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  • reading into table: comma values and quotes SQL

    - by every_answer_gets_a_point
    i have a string like this something = "something, something1, "something2, something else", something3" i need it to be read into a table like this: field1 = "something" field2= "something2" field3 = "something2, something else" field4 = "something3" please notice that the double quotes in the something string signified that the string inside the quotes is to be placed in one field anyone know how to do this with an insert into statement or some other way? the answer can be purely sql or can be vba with sql. thanks!

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  • Is it expensive to hold on to PreparedStatements? (Java & JDBC)

    - by sbook
    I'm trying to figure out if it's efficient for me to cache all of my statements when I create my database connection or if I should only create those that are most used and create the others if/when they're needed.. It seems foolish to create all of the statements in all of the client threads. Any feedback would be greatly appreciated.

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  • Difference between "and" and "where" in joins

    - by Midhat
    Whats the difference between SELECT DISTINCT field1 FROM table1 cd JOIN table2 ON cd.Company = table2.Name and table2.Id IN (2728) and SELECT DISTINCT field1 FROM table1 cd JOIN table2 ON cd.Company = table2.Name where table2.Id IN (2728) both return the same result and both have the same explain output

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  • INSERT ... ON DUPLICATE KEY UPDATE with WHERE?

    - by Raven
    Hi! I'm doing a INSERT ... ON DUPLICATE KEY UPDATE but I need the update part to be conditional, only doing the update if some extra condition has changed. However, WHERE is not allowed on this UPDATE. Is there any workaround for this? I can't do combinations of INSERT/UPDATE/SELECT since this needs to work over a replication.

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  • How do I do Textbox Submit

    - by Newb
    Hello everyone, I have a search box and a buttion. currently a user enter some text and press the search button. But I want to add another feature that instead of clicking the search button people can hit enter to search. How can I do that? Here is my code sample: <form method="post" action=""> <input id="search" name="search" type="text" /> <input id="search_btn" name="search_btn" type="submit" /> </form> Thanks in advance

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  • How to write this loop prettier?

    - by Tom
    I've just read this topic http://stackoverflow.com/questions/2930533/highlight-search-keywords-on-hover and actually I use pretty the same structure, but it looks awful. So can you give me an advice, how to write this loop prettier in one php file, I mean php and html at the same time? <table class="result"> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?>

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  • how to compare the values inside a table in sql

    - by Ranjana
    how to compare the values of same table(say for eg: Order table) each and every time the record get inserted , if the record with same values get inserted already in same table i should not insert the new record with same values. how to do that exactly in sql server 2008

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  • reterview data from two tables using inner join in cakephp

    - by user3593884
    I two tables from database one as user(id,first_name,last_name) and the second table location(id,country). I need to perform inner join with this two tables and the list should display first_name,last_name,country with condition user.id=location.id I have written sql queries in cakephp $this->set('users',$this->User->find('list', array( 'fields' => array('User.id', 'User.first_name','location.country'), array('joins' => array(array('table' => 'location', 'alias' => 'location', 'type' => 'INNER', 'conditions' => array('User.id = location.id'))))))); i get error -Unknown column 'location.country' in 'field list' Please help!

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  • Writing an installer using codigniter

    - by RobertWHurst
    I'm just about finished my first release of automailer, a program I've been working on for a while now. I've just got to finish writing the installer. Its job is to rewrite the codigniter configs from templates. I've got the read/write stuff working, but I'd like to be able to test the server credentials given by the user without codingiter throwing a system error if they're wrong. Is there a function other than mysql_connect that I can use to test a connection that will return true or false and won't make codeigniter have a fit?

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  • Running sql scripts against an attached database?

    - by Will
    I've got an MDF attached to an instance of Sql Server 2008 Express, and I need to run some sql scripts against it to generate tables, indexes, etc. But I can't figure out how to get this to work. If I load the scripts in Visual Studio, it only allows me to connect to the server and run it against a database. I can't choose a different provider (Microsoft Sql Server Database File), so I can't select my MDF. This leaves me the only option of running the script as individual queries, but that won't work as it appears it doesn't support TSQL CREATE statements. How can I run my sql script against an attached database?

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • One on One table relation - is it harmful to keep relation in both tables?

    - by EBAGHAKI
    I have 2 tables that their rows have one on one relation.. For you to understand the situation, suppose there is one table with user informations and there is another table that contains a very specific informations and each user can only link to one these specific kind of informations ( suppose second table as characters ) And that character can only assign to the user who grabs it, Is it against the rules of designing clean databases to hold the relation key in both tables? User Table: user_id, name, age, character_id Character Table: character_id, shape, user_id I have to do it for performance, how do you think about it?

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  • Query table value aliasing in Oracle SQL

    - by Strata
    I have a homework assignment in SQL for Oracle 10g where I have to apply union to two different select statements, to return two columns. I need the values of each cell under vendor_state to indicate CA and every other value in another state to return "Outside CA", to indicate they're elsewhere. I applied the union and produced the two columns and the listings for CA, but many other state IDs were listed and I couldn't find an explanation for how to change the actual values in the query itself. Eventually, I stumbled on an answer, but I can't explain why this works. The code is as follows: SELECT vendor_name, vendor_state FROM vendors WHERE vendor_state IN 'CA' UNION SELECT vendor_name, 'Outside CA' AS vendor_state FROM vendors WHERE vendor_state NOT IN 'CA' ORDER BY vendor_name This gives me the exact answer I need, but I don't know why the aliasing in the second select statement can behave this way....no explanation is given in my textbook and nothing I've read indicates that column aliasing can be done like this. But, by switching the column name and the alias value, I have replaced the value being returned rather than the column name itself...I'm not complaining about the result, but it would help if I knew how I did it.

