Search Results

Search found 5306 results on 213 pages for 'mark sp'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 8/213 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • Is it possible to repair a Cisco 3500 XL (3548) switch with POST Error messages?

    - by Alex
    I've got an old Cisco 3500 XL, and it seems to have hardware issues. I've loaded the latest IOS and cleared all config. Does anyone have any experience fixing the switch core? I'm a reasonably competent SMD solderer, can I replace/reflow some chips? I've checked the power supply voltages and it's all within tolerance, and no visible signs of any component damage. Some chips are hot to the touch. I understand that these were EOL as of 2007, but should have a lifetime warranty for the electronics. I don't have a Cisco support contract, so I can't file a ticket. What should I do? Console output: switch: dir flash: Directory of flash:/ 2 -rwx 1811584 <date> c3500xl-c3h2s-mz.120-5.WC17.bin 1799680 bytes available (1812992 bytes used) switch: boot Loading "flash:c3500xl-c3h2s-mz.120-5.WC17.bin"...################################################################################################################################################################################### File "flash:c3500xl-c3h2s-mz.120-5.WC17.bin" uncompressed and installed, entry point: 0x3000 executing... Restricted Rights Legend Use, duplication, or disclosure by the Government is subject to restrictions as set forth in subparagraph (c) of the Commercial Computer Software - Restricted Rights clause at FAR sec. 52.227-19 and subparagraph (c) (1) (ii) of the Rights in Technical Data and Computer Software clause at DFARS sec. 252.227-7013. cisco Systems, Inc. 170 West Tasman Drive San Jose, California 95134-1706 Cisco Internetwork Operating System Software IOS (tm) C3500XL Software (C3500XL-C3H2S-M), Version 12.0(5)WC17, RELEASE SOFTWARE (fc1) Copyright (c) 1986-2007 by cisco Systems, Inc. Compiled Tue 13-Feb-07 15:04 by antonino Image text-base: 0x00003000, data-base: 0x00352924 Initializing C3500XL flash... flashfs[1]: 1 files, 1 directories flashfs[1]: 0 orphaned files, 0 orphaned directories flashfs[1]: Total bytes: 3612672 flashfs[1]: Bytes used: 1812992 flashfs[1]: Bytes available: 1799680 flashfs[1]: flashfs fsck took 3 seconds. flashfs[1]: Initialization complete. ...done Initializing C3500XL flash. C3500XL POST: System Board Test: Passed C3500XL POST: Daughter Card Test: Passed C3500XL POST: CPU Buffer Test: Passed C3500XL POST: CPU Notify RAM Test: Passed C3500XL POST: CPU Interface Test: Passed C3500XL POST: Testing Switch Core: Passed Error with Switch Core BIST test Phase 0. Returns: Test Complete Low : 0x0FFFFFFF, Test Complete High : 0xFFFFFFFE Test Phase Low : 0x00000040, Test Phase High : 0x00000000 Test Phase Third : 0x00000000, Test Complete Third : 0x000001F8 C3500XL POST FAILURE: Testing Switch Core: Failed C3500XL POST FAILURE: Testing Buffer Table: Failed C3500XL POST FAILURE: Data Buffer Test: Failed C3500XL POST FAILURE: Configuring Switch Parameters: Failed C3500XL POST FAILURE: Switch Core BIST failed. C3500XL POST FAILURE: Cannot test Modules due to failure of Switch Core POST Del Mar Failure (0th Del Mar): req system failed to init C3500XL POST FAILURE: C3500XL POST FAILURE: ATM: required system failed to init C3500XL POST: Ethernet Controller Test: Passed C3500XL POST FAILURE: MII Test: Failed C3500XL POST FAILURE: Error waiting for Ethernet Controller and SW_PARAMS C3500XL POST FAILURE: Initialization/POST failed C3500XL POST FAILURE: AT: Failing because system POST failed Exception (8192)! Debug Exception (Could be NULL pointer dereference) CPU Register Context: Vector = 0x00002000 PC = 0x000F36F4 MSR = 0x00029200 CR = 0x22000024 LR = 0x000F6964 CTR = 0x001DE46C XER = 0x00000000 R0 = 0x00000000 R1 = 0x004E2580 R2 = 0x00000000 R3 = 0x00000000 R4 = 0x00000001 R5 = 0x00000000 R6 = 0x004E2718 R7 = 0x004E2718 R8 = 0x00000008 R9 = 0x00000000 R10 = 0x0000FFFF R11 = 0x00480000 R12 = 0x42000024 R13 = 0x00000000 R14 = 0x00000000 R15 = 0x00000000 R16 = 0x00000000 R17 = 0x00000000 R18 = 0x00000000 R19 = 0x00000000 R20 = 0x00000000 R21 = 0x00000000 R22 = 0x00000000 R23 = 0x00000000 R24 = 0x00000000 R25 = 0x00000020 R26 = 0x004E2718 R27 = 0x004E2718 R28 = 0x00000020 R29 = 0x00002513 R30 = 0x00000001 R31 = 0x00000000 Stack trace: PC = 0x000F36F4, SP = 0x004E2580 Frame 00: SP = 0x004E25A0 PC = 0x40000016 Frame 01: SP = 0x004E2618 PC = 0x000F6964 Frame 02: SP = 0x004E26A8 PC = 0x000F76DC Frame 03: SP = 0x004E26C8 PC = 0x000E8114 Frame 04: SP = 0x004E26F0 PC = 0x001F5BF8 Frame 05: SP = 0x004E2710 PC = 0x001F5CF4 Frame 06: SP = 0x004E2748 PC = 0x0023F4DC Frame 07: SP = 0x004E2750 PC = 0x0023E650 Frame 08: SP = 0x004E27C8 PC = 0x0023E89C Frame 09: SP = 0x004E27E0 PC = 0x0028AF34 Frame 10: SP = 0x004E27E8 PC = 0x001E38F8 Frame 11: SP = 0x004E2808 PC = 0x001E39A8 Frame 12: SP = 0x004E2820 PC = 0x0014E220 Frame 13: SP = 0x004E28C8 PC = 0x0014E39C Frame 14: SP = 0x00000000 PC = 0x001EB510

    Read the article

  • Windows Embedded Standard 7 : la Technical Preview du SP1 est disponible, elle inclut les fonctionnalités du SP 1 de Windows 7

    La CTP du Service Pack 1 de Windows Embedded Standard 7 Elle inclut les fonctionnalités du SP 1 de Windows 7 Mise à jour du 04/01/11 par Hinault Romarick Microsoft annonce la disponibilité de la Community Technical Preview (CTP) du Service Pack 1 de Windows Embedded Standard 7, son système d'exploitation embarqué fondé sur Windows 7. La CTP du Service pack 1 de Windows Embedded Standard 7 inclut toutes les mises à jour du service pack 1 (disponible en release candidate) de Windows 7 y c...

    Read the article

  • Is there an example for mark with right gravit?

    - by Runner
    Quoted from here: The standard left-to-right cursor is a mark with right gravity (when you type, the cursor stays on the right side of the text you're typing). Now I see what's an mark with right gravity. But I still don't have an idea what's a mark with left gravity like,is there an example of left gravity mark?

    Read the article

  • How to pass parameters to stored procedure ?

    - by Kumara
    I used SQL Server 2005 for my small web application. I Want pass parameters to SP . But there is one condition. number of parameter that can be change time to time. Think ,this time i pass neme and Address , next time i pass name,sirname,address , this parameter range may be 1-30 , Please send any answer if you have,Thanks

    Read the article

  • SQL Server: How to remove empty lines in SSMS?

    - by atricapilla
    I have many .sql files with lots of empty lines e.g. WITH cteTotalSales (SalesPersonID, NetSales) AS ( SELECT SalesPersonID, ROUND(SUM(SubTotal), 2) FROM Sales.SalesOrderHeader WHERE SalesPersonID IS NOT NULL GROUP BY SalesPersonID ) SELECT sp.FirstName + ' ' + sp.LastName AS FullName, sp.City + ', ' + StateProvinceName AS Location, ts.NetSales FROM Sales.vSalesPerson AS sp INNER JOIN cteTotalSales AS ts ON sp.BusinessEntityID = ts.SalesPersonID ORDER BY ts.NetSales DESC Is ther a way to remove these empty lines in SQL Server Management Studio? This is what I would like to have: WITH cteTotalSales (SalesPersonID, NetSales) AS ( SELECT SalesPersonID, ROUND(SUM(SubTotal), 2) FROM Sales.SalesOrderHeader WHERE SalesPersonID IS NOT NULL GROUP BY SalesPersonID ) SELECT sp.FirstName + ' ' + sp.LastName AS FullName, sp.City + ', ' + StateProvinceName AS Location, ts.NetSales FROM Sales.vSalesPerson AS sp INNER JOIN cteTotalSales AS ts ON sp.BusinessEntityID = ts.SalesPersonID ORDER BY ts.NetSales DESC

    Read the article

  • Where / how often do I need to show trademarks and registration marks for 3rd-party software?

    - by Aidan Ryan
    In the application my company publishes, we refer to 3rd-party software in several places: user manual, in the application UI itself, etc. Are we legally required to display the trademark or registration mark symbols next to the trademarked/registered names of 3rd-party software? If so, must they be displayed every time the name is mentioned, or is it sufficient to acknowledge the registration once (for example, in the application's splash screen or the introduction section of the user manual)?

    Read the article

  • iptables forwarding to a dummy interface

    - by madinc
    Hi, I'm trying to accomplish the following: I have a box with a service listening on a dummy interface (say 172.16.0.1), udp port 5555. Now what I'd like to do is to take packets that arrive on interfaces eth0 (1.1.1.1:5555) and eth1 (2.2.2.2:5555) and forward them to the service on the dummy interface, and have replies go back to clients out the same physical interface they came in. Clients must think they're talking to 1.1.1.1:5555 or 2.2.2.2:5555. I think I need a mix of iptables rules and packet marking, plus some iproute rules (if it's possible at all). What I tried is to catch packets coming in from eth0 and eth1, udp port 5555, and mark them with 1 and 2 respectively, and --save-mark in the connmark. Then I used a DNAT to 172.16.0.1. The service seems to be getting the packets. Now I'm not sure how to do the reverse. It seems that for packets originating from the box, you can't do anything before the routing decision, but that would be the place to restore the marks, and thus make a routing decision based on those. Here's what I have so far: iptables -t mangle -A PREROUTING -d 1.1.1.1 -p udp --port 5555 -j MARK --set-mark 1 iptables -t mangle -A PREROUTING -d 2.2.2.2 -p udp --port 5555 -j MARK --set-mark 2 iptables -t mangle -A PREROUTING -d 1.1.1.1 -p udp --port 5555 -j CONNMARK --save-mark iptables -t mangle -A PREROUTING -d 2.2.2.2 -p udp --port 5555 -j CONNMARK --save-mark iptables -t nat -A PREROUTING -m mark --mark 1 -j DNAT --to-destination 172.16.0.1 iptables -t nat -A PREROUTING -m mark --mark 2 -j DNAT --to-destination 172.16.0.1 # What next? As I said, I'm not even sure it can be done. To give a bit of background, it's an old OpenVPN installation that cannot be upgraded (otherwise I'd install a recent version that supports multihoming natively). Thanks for any help.

    Read the article

  • La RC2 de ASP.NET MVC3 disponible : encore plus performante, elle est compatible avec la beta du SP 1 de Visual Studio 2010

    La RC2 de ASP.NET MVC3 disponible Encore plus performante, elle est compatible avec la beta du SP 1 de Visual Studio 2010 Mise à jour du 13/12/10 Microsoft, par le billet de son vice-président de la division de développement Scott Guthrie, vient d'annoncer la sortie de la Release Candidate 2 d'ASP.NET MVC 3. Au menu de cette nouvelle version : La correction de plusieurs bugs et l'optimisation des performances. Les tests de performance sur cette version, selon Guthrie, permettent de constater qu'ASP.NET MVC 3 est nettement plus rapide que la version 2 et que les applications ASP.net MVC existantes, après une mise à...

    Read the article

  • Le SP 1 de Windows 7 et Windows Server 2008 R2 disponible, Microsoft recommande l'installation via Windows Update

    Le SP 1 de Windows 7 et Windows Server 2008 R2 disponible Microsoft recommande l'installation via Windows Update Mise à jour du 23/02/11 Une semaine après sa disponibilité pour les abonnés MSDN/TechNet, le Service Pack 1 de Windows 7 et de Windows Server 2008 R2 est disponible pour tous. Ce SP1 est avant tout un pack cumulatif des mises à jours publiées jusqu'en décembre 2010. Pour Windows Server 2008 R2, il ajoute cependant « deux nouvelles fonctionnalités majeures », souligne justement Jean-Michel Ormes sur son blog Développez. « RemoteFX est une plateforme d'accélération graphique qui permet aux utilisateurs distan...

    Read the article

  • Le SP 1 de Windows 7 et Windows Server 2008 R2 disponible pour les abonnés TechNet et MSDN

    Le SP 1 de Windows 7 et Windows Server 2008 R2 disponible Pour les abonnés TechNet et MSDN Mise à jour du 17/02/11 Microsoft vient de mettre en ligne le premier Service Pack pour Windows 7 et Windows Server 2008 R2. Il est pour l'instant réservé aux abonnées TechNet et MSDN. La version publique sera disponible comme prévue le 22 février prochain. Pour rappel, ce service pack intégrera notamment RemoteFX, une amélioration notable de l'accès distant aux machines sous Windows 7 ou Server 2008 R2, qui devrait offrir une expérience-utilisateur 3D graphiquement riche. Ce SP1 inclura bien entendu l'ensem...

    Read the article

  • R:how to get grep to return the match, rather than the whole string

    - by Mike Dewar
    Hi, I have what is probably a really dumb grep in R question. Apologies, because this seems like it should be so easy - I'm obviously just missing something. I have a vector of strings, let's call it alice. Some of alice is printed out below: T.8EFF.SP.OT1.D5.VSVOVA#4 T.8EFF.SP.OT1.D6.LISOVA#1 T.8EFF.SP.OT1.D6.LISOVA#2 T.8EFF.SP.OT1.D6.LISOVA#3 T.8EFF.SP.OT1.D6.VSVOVA#4 T.8EFF.SP.OT1.D8.VSVOVA#3 T.8EFF.SP.OT1.D8.VSVOVA#4 T.8MEM.SP#1 T.8MEM.SP#3 T.8MEM.SP.OT1.D106.VSVOVA#2 T.8MEM.SP.OT1.D45.LISOVA#1 T.8MEM.SP.OT1.D45.LISOVA#3 I'd like grep to give me the number after the D that appears in some of these strings, conditional on the string containing "LIS" and an empty string or something otherwise. I was hoping that grep would return me the value of a capturing group rather than the whole string. Here's my R-flavoured regexp: pattern <- (?<=\\.D)([0-9]+)(?=.LIS) nothing too complicated. But in order to get what I'm after, rather than just using grep(pattern, alice, value = TRUE, perl = TRUE) I'm doing the following, which seems bad: reg.out <- regexpr( "(?<=\\.D)[0-9]+(?=.LIS)", alice, perl=TRUE ) substr(alice,reg.out,reg.out + attr(reg.out,"match.length")-1) Looking at it now it doesn't seem too ugly, but the amount of messing about it's taken to get this utterly trivial thing working has been embarrassing. Anyone any pointers about how to go about this properly? Bonus marks for pointing me to a webpage that explains the difference between whatever I access with $,@ and attr.

    Read the article

  • Self referencing update SQL statement for Informix

    - by CheeseConQueso
    Need some Informix SQL... Courses get a regular grade, but their associated labs get a grade of 'LAB'. I need to update the table so that the lab grade matches the course grade. Also, if there is no corresponding course for a lab, it means the course was canceled. In that case, I want to place a flag value of 'X' for its grade. Example data before update: id yr sess crs_no hrs grd 725 2009 FA COLL101 3.000000000000 C 725 2009 FA ENGL021 3.000000000000 FI 725 2009 FA ENGL021L 1.000000000000 LAB 725 2009 FA ENGL031 3.000000000000 FNI 725 2009 FA ENGL031L 1.000000000000 LAB 725 2009 FA MATH010 3.000000000000 FNI 725 2010 SP AOTE101 3.000000000000 C 725 2010 SP ENGL021L 1.000000000000 LAB 725 2010 SP ENGL031 3.000000000000 FI 725 2010 SP ENGL031L 1.000000000000 LAB 725 2010 SP MATH010 3.000000000000 FNI 726 2010 SP SPAN101 3.000000000000 FN Example data after update: id yr sess crs_no hrs grd 725 2009 FA COLL101 3.000000000000 C 725 2009 FA ENGL021 3.000000000000 FI 725 2009 FA ENGL021L 1.000000000000 FI 725 2009 FA ENGL031 3.000000000000 FNI 725 2009 FA ENGL031L 1.000000000000 FNI 725 2009 FA MATH010 3.000000000000 FNI 725 2010 SP AOTE101 3.000000000000 C 725 2010 SP ENGL021L 1.000000000000 X 725 2010 SP ENGL031 3.000000000000 FI 725 2010 SP ENGL031L 1.000000000000 FI 725 2010 SP MATH010 3.000000000000 FNI 726 2010 SP SPAN101 3.000000000000 FN I worked out a solution for this, but it required a lot of on-the-fly composite foreign keys built from concatenating the id, yr, sess, and substring'd crs_no. My solution is not only overkill, but it has gaps in it and it takes too long to process. I know there is an easier way to do this, but I've gone so far down one road that I am having trouble thinking of a different approach.

    Read the article

  • JVM CMS Garbage Collecting Issues

    - by jlintz
    I'm seeing the following symptoms on an application's GC log file with the Concurrent Mark-Sweep collector: 4031.248: [CMS-concurrent-preclean-start] 4031.250: [CMS-concurrent-preclean: 0.002/0.002 secs] [Times: user=0.00 sys=0.00, real=0.00 secs] 4031.250: [CMS-concurrent-abortable-preclean-start] CMS: abort preclean due to time 4036.346: [CMS-concurrent-abortable-preclean: 0.159/5.096 secs] [Times: user=0.00 sys=0.01, real=5.09 secs] 4036.346: [GC[YG occupancy: 55964 K (118016 K)]4036.347: [Rescan (parallel) , 0.0641200 secs]4036.411: [weak refs processing, 0.0001300 secs]4036.411: [class unloading, 0.0041590 secs]4036.415: [scrub symbol & string tables, 0.0053220 secs] [1 CMS-remark: 16015K(393216K)] 71979K(511232K), 0.0746640 secs] [Times: user=0.08 sys=0.00, real=0.08 secs] The preclean process keeps aborting continously. I've tried adjusting CMSMaxAbortablePrecleanTime to 15 seconds, from the default of 5, but that has not helped. The current JVM options are as follows... Djava.awt.headless=true -Xms512m -Xmx512m -Xmn128m -XX:MaxPermSize=128m -XX:+HeapDumpOnOutOfMemoryError -XX:+UseParNewGC -XX:+UseConcMarkSweepGC -XX:BiasedLockingStartupDelay=0 -XX:+DoEscapeAnalysis -XX:+UseBiasedLocking -XX:+EliminateLocks -XX:+CMSParallelRemarkEnabled -verbose:gc -XX:+PrintGCTimeStamps -XX:+PrintGCDetails -XX:+PrintHeapAtGC -Xloggc:gc.log -XX:+CMSClassUnloadingEnabled -XX:+CMSPermGenPrecleaningEnabled -XX:CMSInitiatingOccupancyFraction=50 -XX:ReservedCodeCacheSize=64m -Dnetworkaddress.cache.ttl=30 -Xss128k It appears the concurrent-abortable-preclean never gets a chance to run. I read through http://blogs.sun.com/jonthecollector/entry/did_you_know which had a suggestion of enabling CMSScavengeBeforeRemark, but the side effects of pausing did not seem ideal. Could anyone offer up any suggestions? Also I was wondering if anyone had a good reference for grokking the CMS GC logs, in particular this line: [1 CMS-remark: 16015K(393216K)] 71979K(511232K), 0.0746640 secs] Not clear on what memory regions those numbers are referring to.

    Read the article

  • Error in Print Function in Bubble Sort MIPS?

    - by m00nbeam360
    Sorry that this is such a long block of code, but do you see any obvious syntax errors in this? I feel like the problem is that the code isn't printing correctly since the sort and swap methods were from my textbook. Please help if you can! .data save: .word 1,2,4,2,5,6 size: .word 6 .text swap: sll $t1, $a1, 2 #shift bits by 2 add $t1, $a1, $t1 #set $t1 address to v[k] lw $t0, 0($t1) #load v[k] into t1 lw $t2, 4($t1) #load v[k+1] into t1 sw $t2, 0($t1) #swap addresses sw $t0, 4($t1) #swap addresses jr $ra #return sort: addi $sp, $sp, -20 #make enough room on the stack for five registers sw $ra, 16($sp) #save the return address on the stack sw $s3, 12($sp) #save $s3 on the stack sw $s2, 8($sp) #save Ss2 on the stack sw $s1, 4($sp) #save $s1 on the stack sw $s0, 0($sp) #save $s0 on the stack move $s2, $a0 #copy the parameter $a0 into $s2 (save $a0) move $s3, $a1 #copy the parameter $a1 into $s3 (save $a1) move $s0, $zero #start of for loop, i = 0 for1tst: slt $t0, $s0, $s3 #$t0 = 0 if $s0 S $s3 (i S n) beq $t0, $zero, exit1 #go to exit1 if $s0 S $s3 (i S n) addi $s1, $s0, -1 #j - i - 1 for2tst: slti $t0, $s1, 0 #$t0 = 1 if $s1 < 0 (j < 0) bne $t0, $zero, exit2 #$t0 = 1 if $s1 < 0 (j < 0) sll $t1, $s1, 2 #$t1 = j * 4 (shift by 2 bits) add $t2, $s2, $t1 #$t2 = v + (j*4) lw $t3, 0($t2) #$t3 = v[j] lw $t4, 4($t2) #$t4 = v[j+1] slt $t0, $t4, $t3 #$t0 = 0 if $t4 S $t3 beq $t0, $zero, exit2 #go to exit2 if $t4 S $t3 move $a0, $s2 #1st parameter of swap is v(old $a0) move $a1, $s1 #2nd parameter of swap is j jal swap #swap addi $s1, $s1, -1 j for2tst #jump to test of inner loop j print exit2: addi $s0, $s0, 1 #i = i + 1 j for1tst #jump to test of outer loop exit1: lw $s0, 0($sp) #restore $s0 from stack lw $s1, 4($sp) #resture $s1 from stack lw $s2, 8($sp) #restore $s2 from stack lw $s3, 12($sp) #restore $s3 from stack lw $ra, 16($sp) #restore $ra from stack addi $sp, $sp, 20 #restore stack pointer jr $ra #return to calling routine .data space:.asciiz " " # space to insert between numbers head: .asciiz "The sorted numbers are:\n" .text print:add $t0, $zero, $a0 # starting address of array add $t1, $zero, $a1 # initialize loop counter to array size la $a0, head # load address of print heading li $v0, 4 # specify Print String service syscall # print heading out: lw $a0, 0($t0) # load fibonacci number for syscall li $v0, 1 # specify Print Integer service syscall # print fibonacci number la $a0, space # load address of spacer for syscall li $v0, 4 # specify Print String service syscall # output string addi $t0, $t0, 4 # increment address addi $t1, $t1, -1 # decrement loop counter bgtz $t1, out # repeat if not finished jr $ra # return

    Read the article

  • "Dedication of the Harvard Mark I computer, 1944 August 7"- Which text is Brooks referring to and where can I find it?

    - by JW01
    I am reading the epilogue of the Anniversary Edition of the Mythical Man Month. The author, Frederic Brooks, says Still vivid in my mind is the wonder and delight with which I - then 13 years old - read the account of the August 7, 1944, dedication of the Harvard Mark I computer... Which text is he referring to? I want to be filled with wonder and delight too. Where can get hold of this text so that I can read it too?

    Read the article

  • Just re-installed Ubuntu 14.04, unstable wireless connection, Lenovo ThinkPad X200

    - by Mark Lawtie
    I re-installed Ubuntu 14.04 as I was having problems with unstable wireless connection... Following re-installation I am having the same problem: connection randomly dropping out, then reconnecting... all my other devices are running well when connected I am a bit of a computer novice so any help would be greatly appreciated... I am running Lenovo ThinkPad X200 laptop... Thanks! mark@mark-ThinkPad-X200:~$ lspci 00:00.0 Host bridge: Intel Corporation Mobile 4 Series Chipset Memory Controller Hub (rev 07) 00:02.0 VGA compatible controller: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller (rev 07) 00:02.1 Display controller: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller (rev 07) 00:03.0 Communication controller: Intel Corporation Mobile 4 Series Chipset MEI Controller (rev 07) 00:19.0 Ethernet controller: Intel Corporation 82567LM Gigabit Network Connection (rev 03) 00:1a.0 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #4 (rev 03) 00:1a.1 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #5 (rev 03) 00:1a.2 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #6 (rev 03) 00:1a.7 USB controller: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #2 (rev 03) 00:1b.0 Audio device: Intel Corporation 82801I (ICH9 Family) HD Audio Controller (rev 03) 00:1c.0 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 1 (rev 03) 00:1c.1 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 2 (rev 03) 00:1c.3 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 4 (rev 03) 00:1d.0 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #1 (rev 03) 00:1d.1 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #2 (rev 03) 00:1d.2 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #3 (rev 03) 00:1d.7 USB controller: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #1 (rev 03) 00:1e.0 PCI bridge: Intel Corporation 82801 Mobile PCI Bridge (rev 93) 00:1f.0 ISA bridge: Intel Corporation ICH9M-E LPC Interface Controller (rev 03) 00:1f.2 SATA controller: Intel Corporation 82801IBM/IEM (ICH9M/ICH9M-E) 4 port SATA Controller [AHCI mode] (rev 03) 00:1f.3 SMBus: Intel Corporation 82801I (ICH9 Family) SMBus Controller (rev 03) 03:00.0 Network controller: Intel Corporation PRO/Wireless 5100 AGN [Shiloh] Network Connection mark@mark-ThinkPad-X200:~$ mark@mark-ThinkPad-X200:~$ lsusb Bus 002 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 008 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 006 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 026: ID 0a5c:2145 Broadcom Corp. BCM2045B (BDC-2.1) [Bluetooth Controller] Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub mark@mark-ThinkPad-X200:~$

    Read the article

  • How long for data highlighter mark up to appear in structured data tool?

    - by Max
    I used the data highlighter in webmaster tools over 3 weeks ago to mark up some local business data, but there is still no structured data being detected in webmaster tools. Does any body have any experience on approx how long it takes for Google Webmaster Tools to start reporting Structured Data that has been marked up with their data highlighter? I'm asking specifically about reporting on it in Web Master Tools Structured Data section, as opposed to actually appearing in the SERPs.

    Read the article

  • Mark your calendar: Get ready for the next generation of the Oracle Database!

    - by Javier Puerta
    Mark your calendar for the following upcoming webcasts for partners on the new version of the Oracle Database: Oracle Database Technical Training Webcast for Partners: July 2nd, at 17:00 CET, 4:00 pm UK - Duration: 1 hour (Access details here) Oracle Database Sales Training Webcast for EMEA Partners: July 8th, at 10:00 am CET, 9am UK - Duration: 1 hour (Details will be communicated very soon)

    Read the article

  • Mark your calendar: Get ready for the next generation of the Oracle Database!

    - by Javier Puerta
    Mark your calendar for the following upcoming webcasts for partners on the new version of the Oracle Database: Oracle Database Technical Training Webcast for Partners: July 2nd, at 17:00 CET, 4:00 pm UK - Duration: 1 hour (Access details here) Oracle Database Sales Training Webcast for EMEA Partners: July 8th, at 10:00 am CET, 9am UK - Duration: 1 hour (Details will be communicated very soon)

    Read the article

  • iPhone development: pointer being freed was not allocated

    - by w4nderlust
    Hello, i got this message from the debugger: Pixture(1257,0xa0610500) malloc: *** error for object 0x21a8000: pointer being freed was not allocated *** set a breakpoint in malloc_error_break to debug so i did a bit of tracing and got: (gdb) shell malloc_history 1257 0x21a8000 ALLOC 0x2196a00-0x21a89ff [size=73728]: thread_a0610500 |start | main | UIApplicationMain | GSEventRun | GSEventRunModal | CFRunLoopRunInMode | CFRunLoopRunSpecific | __CFRunLoopDoObservers | CA::Transaction::observer_callback(__CFRunLoopObserver*, unsigned long, void*) | CA::Transaction::commit() | CA::Context::commit_transaction(CA::Transaction*) | CALayerDisplayIfNeeded | -[CALayer _display] | CABackingStoreUpdate | backing_callback(CGContext*, void*) | -[CALayer drawInContext:] | -[UIView(CALayerDelegate) drawLayer:inContext:] | -[AvatarView drawRect:] | -[AvatarView overlayPNG:] | +[UIImageUtility createMaskOf:] | UIGraphicsGetImageFromCurrentImageContext | CGBitmapContextCreateImage | create_bitmap_data_provider | malloc | malloc_zone_malloc and i really can't understand what i am doing wrong. here's the code of the [UIImageUtility createMaskOf:] function: + (UIImage *)createMaskOf:(UIImage *)source { CGRect rect = CGRectMake(0, 0, source.size.width, source.size.height); UIGraphicsBeginImageContext(CGSizeMake(source.size.width, source.size.height)); CGContextRef context = UIGraphicsGetCurrentContext(); CGContextTranslateCTM(context, 0, source.size.height); CGContextScaleCTM(context, 1.0, -1.0); UIImage *original = [self createGrayCopy:source]; CGContextRef context2 = CGBitmapContextCreate(NULL, source.size.width, source.size.height, 8, 4 * source.size.width, CGColorSpaceCreateDeviceRGB(), kCGImageAlphaNoneSkipLast); CGContextDrawImage(context2, CGRectMake(0, 0, source.size.width, source.size.height), original.CGImage); CGImageRef unmasked = CGBitmapContextCreateImage(context2); const float myMaskingColorsFrameColor[6] = { 1,256,1,256,1,256 }; CGImageRef mask = CGImageCreateWithMaskingColors(unmasked, myMaskingColorsFrameColor); CGContextSetRGBFillColor (context, 256,256,256, 1); CGContextFillRect(context, rect); CGContextDrawImage(context, rect, mask); UIImage *whiteMasked = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); return whiteMasked; } the other custom function called before that is the following: - (UIImage *)overlayPNG:(SinglePart *)sp { NSLog([sp description]); // Rect and context setup CGRect rect = CGRectMake(0, 0, sp.image.size.width, sp.image.size.height); NSLog(@"%f x %f", sp.image.size.width, sp.image.size.height); // Create an image of a color filled rectangle UIImage *baseColor = nil; if (sp.hasOwnColor) { baseColor = [UIImageUtility imageWithRect:rect ofColor:sp.color]; } else { SinglePart *facePart = [editingAvatar.face.partList objectAtIndex:0]; baseColor = [UIImageUtility imageWithRect:rect ofColor:facePart.color]; } // Crete the mask of the layer UIImage *mask = [UIImageUtility createMaskOf:sp.image]; mask = [UIImageUtility createGrayCopy:mask]; // Create a new context for merging the overlay and a mask of the layer UIGraphicsBeginImageContext(CGSizeMake(sp.image.size.width, sp.image.size.height)); CGContextRef context2 = UIGraphicsGetCurrentContext(); // Adjust the coordinate system so that the origin // is in the lower left corner of the view and the // y axis points up CGContextTranslateCTM(context2, 0, sp.image.size.height); CGContextScaleCTM(context2, 1.0, -1.0); // Create masked overlay color layer CGImageRef MaskedImage = CGImageCreateWithMask (baseColor.CGImage, mask.CGImage); // Draw the base color layer CGContextDrawImage(context2, rect, MaskedImage); // Get the result of the masking UIImage* overlayMasked = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); UIGraphicsBeginImageContext(CGSizeMake(sp.image.size.width, sp.image.size.height)); CGContextRef context = UIGraphicsGetCurrentContext(); // Adjust the coordinate system so that the origin // is in the lower left corner of the view and the // y axis points up CGContextTranslateCTM(context, 0, sp.image.size.height); CGContextScaleCTM(context, 1.0, -1.0); // Get the result of the blending of the masked overlay and the base image CGContextDrawImage(context, rect, overlayMasked.CGImage); // Set the blend mode for the next drawn image CGContextSetBlendMode(context, kCGBlendModeOverlay); // Component image drawn CGContextDrawImage(context, rect, sp.image.CGImage); UIImage* blendedImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); CGImageRelease(MaskedImage); return blendedImage; }

