Search Results

Search found 1510 results on 61 pages for 'barycentric coordinates'.

Page 7/61 | < Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >

  • XNA - Mouse coordinates to word space transformation

    - by Gabriel Butcher
    I have a pretty annoying problem. I would like to create a drawing program, using winform + XNA combo. The most important part would be to transform the mouse position into the XNA drawn grid - I was able to make it for the translations, but it only work if I don't zoom in - when I do, the coordinates simply went horrible wrong. And I have no idea what I doing wrong. I tried to transform with scaling matrix, transform with inverse scaling matrix, multiplying with zoom, but none seems to work. In the beginning (with zoom value = 1) the grid starts from (0,0,0) going to (Width, Height, 0). I was able to get coordinates based on this grid as long as the zoom value didn't changed at all. I using a custom shader, with orthographic projection matrix, identity view matrix, and the transformed world matrix. Here is the two main method: internal void Update(RenderData data) { KeyboardState keyS = Keyboard.GetState(); MouseState mouS = Mouse.GetState(); if (ButtonState.Pressed == mouS.RightButton) { camTarget.X -= (float)(mouS.X - oldMstate.X) / 2; camTarget.Y += (float)(mouS.Y - oldMstate.Y) / 2; } if (ButtonState.Pressed == mouS.MiddleButton || keyS.IsKeyDown(Keys.Space)) { zVal += (float)(mouS.Y - oldMstate.Y) / 10; zoom = (float)Math.Pow(2, zVal); } oldKState = keyS; oldMstate = mouS; world = Matrix.CreateTranslation(new Vector3(-camTarget.X, -camTarget.Y, 0)) * Matrix.CreateScale(zoom / 2); } internal PointF MousePos { get { Vector2 mousePos = new Vector2(Mouse.GetState().X, Mouse.GetState().Y); Matrix trans = Matrix.CreateTranslation(new Vector3(camTarget.X - (Width / 2), -camTarget.Y + (Height / 2), 0)); mousePos = Vector2.Transform(mousePos, trans); return new PointF(mousePos.X, mousePos.Y); } } The second method should return the coordinates of the mouse cursor based on the grid (where the (0,0) point of the grid is the top-left corner.). But is just don't work. I deleted the zoom transformation from the matrix trans, as I didnt was able to get any useful result (most of the time, the coordinates was horrible wrong, mostly many thousand when the grid's size is 500x500). Any idea, or suggestion? I trying to solve this simple problem for two days now :\

    Read the article

  • Monitoring GPS Coordinates

    - by Suriyan Suresh
    I need to monitor GPS Coordinates changes at every 15 min and take action based on that. as per bada developer guide report "only one application allowed to run at a time if another application try to run first one is closed" .so that how do i monitor GPS coordinates without interruption from other applications. how do i keep my application running at all times

    Read the article

  • retrieving of coordinates from google search?

    - by cheesebunz
    Is there anyway of retrieving coordinates through google search? right now my search is able to have markers on the map, but however i do not have any idea how to retrieve coordinates through just the search api alone. I have a html page named mapsToolKit.html and two js scripts with maps.js and search.js, i want the coding to be in search.js, so far i have managed to done in the maps section but is there anyway to retrieve it back through the search.js part?

    Read the article

  • Calculate coordinates between startpoint and endpoint

    - by MikeB123
    Given.. 1 - The start-point GPS coordinates, 2 - The end-point GPS coordinates, 3 - The speed at which the object is travelling, 4 - Knowing that the trip trajectory will be a straight line... How can I calculate what my GPS coordinated will be in n minutes' time? That is to say, how can I calculate my position at a given time after the trip has started before the trip has ended?

    Read the article

  • Converting OpenGL coordinates to lower UIView (and UIImagePickerController)

    - by John Qualis
    I am new to OpenGL on the iPhone. I am developing an iPhone app similar to a barcode reader but with an extra OpenGL layer. The bottommost layer is UIImagePickerController, then I use UIView on top and draw a rectangle at certain coordinates on the iPhone screen. So far everything is OK. Then I am trying to draw an OpenGL 3-D model in that rectangle. I am able to load a 3-D model in the iPhone based on this code here - http://iphonedevelopment.blogspot.com/2008/12/start-of-wavefront-obj-file-loader.html I am not able to transform the coordinates of the rectangle into OpenGL coordinates. Appreciate any help. Do I need to use a matrix to translate the currentPosition of the 3-D model so it is drawn within myRect? The code is given below. -(void)setupView:(GLView*)view { const GLfloat zNear = 0.01, zFar = 1000.0, fieldOfView = 45.0; GLfloat size; glEnable(GL_DEPTH_TEST); glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect = view.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glClearColor(0.0f, 0.0f, 0.0f, 0.0f); NSString *path = [[NSBundle mainBundle] pathForResource:@"plane" ofType:@"obj"]; OpenGLWaveFrontObject *theObject = [[OpenGLWaveFrontObject alloc] initWithPath:path]; Vertex3D position; position.z = -8.0; position.y = 3.0; position.x = 2.0; theObject.currentPosition = position; self.plane = theObject; [theObject release]; } - (void)drawView:(GLView*)view; { static GLfloat rotation = 0.0; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glLoadIdentity(); glColor4f(0.0, 0.5, 1.0, 1.0); // the coordinates of the rectangle are // myRect.x, myRect.y, myRect.width, myRect.height // Do I need to use a matrix to translate the currentPosition of the // 3-D model so it is drawn within myRect? //glOrthof(-160.0f, 160.0f, -240.0f, 240.0f, -1.0f, 1.0f); [plane drawSelf]; }

    Read the article

  • Find the end/finish coordinates you a UISwipeGestureRecognizer

    - by Code
    I can find the start coordinates of where a swipe starts by doing the following - (void)oneFingerSwipeUp:(UISwipeGestureRecognizer *)recognizer { CGPoint point = [recognizer locationInView:[self view]]; NSLog(@"Swipe up - start location: %f,%f", point.x, point.y); } Is it possible to find the coordinates where the swipe ended? I looked into the docs and its not mentioned. Is there some work around for this? Many Thanks, -Code

    Read the article

  • Flex - How do I get the absolute X and Y coordinate including HTML offset?

    - by Mauricio
    Hey everyone, I am calling a JS function through the ExternalInterface using Flex which requires the absolute X and Y coordinates to create a pop-up menu. The Flex application is displayed on the center of an HTML page, therefore there is an HTML X and Y offset to consider. I have tried using the LocalToGlobal and ContentToGlobal functions, but these are just giving me the X and Y coordinates relative to the Flex application, it is not considering the HTML X and Y offset of having the Flex app in the center of the page or varying different screen resolutions. Is the best approach to retrieve the HTML X and Y offset using JavaScript? Is there a Flex function I can use that provides the absolute X and Y coordinates based on the HTML page? Thanks!

    Read the article

  • WPF / C#: Transforming coordinates from an image control to the image source

    - by Gabriel
    I'm trying to learn WPF, so here's a simple question, I hope: I have a window that contains an Image element bound to a separate data object with user-configurable Stretch property <Image Name="imageCtrl" Source="{Binding MyImage}" Stretch="{Binding ImageStretch}" /> When the user moves the mouse over the image, I would like to determine the coordinates of the mouse with respect to the original image (before stretching/cropping that occurs when it is displayed in the control), and then do something with those coordinates (update the image). I know I can add an event-handler to the MouseMove event over the Image control, but I'm not sure how best to transform the coordinates: void imageCtrl_MouseMove(object sender, MouseEventArgs e) { Point locationInControl = e.GetPosition(imageCtrl); Point locationInImage = ??? updateImage(locationInImage); } Now I know I could compare the size of Source to the ActualSize of the control, and then switch on imageCtrl.Stretch to compute the scalars and offsets on X and Y, and do the transform myself. But WPF has all the information already, and this seems like functionality that might be built-in to the WPF libraries somewhere. So I'm wondering: is there a short and sweet solution? Or do I need to write this myself? EDIT I'm appending my current, not-so-short-and-sweet solution. Its not that bad, but I'd be somewhat suprised if WPF didn't provide this functionality automatically: Point ImgControlCoordsToPixelCoords(Point locInCtrl, double imgCtrlActualWidth, double imgCtrlActualHeight) { if (ImageStretch == Stretch.None) return locInCtrl; Size renderSize = new Size(imgCtrlActualWidth, imgCtrlActualHeight); Size sourceSize = bitmap.Size; double xZoom = renderSize.Width / sourceSize.Width; double yZoom = renderSize.Height / sourceSize.Height; if (ImageStretch == Stretch.Fill) return new Point(locInCtrl.X / xZoom, locInCtrl.Y / yZoom); double zoom; if (ImageStretch == Stretch.Uniform) zoom = Math.Min(xZoom, yZoom); else // (imageCtrl.Stretch == Stretch.UniformToFill) zoom = Math.Max(xZoom, yZoom); return new Point(locInCtrl.X / zoom, locInCtrl.Y / zoom); }

