Search Results

Search found 28818 results on 1153 pages for 'main loop'.

Page 782/1153 | < Previous Page | 778 779 780 781 782 783 784 785 786 787 788 789  | Next Page >

  • Dynamic memory allocation with default values

    - by viswanathan
    class A { private: int m_nValue; public: A() { m_nValue = 0; } A(int nValue) { m_nValue = nValue); ~A() {} } Now in main if i call A a(2);// 2 will be assigned for m_nValue of object A. Now how do we do this if i want to define an array of objects. Also how do we do this if i dynamically create objects using operator new like A *pA; pA = new A[5];// while creating the object i want the parameterised constructor to be //called I hope the question is clear. Do let me know if more explanation is needed

    Read the article

  • Java inheritance question

    - by user247866
    So I have 3 classes. Abstract class A Class B extends class A independent Class C In class D that contains the main method, I create a list of instances of class B List<B> b = method-call();` // the method returns a list of instances of class B Now in class C I have one method that is common to both A and B, and hence I don't want to duplicate it. I want to have one method that takes as input an instance of class A, as follows: public void some-method(LIst<A> a) However, when I do: C c = new C(). c. some-method(b) I get an error that some-method is not applicable for the argument List, instead it's expecting to get List. Is there a good way to fix this problem? Many thanks!

    Read the article

  • Best way to develop a secured application. With .net

    - by John S
    Hello, we are developing a windows application, and as most apps out there, there is a login form. What I don't like is that the login form validates the user and opens the main form if user and pass are correct. Simple as is. All the function calls etc are called without verifying the user and pass again, what should be the right thing to do. What's the best way to develop a secured application that if for any reason, the login form is by passed, the other function calls won't run? Some devs suggested that we include an user and pass params on each function, which seems to be wrong... thanks!

    Read the article

  • Understanding behaviour of read() and write()

    - by neo730
    hi i am a student and just start learning low level c programming.i tried to understand read() and write() methods with this program. #include <unistd.h> #include <stdlib.h> main() { char *st; st=calloc(sizeof(char),2);//allocate memory for 2 char read(0,st,2); write(1,st,2); } i was expecting that it would give segmentation fault when i would try to input more than 2 input characters.but when i execute program and enter " asdf " after giving " as " as output it executes "df" command. i want to know why it doesn't give segmentation fault when we assign more than 2 char to a string of size 2.and why is it executing rest(after 2 char)of input as command instead of giving it as output only? also reading man page of read() i found read() should give EFAULT error,but it doesn't. I am using linux.

    Read the article

  • Getting URL of executing JavaScript file (IE6-7 problem mostly)...

    - by TooTallNate
    Hey all, I've been trying to throw together a generic function that retrieves the absolute URL of an executing JavaScript file on a web page: http://gist.github.com/433486 It works great in almost all the browsers I've tested (Firefox, Chrome, Safari, Opera v10 at least, and IE 8). It seems to fail, however, in IE 6 and 7. The callback function gets executed, but the retrieved name is simple the URL to the main HTML page, not the JavaScript file. So all I'm really asking is if there's some other way of getting the URL of the current JavaScript file (which could be IE 6 and 7 specific)? Thanks in advance!

    Read the article

  • Multiply without multiplication, division and bitwise operators, and no loops. Recursion

    - by lxx22
    public class MultiplyViaRecursion{ public static void main(String[] args){ System.out.println("8 * 9 == " + multiply(8, 9)); System.out.println("6 * 0 == " + multiply(6, 0)); System.out.println("0 * 6 == " + multiply(0, 6)); System.out.println("7 * -6 == " + multiply(7, -6)); } public static int multiply(int x, int y){ int result = 0; if(y > 0) return result = (x + multiply(x, (y-1))); if(y == 0) return result; if(y < 0) return result = -multiply(x, -y); return result; } } My question is very simple and basic, why after each "if" the "return" still cannot pass the compilation, error shows missing return.

    Read the article

  • Is this syntactically correct?

    - by Borrito
    I have code in one of the source file as follows: #include <stdio.h> #include <math.h> int a ; int b = 256 ; int c = 16 ; int d = 4 ; int main() { if ((d <= (b) && (d == ( c / sizeof(a)))) { printf("%d",sizeof(a) ); } return 0; } I have removed the casts and have simplified on the data names. The sizeof(a) can be taken as 4. I want to know if the the if syntax is a valid one and if so why doesn't it execute? PS : I haven't sat down on this for long due to time constraints. Pardon me if you find a childish error in the code.

    Read the article

  • Inconsistent behaviour from SDL_BlitSurface

    - by bardes
    Here is an example code: #include <SDL/SDL.h> #include <SDL/SDL_image.h> #include <stdio.h> int main() { if(SDL_Init(SDL_INIT_EVERYTHING) == -1) { printf("SDL ERROR: %s", SDL_GetError()); return 1; } SDL_Surface *screen; screen = SDL_SetVideoMode(128, 128, 32, SDL_SWSURFACE); SDL_Surface *img; img = IMG_Load("./debug.png"); SDL_BlitSurface(img, NULL, screen, NULL); SDL_Flip(screen); SDL_Delay(1000); SDL_FreeSurface(img); SDL_Quit(); return 0; } It compiles fine, but when I run it sometimes it works and most times only part of the image is displayed. I really can't imagine what's causing that... EDIT: This is the image I'm using to test the program: http://img140.imageshack.us/img140/3858/debugi.png

    Read the article

  • equivalent to getch(), mac/linux crash

    - by acidzombie24
    Hey guys. So I am using getch() and my app crashes instantly. Including when doing: int main() { getch(); } I can't find the link but supposedly the problem is, it needs to turn off buffering or something strange along those lines and I still want cout to work along with cross platform code. I was told to use std::cin.get(), but I'd like the app to quit when a key is pressed, not when the user typed in a letter or number then press enter to quit. Is there any function for this? The code must work under Mac (my os) and Windows.

    Read the article

  • floating point exception in C++ code !

    - by mekasperasky
    #include<stdio.h> #include<math.h> int main () { FILE *fp; fp=fopen("output","w"); float t,y=0,x=0,e=5,f=1,w=1; for (t=0;t<10;t=t+0.01) { if( y==inf && y== nan) break; fprintf(fp,"%lf\t%lf\n",y,x); y = y + ((e*(1 - x*x)*y) - x + f*cos(w*t))*t; x = x + y*t; } return (0); } why is the ouput giving infinite and NAN values?

    Read the article

  • Weird output as the numbers get bigger in Fibonacci sequence

    - by Jon
    I noticed in my fibonacci sequence that I'm getting negative numbers after a certain point. Does this have to do with the limited range of "int"? or is there something wrong with my code? Here is the code: using std::cout; int main() { int n = 50, f1 = 0, f2 = 1, fn = 0, i = 0; cout << "0 "; for (i = 0; i < n; i++) { fn = f1 + f2; f2 = f1; f1 = fn; cout << fn << " "; }

    Read the article

  • Not working giving error #1069

    - by NativeCoder
    for ( var i:int = 0 ; i < 1; i++) { for ( var j:int = 0 ; j < 1; j++) { if (shape[j][i] == 0 ) { pencil.graphics.beginFill(0); pencil.graphics.drawRect(10,10,5,5); pencil.graphics.endFill(); } } } i am trying to run this code where shape is an array 2*2 gives an error ReferenceError: Error #1069: Property 0 not found on Number and there is no default value. at Main() need help

    Read the article

  • Which icons/buttons to use for help, about, info?

    - by 4thSpace
    I use the info button to display a settings page. This page is a modal. I need another button from here to display "About" info, since I've already used "info" for something. I have a search form that is accessed only from the modal. On the search form, I need a help icon. I can use the info button but that seems confusing, since I already use the info button from the main view to access the modal. What else can I do for help and about icons/buttons?

    Read the article

  • Can typeid() be used to pass a function?

    - by Kerb_z
    I tried this and got the output as: void Please explain the following Code: #include <cstdio> #include <typeinfo> using namespace std ; void foo() { } int main(void) { printf("%s", typeid(foo()).name());// Please notice this line, is it same as typeid( ).name() ? return 0; } AFAIK: The typeid operator allows the type of an object to be determined at run time. So, does this sample code tell us that a function that returns void is of *type void*. I mean a function is a method and has no type. Correct?

    Read the article

  • How to compare string with const char*?

    - by arzeth
    #include <stdlib.h> #include <stdio.h> #include <iostream> #include <string.h> using namespace std; int main() { string cmd; while(strcmp(cmd.c_str(),"exit")==0 && strcmp(cmd.c_str(),"\exit")==0) { cin>>cmd; cout<<cmd; } return 0; } I am stuck.