    Read the article

  • Oracle OpenWorld 2012. Rueda de prensa de Mark Hurd: pilares de la estrategia de Oracle

    - by Fabian Gradolph
    Estamos en la segunda jornada de OpenWorld 2012. La sesión ha comenzado con la presentación de Mark Hurd, quien después de su intervención, ha ofrecido una rueda de prensa multitudinaria. Es probable que más de 80 o 90 periodistas estuviesen presentes en la sala. El presidente de Oracle nos ha presentado una muy buena síntesis sobre la estrategia de la compañía, que básicamente está basada en cuatro pilares. He aquí un breve resumen: 1. Ofrecer los mejores productos y soluciones en cada una de las capas tecnológicas. Es decir, los mejores productos de almacenamiento de información, los mejores servidores, la mejor base de datos… todos ellos basados en estándares de la industria, lo que favorece la interoperabilidad con los productos de otros fabricantes, si esa es la elección del cliente. 2. Integrar los productos desde la fase de diseño y desarrollo para ofrecer a los clientes soluciones que proporcionen un rendimiento extremo. Los mayores exponentes de esta estrategia son los Engineered Systems (sistemas de ingeniería conjunta), que incluyen productos estrella como Exadata, Exalogic, o Exalitycs. Al combinar las mejores capacidades de los productos Oracle e integrarlos verticalmente, se consiguen los siguientes beneficios. Rendimiento extremo de las soluciones tecnológicas. Por ejemplo, la última versión de Exadata, presentada ahora, ofrece una velocidad hasta 100 veces mayor que la anterior. Reducción de costes. Los sistemas integrados permiten reducir la necesidad de espacio, el tiempo de instalación e integración y los costes de mantenimiento. Su mayor rendimiento también se traduce en una menor necesidad de inversión en infraestructura. Simplificación de la gestión y el mantenimiento. Al integrar diferentes tipos de soluciones en una sola, también se simplifica la contratación de sistemas de soporte, centralizándolos en un único proveedor. 3. 3. Una propuesta completa para entornos cloud. La propuesta de Oracle incluye una cloud pública (Oracle Public Cloud), infraestructura para clouds privadas e infraestructura para sistemas híbridos. Así, la compañía ofrece Aplicaciones como Servicio (AaaS), Plataforma como servicio (PaaS) e infraestructura como servicio (IaaS). Al mismo tiempo, facilita soluciones para que las empresas construyan sus propias infraestructuras cloud. La ventaja de la propuesta de Oracle es que se utiliza la misma tecnología para la cloud pública o la privada, de forma que los clientes tengan facilidad para escoger qué aplicaciones mantendrán en un sistema público, cuáles en un sistema privado, etc. La máxima interoperabilidad permite, además, trasnferir aplicaciones de unas modalidades a otras sin problemas. 4. Aplicaciones sectoriales. Oracle está apostando fuertemente por el desarrollo de aplicaciones específicas para los diferentes sectores de actividad. Así, Oracle proporciona soluciones concretas para Banca y Finanzas, Distribución, Logística, Sector Público, Telecomunicaciones y un largo etcétera. Tras sus palabras preliminares hubo una interesante ronda de preguntas. No es posible hacer un resumen de todas ellas, pero me quedo con un mensaje que Mark ha repetido en un par de ocasiones: Oracle quiere seguir creciendo en todos los mercados en los que opera y se trata de una estrategia para crecer. Así lo esperamos todos.

    Read the article

  • Sound vs. Valid Argument

    - by MarkPearl
    Today I spent some time reviewing my Formal Logic course for my up coming exam. I came across a section that I have never really explored in any proper depth… the difference between a valid argument and a sound argument. Here go some notes I made… What is an argument? In this case we are not referring to a verbal fight, but more what we call a set of premise followed by a conclusion. Before we go further we need to understand what a premise is… a premise is a statement that an argument claims will induce or justify a conclusion. Think of a premise as an assumption that something is true. So, an argument can consist of one or more premises and a conclusion… When is an argument valid? An argument can be either valid or invalid. An argument is valid if, and only if, it is impossible for there to be a situation in which all it's premises are TRUE and it's conclusion is FALSE. It is generally easier to determine if an argument is invalid. Do this by applying the following… Assume that all the premises are true, then ask yourself if it is now possible for the conclusion to be false. If the answer is "yes," the argument is invalid. If it's "no," the argument is valid. Example 1… P1 – Mark is Tall P2 – Mark is a boy C –  Mark is a tall boy Walkthrough 1… Assume Mark is Tall is true and also assume that Mark is a boy. Based on these two premises, the conclusion is also true – Mark is a tall boy, thus the it is a valid argument. Let’s make this an invalid argument…   Example 2… P1 – Mark is Tall P2 – Mark is a boy C – Mark is a short boy Walkthrough 2… This would be an invalid argument, since from the premises we assume that Mark is tall and he is a boy, and then the conclusion goes against this by saying that Mark is short. Thus an invalid argument.   When is an argument sound? An argument is said to be sound when it is valid and all the premises are indeed true (not just assumed to be true). Rephrased, an argument is said to be sound when the conclusion will follow from the premises and the premises are indeed true in real life. In example 1 we were referring to a specific person, if we generalized it a bit we could come up with the following example.   Example 3 P1 – All people called Mark are tall P2 – I know a specific person called Mark C – He is a tall person   In this instance, it is a valid argument (we assume the premises are true, which leads to the conclusion being true), but the argument is NOT sound. In the real world there must be at least one person called Mark who is not tall. Something also to note, all invalid arguments are also unsound – this makes sense, if an argument is not valid, how on earth can it be true in the real world.   What happens when the premises contradict themselves? This is an interesting one… An argument is valid if, and only if, it is impossible for there to be a situation in which all it's premises are TRUE and it's conclusion is FALSE. When premises are contradictory, the argument is always valid because it is impossible for all the premises to be true at one time. Lets look at an example.. P1 - Elvis is dead P2 – Elvis is alive C – Laura is a woolly mammoth This is a valid argument, but not a sound one. Think about it. Is it possible to have a situation in which the premises are true and the conclusion is false? Sure, it's possible to have a situation in which the conclusion is false, but for the argument to be invalid, it has to be possible for the premises to all be true at the same time the conclusion is false. So if the premises can't all be true, the argument is valid. (If you still think the argument is invalid, draw a picture in which the premises are all true and the conclusion is false. Remember, there's only one Elvis, and you can't be both dead and alive.) For more info on this I suggest reading the following blog post.

