Search Results

Search found 46178 results on 1848 pages for 'java home'.

Page 980/1848 | < Previous Page | 976 977 978 979 980 981 982 983 984 985 986 987  | Next Page >

  • Swing: Programmatically select a text

    - by HH
    Hey everyone, I have a very simple Swing GUI with just a JTetxtArea. I am trying to programmatically select a part of text using: textArea.select(startSelection,endSelection); This work. However as soon as I add some other components to the GUI I do not see selection anymore frame.getContentPane().add(button); frame.getContentPane().add(textArea); textArea.select(startSelection,endSelection); I suspect that during layouting the gui, some event causes the text to be deselected. Am I right? And could anybody suggest a solution? My goal is to have a program which displays a text, and allows the user to input start and end selection position, and a selection appears between these two position. Thank you.

    Read the article

  • How do I ensure my abstract class's function can only operate on extenders of the same type as the c

    - by incrediman
    For example, let's say this is my abstract class: abstract class A{ int x; int y; void foo(A fooMe); } ...and B and C are two classes which extend A. What I want is for B to only be able to call foo() on other Bs, and for C to only be able to call foo() on other Cs. But I want this to be out of the hands of the programmer who's extending my A class - that is, I want a way to ensure this functionality within As code alone. What can I do? (If possible) I'd like to avoid any hack or generics solution that's too messy - I still want foo to be able to be called like this, for example: B b=new B(); B bb=new B(); bb.foo(b);

    Read the article

  • Logger.setLevel() doesn't enable logging correctly

    - by ripper234
    Situation: I have this log4j logger: private static final Logger logger = Logger.getLogger(ThisClassName.class); And am trying to set it programatically through: Logger.getLogger(ThisClassName.class).setLevel(Level.DEBUG); Still, DEBUG level prints are swalloed (while INFO prints are printed successfully). Even this bit has no effect: Logger.getRootLogger().setLevel(Level.DEBUG); Calling logger.debug("foo") reaches Category.forcedLog() and ConsoleAppender.doAppend(), and then fails (quits) at: if(!isAsSevereAsThreshold(event.getLevel())) Any idea why this is happening?

    Read the article

  • Is this technically thread safe despite being mutable?

    - by Finbarr
    Yes, the private member variable bar should be final right? But actually, in this instance, it is an atomic operation to simply read the value of an int. So is this technically thread safe? class foo { private int bar; public foo(int bar) { this.bar = bar; } public int getBar() { return bar; } } // assume infinite number of threads repeatedly calling getBar on the same instance of foo.

    Read the article

  • Keeping track of threads when creating them recursively

    - by 66replica
    I'm currently working on some code for my Programming Languages course. I can't post the code but I'm permitted to talk about some high level concepts that I'm struggling with and receive input on them. Basically the code is a recursive DFS on a undirected graph that I'm supposed to convert to a concurrent program. My professor already specified that I should create my threads in the recursive DFS method and then join them in another method. Basically, I'm having trouble thinking of how I should keep track of the threads I'm creating so I can join all of them in the other method. I'm thinking an array of Threads but I'm unsure how to add each new thread to the array or even if that's the right direction.

    Read the article

  • DocumentBuilder.parse() / Parsing Entities

    - by stormin986
    I'm new to parsing XML and am having an issue with entities. (Am doing this on Android, if it makes a difference). Is there a way to have it turn an entity into the character it represents? I have this in the child of an element: "isn&#39;t" (minus quotes). I would prefer it parse it and the end result be a single text node. However, right now this is turned in to TEXT, ENTITY, TEXT. Is there a way to automatically have it parse the entity into text, or a manual way to do it?

    Read the article

  • What will happen if the code can't finished on time...

    - by Tattat
    If I set a timer to execute a code every 3 seconds. If the code isn't finished in 3 seconds, what will happen? The computer will terminal the code or wait for the code finish or continue the timer, and execute the code with the unfinished code concurrently. int delay = 0; // delay for 0 sec. int period = 3000; // repeat 3 sec. Timer timer = new Timer(); timer.scheduleAtFixedRate(new TimerTask() { public void run() { // Task here ... // It may take more than 3 sec to finish, what will happen? } }, delay, period);

    Read the article

  • Creating an instance within the Class itself

    - by didxga
    What's going on when the assignment statement executed at Line 4, does compiler ignore the new operator and keep the foo variable being null or something else happen to handle this awkward moment? public class Foo { // creating an instance before its constructor has been invoked, suppose the "initializing" // gets printed in constructor as a result of the next line, of course it will not print it private Foo foo = new Foo();//Line 4 public Foo() { System.out.println("initializing"); } }

    Read the article

  • multiplying all elements in an array by an outside number?

