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  • Ubuntu server 9.10 freezes up after ~10 minutes - unconventional

    - by L33tCh
    There is a topic by essentially the same name, but my answer leads to another question which I would like answered so... My case is as follows: I connect through SSH to my server... no problems for many months on Ubuntu Server 9.04. Eventually I decided to updgrade and straight away I get the 10 minutes freeze problem. I went through all the possible fixes (many can be found here but my quick fix, the only that worked, leaves me with no real answer as to why and how to properly correct it... As ridiculous as it sounds... while I leave a keyboard plugged in... it runs without flaw. Can anyone make sense of this? For the sake of completeness, (although none of the following made any difference upon subsequent completion), some of the permanent changes I have made while trying to correct the issue are: replacing samba config file with 9.04 backup, booting with noapic and modifying sysctl.conf, just uncommenting additional settings for enhanced security.

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  • Does downloading the same torrent from more than one server increase the sources / seeds?

    - by Petruza
    Does downloading the same torrent from more than one server increase the sources / seeds? edit: What I meant with servers is those like mininova, isohunt and the like. Now I know those aren't the trackers, what I want to know is if when more than one of those indexing sites are linked for the same torrent, if they likely contain different lists of trackers, so getting the torrent from both sites will increase the trackers, hence the seeds, or if it's just in case one of the sites goes down. I guess I can test this getting one torrent from one site with a torrent client and the same torrent, from another site with another client and comparing the list of trackers and the amount of seeders and leechers.

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  • non-mapped virtual memory & total number of connections

    - by tszming
    We have two MongoDB data nodes (replica set) - Primary & Secondary. I noticed that the non-mapped virtual memory is relatively high and wondering if they are hurting our MongoDB performance (The server usually peaked at around 6-7K queries per sec). In MMS, it was stated: "The most common case of usage of a high amount of memory for non-mapped is that there are very many connections to the database." So we checked the memory usage with db.serverStatus().mem in our Secondary: { "bits" : 64, "resident" : 6846, "virtual" : 416797, "supported" : true, "mapped" : 205549, "mappedWithJournal" : 411098, "note" : "virtual minus mapped is large. could indicate a memory leak" } Note: We are using 2.0.4 and now the default stack size should be 1MB per connection. The current number of connections is around 1.1K, but the non-mapped virtual memory (virtual-mappedWithJournal) is around 5699 MB. The trend is quite stable so I can't say there is a leak here, but where is the memory gone? Any idea?

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  • Where do I read more about building an architecture like Google has? [on hold]

    - by user107148
    I want to develop a program that watches and traverses a rather big network for data. This data should then be available to search through with my program, maybe through a web interface or something. My intuitive thought at the moment is to build an architecture kind of like the one Google has. One "front-end" (the Google Search page) which is essentially a regular web application and one "back-end" (which in Google's case traverses the web). Now for the hard part: If I decide to make such a system, how should communication be done between these parts? One idea I had is to use some kind of database that both the back-end and front-end can access, but then comes the issues of concurrent writes and reads. Another issue with just using a database to communicate is that it makes it hard to "notify" the other part when something changes. Let's say that I want the "front-end" part to push changes to the UI when a change is noticed in the back-end. Then the back-end would have to have some way of notifying the front-end of this.

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  • Keyboard that can't be removed (W8 CP)

    - by torazaburo
    Somehow I ended up with four keyboards installed (English (United States), Japanese (Japan), Kannada, and Hindi. They are installed in the sense that the tray drop down displays these four, and when I ALT-SHIFT through my keyboards it cycles through them. The mysterious thing is that in the Languages Control Panel, only the first two are shown, so I am stuck as to how to remove the last two. In the past, I may have installed and removed the Kannada and Hindi keyboards. What I did recently was to install the English (India) keyboard, as a way to get the ability to input the rupee symbol with ALT-CTRL-4. That English (India) keyboard did show up in the Languages Control Panel and allow itself to be removed. It almost seems like installing that keyboard somehow activate hidden registry settings left over from back when I had Kannada and Hindi installed. In any case, any ideas about how to remove these keyboards which don't appear in the Language Control Panel?

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  • Why will multiple dvd/cd-rom drives stop reading?

    - by ddc0660
    I'm having difficulty with two dvd/cd drives. When I updated from XP to Vista, I noticed they wouldn't work. I could add cds or dvds to the drives and they would attempt to read the disk, but never "found" a disk in the drive. Vista showed the drives existed without problems. I updated their drivers and nothing changed. I thought perhaps, oddly, both drives were going bad. Then I got Windows 7, and I figured I'd have to do some gymnastics in order to get it onto my system without a working disk drive. However, I can boot from the Windows 7 disk fine! I installed 7 hoping that it was a Vista problem and I'd reclaim my drives, but that is not the case. The same symptoms persist. Thoughts?

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  • Make all text EXCEPT <input> unselectable in Internet Explorer? [migrated]

    - by Ashli
    I have a website where I want to disable users from selecting content EXCEPT for input areas. I currently have some CSS to disable user-select: -webkit-user-select: none; -khtml-user-select: none; -moz-user-select: none; -o-user-select: none; user-select: none; However, this does NOT cover Internet Explorer; thus, I need to implement some JavaScript: <body onselectstart="return false;"> Through CSS and JavaScript, I can make all content unselectable across all popular browsers. BUT, this code also makes areas unselectable, which is a major case of poor usability. I use CSS to make input areas selectable: -webkit-user-select: text; -khtml-user-select: text; -moz-user-select: text; -o-user-select: text; user-select: text; .. and as you might have expected, this does not cover Internet Explorer, since I used JavaScript to disable all content from being selectable. What can I do to make all content unselectable except for input areas?

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  • Sync laptop and desktop solution/ideas?

    - by user1078719
    I have a laptop and a desktop I want to keep files up-to-date on both of them. I was thinking of creating a hard drive on 'server' and then changing "my documents" to that server path. It should work all right when there are two computers but what if a laptop uses wireless access at my house and more importantly, when it's connected wirelessly on a different IP range when I'm at college? For the second case, I guess, creating a VPN/remote server connection to the desktop will work, but if I want to make it automatic (my documents mapping), is there way to do that?

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  • Oracle 10g Failover Database - How to fail back?

    - by rrkwells
    I want to know how the failover database concept works after recovery. We have defined our application to connect to a backup database in case the production database fails. If this happens, then all the transactions will be happening on that backup database. Once the production db server is running again, then how do we make sure the changes made in the backup database will be reflected on the production database? We want to make sure that any changes made while failed over are not lost. We are using Oracle 10g.

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  • ATI HD 5970 display

    - by user55406
    Hello everyone i'm a little worry about my graphic card. before I get into that I will tell you my system specs. I have intel dx58so mainboard, 6gb corsair xms ddr3 ram, intel i7 960 cpu, and ati hd 5970. I'm also using a coolmaster haf92 case. My OS is vista X64. Here is my issue when I type in dxdiag in (Start Search) and I look into display. I see in (approx total memory) 716mb graphic memory. The ati hd 5970 is a 2gb graphic card. Am I being stuipd or is there an issue.

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  • Why is the camera not following the player? [on hold]

    - by Homer_Simpson
    I use the following code to create Parallax Scrolling: http://www.david-gouveia.com/portfolio/2d-camera-with-parallax-scrolling-in-xna/ Parallax Scrolling is working but I don't know how to focus the camera on the player. If the player moves, then the camera doesn't follow the player. The player leaves the screen when I'm moving it. I use the following code(as described in the tutorial), but it's not working: // Updates my camera to lock on the character _camera.LookAt(player.Playerposition); What can I do so that the player is always in the center of the screen/camera? My player class: public class Player { Texture2D Playertex; public Vector2 Playerposition = new Vector2(400, 240); private Game1 game1; public Player(Game1 game) { game1 = game; } public void Load(ContentManager content) { Playertex = content.Load<Texture2D>("8bitmario"); TouchPanel.EnabledGestures = GestureType.HorizontalDrag; } public void Update(GameTime gameTime) { while (TouchPanel.IsGestureAvailable) { GestureSample gs = TouchPanel.ReadGesture(); switch (gs.GestureType) { case GestureType.HorizontalDrag: Playerposition.X += 3f; break; } } } public void Render(SpriteBatch batch) { batch.Draw(Playertex, new Vector2(Playerposition.X - Playertex.Width / 2, Playerposition.Y - Playertex.Height / 2), Color.White); } } In Game1, I update the player and camera class: protected override void Update(GameTime gameTime) { // Updates my character's position player.Update(gameTime); // Updates my camera to lock on the character _camera.LookAt(player.Playerposition); base.Update(gameTime); } protected override void Draw(GameTime gameTime) { GraphicsDevice.Clear(Color.CornflowerBlue); foreach (Layer layer in _layers) layer.Draw(spriteBatch); spriteBatch.Begin(SpriteSortMode.Deferred, null, null, null, null, null, _camera.GetViewMatrix(new Vector2(0.0f, 0.0f))); player.Render(spriteBatch); spriteBatch.End(); base.Draw(gameTime); }

