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  • Complete list of Fonts which support

    - by Yan Cheng CHEOK
    Currently, if I change the locale setting of my application by Locale.setDefault(Locale.ENGLISH); Locale.setDefault(Locale.SIMPLIFIED_CHINESE); What I understand from this JFreeChart forum is that, I am not using correct font. Once you get the reference of the LegentTitle, you can set it to any font. Apparently, JFreeChart's default is "Tahoma" and it doesn't support Chinese characters. May I know, how I can programmatic determine, as list of available Fonts in my system, which support Chinese? I can hard code it to Serif (It fully support Chinese, doesn't it?), its look n feel doesn't looks good to me. I would like to have more choices.

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  • Why does /**[newline] not always insert the Javadoc template including @param and @return in Eclipse

    - by Bas van den Broek
    I'm documenting code in Eclipse and have been using the /** followed by Enter alot to insert the Javadoc template. However this does not always work for some reason, it will create the template for writing comments but it won't automatically insert the @param and @return text. If I copy the exact same method to another class it will insert the full template. It would be a big help if anyone could tell me why it won't do this in some situations.

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  • FacesMessages and rich:effect?

    - by user331747
    I'd like to be able to make an Ajax call using JSF/Seam/RichFaces and have the page update with the relevant h:messages component. That works with no problem. I'm able to perform the appropriate reRender. However, I'd also like to be able to make use of rich:effect to make it a bit prettier. Ideally, I'd like to be able to have the messages fade in and then disappear when the user clicks on them. However, I've been unable to get this working thus far. Has anyone gotten such a scenario working? Does anyone who knows JSF/Seam a bit better than me have any good advice? Thanks in advance!

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  • Project Euler #119 Make Faster

    - by gangqinlaohu
    Trying to solve Project Euler problem 119: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 8^3 = 512. Another example of a number with this property is 614656 = 28^4. We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum. You are given that a2 = 512 and a10 = 614656. Find a30. Question: Is there a more efficient way to find the answer than just checking every number until a30 is found? My Code int currentNum = 0; long value = 0; for (long a = 11; currentNum != 30; a++){ //maybe a++ is inefficient int test = Util.sumDigits(a); if (isPower(a, test)) { currentNum++; value = a; System.out.println(value + ":" + currentNum); } } System.out.println(value); isPower checks if a is a power of test. Util.sumDigits: public static int sumDigits(long n){ int sum = 0; String s = "" + n; while (!s.equals("")){ sum += Integer.parseInt("" + s.charAt(0)); s = s.substring(1); } return sum; } program has been running for about 30 minutes (might be overflow on the long). Output (so far): 81:1 512:2 2401:3 4913:4 5832:5 17576:6 19683:7 234256:8 390625:9 614656:10 1679616:11 17210368:12 34012224:13 52521875:14 60466176:15 205962976:16 612220032:17

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  • Obtaining memory available to JVM at runtime

    - by Bo Tian
    I'm trying to sort a bunch of data such that that the size of data input to the program can be larger than the memory available to the JVM, and handling that requires external sort which is much slower than Quicksort. Is there any way of obtaining memory available to the JVM at runtime such that I could use in place sorting as much as possible, and only switch to Mergesort when data input is too large?

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  • JTable cells not rendering shapes properly

    - by Andrew
    I'm trying to render my JTable cells with a subclassed JPanel and the cells should appear as coloured rectangles with a circle drawn on them. When the table displays initially everything looks OK but then when a dialog or something is displayed over the cells when it is removed the cells that have been covered do not rendered properly and the circles are broken up etc. I then have to move the scroll bar or extend the window to get them to redraw properly. The paintComponent method of the component I'm using to render the cells is below: protected void paintComponent(Graphics g) { setOpaque(true); super.paintComponent(g); Graphics2D g2d = (Graphics2D) g; GradientPaint gradientPaint = new GradientPaint(new Point2D.Double(0, 0), Color.WHITE, new Point2D.Double(0, getHeight()), paintRatingColour); g2d.setPaint(gradientPaint); g2d.fillRect(0, 0, getWidth(), getHeight()); g2d.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); g2d.setRenderingHint(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); Rectangle clipBounds = g2d.getClipBounds(); int x = new Double(clipBounds.getWidth()).intValue() - 15; int y = (new Double(clipBounds.getHeight()).intValue() / 2) - 6; if (level != null) { g2d.setColor(iconColour); g2d.drawOval(x, y, width, height); g2d.fillOval(x, y, width, height); } }

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  • Hash Table question [closed]

    - by Fatimah
    I need your help to solve this program ... Implement a separate chaining hash table that stores strings. You’ll need a hash function that converts string into an index number. Assume the strings will be lowercase words, so 26 characters will suffice.

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  • Given an array of integers [x0 x1 x2], how do you calculate all possible permutations from [0 0 0] t

    - by user319951
    I am writing a program that takes in an ArrayList and I need to calculate all possible permutations starting with a list of zeroes, up to the value in the corresponding input list. Does anyone know how to iteratively calculate these values? For example, given [ 1 2 ] as input, it should find and store the following lists: [0 0], [1 0], [1 1], [1 2], [0 1], [0 2] Thanks!

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  • What features EJB3 bring and also how does EJB3 stack up with Spring Framework ?

    - by Rachel
    I have never worked on ejb, when I started programming Spring was already arrived and all my projects have been with Spring only, recently I had one interview and they wanted knowledge of EJB3.0 and so I want to know how does EJB3.0 stack up with Spring Framework and why many projects now a day are with Spring Framework and not with EJB3.0, do not quote me here as I can be wrong I would really appreciate if difference and benefits of using one over another could be explained from practical perspective.

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  • making a jar file for console

    - by user472221
    Hi I have a program without a GUI and I use console! So first I read a line from a user from console BufferedReader userReader = new BufferedReader(new InputStreamReader(System.in)); and then I will write an answer for the user in the console! System.out.println("Server:"+output); I want to create a jar file for it ! but how can i show my console in jar file with out using GUI? please help me thanks.

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  • JPA + EJB + JSF: how can design complicated query

    - by Harry Pham
    I am using netbean 6.8 btw. Let say that I have 4 different tables: Company, Facility, Project, and Document. So the relationship is this. A company can have multiple facilities. A facility can have multiple projects, and a project can have multiple documents. Company: +companyNum: PK +facilityNum: FK Facility: +facilityNum: PK +projectNum: FK Project: +projectNum: PK +drawingNum: FK So when I create Entity Class From Database in netbean 6.8, I have 4 entity classes that named after the above 4 tables. So if I want to see all the Document in the database, then it is easy. In my SessionBean, I would do this: @PersistenceContext private EntityManager em; List<Document> documents = em.createNamedQuery("Document.findAll").getResultList(); However, that is not all what I need. Let say that I want to know all the Document from a particular Company, or all the Document from a particular Project from a particular Facility from a particular Company. I am very new to JPA + EJB + JSF as a whole. Please help me out.

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  • Contact picker in a dialog

    - by tiex
    I have a custom dialog in my android application. I want to have in this dialog a field for choosing a phone number from contacts. This example describes such snippet. However for this example contact picker is created inside an activity and I do not know how to do this if I do not have activity (in case of dialog)

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  • Interview question : What is the fastest way to generate prime number recursively ?

    - by hilal
    Generation of prime number is simple but what is the fastest way to find it and generate( prime numbers) it recursively ? Here is my solution. However, it is not the best way. I think it is O(N*sqrt(N)). Please correct me, if I am wrong. public static boolean isPrime(int n) { if (n < 2) { return false; } else if (n % 2 == 0 & n != 2) { return false; } else { return isPrime(n, (int) Math.sqrt(n)); } } private static boolean isPrime(int n, int i) { if (i < 2) { return true; } else if (n % i == 0) { return false; } else { return isPrime(n, --i); } } public static void generatePrimes(int n){ if(n < 2) { return ; } else if(isPrime(n)) { System.out.println(n); } generatePrimes(--n); } public static void main(String[] args) { generatePrimes(200); }

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  • multiple screen support

    - by pedr0
    Hi at all, I have some problem with multiple screen support, I work with dp(dpi) for specify the layout_heigth and layout_width and I hope that is the better way to support multiple screen, but when I tried with two smartphone I meet two different result. I give an example, this is a layout I use: <?xml version="1.0" encoding="UTF-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/cities_main_layout" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <ListView android:id="@+id/citieslist" android:layout_width="wrap_content" android:layout_height="320dip" android:layout_gravity="center_vertical" android:layout_below="@id/cities_main_layout" /> <LinearLayout android:id="@+id/cities_button_layout" android:orientation="horizontal" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@id/citieslist" android:layout_gravity="center_vertical"> <Button android:id="@+id/bycountry" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_bycountry" /> <Button android:id="@+id/top10" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_top10" /> <Button android:id="@+id/recommended" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_recommended" /> </LinearLayout> </RelativeLayout> The button are at the bottom of the layout, and I see two different result: In the last smartphone I can see the buttons, instead in the first I cannot...what's wrong? I have to write a layout for any set of screen??!!!

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  • How to clean up my code

    - by simion
    Being new to this i realy am trying to learn how to keep code as simple as possible, whilst doing the job its supposed to. The question i have done is from project eulur, it says Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... Find the sum of all the even-valued terms in the sequence which do not exceed four million. Here is my code below, i was wondering what the best way of simplifying this would be, for a start removing all of the .get(list.length()-1 )..... stuff would be a good start if possible but i dont really no how to? Thanks public long fibb() { ArrayList<Integer> list = new ArrayList<Integer>(); list.add(1); list.add(2); while((list.get(list.size() - 1) + (list.get(list.size() - 2)) < 4000000)){ list.add((list.get(list.size()-1)) + (list.get(list.size() - 2))); } long value = 0; for(int i = 0; i < list.size(); i++){ if(list.get(i) % 2 == 0){ value += list.get(i); } } return value; }

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  • adding elements in to the doubly linked list

    - by user329820
    Hi this is my code for main class and doubly linked class and node class but when I run the program ,in the concole will show this"datastructureproject.DoublyLinkedList@19ee1ac" instead of the random numbers .please help me thanks! main class: public class Main { public static int getRandomNumber(double min, double max) { Random random = new Random(); return (int) (random.nextDouble() * (max - min) + min); } public static void main(String[] args) { int j; int i = 0; i = getRandomNumber(10, 10000); DoublyLinkedList listOne = new DoublyLinkedList(); for (j = 0; j <= i / 2; j++) { listOne.add(getRandomNumber(10, 10000)); } System.out.println(listOne); } } doubly linked list class: public class DoublyLinkedList { private Node head ; private Node tail; private long size = 0; public DoublyLinkedList() { head= new Node(0, null, null); tail = new Node(0, head, null); } public void add(int i){ head.setValue(i); Node newNode = new Node(); head.setNext(newNode); newNode.setPrev(head); newNode = head; } } and the node class is like the class that you have seen before (Node prev,Node next,int value)

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