration process multiple times and resubmit the form once for every person they want to register. What I want to do is give the user a form that has a single <input/> for one person to register with, along with all the other fields they'll need to fill out (Email, phone number, etc); if they want to add more people, they'll be able to press a button and a new <input/> will be generated. This part I know how to do, but I'm including it to best describe what I'm aiming to do. The part I don't know how to approach is processing that data the form submits, I need some way of making a new row in the Registrant table for every <input/> that's added and include the same contact information (phone, email, etc) as the first row with that row. For the record, I'm using the Django framework for my back-end code. What's the best approach here? Should it just POST the form x times for x people, or is there a less "brute force" way of handling this?

    Read the article

  • how to capture the right click event using getMouse()

    - by Leyond
    I am trying to use graphics.py to write a user graphics interface. The problem is that how can I capture the right click event? It seems that the function getMouse() could just returns where the mouse was left-clicked as a Point object. from graphics import * def main(): win = GraphWin("My Circle", 100, 100) c = Circle(Point(50,50), 10) c.draw(win) win.getMouse() # pause for click in window win.close() main() I want to know how can I capture the right-click event in the window, thanks.

    Read the article

  • Time difference in seconds (as a floating point)

    - by pocoa
    >>> from datetime import datetime >>> t1 = datetime.now() >>> t2 = datetime.now() >>> delta = t2 - t1 >>> delta.seconds 7 >>> delta.microseconds 631000 Is there any way to get that as 7.631000 ? I can use time module, but I also need that t1 and t2 variables as DateTime objects. So if there is a way to do it with datettime, that would be great.

    Read the article

  • How would I make this faster? Parsing Word/sorting by heading [on hold]

    - by Doof12
    Currently it takes about 3 minutes to run through a single 53 page word document. Hopefully you all have some advice about speeding up the process. Code: import win32com.client as win32 from glob import glob import io import re from collections import namedtuple from collections import defaultdict import pprint raw_files = glob('*.docx') word = win32.gencache.EnsureDispatch('Word.Application') word.Visible = False oFile = io.open("rawsort.txt", "w+", encoding = "utf-8")#text dump doccat= list() for f in raw_files: word.Documents.Open(f) doc = word.ActiveDocument #whichever document is active at the time doc.ConvertNumbersToText() print doc.Paragraphs.Count for x in xrange(1, doc.Paragraphs.Count+1):#for loop to print through paragraphs oText = doc.Paragraphs(x) if not oText.Range.Tables.Count >0 : results = re.match('(?P<number>(([1-3]*[A-D]*[0-9]*)(.[1-3]*[0-9])+))', oText.Range.Text) stylematch = re.match('Heading \d', oText.Style.NameLocal) if results!= None and oText.Style != None and stylematch != None: doccat.append((oText.Style.NameLocal, oText.Range.Text[:len(results.group('number'))],oText.Range.Text[len(results.group('number')):])) style = oText.Style.NameLocal else: if oText.Range.Font.Bold == True : doccat.append(style, oText) oFile.write(unicode(doccat)) oFile.close() The for Paragraph loop obviously takes the most amount of time. Is there some way of identifying and appending it without going through every Paragraph?

    Read the article

  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

    Read the article

  • Sql Alchemy Duplicated Commit

    - by PythonWolf
    Good Morning i'm currently facing a problem in my Cherrypy application. Im my own custom session module , anyway when performing session.add() The exact same object gets updated Twice. cherrypy.request.SessionManager.user_data = user try: db_session.add(cherrypy.request.SessionManager) db_session.commit() Will Return 2011-06-21 09:16:48,991 INFO sqlalchemy.engine.base.Engine.0x...04cL BEGIN (implicit) 2011-06-21 09:16:49,015 INFO sqlalchemy.engine.base.Engine.0x...04cL SELECT ..... FROM "Clients_Users" WHERE "Clients_Users".username = %(username_1)s AND "Clients_Users".password = %(password_1)s LIMIT 1 OFFSET 0 2011-06-21 09:16:49,015 INFO sqlalchemy.engine.base.Engine.0x...04cL {'password_1': '123', 'username_1': u'1'} 2011-06-21 09:16:49,047 INFO sqlalchemy.engine.base.Engine.0x...04cL UPDATE "SYS_Sessions" SET user_data=%(user_data)s WHERE "SYS_Sessions".id = %(SYS_Sessions_id)s 2011-06-21 09:16:49,067 INFO sqlalchemy.engine.base.Engine.0x...04cL {'SYS_Sessions_id': 92L, 'user_data': } 2011-06-21 09:16:49,071 INFO sqlalchemy.engine.base.Engine.0x...04cL COMMIT 2011-06-21 09:16:49,093 INFO sqlalchemy.engine.base.Engine.0x...04cL BEGIN (implicit) 2011-06-21 09:16:49,095 INFO sqlalchemy.engine.base.Engine.0x...04cL UPDATE "SYS_Sessions" SET user_data=%(user_data)s WHERE "SYS_Sessions".id = %(SYS_Sessions_id)s 2011-06-21 09:16:49,095 INFO sqlalchemy.engine.base.Engine.0x...04cL {'SYS_Sessions_id': 92L, 'user_data': } 2011-06-21 09:16:49,108 INFO sqlalchemy.engine.base.Engine.0x...04cL COMMIT As Anyone seen this before ? P.S This doesn't happen in the rest of the modules i have made.

    Read the article

  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

    Read the article

  • Doing a count over a filter query efficiently in django

    - by apple_pie
    Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

    Read the article

  • how to download data which upload to gae ,

    - by zjm1126
    this is my code : import os from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext import db #from login import htmlPrefix,get_current_user class MyModel(db.Model): blob = db.BlobProperty() class BaseRequestHandler(webapp.RequestHandler): def render_template(self, filename, template_args=None): if not template_args: template_args = {} path = os.path.join(os.path.dirname(__file__), 'templates', filename) self.response.out.write(template.render(path, template_args)) class upload(BaseRequestHandler): def get(self): self.render_template('index.html',) def post(self): file=self.request.get('file') obj = MyModel() obj.blob = db.Blob(file.encode('utf8')) obj.put() self.response.out.write('upload ok') class download(BaseRequestHandler): def get(self): #id=self.request.get('id') o = MyModel.all().get() #self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o))) self.response.out.write(o) application = webapp.WSGIApplication( [ ('/?', upload), ('/download',download), ], debug=True ) def main(): run_wsgi_app(application) if __name__ == "__main__": main() my index.html is : <form action="/" method="post"> <input type="file" name="file" /> <input type="submit" /> </form> and it show : <__main__.MyModel object at 0x02506830> but ,i don't want to see this , i want to download it , how to change my code to run, thanks

    Read the article

  • Django template context not working with imported class

    - by Andy Hume
    I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

    Read the article

  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

    Read the article

  • Default subclass objects in Sqlalchemy?

    - by Timmy
    im using the example from the pylons book orm.mapper(Comment, comment_table) orm.mapper(Tag, tag_table) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) i am mostly copying from this, but is there a simple way have a default Page that gets referenced, but if users requests a change, create a new Page object? thanks i want something similar to this class DefaultPage(Page): __init__(self): self.a = a self.b = b self.c = c orm.mapper(DefaultPage, None, inherits=Nav, yada yada )

    Read the article

< Previous Page | 426 427 428 429 430 431 432 433 434 435 436 437  | Next Page >