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  • Server IP must be a LAN IP (Port Forwarding Netgear Router)? [closed]

    - by rphello101
    I'm trying to set up a server (Apache) on my computer (fairly new to it). As I understand it, for it to be accessible to other computers, I need to forward port 80. When I try to forward the port though, I get the error: Server IP must be a LAN IP. I noticed in ipconfig that my default gateway is different than my wireless router. My computer is not hardwired, not on WiFi. Furthermore, I do not, at this point, have a static IP. I read that it should still work with a dynamic IP until it changes. Any ideas on what I can do? I'm using Windows 7 in case it matters.

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  • Windows 8: How to Lock (not sleep) laptop on lid close?

    - by Eye of Hell
    If my laptop is connected to power source and is not configured to sleep on lid close (it is connected to power source and is working, i don't want it to sleep. It's compiling my code) if i close the lid, laptop will do nothing. This works as expected, but actually if i have my laptop connected to power source in the office it will be good to lock it if i close a lid. So no one can just open the lid and see my unlocked desktop. I searched google and it says thet correct use case is to manually lock laptop via Win + L every time before lid is closed. This is ok, but not very secure - after all, i can forget Win + L. Is t any easy way (maybe some registry value or app) to configure windows laptop so it will lock on lid close even without sleep? Of course i can write app / powershell script for this task, but this is not suitable for non-programmers end users.

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  • Password format not liked by installer

    - by Box293
    I'm installing Chargeback and I get to the database-related information page (step 5 on page 17 of the users guide). Using a Windows account (it is an administrator of the server and I am logged on as that user) Username: DOMAIN\ServiceVMware-CB Password: #$%UuuU2u (this isn't the password but it does start with #$% and is the same length and case) I click the Test Connected and it returns back OK. I click Next and then I am given a warning telling me that the account does not have the right permissions. Check that it has log on as a service etc etc etc. I quit the installer. I change the password in the domain to Uuuuuu3 I reboot the server I restart the server The installer has no problems with the newer password. I'm not fussed either way, I'm just trying to save someone else the pain and perhaps the allowed password format could be added to the documentation. BTW I am using Server 2008 SP2 x64 with SQL Express 2005 x64.

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  • Two way replication

    - by Nidzaaaa
    I have a little problem... I have this case: -2 server instances -2 Databases -1 Table (5 columns) From server 1 I created publication to replicate all columns of table I have in 1. DB From server 2 I created subscription to pull all columns from table which is in server 1 DB But now, I need to publicate one columns of same table from server 2 to server 1 and also it has to be in same DB... I tried with using logic and creating publication for server 2 and subscription on server 1 but there is error appearing "You have selected the Publisher as a Subscriber and entered a subscription database that is the same as the publishing database. Select another subscription database." I hope someone understood my problem and have an answer for me, thanks in advance... p.s. Ask for more info if you need ...

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  • Upgrading Apache, PHP and MySQL

    - by Javacadabra
    I'm looking to upgrade my current version of Apache, PHP and mySQL. I remember when I installed them it was a very intricate and somewhat delicate process and I am sort of afraid to upgrade in case everything just stops working! Currently I am running Apache 2.2.21 and PHP 5.3.5. MySQL is 5.6.4 Does anyone have any ideas how you upgrade these things? I think the current versions are Apache 2.4.3, PHP 5.4.7 and MySQL 5.6. Thanks in advance!