    - by prodo
    I need to multiple all the values in an array by 3000 which in turn would create a new array that I will use to subtract from another array. I've tried to create a separate method that would do that for me but all I got back in the multiplied array was a bunch of numbers and symbols strangely? here is the code that I wrote public static void main(String[] args) { int numberOfTaxpayers = Integer.parseInt(JOptionPane.showInputDialog("Enter how many users you would like to calculate taxes for: "); int[] usernumChild = new int[numberOfTaxPayers]; for (int i = 0; i < usernumChild.length; i++) { usernumChild[i] = Integer.parseInt(JOptionPane.showInputDialog("Enter number of children for user "+ (i+1) +": ")); }//this for loop finds out the number of children per user so we can later multiply each input by 3000 to create an array that determine dependency exemption for each user int[] depndExemp = multiply(usernumChild, 3000);//this was the calling of the multiply method... somewhere here is the error!! }//end main method public static int[] multiply(int[] children, int number) { int array[] = new int[children.length]; for( int i = 0; i < children.length; i++) { children[i] = children[i] * number; }//end for return array; }//this is the method that I was shown in a previous post on how to create return an array in this the dependency exemption array but when I tested this by printing out the dependency array all I received were a jumble of wrong numbers.

    Read the article

  • Unable to establish the connection to the file in BlackBerry

    - by Vikas
    I have tried the example code on SO to read the contents from the file in the resource directory in BlackBerry. But I am having an issue with the FileConnection. I get the following error: File system error (1003) I tried the example from here. I want only the read functionality, the file I want to read is in CSV format as a .txt file placed in the /res/test.txt. public class FileDemo extends MainScreen { public FileDemo() { setTitle("My Page"); String str = readTextFile("file:///test.txt"); System.out.println("Contents of the file::::::: " + str); } public String readTextFile(String fName) { String result = null; FileConnection fconn = null; DataInputStream is = null; try { fconn = (FileConnection) Connector.openInputStream(fName); is = fconn.openDataInputStream(); byte[] data = IOUtilities.streamToBytes(is); result = new String(data); } catch (IOException e) { System.out.println(e.getMessage()); } finally { try { if (null != is) is.close(); if (null != fconn) fconn.close(); } catch (IOException e) { System.out.println(e.getMessage()); } } return result; } } Any suggestions/advice on a better approach or as to how I can get this working??

    Read the article

  • How to unload JVM from a living process?

    - by Guy
    Hi, I'm working with JNI and trying to unload (destroy) the VM using DestoryJavaVM function (I first call DetachCurrentThread method). It seems like the it has now influence on the VM and it is still up after the call. I read in old Sun posts that DestoryJavaVM had problems in the past (JDK1.1-1.3 in 2001) but I'm using JRE 6 and it probably should work now, right? I need to Load\Unload a VM in the same living process since each loading requires another classes to load. Any ideas how it can be done? Thanks, Guy

    Read the article

  • Performance side effect with static internal Util classes?

    - by Fostah
    For a util class that contains a bunch of static functionality that's related to the same component, but has different purposes, I like to use static internal classes to organize the functionality, like so: class ComponentUtil { static class Layout { static int calculateX(/* ... */) { // ... } static int calculateY(/* ... */) { // ... } } static class Process { static int doThis(/* ... */) { // ... } static int doThat(/* ... */) { // ... } } } Is there any performance degradation using these internal classes vs. just having all the functionality in the Util class?

    Read the article

  • How is it possible my array is broken?

    - by user1812765
    I have this piece of code: public lot merge (lot otherlot){ wafer[] mWaferarray = new wafer[16]; byte[] bytearray = new byte[16]; wafer resultwafer = new wafer(bytearray); wafer w1; wafer w2; int i; int[][] assignmentmatrix = HungarianAlgorithm.computeAssignments(convertinttofloat (solutionmatrix(otherlot))); for (i=0; i != assignmentmatrix.length ;i++){ w1 = otherlot.getWaferarray()[assignmentmatrix[i][0]]; w2 = getWaferarray()[assignmentmatrix[i][1]]; resultwafer.setWafer(w1.wafercompare(w2)); mWaferarray[i] = resultwafer; mWaferarray[i].print(); } System.out.println("HERE\n"); mWaferarray[5].toString(); resultlot = new lot(mWaferarray); resultlot.print();// Problem occurs here. return resultlot; } As you can see I create an array of wafers (selfdefined class). Then I fill this up with new wafers. When I print this array (mWaferarray[i].print()) it gives me the wanted results. But when I go out of the "for"-loop the array is broken and it is as if the last item I add to mWaferarray fills it up (the entire array, 16 long, is filled with this wafer). So if run this program this is what I get: 1011110010111100 0011011111111110 0111110111101101 1010111001101111 0110110111101111 1010110101111010 1010110111011110 1011111010111100 1111110011101110 0111111111011011 1111111111011010 1101111011111010 1010110101011110 0101111011011010 1011111011011000 0101111011011010 HERE 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 As you can see it is as if the array is filled with the last wafer. I have been looking at this for some time now, I hope you guy can help me out. Thx in advance PS: my print functions are written like this: void print(){ int j; for (j=0; j != waferarray.length ;j++){ waferarray[j].print(); } } EDIT: added code for lot this is the beginning of the lot class public class lot { wafer[] waferarray = new wafer[16]; lot resultlot; public lot (wafer wafer1,wafer wafer2,wafer wafer3,wafer wafer4, wafer wafer5,wafer wafer6,wafer wafer7,wafer wafer8, wafer wafer9,wafer wafer10,wafer wafer11,wafer wafer12, wafer wafer13,wafer wafer14,wafer wafer15,wafer wafer16){ waferarray[0] = wafer1; waferarray[1] = wafer2; waferarray[2] = wafer3; waferarray[3] = wafer4; waferarray[4] = wafer5; waferarray[5] = wafer6; waferarray[6] = wafer7; waferarray[7] = wafer8; waferarray[8] = wafer9; waferarray[9] = wafer10; waferarray[10] = wafer11; waferarray[11] = wafer12; waferarray[12] = wafer13; waferarray[13] = wafer14; waferarray[14] = wafer15; waferarray[15] = wafer16; } public lot (wafer[] thiswaferarray){ waferarray = thiswaferarray; }

    Read the article

  • how can i display the database data to an jtable(dynamic) in the swings!

    - by harish0510
    we are using hibernate in business layer,but the task is, by using the jtable in swings to display the dynamic data(swings) from the database. code: Criteria criteria=session.createCriteria(User.class); //here user.class is pojo class in hibernate. List studentlist= criteria.list(); System.out.println("records"+studentlist); here the data is showing in hibernate console, but how to represent that data in the format of "jtable".

    Read the article

  • I asked a question about arrays before, but this one won't compile

    - by unit
    I asked about this array a little while ago, and I can't see what the problem is. Too tired. What have I done wrong? Basically, I am taking a string array and trying to check to see if it contains numbers or an x (ISBN number validation). I want to take the number from a given input (bookNum), check the input, and feed any valid input into a new array (book). At the line 'bookNum.charAt[j]==book[i]' I get the 'not a statement error'. What gives? String[] book = new String [ISBN_NUM]; bookNum.replaceAll("-",""); if (bookNum.length()!=ISBN_NUM) throw new ISBNException ("ISBN "+ bookNum + " must be 10 characters"); for (int i=0;i<bookNum.length();i++) { if (Character.isDigit(bookNum.charAt(i))) bookNum.CharAt[j]==book[i]; j++; if (book[9].isNotDigit()|| book[9]!="x" || book[9]!="X") throw new ISBNException ("ISBN " + bookNum + " must contain all digits" + "or 'X' in the last position");

    Read the article

  • Android - Help needed with designing a screen with either table layout or list views

    - by A. Cusano
    I am currently developing an android app that is to be a counterpart to its sister iphone prototype. My task is to recreate the screen from a design mockup from the iphone app in android, as shown here (can't display an image as a new user - sorry!): http://img.photobucket.com/albums/v439/thrawn891/iphone.jpg What would be the best layouts / views to use for replicating this screen in an activity? Thanks.

    Read the article

  • AJAX Problem - No response text in FireFox, but ok in IE

    - by Taiba
    Hi, I am making a simple AJAX call to an external site. It works ok in IE, but in Firefox, not response text is returned. I think it might have something to do with the response being "chunked", but I'm not sure. Any ideas? Thanks. function loadXMLDoc() { var xmlhttp; var urlString = "http://drc.edeliver.com.au/ratecalc.asp?Pickup_Postcode=6025&Destination_Postcode=6055&Country=AU&Weight=100&Service_Type=STANDARD&Length=100&Width=100&Height=100&Quantity=2"; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { window.alert(xmlhttp.responseText); } } xmlhttp.open("GET", urlString, true); xmlhttp.send(); }

    Read the article

  • Creating Linear Layout with TextViews using a for loop

    - by cad8
    Hi all, I was wondering if there is a way to dynamically create an additional linear layout with a textview within a predefined liner layout. THis is my code so you get the gist of what I am asking: LinearLayout MainLL= (LinearLayout) findViewById(R.id.myLayoutId); for(int i=0; i<5; i++) { LinearLayout childLL= new LinearLayout(this); childLL.setOrientation(LinearLayout.VERTICAL); childLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); childLL.setGravity(Gravity.LEFT); TextView text = new TextView(this); text.setText("The Value of i is :"i); text.setTextSize(12); text.setGravity(Gravity.LEFT); text.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT)); childLL.addView(text); MainLL.addView(childLL); } My problem is that I am only getting "The Value of i is :0" as the output, i.e. the first instance. Any help would be much appreciated

    Read the article

< Previous Page | 976 977 978 979 980 981 982 983 984 985 986 987  | Next Page >