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  • Spring Roo and aspect-oriented programming

    - by marcos
    Hello, i've been running some experiments of my own with Spring Roo and it seems to be pretty cool, but i noticed that this tool makes heavy use of AOP on the model layer. I'm thinking about creating a real project using Roo and what i would like to know is: Why AOP is everywhere? Is That ok? What are advantages and disadvantages of this approach? I'm quite new to aspect-oriented programming and some guidance would be greatly appreciated. Thanks in advance!

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  • Error in my web.xml

    - by Mercer
    Why i have an error in my web.xml when i want add servlet..? <servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>org.task.ClientServlet</servlet-class> <servlet-name>FactoryServlet</servlet-name> <servlet-class>org.task.FactoryServlet</servlet-class> <servlet-name>TraderServlet</servlet-name> <servlet-class>org.task.TraderServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> <servlet-name>FactoryServlet</servlet-name> <url-pattern>/FactoryServlet</url-pattern> <servlet-name>TraderServlet</servlet-name> <url-pattern>/TraderServlet</url-pattern> </servlet-mapping>

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  • send email to list of users with different timezones?

    - by ylazez
    i use the following method to send email to list of users i want the (To) in each email to be for just the user only not all users i.e appears to the users that the email is sent to only him my guess is to loop on: message.addRecipients(Message.RecipientType.TO, address); then send the message right? , but this is a heavy process sending an email many times any ideas ? suppose that i have the timezone for each user and i want to send each user the message in his timzone, the same issue i guess setting sent date for each user in his timezone then sending the message, right ? the method is: try { Properties props = System.getProperties(); props.put("mail.smtp.host", "localhost"); // Get a mail session Session session = Session.getDefaultInstance(props, null); // Define a new mail message Message message = new MimeMessage(session); InternetAddress ia = new InternetAddress(); ia.setPersonal("MySite"); ia.setAddress(from); message.setFrom(ia); Address[] address = new Address[recievers.size()]; for (int i = 0; i < recievers.size(); i++) { address[i] = new InternetAddress(recievers.get(i)); } message.addRecipients(Message.RecipientType.TO, address); message.setSubject(subject); // Create a message part to represent the body text BodyPart messageBodyPart = new MimeBodyPart(); messageBodyPart.setContent(body, "text/html"); // use a MimeMultipart as we need to handle the file attachments Multipart multipart = new MimeMultipart(); // add the message body to the mime message multipart.addBodyPart(messageBodyPart); // Put all message parts in the message message.setContent(multipart); message.setSentDate(getCurrentDate()); // Send the message Transport.send(message); } catch (Exception ex) {}

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  • Overriding a method in statically created objects

    - by I82Much
    All, Due to a bug in a library I'm using, I need to override the dispose() method on all objects extending a certain class and make it a NO-OP. I know that if I'm making new instances of the classes directly, this is easy to do: layerManager = new LayerManagerLayer(wwd) { @Override public void dispose() {} }; The problem is that a lot of the object instances I get are not directly constructed by my client code, but instead are created via static library method calls. // Here I want to override the dispose method, but I cannot. Layer l = ShapefileLoader.makeShapefileLayer(this.getClass().getResource("polylines10.shp")); Is there a way I can inject my dispose method into that statically created object without modifying the original sourcecode?

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  • How to lowercase every element of a collection efficiently?

    - by Chris
    Whats the most efficient way to lower case every element of a list or set? My idea for a List: final List<String> strings = new ArrayList<String>(); strings.add("HELLO"); strings.add("WORLD"); for(int i=0,l=strings.size();i<l;++i) { strings.add(strings.remove(0).toLowerCase()); } is there a better, faster way? How would this exmaple look like for a set? As there is currently no method for applying an operation to each element of a set (or list) can it be done without creating an additional temporary set? Something like this would be nice: Set<String> strings = new HashSet<String>(); strings.apply( function (element) { this.replace(element, element.toLowerCase();) } ); Thanks,

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Strange IP addresses in tomcat

    - by mdev
    Some where I have this in some generic class. public static String getRequestIp (HttpServletRequest request){ String ipaddr = request.getHeader("X-FORWARDED-FOR"); if (ipaddr == null)ipaddr = request.getRemoteAddr(); return ipaddr; } For every request i call that method and in a certain moment i insert a record in a mysql database. In most cases it works normally and i can see a record for every request with a valid ip address in the right field. But sometimes where the IP should be there is something like this. "unknown, 93.186.30.120" or "10.0.1.169, 186.38.84.3" Apache is at the front listening at port 80 and used as proxy to Tomcat that listens at port 8081. My router config would not allow to pass any conection that come by any port other than 80. Any Help? Thanks in advance.

