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  • Operand should contain 1 column(s) about insert into & select

    - by user1038890
    "insert into NodeProfileSections (profile_no, tpl_section_no) select (np.profile_no, tps.tpl_section_no) from NodeProfile np, TemplateProfileSection tps, TemplateProfile tp where np.hostname = '%s' AND np.role = '%s' AND tp.tpl_profile_no = tps.tpl_profile_no AND tp.tpl_name = '%s' AND tp.role = '%s' AND tps.tpl_section_name = '%s';" %(hostname, role, template_name, role, section_name) error_message = 'Operand should contain 1 column(s)' How to solve this problem?

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  • The table '#sql-5f8_9c' is full

    - by gansodesoya
    hello, im trying to delete a foreign key with the following syntax (5.0.45-community-nt): alter table [table] drop foreign key [fk_name] but I'm getting the folling error: The table '#sql-5f8_9c' is full – 99543 ms any ideas? thanks!

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  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

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  • SELECT Data from multiple tables?

    - by Kyle R
    I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

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  • SQL - Query to display average as either "longer than" or "shorter than"

    - by user1840801
    Here are the tables I've created: CREATE TABLE Plane_new (Pnum char(3), Feature varchar2(20), Ptype varchar2(15), primary key (Pnum)); CREATE TABLE Employee_new (eid char(3), ename varchar(10), salary number(7,2), mid char(3), PRIMARY KEY (eid), FOREIGN KEY (mid) REFERENCES Employee_new); CREATE TABLE Pilot_new (eid char(3), Licence char(9), primary key (eid), foreign key (eid) references Employee_new on delete cascade); CREATE TABLE FlightI_new (Fnum char(4), Fdate date, Duration number(2), Pid char(3), Pnum char(3), primary key (Fnum), foreign key (Pid) references Pilot_new (eid), foreign key (Pnum) references Plane_new); And here is the query I must complete: For each flight, display its number, the name of the pilot who implemented the flight and the words ‘Longer than average’ if the flight duration was longer than average or the words ‘Shorter than average’ if the flight duration was shorter than or equal to the average. For the column holding the words ‘Longer than average’ or ‘Shorter than average’ make a header Length. Here is what I've come up with - with no luck! SELECT F.Fnum, E.ename, CASE Length WHEN F.Duration>(SELECT AVG(F.Duration) FROM FlightI_new F) THEN "Longer than average" WHEN F.Duration<=(SELECT AVG(F.Duration) FROM FlightI_new F) THEN 'Shorter than average' END FROM FlightI_new F LEFT OUTER JOIN Employee_new E ON F.Pid=E.eid GROUP BY F.Fnum, E.ename; Where am I going wrong?

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  • Invalid attempt to access a field before calling Read() INSERT

    - by Raphael Fernandes
    I'm trying to use this code to check if the system already exists a field with this value Dim adap As New MySqlDataAdapter Dim sqlquery = "SELECT * FROM client WHERE code ='"+ TxtCode.Text +"'" Dim comand As New MySqlCommand() comand.Connection = con comand.CommandText = sqlquery adap.SelectCommand = comand Dim data As MySqlDataReader data = comando2.ExecuteReader() leitor.Read() If (data(3).ToString) = code Then MsgBox("already exists", MsgBoxStyle.Information) TxtCode.ResetText() TxtCode.Focus() Else Console.WriteLine(insert("INSERT INTO client (name, tel, code) VALUES ('" & name & "', '" & tel & "')")) con.Close() End If

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  • Count of Sums possibly using group_by

    - by Daniel Johnson
    Say you have a user table and an order table which references user (user has_many orders) and contains an item count field. How could you efficiently ask "how many uses ordered how many items?" That is, to generate something along the lines of: Number of users | sum of items ------------------------------- 5 users | 1 item 4 users | 5 items 1 user | 7 items Thanks in advance.

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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  • Android-SQLite: How to Count specific value from Column?

    - by sanpatil
    I have two table (TABLE_EXAM,TABLE_RESULT). Here is value of my TABLE_RESULT. result_id exam_id question_id correct_answer 1 2 4 y 2 2 5 y 3 2 6 n 4 2 7 y I need to count how many correct_answer='y' where exam_id=2. I try following code but it return 0. public int calculateResult(int examId,String confirmAnswer) { int correctAnswer=0; try { SQLiteDatabase db=this.getWritableDatabase(); String selectQuery=("select count(correctAnswer) from result where exam_id ='" + examId + "' and correctAnswer ='" + 'y' +"'" ); // String selectQuery=("SELECT COUNT(*)FROM result WHERE exam_id ='" + examId + "' and correctAnswer ='" + confirmAnswer +"'" ); Cursor cursor = db.rawQuery(selectQuery, null); if(cursor.moveToLast()) { correctAnswer=cursor.getInt(3); } } catch(Exception e) { e.printStackTrace(); } return correctAnswer; } In variable confirm_answer i pass "y". Give me some hint or reference. Any help is appreciated. Thanks in Advance

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  • mysql_affected_rows() always returns 1 even though no row was updated.

    - by happyhardik
    What I am trying to do is: (programmatically) Update status where id is something, if no rows where updated, give error: we cannot find the record with id something, otherwise give message success. Here I am using mysql_affected_rows() to know if a row was updated or not, but it always return 1, so the user gets a success message, even though there was no row updated. Can anyone tell me what could it be?

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  • How To Get YEARWEEK() To See Sunday As The Start Of The Week?

    - by tan
    I'm trying to get the YEARWEEK function to see Sunday as the 1st day of the week. An example date is: Sunday 1st Mar 2009 Here is my sql SELECT YEARWEEK('2009-03-01') and the result is - 200909 Which is week 9. I believe it is telling me this is week 9 because it sees the sunday as the last day of the previous week. How would I get this function to see sunday as the 1st day of the week and therefore return as week 10?

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  • Allow users to pull temporary data then delete table data (headers remain)?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • error defining foreign key PhpMyAdmin

    - by Ngounou lassale
    I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

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  • What statistics app should I use for my website?

    - by Camran
    I have my own server (with root access). I need statistics of users who visit my website etc etc... I have looked at an app called Webalyzer... Is this a good choice? I run apache2 on a Ubuntu 9 system... If you know of any good statistics apps for servers please let me know. And a follow-up question: All statistics are saved in log-files right? So how large would these log-files become then? Possibility to split them would be good, dont know if this is possible with Webalyzer though...

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  • "=null" and select statement!

    - by user329820
    Hi I have asked this question before in this forum and they told me that it will retun an empty result set,I want to know that if I set the column with null values it will retun an empty result set?also the ANSI_NULLS is OFF ,thanks SELECT 'A' FROM T WHERE A = NULL;

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  • Return Total Rows from a table.

    - by theband
    while($row=mysql_fetch_array($result)) { $output .= "<Reports>"; $output .= "<ProjectName>"; $output .= $row['ProjectName']; $output .= "</ProjectName>"; $output .= "<ProjectCount>"; $output .= $row=mysql_fetch_array($result) $output .= "</ProjectCount>"; $output .= "</Reports>"; } Can i return the number of rows in table like this, i am getting XML markup error.

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  • Dont know how to select a few records from a table as utf8

    - by kwokwai
    Hi all, I don't have phpMyAdmin installed in my web site. Sometimes I was doing some select SQL command at the backend, but when I typed in this command to show all records from table Users: select * from Users; The records were printed as ???? | ??? ??? ??? |. I don't want to make any permanent changes to the charset in the database, so, how is it possible to temporarily displayed a few records as utf8 when needed?

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