Search Results

Search found 28818 results on 1153 pages for 'main loop'.

Page 771/1153 | < Previous Page | 767 768 769 770 771 772 773 774 775 776 777 778  | Next Page >

• Problem while compiling the code

  - by Atul

  Can someone points me the problem in the code when compiled with gcc 4.1.0. #define X 10 int main() { double a = 1e-X; return 0; } I am getting error:Exponent has no digits. When i replace X with 10, it works fine. Also i checked with g++ -E command to see the file with preprocessors applied, it has not replaced X with 10. I was under the impression that preprocessor replaces every macro defined in the file with the replacement text with applying any intelligence. Am I wrong? I know this is a really silly question but I am confused and I would rather be silly than confused :). Any comments/suggestions.

  Read the article

• Function to set an auth_token

  - by john mossel

  In my form I have a hidden field: <input type="hidden" name="auth_token" value="<?php echo $auth_token; ?>"> This value is also stored in a session and a variable: $_SESSION['auth_token'] = hash('sha256', rand() . time() . $_SERVER['HTTP_USER_AGENT']); # TODO: put this in a function $auth_token = $_SESSION['auth_token']; When the form is submitted the two values are compared. It's a basic form token. Should this be made into two functions or just one when refactored? set_form_token() and get_form_token(), get_form_token() returning the session value, then I can compare it in my main code. What is the proper way of doing this?

  Read the article

• DWORD to bytes using bitwise shift operators

  - by Dave18

  I can't get it to work correctly. #include <windows.h> int main() { DWORD i = 6521; BYTE first = i >> 32; BYTE second = i >> 24; BYTE third = i >> 16; BYTE fourth = i >> 8; i = (((DWORD)fourth) << 24) | (((DWORD)third) << 16) | (((DWORD)second) << 8) | first; }

  Read the article

• multitreading scheduling related java

  - by vichi

  class A implements Runnable{ B b=new B(); public void run(){ while(true){ System.out.println("H1"+Thread.currentThread().getName()); } } } public class Test { public static void main(String[] str){ A a1 =new A(); // A a2 =new A(); // Thread t1 =new Thread(a1, "Vichi"); Thread t2 =new Thread(a1,"Vishu"); t1.start(); t2.start(); } } what will be the ans: 1) only one of them will get the chance to execute 2) both will get chance in arbitrary manner please suggest possible ans with explations

  Read the article

• Is it possible to supply template parameters when calling operator()?

  - by Paul

  I'd like to use a template operator() but am not sure if it's possible. Here is a simple test case that won't compile. Is there something wrong with my syntax, or is this simply not possible? struct A { template<typename T> void f() { } template<typename T> void operator()() { } }; int main() { A a; a.f<int>(); // This compiles. a.operator()<int>(); // This compiles. a<int>(); // This won't compile. return 0; }

  Read the article

• How to pass sockets created to another Java Process

  - by whoi

  Hi; We have an application which creates many sockets which belongs to its thread, By design if this application somehow fails, all threads stop which is not wanted. So to overcome this issue, each thread must be separated from the main application, if one of the threads fails, the other ones should be running. One thing in our mind is to pass created socket to another java process, so what is the correct way? An other approach also is welcome? Waiting for your suggestions...

  Read the article

• Simple Java math operations

  - by user1730056

  I'm making a BMI calculator that doesn't seem to be working. The math operations work if i just do something like w/h, but once i had the brackets, it returns an error. If i change the variables w and h and use a constant number, the operation works. Another problem is that although i'm making result a double, it seems to be rounding to the nearest int. Could someone tell me what I'm doing wrong here? public class ass10 { public static void main(String[] args) { bmi(223,100); } public static bmi(int w, int h){ double result; result = (w/(h*h))*703 System.out.println(result) } }

  Read the article

• In R draw two lines, with slopes double and half the value of the best fit line

  - by D W

  I have data with a best fit line draw. I need to draw two other lines. One needs to have double the slope and the other need to have half the slope. Later I will use the region to differentially color points outside it as per: http://stackoverflow.com/questions/2687212/conditionally-colour-data-points-outside-of-confidence-bands-in-r Example dataset: ## Dataset from http://www.apsnet.org/education/advancedplantpath/topics/RModules/doc1/04_Linear_regression.html ## Disease severity as a function of temperature # Response variable, disease severity diseasesev<-c(1.9,3.1,3.3,4.8,5.3,6.1,6.4,7.6,9.8,12.4) # Predictor variable, (Centigrade) temperature<-c(2,1,5,5,20,20,23,10,30,25) ## For convenience, the data may be formatted into a dataframe severity <- as.data.frame(cbind(diseasesev,temperature)) ## Fit a linear model for the data and summarize the output from function lm() severity.lm <- lm(diseasesev~temperature,data=severity) # Take a look at the data plot( diseasesev~temperature, data=severity, xlab="Temperature", ylab="% Disease Severity", pch=16, pty="s", xlim=c(0,30), ylim=c(0,30) ) title(main="Graph of % Disease Severity vs Temperature") par(new=TRUE) # don't start a new plot abline(severity.lm, col="blue")

  Read the article

• Java swing doesn't show changes to source

  - by out_sider

  I'm using Java Swing graphical editor with netbeans to make my project...but using it brings some limitations like I can't add to a jpanel an image,using java swing options. So i'll need to code it, implementing a new jPanel. My problem is that the code generated by the java swing graphical editor can't be edited so instead of adding the new JPanel code in the initComponents() section I'm doing it after this function is called in the constructor of my main JPanel. But any code I add is not recognized by the "Designer" which means that after making my coded objects I can't use them in the "Designer" and everything must be coded, which is a pain considering how much easier is previewing and moving elements in the "Designer" tool. How can I code what I want but steel appear in the "DEsigner"? Thx in advance

  Read the article

• Set intersection of two strings

  - by user1785712

  import java.util.*; class set { public static void main(String args[]) { TreeSet<Character> t1 = new TreeSet<Character>(); TreeSet<Character> t2 = new TreeSet<Character>(); String s1 = "Ambitab bachan"; String s2 = "Ranjikanth"; for(char c1:s1.toCharArray()) t1.add(c1); for(char c2:s2.toCharArray()) t2.add(c2); t2.retainAll(t1); System.out.println(t2); } } this program find the common character in two different string. in this program Treeset is used to store the value and retainAll() method is used to find the common characters. can anybody help me reduce the line of coding.thanks in advance

  Read the article

• Structure within union and bit field

  - by java

  #include <stdio.h> union u { struct st { int i : 4; int j : 4; int k : 4; int l; } st; int i; } u; int main() { u.i = 100; printf("%d, %d, %d", u.i, u.st.i, u.st.l); } I'm trying to figure out the output of program. The first outputs u.i = 100 but I can't understand the output for u.st.i and u.st.l. Please also explain bit fields.

  Read the article

• Bash redirection: save stderr/stdout to different files and still print them out on a console

  - by Alby

  Here is a simple program. class Redirection { public static void main (String args[]){ System.out.println("Hello World_Stdout"); System.err.println("Hello World_Stderr"); } } I want to see the all the outputs on a console, but at the same time I want to store stdout and stderr in different files. I tried the following command, to no avail. $java Redirection 3>&1 2>stderr 1>stdout 1>&3 2>&3 stderr& stdout files have the file size of 0. So basically I want to do what "tee" command does but I also want to capture stderr as well.

  Read the article

• Jquery to slide on load

  - by Pexsol

  I have a simple slider that works on click. How can I automate it so it runs automatically yet keeping the click function as it is? $(document).ready(function() { var currentPosition = 0; var slideHeight = 360; var slides = $('.main-item'); var numberOfSlides = slides.length; var tracker = 0; $('.slider-height').css('height', slideHeight * numberOfSlides); $('.slide-option li a').click(function() { tracker = $('.slide-option li a').index($(this)); $('.slide-option li a').removeClass('current-item'); $(this).addClass('current-item'); //alert(tracker); $('.slider-height').animate({ 'top': slideHeight * (-tracker) }); return false; //alert(tracker); }); });

  Read the article

• Custom Global Hotkey

  - by UK

  I am trying to get the user defined global hot key for my application. Here is my application code, user.rc CONTROL "", IDC_MHOTKEY, HOTKEY_CLASS, WS_TABSTOP, 91, 86, 68, 14 function.cpp WORD wHotKey = SendDlgItemMessage(hwnd, IDC_MHOTKEY, HKM_GETHOTKEY, 0, 0); GLOBAL_HOTKEY= wHotKey; RegisterHotKey ( NULL, TURN_OFF_HOTKEY, HIBYTE(LOWORD(wHotKey)) , wHotKey); main.cpp if ( messages.message == WM_HOTKEY && ( HIWORD ( messages.lParam ) == GLOBAL_HOTKEY) ) alert("Coming only for Single Key"); This code works well, Only If the user selects a single key and not working when he selects multiple key combined like CTRL+F8.

  Read the article

• OSGI bundle (or service)- how to register for a given time period?

  - by Alec

  Hello, all! Search did not give me a hint, how can i behave with the following situation: I'd love to have 2 OSGI implementations of the same interface: one is regular, the other should work (be active/present/whatever) on the given time period (f.e for Christmas weeks :)) The main goal is to call the same interface without specifying any flags/properties/without manual switching of ranking. Application should somehow switch implementation for this special period, doing another/regular job before and after :) I'm a newbie, maybe i do not completely understand OSGI concept somewhere, sorry for that of give me a hint or link, sorry for my English. Using Felix/Equinox with Apache Aries.

  Read the article

• Pass, edit and return variable in C

  - by Supertecnoboff

  I am new to C programming and recently I have been playing around with functions in C programming. But I have a simple problem: Basically I want to pass an integer to a function, have the function edit it and then pass back the integer to the main function. I am working on this but it isn't working..... Here is my code: int update_SEG_values(int DIGIT_1, int DIGIT_2) { // How many tens in the "TEMP_COUNT". DIGIT_2 = ((TEMP_COUNT) / 10); // How much is left for us to display. TEMP_COUNT = TEMP_COUNT - ((DIGIT_2) * 10); // How many ones. DIGIT_1 = ((TEMP_COUNT) / 1); return(DIGIT_1, DIGIT_2); } What am I doing wrong here?

  Read the article

• Text in gtk.ComboBox without active item

  - by Yotam

  The following PyGTk code, gives a combo-box without an active item. This serves a case where we do not want to have a default, and force the user to select. Still, is there a way to have the empty combo-bar show something like: "Select an item..." without adding a dummy item? import gtk import sys say = sys.stdout.write def cb_changed(w): say("Active index=%d\n" % w.get_active()) topwin = gtk.Window() topwin.set_title("No Default") topwin.set_size_request(0x100, 0x20) topwin.connect('delete-event', gtk.main_quit) vbox = gtk.VBox() ls = gtk.ListStore(str, str) combo = gtk.ComboBox(ls) cell = gtk.CellRendererText() combo.pack_start(cell) combo.add_attribute(cell, 'text', 0) combo.connect('changed', cb_changed) ls.clear() map(lambda i: ls.append(["Item-%d" % i, "Id%d" % i]), range(3)) vbox.pack_start(combo, padding=2) topwin.add(vbox) topwin.show_all() gtk.main() say("%s Exiting\n" % sys.argv[0]) sys.exit(0)

  Read the article

• Problem with nhibernate join

  - by MexicanHacker

  I'm trying to do a join like this using fluent nhibernate: Id(x => x.Id); Map(x => x.SourceSystemRecordId,"sourceSystemRecord_id"); Then Join("cat.tbl_SourceSystemRecords", SourceSystemRecords); But, it seems I don't have a way to specify the column I want to join with from the first table, in this case I need to join on SourceSystemRecordId and not on Id Is there any way I can specify this? I tried References() but that requires me to create an object for this relationship, what I need is to aggregate the columns in sourcesystem records to the ones in the main table.

  Read the article

• How to decrease front end development time in a company/team environment?

