Search Results

Search found 39406 results on 1577 pages for 'two legged'.

Page 595/1577 | < Previous Page | 591 592 593 594 595 596 597 598 599 600 601 602  | Next Page >

  • MySQL index building performance

    - by Christian
    I tried to build an index over a two columns of a 30,000,000 entry database. I canceled the process after ~60hr as it didn't seem to work. For some reason MySQL takes only 22 mb ram instead of using the RAM fully. Is index building an operation that needs no Ram or is there some way to tell MySQL to use more RAM to be faster?

    Read the article

  • Enable/Disable WPF buttons depending on the number of clicks

    - by eibhrum
    I have two buttons 'btnPrev' and 'btnNext' What I want to do is to be able to determine the number of clicks of the button so that I could enable and disable them. The process is almost similar to 'paging' method. Initial state: btnPrev - disabled, btnNext - enabled 1st Click (btnNext): btnPrev - enabled, btnNext - enabled 2nd Click (btnNext): btnPrev - enabled, btnNext - enabled 3rd Click (btnNext): btnPrev - enabled, btnNext - disabled the idea is almost the same vice-versa (for btnPrev).

    Read the article

  • Perl String operations

    - by imerez
    I have a string with the following e.g. $workingFile = '/var/tmp/A/B/filename.log.timestamps.etc'; And two strings representing a dirs e.g. $dir = '/var/tmp'; $newDir = '/users/asdf'; I'd like to get the following: '/users/asdf/A/B/filename.log.timestamps.etc' However my Perl isnt up to much .. any pointers ? Thanks W

    Read the article

  • How Can I create different selectors for accepting new connection in java NIO

    - by Deepak
    I want to write java tcp socket programming using java NIO. Its working fine. But I am using the same selector for accepting reading from and writing to the clients. How Can I create different selectors for accepting new connection in java NIO, reading and writing. Is there any online help. Actually when I am busy in reading or writing my selector uses more iterator. So If more number of clients are connected then performance of accepting new coneection became slow. But I donot want the accepting clients to be slow // Create a selector and register two socket channels Selector selector = null; try { // Create the selector selector = Selector.open(); // Create two non-blocking sockets. This method is implemented in // e173 Creating a Non-Blocking Socket. SocketChannel sChannel1 = createSocketChannel("hostname.com", 80); SocketChannel sChannel2 = createSocketChannel("hostname.com", 80); // Register the channel with selector, listening for all events sChannel1.register(selector, sChannel1.validOps()); sChannel2.register(selector, sChannel1.validOps()); } catch (IOException e) { } // Wait for events while (true) { try { // Wait for an event selector.select(); } catch (IOException e) { // Handle error with selector break; } // Get list of selection keys with pending events Iterator it = selector.selectedKeys().iterator(); // Process each key at a time while (it.hasNext()) { // Get the selection key SelectionKey selKey = (SelectionKey)it.next(); // Remove it from the list to indicate that it is being processed it.remove(); try { processSelectionKey(selKey); } catch (IOException e) { // Handle error with channel and unregister selKey.cancel(); } } } public void processSelectionKey(SelectionKey selKey) throws IOException { // Since the ready operations are cumulative, // need to check readiness for each operation if (selKey.isValid() && selKey.isConnectable()) { // Get channel with connection request SocketChannel sChannel = (SocketChannel)selKey.channel(); boolean success = sChannel.finishConnect(); if (!success) { // An error occurred; handle it // Unregister the channel with this selector selKey.cancel(); } } if (selKey.isValid() && selKey.isReadable()) { // Get channel with bytes to read SocketChannel sChannel = (SocketChannel)selKey.channel(); // See e174 Reading from a SocketChannel } if (selKey.isValid() && selKey.isWritable()) { // Get channel that's ready for more bytes SocketChannel sChannel = (SocketChannel)selKey.channel(); } } Thanks Deepak

    Read the article

  • Problem making local copy of a webpage

    - by Claudiu
    I want to run this chrome experiment locally. I copied the .html and .js files, along with the two .jpgs that the demo uses. However, when I run it off my local drive, Chrome gives this error: light.js:89 - Uncaught Error: SECURITY_ERR: DOM Exception 18 Line 89 returns the image data from the canvas after drawing the image to it. What's causing this security exception? It seems to not be Chrome-specific, as Firefox gives the same error.

    Read the article

  • communicating swf files.

    - by Addis Abebayehu
    I have two swf files I would like communicate. I have a videoplaylist.swf and a player.swf. I would like to select a video from videoplaylist.swf and have it played in the player.swf. How do I do that? How am I going to dispatch the click event with the video url to the player.swf? from the videoplaylist.swf. Please help.

    Read the article

  • What is the web.debug.config and web.release.config file for?

    - by chobo
    Hi, I just upgraded to VS 2010 and MVC 2.0 and I noticed the web.config has two additional files attached to it? Are thee files used to specify debug and release specific settings, so you don't clutter up the main web.config? Does it even make sense to place a connection string in the root web.config file if I have have a local and remote one in the debug and release web.configs respectively. Thanks!

    Read the article

  • Android MapView: Disable auto zoom

    - by Ola Andersson
    Hi. I have made an Android app that shows a MapView with two overlays, one MyLocationOverlay and one custom overlay. I am programmatically zooming and panning to what I want the map to show. It also auto pans to my current location. The auto pan is moving the map away from what I want to show. So my question is simply: How can I disable the auto pan? Thanks, Ola

    Read the article

  • Java: minimum number of operations for conjunctive inequalities?

    - by HH
    I try to simplify conditionals in for (int t=0,size=fo.getPrintViewsPerFile().size();t<size&&t<countPerFile;t++){, more precisely: t<s&&t<c You need to compare two times, then calc the boolean value from them. Is there any simpler way to do it? If no, how can you prove it? I can simplify it to some extent, proof tree.

    Read the article

  • Foreign key,local key?

    - by user198729
    CREATE TABLE products ( id integer unsigned auto_increment primary key ) ENGINE=INNODB; CREATE TABLE orders ( id integer PRIMARY KEY auto_increment, product_id integer unsigned, quantity integer, INDEX product_id_idx (product_id), FOREIGN KEY (product_id) REFERENCES products (id) ) ENGINE=INNODB; Here the products and orders obviously have some kind of relation--foreign key relation. Also a coin has two sides,so I'm doubting how do we say which table is the foreign key side or local key side?

    Read the article

  • about sending messages among bg.html, popup.html and contentscript.js

    - by T_t
    Hi!:) In my extension, when a button named "mybutton1" in the popup.html is clicked, it sends a message "getvar1" to the contentscript.js, then the contentscript.js sends a message "i want var1" to the background.html to get an object named "var1".If the button named "mybutton2" is clicked, the contentscript.js gets the "var2" object. How should i do under this condition? What's more, i am a little confused about the chrome.extension.onRequest.addListener method and chrome.extension.sendRequest method.Could someone tell me the mechanism of the two methods? Thanks!

    Read the article

  • How to create a 2D map in Java?

    - by Roman
    I would like to have a mapping which maps two string into one string. For example: map["MainServer","Status"] return "active". What is the best way to do it in Java. Should I use HashMap which include another HashMap as its elements?

    Read the article

  • HMVC/PAC - how to handle shared abstractions/models?

    - by fig-gnuton
    In HMVC/PAC, what's the recommended way to code if two or more triads/agents share a common model/abstraction? Do you instantiate a new instance of that model wherever needed, and propogate a change in one to all the other instances via the controllers? Or do instantiate one model at some common upper level, and inject that instance wherever needed? (Or neither if I'm missing something fundamental about these patterns?)

    Read the article

  • iPhone localization - some localized XIBs do not load

    - by Jacek
    Hello, I have made an iPhone app with localized versions. It mostly works fine, but there are two views in which localized NIBs do not load. Standard NIBs (in English) are used. I am sure I made localization properly ("Get Info", "Make file localizable", "Add Localization", added "pl" - for Polish, and then edited created NIB). All the other views are fine. What might be the problem? Thanks for helping me.

    Read the article

  • Proper binding data to combobox and handling its events.