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  • Transient mysqlcheck errors about "size of datafile" (file too small)

    - by Adam Backstrom
    Running mysqlcheck on a live database is giving me transient errors like this one: mydatabase.mytable error : Size of datafile is: 500719688 Should be: 501000484 error : Corrupt When I run the command again or check the table one-off using mysql, it's listed as OK. Is this just a side effect of running checks on live tables? Is it possible that data is not flushed, hence the strange discrepancy? We moved several databases this morning by shutting down mysqld on the source and rsyncing files across to the new server, but these are all MyISAM tables so I don't believe the two things are related. (But I mention it just in case.)

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  • Open Source or Low Cost Layer 7 ("Content") Switch?

    - by Rob
    I have several web servers that host a number of different applications and web sites. I want to make it easy to host apps or parts of web sites on different servers (e.g. example.com/foo might be on one physical server and example.com/bar might be on another). We do this Apache redirects right now, but that gets messy fast and in any case we have other problems we want to solve, such as throttling requests from individual clients, and reducing dependency on specific physical hosts. Is there an open source or low cost layer 7 switch that would be suitable for this sort of task? I was hoping to find something like a stripped down Linux VMware guest/appliance built for this purpose, but haven't seen anything suitable out there so far.

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  • ???? “Java?”???????? ?Java???????????!--Java Day Tokyo 2013????

    - by ???Y
    2013?5?14????????Java Day Tokyo 2013?????????????????????1????????Java??????????????JavaOne???????????????????????????Java????????????????????????????????????????????????????????????????????????????????????(????) JavaOne?????????Java Day Tokyo 2013??? ??????Java?????????Java????????(JJUG)??????????????????????????????JJUG????????????????????????????????????????????????????????????????? ???????????????(?????) ???????????????????????????????4???????????????????????"Java SE 8"???????????????????????????????????????????????????? ??????????????????????????????????????2???????????? ???BigDecimal?????equals????????? 1???????BigDecimal?????equals???????????????????????????????????(equity)???(liabilities)?????????(asset)??????1???????????????? ????????Java SE 8???????????????????????????????????????????2??????????????????????????????????????????????????????????????????????????????????????????????????????????0???1???2?????????????? ?????????????BigDecimal???????????????????????????"100"???????????????????????100.00??????????????????????"10000"?????????????????10000????? ??????????BigDecimal?????equals?????????????????????????????2??????????????"10000"??????10000?????????????1???????????"100"???100.00??????????????????? ????????????????equals?????????2???????????????????????????????????????1??????????????????????compareTo???????????????????????????? switch????????? ??????HTML???HTML5????????????????Map?????<Progress>???<tt>???<applet>????3???????????????(new=?????deprecated=????removed=??)???????????switch??????????????????????????????????? ????????????????????????(????applet)?????????????????????????????decorate????????????????????????StringBuilder?????????????????????????? ??????????????????"<applet>?HTML5?????????"??????????????????????????????????????????4????? ???????????????????? ????????????????????????switch???case?break??????????????????????????????????"<applet>?HTML5?????????"???????????????????? ???????????????????????????????????switch??????????????????????????Java SE 6???switch????????????????????????Java SE 7?????????????????????????????????????????? ?????????????????? ????????????????????????????????????????????decorate??????????StringBuilder?????????????????????????????char???????(<)??????????????StringBuilder?????????char????????????????????????????????????????????int???99????????????? ????????????????????????append???????????name???(applet)??>?????????????????????????applet>????????? ????????????Map?status??<applet>???????applet>???????????switch??????status.get(key)????????????status?????null??????????? ???????"??"?????Java?????switch???????null????????NullPointerException??????????? ????????????????????????????????????? ????char?????????????????????????????(IDE)??????????????????????????????????????switch?????????????null????????????????????? ???????2???????????????????Java????·?????????????????????????????????????????????????????????????????????????

