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  • How to Use Calculated Color Values with ColorMatrix?

    - by Otaku
    I am changing color values of each pixel in an image based on a calculation. The problem is that this takes over 5 seconds on my machine with a 1000x1333 image and I'm looking for a way to optimize it to be much faster. I think ColorMatrix may be an option, but I'm having a difficult time figure out how I would get a set of pixel RGB values, use that to calculate and then set the new pixel value. I can see how this can be done if I was just modifying (multiplying, subtracting, etc.) the original value with ColorMatrix, but now how I can use the pixels returned value to use it to calculate and new value. For example: Sub DarkenPicture() Dim clrTestFolderPath = "C:\Users\Me\Desktop\ColorTest\" Dim originalPicture = "original.jpg" Dim Luminance As Single Dim bitmapOriginal As Bitmap = Image.FromFile(clrTestFolderPath + originalPicture) Dim Clr As Color Dim newR As Byte Dim newG As Byte Dim newB As Byte For x = 0 To bitmapOriginal.Width - 1 For y = 0 To bitmapOriginal.Height - 1 Clr = bitmapOriginal.GetPixel(x, y) Luminance = ((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B))/ 255 newR = Clr.R * Luminance newG = Clr.G * Luminance newB = Clr.B * Luminance bitmapOriginal.SetPixel(x, y, Color.FromArgb(newR, newG, newB)) Next Next bitmapOriginal.Save(clrTestFolderPath + "colorized.jpg", ImageFormat.Jpeg) End Sub The Luminance value is the calculated one. I know I can set ColorMatrix's M00, M11, M22 to 0, 0, 0 respectively and then put a new value in M40, M41, M42, but that new value is calculated based of a value multiplication and addition of that pixel's components (((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B)) and the result of that - Luminance - is multiplied by the color component). Is this even possible with ColorMatrix?

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  • How to delete characters and append strings?

    - by devin250
    i am adding a new record to xml file im first quering all existing items and storing the count in an int int number = query.count() and then incrementing number by 1; number = number +1; now i want to format this value in a string having "N00000000" format and the number will ocuppy the last positions Pseudo code: //declare the format string sting format = "N00000000" //calculate the length of number string int length =number.ToString().Length(); // delete as many characters from right to left as the length of number string ??? // finally concatenate both strings with + operator ??? help please

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  • strcasecmp in C returns 156 instead of 0, any ideas why?

    - by hora
    I have the following code: printf("num: %d\n", strcasecmp(buf, "h\n")); And I get the following results when I try plugging in different letters: a: -7 g: -1 i: 1 j: 2 h: 156 H: 156 Should strcasecmp not return 0 when buf is equal to H or h? Any ideas why it's returning 156? I need to figure out how to check whether the user types H or h. Thanks!

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  • How can I remove certain characters from inside angle-brackets, leaving the characters outside alone

    - by Iain Fraser
    Edit: To be clear, please understand that I am not using Regex to parse the html, that's crazy talk! I'm simply wanting to clean up a messy string of html so it will parse Edit #2: I should also point out that the control character I'm using is a special unicode character - it's not something that would ever be used in a proper tag under any normal circumstances Suppose I have a string of html that contains a bunch of control characters and I want to remove the control characters from inside tags only, leaving the characters outside the tags alone. For example Here the control character is the numeral "1". Input The quick 1<strong>orange</strong> lemming <sp11a1n 1class1='jumpe111r'11>jumps over</span> 1the idle 1frog Desired Output The quick 1<strong>orange</strong> lemming <span class='jumper'>jumps over</span> 1the idle 1frog So far I can match tags which contain the control character but I can't remove them in one regex. I guess I could perform another regex on my matches, but I'd really like to know if there's a better way. My regex Bear in mind this one only matches tags which contain the control character. <(([^>])*?`([^>])*?)*?> Thanks very much for your time and consideration. Iain Fraser

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  • Remove All After Delimiter PHP

    - by Belgin Fish
    Hi, I'm just wondering how I could remove everything after a certain substring in PHP ex: Posted On April 6th By Some Dude I'd like to have it so that it removes all the text including, and after, the sub string "By" Thanks

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  • How can I append text to a start and end of a file as header and footer ?

    - by Morano88
    I'm filling an XML document manually using C# and I need to have <data> as header and </data> as footer for the whole XML file. Is there an easy way to do that ? I know It can be done but I couldn't find a way to do it. Keep in mind that I'm updating the entries so I need to make sure that they always come between the header and the footer. Thanks Example <data> Entry New Entry 1 New Entry 2 </data>

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  • ImageMagick Reflection

    - by dbruns
    Brief: convert ( -size 585x128 gradient: ) NewImage.png How do I change the above ImageMagick command so it takes the width and height from an existing image? I need it to remain a one line command. Details: I'm trying to programatically create an image reflection using ImageMagick. The effect I am looking for is similar to what you would see when looking at an object on the edge of a pool of water. There is a pretty good thread on what I am trying to do here but the solution isn't exactly what I am looking for. Since I will be calling ImageMagick from a C#.Net application I want to use one call without any temp files and return the image through stdout. So far I have this... convert OriginalImage.png ( OriginalImage.png -flip -blur 3x5 \ -crop 100%%x30%%+0+0 -negate -evaluate multiply 0.3 \ -negate ( -size 585x128 gradient: ) +matte -compose copy_opacity -composite ) -append NewImage.png This works ok but doesn't give me the exact fade I am looking for. Instead of a nice solid fade from top to bottom it is giving me a fade from top left to bottom right. I added the (-negate -evaluate multiply 0.3 -negate) section in to lighten it up a bit more since I wasn't getting the fade I wanted. I also don't want to have to hard code in the size of the image when creating the gradient ( -size 585x128 gradient: ) I'm also going to want to keep the original image's transparency if possible. To go to stdout I plan on replacing "NewImage.png" with "-"

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  • Is their an optimal config/format for a TIFF when using Tesseract or other OCR?

    - by Zando
    I'm having a bizarre problem with Tesseract. I have a name, "Janice" that is in a 200x40 pixel tiff, that Tesseract interprets as a blank. I'm running hundreds of names through Tesseract and they are processed fine. What I'm actually doing, though, is breaking up a larger TIFF into smaller tiffs of one word each. In the larger TIFF, tesseract recognizes "Janice". What could cause it to hiccup in a TIFF that solely contains that word (and there's enough space around the word to not truncate any of the pixels)? I'm using ImageMagick to split the big TIFF, are there options I should set when reconstituting the new TIFF files?

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  • Copying part of a string in C

    - by wolfPack88
    This seems like it should be really simple, but for some reason, I'm not getting it to work. I have a string called seq, which looks like this: ala ile val I want to take the first 3 characters and copy them into a different string. I use the command: memcpy(fileName, seq, 3 * sizeof(char)); That should make fileName = "ala", right? But for some reason, I get fileName = "ala9". I'm currently working around it by just saying fileName[4] = '\0', but was wondering why I'm getting that 9. Note: After changing seq to ala ile val ser and rerunning the same code, fileName becomes "alaK". Not 9 anymore, but still an erroneous character.

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  • How to map EnumSet (or List of Enums) in an entity using JPA2

    - by arteq007
    I have entity Person: @Entity @Table(schema="", name="PERSON") public class Person { List<PaymentType> paymentTypesList; //some other fields //getters and setters and other logic } and I have enum PaymentType: public enum PaymentType { FIXED, CO_FINANCED, DETERMINED; } how to persist Person and its list of enums (in this list i have to place variable amount of enums, there may be one of them, or two or all of them) I'm using Spring with Postgres, Entity are created using JPA annotation, and managed using Hibernate

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  • Changing href atributes with nokogiri and ruby on rails

    - by fool
    Hi, I Have a HTML document with links links, for exemple: <html> <body> <ul> <li><a href="http://someurl.com/etc/etc">teste1</a></li> <li><a href="http://someurl.com/etc/etc">teste2</a></li> <li><a href="http://someurl.com/etc/etc">teste3</a></li> <ul> </body> </html> I want with Ruby on Rails, with nokogiri or some other method, to have a final doc like this: <html> <body> <ul> <li><a href="http://myproxy.com/?url=http://someurl.com/etc/etc">teste1</a></li> <li><a href="http://myproxy.com/?url=http://someurl.com/etc/etc">teste2</a></li> <li><a href="http://myproxy.com/?url=http://someurl.com/etc/etc">teste3</a></li> <ul> </body> </html> What's the best strategy to achieve this?