    Read the article

  • Transforming coordinates from an image control to the image source in WPF

    - by Gabriel
    I'm trying to learn WPF, so here's a simple question, I hope: I have a window that contains an Image element bound to a separate data object with user-configurable Stretch property <Image Name="imageCtrl" Source="{Binding MyImage}" Stretch="{Binding ImageStretch}" /> When the user moves the mouse over the image, I would like to determine the coordinates of the mouse with respect to the original image (before stretching/cropping that occurs when it is displayed in the control), and then do something with those coordinates (update the image). I know I can add an event-handler to the MouseMove event over the Image control, but I'm not sure how best to transform the coordinates: void imageCtrl_MouseMove(object sender, MouseEventArgs e) { Point locationInControl = e.GetPosition(imageCtrl); Point locationInImage = ??? updateImage(locationInImage); } Now I know I could compare the size of Source to the ActualSize of the control, and then switch on imageCtrl.Stretch to compute the scalars and offsets on X and Y, and do the transform myself. But WPF has all the information already, and this seems like functionality that might be built-in to the WPF libraries somewhere. So I'm wondering: is there a short and sweet solution? Or do I need to write this myself? EDIT I'm appending my current, not-so-short-and-sweet solution. Its not that bad, but I'd be somewhat suprised if WPF didn't provide this functionality automatically: Point ImgControlCoordsToPixelCoords(Point locInCtrl, double imgCtrlActualWidth, double imgCtrlActualHeight) { if (ImageStretch == Stretch.None) return locInCtrl; Size renderSize = new Size(imgCtrlActualWidth, imgCtrlActualHeight); Size sourceSize = bitmap.Size; double xZoom = renderSize.Width / sourceSize.Width; double yZoom = renderSize.Height / sourceSize.Height; if (ImageStretch == Stretch.Fill) return new Point(locInCtrl.X / xZoom, locInCtrl.Y / yZoom); double zoom; if (ImageStretch == Stretch.Uniform) zoom = Math.Min(xZoom, yZoom); else // (imageCtrl.Stretch == Stretch.UniformToFill) zoom = Math.Max(xZoom, yZoom); return new Point(locInCtrl.X / zoom, locInCtrl.Y / zoom); }

    Read the article

  • Flex Sprite xy Coordinates

    - by Ian
    Hi, I have a drawing that looks more or less like the attached image. image The orange square is the currently selected selected sprite. The sprites are all draws from coordinates that i receive from XML. var sprObject:Sprite = new Sprite(); sprObject.graphics.beginFill(itemList.c.toString()); sprObject.name = strName; sprObject.graphics.moveTo(iX, iY); sprObject.graphics.lineTo(iX2, iY2); sprObject.graphics.lineTo(iX3, iY3); sprObject.graphics.lineTo(iX4, iY4); sprObject.graphics.lineTo(iX, iX); sprObject.graphics.endFill(); mainUI.addChild(sprObject); // mainUI is a mx:UIComponent g_Sprite.push(sprObject); // array of sprites. What I want to do is the following. If I'm currently on the orange square and I use my keyboard direction buttons (up/down/left/right). I want to deselect the current sprite and select the next sprite in the appropriate direction. The problem I'm having is that I cannot get the x and y coordinates of the drawn sprites. If I look in the array, the x and y coordinates of the sprites are all 0. If I can retrieve that I can write an algorithm to determine the next sprite to select. Any help would be appreciated.

    Read the article

  • Draw rectangle using latitude/longitude on screen

    - by jamesM
    The existing application is providing me 8 coordinates like NElatitude, NElongitude, NWlatitude, NWlongitude, SElatitude, SElongitude, SWlatitude, SWlongitude and I have been asked to draw rectangles on screen using these coordinates as screen points. These rectangles should be with scaling. Thank you for your help. JamesM

    Read the article

  • draw rectangel using latitude\longitude on screen

    - by jamesM
    the existing Application is providing me 8 coordinates like NElatitude,NElongitude, NWlatitude,NWlongitude, SElatitude,SElongitude, SWlatitude,SWlongitudepoints and i have been asked draw rectangles on screen using this coordinates as a screen points. These rectangles should be with scaling. thank you for your help JamesM

    Read the article

  • crashing out in a while loop python

    - by Edward
    How to solve this error? i want to pass the values from get_robotxya() and get_ballxya() and use it in a loop but it seems that it will crash after awhile how do i fix this? i want to get the values whithout it crashing out of the while loop import socket import os,sys import time from threading import Thread HOST = '59.191.193.59' PORT = 5555 COORDINATES = [] def connect(): globals()['client_socket'] = socket.socket(socket.AF_INET, socket.SOCK_STREAM) client_socket.connect((HOST,PORT)) def update_coordinates(): connect() screen_width = 0 screen_height = 0 while True: try: client_socket.send("loc\n") data = client_socket.recv(8192) except: connect(); continue; globals()['COORDINATES'] = data.split() if(not(COORDINATES[-1] == "eom" and COORDINATES[0] == "start")): continue if (screen_width != int(COORDINATES[2])): screen_width = int(COORDINATES[2]) screen_height = int(COORDINATES[3]) return def get_ballxy(): update_coordinates() ballx = int(COORDINATES[8]) bally = int(COORDINATES[9]) return ballx,bally def get_robotxya(): update_coordinates() robotx = int(COORDINATES[12]) roboty = int(COORDINATES[13]) angle = int(COORDINATES[14]) return robotx,roboty,angle def print_ballxy(bx,by): print bx print by def print_robotxya(rx,ry,a): print rx print ry print a def activate(): bx,by = get_ballxy() rx,ry,a = get_robotxya() print_ballxy(bx,by) print_robotxya(rx,ry,a) Thread(target=update_coordinates).start() while True: activate() this is the error i get:

    Read the article

  • Setting the origin to center of the screen instead of the top left screen?(iPhone)

    - by thyrgle
    Hi, I am working on an iPhone app and I am trying to make something that has to do with line-circle collision detection. I am using the slope of the line and checking if the coordinates of a circle suffice the equation y = mx + b. But, with the current origin (0,0) at the top left it is a pain to get the slope. Any way I can convert the coordinates so the origin is in the center of the screen?

    Read the article

  • Best practice to calculate the average speed from GPS coordinates

    - by Sebi
    i have here a device which can give me gps coordinates. the time intervall i can define. i want to use it to calculate the average speed during driving or travelling by car. actually i used a orthodrome formula to calculate the distance between two points and then divided it by the given time intervall. by the implemenation i followed this term (http://de.wikipedia.org/wiki/Orthodrome#Genauere_Formel_zur_Abstandsberechnung_auf_der_Erde). Unfortunately i could only find a german link, but i think the formula should be understandable in any language ;) Unfortunately, using this formula and a time intverall of 1 seconds gives very unprecises results. the speed while walking is between 1 km/h and 20km/h. So i wonder if there is a general reference how to implement distance calculation between two gps coordinates (i found something similar on SO) and particulary, which is the best time intervall to update the GPS coordiantes.

    Read the article

  • Cropping an image, saving output to a new file and get crop coordinates

    - by synic
    I'm interfacing with a service that allows you to upload an image, and also upload coordinates of a thumbnail of that image. I'm thinking that (if there isn't some sort of prefab Activity specifically for this) that I can use Android's crop utility. The only problem is that I can't overwrite the original file, the crop window needs to have a custom message (instead of "crop image"), and I'll need the coordinates of the crop. Is this possible? Is there another way to do this without writing my own Activity?

    Read the article

  • How to change handedness of coordinates?

    - by 742
    How to convert from Euler's coordinates E1 = (x1, y1, z1, yaw1, pitch1, roll1) to E2 = (x2, y2, z2, yaw2, pitch2, roll2) where x, y, z are the coordinates of a point and yaw, pitch, roll the direction/orientation of a vector which origin is the point. yaw is around y, pitch around x, roll around z. They are performed in that order. Yaw 0 is normal to the plan xy (opposite to z in E1 and equal to z in E2). E1 uses a right handed space and E2 a left handed space. Both have the same origin, the same direction for y (top) and z (into the screen). They differ by x which is to the left on E1 and to the right on E2. They also differ by their direction of positive rotations. I've a custom type to hold the scalar representation and to convert from and to the equivalent WPF Matrix3d representation.

    Read the article

< Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >