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  • How to make Python check if ftp directory exists?

    - by Phil
    I'm using this script to connect to sample ftp server and list available directories: from ftplib import FTP ftp = FTP('ftp.cwi.nl') # connect to host, default port (some example server, i'll use other one) ftp.login() # user anonymous, passwd anonymous@ ftp.retrlines('LIST') # list directory contents ftp.quit() How do I use ftp.retrlines('LIST') output to check if directory (for example public_html) exists, if it exists cd to it and then execute some other code and exit; if not execute code right away and exit?

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  • Want to show <embed> and <object> tags from YUI editor as a text rather then a video.

    - by user208678
    I am using YUI rich text editor on my website (php/mysql), so that a user may enter textual matter/articles through it. But if a user copies and paste some embed code in the textarea, from any video sites like youtube, it should get saved as a text block and not as a playing video when showing the text content on the browser. Now YUI automatically converts the characters into html entities which ever is needed. Please note that if I put a new line in the yui editor (by pressing "Enter" key), it will be converted into a "<br>" tag in the background and this will not get html entity encoded when passing the value to my backend PHP script. But If I copy and paste any embed tag or for that reason any valid html tags in the textarea, it will be html entity encoded by YUI. Now to support UTF-8 characters, I am using a function (DBVarConv) in my php script before saving it into my database. The code for the function is given below function DBVarConv($var,$isEncoded = false) { if($isEncoded) return addslashes(htmlentities($var, ENT_QUOTES, 'UTF-8', false)); else return htmlentities ($var, ENT_QUOTES, 'UTF-8', false); } $myeditorData = DBVarConv($myeditorData, true); // Save $myeditorData in database. While showing the data in the browser, I am using another function called "smart_html_entity_decode". The code is given below. function smart_html_entity_decode($text, $isAddslashesUsed = false) { if($isAddslashesUsed) $tmp = stripslashes(html_entity_decode($text, ENT_QUOTES, 'UTF-8')); else $tmp = html_entity_decode($text, ENT_QUOTES, 'UTF-8'); if ($tmp == $text) return $tmp; return smart_html_entity_decode($tmp, $isAddslashesUsed); } // Get $myData from database $myData=smart_html_entity_decode($myData, true); echo $myData; The problem is that in doing so, it is also decoding the embed and object tags from their html encoded entities and as a result my obejct tags are shown as a video and not as a simple text. Try using the text editor at tumblr.com. If you paste an embed code in the editor, it will be shown as a text block not as a video. I am trying to build the same functionality on my website with UTF-8 support. Any help will be highly appreciated.

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  • unable to copy release folder to desktop using AppleScript

    - by Miraaj
    Hi all, I tried this script to copy release folder of one of my Xcode projects to desktop: tell application "Finder" set targetFolder to folder "release" of folder "build" of folder "8_15pm" of folder "26th_March" of folder "XYZ" of startup disk set destinationFolder to folder "Desktop" of folder "miraaj" of folder "Users" of startup disk copy targetFolder to destinationFolder end tell I was expecting that I will obtain a folder named as release on my desktop but I did not get any :( Can anyone suggest me where I am wrong or some better way to do this?? Thanks, Miraaj

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  • Programming interface

    - by user309010
    Hi All, I currently building a data collection system [mainly "EFM" - enterprise feed back management] using .NET. I was wondering if there is a possibility to provide the user to script and manipulate the objects - like a programming language but with minor functionalities Thanks

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  • Issue while trying to give a floating effect to a footer bar in IE

    - by Shailesh
    Hi, I'm trying to put a footer bar at the bottom of the browser no matter what the length of the content is. The footer bar should always be visible to the user and should be on the top layer. Following is my code: <html> <head> <style type="text/css"> #wrapper { width: 910px; margin: 0 auto; padding: 0px 20px 50px 20px; text-align: left; } #footer-wrapper { -moz-background-clip:border; -moz-background-inline-policy:continuous; -moz-background-origin:padding; bottom:0; clear:both; font-size:11px !important; left:0; position:fixed; white-space:nowrap; width:100%; z-index:8000; } </style> <script> var counter = 0; function addContent(ctr) { document.getElementById(ctr).innerHTML=document.getElementById (ctr).innerHTML+" dynaContent"+counter; counter++; } </script> </head> <body> <div> <div><input type="button" onclick="addContent('wrapper')" value="Add dynaContent" /></div> <div id="wrapper" style="color:#FFFFFF; background-color: #111111;"> STATIC TEXT - HEADER-WRAPPER </div> <div style="color:#FFFFFF;background-color: #555555;">STATIC TEXT - FOOTER-WRAPPER</div> </div> </body> </html> It's working fine in Mozilla Firefox and giving the intended results, but, in IE, the footer bar always sticks just under the header. Please help. Thanks in advance, Shailesh.

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  • PHP Increasing write to page speed.

    - by Frederico
    I'm currently writing out xml and have done the following: header ("content-type: text/xml"); header ("content-length: ".strlen($xml)); $xml being the xml to be written out. I'm near about 1.8 megs of text (which I found via firebug), it seems as the writing is taking more time than the script to run.. is there a way to increase this write speed? Thank you in advance.

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  • problem with printf() function

    - by Syom
    i have the variable $a = 5; i want to show it in binary form, with length, equal 8, with writing * at white spaces, just like this, like this * * * * *101 here the script $number = 5; printf("%*8b", $number); it doesn't work with *, but if "0"-s it works printf("%08b", $number); //returns 00000101 why it doesn't work with *?

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  • Animation using AniMate with Unity3D doesn't interact with physical objects

    - by Albz
    I'm designing a maze with Unity3D. The maze has a number of bifurcations and the player will stop before each bifurcation and simply choose left or right. Then an automatic animation will move the player through the next bifurcation till the end of the maze (or till a dead end). To animate the player I'm using AniMate and C# in my Unity project. Using AniMate I'm simply creating a point-to-point animation for each bifurcation (e.g. mage below: from the start/red arrow to point 5) My problem is that my animation script (associated to the "First Person Controller") is not working properly since physics is not respected (the player passes through walls). If in the same project I enable the standard character controls in Unity, then I can navigate in the maze with the physical contrains of walls etc... (i.e. I have colliders). This is an example of the code I'm using when I press left to pass from starting point, trough point 1 to point 2: void FixedUpdate () { if (Input.GetKey(KeyCode.LeftArrow)) { //To point 1 Hashtable props = new Hashtable(); props.Add("position", new Vector3(756f,112f,1124f)); props.Add("physics", true); Ani.Mate.To(transform, 2, props); //To point 2 Hashtable props2 = new Hashtable(); props2.Add("position", new Vector3(731f,112f,1124f)); props2.Add("physics", true); Ani.Mate.To(transform, 2, props2); } } What happens practically when I press the left arrow button is that the player moves directly to point 2 using a straight line passing through the wall. I tried to pass to AniMate "Physics = true" but it doesn't seem to help. Any idea on how to solve this issue? Alternatively... any hint on how to have a more optimized code and just use a series of vector3 coordinates (one for each point) to obtain the simple animation I want without having to declare new Hashtable(); etc... every time? I chose AniMate simply because 1. I'm a beginner with Unity 2. I don't need complex animations (e.g. I don't need to use iTween), just fixed animations along straight lines and I need something really simple and quick to implement in a script. However, if someone has an equally simple solution it will be welcome. thank you in advance for your help

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  • how to copy files from TFS to clear case??

    - by barry
    Can i use powershell script to copy a set of files from a folder to Clear Case..?? i have the task of synchronising files from TFS to Clear Case.. like i need to take a set of files aftr a certain date from tfs server and synchronise these files to Clear case..

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  • Escaping Code for Different Shells

    - by Jon Purdy
    Question: What characters do I need to escape in a user-entered string to securely pass it into shells on Windows and Unix? What shell differences and version differences should be taken into account? Can I use printf "%q" somehow, and is that reliable across shells? Backstory (a.k.a. Shameless Self-Promotion): I made a little DSL, the Vision Web Template Language, which allows the user to create templates for X(HT)ML documents and fragments, then automatically fill them in with content. It's designed to separate template logic from dynamic content generation, in the same way that CSS is used to separate markup from presentation. In order to generate dynamic content, a Vision script must defer to a program written in a language that can handle the generation logic, such as Perl or Python. (Aside: using PHP is also possible, but Vision is intended to solve some of the very problems that PHP perpetuates.) In order to do this, the script makes use of the @system directive, which executes a shell command and expands to its output. (Platform-specific generation can be handled using @unix or @windows, which only expand on the proper platform.) The problem is obvious, I should think: test.htm: <!-- ... --> <form action="login.vis" method="POST"> <input type="text" name="USERNAME"/> <input type="password" name="PASSWORD"/> </form> <!-- ... --> login.vis: #!/usr/bin/vision # Think USERNAME = ";rm -f;" @system './login.pl' { USERNAME; PASSWORD } One way to safeguard against this kind of attack is to set proper permissions on scripts and directories, but Web developers may not always set things up correctly, and the naive developer should get just as much security as the experienced one. The solution, logically, is to include a @quote directive that produces a properly escaped string for the current platform. @system './login.pl' { @quote : USERNAME; @quote : PASSWORD } But what should @quote actually do? It needs to be both cross-platform and secure, and I don't want to create terrible problems with a naive implementation. Any thoughts?

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  • how to display user name in login name control

    - by user569285
    I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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  • Defaults for null values

    - by OldFart
    Working on a Powershell script I had several places where I wanted A unless it was null, else B. Essentially the ?? operator in C#. I ended up writing the function shown below, but I can't help but think there is a built-in way to do this. Is there a better, built-in, way? function Get-ValueOrDefault() { foreach ($value in $args) { if ($value -ne $null) { return $value } } } I think this works better: function Get-ValueOrDefault() { $args | select -first 1 }

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  • Custom Grails plugin dependency

    - by ankimal
    I have a custom grails plugin I m trying to develop and set this def dependsOn = [tomcat: "1.0"] in the Plugin script. Now, my custom plugin loads just fine but I dont see tomcat installed in my application. How does one install a dependency plugin (prompt the user to say yes/no)? Is this even possible?

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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