    Read the article

  • C Struct as an argument

    - by Brian
    I'm wondering what's the difference between sample1 and sample2. Why sometimes I have to pass the struct as an argument and sometimes I can do it without passing it in the function? and how would it be if samplex function needs several structs to work with? would you pass several structs as an argument? struct x { int a; int b; char *c; }; void sample1(struct x **z;){ printf(" first member is %d \n", z[0]->a); } void sample2(){ struct x **z; printf(" first member is %d \n", z[0]->a); // seg fault } int main(void) { struct x **z; sample1(z); sample2(); return 0; }

    Read the article

  • How to distinguish between new and returning anonymous Drupal users?

    - by Matt V.
    Is there an easy way (or a module) in Drupal to distinguish between anonymous users who have never created an account versus those who are returning but are not currently logged in? For non-returning (ie, completely new) users, I'd like to have a front page that is very streamlined and focused on registration as the call-to-action. However, if someone is a returning user but not currently logged in, I'd like to present a lot more information on the front page and have login as the main call-to-action. I realize both pages would still need to have both login and register options available, I just want to make the focus significantly different between the two.

    Read the article

  • Confusing calling method in Java

    - by vBx
    class Parent { private void method1() { System.out.println("Parent's method1()"); } public void method2() { System.out.println("Parent's method2()"); method1(); } } class Child extends Parent { public void method1() { System.out.println("Child's method1()"); } } class test { public static void main(String args[]) { Parent p = new Child(); p.method2(); } } I'm confuse why does in Parent::method2() when invoking method1() it will cal Parents method1() and not Childs method1 ? I see that this happens only when method1() is private? Can someone explain me why ? Thanks you.

    Read the article

  • How to simulate Func<T1, T2, TResult> in C++?

    - by Zach
    Hello all, In C#, I use Func to replace Factories. For example: class SqlDataFetcher { public Func<IConnection> CreateConnectionFunc; public void DoRead() { IConnection conn = CreateConnectionFunc(); // call the Func to retrieve a connection } } class Program { public void CreateConnection() { return new SqlConnection(); } public void Main() { SqlDataFetcher f = new SqlDataFetcher(); f.CreateConnectionFunc = this.CreateConnection; ... } } How can I simulate the code above in C++?

    Read the article

  • c++ constructors

    - by aharont
    i wrote this code: class A { public: A(){d=2.2;cout<<d;} A(double d):d(d){cout<<d;} double getD(){return d;} private: double d; }; class Bing { public: Bing(){a=A(5.3);} void f(){cout<<a.getD();} private: A a; }; int main() { Bing b; b.f(); } i get the output: 2.2 5.3 5.3 instead of 5.3 5.3. it's something in the constructor.... wahy am i getting this? how can i fix it?

    Read the article

  • What is the correct way to set size of elements of GUI?

    - by Roman
    I am using swing to create my GUI. J have a JFrame containing one main JPanel which, in its turn contain several JPanels which, in their turn, contain buttons. I would like to set certain sizes to mu buttons and JPanels. How does it work? Should I set sizes of my buttons and then the size of the JPanel and the JFrame will be set according to the buttons sizes? Or it works in the opposite direction? I set size for the JPanel and the size of the buttons will be set automatically?

    Read the article

  • Compare to a defined constants in C?

    - by J.W.
    I am trying to compare to a defined constants in C, and I have simplified my program to the following.. #include "stdio.h" #include "stdlib.h" #define INVALID_VALUE -999; int main(int argc, const char* argv[]) { int test=0; if(test==INVALID_VALUE) //The error line.. return INVALID_VALUE; return 0; }; And when I use gcc to compile. it gives out error "error: expected ‘)’ before ‘;’ token" Any reason that this cannot be done.

    Read the article

  • I have a Segmentation fault (core dumped) when using strcpy, malloc, and struct

    - by malsh002
    Okay, when I run this code, I have a segmentation fault #include<stdio.h> #include<stdlib.h> #include<string.h> #define MAX 64 struct example { char *name; }; int main() { struct example *s = malloc (MAX); strcpy(s->name ,"Hello World!!"); return !printf("%s\n", s->name); } the terminal output: alshamlan@alshamlan-VGN-CR520E:/tmp/interview$ make q1 cc -Wall -g q1.c -o q1 alshamlan@alshamlan-VGN-CR520E:/tmp/interview$ ./q1 Segmentation fault (core dumped) alshamlan@alshamlan-VGN-CR520E:/tmp/interview$ gedit q1.c Can someone explain what's going on? thanks.

    Read the article

< Previous Page | 778 779 780 781 782 783 784 785 786 787 788 789  | Next Page >