    Read the article

  • In bash, how do I escape an exclamation mark?

    - by Matthew
    I want to do something like bzr commit -m "It works!". I can sort of escape the exclamation mark by doing bzr commit -m "It works\!". However, then my commit message includes the backslash. How do I escape the exclamation mark, while still ignoring the backslash?

    Read the article

  • dd-wrt router firmware QoS troubleshooting

    - by Jeff Atwood
    I've been using the dd-wrt firmware on my router and I like it a lot! But -- I'm not sure the quality of service (QoS) is working on it. I have it set up as follows: http, port 80 -- Premium bittorrent, port 6969 -- Bulk https, port 443 -- Premium dns, port 53 -- Premium Per the QoS documentation, these levels are: bandwidth is allocated based on the following percentages of uplink and downlink values for each class: Exempt: 100mbps - ignores global limits. Premium: 75% - 100% Express: 15% - 100% Standard: 10% - 100% Bulk: 1.5% - 100% This doesn't entirely seem to work, though -- with busy torrents going I get major pauses in my web browsing which sucks! The QoS documentation gives some steps to check the QoS ... What you'll be interested to look at will be the first set of source and destination IP, including the port numbers. Next the presence of l7proto and the "mark" field. The entries indicate the current live connection QoS priority applied on them based on the "mark" field. The "mark" values correspond to the following Exempt: 100 Premium: 10 Express: 20 Standard: 30 Bulk: 40 (no QoS matched): 0 You may see "mark=0" for some l7proto service even though they are in configured in the list of QoS rules. This may mean that the layer 7 pattern matching system didn't match a new or changed header for that protocol. Custom service on port matches will usually take care of these. On port 6969 (bittorrent) I see a weird mixture of stuff with mark=0 and mark=40 like so cat /proc/net/ip_conntrack udp 17 105 src=98.162.182.42 dst=1.2.3.4 sport=64512 dport=6969 packets=3 bytes=290 src=10.0.0.2 dst=98.162.182.42 sport=6969 dport=64512 packets=4 bytes=202 [ASSURED] mark=0 secmark=0 use=1 tcp 6 117 TIME_WAIT src=98.248.173.174 dst=1.2.3.4 sport=51114 dport=6969 packets=12 bytes=704 src=10.0.0.2 dst=98.248.173.174 sport=6969 dport=51114 packets=10 bytes=440 [ASSURED] mark=40 secmark=0 use=1 tcp 6 598 ESTABLISHED src=165.132.128.201 dst=1.2.3.4 sport=57218 dport=6969 packets=8024 bytes=9919881 src=10.0.0.2 dst=165.132.128.201 sport=6969 dport=57218 packets=4211 bytes=239607 [ASSURED] mark=0 secmark=0 use=1 tcp 6 586 ESTABLISHED src=68.46.9.24 dst=1.2.3.4 sport=64688 dport=6969 packets=6 bytes=490 src=10.0.0.2 dst=68.46.9.24 sport=6969 dport=64688 packets=8 bytes=944 [ASSURED] mark=40 secmark=0 use=1 udp 17 45 src=222.254.228.38 dst=1.2.3.4 sport=25438 dport=6969 packets=5 bytes=454 src=10.0.0.2 dst=222.254.228.38 sport=6969 dport=25438 packets=3 bytes=154 [ASSURED] mark=0 secmark=0 use=1 ( full file visible at http://pastebin.com/AZE6EtWm ) I've been playing around with this log for a little while and I can't see any patterns! Why is some port 6969 bittorrent traffic tagged mark=0 (not matched) by dd-wrt's QoS while others are tagged mark=40 (Bulk) .. any ideas?

    Read the article

  • How to get dynamic SQL result from SP in entity framework?

    - by KentZhou
    Suppose I have following SP to run a dynamic sql ALTER PROCEDURE [dbo].[MySP] AS BEGIN declare @sql varchar(4000) select @sql = 'select cnt = count(*) from Mytable ..... '; exec (@sql) END then in edmx, I add the sp and import function for this sp. the return type is scalars int32. then I want to use this function in code like: int? result = context.MySP(); I got error said "cannot implicitly convert type System.Data.Objects.ObjectResults to int?" If use var result = context.MySP(); then Single() cann't be applied to context.MySP(). How to get the result for this case?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >