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  • Using the Queue class in Python 2.6

    - by voipme
    Let's assume I'm stuck using Python 2.6, and can't upgrade (even if that would help). I've written a program that uses the Queue class. My producer is a simple directory listing. My consumer threads pull a file from the queue, and do stuff with it. If the file has already been processed, I skip it. The processed list is generated before all of the threads are started, so it isn't empty. Here's some pseudo-code. import Queue, sys, threading processed = [] def consumer(): while True: file = dirlist.get(block=True) if file in processed: print "Ignoring %s" % file else: # do stuff here dirlist.task_done() dirlist = Queue.Queue() for f in os.listdir("/some/dir"): dirlist.put(f) max_threads = 8 for i in range(max_threads): thr = Thread(target=consumer) thr.start() dirlist.join() The strange behavior I'm getting is that if a thread encounters a file that's already been processed, the thread stalls out and waits until the entire program ends. I've done a little bit of testing, and the first 7 threads (assuming 8 is the max) stop, while the 8th thread keeps processing, one file at a time. But, by doing that, I'm losing the entire reason for threading the application. Am I doing something wrong, or is this the expected behavior of the Queue/threading classes in Python 2.6?

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  • ssh & script problem

    - by Nishanth
    I am having a strange problem while doing ssh. I am not sure where the term Unmatched ` is coming from. What I need to do is run script that logs information of what I am doing on the terminal to text file. After ssh - Sun Microsystems Inc. SunOS 5.8 Generic Patch October 2001 This is /etc/motd, last updated 3 Feb 2003. To learn about the UCS system and other aspects of computing at UL-Lafayette visit our home page http://helpdesk.louisiana.edu/ . For more information about system use, contact the Help Desk, Stephens Hall, Room 201, 482-5516 (x25516), during normal UL office hours; or send e-mail to [email protected]. ATTENTION: Unsecure Telnet and FTP will be turned off soon. Please make arrange to use ssh or sftp. Putty(telnet) and WinSCP(ftp) would be a good replacement. Unmatched ` d13.ucs.louisiana.edu% bash bash-2.04$ script -a myInformation.txt Script started, file is myInformation.txt Unmatched ` d13.ucs.louisiana.edu% When I tried to start the script with name myInformation.txt, you can see the message I am getting - Script started, file is myInformation.txt. But again I am getting that message Unmatched ` and is coming out of bash, as you can notice. What is the problem ? Any insights suggested would be very great. Note: file with name myInformation.txt is being created but nothing goes in to it. As I have even tried running certain commands like ls and then exited the script with ctrl+d. But when I open the file, nothing is there.

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  • Iterating Over <select> Using jQuery + Multi Select

    - by Kezzer
    This isn't quite as straight forward as one may think. I'm using a plugin called jQuery MultiSelect and multiple <select options using XSLT as follows: <xsl:for-each select="RootField"> <select id="{RootField}" multiple="multiple" size="3"> <option value=""></option> <xsl:for-each select="ChildField"> <option value="{ChildField}"><xsl:value-of select="ChildField"/></option> </xsl:for-each> </select> </xsl:for-each> The accompanying JavaScript is as follows: var selects = document.getElementsByTagName("select"); $.each(selects, function() { $(this).multiSelect(); }); This allows me to apply the multiSelect(); function to every single <select on the page. The behaviour is quite strange, every other <select is being changed into the dropdown list (all the even ones anyway). I can't see anything wrong in my JavaScript to cause this issue as it would iterate over every single one. To make it more clear, the only lists that have that JavaScript applied to it are ones in position 2, 4, 6 and 8 (out of the 9 which are on the page). Any ideas?

