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  • scalable background image of popup. html, css

    - by Mayur
    Hi All, I'm getting a problem in html and css, I used a bg image for my popup window whose size is 500px width and 400px height; having a scrollable text in it. but problem is that if i reduce a size of browser it get distorted. Please help me if i can make it scalable background and according to that text as per browser size. Thanks Mayur Mate

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  • Image stretching

    - by NIL
    Hi All, I want Stretch a image. For that i use sprite. I want stretch sprite & this stretching is may be Circular or curve animation. I don't understand what methode used for that. Can anyone help me?

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  • iPhone Camera and Image Chooser

    - by PF1
    Hi Everyone: I have found a lot of information on using UIImagePickerController to let the user choose the image they want from the Photos application's data. I am wondering how I can create this same effect on 3.0, as it doesn't seem as if a lot of the old code works anymore. In addition, I would like the user to be able to take a new picture from this same pop-up. Thanks for any help!

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  • jquery popup image

    - by sam
    Hello Folks., I am looking for jquery script of popping up an image onmouseover.. i did this using javascript but it is not browser supportive.. so looking for jquery script.. Thanks

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  • Background image is not displayed in Firefox

    - by petersidor
    An image set as the background of a DIV is displayed in IE, but not in Firefox. CSS example: div.something { background:transparent url(../images/table_column.jpg) repeat scroll 0 0; } (The issue is described in many places but haven't seen any conclusive explanation or fix.)

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  • Numpy zero rank array indexing/broadcasting

    - by Lemming
    I'm trying to write a function that supports broadcasting and is fast at the same time. However, numpy's zero-rank arrays are causing trouble as usual. I couldn't find anything useful on google, or by searching here. So, I'm asking you. How should I implement broadcasting efficiently and handle zero-rank arrays at the same time? This whole post became larger than anticipated, sorry. Details: To clarify what I'm talking about I'll give a simple example: Say I want to implement a Heaviside step-function. I.e. a function that acts on the real axis, which is 0 on the negative side, 1 on the positive side, and from case to case either 0, 0.5, or 1 at the point 0. Implementation Masking The most efficient way I found so far is the following. It uses boolean arrays as masks to assign the correct values to the corresponding slots in the output vector. from numpy import * def step_mask(x, limit=+1): """Heaviside step-function. y = 0 if x < 0 y = 1 if x > 0 See below for x == 0. Arguments: x Evaluate the function at these points. limit Which limit at x == 0? limit > 0: y = 1 limit == 0: y = 0.5 limit < 0: y = 0 Return: The values corresponding to x. """ b = broadcast(x, limit) out = zeros(b.shape) out[x>0] = 1 mask = (limit > 0) & (x == 0) out[mask] = 1 mask = (limit == 0) & (x == 0) out[mask] = 0.5 mask = (limit < 0) & (x == 0) out[mask] = 0 return out List Comprehension The following-the-numpy-docs way is to use a list comprehension on the flat iterator of the broadcast object. However, list comprehensions become absolutely unreadable for such complicated functions. def step_comprehension(x, limit=+1): b = broadcast(x, limit) out = empty(b.shape) out.flat = [ ( 1 if x_ > 0 else ( 0 if x_ < 0 else ( 1 if l_ > 0 else ( 0.5 if l_ ==0 else ( 0 ))))) for x_, l_ in b ] return out For Loop And finally, the most naive way is a for loop. It's probably the most readable option. However, Python for-loops are anything but fast. And hence, a really bad idea in numerics. def step_for(x, limit=+1): b = broadcast(x, limit) out = empty(b.shape) for i, (x_, l_) in enumerate(b): if x_ > 0: out[i] = 1 elif x_ < 0: out[i] = 0 elif l_ > 0: out[i] = 1 elif l_ < 0: out[i] = 0 else: out[i] = 0.5 return out Test First of all a brief test to see if the output is correct. >>> x = array([-1, -0.1, 0, 0.1, 1]) >>> step_mask(x, +1) array([ 0., 0., 1., 1., 1.]) >>> step_mask(x, 0) array([ 0. , 0. , 0.5, 1. , 1. ]) >>> step_mask(x, -1) array([ 0., 0., 0., 1., 1.]) It is correct, and the other two functions give the same output. Performance How about efficiency? These are the timings: In [45]: xl = linspace(-2, 2, 500001) In [46]: %timeit step_mask(xl) 10 loops, best of 3: 19.5 ms per loop In [47]: %timeit step_comprehension(xl) 1 loops, best of 3: 1.17 s per loop In [48]: %timeit step_for(xl) 1 loops, best of 3: 1.15 s per loop The masked version performs best as expected. However, I'm surprised that the comprehension is on the same level as the for loop. Zero Rank Arrays But, 0-rank arrays pose a problem. Sometimes you want to use a function scalar input. And preferably not have to worry about wrapping all scalars in at least 1-D arrays. >>> step_mask(1) Traceback (most recent call last): File "<ipython-input-50-91c06aa4487b>", line 1, in <module> step_mask(1) File "script.py", line 22, in step_mask out[x>0] = 1 IndexError: 0-d arrays can't be indexed. >>> step_for(1) Traceback (most recent call last): File "<ipython-input-51-4e0de4fcb197>", line 1, in <module> step_for(1) File "script.py", line 55, in step_for out[i] = 1 IndexError: 0-d arrays can't be indexed. >>> step_comprehension(1) array(1.0) Only the list comprehension can handle 0-rank arrays. The other two versions would need special case handling for 0-rank arrays. Numpy gets a bit messy when you want to use the same code for arrays and scalars. However, I really like to have functions that work on as arbitrary input as possible. Who knows which parameters I'll want to iterate over at some point. Question: What is the best way to implement a function as the one above? Is there a way to avoid if scalar then like special cases? I'm not looking for a built-in Heaviside. It's just a simplified example. In my code the above pattern appears in many places to make parameter iteration as simple as possible without littering the client code with for loops or comprehensions. Furthermore, I'm aware of Cython, or weave & Co., or implementation directly in C. However, the performance of the masked version above is sufficient for the moment. And for the moment I would like to keep things as simple as possible.

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  • Win32 C/C++ Load Image from memory buffer

    - by Bruno
    I want to load a image (.bmp) file on a Win32 application, but I do not want to use the standard LoadBitmap/LoadImage from Windows API: I want it to load from a buffer that is already in memory. I can easily load a bitmap directly from file and print it on the screen, but this issue is making me stuck :( What I'm looking for is a function that works like this: HBITMAP LoadBitmapFromBuffer(char* buffer, int width, int height); Thanks.

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  • How to get rid of box around linked image

    - by Earlz
    Hello, I know I've solved this problem before, but I can't remember or find the solution, so here I am... In Firefox 3.5 this code causes an undesirable blue border around the image. How do I get rid of this blue border? <a style="text-decoration: none;" href="index.html"> <img src="http://www.google.com/logos/stpatricksday10-hp.gif" /> </a> http://jsbin.com/umuzo3

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  • Show Category Image with Link in Magento

    - by Daniel Hirsch
    On my Magento homepage, I'd like to include a link to a few categories, along with their respective Category images. Obviously, I could manually link to the images, but it seems like it would only make sense there is a way to automatically pull the Category image along with the link. Help?

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  • wpf Image resources and visual studio 2010 resource editor

    - by Berryl
    Hello My motivation for this question is really just to specify an image to be used in a user control via a dependency property for ImageSource. I'm hitting some pain points involving the management, access, and unit testing for this. Is the resource editor a good tool to use to maintain images for the application? What is the best way to translate the Bitmap from the editor to an ImageSource? How can I grab the resource Filename from the editor? Cheers, Berryl

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