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  • asp.net mvc jquery + tabs +jqgrid +jqgrid loaded only for first tab

    - by niao
    Greetings, I have a problem using jqgrid and jquery tab (I am coding in asp.net mvc) I have two tabs. Each tabs should contains jqgrid with different data. I specify tabs as follows: <script type="text/javascript"> $(document).ready(function() { $("#tabs").tabs(); getContentTab (1); }); function getContentTab(index) { var url='<%= Url.Content("~/Admin/GetWorkspaces") %>/' + index; var targetDiv = "#tabs-" + index; var ajaxLoading = "<img id='ajax-loader' src='<%= Url.Content("~/Content") %>/ajax-loader.gif' align='left' height='28' width='28'>"; $(targetDiv).html("<p>" + ajaxLoading + " Loading...</p>"); $.get(url,null, function(result) { $(targetDiv).html(result); }); } </script> <div id="tabs"> <ul> <li><a href="#tabs-1" onclick="getContentTab(1);">tab1</a></li> <li><a href="#tabs-2" onclick="getContentTab(2);">tab2</a></li> </ul> <div id="tabs-1"> </div> <div id="tabs-2"> </div> </div> As seen above GetWorkspaces action gets my tabs: public ActionResult GetWorkspaces(int id) { string viewName = string.Empty; switch (id) { case 1: viewName = "MarketplaceOfferView"; break; case 2: viewName = "MyMessagesView"; break; } return PartialView(viewName); } each of view is a partial view. In these partial views I have jqgrids specified as follows: <script type="text/javascript"> jQuery("#list").ready(function() { jQuery("#list").jqGrid({ url: '/Admin/GetGridData/', datatype: 'json', mtype: 'GET', colNames: ['Klient', 'Zapytanie', 'Atrakcyjnosc', 'Cena', 'Data poczatkowa', 'Data koncowa', 'Branza', 'Lokalizacja' ], colModel: [ { name: 'CompanyName', index: 'CompanyName', width: 150, align: 'left' }, { name: 'Content', index: 'ContactName', width: 300, align: 'left' }, { name: 'Rating', index: 'Address', width: 150, align: 'left' }, { name: 'Price', index: 'City', width: 150, align: 'left' }, { name: 'Price', index: 'City', width: 150, align: 'left' }, { name: 'Price', index: 'City', width: 150, align: 'left' }, { name: 'Price', index: 'City', width: 150, align: 'left' }, { name: 'Price', index: 'PostalCode', width: 100, align: 'left' } ], pager: jQuery('#pager'), rowNum: 100, rowList: [5, 10, 20, 50], sortname: 'Operator.FullName', sortorder: "asc", viewrecords: true, imgpath: '/scripts/themes/steel/images', caption: 'Historia moich wiadomosci', height:400 }); // .navGrid(pager, { edit: true, add: false, del: false, refresh: true, search: false }); }); </script> Historia moich wiadomosci <table id="list" class="scroll" cellpadding="0" cellspacing="0" width="100%"> </table> <div id="pager" class="scroll" style="text-align: center;"> </div> For second view I have an action: /Admin/GetGridDataForTab2/ THe problem is that I see a jqgrid only when I click on first tab. When I click on second tab the grid is not displayed and /Admin/GetGridData/ is not executed. Does anybody have an idea what is wrong?

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  • jQuery Validate - require at least one field in a group to be filled

    - by Nathan Long
    I'm using the excellent jQuery Validate Plugin to validate some forms. On one form, I need to ensure that the user fills in at least one of a group of fields. I think I've got a pretty good solution, and wanted to share it. Please suggest any improvements you can think of. Finding no built-in way to do this, I searched and found Rebecca Murphey's custom validation method, which was very helpful. I improved this in three ways: To let you pass in a selector for the group of fields To let you specify how many of that group must be filled for validation to pass To show all inputs in the group as passing validation as soon as one of them passes validation. So you can say "at least X inputs that match selector Y must be filled." The end result is a rule like this: partnumber: { require_from_group: [2,".productinfo"] } //The partnumber input will validate if //at least 2 `.productinfo` inputs are filled For best results, put this rule AFTER any formatting rules for that field (like "must contain only numbers", etc). This way, if the user gets an error from this rule and starts filling out one of the fields, they will get immediate feedback about the formatting required without having to fill another field first. Item #3 assumes that you're adding a class of .checked to your error messages upon successful validation. You can do this as follows, as demonstrated here. success: function(label) { label.html(" ").addClass("checked"); } As in the demo linked above, I use CSS to give each span.error an X image as its background, unless it has the class .checked, in which case it gets a check mark image. Here's my code so far: jQuery.validator.addMethod("require_from_group", function(value, element, options) { // From the options array, find out what selector matches // our group of inputs and how many of them should be filled. numberRequired = options[0]; selector = options[1]; var commonParent = $(element).parents('form'); var numberFilled = 0; commonParent.find(selector).each(function(){ // Look through fields matching our selector and total up // how many of them have been filled if ($(this).val()) { numberFilled++; } }); if (numberFilled >= numberRequired) { // This part is a bit of a hack - we make these // fields look like they've passed validation by // hiding their error messages, etc. Strictly speaking, // they haven't been re-validated, though, so it's possible // that we're hiding another validation problem. But there's // no way (that I know of) to trigger actual re-validation, // and in any case, any other errors will pop back up when // the user tries to submit the form. // If anyone knows a way to re-validate, please comment. // // For imputs matching our selector, remove error class // from their text. commonParent.find(selector).removeClass('error'); // Also look for inserted error messages and mark them // with class 'checked' var remainingErrors = commonParent.find(selector) .next('label.error').not('.checked'); remainingErrors.text("").addClass('checked'); // Tell the Validate plugin that this test passed return true; } // The {0} in the next line is the 0th item in the options array }, jQuery.format("Please fill out at least {0} of these fields.")); Questions? Comments?

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  • using Silverlight 3's HtmlPage.Window.Navigate method to reuse an already open browser window

    - by Phil
    Hi, I want to use an external browser window to implement a preview functionality in a silverlight application. There is a list of items and whenever the user clicks one of these items, it's opened in a separate browser window (the content is a pdf document, which is why it is handled ouside of the SL app). Now, to achieve this, I simply use HtmlPage.Window.Navigate(new Uri("http://www.bing.com")); which works fine. Now my client doesn't like the fact that every click opens up a new browser window. He would like to see the browser window reused every time an item is clicked. So I went out and tried implementing this: Option 1 - Use the overload of the Navigate method, like so: HtmlPage.Window.Navigate(new Uri("http://www.bing.com"), "foo"); I was assuming that the window would be reused when the same target parameter value (foo) would be used in subsequent calls. This does not work. I get a new window every time. Option 2 - Use the PopupWindow method on the HtmlPage HtmlPage.PopupWindow(new Uri("http://www.bing.com"), "blah", new HtmlPopupWindowOptions()); This does not work. I get a new window every time. Option 3 - Get a handle to the opened window and reuse that in subsequent calls private HtmlWindow window; private void navigationButton_Click(object sender, RoutedEventArgs e) { if (window == null) window = HtmlPage.Window.Navigate(new Uri("http://www.bing.com"), "blah"); else window.Navigate(new Uri("http://www.bing.com"), "blah"); if (window == null) MessageBox.Show("it's null"); } This does not work. I tried the same for the PopupWindow() method and the window is null every time, so a new window is opened on every click. I have checked both the EnableHtmlAccess and the IsPopupWindowAllowed properties, and they return true, as they should. Option 4 - Use Eval method to execute some custom javascript private const string javascript = @"var popup = window.open('', 'blah') ; if(popup.location != 'http://www.bing.com' ){ popup.location = 'http://www.bing.com'; } popup.focus();"; private void navigationButton_Click(object sender, RoutedEventArgs e) { HtmlPage.Window.Eval(javascript); } This does not work. I get a new window every time. option 5 - Use CreateInstance to run some custom javascript on the page private void navigationButton_Click(object sender, RoutedEventArgs e) { HtmlPage.Window.CreateInstance("thisIsPlainHell"); } and in my aspx I have function thisIsPlainHell() { var popup = window.open('http://www.bing.com', 'blah'); popup.focus(); } Guess what? This does work. The only thing is that the window behaves a little strange and I'm not sure why: I'm behind a proxy and in all other scenarios I'm being prompted for my password. In this case however I am not (and am thus not able to reach the external site - bing in this case). This is not really a huge issue atm, but I just don't understand what's goign on here. Whenever I type another url in the address bar of the popup window (eg www.google.com) and press enter, it opens up another window and prompts me for my proxy password. As a temporary solution option 5 could do, but I don't like the fact that Silverlight is not able to manage this. One of the main reasons my client has opted for Silverlight is to be protected against all the browser specific hacking that comes with javascript. Am I doing something wrong? I'm definitely no javascript expert, so I'm hoping it's something obvious I'm missing here. Cheers, Phil