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  • For loop index out of range ArgumentOutOfRangeException when multithreading

    - by Lirik
    I'm getting some strange behavior... when I iterate over the dummyText List in the ThreadTest method I get an index out of range exception (ArgumentOutOfRangeException), but if I remove the threads and I just print out the text, then everything works fine. This is my main method: public static Object sync = new Object(); static void Main(string[] args) { ThreadTest(); Console.WriteLine("Press any key to continue."); Console.ReadKey(); } This method throws the exception: private static void ThreadTest() { Console.WriteLine("Running ThreadTest"); Console.WriteLine("Running ThreadTest"); List<String> dummyText = new List<string>() { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"}; for (int i = 0; i < dummyText.Count; i++) { Thread t = new Thread(() => PrintThreadName(dummyText[i])); // <-- Index out of range?!? t.Name = ("Thread " + (i)); t.IsBackground = true; t.Start(); } } private static void PrintThreadName(String text) { Random rand = new Random(DateTime.Now.Millisecond); while (true) { lock (sync) { Console.WriteLine(Thread.CurrentThread.Name + " running " + text); Thread.Sleep(1000+rand.Next(0,2000)); } } } This does not throw the exception: private static void ThreadTest() { Console.WriteLine("Running ThreadTest"); List<String> dummyText = new List<string>() { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"}; for (int i = 0; i < dummyText.Count; i++) { Console.WriteLine(dummyText[i]); // <-- No exception here } } Does anybody know why this is happening?

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  • ASP.NET GridView "Client-Side Confirmation when Deleting" stopped working on ie - how come?

    - by tarnold
    A few months ago, I have programmed an ASP.NET GridView with a custom "Delete" LinkButton and Client-Side JavaScript Confirmation according to this msdn article: http://msdn.microsoft.com/en-us/library/bb428868.aspx (published in April 2007) or e.g. http://stackoverflow.com/questions/218733/javascript-before-aspbuttonfield-click The code looks like this: <ItemTemplate> <asp:LinkButton ID="deleteLinkButton" runat="server" Text="Delete" OnCommand="deleteLinkButtonButton_Command" CommandName='<%# Eval("id") %>' OnClientClick='<%# Eval("id", "return confirm(\"Delete Id {0}?\")") %>' /> </ItemTemplate> Surprisingly, "Cancel" doesn't work no more with my ie (Version: 6.0.2900.2180.xpsp_sp2_qfe.080814-1242) - it always deletes the row. With Opera (Version 9.62) it still works as expeced and described in the msdn article. More surprisingly, on a fellow worker's machine with the same ie version, it still works ("Cancel" will not delete the row). The generated code looks like <a onclick="return confirm(...);" href="javascript:__doPostBack('...')"> As confirm(...) returns false on "Cancel", I expect the __doPostBack event in the href not to be fired. Are there any strange ie settings I accidentally might have changed? What else could be the cause of this weird behaviour? Or is this a "please reinstall WinXP" issue?

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  • Java - Call to start method on thread : how does it route to Runnable interface's run () ?

    - by Bhaskar
    Ok , I know the two standard ways to create a new thread and run it in Java : 1 Implement Runnable in a class , define run method ,and pass an instance of the class to a new Thread. When the start method on the thread instance is called , the run method of the class instance will be invoked. 2 Let the class derive from Thread, so it can to override the method run() and then when a new instance's start method is called , the call is routed to overridden method. In both methods , basically a new Thread object is created and its start method invoked. However , while in the second method , the mechanism of the call being routed to the user defined run() method is very clear ,( its a simple runtime polymorphism in play ), I dont understand how the call to start method on the Thread object gets routed to run() method of the class implementing Runnable interface. Does the Thread class have an private field of Type Runnable which it checks first , and if it is set then invokes the run method if it set to an object ? that would be a strange mechanism IMO. How does the call to start() on a thread get routed to the run method of the Runnable interface implemented by the class whose object is passed as a parameter when contructing the thread ?

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  • Why doesn't access database update?

    - by Ryan
    Recently I met a strange problem, see code snips as below: var sqlCommand: string; connection: TADOConnection; qry: TADOQuery; begin connection := TADOConnection.Create(nil); try connection.ConnectionString := 'Provider=Microsoft.Jet.OLEDB.4.0;Data Source=Test.MDB;Persist Security Info=False'; connection.Open(); qry := TADOQuery.Create(nil); try qry.Connection := connection; qry.SQL.Text := 'Select * from aaa'; qry.Open; qry.Append; qry.FieldByName('TestField1').AsString := 'test'; qry.Post; beep; finally qry.Free; end; finally connection.Free; end; end; First, Create a new access database named test.mdb and put it under the directory of this test project, we can create a new table named aaa in it which has only one text type field named TestField1. We set a breakpoint at line of "beep", then lunch the test application under ide debug mode, when ide stops at the breakpoint line (qry.post has been executed), at this time we use microsoft access to open test.mdb and open table aaa you will find there are no any changes in table aaa, if you let the ide continue running after pressing f9 you can find a new record is inserted in to table aaa, but if you press ctrl+f2 to terminate the application at the breakpoint, you will find the table aaa has no record been inserted, but in normal circumstance, a new record should be inserted in to the table aaa after qry.post executed. who can explain this problem , it troubles me so long time. thanks !!! BTW, the ide is delphi 2010, and the access mdb file is created by microsoft access 2007 under windows 7

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  • NMEA data received but empty. Is there any secret?