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  • how to share a variable between two threads

    - by prmatta
    I just inherited some code, two threads within this code need to perform a system task. One thread should do the system task before the other thread. They should not be performing the system task together. The two threads do not have references to each other. Now, I know I can use some sort of a semaphore to achieve this. But my question is what is the right way to get both threads to access this semaphore. I could create a static variable/method a new class : public class SharedSemaphore { private static Semaphore s = new Semaphore (1, true); public static void performSystemTask () { s.acquire(); } public static void donePerformingSystemTask() { s.release(); } } This would work (right?) but this doesn't seem like the right thing to do. Because, the threads now have access to a semaphore, without ever having a reference to it. This sort of thing doesn't seem like a good programming practice. Am I wrong?

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  • BFS Shortest Path: Edge weight either 1 or 2

    - by Hackster
    I am trying to implement a shortest path algorithm using BFS. That is I am trying to find the shortest path from a specified vertex to every other vertex. However, its a special case where all edge weights are either 1 or 2. I know it could be done with Dijkstra's algorithm but I must use Breadth First Search. So far I have a working version of BFS that searches first for a vertex connected with an edge of weight 1. If it cannot find it, then returns a vertex connected with an edge of weight 2. After thinking about it, this is not the correct way to find the shortest path. The problem is I cannot think of any reasoning why BFS would work with weights 1 or 2, as opposed to any weight. Here is the code: public void addEdge(int start, int end, int weight) { adjMat[start][end] = 1; adjMat[end][start] = 1; edge_weight[start][end] = weight; edge_weight[end][start] = weight; } // ------------------------------------------------------------- public void bfs() // breadth-first search { // begin at vertex 0 vertexList[0].wasVisited = true; // mark it displayVertex(0); // display it theQueue.insert(0); // insert at tail int v2; while( !theQueue.isEmpty() ) // until queue empty, { int v1 = theQueue.remove(); // remove vertex at head // until it has no unvisited neighbors while( (v2=getAdjUnvisitedVertex(v1)) != -1 ){// get one, vertexList[v2].wasVisited = true; // mark it displayVertex(v2); // display it theQueue.insert(v2); // insert it } } // end while(queue not empty) // queue is empty, so we're done for(int j=0; j<nVerts; j++) // reset flags vertexList[j].wasVisited = false; } // end bfs() // ------------------------------------------------------------- // returns an unvisited vertex adj to v -- ****WITH WEIGHT 1**** public int getAdjUnvisitedVertex(int v) { for (int j = 0; j < nVerts; j++) if (adjMat[v][j] == 1 && vertexList[j].wasVisited == false && edge_weight[v][j] == 1){ //System.out.println("Vertex found with 1:"+ vertexList[j].label); return j; } for (int k = 0; k < nVerts; k++) if (adjMat[v][k] == 1 && vertexList[k].wasVisited == false && edge_weight[v][k] == 2){ //System.out.println("Vertex found with 2:"+vertexList[k].label); return k; } return -1; } // end getAdjUnvisitedVertex() // ------------------------------------------------------------- } //////////////////////////////////////////////////////////////// public class BFS{ public static void main(String[] args) { Graph theGraph = new Graph(); theGraph.addVertex('A'); // 0 (start for bfs) theGraph.addVertex('B'); // 1 theGraph.addVertex('C'); // 2 theGraph.addEdge(0, 1,2); // AB theGraph.addEdge(1, 2,1); // BC theGraph.addEdge(2, 0,1); // AD System.out.print("Visits: "); theGraph.bfs(); // breadth-first search System.out.println(); } // end main() } The problem then is, that I don't know why BFS can work for the shortest path problem with edges of weight 1 or 2 as opposed to any edges of any weight. Any help is appreciated. Thanks!

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  • view is not rendered when returning ModelAndView

    - by adancu
    Hi, I have the following problem. I need to export a PDF in a controller The code below, where I return a View, works as expected. @RequestMapping(method = RequestMethod.GET) public View exportReport( @RequestParam(value = "userName", required = true) String userName, @RequestParam(value = "startDate", required = true) Date startDate, @RequestParam(value = "endDate", required = true) Date endDate) { /////////////////////////////////////////// return new TimeSheetReportPdfView(); } The problem occurs if I change the method to return a ModelAndView: @RequestMapping(method = RequestMethod.GET) public ModelAndView exportReport( @RequestParam(value = "userName", required = true) String userName, @RequestParam(value = "startDate", required = true) Date startDate, @RequestParam(value = "endDate", required = true) Date endDate) { /////////////////////////////////////////// return new ModelAndView(new TimeSheetReportPdfView(), model); } Now, the PDF is not exported, all I get is a blank page and nothing in the logs. Any help appreciated. Thanks.

