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  • What's the easiest way to add Java servlets to a WAMP configured machine?

    - by Rhubarb
    I have WAMP installed on my local machine and am looking to serve up charts using jFree's Eastwood charting, which requires me to use servlets. So basically I will insert images with src tags that have URLs pointing to my servlet on the same machine. What's the easiest way to enable servlets on the same machine? Do I need to install a servlet server on a different port? Or is there a way to integrate it into WAMP?

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  • How to test whether a char is NOT in a string? (java, junit)

    - by JB
    As title says, im having trouble with my junit tests passing for checking if a character is not in a string and how to check if an empty string doesnt have a character. here is the method i have: public static boolean isThere(String s, char value){ for(int x = 0; x <= s.length(); x++){ if(s.charAt(x) == value){ return true; } else if(s.length() == 0){ return false; } } return false; And here is the junit test: public void testIsThere() { { String sVal = "Jeff George"; boolean hasA = StringMethods.isThere(sVal,'e'); assertTrue(hasA); boolean hasE = StringMethods.isThere(sVal, 'o'); assertTrue(hasE); boolean notIn = StringMethods.isThere(sVal,'b'); assertTrue(notIn); } { String sVal = ""; boolean nothingIn = StringMethods.isThere(sVal,'a'); assertFalse(nothingIn); boolean notIn = StringMethods.isThere(sVal,'b'); assertFalse(notIn); } } Thank you very much, appreciated

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  • How to map oracle timestamp to appropriate java type in hibernate?

    - by jschoen
    I am new to hibernate and I am stumped. In my database I have tables that have a columns of TIMESTAMP(6). I am using Netbeans 6.5.1 and when I generate the hibernate.reveng.xml, hbm.xml files, and pojo files it sets the columns to be of type Serializable. This is not what I expected, nor what I want them to be. I found this post on the hibernate forums saying to place: in the hibernate.reveng.xml file. In Netbeans you are not able to generate the mappings from this file (it creates a new one every time) and it does not seem to have the ability to re-generate them from the file either (at least according to this it is slated to be available in version 7). So I am trying to figure out what to do. I am more inclined to believe I am doing something wrong since I am new to this, and it seems like it would be a common problem for others. So what am I doing wrong? If I am not doing anything wrong, how do I work around this? I am using Netbeans 6.5, Oracle 10G, and I believe Hibernate 3 (it came with my netbeans). Edit: Meant to say I found this stackoverflow question, but it is really a different problem.

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  • How do I close a file after catching an IOException in java?

    - by DimDom
    All, I am trying to ensure that a file I have open with BufferedReader is closed when I catch an IOException, but it appears as if my BufferedReader object is out of scope in the catch block. public static ArrayList readFiletoArrayList(String fileName, ArrayList fileArrayList) { fileArrayList.removeAll(fileArrayList); try { //open the file for reading BufferedReader fileIn = new BufferedReader(new FileReader(fileName)); // add line by line to array list, until end of file is reached // when buffered reader returns null (todo). while(true){ fileArrayList.add(fileIn.readLine()); } }catch(IOException e){ fileArrayList.removeAll(fileArrayList); fileIn.close(); return fileArrayList; //returned empty. Dealt with in calling code. } } Netbeans complains that it "cannot find symbol fileIn" in the catch block, but I want to ensure that in the case of an IOException that the Reader gets closed. How can I do that without the ugliness of a second try/catch construct around the first? Any tips or pointers as to best practise in this situation is appreciated,

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  • Is there anything inherently wrong with long variable/method names in Java?

    - by Doug Smith
    I know this is probably is a question of personal opinion, but I want to know what's standard practice and what would be frowned upon. One of my profs in university always seems to make his variable and method names as short as possible (getAmt() instead of getAmount) for instance. I have no objection to this, but personally, I prefer to have mine a little longer if it adds descriptiveness so the person reading it won't have to check or refer to documentation. For instance, we made a method that given a list of players, returns the player who scored the most goals. I made the method getPlayerWithMostGoals(), is this wrong? I toiled over choosing a way to make it shorter for awhile, but then I thought "why?". It gets the point across clearly and Eclipse makes it easy to autocomplete it when I type. I'm just wondering if the short variable names are a piece of the past due to needing everything to be as small as possible to be efficient. Is this still a requirement?

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  • How do I create a right click context menu in Java Swing?

    - by Wayne
    I'm working on a school project and we want to implement a right click pop-up menu in the gui. Currently we are doing something like creating a JMenu on right click and setting its location to that of the mouse's position... This seems really ugly and is very buggy, is there any better way of doing this? I'm sure there must be.

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  • I'm new to Java most basic question about arrays!

    - by ambidextorous
    Hey I have not been able to find a proper answer on any forums about this but how exactly do I pass an array to a class? public class TestArray { String name; String[] array; public TestArray(String name, String[] anArray){ this.name = name; int len = anArray.length; this.array = new String[len]; for (int i = 0; i < len; i++){ this.array[i] = new String(anArray[i]); } } } public static void main(String[] args){ String[] anArray = new String[2]; anArray[0] = new String("Test"); anArray[1] = new String("Test2"); TestArray work = new TestArray("Jordan", anArray?); } }

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  • JAVA. Writing a matrix in a file using column information.

    - by Dmitry
    Hello, everybody! I have a file in which a matrix is stored. This file has a RandomAccessFile type. This matrix is stored by columns. I mean that in an i-th row of this matrix an i-th column (of a real matrix) is stored. There is an example: i-th row: 1 2 3 4 (in the file). That means that the real matrix has an i-th column: (1 2 3 4)(transpose). I need to save this matrix in natural way (by rows) in a new file, which I will then open with FileReader and display with TestArea. DO you know, how to do that? If so, please help =)

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  • Java- Copy file to either new file or existing file.

    - by jared
    Hi- I would like to write a function copy(File f1, File f2) f1 is always a file. f2 is either a file or a directory. If f2 is a directory I would like to copy f1 to this directory (the file name should stay the same). If f2 is a file I would like to copy the contents of f1 to the end of the file f2. So for example if F2 has the contents: 2222222222222 And F1 has the contents 1111111111111 And I do copy(f1,f2) then f2 should become 2222222222222 1111111111111 Thanks!

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  • How does a Java Arraylist contains() method evaluate objects?

    - by mvid
    Say i create one object and add it to my ArrayList. If I then create another object with exactly the same constructor input, will the contain() method evaluate the two objects to be the same? Assume the constructor doesn't do anything funny with the input, and the variables stored in both objects are identical. ArrayList<Thing> basket = new ArrayList<Thing>(); Thing thing = new Thing(100); basket.add(thing); Thing another = new Thing(100); basket.contains(another); // true or false?

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  • Can i create different observables and different corresponding observers in java?

    - by mithun1538
    Hello everyone, Currently, I have one observable and many observers. What i need is different observables, and depending on the observable, different observers. How do I achieve this? ( For understanding, assume I have different apples - say apple1 apple2... I have observer_1 observing apple1, observer_2 observing apple2, observer_3 observing apple 2 and so on..). I tried creating different objects of the Observable class, but since observers are observing the same class of observable, I don't know how to access a particular instance of the Observable. I have included the following servlet code that contains Observer and Observable classes: public class CustomerServlet extends HttpServlet { public String getNextMessage() { // Create a message sink to wait for a new message from the // message source. return new MessageSink().getNextMessage(source); } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); String recMSG = getNextMessage(); dout.writeObject(recMSG); dout.flush(); } public void broadcastMessage(String message) { // Send the message to all the HTTP-connected clients by giving the // message to the message source source.sendMessage(message); } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { ObjectInputStream din= new ObjectInputStream(request.getInputStream()); String message = (String)din.readObject(); ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); dout.writeObject("1"); dout.flush(); if (message != null) { broadcastMessage(message); } // Set the status code to indicate there will be no response response.setStatus(response.SC_NO_CONTENT); } catch (Exception e) { e.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; }// </editor-fold> MessageSource source = new MessageSource(); } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSink implements Observer { String message = null; // set by update() and read by getNextMessage() // Called by the message source when it gets a new message synchronized public void update(Observable o, Object arg) { // Get the new message message = (String)arg; // Wake up our waiting thread notify(); } // Gets the next message sent out from the message source synchronized public String getNextMessage(MessageSource source) { // Tell source we want to be told about new messages source.addObserver(this); // Wait until our update() method receives a message while (message == null) { try { wait(); } catch (Exception e) { System.out.println("Exception has occured! ERR ERR ERR"); } } // Tell source to stop telling us about new messages source.deleteObserver(this); // Now return the message we received // But first set the message instance variable to null // so update() and getNextMessage() can be called again. String messageCopy = message; message = null; return messageCopy; } }

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  • What is the best way to manage Time in a Java application?

    - by DanielHonig
    So I'm using hibernate and working with an application that manages time. What is the best way to deal with times in a 24 hour clock? I do not need to worry about TimeZone issues at the beginning of this application but it would be best to ensure that this functionality is built in at the beginning. I'm using hibernate as well, just as an fyi

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  • What is the explanation of this results in Java ?

    - by M.H
    I have the following code : public class Main { private int i = j; //1 private int j = 10; public static void main(String[] args) { System.out.println((new Main()).i); } } and there is a compiler error in line 1 because an illegal forward reference. But when I am trying the following code : public class Main { int i = getJ(); //1 int getJ(){ return j; } int j=10; public static void main(String[] args) { System.out.println(new Main().i); } } it works fine and the result is 0.Why there is no illegal forward reference in line 1 here?.The two codes look similar to me.

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  • Java long task - Did it stop writing to file?

    - by rockit
    I am writing a lot of data to a file, and while keeping my eye on the file it eventually stopped growing in size. Essentially my task is getting information from a database, and printing out all non-unique values in column A. Since there are many rows to the database table, and the database table is across my network, this is taking days to complete. Thus I'm concerned that since the file isn't growing, that it isn't actually writing to the file anymore. Which is odd, I have no "catch"'s in my code, so if there was a problem writing to file, wouldn't it have thrown an error?! Should I let the task complete (estimate 2-3 days from today), or is there something else that I don't know going on here making my application not write to the file?! my algorithm goes something like this Declare file Create new file Open file for writing get database connection get resultset from database for each row in the resultset - write column "A" to file - if row# % 100000 then write to screen "completed " + row# + " rows" when no more rows exist close file write to screen - "completed"

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  • Java: How to I change the color of a specific line or row of string in a Text area?

    - by Kevin
    Hi all, the one way I could change the color is by setForground(). However when there are multiple lines of code it makes everything green or black. Is there another method or any way of solving this problem? Thanks! int key = evt.getKeyCode(); if (key == KeyEvent.VK_ENTER) { String tb1EnterdValue = tb1.getText().toString(); if((tb1EnterdValue.equals("yes")) ) { TextArea1.setForeground(Color.green); else { TextArea1.setForeground(Color.lightGray); } this.TextArea1.append(">"+tb1EnterdValue+newline); this.tb1.setText("");

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