  - by metal-gear-solid

  How to decrease front end development time in a company/team environment? My company is asking to suggest idea to make front end development process faster? Some points I realized main problem is client never provide right information at first time and many front end developer works on same project on same CSS so everyone makes his own method sometimes. It increase time of process. Graceful degradation and progressive enhancement both takes time to think and development. should we think about it? it increase the project cost. How to judge time estimation by just seeing a PSD for to make PSD in Cross browser Compatible XHTML CSS. Most of the time I always give less time then then takes more time. Any other suggestions to improve work efficiency in a team (50 people) environment?

  Read the article

• C++ std::equal -- rationale behind not testing for the 2 ranges having equal size?

  - by ShaChris23

  I just wrote some code to test the behavior of std::equal, and came away surprised: int main() { try { std::list<int> lst1; std::list<int> lst2; if(!std::equal(lst1.begin(), lst1.end(), lst2.begin())) throw std::logic_error("Error: 2 empty lists should always be equal"); lst2.push_back(5); if(std::equal(lst1.begin(), lst1.end(), lst2.begin())) throw std::logic_error("Error: comparing 2 lists where one is not empty should not be equal"); } catch(std::exception& e) { std::cerr << e.what(); } } The output (a surprise to me): Error: comparing 2 lists where one is not empty should not be equal Observation: why is it the std::equal does not first check if the 2 containers have the same size() ? Was there a legitimate reason?

  Read the article

• Newbie: C, casting, String hexa to bin after logical operations

  - by user355926

  I want: 111 || 100 ---> 111, not 1 100 && 100 ---> 100, not 1 101 && 010 ---> 000, not 0 Broken code #include <stdio.h> main(void){ string hexa = 0xff; strig hexa2 = 0xf1; // CONVERT TO INT??? cast int hexa3 = hexa || hexa2; int hexa4 = hexa && hexa2; puts(hexa3); puts(hexa4); }

  Read the article

• What magical thing could be killing my Drupal session and anywhere from 15-45 minutes of activity?

  - by jini

  I am using a standard Drupal install hosted on a LAMP stack. My settings.php has the following set: ini_set('session.gc_probability', 1); ini_set('session.gc_divisor', 100); ini_set('session.gc_maxlifetime', 200000); ini_set('session.cookie_lifetime', 2000000); my php.ini file has: session.gc_probability = 1 session.gc_divisor = 1000 session.gc_maxlifetime = 1440 Also I have checked that the safe mode is off so that my settings.php file is able to override main php.ini variables. Also since the person can get log out at 15 minutes, it is making me wonder whether php.ini has anything to do with it anyways. I have combed through my code and it seems to work fine on my local host however on server it is having issues. Where else can i possibly check?????

  Read the article

• C# Console Application - Odd behaviour - char '\a'

  - by KHT

  After extensive debugging of an application, I noticed the console window would hang when searching text for the char '\a'. The goal is to strip out characters from a file. The console window would always hang upon exiting the program, and it would make it to the last statement of main. I removed the '\a' from the switch statement and the console application does not hang anymore. Any idea why? I still need to strip out the char '\a', but cannot get the application to work without hanging. switch (c) { case '\t': //Horizontal Tab case '\v': //Vertical Tab case '\n': //Newline case '\f': //Form feed case '\r': //carriage return case '\b': //Backspace case '\x7f': //delete character case '\x99': //TM Trademark case '\a': //Bell Alert **REMOVED THIS** return true; }

  Read the article

• simple c++ file opening issue

  - by Robert

  #include <iostream> #include <fstream> using namespace std; int main () { ofstream testfile; testfile.open ("test.txt"); testfile << "success!\n"; testfile.close(); return 0; } 1)called "g++ testfile.cpp" 2)created "test.txt" 3)called "chmod u+x a.out" 4)??? 5)file remains blank. I feel like an idiot for failing at something as trivial as this is supposed to be.

  Read the article

• [c++] does a const reference prolong the life of a temporary or not?

  - by Kyle

  Why is the output to this #include <string> #include <iostream> using namespace std; class Sandbox { public: Sandbox(const string& n) : member(n) {} const string& member; }; int main() { Sandbox sandbox(string("four")); cout << sandbox.member << endl; return 0; } this The answer is: and not The answer is: four ?

  Read the article

< Previous Page | 767 768 769 770 771 772 773 774 775 776 777 778  | Next Page >