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  • Easiest way to find the correct kademlia bucket

    - by Martin
    In the Kademlia protocol node IDs are 160 bit numbers. Nodes are stored in buckets, bucket 0 stores all the nodes which have the same ID as this node except for the very last bit, bucket 1 stores all the nodes which have the same ID as this node except for the last 2 bits, and so on for all 160 buckets. What's the fastest way to find which bucket I should put a new node into? I have my buckets simply stored in an array, and need a method like so: Bucket[] buckets; //array with 160 items public Bucket GetBucket(Int160 myId, Int160 otherId) { //some stuff goes here } The obvious approach is to work down from the most significant bit, comparing bit by bit until I find a difference, I'm hoping there is a better approach based around clever bit twiddling. Practical note: My Int160 is stored in a byte array with 20 items, solutions which work well with that kind of structure will be preferred.

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  • GD! Converting a png image to jpeg and making the alpha by default white and not black.

    - by Shawn
    I tried something like this but it just makes the background of the image white, not necessarily the alpha of the image. I wanted to just upload everything as jpg's so if i could somehow "flatten" a png image with some transparently to default it to just be white so i can use it as a jpg instead. Appreciate any help. Thanks. $old = imagecreatefrompng($upload); $background = imagecolorallocate($old,255,255,255); imagefill($old, 0, 0, $background); imagealphablending($old, false); imagesavealpha($old, true);

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  • Removing the transparency from image while keeping the actual image

    - by KPL
    Hello people, I have three images,and , they are not square or rectangular in shape. They are just like face of anyone. So, basically, my images are in the size 196x196 or anything like that, but complete square or rectangle with the face in the middle and transperant background in the rest of the portion. Now, I want to remove the transperant background too and just keep the faces. Don't know if this is possible and mind you, this isn't a programming question.

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  • Get a list of mutex?

    - by Patrick
    A program creates a mutex as part of its start-up. I don't know the format of this mutex so I wondered if there is a way to get a list of all non-abandoned mutex, open the program, get a new list and see if I can find the mutex by removing all duplicate entries. Is there a way to get this list?

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  • Set postion in customized list field in blackberry