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  • Servlet Security question about j_security_check, j_username and j_password

    - by Nitesh Panchal
    Hello, I used jdbcRealm in my web application and it's working fine. I defined all constraints also in my web.xml. Like all pages of url pattern /Admin/* should be accessed by only admin. I have a login form with uses standard j_security_check, j_username and j_password. Now, when i type Admin/home.jsf it rightly redirects me login.jsf and there when i type the password i am redirected to home.jsf. This works alright but problem comes i directly go to login.jsf and then type password and username. This time it again redirects me to login.jsf. Is there any way through which i can specify which page to go when successful login is there? I need to specify different different pages for different roles. For Admin, it is /Admin/home.jsf for general users it is /General/home.jsf because login form is shared between different type of users. Where do i specify all these things? Secondly, i want to have a remember me checkbox at the end of login form. How do i do this? By default, it is submitted to j_security_check servlet and i have no control over its execution. Please help. This doesn't seem so hard but looks like i am missing something.

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  • Poor performance / speed of regex with lookahead

    - by Hugo Zaragoza
    I have been observing extremely slow execution times with expressions with several lookaheads. I suppose that this is due to underlying data structures, but it seems pretty extreme and I wonder if I do something wrong or if there are known work-arounds. The problem is determining if a set of words are present in a string, in any order. For example we want to find out if two terms "term1" AND "term2" are somewhere in a string. I do this with the expresion: (?=.*\bterm1\b)(?=.*\bterm2\b) But what I observe is that this is an order of magnitude slower than checking first just \bterm1\b and just then \bterm2\b This seems to indicate that I should use an array of patterns instead of a single pattern with lookaheads... is this right? it seems wrong... Here is an example test code and resulting times: public static void speedLookAhead() { Matcher m, m1, m2; boolean find; int its = 1000000; // create long non-matching string char[] str = new char[2000]; for (int i = 0; i < str.length; i++) { str[i] = 'x'; } String test = str.toString(); // First method: use one expression with lookaheads m = Pattern.compile("(?=.*\\bterm1\\b)(?=.*\\bterm2\\b)").matcher(test); long time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m.reset(test); find = m.find(); } time = System.currentTimeMillis() - time; System.out.println(time); // Second method: use two expressions and AND the results m1 = Pattern.compile("\\bterm1\\b").matcher(test); m2 = Pattern.compile("\\bterm2\\b").matcher(test); time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m1.reset(test); m2.reset(test); find = m1.find() && m2.find(); } time = System.currentTimeMillis() - time; System.out.println(time); } This outputs in my computer: 1754 150

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  • How to add chain of certificate in spring ws client request

    - by hudi
    I have simply spring ws client which sending request to some url: @SuppressWarnings("unchecked") private JAXBElement<O> sendSyncSoapRequest(final JAXBElement<I> req, final String iszrUrl) { if (iszrUrl != null) { return (JAXBElement<O>) this.wsTemplate.marshalSendAndReceive(iszrUrl, req); } else { return (JAXBElement<O>) this.wsTemplate.marshalSendAndReceive(req); } } Now I need attach chain of certificate to the soap request. How should I do this ? Please help

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  • Long running method causing race condition

    - by keeleyt83
    Hi, I'm relatively new with hibernate so please be gentle. I'm having an issue with a long running method (~2 min long) and changing the value of a status field on an object stored in the DB. The pseudo-code below should help explain my issue. public foo(thing) { if (thing.getStatus() == "ready") { thing.setStatus("finished"); doSomethingAndTakeALongTime(); } else { // Thing already has a status of finished. Send the user back a message. } } The pseudo-code shouldn't take much explanation. I want doSomethingAndTakeALongTime() to run, but only if it has a status of "ready". My issue arises whenever it takes 2 minutes for doSomethingAndTakeALongTime() to finish and the change to thing's status field doesn't get persisted to the database until it leaves foo(). So another user can put in a request during those 2 minutes and the if statement will evaluate to true. I've already tried updating the field and flushing the session manually, but it didn't seem to work. I'm not sure what to do from here and would appreciate any help. PS: My hibernate session is managed by spring.

