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  • La vulnérabilité de Java déjà exploitée depuis des serveurs russes, Oracle reste sur sa position

    Mise à jour du 15/04/10 La vulnérabilité de Java déjà exploitée Depuis des serveurs russes, Oracle reste sur sa position La faille de Java récemment mise à jour par un ingénieur de Google (lire ci-avant) serait déjà exploitée. Roger Thompson, chef chercheur chez AVG, a repéré des attaques depuis des serveurs russes utilisés par des sites qui ciblent le grand public (comme Songlyrics.com, qui propose les paroles de chansons de Lady Gaga, Rihanna, etc.). En arrivant sur ce site, un iFrame malicieux camouflé dans une publicité redirige l'utilisateur (sans que celui-ci ne s'en aperçoive) vers un serveur hébergeant l'exploit....

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  • Best way to move your domain and keep the Google position

    - by netadictos
    I have to move one domain to a new one which is semantically better for SEO. I would like to know the best way to do it so that the new domain keeps the google position. I know the basic steps: to put a redirection 301 in the old one, with an apache script, it can be very detailed, but the important is the 301 header for google you can tell them through the webmaster tools page try to gain pagerank for the new domain

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  • Taking too long to get skills for entry level programmer position [closed]

    - by greenonion
    I don't have the skills for an entry level position as a .Net programmer. I am trying to learn what I need but there is too much to learn and too little time. What can I do? About two months ago, I went to a job interview for an entry level C# .Net programming/consultant position in NYC. When I heard back from them, they told me that the knowledge gap between what I knew and what they needed me to know was too big and I might have been a better fit if I had 6 months of experience. This was the first interview that I went on since graduating college. before the interview, I read a book on visual C#. Turns out it wasn't a very good book and I was missing a lot of key areas of knowledge such as ADO.net SQL (I had learned some LINQ) A little bit about how memory is handled Multiple threaded programming, etc. Because the book wasn't very good, the stuff I did know, I didn't know very well. I felt crushed. I've applied for jobs to gain experience but when recruiters hear that I have no experience they lose interest. I figured that I can at least work on my knowledge. Since then, I read "SQL Essentials" to cover the SQL bit and I found a pretty awesome book that is good enough to clear up what's hazy in my mind and covers almost all of the extra topics. The book is "C# 4.0: The Complete Reference" by Herbert Schildt. I'm even learning a lot about the topics I was familiar with. For a month now I've been working my way through this beast of a book. However, gaining the knowledge I need is taking too long. I can't hold off not having a full-time job much longer. I'm not stupid and I'm studying constantly pouring through the book, asking questions on stackoverflow, referencing the C# specification, etc. I have made great progress but there is just too much ground to cover. I'm on chapter 12 which is about a 3rd through the book. To get an idea of what I know vs don't know, the table of contents is on amazon: http://www.amazon.com/C-4-0-The-Complete-Reference/dp/007174116X How on earth can someone know enough to function as a programmer in the real world? Can I try for a job in academia? Will I have time to finish learning the rest of the C# language or am I just un-hireable?

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  • Position sprite at center of screen

    - by Wellie
    I am trying to get a sprite to position itself at the center of the screen but nothing seems to be working for me. I'm trying Viewport viewport = graphics.GraphicsDevice.Viewport; logoPosition = new Vector2((viewport.Width - towerImage.Width) / 2, (viewport.Height - towerImage.Height) / 2); and spriteBatch.Draw(towerImage, centre, null, Color.White, 0, baseOrigin, 1.0f, SpriteEffects.None, 0); This is my first time using XNA and I don't really have a clue what I'm doing.

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  • Transition Player Position

    - by Lycrios
    I'm currently working on a java MMO with a pretty solid start, but I've come across an issue I need a little help with. I'm working on player position's. Meaning there X/Y on the screen, if the PlayerA has a higher FPS(Frames Per Second) then other players, the resulting action will be that PlayerA will move faster than everyone else. I know the reasoning for this, it's because when the game draws I just use: x++; What would a better method be?

