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• JPA/Hibernate Embedded id and fields

  - by RoD

  I would like to do something like that: An object ReportingFile that can be a LogRequest or a LogReport file. ( both got the same structure) An object Reporting containing for one logRequest, a list of logReport with a date. An example (not working) would be: @Entity @AssociationOverride( name="logRequest.fileName", joinColumns = { @JoinColumn(name="log_request_file_name") } ) public class Reporting { @EmbeddedId private ReportingFile logRequest; @CollectionOfElements(fetch = FetchType.EAGER) @JoinTable(name = "t_reports", schema="", joinColumns = {@JoinColumn(name = "log_report")}) @Fetch(FetchMode.SELECT) private List<ReportingFile> reports; @Column(name="generated_date",nullable=true) private Date generatedDate; [...] } @Embeddable public class ReportingFile { @Column(name="file_name",length=255) private String fileName; @Column(name="xml_content") private Clob xmlContent; [...] } In this sample, i have a the following error: 15.03.2010 16:37:59 [ERROR] org.springframework.web.context.ContextLoader Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor#0' defined in class path resource [config/persistenceContext.xml]: Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [config/persistenceContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: test] Unable to configure EntityManagerFactory at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:480) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:221) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:881) at org.springframework.context.support.AbstractApplicationContext.registerBeanPostProcessors(AbstractApplicationContext.java:597) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:366) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3843) at org.apache.catalina.core.StandardContext.start(StandardContext.java:4350) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045) at org.apache.catalina.core.StandardHost.start(StandardHost.java:719) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045) at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443) at org.apache.catalina.core.StandardService.start(StandardService.java:516) at org.apache.catalina.core.StandardServer.start(StandardServer.java:710) at org.apache.catalina.startup.Catalina.start(Catalina.java:578) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:413) Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [config/persistenceContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: test] Unable to configure EntityManagerFactory at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1337) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:221) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBeansOfType(DefaultListableBeanFactory.java:308) at org.springframework.beans.factory.BeanFactoryUtils.beansOfTypeIncludingAncestors(BeanFactoryUtils.java:270) at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.detectPersistenceExceptionTranslators(PersistenceExceptionTranslationInterceptor.java:122) at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.<init>(PersistenceExceptionTranslationInterceptor.java:78) at org.springframework.dao.annotation.PersistenceExceptionTranslationAdvisor.<init>(PersistenceExceptionTranslationAdvisor.java:70) at org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor.setBeanFactory(PersistenceExceptionTranslationPostProcessor.java:97) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1325) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473) ... 29 more Caused by: javax.persistence.PersistenceException: [PersistenceUnit: test] Unable to configure EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:265) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:125) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at org.springframework.orm.jpa.LocalEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalEntityManagerFactoryBean.java:91) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:291) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1368) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1334) ... 46 more Caused by: org.hibernate.AnnotationException: A Foreign key refering Reporting from Reporting has the wrong number of column. should be 2 at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:272) at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1319) at org.hibernate.cfg.annotations.CollectionBinder.bindManyToManySecondPass(CollectionBinder.java:1158) at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:600) at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:541) at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:43) at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1140) at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:319) at org.hibernate.cfg.Configuration.buildMappings(Configuration.java:1125) at org.hibernate.ejb.Ejb3Configuration.buildMappings(Ejb3Configuration.java:1226) at org.hibernate.ejb.EventListenerConfigurator.configure(EventListenerConfigurator.java:159) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:854) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:191) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:253) ... 52 more

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• How to use Enum as NamedQuery parameters in JPA

  - by n002213f

  I have an Entity with a enum attribute and a couple on NamedQueries. One of these NamedQueries has a the enum attribute as a parameter i.e. SELECT m FROM Message m WHERE status = :status When i try to ru n the query i get the following error; Caused by: java.lang.IllegalArgumentException: You have attempted to set a value of type class my.package.Status for parameter status with expected type of class my.package.Status from query string SELECT m FROM Message m WHERE m.status = :status. I'm using Toplink How is this? How would i make JPA happy?

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• How to solve lazy initialization exception using JPA and Hibernate as provider

  - by rupertin

  I am working on a project for a customer who wants to use lazy initialization. They always get "lazy initialization exception" when mapping classes with the default lazy loading mode. @JoinTable(name = "join_profilo_funzionalita", joinColumns = {@JoinColumn(name = "profilo_id", referencedColumnName = "profilo_id")}, inverseJoinColumns = {@JoinColumn(name = "funzionalita_id", referencedColumnName = "funzionalita_id")}) //@ManyToMany(fetch=FetchType.EAGER) - no exceptions if uncommented @ManyToMany private Collection<Funzionalita> funzionalitaIdCollection; Is there a standard pattern using JPA classes to avoid this error? Snippets are welcome, thanks a lot for your time.