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  • LWJGL Circle program create's an oval-like shape

    - by N1ghtk1n9
    I'm trying to draw a circle in LWJGL, but when I draw I try to draw it, it makes a shape that's more like an oval rather than a circle. Also, when I change my circleVertexCount 350+, the shape like flips out. I'm really not sure how the code works that creates the vertices(I have taken Geometry and I know the basic trig ratios). I haven't really found that good of tutorials on creating circles. Here's my code: public class Circles { // Setup variables private int WIDTH = 800; private int HEIGHT = 600; private String title = "Circle"; private float fXOffset; private int vbo = 0; private int vao = 0; int circleVertexCount = 300; float[] vertexData = new float[(circleVertexCount + 1) * 4]; public Circles() { setupOpenGL(); setupQuad(); while (!Display.isCloseRequested()) { loop(); adjustVertexData(); Display.update(); Display.sync(60); } Display.destroy(); } public void setupOpenGL() { try { Display.setDisplayMode(new DisplayMode(WIDTH, HEIGHT)); Display.setTitle(title); Display.create(); } catch (LWJGLException e) { e.printStackTrace(); System.exit(-1); } glClearColor(0.0f, 0.0f, 0.0f, 0.0f); } public void setupQuad() { float r = 0.1f; float x; float y; float offSetX = 0f; float offSetY = 0f; double theta = 2.0 * Math.PI; vertexData[0] = (float) Math.sin(theta / circleVertexCount) * r + offSetX; vertexData[1] = (float) Math.cos(theta / circleVertexCount) * r + offSetY; for (int i = 2; i < 400; i += 2) { double angle = theta * i / circleVertexCount; x = (float) Math.cos(angle) * r; vertexData[i] = x + offSetX; } for (int i = 3; i < 404; i += 2) { double angle = Math.PI * 2 * i / circleVertexCount; y = (float) Math.sin(angle) * r; vertexData[i] = y + offSetY; } FloatBuffer vertexBuffer = BufferUtils.createFloatBuffer(vertexData.length); vertexBuffer.put(vertexData); vertexBuffer.flip(); vao = glGenVertexArrays(); glBindVertexArray(vao); vbo = glGenBuffers(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferData(GL_ARRAY_BUFFER,vertexBuffer, GL_STATIC_DRAW); glVertexAttribPointer(0, 2, GL_FLOAT, false, 0, 0); glBindBuffer(GL_ARRAY_BUFFER, 0); glBindVertexArray(0); } public void loop() { glClear(GL_COLOR_BUFFER_BIT); glBindVertexArray(vao); glEnableVertexAttribArray(0); glDrawArrays(GL_TRIANGLE_FAN, 0, vertexData.length / 2); glDisableVertexAttribArray(0); glBindVertexArray(0); } public static void main(String[] args) { new Circles(); } private void adjustVertexData() { float newData[] = new float[vertexData.length]; System.arraycopy(vertexData, 0, newData, 0, vertexData.length); if(Keyboard.isKeyDown(Keyboard.KEY_W)) { fXOffset += 0.05f; } else if(Keyboard.isKeyDown(Keyboard.KEY_S)) { fXOffset -= 0.05f; } for(int i = 0; i < vertexData.length; i += 2) { newData[i] += fXOffset; } FloatBuffer newDataBuffer = BufferUtils.createFloatBuffer(newData.length); newDataBuffer.put(newData); newDataBuffer.flip(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferSubData(GL_ARRAY_BUFFER, 0, newDataBuffer); glBindBuffer(GL_ARRAY_BUFFER, 0); } } 300 Vertex Count(This is my main problem) 400 Vertex Count - I removed this image, it's bugged out, should be a tiny sliver cut out from the right, like a secant 500 Vertex Count Each 100, it removes more and more of the circle, and so on.

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  • How to center elements in the BoxLayout using center of the element?

    - by Roman
    I use outputPanel.setLayout(new BoxLayout(outputPanel, BoxLayout.Y_AXIS)); and then I add elements (for example JLabels, JButtons) to the outputPanel. For example: outputPanel.add(submitButton);. I see that all added elements are "centered". It is good, because I do want my elements to be in the center. When I write "center" I mean "equal distance from left and right". But the problem is that the left part of the element is put into the center. And I want to have center of elements to be put into the center. How can I get this behavior?

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  • Beautifying a SWT application on Mac

    - by Mark
    SWT is designed to be cross-platform, so it can run on a Mac. The problem is it commits the cardinal sin of Macland - it's UGLY. Toolbars don't look like Mac toolbars, status bars don't look like Mac status bars, etc. Does anyone have any experience in making an SWT application look more like a Mac application? For example, by making platform-specific JNI calls via the 'OS' class in SWT? If so, how difficult was it? (This question arises because we are looking at porting an existing SWT app designed to run on Windows) Thanks

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  • which toString() method can be used performance wise??

    - by Mrityunjay
    hi, I am working on one project for performance enhancement. I had one doubt, while we are during a process, we tend to trace the current state of the DTO and entity used. So, for this we have included toString() method in all POJOs for the same. I have now implemented toString() in three different ways which are following :- public String toString() { return "POJO :" + this.class.getName() + " RollNo :" + this.rollNo + " Name :" + this.name; } public String toString() { StringBuffer buff = new StringBuffer("POJO :").append(this.class.getName()).append(" RollNo :").append(this.rollNo).append(" Name :").append(this.name); return buff.toString(); } public String toString() { StringBuilder builder = new StringBuilder("POJO :").append(this.class.getName()).append(" RollNo :").append(this.rollNo).append(" Name :").append(this.name); return builder .toString(); } can anyone please help me to find out which one is best and should be used for enhancing performance.

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  • Database connection via Hibernate in servlets

    - by blackliteon
    What is the best place in servlet for Hibernate code that returns HibernateSessionFactory ? I saw many examples: ones put db connection in service methods. Others - use smth like HibernateUtil (Singleton) that returns HibernateSessionFactory. I don't know is it safe to use HibernateUtil in multithreaded Servlets ?

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  • JFrame does not refresh after deleting an image

    - by dajackal
    Hi! I'm working for the first time with images in a JFrame, and I have some problems. I succeeded in putting an image on my JFrame, and now i want after 2 seconds to remove my image from the JFrame. But after 2 seconds, the image does not disappear, unless I resize the frame or i minimize and after that maximize the frame. Help me if you can. Thanks. Here is the code: File f = new File("2.jpg"); System.out.println("Picture " + f.getAbsolutePath()); BufferedImage image = ImageIO.read(f); MyBufferedImage img = new MyBufferedImage(image); img.resize(400, 300); img.setSize(400, 300); img.setLocation(50, 50); getContentPane().add(img); this.setSize(600, 400); this.setLocationRelativeTo(null); this.setVisible(true); Thread.sleep(2000); System.out.println("2 seconds over"); getContentPane().remove(img); Here is the MyBufferedImage class: public class MyBufferedImage extends JComponent{ private BufferedImage image; private int nPaint; private int avgTime; private long previousSecondsTime; public MyBufferedImage(BufferedImage b) { super(); this.image = b; this.nPaint = 0; this.avgTime = 0; this.previousSecondsTime = System.currentTimeMillis(); } @Override public void paintComponent(Graphics g) { Graphics2D g2D = (Graphics2D) g; g2D.setColor(Color.BLACK); g2D.fillRect(0, 0, this.getWidth(), this.getHeight()); long currentTimeA = System.currentTimeMillis(); //g2D.drawImage(this.image, 320, 0, 0, 240, 0, 0, 640, 480, null); g2D.drawImage(image, 0,0, null); long currentTimeB = System.currentTimeMillis(); this.avgTime += currentTimeB - currentTimeA; this.nPaint++; if (currentTimeB - this.previousSecondsTime > 1000) { System.out.format("Drawn FPS: %d\n", nPaint++); System.out.format("Average time of drawings in the last sec.: %.1f ms\n", (double) this.avgTime / this.nPaint++); this.previousSecondsTime = currentTimeB; this.avgTime = 0; this.nPaint = 0; } } }

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  • Compare Long values Struts2

    - by Marquinio
    Hi everyone I'm trying to compare two values using struts2 s:if tag but its not working. If I hardcode the values it works but I want it to be dynamic. The variable stringValue is of type String. The variable currentLongValue is of type Long. <s:set var="stringValue" value="order"/> <s:iterator value="listTest"> <s:set var="currentLongValue" value="value"/> <s:if test="#currentLongValue.toString() == #stringValue" > //Do something </s:if> <s:else> //Do something else </s:else> </s:iterator> For the s:if I have tried toString and also the equals(). It only works if I hardcode the values. Example: <s:if test="#currentLongValue == 1234"> Any clues? Thank you.

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