    - by Roland Bertolom
    I have a tablet "Futjitsu Stylistic Q550". It's running on Windows 7 (not Phone!). It has a built-in GPS-receiver "Sierra Wireless". I need to parse NMEA data from COM-port. I can do it but it's always empty! Like "$GPRMC,,V,,,,,,,,,,N*53". I've tried standing on open space a long time (so my Android device had located me via GPS for a long time) but NMEA data still empty. So I suppose that GPS is off. But I don't know how to figure it out. I've tried send to COM port $PARAM,START,0*61 but no changes. I've tried to insert SIM-card into the device, as it was suggested on one forum but result was the same. Well is it possible that GPS is idle or something or it's just not working? And if it is idle or off how can I enable it? And.. That looks strange but GSV enumerates satellites but everyone of them has still no data e.g.: $GPGSV,4,1,16,32,,,,11,,,,23,,,*78

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  • YouTube - Encrypted cookie string

    - by Robertof
    Hello! I'm new to Stack Overflow. I'm building a YouTube Downloader in PHP. But YouTube have some IP-checks. Because the PHP file is on a remote server, the ip of the server != the ip of the user and the video-download fails. So, maybe I've found a solution. YouTube sends a cookie with an encrypted string, which is the user IP. I need to know the encrypted-string algorithm and know how to crypt a string with this. Here there is the string: nQ0CrJmASJk . It could be base64, but when I try to decode it with base64_decode, it gives me strange characters. You could check the cookie by requesting the main page of youtube, and check the headers "Set-Cookie". You will found a cookie with the name "VISITOR_INFO1_LIVE". Here there is the encrypyed string. Anyone knows what is the algorithm? Thanks. PS: sorry for my bad english. Cheers, Roberto.

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  • Inheritance and type parameters of Traversable

    - by Jesper
    I'm studying the source code of the Scala 2.8 collection classes. I have questions about the hierarchy of scala.collection.Traversable. Look at the following declarations: package scala.collection trait Traversable[+A] extends TraversableLike[A, Traversable[A]] with GenericTraversableTemplate[A, Traversable] trait TraversableLike[+A, +Repr] extends HasNewBuilder[A, Repr] with TraversableOnce[A] package scala.collection.generic trait HasNewBuilder[+A, +Repr] trait GenericTraversableTemplate[+A, +CC[X] <: Traversable[X]] extends HasNewBuilder[A, CC[A] @uncheckedVariance] Question: Why does Traversable extend GenericTraversableTemplate with type parameters [A, Traversable] - why not [A, Traversable[A]]? I tried some experimenting with a small program with the same structure and got a strange error message when I tried to change it to Traversable[A]: error: Traversable[A] takes no type parameters, expected: one I guess that the use of the @uncheckedVariance annotation in GenericTraversableTemplate also has to do with this? (That seems like a kind of potentially unsafe hack to force things to work...). Question: When you look at the hierarchy, you see that Traversable inherits HasNewBuilder twice (once via TraversableLike and once via GenericTraversableTemplate), but with slightly different type parameters. How does this work exactly? Why don't the different type parameters cause an error?

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  • response.redirect to classic asp failing

    - by jeff
    I have the following code pasted below. For some reason, the response.redirect seems to be failing and it is maxing out the cpu on my server and just doesn't do anything. The .net code uploads the file fine, but does not redirect to the asp page to do the processing. I know this is absolute rubbish why would you have .net code redirecting to classic asp, it is a legacy app. I have tried putting false or true etc. at the end of the redirect as I have read other people have had issues with this. Please help as it's driving me insane! It's so strange, it runs locally on my machine but won't run on my server! public void btnUploadTheFile_Click(object Source, EventArgs evArgs) { //need to check that the uploaded file is an xls file. string strFileNameOnServer = "PJI3.txt"; string strBaseLocation = ConfigurationSettings.AppSettings["str_file_location"]; if ("" == strFileNameOnServer) { txtOutput.InnerHtml = "Error - a file name must be specified."; return; } if (null != uplTheFile.PostedFile) { try { uplTheFile.PostedFile.SaveAs(strBaseLocation+strFileNameOnServer); txtOutput.InnerHtml = "File <b>" + strBaseLocation+strFileNameOnServer+"</b> uploaded successfully"; Response.Redirect ("/COBRA/pages/sap_import_pji3_prc.asp"); } catch (Exception e) { txtOutput.InnerHtml = "Error saving <b>" + strBaseLocation+strFileNameOnServer+"</b><br>"+ e.ToString(); } } }

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • Socket isn't listed by netstat unless using certain ports

    - by illuzive
    I'm a computer science student with a few years of programming experience. Yesterday, while working on a project (Mac OS X, BSD sockets) at school, I encountered a strange problem. I was adding several modules to a very basic "server" (mostly a bunch of functions to set up and manage an UDP socket on a certain port). While doing this, I started the server from time to time in order to see that everything worked like it should. I've been using port 32000 during the development of the server. When I start the server and run netstat, the socket is listed as expected. > netstat -p UDP | grep 32000 udp46 0 0 *.32000 *.* However, when I run the server on other ports (random (10000 - 50000)), it's not listed by netstat. My thought was that I had somehow hard coded the port somewhere in the code, but that's not the case. The thing is - I can connect to the socket on any of the tested ports, and it reads data sent to it without any problem at all. It just doesn't get listed by netstat. What I wonder, is if anyone of you have any idea of why this happens? Note: Although this is a project at school, it's not homework. This is just something I want to understand for my own benefit.

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  • active record relations – who needs it?

    - by M2_
    Well, I`m confused about rails queries. For example: Affiche belongs_to :place Place has_many :affiches We can do this now: @affiches = Affiche.all( :joins => :place ) or @affiches = Affiche.all( :include => :place ) and we will get a lot of extra SELECTs, if there are many affiches: Place Load (0.2ms) SELECT "places".* FROM "places" WHERE "places"."id" = 3 LIMIT 1 Place Load (0.3ms) SELECT "places".* FROM "places" WHERE "places"."id" = 3 LIMIT 1 Place Load (0.8ms) SELECT "places".* FROM "places" WHERE "places"."id" = 444 LIMIT 1 Place Load (1.0ms) SELECT "places".* FROM "places" WHERE "places"."id" = 222 LIMIT 1 ...and so on... And (sic!) with :joins used every SELECT is doubled! Technically we cloud just write like this: @affiches = Affiche.all( ) and the result is totally the same! (Because we have relations declared). The wayout of keeping all data in one query is removing the relations and writing a big string with "LEFT OUTER JOIN", but still there is a problem of grouping data in multy-dimentional array and a problem of similar column names, such as id. What is done wrong? Or what am I doing wrong? UPDATE: Well, i have that string Place Load (2.5ms) SELECT "places".* FROM "places" WHERE ("places"."id" IN (3,444,222,57,663,32,154,20)) and a list of selects one by one id. Strange, but I get these separate selects when I`m doing this in each scope: <%= link_to a.place.name, **a.place**( :id => a.place.friendly_id ) %> the marked a.place is the spot, that produces these extra queries.

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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • How can I handle unread push notifications in iOS?

    - by Bartserk
    I have a iOS 5.1 application that registers to the APNS service to receive notifications. The register is successful and I receive the notifications correctly. The problem comes when I try to handle the notifications. Once the application is running, the method didReceiveRemoteNotification in the AppDelegate is called correctly and so the notification is handled as intended. This, however, only happens when the application is running on the foreground. However, when the application is running on the background or is simply stopped, that method is not called. I've read that you should add some lines to the method didFinishLaunchingWithOptions method to obtain the notification from the userInfo dictionary, and handle it. This works just fine, but ONLY when the application is opened by clicking on the notification at the Notification Center. This means that if you open the application by clicking on its badge, or simply by changing context if you were running it on the background, the app never realises that a notification came in. Additionally, if more than one notification was received, we can only handle one of them at once by clicking on the Notification Center, which is a pain :-) Is there any way to read the pending notifications in the Notification Center? I know there is a way to flush them using the method cancelAllLocalNotifications but I haven't found a way to just read them. And I really need to handle all of them. I thought of implementing a communication protocol with the third-party notification server to retrieve the information again when the application comes to the foreground, but since the information is already in the operating system I would find it strange if it's impossible to access it somehow. So, does anybody know a way to do it? Thanks in advance.

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  • Problem with UITextView

    - by user367039
    I have a strange problem with trying to pass a string from one viewcontroller to another view controller if the string originates from a UITextview instead of UITextfield. Both UITextview.text and UITextfield.text are of type NSString. The following code takes either Textfield.text or Textview.text depending on the fieldType and puts it into a string called aString. NSString *aString = [[NSString alloc] init]; if (fieldType == 3) { aString = textView.text; } else { aString = textField.text; } When I examine aString on either cases, I can see that it has successfully assigned the text into aString. I then pass the string to the other view controller using this code. [delegate updateSite:aString :editedFieldKey :fieldType]; [self.navigationController popViewControllerAnimated:YES]; This works fine if aString originated from textfield.text but nothing happens except the view controller is popped if aString was from textview.text This is the code that takes aString and does stuff with it, however it doesn't even execute the first line of code "NSLog(@"Returned object: %@, field type:%@", aString,editedFieldKey);" if aString was from textview.text Any help will be appreciated. -(void)updateSite:(NSString *)aString :(NSString *)editedFieldKey :(int)fieldType { NSLog(@"Returned object: %@, field type:%@", aString,editedFieldKey); switch (fieldType) { case 0: //string [aDiveSite setValue:aString forKey:editedFieldKey] ; NSLog(@"String set %@",[aDiveSite valueForKey:editedFieldKey] ); break; case 1: //int [aDiveSite setValue:[NSNumber numberWithInt:aString.intValue] forKey:editedFieldKey]; NSLog(@"Integer set"); break; case 2: //float NSLog(@"Saving floating value"); [aDiveSite setValue:[NSNumber numberWithFloat:aString.floatValue] forKey:editedFieldKey]; NSLog(@"Float set"); break; case 3: //Text view [aDiveSite setValue:aString forKey:editedFieldKey]; NSLog(@"Textview text saved"); default: break; } [self.tableView reloadData]; }

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  • ZeroMQ REQ/REP on ipc:// and concurrency

    - by Metiu
    I implemented a JSON-RPC server using a REQ/REP 0MQ ipc:// socket and I'm experiencing strange behavior which I suspect is due to the fact that the ipc:// underlying unix socket is not a real socket, but rather a single pipe. From the documentation, one has to enforce strict zmq_send()/zmq_recv() alternation, otherwise the out-of-order zmq_send() will return an error. However, I expected the enforcement to be per-client, not per-socket. Of course with a Unix socket there is just one pipeline from multiple clients to the server, so the server won't know who it is talking with. Two clients could zmq_send() simultaneously and the server would see this as an alternation violation. The sequence could be: ClientA: zmq_send() ClientB: zmq_send() : will it block until the other send/receive completes? will it return -1? (I suspect it will with ipc:// due to inherent low-level problems, but with TCP it could distinguish the two clients) ClientA: zmq_recv() ClientB: zmq_recv() so what about tcp:// sockets? Will it work concurrently? Should I use some other locking mechanism to work around this?

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  • Median calculation in ActionScript 3

    - by Gabor Kako
    I have a number array and I'd like to calculate the median. When the array is odd, the calculation is OK, when it's even strange number comes up. private var numbers:String = "2,5,3,4,6,1"; private var array:Array = numbers.split(","); private function getMedian(array:Array):Number { var sortnums:Array = array.sort(Array.NUMERIC); var length:Number = sortnums.length; var mid1:Number; var mid2:Number; var median:Number; if(length % 2 == 0){ mid1 = length / 2; trace("mid1: "+mid1); mid2= ((length - 1) / 2)-0.5; trace("mid2: "+mid2); trace ("mid1: "+sortnums[mid1]+", mid2: "+sortnums[mid2]); median = (sortnums[mid1] + sortnums[mid2]) / 2; }else{ mid1 = (length / 2)-0.5 median = sortnums[mid1] } trace (median); return median; } The result is 21.5, but should be 3.5 mid1 and mid2 are a position in the array. Could somebody help?

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  • Amazone API ItemSearch returns (400) Bad Request.

    - by BuzzBubba
    I'm using a simple example from Amazon documentation for ItemSearch and I get a strange error: "The remote server returned an unexpected response: (400) Bad Request." This is the code: public static void Main() { //Remember to create an instance of the amazon service, including you Access ID. AWSECommerceServicePortTypeClient service = new AWSECommerceServicePortTypeClient(new BasicHttpBinding(), new EndpointAddress( "http://webservices.amazon.com/onca/soap?Service=AWSECommerceService")); AWSECommerceServicePortTypeClient client = new AWSECommerceServicePortTypeClient( new BasicHttpBinding(), new EndpointAddress("http://webservices.amazon.com/onca/soap?Service=AWSECommerceService")); // prepare an ItemSearch request ItemSearchRequest request = new ItemSearchRequest(); request.SearchIndex = "Books"; request.Title = "Harry+Potter"; request.ResponseGroup = new string[] { "Small" }; ItemSearch itemSearch = new ItemSearch(); itemSearch.Request = new ItemSearchRequest[] { request }; itemSearch.AWSAccessKeyId = accessKeyId; // issue the ItemSearch request try { ItemSearchResponse response = client.ItemSearch(itemSearch); // write out the results foreach (var item in response.Items[0].Item) { Console.WriteLine(item.ItemAttributes.Title); } } catch(Exception e) { Console.ForegroundColor = ConsoleColor.Red; Console.WriteLine(e.Message); Console.ForegroundColor = ConsoleColor.White; Console.WriteLine("Press any key to quit..."); Clipboard.SetText(e.Message); } Console.ReadKey(); What is wrong?

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  • A feeling that I'm not that good developer

    - by Karim
    Hi, Im having a strange feeling, but let me first introduce myself as a software developer. I started to program when I was still a kid, I had about 10 or 11 years. I really enjoy my work and never get bored from it. It's amazing how somebody could be paid for what he really likes to do and would be doing it anyway even for free. WHen I first started to program, I was feeling proud of what I was doing, each application I built was for me a success and after 2-3 year I had a feeling that I'm a coding guru. It was a nice feeling ;-) But the more I was in the field, the more types of software I started to develop I was starting to have a feeling that I'm completely wrong in that I'm guru. I felt that I'm not even a mediocre developer. Each new field I start to work on is giving me this feeling. Like when I once developed a device driver for a client, I saw how much I need to learn about device drivers. When I developed a video filter for an application, I saw how much do I still need to learn about DirectShow, Color Spaces, and all the theory behind that. The worst thing was when I started to learn algorithms. It was several years ago. I knew then the basic structures and algorithms like the sorting, some types of trees, some hashtables, strings etc.. and when I really wanted to learn a group of structures I learned about 5-6 new types and saw that in fact even this small group has several hundred subtypes of structures. It's depressing how little time people have in their lives to learn all this stuff. I'm now a software developer with about 10 years of experience and I still feel that I'm not a proficient developer when I think about things that others do in the industry. Is this normal what I'm experiencing or is it a sign of a destructive excessive ambition? Thanks in advance for any comments.

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  • Python modules not updating after restarting the main module.

    - by Ian
    I've recently come back to a project having had to stop for about 6 months, and after reinstalling my operating system and coming back to it I'm having all kinds of crazy things happen. I made sure to install the same version(2.6) of python that I was using before. It started by giving me strange tkinter error that I hadn't had trouble with before, the program is relatively simple and the 2 or 3 bugs that were left when i quit, I had documented and weren't related to the interface. Things got even weirder when the same error would pop up even after I had removed the offending section of code. In fact, the traceback pointed to a line that didn't even exist in the module it was referencing, eg: line 262 when the module was only 200 lines long. After just starting a completely new file for the main module and copy/pasting it finally recognized that the offending code was gone and I stopped getting the error only to find that any updates to the code I made in another module didn't show up when I restarted the program through the shell. (I didn't forget to save.) After fiddling with this, of course, the old interface error came back, only in a different section of code that had been working previously. In fact, if I revert back to the files I had six months ago, the program works fine. As soon as I change anything in the main module, however, the interface bug comes back. Here's the original error: Exception in Tkinter callback Traceback (most recent call last): File "C:\Python26\lib\lib-tk\Tkinter.py", line 1410, in __call__ return self.func(*args) File "C:\PyStuff\interface.py", line 202, in dispOne __main__.top.destroy() File "C:\Python26\lib\lib-tk\Tkinter.py", line 1938, in destroy self.tk.call('destroy', self._w) TclError: can't invoke "destroy" command: application has been destroyed I'm guessing something else is going on here other than my own poor programming. Anyone have any ideas?

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  • FragmentActivity doesn't see activity in onActivityCreate(), after screen orientation changed

    - by hai bison
    I'm using Android support library v13. There is a strange thing I couldn't understand. When creating new activity, I load fragment as: Main activity layout: ... <FrameLayout android:id="@+id/fragment_1" ... /> In onCreate() of main activity: mFragment = (FragmentActivity) getSupportFragmentManager().findFragmentById(R.id.fragment_1); // if screen orientation changed, no need to create new instance of fragment if (mFragment == null) { mFragment = ...; // create new instance of fragment FragmentTransaction ft = getSupportFragmentManager().beginTransaction(); ft.replace(R.id.fragment_1, mFragment); // because this is called ONCE, we can use this method ft.commitAllowingStateLoss(); } Now, everything works perfectly in emulators 1.5, 1.6 and 2.2. I have a phone 2.2.2. But there is an exception: if the app is running, and screen orientation changed. Inside onActivityCreated(), getActivity() sometimes returns null. This only happens in emulators 1.5/ 1.6/ 2.2. My phone 2.2.2 works very well, I test hundreds of times but never catch that bug. Even other emulators 3.x, 4.x work well too. Unfortunately I don't have phone 1.5/ 1.6/ 2.2. So did you have experience with this? Is that a bug of the support library, or emulators? Could you please help me? Thank you in advance.

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  • Using tarantula to test a Rails app

    - by Benjamin Oakes
    I'm using Tarantula to test a Rails app I'm developing. It works pretty well, but I'm getting some strange 404s. After looking into it, Tarantula is following DELETE requests (destroy actions on controllers) throughout my app when it tests. Since Tarantula gets the index action first (and seems to keep a list of unvisited URLs), it eventually tries to follow a link to a resource which it had deleted... and gets a 404. Tarantula is right that the URL doesn't exist anymore (because it deleted the resource itself). However, it's flagging it as an error -- that's hardly the behavior I would expect. I'm basically just using the Rails scaffolding and this problem is happening. How do I prevent Tarantula doing this? (Or, is there a better way of specifying the links?) Updates: Still searching, but I found a relevant thread here: http://github.com/relevance/tarantula/issues#issue/3 Seems to be coming from relying on JS too much, in a way (see also http://thelucid.com/2010/03/15/rails-can-we-please-have-a-delete-action-by-default/)

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  • em1: watchdog timeout -- resetting virtualbox

    - by lightmanhk
    everyone. I try to configure network adapter of my freebsd on virtualbox machine. At first setting up, I got it right. However, after a couple of reboots, my VM gives me a error message: says "em1:Watchdog timeout -- resetting" I tried to google it, and there is no solution that works for me. The following is my network adapter of my VM: Apapter1: NAT Adapter2: Host-only Adapter vboxnet0 On my Virtualbox setting: Host-only networks: Adapter: IPv4 address: 192.168.56.10 IPv4 network mask: 255.255.255.0 On my FreeBSD VM /etc/rc.conf ifconfig_em0="DHCP" ifconfig_em1="inet 192.168.56.11 netmask 255.255.255.0" Moreover, strange thing is that, for example, if timeout error message show at ttyv0 , when I log in at different ttyv[1-9], the error message will not be shown. but in ttyv0, it still gives me the message. And, in term of functionality of em1, it does work. I have no clue about this problem. Hoping any one can give me a solution or suggestion. That will be great! Thanks a lot. Freebsd version: 9.0-RELEASE FreeBSD 9.0-RELEASE i386 Virtual box: 4.1.2 r73507

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