Yield only as many are required from a generator
- by Matt Joiner
I wish to yield from a generator only as many items are required.
In the following code
a, b, c = itertools.count()
I receive this exception:
ValueError: too many values to unpack
I've seen several related questions, however I have zero interest in the remaining items from the generator, I only wish to receive as many as I ask for, without providing that quantity in advance.
It seems to me that Python determines the number of items you want, but then proceeds to try to read and store more than that number.
How can I yield only as many items as I require, without passing in how many items I want?