    - by arunabha
    I want three list field items to be displayed, from bottom to top. I am able to display three list field items, but they display from top to bottom. I have tried setting the position, but it isn't working. import java.util.Vector; import net.rim.device.api.system.Bitmap; import net.rim.device.api.system.Display; import net.rim.device.api.ui.ContextMenu; import net.rim.device.api.ui.DrawStyle; import net.rim.device.api.ui.Field; import net.rim.device.api.ui.Font; import net.rim.device.api.ui.Graphics; import net.rim.device.api.ui.Manager; import net.rim.device.api.ui.MenuItem; import net.rim.device.api.ui.UiApplication; import net.rim.device.api.ui.component.BitmapField; import net.rim.device.api.ui.component.Dialog; import net.rim.device.api.ui.component.LabelField; import net.rim.device.api.ui.component.ListField; import net.rim.device.api.ui.component.ListFieldCallback; import net.rim.device.api.ui.component.NullField; import net.rim.device.api.ui.container.FullScreen; import net.rim.device.api.ui.container.MainScreen; import net.rim.device.api.util.Arrays; import net.rim.device.api.ui.component.ListField; /** * @author Jason Emerick */ public class TaskListField extends UiApplication { //statics ------------------------------------------------------------------ public static void main(String[] args) { TaskListField theApp = new TaskListField(); theApp.enterEventDispatcher(); } public TaskListField() { pushScreen(new TaskList()); } } /*class List extends FullScreen { TaskList tl; List(){ super(); TaskList tl=new TaskList(); } }*/ class TaskList extends MainScreen implements ListFieldCallback { private Vector rows; private Bitmap p1; private Bitmap p2; private Bitmap p3; String Task; ListField listnew=new ListField(); public TaskList() { super(); listnew.setRowHeight(50); //setEmptyString("Hooray, no tasks here!", DrawStyle.HCENTER); listnew.setCallback(this); p1 = Bitmap.getBitmapResource("1.png"); p2 = Bitmap.getBitmapResource("2.png"); p3 = Bitmap.getBitmapResource("3.png"); rows = new Vector(); for (int x = 0; x < 3; x++) { TableRowManager row = new TableRowManager(); if (x== 0) { Task="On Air Now"; } if (x== 1) { Task="Music Channel"; } if (x==2) { Task="News Channel"; } // SET THE PRIORITY BITMAP FIELD // if high priority, display p1 bitmap if (x % 2 == 0) { row.add(new BitmapField(p1)); } // if priority is 2, set p2 bitmap else if (x % 3 == 0) { row.add(new BitmapField(p2)); } // if priority is 3, set p3 bitmap else { row.add(new BitmapField(p3)); } // SET THE TASK NAME LABELFIELD // if overdue, bold/underline LabelField task = new LabelField(Task, DrawStyle.ELLIPSIS); // if due today, bold if (x % 2 == 0) { task.setFont(Font.getDefault().derive( Font.BOLD)); } else { task.setFont(Font.getDefault().derive(Font.BOLD)); } row.add(task); LabelField task1 = new LabelField("Now Playing" + String.valueOf(x), DrawStyle.ELLIPSIS); // if due today, bold /* if (x % 2 == 0) { task.setFont(Font.getDefault().derive( Font.BOLD)); } else { task.setFont(Font.getDefault().derive(Font.BOLD)); }*/ Font myFont = Font.getDefault().derive(Font.PLAIN, 12); task1.setFont(myFont); row.add(task1); // SET THE DUE DATE/TIME row.add(new LabelField("", DrawStyle.ELLIPSIS | LabelField.USE_ALL_WIDTH | DrawStyle.RIGHT) { protected void paint(Graphics graphics) { graphics.setColor(0x00878787); super.paint(graphics); } }); rows.addElement(row); } listnew.setSize(rows.size()); this.add(listnew); } // ListFieldCallback Implementation public void drawListRow(ListField listField, Graphics g, int index, int y, int width) { //TaskList list =(TaskListField) listnew; TableRowManager rowManager = (TableRowManager)rows .elementAt(index); rowManager.drawRow(g, 0, y, width, listnew.getRowHeight()); } private class TableRowManager extends Manager { public TableRowManager() { super(0); } // Causes the fields within this row manager to be layed out then // painted. public void drawRow(Graphics g, int x, int y, int width, int height) { // Arrange the cell fields within this row manager. layout(0, 1); // Place this row manager within its enclosing list. setPosition(x,y); // Apply a translating/clipping transformation to the graphics // context so that this row paints in the right area. g.pushRegion(getExtent()); // Paint this manager's controlled fields. subpaint(g); g.setColor(0x00CACACA); g.drawLine(0, 0, getPreferredWidth(), 0); // Restore the graphics context. g.popContext(); } // Arrages this manager's controlled fields from left to right within // the enclosing table's columns. protected void sublayout(int width, int height) { // set the size and position of each field. int fontHeight = Font.getDefault().getHeight(); int preferredWidth = getPreferredWidth(); // start with the Bitmap Field of the priority icon /* Field field = getField(0); layoutChild(field, 0, 0); setPositionChild(field, 150, 300);*/ // set the task name label field /* field = getField(1); layoutChild(field, preferredWidth - 16, fontHeight + 1); setPositionChild(field, 34, 3); // set the list name label field field = getField(2); layoutChild(field, 150, fontHeight + 1); setPositionChild(field, 34, fontHeight + 6);*/ // set the due time name label field /* field = getField(3); layoutChild(field, 150, fontHeight + 1); setPositionChild(field,4,340);*/ /* layoutChild(listnew, preferredWidth, fontHeight); setPositionChild(listnew, 3, 396);*/ setExtent(360, 480); } // The preferred width of a row is defined by the list renderer. public int getPreferredWidth() { return getWidth(); } // The preferred height of a row is the "row height" as defined in the // enclosing list. public int getPreferredHeight() { return listnew.getRowHeight(); } } public Object get(ListField listField, int index) { // TODO Auto-generated method stub return null; } public int getPreferredWidth(ListField listField) { // TODO Auto-generated method stub return 0; } public int indexOfList(ListField listField, String prefix, int start) { // TODO Auto-generated method stub return 0; } }

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  • Need a explanation for the matlab code snippet

    - by Mask
    %# load a grayscale image img = imread('coins.png'); %# display the image figure imshow(img,[]); %# false-color colormap('hot') The above code is from here: http://stackoverflow.com/questions/2592755/infrared-image-processing-in-matlab/2592793#2592793 But I don't understand how figure(What's the difference with/without it?) and colormap(How does it affect the already shown img?) work?

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  • Respecting EXIF orientation when displaying iPhone photos on the web

    - by GingerBreadMane
    I am developing an iPhone camera app that uploads an image to Amazon S3 and that image is displayed on a website. When the iPhone takes a picture, it always saves the photo in an upright orientation, while the orientation used to correctly view the photo is saved in the image's EXIF data. So if I take a photo with the iPhone and open it in FireFox without processing the EXIF data, the image could be sideways or upside down. My problem is that I don't know how to display the photo in it's correct orientation on the website. My current solution is to rotate the photo in the iPhone app, but I'd rather not do that. Is there anyway to respect the EXIF data when displaying on the web without pre-processing the image?

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