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  • Animating the offset of the scrollView in a UICollectionView/UITableView causes prematurely disappearing cells

    - by radutzan
    We have a UICollectionView with a custom layout very similar to UITableView (it scrolls vertically). The UICollectionView displays only 3 cells simultaneously, with one of them being the currently active cell: [ 1 ] [*2*] [ 3 ] (The active cell here is #2.) The cells are roughly 280 points high, so only the active cell is fully visible on the screen. The user doesn't directly scroll the view to navigate, instead, she swipes the active cell horizontally to advance to the next cell. We then do some fancy animations and scroll the UICollectionView so the next cell is in the "active" position, thus making it the active one, moving the old one away and bringing up the next cell in the queue: [ 2 ] [*3*] [ 4 ] The problem here is setting the UICollectionView's offset. We currently set it in a UIView animation block (self.collectionView.contentOffset = targetOffset;) along with three other animating properties, which mostly works great, but causes the first cell (the previously active one, in the latter case, #2) to vanish as soon as the animation starts running, even before the delay interval completes. This is definitely not ideal. I've thought of some solutions, but can't figure out the best one: Absurdly enlarge the UICollectionView's frame to fit five cells instead of three, thus forcing it to keep the cells in memory even if they are offscreen. I've tried this and it works, but it sounds like an awfully dirty hack. Take a snapshot of the rendered content of the vanishing cell, put it in a UIImageView, add the UIImageView as a subview of the scrollView just before the cell goes away in the exact same position of the old cell, removing it once the animation ends. Sounds less sucky than the previous option (memory-wise, at least), but still kinda hacky. I also don't know the best way to accomplish this, please point me in the right direction. Switch to UIScrollView's setContentOffset:animated:. We actually used to have this, and it fixed the disappearing cell issue, but running this in parallel with the other UIView animations apparently competes for the attention of the main thread, thus creating a terribly choppy animation on single-core devices (iPhone 3GS/4). It also doesn't allow us to change the duration or easing of the animation, so it feels out of sync with the rest. Still an option if we can find a way to make it work in harmony with the UIView block animations. Switch to UICollectionView's scrollToItemAtIndexPath:atScrollPosition:animated:. Haven't tried this, but it has a big downside: it only takes 3 possible constants (that apply to this case, at least) for the target scroll position: UICollectionViewScrollPositionTop, UICollectionViewScrollPositionCenteredVertically and UICollectionViewScrollPositionBottom. The active cell could vary its height, but it always has to be 35 points from the top of the window, and these options don't provide enough control to accomplish the design. It could also potentially be just as problematic as 3.1. Still an option because there might be a way to go around the scroll position thing that I don't know of, and it might not have the same issue with the main thread, which seems unlikely. Any help will be greatly appreciated. Please ask if you need clarification. Thanks a lot!

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  • WPF ContextMenu with bound items: Items.Count == 0 in ContextMenuOpening event