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  • MediaElement.Position behaviour and Windows Phone 7 issue

    - by RoguePlanetoid
    I have a problem, I have written a simple Media Player for Windows Phone 7 and can Play, Stop and control the Volume of a Video (loaded from a URI) however when I try to set the position, this causes the application to freeze. I have used both these lines, but either does not work: Player.Position = new TimeSpan(0, 0, 0, 0, (int)Position.Value); Player.Position = TimeSpan.FromSeconds((int)(Position.Value)); I do have this event handler: void Player_MediaOpened(object sender, RoutedEventArgs e) { Position.Maximum = Player.NaturalDuration.TimeSpan.TotalMilliseconds; } And have tried using the Seconds value, casting to Ints etc, however everytime I try to set the Position, the app freezes. The video otherwise plays normally - anyone know what the problem may be here?

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  • Computing pixel's screen position in a vertex shader: right or wrong?

    - by cubrman
    I am building a deferred rendering engine and I have a question. The article I took the sample code from suggested computing screen position of the pixel as follows: VertexShaderFunction() { ... output.Position = mul(worldViewProj, input.Position); output.ScreenPosition = output.Position; } PixelShaderFunction() { input.ScreenPosition.xy /= input.ScreenPosition.w; float2 TexCoord = 0.5f * (float2(input.ScreenPosition.x,-input.ScreenPosition.y) + 1); ... } The question is what if I compute the position in the vertex shader (which should optimize the performance as VSF is launched significantly less number of times than PSF) would I get the per-vertex lighting insted. Here is how I want to do this: VertexShaderFunction() { ... output.Position = mul(worldViewProj, input.Position); output.ScreenPosition.xy = output.Position / output.Position.w; } PixelShaderFunction() { float2 TexCoord = 0.5f * (float2(input.ScreenPosition.x,-input.ScreenPosition.y) + 1); ... } What exactly happens with the data I pass from VS to PS? How exactly is it interpolated? Will it give me the right per-pixel result in this case? I tried launching the game both ways and saw no visual difference. Is my assumption right? Thanks. P.S. I am optimizing the point light shader, so I actually pass a sphere geometry into the VS.

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  • Is title tag position relevant in html pages?

    - by webose
    I'd like know if having the title tag positioned at the end of <head> tag or in any other position, always inside the <head></head>, can lead to some kind of problem, I'm not talking about SEO stuffs, I'm talking about standards, browser rules, web application rules, or something like this. I'd like to load a page from two different php file like this, is it a wrong way? <!-- file1.php --> <html> <head> .... <!-- file2.php --> <title><?php echo($var)?> </head> <body> ... <head> tag is not closed, because with the second file I dynamically add the <title> tag.

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  • SQL Interview Preparation : QA Engineer Position

    - by user9009
    Hello, I have interview with enterprise company for QA Engineer(New Grad-Mid level experience) position. I was told i would expect some questions on SQL. The company is eCommerce shopping portal. So what kind of questions do i expect for SQL coding ? . DO i need to learn how to code complex queries? Any inputs would be appreciated. Please provide links which you think can be helpful. Yes i found similar question on StackOverflow, but i wanted to know important SQL topics from QA Engineer Perspective Thanks

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  • how to retain the animated position in opengl es 2.0

    - by Arun AC
    I am doing frame based animation for 300 frames in opengl es 2.0 I want a rectangle to translate by +200 pixels in X axis and also scaled up by double (2 units) in the first 100 frames Then, the animated rectangle has to stay there for the next 100 frames. Then, I want the same animated rectangle to translate by +200 pixels in X axis and also scaled down by half (0.5 units) in the last 100 frames. I am using simple linear interpolation to calculate the delta-animation value for each frame. Pseudo code: The below drawFrame() is executed for 300 times (300 frames) in a loop. float RectMVMatrix[4][4] = {1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 }; // identity matrix int totalframes = 300; float translate-delta; // interpolated translation value for each frame float scale-delta; // interpolated scale value for each frame // The usual code for draw is: void drawFrame(int iCurrentFrame) { // mySetIdentity(RectMVMatrix); // comment this line to retain the animated position. mytranslate(RectMVMatrix, translate-delta, X_AXIS); // to translate the mv matrix in x axis by translate-delta value myscale(RectMVMatrix, scale-delta); // to scale the mv matrix by scale-delta value ... // opengl calls glDrawArrays(...); eglswapbuffers(...); } The above code will work fine for first 100 frames. in order to retain the animated rectangle during the frames 101 to 200, i removed the "mySetIdentity(RectMVMatrix);" in the above drawFrame(). Now on entering the drawFrame() for the 2nd frame, the RectMVMatrix will have the animated value of first frame e.g. RectMVMatrix[4][4] = { 1.01, 0, 0, 2, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 };// 2 pixels translation and 1.01 units scaling after first frame This RectMVMatrix is used for mytranslate() in 2nd frame. The translate function will affect the value of "RectMVMatrix[0][0]". Thus translation affects the scaling values also. Eventually output is getting wrong. How to retain the animated position without affecting the current ModelView matrix? =========================================== I got the solution... Thanks to Sergio. I created separate matrices for translation and scaling. e.g.CurrentTranslateMatrix[4][4], CurrentScaleMatrix[4][4]. Then for every frame, I reset 'CurrentTranslateMatrix' to identity and call mytranslate( CurrentTranslateMatrix, translate-delta, X_AXIS) function. I reset 'CurrentScaleMatrix' to identity and call myscale(CurrentScaleMatrix, scale-delta) function. Then, I multiplied these 'CurrentTranslateMatrix' and 'CurrentScaleMatrix' to get the final 'RectMVMatrix' Matrix for the frame. Pseudo Code: float RectMVMatrix[4][4] = {0}; float CurrentTranslateMatrix[4][4] = {0}; float CurrentScaleMatrix[4][4] = {0}; int iTotalFrames = 300; int iAnimationFrames = 100; int iTranslate_X = 200.0f; // in pixels float fScale_X = 2.0f; float scaleDelta; float translateDelta_X; void DrawRect(int iTotalFrames) { mySetIdentity(RectMVMatrix); for (int i = 0; i< iTotalFrames; i++) { DrawFrame(int iCurrentFrame); } } void getInterpolatedValue(int iStartFrame, int iEndFrame, int iTotalFrame, int iCurrentFrame, float *scaleDelta, float *translateDelta_X) { float fDelta = float ( (iCurrentFrame - iStartFrame) / (iEndFrame - iStartFrame)) float fStartX = 0.0f; float fEndX = ConvertPixelsToOpenGLUnit(iTranslate_X); *translateDelta_X = fStartX + fDelta * (fEndX - fStartX); float fStartScaleX = 1.0f; float fEndScaleX = fScale_X; *scaleDelta = fStartScaleX + fDelta * (fEndScaleX - fStartScaleX); } void DrawFrame(int iCurrentFrame) { getInterpolatedValue(0, iAnimationFrames, iTotalFrames, iCurrentFrame, &scaleDelta, &translateDelta_X) mySetIdentity(CurrentTranslateMatrix); myTranslate(RectMVMatrix, translateDelta_X, X_AXIS); // to translate the mv matrix in x axis by translate-delta value mySetIdentity(CurrentScaleMatrix); myScale(RectMVMatrix, scaleDelta); // to scale the mv matrix by scale-delta value myMultiplyMatrix(RectMVMatrix, CurrentTranslateMatrix, CurrentScaleMatrix);// RectMVMatrix = CurrentTranslateMatrix*CurrentScaleMatrix; ... // opengl calls glDrawArrays(...); eglswapbuffers(...); } I maintained this 'RectMVMatrix' value, if there is no animation for the current frame (e.g. 101th frame onwards). Thanks, Arun AC

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  • Logic that can traverse all possible layouts, but not checking every combination of identical pieces?

    - by George Bailey
    Suppose we have a grid of arbitrary size, which is filled by blocks of various widths and heights. There are many 2x2 blocks (meaning they take a total of 4 cells in the grid) and many 3x3 blocks, as well as some 5x4, 4x5, 2x3, etc. I was hoping I could set up a program that would look at all possible layouts, and rank them, and find the best one. Simply it would look at all possible positions of these blocks, and see what setup is the best rank. (the rank based on how many of these can be connected by a roadway system of 1x1 road blocks, and how many squares can be left empty after this is done. - wanting to fit the most blocks as possible with the least roads.) My question, is how should I traverse all the possibilities? I could take all the blocks and try them one at a time, but since all 2x2 blocks are equal, and there are a couple dozen of them, there is no point in trying every combination there, as in the following AA BBB AA BBB CCBBB CCEEE DD EEE DD EEE is exactly the same as CC EEE CC EEE AAEEE AABBB DD BBB DD BBB You notice that there are 2 3x3 blocks and 3 2x2 blocks in my two examples. Based on the model I have now, the computer would try both of these combinations, as well as many others. The problem is that it is going to try every single possible variation of my couple dozen 2x2 blocks. And that is sorely inefficient. Is there a reasonable way to take out this duplicated work, somehow getting the computer program to treat all 2x2 blocks as equal/identical, instead of one requiring rearranging/swapping of these identical blocks? Can this be done?

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  • MySQL tech writer position on Oracle jobs site

    - by stefanhinz
    Just in case you missed this, last week I announced that my team is looking for an experienced technical writer. Now the job offer has gone live on the Oracle website. Have a look! That's the EMEA job site, but the position is actually available for Europe or North America. The job offer should appear on the American site soon, too. If you want to join a great team, or if you know someone suitable who does, don't hesitate to contact me!

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  • Set vertex position

    - by user1806687
    Can anyone tell me how to set the positions of model vertices? I want to be able to change the position of some of the vertices of a Model. Is there any way to make that happen? And make the changed visible at that moment. EDIT: Well, the thing is,I have a model, a cube, that is made up of four "thin" cubes(top,bottom,left side, right side), so I get this cube with "hole" in the middle. And I want to scale it on Y axis. If I do Scale(0,2,0) it will scale the whole object meaning, it will double the Y size of left and right side, but also double the size of the top and bottom cube, which I do not want. Same for X axis I want to double the size of top and bottom cubes but not the left and right one. Hope you can help

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  • Tree position terminology/naming

    - by wst
    This is a naming things question. I am processing trees (XML documents), and there are often special rules applied to nodes based on structure. It's been very difficult coming up with concise naming conventions for some cases, namely for nodes in the first position among their siblings, along with some recursive relationship: Given an arbitrary node, I want to describe its first child, and then that node's first child, and so on recursively. Given another arbitrary node, I want to describe its parent if the parent is first among its siblings, and that parent's parent if it's first, and so on recursively. Is there existing terminology to describe these tree positions? How would you name a variable or function that captures one of these cases so that it's intuitive to an unfamiliar developer trying to understand an algorithm?

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  • Unity3D Android - Move your character to a specific x position

    - by user3666251
    Im making a new game for android and I wanted to move my character (which is a cube for now) to a specific x location (on top of a flying floor/ground thingy) but I've been having some troubles with it.I've been using this script : var jumpSpeed: float = 3.5; var distToGround: float; function Start(){ // get the distance to ground distToGround = collider.bounds.extents.y; } function IsGrounded(): boolean { return Physics.Raycast(transform.position, -Vector3.up, distToGround + 0.1); } function Update () { // Move the object to the right relative to the camera 1 unit/second. transform.Translate(Vector3.forward * Time.deltaTime); if (Input.anyKeyDown && IsGrounded()){ rigidbody.velocity.x = jumpSpeed; } } And this is the result (which is not what I want) : https://www.youtube.com/watch?v=Fj8B6eI4dbE&feature=youtu.be Anyone has any idea how to do this ? Im new in unity and scripting.Im using java btw. Ty.

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  • Set Position of multiple bodies

    - by philipp
    I have a character composed of five bodies which are tied together by a lot of joints. On of them is the overall chassis, to which all forces and impulses are applied to move the whole Character. All in all that works very fine, except one thing: I need to set the Position of the Character so that it get Beamed from one place to the other in one single frame. Unfortunately I cannot get this to work. I tried the following code, without any success… playerbodies.forEach(function (bd) { bd.SetLinearVelocity(new b2.Vec2()); var t = bd.GetTransform(); t.p.x -= 10; bd.SetTransform(t, bd.GetAngle()); }); How can I make that happen?

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  • Camera placement sphere for an always fully visible object

    - by BengtR
    Given an object: With the bounds [x, y, z, width, height, depth] And an orthographic projection [left, right, bottom, top, near, far] I want to determine the radius of a sphere which allows me to randomly place my camera on so that: The object is fully visible from all positions on this sphere The sphere radius is the smallest possible value while still satisfying 1. Assume the object is centered around the origin. How can I find this radius? I'm currently using sqrt(width^2 + height^2 + depth^2) but I'm not sure that's the correct value, as it doesn't take the camera into account. Thanks for any advice. I'm sorry for confusing a few things here. My comments below should clarify what I'm trying to do actually.

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  • How to properly position 3rd level menu [migrated]

    - by drewrowalnd
    If you look here: http://snippetmagazine.com/ under about isl-board of trustees you can se I have created a third level dropdown, but how can I properly align that drop down? Below you will see my css. #menudiv { width: 999px; float: left; clear: left; height: 250px; background: url(images/top_bg.png) no-repeat; margin-top: 10px; } mainmenu { width: 948px; height: 63px; float: left; margin-left: 16px; margin-top:5px; border: 1px solid #D5D5D5; -moz-border-radius: 3px; -webkit-border-radius: 3px; -webkit-box-shadow: 0px 1px 2px rgba(0, 0, 0, 0.1); -moz-box-shadow: 0px 1px 2px rgba(0, 0, 0, 0.1); background:url(images/nav_bg.gif) repeat; } .mainnav { margin: 0; padding: 0; list-style: none; } .mainnav * { margin: 0; padding: 0; list-style: none; } .mainnav ul { position: absolute; top: -999em; display: none; } .mainnav li { float: left; position: relative; z-index: 999; height: 63px; line-height: 55px; margin-right: 0px; border-right: 1px solid #D5D5D5; } .mainnav li.last { border-right: none; } .mainnav a { display: block; font-size: 19px; margin: 0; color: #cc9900; font-family: Copperplate, Arial, Helvetica, Sans serif; font-weight:600; text-decoration: none; padding: 3px 13px 3px 12px; color: #555; text-shadow: 0 1px 1px white; } .mainnav li:hover { text-decoration: none; border-bottom: solid 0px #ccc; background: white; } .mainnav ul li{ width: 132px; } .mainnav li:hover ul, ul.mainnav li.sfHover ul { left: 0px; top: 50px; padding-top: 0px; width: 132px; border-bottom: solid 0px #eaeaea; background: url(images/nav_dropdown_shadow.gif) repeat-x top; padding: 6px 0 0px 0px; margin: 13px 0 0 -1px; border: 1px solid #D5D5D5; -moz-border-radius-bottomleft: 3px; -webkit-border-bottom-left-radius: 3px; -moz-border-radius-bottomright: 3px; -webkit-border-bottom-right-radius: 3px; -webkit-box-shadow: 0px 1px 3px rgba(0, 0, 0, 0.1); -moz-box-shadow: 0px 1px 3px rgba(0, 0, 0, 0.1); width: 175px; border-bottom-left-radius: 3px 3px; border-bottom-right-radius: 3px 3px; } .mainnav li:hover li ul, .mainnav li.sfHover li ul { top: -999em; } .mainnav li li:hover ul, ul.mainnav li li.sfHover ul { left: 132px; top: -8px; } .mainnav li:hover ul, .mainnav li li:hover ul { top: -999em; } .mainnav li li { color: #555; display: block; padding: 0px; height: auto !important; border: none; width:175px; background: url(images/nav_dropdown_bg.gif) repeat; margin: 0; } .mainnav li li a:link, .mainnav li li a:visited { display: block; height: auto !important; line-height: 30px; color: #333; font-weight: normal; font-family: arial, helvetica, sans-serif; font-size: 12px; border: none; margin: 0; padding-left: 10px; overflow:hidden; border-bottom: 1px solid #E3E3E3; } .mainnav li li :hover{ } .mainnav li li a:hover { background: none; color:#555 ; border-bottom: 1px solid #E3E3E3; }

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  • XNA - positioning after rotation

    - by DijkeMark
    I have a turret with a 2 gunbarrels. The turret rotates towards my mouse. So far no problem. When it creates a few bullets and positions them at the end of the gun barrels. Here is the problem. It only works the moment the gun is point upwards. The moment it rotates the end of the gun barrels have moved ofcourse, thus the bullets don't spawn at the end of the gun battels, but at the place the where the gun barrels are when the turret is pointing upwards. How can I check where the end of the gun barrels are the moment it rotates? Thanks in Advance, Mark Dijkema PS. If you need code please let me know, I didn't post any yet, because I didn't what code you would need.

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  • JavaScript: scroll position (Webkit engine) [migrated]

    - by Julien
    I'm currently trying to use JavaScript to find out how far down the page the user has scrolled; for Firefox 8.0, the keyword is pageYOffset. To say things mechanically: The page has a certain height. In Firefox, the useful object is document.documentElement.scrollHeight. The browser's visible area also has a certain height. In Firefox, the object is window.innerHeight; in IE8, document.documentElement.clientHeight. I need to know where the user is in the page vertically; in other words, how many pixels down the page the user has scrolled. Does Webkit have a DOM object that refers to the current scroll position? Thank you.

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  • Certain windows are not opening in the last position/size I used them at

    - by Spacecraft
    Certain windows are not opening in the last position/size I used them at. Opening "compose a message" with evolution through the message menu on the toolbar opens a window that is always in the top left of my screen. Opening Firefox 4.0 always opens maximized, even if i last used it in "windowed" mode. Other things I've tried that won't remember my custom positions: ccsm, terminal, gedit, sound recorder, calculator. Some other stuff works fine like banshee, empathy, shutter, deluge. Is this a bug? Is there a way to make these applications open in their last used positions/sizes?

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  • Re-opening closed dialog puts it in the start position after moving it

    - by semmelbroesel
    I'm using multiple instances of the JQuery-UI dialog along with draggable and resizable. Whenever I drag or resize one of the dialog boxes, the position and dimensions of the current box are saved to a database and then loaded the next time the page opens. This is working well. However, when I close a dialog box and re-open it using a button, jQuery sets the position of the box back to its original location in the center of the screen. Furthermore, I use a show effect to slide the box off to the left on closing and in from the left on re-opening. I found two ways to update its position when the slide in animation is done, however, it still slides into the center of the screen, and I have yet to find a way to get it to slide in towards the location it is supposed to have. Here are the parts of the code that play a part in this: $('.box').dialog({ closeOnEscape: false, hide: { effect: "drop", direction: 'left' }, beforeClose: function (evt, ui){ var $this = $(this); SavePos($this); // saves the dimensions to db }, dragStop: function() { var $this = $(this); SavePos($this); }, resizeStop: function() { var $this = $(this); SavePos($this); }, open: function() { var $this = $(this); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) // meaning only load this code when the page has finished initializing { // tried it both ways - set the position before and after the effect - no success UpdatePos($this.attr('id')); // I tried this section with promise() and effect / complete - I found no difference $this.parent().promise().done(function() { UpdatePos($this.attr('id')); }); } } }); function UpdatePos(key) { // boxpos is an object holding the position for each box by the box's id var $this = $('#' + key); //console.log('updating pos for box ' + boxid); if ($this && $this.hasClass('ui-dialog-content')) { //console.log($this.dialog('widget').css('left')); $this.dialog('option', { width: boxpos[key].width, height: boxpos[key].height }); $this.dialog('widget').css({ left: boxpos[key].left + 'px', top: boxpos[key].top + 'px' }); //console.log('finished updating pos'); //console.log($this.dialog('widget').css('left')); } } The button that re-opens the box has this code on it to make that happen: var $box = $('#boxid'); if ($box) { if ($box.dialog('isOpen')) { $box.dialog('moveToTop'); } else { $box.dialog("open") } } I don't know what jQuery-UI does to the box as it hides it (other than display:none) or to make it slide in, so maybe there's something I'm missing here that might help... Basically, I need JQuery to remember the box' position and put the box back into that location when it is re-opened. It took me days to make it this far, but this is one obstacle I have yet to overcome. Maybe there's a different way I can re-open the box? Thanks! EDIT: Forgot - this issue ONLY happens when I use my UpdatePos function to set the location of a box (i.e. on page load). When I drag a box with my mouse, close it, and re-open it, everything works. So I'm guessing there's one more storage location for the box' position that I'm missing here... EDIT2: After more messing with it, my code for debugging now looks like this: open: function() { var $this = $(this); console.log('box open'); console.log($this.dialog('widget').position()); // { top=0, left=-78.5} console.log($this.dialog('widget').css('left')); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) { UpdatePos($this.attr('id')); $this.parent().promise().done(function() { console.log($this.dialog('widget').position()); // { top=313, left=641.5} console.log($this.dialog('widget').css('left')); UpdatePos($this.attr('id')); console.log($this.dialog('widget').position()); // { top=121, left=107} console.log($this.dialog('widget').css('left')); }); } The results I'm getting are: box open Object { top=0, left=-78.5} -78.5px Object { top=313, left=641.5} 641.5px Object { top=121, left=107} 107px So looks to me as if the widget is being moved off screen (left=-78.5) and then moved for the animation, and then my code moves it into the location that it should be in (121/107). The position() results for $box.position() or $box.dialog().position() do not change during this debugging section. Maybe this will help someone here - I'm still out of ideas here... ... and I just discovered that when I drag the item around myself, then close and re-open it, it is very unpredictable. Sometimes, it will end up in the correct location horizontally, but not vertically. Sometimes, it will end up back in the center of the screen...

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  • How to change the handler position by dragging/single click on the slider

    - by Geetha
    Hi All, I am using the following files to create a slider. Problem:Needs double click to change the handler position first click: it move the handler but the following code is not working. a second later it return back to the previous position. second click on the handler in new position, before it moves back the following code is working. Needs: I want change the media player current position with the handler current position value by dragging the handler or single click on the new position of the slider. Ex: initial position of the handler: l-------------------------------- document.mediaPlayer.currentPosition = 0 After dragging it some other position ----------------------l---------- document.mediaPlayer.currentPosition = 125 Code: var endTime = document.mediaPlayer.SelectionEnd; $("#slider-constraints").slider({ animate: true, max: endTime, range: $R(0, endTime), value: 1, enforceConstraints: false, start:function(event,index){document.mediaPlayer.currentPosition=index.value; $('#slider-constraints').slider("constraints", [0, index.value]); $('#slider-constraints').slider("value", index.value);} }); window.setInterval(function() { $('#slider-constraints').slider("value", document.mediaPlayer.currentPosition); }, 4000);

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  • Re-open Word document to previous cursor location with identical page vertical position

    - by Malcolm
    I would like to return to my previous point of edit with the page vertically positioned identical to its original vertical position. The Shift+F5 technique returns me to the previous point of edit, but the page I return to is vertically positioned on the screen in a somewhat random manner. In other words, if my cursor is 300 vertical pixels from the top of the document viewport, I would like to re-open my page so that the location of the cursor is still 300 vertical pixels from the top of my viewport. The following can be used to determine the vertical position (on the screen) of my text cursor: ActiveWindow.GetPoint pLeft, pTop, pWidth, pHeight, Selection.Range So the challenge becomes how to scroll my document in such a manner as to return my text cursor to its original vertical position (pHeight)? There is no corresponding ActiveWindow.SetPoint and ActiveWindow.ScrollIntoView scrolls a selection range into view, but offers no control over the vertical position of the selection range on the screen.

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