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  • SQL Join only returning 1 row.

    - by kevin
    Not quite sure what I'm missing, but my SQL statement is only returning one row. SELECT tl.*, (tl.topic_total_rating/tl.topic_rates) as topic_rating, COUNT(pl.post_id) - 1 as reply_count, MIN(pl.post_time) AS topic_time, MAX(pl.post_time) AS topic_bump FROM topic_list tl JOIN post_list pl ON tl.topic_id=pl.post_parent WHERE tl.topic_board_link = %i AND topic_hidden != 1 ORDER BY %s I have two tables (post_list and topic_list), and post_list's post_parent links to a topic_list's topic_id. Instead of returning all the topics (where their board's topic_board_link is n), it only returns one topic.

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  • wp+sql+image not goin in the folder

    - by happy
    this is my code for uploading image in database but image are going to the desird forlder...but when i m tryin to retrieve the images to diaplay,,they are not displayed..anyone help me...... $category=$_POST['category']; $uploadDir = 'D:/xampp/htdocs/js/wordpress/wp-content/plugins/img/imagess/ '; $fileName = $_FILES['Photo']['name']; $tmpName = $_FILES['Photo']['tmp_name']; $fileSize = $_FILES['Photo']['size']; $fileType = $_FILES['Photo']['type']; $filePath = $uploadDir . $fileName; $result = move_uploaded_file($tmpName,$filePath); if (!$result) { echo "Error uploading file"; exit; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } global $wpdb; //$insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category),array('%b','%s')); $insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category)); $wpdb->insert('categories',array('cat_name'=>$category)); echo "Successfully Submitted";

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  • Not sure how to use Decode, NVL, and/or isNull (or something else?) in this situation

    - by RSW
    I have a table of orders for particular products, and a table of products that are on sale. (It's not ideal database structure, but that's out of my control.) What I want to do is outer join the order table to the sale table via product number, but I don't want to include any particular data from the sale table, I just want a Y if the join exists or N if it doesn't in the output. Can anyone explain how I can do this in SQL? Thanks in advance!

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  • Incorrect usage of UPDATE and ORDER BY

    - by nico55555
    I have written some code to update certain rows of a table with a decreasing sequence of numbers. To select the correct rows I have to JOIN two tables. The last row in the table needs to have a value of 0, the second last -1 and so on. To achieve this I use ORDER BY DESC. Unfortunately my code brings up the following error: Incorrect usage of UPDATE and ORDER BY My reading suggests that I can't use UPDATE, JOIN and ORDER BY together. I've read that maybe subqueries might help? I don't really have any idea how to change my code to do this. Perhaps someone could post a modified version that will work? while($row = mysql_fetch_array( $result )) { $products_id = $row['products_id']; $products_stock_attributes = $row['products_stock_attributes']; mysql_query("SET @i = 0"); $result2 = mysql_query("UPDATE orders_products op, orders ord SET op.stock_when_purchased = (@i:=(@i - op.products_quantity)) WHERE op.orders_id = ord.orders_id AND op.products_id = '$products_id' AND op.products_stock_attributes = '$products_stock_attributes' AND op.stock_when_purchased < 0 AND ord.orders_status = 2 ORDER BY orders_products_id DESC") or die(mysql_error()); }

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  • custom function is not getting called

    - by nectar
    here my code - $child1 = create_childid()."01"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); echo $newid; update_level(); $child2 = create_childid()."02"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child2', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child3 = create_childid()."03"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child3', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child4 = create_childid()."04"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child4', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child5 = create_childid()."05"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child5', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); ERROR : update_level(); is executing only once why??

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  • Convert tax like IRS function to SQL

    - by CrashRoX
    Trying to convert this tax-like IRS function http://stackoverflow.com/questions/1817920/calculating-revenue-share-at-different-tiers to SQL. The assumption is the table would be one column (price) and the tiers will be added dynamically. My first attempt has some case statements that didn't work out well. I have since scrapped it :) Thanks for the help!

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  • Prioritize SQL WHERE clause

    - by JaTochNietDan
    Basically I want to do this: SELECT * FROM `table` WHERE x = 'hello' OR x = 'bye' LIMIT 1'; I want it to return 1 value, but to prioritize results from the 1st where clause. So if there exists a row where column x's value is "hello", it will not return the result from the 'bye' value. If the "hello" value doesn't exist though, it will return the result from the 'bye' value. Can't figure out a way to do it even though it seems fairly trivial. Any ideas?

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  • How could I compare these database values in PHP?

    - by Dan
    So a user selects from a drop down list a value. I take this value, put it into a variable, then select from the database the ID value of that table A holding the selected value also. So now I'm trying to use that ID value to get to a many-to-many relationship table that has the selected value from table A to a different table B. The many-to-many relationship table has both IDs. How can I compare this using PHP? So it would be like: $A = $_POST['a']; $sql = "SELECT a, aID from TABLEA WHERE a = $A"; What do I do then to compare the aID with the many-to-many relationships table, then get the other ID in that table and then take that ID to get values from table B?

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