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  • Mac OS X: java.lang.ClassNotFoundException: com.sun.java.browser.plugin2.DOM

    - by Thilo
    I am trying to use the new LiveConnect features introduced in Java 6 Update 10. Code looks like this (copied from the applet tutorial): Class<?> c = Class.forName("com.sun.java.browser.plugin2.DOM"); Method m = c.getMethod("getDocument", java.applet.Applet.class); Document document = (Document) m.invoke(null, this); But all I am getting is a ClassNotFoundException for the entry-point class. This on the Mac, 10.6, with both Firefox and Safari. Java Plug-in 1.6.0_22 Using JRE version 1.6.0_22-b04-307-10M3261 Java HotSpot(TM) 64-Bit Server VM Is this not implemented on the Mac? Or do I need to configure something? All I need to do is get and set the value of form elements on the page, so I would be fine with an older (pre-6u10) API if that works better.

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  • Extending Java Enums

    - by CaseyB
    Here's what I am looking to accomplish, I have a class that has an enum of some values and I want to subclass that and add more values to the enum. This is a bad example, but: public class Digits { public enum Digit { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 } } public class HexDigits extends Digits { public enum Digit { A, B, C, D, E, F } } so that HexDigits.Digit contains all Hex Digits. Is that possible?

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  • Documenting PHP multiple inheritance with PhpDoc

    - by Sam Dark
    I have multiple inheritance like this one: http://stackoverflow.com/questions/356128/can-i-extend-a-class-using-more-than-1-class-in-php (let's not discuss this approach itself please) and want my IDE to know about inherited class methods and properties. Is there a way to do it with PhpDoc?

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  • ASP.NET MVC security: how to check if a controller method is allowed to execute under current user's

    - by Gart
    Given an ASP.NET MVC Controller class declaration: public class ItemController : Controller { public ActionResult Index() { // ... } public ActionResult Details() { // ... } [Authorize(Roles="Admin, Editor")] public ActionResult Edit() { // ... } [Authorized(Roles="Admin")] public ActionResult Delete() { // .. } } I need to reflect a list of methods in this class which may be invoked with the current user's permissions. Please share some ideas of what could be done in this case.

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  • What does ruby include when it encounters the "include module" statement?

    - by Steve Weet
    If I have the following project structure project/ lib/ subproject/ a.rb b.rb lib.rb where lib.rb looks like this :- module subproject def foo do_some_stuff end end and a.rb and b.rb both need to mixin some methods within lib.rb and are both namespaced within a module like so :- require 'subproject/lib' module subproject class A include Subproject def initialize() foo() end end end What does ruby do when it encounters the include statement? How does it know that I want to only include the mixin from lib.rb rather than the whole module which includes both class A and class B, is this based purely on the require of subproject/lib or am I getting it wrong and it is including the whole of the module, including the definitions of Class A and B within themselves?

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  • UML Modelling in C++Builder 2010 Professional

    - by Gordon Brandly
    I'd like to do some basic class diagram UML models in the Pro version of C++Builder 2010. Embarcadero has a C++Builder Features Matrix document, one line of which says "UML Code Visualization – at any time, get a UML model view of your source code" and has a check in the "Professional" column of that table -- I assume this means it should be available to me. Yet, when I open an existing project and do a View | Model View, there's nothing in the Model View window. The only diagram I can find is on the Graph tab of the C++ Class Explorer. I wouldn't call that a UML diagram myself -- is that what Embarcadero is referring to? Embarcadero's table shows that many UML diagrams are not available in Pro, but it looks to me like Class Diagrams should be available. Other lines in that same table indicate that both "Full two-way class diagrams with synchronization between code and diagrams" and "Diagram hyper-linking and annotations" are also supposed to be available in Pro. The Class Explorer graph is one-way only as far as I can tell, so I hope they're referring to something else I haven't been able to find so far. Thanks for any insight into this.

