Search Results

Search found 16467 results on 659 pages for 'request filtering'.

Page 462/659 | < Previous Page | 458 459 460 461 462 463 464 465 466 467 468 469  | Next Page >

  • Facebook links to my site resolve as 403 forbidden

    - by filip
    Hi I'm experiencing a super weird problem. Whenever I post links to my website on Facebook, they come up as Forbidden. The site itself works great and I have no seen this when linking on other sites. Could this be a server misconfiguration? Any thoughts on where to look? here's some Info: I have a dedicated server running WHM 11.25.0 i have 2 sites hosted here using cPanel 11.25.0 the error msg: Forbidden You don't have permission to access / on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request. Apache/2.2.14 (Unix) mod_ssl/2.2.14 OpenSSL/0.9.8i DAV/2 mod_auth_passthrough/2.1 mod_bwlimited/1.4 FrontPage/5.0.2.2635 Server at ---- Port 80

    Read the article

  • Amazon Product Availability

    - by user201140
    Many products on amazon are unavailable but a date is given for when they'll be in stock. I've used AWS and got an XML reply but I can't find the date information anywhere. Is it possible to get this information? Thanks. NOTE: This is what i've got as a request, what should I alter? http://ecs.amazonaws.com/onca/xml?AWSAccessKeyId=MYID&AssociateTag=MYTAG&ItemId=THEITEMID&Operation=ItemLookup&ResponseGroup=Large&ReviewSort=-HelpfulVotes&Service=AWSECommerceService&Signature=MYSIGNATURE&Timestamp=2009-12-04T17%3A35%3A43Z&Version=2009-06-01

    Read the article

  • ASP.Net Cross Page Posting

    - by John
    Currently I have two pages: The first page contains an input form, and the 2nd page generates an excel document. The input form's button posts to this 2nd page. What I'd like to do is add a second button which also posts to the 2nd page; however, I'll need requests created from this new button to act differently, which brings me to my question: Is there a way I can tell, from the 2nd page, which button was pressed to submit the request? The main reason I'm asking is I'd like to re-use the 2nd page's logic in parsing the information from the first page if possible; I'd rather not have to copy it to a new page and have the new button post to that. Thanks!

    Read the article

  • How to easily pass a very long string to a worker process under Windows?

    - by sharptooth
    My native C++ Win32 program spawns a worker process and needs to pass a huge configuration string to it. Currently it just passes the string as a command line to CreateProcess(). The problem is the string is getting longer and now it doesn't fit into the 32K characters limitation imposed by Windows. Of course I could do something like complicating the worker process start - I use the RPC server in it anyway and I could introduce an RPC request for passing the configuration string, but this will require a lot of changes and make the solution not so reliable. Saving the data into a file for passing is also not very elegant - the file could be left on the filesystem and become garbage. What other simple ways are there for passing long strings to a worker process started by my program on Windows?

    Read the article

  • Ruby Rack: startup and teardown operations (Tokyo Cabinet connection)

    - by clint.tseng
    I have built a pretty simple REST service in Sinatra, on Rack. It's backed by 3 Tokyo Cabinet/Table datastores, which have connections that need to be opened and closed. I have two model classes written in straight Ruby that currently simply connect, get or put what they need, and then disconnect. Obviously, this isn't going to work long-term. I also have some Rack middleware like Warden that rely on these model classes. What's the best way to manage opening and closing the connections? Rack doesn't provide startup/shutdown hooks as I'm aware. I thought about inserting a piece of middleware that provides reference to the TC/TT object in env, but then I'd have to pipe that through Sinatra to the models, which doesn't seem efficient either; and that would only get be a per-request connection to TC. I'd imagine that per-server-instance-lifecycle would be a more appropriate lifespan. Thanks!

    Read the article

  • OAuth java implementation, oauth_callback missing

    - by l245c4l
    Hey, My problem is I get error while trying to get request token from Yahoo. The error says Im missing oauth_callback parameter and yes I miss it because I dont need it. Ive read I need to set it to "oob" value if I dont want to use it(desktop app). And I did that but to no avail. If I set it to null the same happens. Im using OAuth for java: http://oauth.googlecode.com/svn/code/java/core/ OAuthServiceProvider serviceProvider = new OAuthServiceProvider("https://api.login.yahoo.com/oauth/v2/get_request_token", "https://api.login.yahoo.com/oauth/v2/request_auth", "https://api.login.yahoo.com/oauth/v2/get_token"); OAuthConsumer consumer = new OAuthConsumer("oob", consumerKey, consumerSecret, serviceProvider); OAuthAccessor accessor = new OAuthAccessor(consumer); OAuthClient client = new OAuthClient(new HttpClient4()); OAuthMessage response = client.getRequestTokenResponse(accessor, OAuthMessage.POST, null); System.out.println(response.getBodyAsStream());

    Read the article

  • Android: Displaying Video on VideoView

    - by AndroidDev93
    I'm trying to display a video in my sdcard on the video view. Here is my code: String name = Environment.getExternalStorageDirectory() + "/test.mp4"; final VideoView videoView = (VideoView)findViewById(R.id.videoView1); videoView.setOnPreparedListener(new MediaPlayer.OnPreparedListener() { public void onPrepared(MediaPlayer arg0) { videoView.start(); } }); videoView.setVideoPath(name); The file I am trying to open is called test.mp4 and its located within the sdcard folder. I get an error saying the application has unfortunately stopped. I would appreciate it if someone could help me. Thanks. EDIT : I used the debugger and found out that I get an InvocationTargetException. The detailed message says that : Failure delivering result ResultInfo{who=null, request=1001, result=-1, data=Intent { dat=file:///mnt/sdcard/test.mp4 }} to activity : java.lang.NullPointerException EDIT : I looked at the logcat again and it seems to give the error at videoView.setOnPreparedListener(new MediaPlayer.OnPreparedListener() { I'm guessing either videoView or MediaPlayer is null.

    Read the article

  • How to limit a google calendar xml / rss feed by date range (not working!!)

    - by Phil
    For the life of me I cannot get my google calendar xml feed to only display events within a certain date range. I know that start-min and start-max are supposed to limit the output (according to these posts: (links to posts deleted because I am a newbie and can only post one hyperlink argh) BUT I CAN'T GET IT TO WORK. It keeps showing lot of things outside the range. I created a sample calendar and made it public. It is some events the first week of april. Can anyone show me how to construct a request that only returns those three events from the first week in april? I'll GLADLY and GRATEFULLY paypal $10 to anyone who helps me break through on this. Here is the calendar's public feed: http://www.google.com/calendar/feeds/66m31c36sj9u5k8kekrvt2lpr8%40group.calendar.google.com/public/basic

    Read the article

  • UpdatePanel codebehind error "Page cannot be null"

    - by Nandoviski
    Hi guys, i'm trying create a updatepanel for my controls in a codebehind. But i get the follow error: Page cannot be null. Please ensure that this operation is being performed in the context of an ASP.NET request. My code: List<Control> novoControl = new List<Control>(); control.Controls.ForEach<Control>(c => novoControl.Add(c)); control.Controls.Clear(); // This control is a contentplaceholder of my masterpage control.Controls.Add(IcpScriptManager); //Add ScriptManager in the page foreach (Control item in novoControl) { UpdatePanel up = new UpdatePanel(); up.ID = "up_" + item.ID; up.ChildrenAsTriggers = true; up.UpdateMode = UpdatePanelUpdateMode.Conditional; up.ContentTemplateContainer.Controls.Add(item); control.Controls.Add(up); //ERROR happens here } Any ideia?? Thanks, Fernando

    Read the article

  • A web framework where AJAX was not an after thought

    - by Pirate for Profit
    AJAX is a pain in the ass because it essentially means you'll have to write two sets of similarish code: one for browsers with JavaScript enabled and those without. Not only this, but you have to connect JavaScript events to hook into your models and display the results. And if all that weren't bad enough, you need to send an address change with the request, otherwise the user won't be able to "click back" correctly (if confused look at what happens to the address bar when you click links in GMail). We're searching for something that had the foresight and design goals with all these concerns in mind. Performance and security are also obvious major concerns. We love config-based systems as well, where you don't have to write a lot of code you just drop it into an easily read config format. It's like asking for the holy grail right?

    Read the article

  • Browser back button creating problem

    - by user175084
    I have a dynamically generated gridview on page with sorting provided in the code behind also. Now i move from page A to page B using a link, this also works fine. But when i press the browser back button and come back to my page A and again try to sort... page A throws an exception... is there a way to program this back button like we program a button normally.. Thanks ` Cannot find column machinename. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.IndexOutOfRangeException: Cannot find column machinename. Source Error: Line 519: Line 520: //Sort the data. Line 521: dt.DefaultView.Sort = e.SortExpression + " " + GetSortDirection(e.SortExpression); Line 522: GridView1.DataSource = Session["TaskTable"]; Line 523: GridView1.DataBind();`

    Read the article

  • Tomcat upgradation

    - by cedar715
    We are planning to upgrade our Tomcat from 4.1.31. Our's is an Axis 1.4 application where we have our web services. Request you to suggest the latest stable version of Tomcat 5 or Tomcat 6 suitable for our application. And the things to consider while upgrading. Will the existing 1.4 Java code base works smoothly on Tomcat 5 or 6? And going further we may write the code in JDK 1.5 as well. So, having Java 1.4 code and Java 1.5 code together, will create any problems? Kindly suggest. Please share your upgradation experiences. Thank You :)

    Read the article

  • ASMX Still slow after 'Generate serialization assembly'

    - by Buzzer
    This question is related to: http://stackoverflow.com/questions/784918/asmx-web-service-slow-first-request. I inherited a proxy to a legacy ASMX Service. Basically as the post above states, the first call performance is literally 10 times slower than the subsequent calls. I went ahead and turned on ‘Generate serialization assembly' on the project that contains the proxy. The 'serializers' assembly is actually generated. However, I haven't seen any performance increase at all. Do I need to do anything else other than make sure the 'serializers' assembly is in the client's bin directory? Do I have to 'link' the proxy to the 'serializers' assembly during proxy generation (wsdl.exe)? I guess I'm stuck at this point. J Saunders where u at? :)

    Read the article

  • Fragment caching

    - by red5
    I would like to fragment cache part of a page. On the view I have <% cache("saved_area") do %> . <% end -%> In the controller: def index read_fragment("saved_area") end In config/production: config.cache_store = :file_store, File.join(RAILS_ROOT, 'tmp', 'cache') The file was created in the tmp/cache directory. But I am not sure if the cache is being used in the request, since I presume there should be a line in the log stating that the cache is being used (and there is not).

    Read the article

  • Cannot execute a program. The command being executed "dqiitg0c.cmdline"

    - by Laxman
    i have used impersonation in this application. whenever this error occurs i required to restart the IIS.. please guide me to solve this issue. Error: Cannot execute a program. The command being executed was "C:\Windows\Microsoft.NET\Framework64\v2.0.50727\csc.exe" /noconfig /fullpaths @"C:\Windows\Microsoft.NET\Framework64\v2.0.50727\Temporary ASP.NET Files\root\c825d188\1fae8a71\dqiitg0c.cmdline". Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Runtime.InteropServices.ExternalException: Cannot execute a program. The command being executed was "C:\Windows\Microsoft.NET\Framework64\v2.0.50727\csc.exe" /noconfig /fullpaths @"C:\Windows\Microsoft.NET\Framework64\v2.0.50727\Temporary ASP.NET Files\root\c825d188\1fae8a71\dqiitg0c.cmdline".

    Read the article

  • REST API unauthenticated requests exception based on the User-Agent

    - by Shay Tsadok
    Hi All, I am developing a REST API that supports two kinds of authentication protocols: login form authentication - for browser based clients. Simple Basic authentication - for non-browser clients. I developed a flow in which unauthenticated requests redirected to the "login form", the problem is that this is an undesired behavior for non-borwser clients! I thought to solve it by decide according to the "User-Agent" what to do: browsers will be redirected to the "login form" and non-browser clients will get the standard 401:Basic Authentication. A. What do you think about this solution? B. Is there a standard way in Java to check if the request came from browser, or do i need to develop this kind of mechanism by my own? Thanks in advance!

    Read the article

  • Accessing a module's action rendered output

    - by Flavius
    Hi. I'm writing an "Account" module which should take care of everything about accounts: registration, login/logout, user administration, password recovery, account activation, etc. So I thought it would be best to reuse whatever the module's DefaultController::actionRegister() generates to show on the main page. So my question is: how to create a new "sub request" (similar to CController::forward()) from any controller (either SiteController, read: from views/layouts/main.php, or another controller, eventually of another submodule) to a given module/controller/action? I've tried with $this-forward() from within my application layout without success: it shows a blank page, no error whatsoever. Thanks

    Read the article

  • Upload and parse csv file with "universal newline" in python on Google App Engine

    - by greg
    Hi, I'm uploading a csv/tsv file from a form in GAE, and I try to parse the file with python csv module. Like describe here, uploaded files in GAE are strings. So I treat my uploaded string a file-like object : file = self.request.get('catalog') catalog = csv.reader(StringIO.StringIO(file),dialect=csv.excel_tab) But new lines in my files are not necessarily '\n' (thanks to excel..), and it generated an error : Error: new-line character seen in unquoted field - do you need to open the file in universal-newline mode? Does anyone know how to use StringIO.StringIO to treat strings like files open in universal-newline?

    Read the article

  • Is it inmoral to put a captcha on a login form?

    - by azkotoki
    In a recent project I put a captcha test on a login form, in order to stop possible brute force attacks. The inmediate reaction of other coworkers was a request to remove it, saying that it was innapropiate for that purpose, and that it was quite exotic to see a captcha in that place. I've seen captcha images on signup, contact, password recovery forms, etc. So I personally don't see innapropiate to put a captcha also on a place like that. Well, it obviously burns down usability a little bit, but it's a matter of time and getting used to it. With the lack of a captcha test, one would have to put some sort of blacklist / account locking mechanism, which also has some drawbacks. Is it a good choice for you? Am I getting somewhat captcha-aholic and need some sort of group therapy? Thanks in advance.

    Read the article

  • Load first page on splashscreen using phonegap on android

    - by Syg
    Hi i'm using phonegap in conjunction with Jquery mobile. I'm trying to immediately fetch the main page, while showing the user a splashscreen. In PhoneGap for Android i'm using this super.setIntegerProperty("splashscreen", R.drawable.splash); super.loadUrl("file:///android_asset/www/index.html", 2000); While this loads the splash, it also delays the loading of index.html. It it possible to start fetching it right away? Also, if not with phonegap, has anybody done this using JQM instead of phonegap? UPDATE: After using it with a slower loading first page (doing a json request) it kinda looks like the splash screens shows for a longer period of time, so this appears to be the default behavior

    Read the article

  • Twitter oauth_callback parameter being ignored!

    - by Astrofaes
    Hi guys, I'm trying to get Twitter authentication working on my ASP.NET site. When you create the app on the Twitter website, you have to specify a callback URL, which for sake of argument, I have set to http://mydomain.com I've read the oAuth 1.0a spec, and to override this callback URL with your own custom one you have to send the oauth_callback parameter in the request_token phase (url-encoded of course). So my request URL looks like this: http://twitter.com/oauth/request_token?oauth_callback_url=http%3A%2F%2Fmydomain.com%2Ftwittercallback Supposedly, if all goes to plan, in your response data, you are supposed to receive a new parameter of oauth_callback_confirmed=true in addition to your token and token secret parameters. However, my response comes through as: oauth_token=MYTOKEN&oauth_token_secret=MYTOKENSECRET I know I haven't given you guys the greatest amount to go on, but I'm at my wits end as to why I am not receiving the oauth_callback_confirmed parameter. Without this, my application keeps defaulting back to the callback URL hard-coded on the Twitter website. Please if anyone could help me out, I will be eternally grateful! Thanks, A.

    Read the article

  • Google app engine - what is the lifecycle of PersistenceManager?

    - by Domchi
    What is the preferred way of using GAE datastore PersistenceManager for web app? GAE instructions are a bit ambiguous on the matter. Do I instantiate PersistenceManagerFactory for each RPC call, or do I use only one factory for all requests? Do I call PMF.get().getPersistenceManager(), or do I call PMF.get().getPersistenceManagerProxy()? Do I close PM after each RPC call, or do I leave it open? What are you guys doing? Furthermore, I'm not certain how GAE handles 30-second-per-request limit. Is it even possible to reference the same PM between requests?

    Read the article

  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

    Read the article

  • System.Web.AspNetHostingPermission Exception on New Deployment

    - by Jason N. Gaylord
    I have a friend that is moving a web application from one server over to another. The new server has the same settings as the first server, however, he's running into a Security issue. Here's the error details: Request for the permission of type 'System.Web.AspNetHostingPermission, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed. The Event Viewer does not point to anything specific in the web.config file or anything. The web applicaiton is on the C: drive. This is a Windows Server 2008 R2 x64 server with a brand new IIS 7 installation. IIS is set in classic mode for this app pool.

    Read the article

  • How does refer(r)er work technically?

    - by NoozNooz42
    I don't understand: how are webserver and trackers like Google Analytics able to track referrals? Is it part of HTTP? Is it some (un)specified behavior of the browsers? Apparently every time you click on a link on a web page, the original web page is passed along the request. What is the exact mechanism behind that? Is it specified by some spec? I've read a few docs and I've played with my own Tomcat server and my own Google Analytics account, but I don't understand how the "magic" happens. Bonus (totally related) question: if, on my own website (served by Tomcat), I put a link to another site, does the other site see my website as the "referrer" without me doing anything special in Tomcat?

    Read the article

< Previous Page | 458 459 460 461 462 463 464 465 466 467 468 469  | Next Page >