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  • SQL Join to only the maximum row puzzle

    - by Billy ONeal
    Given the following example data: Users +--------------------------------------------------+ | ID | First Name | Last Name | Network Identifier | +--------------------------------------------------+ | 1 | Billy | O'Neal | bro4 | +----+------------+-----------+--------------------+ | 2 | John | Skeet | jsk1 | +----+------------+-----------+--------------------+ Hardware +----+-------------------+---------------+ | ID | Hardware Name | Serial Number | +----+-------------------+---------------+ | 1 | Latitude E6500 | 5555555 | +----+-------------------+---------------+ | 2 | Latitude E6200 | 2222222 | +----+-------------------+---------------+ HardwareAssignments +---------+-------------+-------------+ | User ID | Hardware ID | Assigned On | +---------+-------------+-------------+ | 1 | 1 | April 1 | +---------+-------------+-------------+ | 1 | 2 | April 10 | +---------+-------------+-------------+ | 2 | 2 | April 1 | +---------+-------------+-------------+ | 2 | 1 | April 11 | +---------+-------------+-------------+ I'd like to write a SQL query which would give the following result: +--------------------+------------+-----------+----------------+---------------+-------------+ | Network Identifier | First Name | Last Name | Hardware Name | Serial Number | Assigned On | +--------------------+------------+-----------+----------------+---------------+-------------+ | bro4 | Billy | O'Neal | Latitude E6200 | 2222222 | April 10 | +--------------------+------------+-----------+----------------+---------------+-------------+ | jsk1 | John | Skeet | Latitude E6500 | 5555555 | April 11 | +--------------------+------------+-----------+----------------+---------------+-------------+ My trouble is that the maximum "Assigned On" date for each user needs to be selected for each individual user and used for the actual join ... Is there a clever way accomplish this in SQL?

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  • Slug ID's with the same name?

    - by James Jeffery
    I want to create slug URL's from a users title in my system. If a user types "The best way's to get slim; period!", then I want the slug to be "the-best-ways-to-get-slim-period". Also, if someone has already created a page with that title I want the slug to be "the-best-ways-to-get-slim-period-1". My question is how can I check the database before a record is created? Ok, obviously I am going to have to perform a check in the database, and then a write. That's 2 queries. Is this the normal way to do it? Also, are there any conventional regular expressions for filtering non alpha/number characters and replacing spaces with hyphens? Any help is much appreciated. Thanks.

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  • Retrieve object from jquery in php script

    - by majc
    I'm trying to rebuild an object encoded with Json but i'm not getting any value. JQuery: $.post("views/insert_tasks.php",{ clickedRows : clickrows , <?php echo "tasks:'" . json_encode($tasks) . "'"; ?> }, function(data) { }); this is the PHPcode to retrieve the object: $tasks = json_decode(stripslashes($_POST['tasks']), true); $tasks is empty after execute the code above. This is what I'm getting with the $_POST['tasks']: [{"task_id":"1","description":"<p>Fazer heroi</p>","createdat":"Saturday 22nd of May 2010 11:37:37 PM","createdby":"Miguel Cardoso","max_requests":"2","max_duration":"5","job_id":"Concept Artist"},{"task_id":"2","description":"<p>teste2</p>","createdat":"Sunday 23rd of May 2010 11:23:55 AM","createdby":"Miguel Cardoso","max_requests":"2","max_duration":"5","job_id":"3D Modeller"},{"task_id":"3","description":"<p>teste3</p>","createdat":"Sunday 23rd of May 2010 11:45:39 AM","createdby":"Miguel Cardoso","max_requests":"1","max_duration":"10","job_id":"Writer"}] What I'm doing wrong?

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  • Multi-Page invoice printing on one page

    - by ryan
    I have an invoice that contains over 100 lines of product that I am trying to print. This single invoice should take over 3 pages, but when printed, the content flows off the footer and the next page is the following invoice. I am using divs instead of tables, and I can't understand why the long invoices will not print on multiple pages. Any ideas?

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  • php cli script hangs with no messages

    - by julio
    Hi-- I've written a PHP script that runs via SSH and nohup, meant to process records from a database and do stuff with them (eg. process some images, update some rows). It works fine with small loads, up to maybe 10k records. I have some larger datasets that process around 40k records (not a lot, I realize, but it adds up to a lot of work when each record requires the download and processing of up to 50 images). The larger datasets can take days to process. Sometimes I'll see in my debug logs memory errors, which are clear enough-- but sometimes the script just appears to "die" or go zombie on me. My tail of the debug log just stops, with no error messages, the tail of the nohup log ends with no error, and the process is still showing in a ps list, looking like this-- 26075 pts/0 S 745:01 /usr/bin/php ./import.php but no work is getting done. Can anyone give me some ideas on why a process would just quit? The obvious things (like a php script timeout and memory issues) are not a factor, as far as I can tell. Thanks for any tips PS-- this is hosted on a godaddy VDS (not my choice). I am sort of suspecting that godaddy has some kind of limits that might kick in on me despite what overrides I put in the code (such as set_time_limit(0);).

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  • DataMapper is only returning the last part of this query

    - by Josh K
    So I'm using the following: $r = new Record(); $r->select('ip, count(*) as ipcount'); $r->group_by('ip'); $r->order_by('ipcount', 'desc'); $r->limit(5); $r->get(); foreach($r->all as $record) { echo($record->ip." "); echo($record->ipcount." <br />"); } And I only get the last (fifth) record echo'ed out and no ipcount echoed. Is there a different way to go around this? I'm working on learning DataMapper (hence the questions) and need to figure some of this out. I haven't quite wrapped my head around the whole ORM thing.

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  • SQL: Daily Average of Logins Per Hour

    - by jerrygarciuh
    This query is producing counts of logins per hour: SELECT DATEADD(hour, DATEDIFF(hour, 0, EVENT_DATETIME), 0), COUNT(*) FROM EVENTS_ALL_RPT_V1 WHERE EVENT_NAME = 'Login' AND EVENT_DATETIME >= CONVERT(DATETIME, '2010-03-17 00:00:00', 120) AND EVENT_DATETIME <= CONVERT(DATETIME, '2010-03-24 00:00:00', 120) GROUP BY DATEADD(hour, DATEDIFF(hour, 0, EVENT_DATETIME), 0) ORDER BY DATEADD(hour, DATEDIFF(hour, 0, EVENT_DATETIME), 0) ...with lots of results like this: Datetime COUNT(*) ---------------------------------- 2010-03-17 12:00:00.000 135 2010-03-17 13:00:00.000 129 2010-03-17 14:00:00.000 147 What I need to figure out is how to query the average logins per hour for a given day. Any help?

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  • Locking a table for getting MAX in LINQ

    - by Hossein Margani
    Hi Every one! I have a query in LINQ, I want to get MAX of Code of my table and increase it and insert new record with new Code. just like the IDENTITY feature of SQL Server, but here my Code column is char(5) where can be alphabets and numeric. My problem is when inserting a new row, two concurrent processes get max and insert an equal Code to the record. my command is: var maxCode = db.Customers.Select(c=>c.Code).Max(); var anotherCustomer = db.Customers.Where(...).SingleOrDefault(); anotherCustomer.Code = GenerateNextCode(maxCode); db.SubmitChanges(); I ran this command cross 1000 threads and each updating 200 customers, and used a Transaction with IsolationLevel.Serializable, after two or three execution an error occured: using (var db = new DBModelDataContext()) { DbTransaction tran = null; try { db.Connection.Open(); tran = db.Connection.BeginTransaction(IsolationLevel.Serializable); db.Transaction = tran; . . . . tran.Commit(); } catch { tran.Rollback(); } finally { db.Connection.Close(); } } error: Transaction (Process ID 60) was deadlocked on lock resources with another process and has been chosen as the deadlock victim. Rerun the transaction. other IsolationLevels generates this error: Row not found or changed. Please help me, thank you.

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  • Query for props list with or without values

    - by vitto
    Hi, I'm trying to make a SELECT on three relational tables like these ones: table_materials -> material_id - material_name table_props -> prop_id - prop_name table_materials_props - row_id -> material_id -> prop_id - prop_value On my page, I'd like to get a result like this one but i have some problem with the query: material prop A prop B prop C prop D prop E wood 350 NULL NULL 84 16 iron NULL 17 NULL NULL 201 copper 548 285 99 NULL NULL so the query should return something like: material prop_name prop_value wood prop A 350 wood prop B NULL wood prop C NULL wood prop D 84 wood prop E 16 // and go on with others rows i thought to use something like: SELECT * FROM table_materials AS m INNER JOIN table_materials_props AS mp ON m.material_id = mp.material_id INNER JOIN table_materials_props AS p ON mp.prop_id = p.prop_id ORDER BY p.prop_name the problem is the query doesn't return the NULL values, and I need the same prop order for all the materials regardless of prop values are NULL or not I hope this example is clear!

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  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

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  • Configuration "diff" across Oracle WebCenter Sites instances

    - by Mark Fincham-Oracle
    Problem Statement With many Oracle WebCenter Sites environments - how do you know if the various configuration assets and settings are in sync across all of those environments? Background At Oracle we typically have a "W" shaped set of environments.  For the "Production" environments we typically have a disaster recovery clone as well and sometimes additional QA environments alongside the production management environment. In the case of www.java.com we have 10 different environments. All configuration assets/settings (CSElements, Templates, Start Menus etc..) start life on the Development Management environment and are then published downstream to other environments as part of the software development lifecycle. Ensuring that each of these 10 environments has the same set of Templates, CSElements, StartMenus, TreeTabs etc.. is impossible to do efficiently without automation. Solution Summary  The solution comprises of two components. A JSON data feed from each environment. A simple HTML page that consumes these JSON data feeds.  Data Feed: Create a JSON WebService on each environment. The WebService is no more than a SiteEntry + CSElement. The CSElement queries various DB tables to obtain details of the assets/settings returning this data in a JSON feed. Report: Create a simple HTML page that uses JQuery to fetch the JSON feed from each environment and display the results in a table. Since all assets (CSElements, Templates etc..) are published between environments they will have the same last modified date. If the last modified date of an asset is different in the JSON feed or is mising from an environment entirely then highlight that in the report table. Example Solution Details Step 1: Create a Site Entry + CSElement that outputs JSON Site Entry & CSElement Setup  The SiteEntry should be uncached so that the most recent configuration information is returned at all times. In the CSElement set the contenttype accordingly: Step 2: Write the CSElement Logic The basic logic, that we repeat for each asset or setting that we are interested in, is to query the DB using <ics:sql> and then loop over the resultset with <ics:listloop>. For example: <ics:sql sql="SELECT name,updateddate FROM Template WHERE status != 'VO'" listname="TemplateList" table="Template" /> "templates": [ <ics:listloop listname="TemplateList"> {"name":"<ics:listget listname="TemplateList"  fieldname="name"/>", "modified":"<ics:listget listname="TemplateList"  fieldname="updateddate"/>"}, </ics:listloop> ], A comprehensive list of SQL queries to fetch each configuration asset/settings can be seen in the appendix at the end of this article. For the generation of the JSON data structure you could use Jettison (the library ships with the 11.1.1.8 version of the product), native Java 7 capabilities or (as the above example demonstrates) you could roll-your-own JSON output but that is not advised. Step 3: Create an HTML Report The JavaScript logic looks something like this.. 1) Create a list of JSON feeds to fetch: ENVS['dev-mgmngt'] = 'http://dev-mngmnt.example.com/sites/ContentServer?d=&pagename=settings.json'; ENVS['dev-dlvry'] = 'http://dev-dlvry.example.com/sites/ContentServer?d=&pagename=settings.json';  ENVS['test-mngmnt'] = 'http://test-mngmnt.example.com/sites/ContentServer?d=&pagename=settings.json';  ENVS['test-dlvry'] = 'http://test-dlvry.example.com/sites/ContentServer?d=&pagename=settings.json';   2) Create a function to get the JSON feeds: function getDataForEnvironment(url){ return $.ajax({ type: 'GET', url: url, dataType: 'jsonp', beforeSend: function (jqXHR, settings){ jqXHR.originalEnv = env; jqXHR.originalUrl = url; }, success: function(json, status, jqXHR) { console.log('....success fetching: ' + jqXHR.originalUrl); // store the returned data in ALLDATA ALLDATA[jqXHR.originalEnv] = json; }, error: function(jqXHR, status, e) { console.log('....ERROR: Failed to get data from [' + url + '] ' + status + ' ' + e); } }); } 3) Fetch each JSON feed: for (var env in ENVS) { console.log('Fetching data for env [' + env +'].'); var promisedData = getDataForEnvironment(ENVS[env]); promisedData.success(function (data) {}); }  4) For each configuration asset or setting create a table in the report For example, CSElements: 1) Get a list of unique CSElement names from all of the returned JSON data. 2) For each unique CSElement name, create a row in the table  3) Select 1 environment to represent the master or ideal state (e.g. "Everything should be like Production Delivery") 4) For each environment, compare the last modified date of this envs CSElement to the master. Highlight any differences in last modified date or missing CSElements. 5) Repeat...    Appendix This section contains various SQL statements that can be used to retrieve configuration settings from the DB.  Templates  <ics:sql sql="SELECT name,updateddate FROM Template WHERE status != 'VO'" listname="TemplateList" table="Template" /> CSElements <ics:sql sql="SELECT name,updateddate FROM CSElement WHERE status != 'VO'" listname="CSEList" table="CSElement" /> Start Menus <ics:sql sql="select sm.id, sm.cs_name, sm.cs_description, sm.cs_assettype, sm.cs_assetsubtype, sm.cs_itemtype, smr.cs_rolename, p.name from StartMenu sm, StartMenu_Sites sms, StartMenu_Roles smr, Publication p where sm.id=sms.ownerid and sm.id=smr.cs_ownerid and sms.pubid=p.id order by sm.id" listname="startList" table="Publication,StartMenu,StartMenu_Roles,StartMenu_Sites"/>  Publishing Configurations <ics:sql sql="select id, name, description, type, dest, factors from PubTarget" listname="pubTargetList" table="PubTarget" /> Tree Tabs <ics:sql sql="select tt.id, tt.title, tt.tooltip, p.name as pubname, ttr.cs_rolename, ttsect.name as sectname from TreeTabs tt, TreeTabs_Roles ttr, TreeTabs_Sect ttsect,TreeTabs_Sites ttsites LEFT JOIN Publication p  on p.id=ttsites.pubid where p.id is not null and tt.id=ttsites.ownerid and ttsites.pubid=p.id and tt.id=ttr.cs_ownerid and tt.id=ttsect.ownerid order by tt.id" listname="treeTabList" table="TreeTabs,TreeTabs_Roles,TreeTabs_Sect,TreeTabs_Sites,Publication" />  Filters <ics:sql sql="select name,description,classname from Filters" listname="filtersList" table="Filters" /> Attribute Types <ics:sql sql="select id,valuetype,name,updateddate from AttrTypes where status != 'VO'" listname="AttrList" table="AttrTypes" /> WebReference Patterns <ics:sql sql="select id,webroot,pattern,assettype,name,params,publication from WebReferencesPatterns" listname="WebRefList" table="WebReferencesPatterns" /> Device Groups <ics:sql sql="select id,devicegroupsuffix,updateddate,name from DeviceGroup" listname="DeviceList" table="DeviceGroup" /> Site Entries <ics:sql sql="select se.id,se.name,se.pagename,se.cselement_id,se.updateddate,cse.rootelement from SiteEntry se LEFT JOIN CSElement cse on cse.id = se.cselement_id where se.status != 'VO'" listname="SiteList" table="SiteEntry,CSElement" /> Webroots <ics:sql sql="select id,name,rooturl,updatedby,updateddate from WebRoot" listname="webrootList" table="WebRoot" /> Page Definitions <ics:sql sql="select pd.id, pd.name, pd.updatedby, pd.updateddate, pd.description, pdt.attributeid, pa.name as nameattr, pdt.requiredflag, pdt.ordinal from PageDefinition pd, PageDefinition_TAttr pdt, PageAttribute pa where pd.status != 'VO' and pa.id=pdt.attributeid and pdt.ownerid=pd.id order by pd.id,pdt.ordinal" listname="pageDefList" table="PageDefinition,PageAttribute,PageDefinition_TAttr" /> FW_Application <ics:sql sql="select id,name,updateddate from FW_Application where status != 'VO'" listname="FWList" table="FW_Application" /> Custom Elements <ics:sql sql="select elementname from ElementCatalog where elementname like 'CustomElements%'" listname="elementList" table="ElementCatalog" />

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  • recursive function to get all the child categories

    - by user253530
    Here is what I'm trying to do: - i need a function that when passed as an argument an ID (for a category of things) will provide all the subcategories and the sub-sub categories and sub-sub-sub..etc. - i was thinking to use a recursive function since i don't know the number of subcategories their sub-subcategories and so on so here is what i've tried to do so far function categoryChild($id) { $s = "SELECT * FROM PLD_CATEGORY WHERE PARENT_ID = $id"; $r = mysql_query($s); if(mysql_num_rows($r) > 0) { while($row = mysql_fetch_array($r)) echo $row['ID'].",".categoryChild($row['ID']); } else { $row = mysql_fetch_array($r); return $row['ID']; } } If i use return instead of echo, i won't get the same result. I need some help in order to fix this or rewrite it from scratch

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  • PHP/SQL/Wordpress: Group a user list by alphabet

    - by rayne
    I want to create a (fairly big) Wordpress user index with the users categorized alphabetically, like this: A Amy Adam B Bernard Bianca and so on. I've created a custom Wordpress query which works fine for this, except for one problem: It also displays "empty" letters, letters where there aren't any users whose name begins with that letter. I'd be glad if you could help me fix this code so that it only displays the letter if there's actually a user with a name of that letter :) I've tried my luck by checking how many results there are for that letter, but somehow that's not working. (FYI, I use the user photo plugin and only want to show users in the list who have an approved picture, hence the stuff in the SQL query). <?php $alphabet = range('A', 'Z'); foreach ($alphabet as $letter) { $user_count = $wpdb->get_results("SELECT COUNT(*) FROM wp_users WHERE display_name LIKE '".$letter."%' ORDER BY display_name ASC"); if ($user_count > 0) { $user_row = $wpdb->get_results("SELECT wp_users.user_login, wp_users.display_name FROM wp_users, wp_usermeta WHERE wp_users.display_name LIKE '".$letter."%' AND wp_usermeta.meta_key = 'userphoto_approvalstatus' AND wp_usermeta.meta_value = '2' AND wp_usermeta.user_id = wp_users.ID ORDER BY wp_users.display_name ASC"); echo '<li class="letter">'.$letter.''; echo '<ul>'; foreach ($user_row as $user) { echo '<li><a href="/author/'.$user->user_login.'">'.$user->display_name.'</a></li>'; } echo '</ul></li>'; } } ?> Thanks in advance!

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  • find elements of a varchar in another varchar

    - by Luca Romagnoli
    hi, i have a varchar field with the content like these: a,b,c,d e,d,a,c b,q,d,e i need to do a query that select only the rows with the field that has elements equals with an input string. ex input: c,a rows selected: a,b,c,d e,d,a,c is possible without use the OR (field like '%a%' OR field like '%c%') ? thanks

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  • Login failed for user 'NT AUTHORITY\NETWORK SERVICE'.

    - by kumar
    Hi Guys, i tried to open the website from broswer project is deployed at IIS i am getting this exception Exception information: Exception type: SqlException Exception message: Cannot open database "TestDB" requested by the login. The login failed. Login failed for user 'NT AUTHORITY\NETWORK SERVICE'. any solution? Regards kumar

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  • Use SQL Result to Query second time and grab more results via php

    - by maxwell
    I am grabbing a list of school names from a database. When the user clicks on the school name, i want the code to fetch 2-3 other attributes related to the school name that the user has clicked on. My code for the single school name list: $query = mysql_query("Select schoolname, product, username, password from credentials c join products p on p.productid = c.productid join schools s on s.schoolid = c.schoolid join icons i on i.productid = p.productid order by s.schoolname"); echo '<ul>'; while($row = mysql_fetch_array($query)) { echo "<li> <a href='#'>" . $row['schoolname'] . "</a> </li>"; } echo ''; Current Output: School A School A School B School B School B School C School C Expected Output: School name displayed only once (distinct won't work because each school name has 2-3 product credentials School A School B School C Ability for User to click on a school. then the school names underneath will move down (toggle effect) and user can see product, username and password displayed for the school clicked (for example: user clicked on School A) School A productname1, username, password productname2, username, password School B School C

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  • How to evaluate query by DBMS?

    - by Kevinniceguy
    Sorry...I mean what question will be for this query? SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • T-SQL - Left Outer Joins - Filters in the where clause versus the on clause.

    - by Greg Potter
    I am trying to compare two tables to find rows in each table that is not in the other. Table 1 has a groupby column to create 2 sets of data within table one. groupby number ----------- ----------- 1 1 1 2 2 1 2 2 2 4 Table 2 has only one column. number ----------- 1 3 4 So Table 1 has the values 1,2,4 in group 2 and Table 2 has the values 1,3,4. I expect the following result when joining for Group 2: `Table 1 LEFT OUTER Join Table 2` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL `Table 2 LEFT OUTER Join Table 1` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 The only way I can get this to work is if I put a where clause for the first join: PRINT 'Table 1 LEFT OUTER Join Table 2, with WHERE clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL and a filter in the ON for the second: PRINT 'Table 2 LEFT OUTER Join Table 1, with ON clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Can anyone come up with a way of not using the filter in the on clause but in the where clause? The context of this is I have a staging area in a database and I want to identify new records and records that have been deleted. The groupby field is the equivalent of a batchid for an extract and I am comparing the latest extract in a temp table to a the batch from yesterday stored in a partioneds table, which also has all the previously extracted batches as well. Code to create table 1 and 2: create table table1 (number int, groupby int) create table table2 (number int) insert into table1 (number, groupby) values (1, 1) insert into table1 (number, groupby) values (2, 1) insert into table1 (number, groupby) values (1, 2) insert into table2 (number) values (1) insert into table1 (number, groupby) values (2, 2) insert into table2 (number) values (3) insert into table1 (number, groupby) values (4, 2) insert into table2 (number) values (4) EDIT: A bit more context - depending on where I put the filter I different results. As stated above the where clause gives me the correct result in one state and the ON in the other. I am looking for a consistent way of doing this. Where - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number AND table1.groupby = 2 --****************************** WHERE table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 1 1 NULL 2 2 NULL 1 2 NULL Where (table 2 this time) - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number --****************************** WHERE table1.number IS NULL AND table1.groupby = 2 Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- (0) rows returned

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  • php smart learner

    - by rajesh1984
    Is there a possibility to create a html or a php page that will count redirects? I mean, let's say you have a page with a link in it. I want the page to count how many times the link is clicked per ip adress or username. The counting would be reported into a log file or text document.

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