    - by Wodzu
    Hi guys. I have a table in SQL Server which looks like this: ID Code Name Surname 1 MS Mike Smith 2 JD John Doe 3 UP Unknown Person and so on... Now I want to bind the data from this table into the ComboBox in a way that in the ComboBox I have displayed value from the Code column. I am doing the binding in this way: SqlDataAdapter sqlAdapter = new SqlDataAdapter("SELECT * FROM dbo.Users ORDER BY Code", MainConnection); sqlAdapter.Fill(dsUsers, "Users"); cbxUsers.DataSource = dsUsers.Tables["Users"]; cmUsers = (CurrencyManager)cbxUsers.BindingContext[dsUsers.Tables["Users"]]; cbxUsers.DisplayMember = "Code"; And this code seems to work. I can scroll through the list of Codes. Also I can start to write code by hand and ComboBox will autocomplete the code for me. However, I wanted to put a label at the top of the combobox to display Name and Surname of the currently selected user code. My line of though was like that: "So, I need to find an event which will fire up after the change of code in combobox and in that event I will get the current DataRow..." I was browsing through the events of combobox, tried many of them but without a success. For example: private void cbxUsers_SelectionChangeCommitted(object sender, EventArgs e) { if (cmUsers != null) { DataRowView drvCurrentRowView = (DataRowView)cmUsers.Current; DataRow drCurrentRow = drvCurrentRowView.Row; lblNameSurname.Text = Convert.ToString(drCurrentRow["Name"]) + " " + Convert.ToString(drCurrentRow["Surname"]); } } This give me a strange results. Firstly when I scroll via mouse scroll it doesn't return me the row wich I am expecting to obtain. For example on JD it shows me "Mike Smith", on MS it shows me "John Doe" and on UP it shows me "Mike Smith" again! The other problem is that when I start to type in ComboBox and press enter it doesn't trigger the event. However, everything works as expected when I bind data to lblNameSurname.Text in this way: lblNameSurname.DataBindings.Add("Text", dsusers.Tables["Users"], "Name"); The problem here is that I can bind only one column and I want to have two. I don't want to use two labels for it (one to display name and other to display surname). So, what is the solution to my problem? Also, I have one question related to the data selection in ComboBox. Now, when I type something in the combobox it allows me to type letters that are not existing in the list. For example, I start to type "J" and instead of finishing with "D" so I would have "JD", I type "Jsomerandomtexthere". Combobox will allow that but such item does not exists on the list. In other words, I want combobox to prevent user from typing code which is not on the list of codes. Thanks in advance for your time.

    Read the article

  • WPF Grid scroll

    I want to create two grids in the WPF Page. One grid need scrollbar or scroll viewer. Another grid is static.The grids are placed one by one in the page. How to create and set the scroll in first grid.? plz explain me.

    Read the article

  • What is a .NET app domain?

    - by Luke
    In particular, what are the implications of running code in two different app domains? How is data normally passed across the app domain boundary? Is it the same as passing data across the process boundary? I'm curious to know more about this abstraction and what it is useful for. EDIT: Good existing coverage of AppDomains in general at http://stackoverflow.com/questions/622516/i-dont-understand-appdomains

    Read the article

  • Helping using FirePHP to debug a .php application

    - by Angela
    Hi, just set up FirePHP and using a framework called Qcodo / Qcubed. Has anyone heard of these on SO? Been having challenges debugging -- trying to do a fairly simple new() and save() and then output via Ajax but not getting any kind of responsiveness from errors. Any help for us, two of us have checked it out but can't seem to get a response. Thanks! BTW, here's the class which seems to be creating the problems: http://github.com/allyforce/AF-upload/blob/master/Library/Target1.class.php

    Read the article

  • How to create a "facade" table?

    - by tputkonen
    A legacy database contains a join table which links tables table1 and table2, and contains just two foreign keys: TABLE_ORIG: table1_id table2_id In order to utilize this table using JPA I would need to create a surrogate primary key to the link table. However, the existing table must not be modified at all. I would like to create another table which would contain also a primary key in addition to the foreign keys: TABLE_NEW: id table1_id table2_id All changes to TABLE_ORIG should be reflected in TABLE_NEW, and vice versa. Is this doable in mysql?

    Read the article

  • javascript associative array length using jquery

    - by Prashant
    Hello All I am using javascript associative array like: var testarray = []; testarray['one'] = '1'; testarray['two'] = '2'; testarray['three'] = '3'; I am also using jquery alongside. How can I check length of this associative array using jquery or any other method? Basically i want to check whether this array is empty or not. Thank you.

    Read the article

< Previous Page | 591 592 593 594 595 596 597 598 599 600 601 602  | Next Page >