Doing a roll-in/roll-out slideshow in jQuery
- by erizias
I am trying to create a roll-in / roll-out slideshow in jQuery/JavaScript.
My problem is, that it needs to be repeated. And right now when it's starting over, the pictures doesnt come from the right side anymore :(
The reason for which I have created the slideLeft function, is that afterwards I need to create 2 functions, where the user can interrupt the slideshow manually pressing a left or right button.
This is what I've got:
<script class="jsbin" src="http://code.jquery.com/jquery-1.7.2.min.js"></script>
<div style='background: #c4c4c4; border: 1px solid #7b7b7b; height: 220px; overflow: hidden; padding: 5px; position: absolute; width: 590px;'>
<div id='slider-image-1' style='left: 5px; background: red; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
<div id='slider-image-2' style='left: 600px; background: yellow; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
<div id='slider-image-3' style='left: 600px; background: green; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
<div id='slider-image-4' style='left: 600px; background: blue; height: 216px; padding: 2px; position: absolute; top: 5px; width: 586px;'></div>
</div>
<script type='text/javascript'>
$(document).ready(function() {
var amount = 0;
var nextamount = 1;
setInterval(function() {
amount++;
nextamount++;
if (nextamount === 5) nextamount = 1;
if (amount === 5) amount = 1;
slideLeft(amount, nextamount);
}, 2000);
});
function slideLeft(i, j) {
var $theItem = $('#slider-image-' + i);
$theItem.animate({
left: parseInt($theItem.css('left'), 10) == 5 ? -$theItem.outerWidth() : 5
}, 500);
var $theItem = $('#slider-image-' + j);
$theItem.animate({
left: parseInt($theItem.css('left'), 10) == 5 ? $theItem.outerWidth() + 10 : 5
}, 500);
};
</script>