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• Hibernates generates VARBINARY column with JPA @Enumerated annotation

  - by tran

  Hibernates is generating a VARBINARY column with JPA @Enumerated annotation. I'm using SQL Server 2005 w/ JTDS driver. The mapping is dirt simple: @Basic @Enumerated(EnumType.ORDINAL) private MyEnum foo; I would have expected Hibernate to generate an integer column? I've also tried EnumType.STRING (expecting a varchar column) with no success. Note that my app works fine; the column type makes it hard to inspect the DB, and to issue adhoc SQL when poking at the database.

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• Enabling Hibernate second-level cache with JPA on JBoss 4.2

  - by Peter Hilton

  What are the steps required to enable Hibernate's second-level cache, when using the Java Persistence API (annotated entities)? How do I check that it's working? I'm using JBoss 4.2.2.GA. From the Hibernate documentation, it seems that I need to enable the cache and specify a cache provider in persistence.xml, like: <property name="hibernate.cache.use_second_level_cache" value="true" /> <property name="hibernate.cache.provider_class" value="org.hibernate.cache.HashtableCacheProvider" /> What else is required? Do I need to add @Cache annotations to my JPA entities? How can I tell if the cache is working? I have tried accessing cache statistics after running a Query, but Statistics.getSecondLevelCacheStatistics returns null, perhaps because I don't know what 'region' name to use.

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• JPA Cascading Delete: Setting child FK to NULL on a NOT NULL column

  - by JBristow

  I have two tables: t_promo_program and t_promo_program_param. They are represented by the following JPA entities: @Entity @Table(name = "t_promo_program") public class PromoProgram { @Id @Column(name = "promo_program_id") private Long id; @OneToMany(cascade = {CascadeType.REMOVE}) @JoinColumn(name = "promo_program_id") private List<PromoProgramParam> params; } @Entity @Table(name = "t_promo_program_param") public class PromoProgramParam { @Id @Column(name = "promo_program_param_id") private Long id; //@NotNull // This is a Hibernate annotation so that my test db gets created with the NOT NULL attribute, I'm not married to this annotation. @ManyToOne @JoinColumn(name = "PROMO_PROGRAM_ID", referencedColumnName = "promo_program_id") private PromoProgram promoProgram; } When I delete a PromoProgram, Hibernate hits my database with: update T_PROMO_PROGRAM_PARAM set promo_program_id=null where promo_program_id=? delete from t_promo_program where promo_program_id=? and last_change=? I'm at a loss for where to start looking for the source of the problem.

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• hibernate update JPA foregin key

  - by cometta

  my jpa look like below public class TESTClass implements Serializable { ... private String name; @EmbeddedId protected IssTESTPK issTESTPK; @JoinColumns({@JoinColumn(name = "DIVISION_CODE", referencedColumnName = "DIVISION_CODE", nullable = false , insertable = false, updatable = false), @JoinColumn(name = "SURVEY_NUM", referencedColumnName = "SURVEY_NUM", nullable = false, insertable = false, updatable = false)}) @ManyToOne(optional = false) private IssDivision issDivision; } if i make change to 'name' and call merge, it able to update into database, but when i change issDivision, and call merge, it doesnt update database. how to solve this? does it related to because i'm using embededId (composite primary keys) ?

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• JPA query for getting the whole tree

  - by Javi

  Hello, I have a class which models all categories and they can be ordered hierarchically. @Entity @Table(name="categories") public class Category { @Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="sequence") @SequenceGenerator(name="sequence", sequenceName="categories_pk_seq", allocationSize=1) @Column(name="id") private Long id; @Column private String name; @OneToOne @JoinColumn(name="idfather") private Category father; } I need to get all categories ordered hierarchically (I mean every father followed by its children and fathers ordered alphabetically on each level) as they could be made for example with PRIOR in oracle. Is it possible to do this with a JPA Query (not a SQL one)? Thanks.

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• JPA optimistic lock - setting @Version to entity class cause query to include VERSION as column

  - by masato-san

  I'm using JPA Toplink Essential, Netbean6.8, GlassFish v3 In my Entity class I added @Version annotation to enable optimistic locking at transaction commit however after I added the annotation, my query started including VERSION as column thus throwing SQL exception. None of this is mentioned in any tutorial I've seen so far. What could be wrong? Snippet public class MasatosanTest2 implements Serializable { private static final long serialVersionUID = 1L; @Id @Basic(optional = false) @Column(name = "id") private Integer id; @Column(name = "username") private String username; @Column(name = "note") private String note; //here adding Version @Version int version; query used: SELECT m FROM MasatosanTest2 m Internal Exception: com.microsoft.sqlserver.jdbc.SQLServerException Call: SELECT id, username, note, VERSION FROM MasatosanTest2

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• JPA character encoding

  - by wheelie

  Hi there, I have a Java Web application using GlassFish 3, JSF2.0 (facelets) and JPA (EclipseLink) on MySQL (URL: jdbc:mysql://localhost:3306/administer). The problem I'm facing is that if I'm saving entities to the database with the update() method, String data loses integrity; '?' is shown instead of some characters. The server, pages and database is/are configured to use UTF-8. After I post form data, the next page shows the data correctly. Furthermore it "seems" in debug that the String property of the current entity stores the correct value too. Dunno if NetBeans debug can be trusted; might be that it decodes correctly, however it's incorrect. Any help would be appreciated, thanks in advance! Daniel

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• JPA entitymanager remove operation is not performant

  - by Samuel

  When I try to do an entityManager.remove(instance) the underlying JPA provider issues a separate delete operation on each of the GroupUser entity. I feel this is not right from a performance perspective, since if a Group has 1000 users there will be 1001 calls issued to delete the entire group and itr groupuser entity. Would it make more sense to write a named query to remove all entries in groupuser table (e.g. delete from group_user where group_id=?), so I would have to make just 2 calls to delete the group. @Entity @Table(name = "tbl_group") public class Group { @OneToMany(mappedBy = "group", cascade = CascadeType.ALL, fetch = FetchType.LAZY) @Cascade(value = DELETE_ORPHAN) private Set<GroupUser> groupUsers = new HashSet<GroupUser>(0);

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• JPA, scope, and autosave?

  - by arinte

  I am using JPA and lets say I do something like this public class MoRun extends Thread {... public void run() { final EntityManagerFactory emFactory = Persistence.createEntityManagerFactory("pu"); EntityManager manager = emFactory.createEntityManager(); manager.setFlushMode(FlushModeType.COMMIT); someMethod(manager); ... } public void someMethod(EntityManager manager){ Query query = manager.createNamedQuery("byStates"); List<State> list = query.getResultList(); for (State state : list) { if(someTest) state.setValue(...) } ... } So for those objects that pass "someTest" and values are updated are those changes automatically persisted to the db even though there is no transaction and I don't explicitly "manager.save(state)" the object? I ask because it seems like it is and I was wondering if the flush is doing it?

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• JPA and MySQL transaction isolation level

  - by armandino

  I have a native query that does a batch insert into a MySQL database: String sql = "insert into t1 (a, b) select x, y from t2 where x = 'foo'"; EntityTransaction tx = entityManager.getTransaction(); try { tx.begin(); int rowCount = entityManager.createNativeQuery(sql).executeUpdate(); tx.commit(); return rowCount; } catch(Exception ex) { tx.rollback(); log.error(...); } This query causes a deadlock: while it reads from t2 with insert .. select, another process tries to insert a row into t2. I don't care about the consistency of reads from t2 when doing an insert .. select and want to set the transaction isolation level to READ_UNCOMMITTED. How do I go about setting it in JPA?

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• JPA : Inheritance - Discriminator value not taken into account in generated SQL

  - by Julien

  I try to use this mapping : @Entity @Table(name="ecc.\"RATE\"") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="DISCRIMINATOR", discriminatorType= DiscriminatorType.STRING) public abstract class Rate extends GenericBusinessObject { ... } @Entity @DiscriminatorValue("E") public class EntranceRate extends Rate { @ManyToOne @JoinColumn(name = "\"RATES_GRID_ID\"") protected RatesGrid ratesGrid; ... } @Entity @Table(name="ecc.\"RATES_GRID\"") public class RatesGrid extends GenericBusinessObject { /** */ @OneToMany(mappedBy = "ratesGrid", targetEntity = EntranceRate.class, fetch=FetchType.LAZY) private List<EntranceRate> entranceRates; } When I try to access my entranceRates list from a ratesGrid object, I get this error : Object with id: 151 was not of the specified subclass: com.ecc.bo.rate.EntranceRate (loaded object was of wrong class class com.ecc.bo.rate.AnnualRate) Looking at the sql generated, I found no trace of "discriminator=" in the where clause. What am I doing wrong ? I use a PostGreSQL database and a Hibernate as JPA provider.

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• flex/actionscript client entity state refresh on JPA update using Pimento EntityManager

  - by Chris

  My Flex application uses a client-side pimento EntityManager which fetches quite a few objects and associations. It does this by forcing eager fetching of particular association ends in the form of fetch plans. I would like to update the client whenever a change has been made to an entity existing in the EntityManager's cache. Is it possible to update the state of the changed entity ONLY, including updating which entities are associated, without resetting the state of these associated entities? I have setup an EntityListener with a JPA post-update method that notifies clients when a persisted entity has been updated. I want this to trigger a refresh for the modified client-side entity, but calling EntityManager.refresh(entity) resets all lazy associations to proxies. Initializing these proxies resets the associated entities, even if they were loaded previously. I'm looking for an efficient way to keep the client's state in synch with the server's state, at least with respect to the entities that have already been retrieved by the initial load.

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• Jpa subclass mapping

  - by Roy Chan

  I am making a POS like system. I wonder how to map subclass using JPA (this is for my DAO). Product class has product details and OrderProduct class has information about the Product and details about the order. @Entity @Table(name="products") public class Product implements Serializable{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO public int getId(){ return id;} /** Other get/set methods */ } @Entity @Table(name="order_products") public class OrderProduct extends Product{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO) public int getId(){ return id;} /** Other get/set methods */ } I got complain about duplicate @Id. But OrderProduct class really need another id than the product one. How should I map this? DB is something like this Table products id int name varchar(32) Table order_product id int quantity int productid int fk referencing product table Would @IdClass or @AttributeOverride help?

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• Java: JPA classes, refactoring from Date to DateTime

  - by bguiz

  With a table created using this SQL Create Table X ( ID varchar(4) Not Null, XDATE date ); and an entity class defined like so @Entity @Table(name = "X") public class X implements Serializable { @Id @Basic(optional = false) @Column(name = "ID", nullable = false, length = 4) private String id; @Column(name = "XDATE") @Temporal(TemporalType.DATE) private Date xDate; //java.util.Date ... } With the above, I can use JPA to achieve object relational mapping. However, the xDate attribute can only store dates, e.g. dd/MM/yyyy. How do I refactor the above to store a full date object using just one field, i.e. dd/MM/yyyy HH24:mm?

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• Mixing JPA annotations and XML configuration

  - by HDave

  I have a fairly large (new) project in which we have annotated many domain classes with JPA mappings. Now it is time to implement many named queries -- some entities may have as many as 15-20 named queries. I am thinking that writing these named queries in annotations will clutter the source files and therefore am considering putting these in XML mapping files. Is this possible? Mort importantly, is this reasonable? Are there better approaches? How is this done?

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• Hibernate/JPA and PostgreSQL - Primary Key?

  - by Shadowman

  I'm trying to implement some basic entities using Hibernate/JPA. Initially the code was deployed on MySQL and was working fine. Now, I'm porting it over to use PostgreSQL. In MySQL, my entity class defines its primary key as an auto-incrementing long value with the following syntax: @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; However, I've found that I get errors with PostgreSQL when I try and insert numerous records at a time. What do I need to annotate my primary key with to get the same auto-incrementing behavior in PostgreSQL as I have with MySQL? Thanks for any help you can provide!

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• Need help in setting application name with JPA (EclipseLink)

  - by enrique

  hello everybody i am using JPA with EclipseLink and oracle as DB and i need to set the property v$session of jdbc4 it allows to set an identification name to the application for auditing purposes but i had no lucky setting it up....i have been trying through entitiyManager following the example in this page: http://wiki.eclipse.org/Configuring_a_EclipseLink_JPA_Application_(ELUG) it does not show any error but does not set the application name at all... when i see the audit in oracle it is not being audited with the name i set by code "Customers" but with OS_program_name=JDBC Thin Client it means that the property in the code is not being set properly and i have no idea where the issue is, the code i am using is the following : emProperties.put("v$session.program","Customers"); factory=Persistence.createEntityManagerFactory("clients",emProperties); em=factory.createEntityManager(emProperties); em.merge(clients); does anybody know how to do it or any idea.... thanks.-

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• jpa-Primarykey relationship

  - by megala

  Hi created student entity in gogole app engine datastore using JPA. Student---Coding @Entity @Table(name="StudentPersonalDetails", schema="PUBLIC") public class StudentPersonalDetails { @Id @Column(name = "STUDENTNO") private Long stuno; @Basic @Column(name = "STUDENTNAME") private String stuname; public void setStuname(String stuname) { this.stuname = stuname; } public String getStuname() { return stuname; } public void setStuno(Longstuno) { this.stuno = stuno; } public Long getStuno() { return stuno; } public StudentPersonalDetails(Long stuno,String stuname) { this.stuno = stuno; this.stuname = stuname; } } I stored Property value as follows Stuno Stuname 1 a 2 b If i stored Again Stuno No 1 stuname z means it wont allow to insert the record But. It Overwrite the value Stuno Stuname 1 z 2 b How to solve this?

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• Hibernate/JPA DB Schema Generation Best Practices

  - by Bytecode Ninja

  I just wanted to hear the opinion of Hibernate experts about DB schema generation best practices for Hibernate/JPA based projects. Especially: What strategy to use when the project has just started? Is it recommended to let Hibernate automatically generate the schema in this phase or is it better to create the database tables manually from earliest phases of the project? Pretending that throughout the project the schema was being generated using Hibernate, is it better to disable automatic schema generation and manually create the database schema just before the system is released into production? And after the system has been released into production, what is the best practice for maintaining the entity classes and the DB schema (e.g. adding/renaming/updating columns, renaming tables, etc.)? Thanks in advance.

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• Map null column as 0 in a legacy database (JPA)

  - by Indrek

  Using Play! framework and it's JPASupport class I have run into a problem with a legacy database. I have the following class: @Entity @Table(name="product_catalog") public class ProductCatalog extends JPASupport { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) public Integer product_catalog; @OneToOne @JoinColumn(name="upper_catalog") public ProductCatalog upper_catalog; public String name; } Some product catalogs don't have an upper catalog, and this is referenced as 0 in a legacy database. If I supply the upper_catalog as NULL, then expectedly JPA inserts a NULL value to that database column. How could I force the null values to be 0 when writing to the database and the other way around when reading from the database?

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• jpa join query on a subclass

  - by Brian

  I have the following relationships in JPA (hibernate). Object X has two subclasses, Y and Z. Object A has a manyToOne relationship to object X. (Note, this is a one-sided relationship so object X cannot see object A). Now, I want to get the max value of a column in object A, but only where the relationship is of a specific subtype, ie...Y. So, that equates to...get the max value of column1 in object A, across all instances of A where they have a relationship with Y. Is this possible? I'm a bit lost as how to query it. I was thinking of something like: String query = "SELECT MAX(a.columnName) FROM A a join a.x; Query query = super.entityManager.createQuery(query); query.execute(); However that doesn't take account of the subclass of X...so I'm a bit lost. Any help would be much appreciated.

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• JPA EclipseLink Auditing for Oracle issue with SessionCustomizer...

  - by enrique

  I was trying to use the SessionCustomizer for auditing with v$session.program for oracle and it works with JDBC but i need it working with JPA, so i read a bit more the documentation for SESSION_CUSTOMIZER in this site: http://wiki.eclipse.org/Using_EclipseLink_JPA_Extensions_(ELUG)#EclipseLink_JPA_Persistence_Unit_Properties_for_Customization_and_Validation but had not lucky in making it work in passing the program name parameter to oracle with the v$session.program... i was using the SessionCustomizer and it is an interface so my code is as follows: package com.util; import org.eclipse.persistence.config.SessionCustomizer; import org.eclipse.persistence.sessions.Session; /** * * @author xkalibur */ public class ProgramCustomizer implements SessionCustomizer{ public void customize(Session s) throws Exception { s.getDatasourceLogin().setProperty("v$session.program","Customers"); } } then in CustomerFacade : ProgramCustomizer pc=new ProgramCustomizer(); public void edit(Customer customer) { emProperties.put(PersistenceUnitProperties.SESSION_CUSTOMIZER,pc); em=factory.createEntityManager(emProperties); em.merge(customer); } and returns the following error: javax.ejb.EJBException Caused by: java.lang.NullPointerException at com.facades.CustomerFacade.edit(CustomerFacade.java:48) please some help...

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