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  • Persist collection of interface using Hibernate

    - by Olvagor
    I want to persist my litte zoo with Hibernate: @Entity @Table(name = "zoo") public class Zoo { @OneToMany private Set<Animal> animals = new HashSet<Animal>(); } // Just a marker interface public interface Animal { } @Entity @Table(name = "dog") public class Dog implements Animal { // ID and other properties } @Entity @Table(name = "cat") public class Cat implements Animal { // ID and other properties } When I try to persist the zoo, Hibernate complains: Use of @OneToMany or @ManyToMany targeting an unmapped class: blubb.Zoo.animals[blubb.Animal] I know about the targetEntity-property of @OneToMany but that would mean, only Dogs OR Cats can live in my zoo. Is there any way to persist a collection of an interface, which has several implementations, with Hibernate?

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  • C#: What is the preferred way to handle this error?

    - by Ash
    I have a class 'Hand' that consists of two playing cards as below: public class Card { public char r, s; public Card(char rank, char suit) { r = rank; s = suit; } } public class Hand { public Card c1, c2; public Hand(Card one, Card two) { c1 = one; c2 = two; } } In a 52 card deck we can't have two identical cards. How should I deal with an error where I accidentally instance a class with two identical cards, e.g (Ah, Ah)? Thanks, Ash

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  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

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  • How can I configure a Factory with the possible providers?

    - by Jonathas Costa
    I have three assemblies: "Framework.DataAccess", "Framework.DataAccess.NHibernateProvider" and "Company.DataAccess". Inside the assembly "Framework.DataAccess", I have my factory (with the wrong implementation of discovery): public class DaoFactory { private static readonly object locker = new object(); private static IWindsorContainer _daoContainer; protected static IWindsorContainer DaoContainer { get { if (_daoContainer == null) { lock (locker) { if (_daoContainer != null) return _daoContainer; _daoContainer = new WindsorContainer(new XmlInterpreter()); // THIS IS WRONG! THIS ASSEMBLY CANNOT KNOW ABOUT SPECIALIZATIONS! _daoContainer.Register( AllTypes.FromAssemblyNamed("Company.DataAccess") .BasedOn(typeof(IReadDao<>)).WithService.FromInterface(), AllTypes.FromAssemblyNamed("Framework.DataAccess.NHibernateProvider") .BasedOn(typeof(IReadDao<>)).WithService.Base()); } } return _daoContainer; } } public static T Create<T>() where T : IDao { return DaoContainer.Resolve<T>(); } } This assembly also defines the base interface for data access IReadDao: public interface IReadDao<T> { IEnumerable<T> GetAll(); } I want to keep this assembly generic and with no references. This is my base data access assembly. Then I have the NHibernate provider's assembly, which implements the above IReadDao using NHibernate's approach. This assembly references the "Framework.DataAccess" assembly. public class NHibernateDao<T> : IReadDao<T> { public NHibernateDao() { } public virtual IEnumerable<T> GetAll() { throw new NotImplementedException(); } } At last, I have the "Company.DataAccess" assembly, which can override the default implementation of NHibernate provider and references both previously seen assemblies. public interface IProductDao : IReadDao<Product> { Product GetByName(string name); } public class ProductDao : NHibernateDao<Product>, IProductDao { public override IEnumerable<Product> GetAll() { throw new NotImplementedException("new one!"); } public Product GetByName(string name) { throw new NotImplementedException(); } } I want to be able to write... IRead<Product> dao = DaoFactory.Create<IRead<Product>>(); ... and then get the ProductDao implementation. But I can't hold inside my base data access any reference to specific assemblies! My initial idea was to read that from a xml config file. So, my question is: How can I externally configure this factory to use a specific provider as my default implementation and my client implementation?

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  • Nhibernate join on a table twice

    - by Zuber
    Consider the following Class structure... public class ListViewControl { public int SystemId {get; set;} public List<ControlAction> Actions {get; set;} public List<ControlAction> ListViewActions {get; set;} } public class ControlAction { public string blahBlah {get; set;} } I want to load class ListViewControl eagerly using NHibernate. The mapping using Fluent is as shown below public UIControlMap() { Id(x => x.SystemId); HasMany(x => x.Actions) .KeyColumn("ActionId") .Cascade.AllDeleteOrphan() .AsBag() .Cache.ReadWrite().IncludeAll(); HasMany(x => x.ListViewActions) .KeyColumn("ListViewActionId") .Cascade.AllDeleteOrphan() .AsBag() .Cache.ReadWrite().IncludeAll(); } This is how I am trying to load it eagerly var baseActions = DetachedCriteria.For<ListViewControl>() .CreateCriteria("Actions", JoinType.InnerJoin) .SetFetchMode("BlahBlah", FetchMode.Eager) .SetResultTransformer(new DistinctRootEntityResultTransformer()); var listViewActions = DetachedCriteria.For<ListViewControl>() .CreateCriteria("ListViewActions", JoinType.InnerJoin) .SetFetchMode("BlahBlah", FetchMode.Eager) .SetResultTransformer(new DistinctRootEntityResultTransformer()); var listViews = DetachedCriteria.For<ListViewControl>() .SetFetchMode("Actions", FetchMode.Eager) .SetFetchMode("ListViewActions",FetchMode.Eager) .SetResultTransformer(new DistinctRootEntityResultTransformer()); var result = _session.CreateMultiCriteria() .Add("listViewActions", listViewActions) .Add("baseActions", baseActions) .Add("listViews", listViews) .SetResultTransformer(new DistinctRootEntityResultTransformer()) .GetResult("listViews"); Now, my problem is that the class ListViewControl get the correct records in both Actions and ListViewActions, but there are multiple entries of the same record. The number of records is equal to the number of joins made to the ControlAction table, in this case two. How can I avoid this? If I remove the SetFetchMode from the listViews query, the actions are loaded lazily through a proxy which I don't want.

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  • Response is not available in this context when creation cookie's

    - by Sadegh
    hi i defined one class to create cookie by received parameter's from user. when i want to add cookie to context i receive an exception. My Class public static class ManageCookies { public static void Create(string name, string value) { HttpCookie cookie = new HttpCookie(name); cookie.Value = value; cookie.Expires = DateTime.Now.AddYears(1); HttpContext.Current.Response.Cookies.Add(cookie); } } Occured Exception: Response is not available in this context.

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  • How to include the login form on the Home index page in MVC

    - by Bernard Larouche
    Hi guys I really need your help for this. I am relatively new to programming and I need help to something that could be easy for a experienced programmer. I would like to get the login form that we get for free in an MVC application on the left sidebar of my Home index page instead of the usual Account/Login page. I am facing some problems. First I need a product object to be displayed on my Home Index page as well. What I did is that I added a product object to the LogOnModel that they provide in the AccountModels class and I created a UserControl (partial view) copying the content of the LogOn.aspx view. Now my Home index.aspx as well as my partial view inherits the LogOnModel class. I can see the Login form on my Home Index page as well as my product object BUT the login Form is never empty. The last username and password always appear there. I know I must have forgotten something or have done something wrong or the way did it is completely wrong !! Please could you give me some advice Thks <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<CoderForTradersSite.Models.LogOnModel>" %> <h4>Login Form</h4> <p> Please enter your username and password. <%= Html.ActionLink("Register", "Register") %> if you don't have an account. </p> <% using (Html.BeginForm()) { %> <%= Html.ValidationSummary(true, "Login was unsuccessful. Please correct the errors and try again.") %> <div> <fieldset> <legend>Account Information</legend> <div class="editor-label"> <%= Html.LabelFor(m => m.UserName) %> </div> <div class="editor-field"> <%= Html.TextBoxFor(m => m.UserName) %> <%= Html.ValidationMessageFor(m => m.UserName) %> </div> <div class="editor-label"> <%= Html.LabelFor(m => m.Password) %> </div> <div class="editor-field"> <%= Html.PasswordFor(m => m.Password) %> <%= Html.ValidationMessageFor(m => m.Password) %> </div> <div class="editor-label"> <%= Html.CheckBoxFor(m => m.RememberMe) %> <%= Html.LabelFor(m => m.RememberMe) %> </div> <p> <input type="submit" value="Log On" /> </p> </fieldset> </div> <% } %>

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  • Extending Controller

    - by MakDotGNU
    Hi, I'm very new to Kohana and I'm trying to make a project in kohana 2.x, in my previous projects i had created a Base controller which used to extends Controller. and all other controller to Base_Controller. in Kohana I'm facing the problem. here is my structure. class Base_Controller extends Template_Controller class Home_Controller extends Base_Controller both these Controllers are in application/controller folder Fatal error: Class 'Base_Controller' not found in /home/myadav/public_html/innteract/innteract/controllers/home.php on line 2

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  • jQuery ajax delete script not actually deleting.

    - by werm
    I have a little personal webapp that I'm working on. I have a link that, when clicked, is supposed to make an ajax call to a php that is supposed to delete that info from a database. For some unknown reason, it won't actually delete the row from the database. I've tried everything I know, but still nothing. I'm sure it's something incredibly easy... Here are the scripts involved. Database output: $sql = "SELECT * FROM bookmark_app"; foreach ($dbh->query($sql) as $row) { echo '<div class="box" id="',$row['id'],'"><img src="images/avatar.jpg" width="75" height="75" border="0" class="avatar"/> <div class="text"><a href="',$row['url'],'">',$row['title'],'</a><br/> </div> /*** Click to delete ***/ <a href="?delete=',$row['id'],'" class="delete">x</a></div> <div class="clear"></div>'; } $dbh = null; Ajax script: $(document).ready(function() { $("a.delete").click(function(){ var element = $(this); var noteid = element.attr("id"); var info = 'id=' + noteid; $.ajax({ type: "GET", url: "includes/delete.php", data: info, success: function(){ element.parent().eq(0).fadeOut("slow"); } }); return false; }); }); Delete code: include('connect.php'); //delete.php?id=IdOfPost if($_GET['id']){ $id = $_GET['id']; //Delete the record of the post $delete = mysql_query("DELETE FROM `db` WHERE `id` = '$id'"); //Redirect the user header("Location:xxxx.php"); }

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  • How to read Windows.UI.XAML.Style properties in C#

    - by Igor Kulman
    I am writing a class that will convert a HTML document to a list of Paragrpahs that can be used with RichTextBlock in Windows 8 apps. I want to be able to give the class a list of Styles defined in XAML and the class will read useful properties from the style and apply them. If I have a Windows.UI.XAML.Style style how do I read a property from it? I tried var fontWeight = style.GetValue(TextElement.FontWeightProperty) for a style defined in XAML with TargetProperty="TextBlock" but this fails with and exception

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  • Recommendations for a C++ polymorphic, seekable, binary I/O interface

    - by Trevor Robinson
    I've been using std::istream and ostream as a polymorphic interface for random-access binary I/O in C++, but it seems suboptimal in numerous ways: 64-bit seeks are non-portable and error-prone due to streampos/streamoff limitations; currently using boost/iostreams/positioning.hpp as a workaround, but it requires vigilance Missing operations such as truncating or extending a file (ala POSIX ftruncate) Inconsistency between concrete implementations; e.g. stringstream has independent get/put positions whereas filestream does not Inconsistency between platform implementations; e.g. behavior of seeking pass the end of a file or usage of failbit/badbit on errors Don't need all the formatting facilities of stream or possibly even the buffering of streambuf streambuf error reporting (i.e. exceptions vs. returning an error indicator) is supposedly implementation-dependent in practice I like the simplified interface provided by the Boost.Iostreams Device concept, but it's provided as function templates rather than a polymorphic class. (There is a device class, but it's not polymorphic and is just an implementation helper class not necessarily used by the supplied device implementations.) I'm primarily using large disk files, but I really want polymorphism so I can easily substitute alternate implementations (e.g. use stringstream instead of fstream for unit tests) without all the complexity and compile-time coupling of deep template instantiation. Does anyone have any recommendations of a standard approach to this? It seems like a common situation, so I don't want to invent my own interfaces unnecessarily. As an example, something like java.nio.FileChannel seems ideal. My best solution so far is to put a thin polymorphic layer on top of Boost.Iostreams devices. For example: class my_istream { public: virtual std::streampos seek(stream_offset off, std::ios_base::seekdir way) = 0; virtual std::streamsize read(char* s, std::streamsize n) = 0; virtual void close() = 0; }; template <class T> class boost_istream : public my_istream { public: boost_istream(const T& device) : m_device(device) { } virtual std::streampos seek(stream_offset off, std::ios_base::seekdir way) { return boost::iostreams::seek(m_device, off, way); } virtual std::streamsize read(char* s, std::streamsize n) { return boost::iostreams::read(m_device, s, n); } virtual void close() { boost::iostreams::close(m_device); } private: T m_device; };

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  • Spring transactions not committing

    - by Clinton Bosch
    I am struggling to get my spring managed transactions to commit, could someone please spot what I have done wrong. All my tables are mysql InnonDB tables. My RemoteServiceServlet (GWT) is as follows: public class TrainTrackServiceImpl extends RemoteServiceServlet implements TrainTrackService { @Autowired private DAO dao; @Override public void init(ServletConfig config) throws ServletException { super.init(config); WebApplicationContext ctx = WebApplicationContextUtils.getRequiredWebApplicationContext(config.getServletContext()); AutowireCapableBeanFactory beanFactory = ctx.getAutowireCapableBeanFactory(); beanFactory.autowireBean(this); } @Transactional(propagation= Propagation.REQUIRED, rollbackFor=Exception.class) public UserDTO createUser(String firstName, String lastName, String idNumber, String cellPhone, String email, int merchantId) { User user = new User(); user.setFirstName(firstName); user.setLastName(lastName); user.setIdNumber(idNumber); user.setCellphone(cellPhone); user.setEmail(email); user.setDateCreated(new Date()); Merchant merchant = (Merchant) dao.find(Merchant.class, merchantId); if (merchant != null) { user.setMerchant(merchant); } // Save the user. dao.saveOrUpdate(user); UserDTO dto = new UserDTO(); dto.id = user.getId(); dto.firstName = user.getFirstName(); dto.lastName = user.getLastName(); return dto; } The DAO is as follows: public class DAO extends HibernateDaoSupport { private String adminUsername; private String adminPassword; private String godUsername; private String godPassword; public String getAdminUsername() { return adminUsername; } public void setAdminUsername(String adminUsername) { this.adminUsername = adminUsername; } public String getAdminPassword() { return adminPassword; } public void setAdminPassword(String adminPassword) { this.adminPassword = adminPassword; } public String getGodUsername() { return godUsername; } public void setGodUsername(String godUsername) { this.godUsername = godUsername; } public String getGodPassword() { return godPassword; } public void setGodPassword(String godPassword) { this.godPassword = godPassword; } public void saveOrUpdate(ModelObject obj) { getHibernateTemplate().saveOrUpdate(obj); } And my applicationContext.xml is as follows: <context:annotation-config/> <context:component-scan base-package="za.co.xxx.traintrack.server"/> <!-- Application properties --> <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="locations"> <list> <value>file:${user.dir}/@propertiesFile@</value> </list> </property> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${connection.dialect}</prop> <prop key="hibernate.connection.username">${connection.username}</prop> <prop key="hibernate.connection.password">${connection.password}</prop> <prop key="hibernate.connection.url">${connection.url}</prop> <prop key="hibernate.connection.driver_class">${connection.driver.class}</prop> <prop key="hibernate.show_sql">${show.sql}</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.c3p0.min_size">5</prop> <prop key="hibernate.c3p0.max_size">20</prop> <prop key="hibernate.c3p0.timeout">300</prop> <prop key="hibernate.c3p0.max_statements">50</prop> <prop key="hibernate.c3p0.idle_test_period">60</prop> </props> </property> <property name="annotatedClasses"> <list> <value>za.co.xxx.traintrack.server.model.Answer</value> <value>za.co.xxx.traintrack.server.model.Company</value> <value>za.co.xxx.traintrack.server.model.CompanyRegion</value> <value>za.co.xxx.traintrack.server.model.Merchant</value> <value>za.co.xxx.traintrack.server.model.Module</value> <value>za.co.xxx.traintrack.server.model.Question</value> <value>za.co.xxx.traintrack.server.model.User</value> <value>za.co.xxx.traintrack.server.model.CompletedModule</value> </list> </property> </bean> <bean id="dao" class="za.co.xxx.traintrack.server.DAO"> <property name="sessionFactory" ref="sessionFactory"/> <property name="adminUsername" value="${admin.user.name}"/> <property name="adminPassword" value="${admin.user.password}"/> <property name="godUsername" value="${god.user.name}"/> <property name="godPassword" value="${god.user.password}"/> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory"> <ref local="sessionFactory"/> </property> </bean> <!-- enable the configuration of transactional behavior based on annotations --> <tx:annotation-driven transaction-manager="transactionManager"/> If I change the sessionFactory property to be autoCommit=true then my object does get persisited. <prop key="hibernate.connection.autocommit">true</prop>

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  • Initialize static members in PHP

    - by Senthil
    class Person { public static function ShowQualification() { } } class School { public static $Headmaster = new Person(); // NetBeans complains about this line } Why is this not possible? I want to be able to use this like School::Headmaster::ShowQualification(); ..without instantiating any class. How can I do it?

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  • Passing Objects between different files

    - by user309779
    Typically, if I want to pass an object to an instance of something I would do it like so... Listing 1 File 1: public class SomeClass { // Some Properties public SomeClass() { public int ID { get { return mID; } set { mID = value; } } public string Name { set { mName = value; } get { return mName; } } } } public class SomeOtherClass { // Method 1 private void Method1(int one, int two) { SomeClass USER; // Create an instance Squid RsP = new Squid(); RsP.sqdReadUserConf(USER); // Able to pass 'USER' to class method in different file. } } In this example, I was not able to use the above approach. Probably because the above example passes an object between classes. Whereas, below, things are defined in a single class. I had to use some extra steps (trial & error) to get things to work. I am not sure what I did here or what its called. Is it good programming practice? Or is there is an easier way to do this (like above). Listing 2 File 1: private void SomeClass1 { [snip] TCOpt_fM.AutoUpdate = optAutoUpdate.Checked; TCOpt_fM.WhiteList = optWhiteList.Checked; TCOpt_fM.BlackList = optBlackList.Checked; [snip] private TCOpt TCOpt_fM; TCOpt_fM.SaveOptions(TCOpt_fM); } File 2: public class TCOpt: { public TCOpt OPTIONS; [snip] private bool mAutoUpdate = true; private bool mWhiteList = true; private bool mBlackList = true; [snip] public bool AutoUpdate { get { return mAutoUpdate; } set { mAutoUpdate = value; } } public bool WhiteList { get { return mWhiteList; } set { mWhiteList = value; } } public bool BlackList { get { return mBlackList; } set { mBlackList = value; } } [snip] public bool SaveOptions(TCOpt OPTIONS) { [snip] Some things being written out to a file here [snip] Squid soSwGP = new Squid(); soSgP.sqdWriteGlobalConf(OPTIONS); } } File 3: public class SomeClass2 { public bool sqdWriteGlobalConf(TCOpt OPTIONS) { Console.WriteLine(OPTIONS.WhiteSites); // Nothing prints here Console.WriteLine(OPTIONS.BlackSites); // Or here } } Thanks in advance, XO

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  • error LNK2001: unresolved external symbol

    - by numerical25
    I am receiving this error >GXRenderManager.obj : error LNK2001: unresolved external symbol "private: static class GXRenderer * GXRenderManager::renderDevice" (?renderDevice@GXRenderManager@@0PAVGXRenderer@@A) The following is my code... GXDX.h class GXDX: public GXRenderer { public: void Render(); void StartUp(); }; GXGL.h class GXGL: public GXRenderer { public: void Render(); void StartUp(); }; GXRenderer class GXRenderer { public: virtual void Render() = 0; virtual void StartUp() = 0; }; GXRenderManager.h #ifndef GXRM #define GXRM #include <windows.h> #include "GXRenderer.h" #include "GXDX.h" #include "GXGL.h" enum GXDEVICE { DIRECTX, OPENGL }; class GXRenderManager { public: static int Ignite(GXDEVICE); private: static GXRenderer *renderDevice; }; #endif GXRenderManager.cpp #include "GXRenderManager.h" int GXRenderManager::Ignite(GXDEVICE DeviceType) { switch(DeviceType) { case DIRECTX: GXRenderManager::renderDevice = new GXDX; return 1; break; case OPENGL: GXRenderManager::renderDevice = new GXGL; return 1; break; default: return 0; } } main.cpp #include "GXRenderManager.h" int WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow) { return 0; } I am not trying to get it to do anything. I am just trying to compile with no errors. I am new with all this so if anyone can give me a hand. that will be great. thanks

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  • can the python wave module accept StringIO object

    - by user368005
    i'm trying to use the wave module to read wav files in python. whats not typical of my applications is that I'm NOT using a file or a filename to read the wav file, but instead i have the wav file in a buffer. And here's what i'm doing import StringIO buffer = StringIO.StringIO() buffer.output(wav_buffer) file = wave.open(buffer, 'r') but i'm getting a EOFError when i run it... File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 493, in open return Wave_read(f) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 163, in __init__ self.initfp(f) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 128, in initfp self._file = Chunk(file, bigendian = 0) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/chunk.py", line 63, in __init__ raise EOFError i know the StringIO stuff works for creation of wav file and i tried the following and it works import StringIO buffer = StringIO.StringIO() audio_out = wave.open(buffer, 'w') audio_out.setframerate(m.getRate()) audio_out.setsampwidth(2) audio_out.setcomptype('NONE', 'not compressed') audio_out.setnchannels(1) audio_out.writeframes(raw_audio) audio_out.close() buffer.flush() # these lines do not work... # buffer.output(wav_buffer) # file = wave.open(buffer, 'r') # this file plays out fine in VLC file = open(FILE_NAME + ".wav", 'w') file.write(buffer.getvalue()) file.close() buffer.close()

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  • How to avoid multiple, unused has_many associations when using multiple models for the same entity (

    - by mikep
    Hello, I'm looking for a nice, Ruby/Rails-esque solution for something. I'm trying to split up some data using multiple tables, rather than just using one gigantic table. My reasoning is pretty much to try and avoid the performance drop that would come with having a big table. So, rather than have one table called books, I have multiple tables: books1, books2, books3, etc. (I know that I could use a partition, but, for now, I've decided to go the 'multiple tables' route.) Each user has their books placed into a specific table. The actual book table is chosen when the user is created, and all of their books go into the same table. The goal is to try and keep each table pretty much even -- but that's a different issue. One thing I don't particularly want to have is a bunch of unused associations in the User class. Right now, it looks like I'd have to do the following: class User < ActiveRecord::Base has_many :books1, :books2, :books3, :books4, :books5 end class Books1 < ActiveRecord::Base belongs_to :user end class Books2 < ActiveRecord::Base belongs_to :user end First off, for each specific user, only one of the book tables would be usable/applicable, since all of a user's books are stored in the same table. So, only one of the associations would be in use at any time and any other has_many :bookX association that was loaded would be a waste. I don't really know Ruby/Rails does internally with all of those has_many associations though, so maybe it's not so bad. But right now I'm thinking that it's really wasteful, and that there may just be a better, more efficient way of doing this. Is there's some sort of special Ruby/Rails methodology that could be applied here to avoid having to have all of those has_many associations? Also, does anyone have any advice on how to abstract the fact that there's multiple book tables behind a single books model/class?

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  • How to use log4j for a axis2 webservice

    - by KItis
    I have created a simple axis2 webservice to understand logging functionality in a webservice. in this sample webservice, when a client calls this webservice, first it reads the log4j.property file. then i can see the logs being printed on console. but i have included file appender too into the property file. but i can not file the log file any where in my sample webapplication. i am using tomcat to run the webservice. following is webservice interface method called by client. package test; import java.io.IOException; import java.io.InputStream; import java.util.Properties; import org.apache.log4j.BasicConfigurator; import org.apache.log4j.Logger; import org.apache.log4j.PropertyConfigurator; public class WSInterface { static final Logger logger = Logger.getLogger(WSInterface.class); public String log4jTest(String input){ InputStream inputStream = this.getClass().getClassLoader() .getResourceAsStream(input); Properties properties = new Properties(); System.out.println("InputStream is: " + inputStream); //load the inputStream using the Properties try { properties.load(inputStream); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } PropertyConfigurator.configure(properties); logger.debug("Hello World!"); Class myclass = WSInterface.class; String url = myclass.getResource("WSInterface.class").toString(); String output = ""; return url; } }

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