    - by OregonGhost
    I have a ContextMenu with the ItemsSource bound to the selected item of a list view, like this: <ContextMenu ItemsSource="{Binding Path=PlacementTarget.SelectedItem, RelativeSource={RelativeSource Self}, Converter={StaticResource possibleConverter}}"/> The possibleConverter enumerates all possible values for a property of the the selected item, which are shown in the context menu. In the Opened event of the context menu, I select the current value like this: var cm = e.OriginalSource as ContextMenu; if (cm != null) { var lv = cm.PlacementTarget as ListView; var field = lv.SelectedItem as Field; var item = cm.ItemContainerGenerator.ContainerFromItem(cm.Items.OfType<object>().Where(o => o.ToString().Equals(field.StringValue)).FirstOrDefault()) as MenuItem; if (item != null) { item.IsChecked = true; } } Not particularly elegant, but it works. With the debugger I verified that the ContextMenu.Items.Count property has a non-zero value when expected (i.e. cm.Items.Count is non-zero in the if). So far, so good. There are, however, items in the listview where the context menu will have no items. In this case, an empty menu is shown. I tried to suppress this in the ContextMenuOpening event in the list view, like this: var lv = sender as ListView; if (lv != null) { var cm = lv.ContextMenu; if ((cm != null) && (cm.Items.Count > 0)) { // Here we want to check the current item, which is currently done in the Opened event. } else { e.Handled = true; } } Seems like it should work. However, cm.Items.Count is always zero. This is true even if ListView.SelectedItem did not change: For an item with menu entries, the menu is shown correctly after the first click, so the data binding has already happend. It is shown correct the second time as well, but in any case, Items.Count is zero in the ContextMenuOpening event. What am I missing? How can I suppress empty context menus? Why is the count zero in the ContextMenuOpening handler, which is in Windows Forms (ContextMenuStrip.Opening) the canonical point where to do these things? EDIT: Upon further investigating, it turns out that in the ContextMenuOpening handler, any binding to the listview fails, which is why ItemsSource is null. I tried to bind via ElementName, via a FindAncestor relationship, all to no avail. The PlacementTarget is null during that event. An ugly hack worked though: In the ContextMenuOpening event, I assign the list view to the ContextMenu.Tag property, while the ItemsSource binding now binds to Tag.SelectedItem. This updates the binding, so Items.Count is what it should be. It's still strange. How can you do meaningful things in ContextMenuOpening other than replacing the menu or something, if the binding fails because somehow the context menu is out of context during the event? Was it only tested with static pre-defined menu items?

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  • .NET SerialPort DataReceived event not firing

    - by Klay
    I have a WPF test app for evaluating event-based serial port communication (vs. polling the serial port). The problem is that the DataReceived event doesn't seem to be firing at all. I have a very basic WPF form with a TextBox for user input, a TextBlock for output, and a button to write the input to the serial port. Here's the code: public partial class Window1 : Window { SerialPort port; public Window1() { InitializeComponent(); port = new SerialPort("COM2", 9600, Parity.None, 8, StopBits.One); port.DataReceived += new SerialDataReceivedEventHandler(port_DataReceived); port.Open(); } void port_DataReceived(object sender, SerialDataReceivedEventArgs e) { Debug.Print("receiving!"); string data = port.ReadExisting(); Debug.Print(data); outputText.Text = data; } private void Button_Click(object sender, RoutedEventArgs e) { Debug.Print("sending: " + inputText.Text); port.WriteLine(inputText.Text); } } Now, here are the complicating factors: The laptop I'm working on has no serial ports, so I'm using a piece of software called Virtual Serial Port Emulator to setup a COM2. VSPE has worked admirably in the past, and it's not clear why it would only malfunction with .NET's SerialPort class, but I mention it just in case. When I hit the button on my form to send the data, my Hyperterminal window (connected on COM2) shows that the data is getting through. Yes, I disconnect Hyperterminal when I want to test my form's ability to read the port. I've tried opening the port before wiring up the event. No change. I've read through another post here where someone else is having a similar problem. None of that info has helped me in this case. EDIT: Here's the console version (modified from http://mark.michaelis.net/Blog/TheBasicsOfSystemIOPortsSerialPort.aspx): class Program { static SerialPort port; static void Main(string[] args) { port = new SerialPort("COM2", 9600, Parity.None, 8, StopBits.One); port.DataReceived += new SerialDataReceivedEventHandler(port_DataReceived); port.Open(); string text; do { text = Console.ReadLine(); port.Write(text + "\r\n"); } while (text.ToLower() != "q"); } public static void port_DataReceived(object sender, SerialDataReceivedEventArgs args) { string text = port.ReadExisting(); Console.WriteLine("received: " + text); } } This should eliminate any concern that it's a Threading issue (I think). This doesn't work either. Again, Hyperterminal reports the data sent through the port, but the console app doesn't seem to fire the DataReceived event. EDIT #2: I realized that I had two separate apps that should both send and receive from the serial port, so I decided to try running them simultaneously... If I type into the console app, the WPF app DataReceived event fires, with the expected threading error (which I know how to deal with). If I type into the WPF app, the console app DataReceived event fires, and it echoes the data. I'm guessing the issue is somewhere in my use of the VSPE software, which is set up to treat one serial port as both input and output. And through some weirdness of the SerialPort class, one instance of a serial port can't be both the sender and receiver. Anyway, I think it's solved.

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